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JEE Main 4 April 2026 Shift 2 Question Paper with Answers

4 April 2026 · April session · 75 questions

The complete JEE Main 4 April 2026 Shift 2 paper — all 75 questions with the correct answer for each, tagged to the chapter it tests. Free to read, no account needed.

Physics
25
Chemistry
25
Mathematics
25

Physics — JEE Main 4 April 2026 Shift 2

Q1·PhysicsSingle correct
Match the LIST-I with LIST-II. Choose the correct answer from the options given below:
List-IList-II
A.Planck's constantI.ML2T−2ML^{2}T^{-2}ML2T−2
B.Stopping potentialII.T−1T^{-1}T−1
C.Work functionIII.ML2T−1ML^{2}T^{-1}ML2T−1
D.Threshold frequencyIV.ML2T−3A−1ML^{2}T^{-3}A^{-1}ML2T−3A−1
  1. (A)A-III, B-IV, C-I, D-II
  2. (B)A-I, B-II, C-III, D-IV
  3. (C)A-IV, B-III, C-I, D-II
  4. (D)A-I, B-IV, C-III, D-II

Correct answer: (A)

Step-by-step solution →
Q2·PhysicsSingle correct
Two cars AAA and BBB are moving in the same direction along a straight line with speeds 100 km/h and 80 km/h, respectively such that car AAA is moving ahead of car BBB. A person in car BBB throws a stone with a speed vvv so that it hits the car AAA with a speed of 5 m/s. The value of vvv is ______ km/h.
  1. (A)18
  2. (B)28
  3. (C)38
  4. (D)48

Correct answer: (C)

Step-by-step solution →
Q3·PhysicsSingle correct
At t=0t = 0t=0, a body of mass 100 g starts moving under the influence of a force (5i^+10j^)(5\hat{i} + 10\hat{j})(5i^+10j^​) N. After 2 s its position is (2xi^+5yj^)(2x\hat{i} + 5y\hat{j})(2xi^+5yj^​) m. The ratio x:yx : yx:y is ______.
  1. (A)1 : 2
  2. (B)2 : 5
  3. (C)5 : 2
  4. (D)5 : 4

Correct answer: (D)

Step-by-step solution →
Q4·PhysicsSingle correct
If xxx and yyy coordinates of a projectile as a function of time (t)(t)(t) are given as 24t24t24t and 43.6t−4.9t243.6t - 4.9t^{2}43.6t−4.9t2, respectively, then the angle (in degrees) made by the projectile with horizontal when t=2t = 2t=2 s is ______.
  1. (A)60
  2. (B)45
  3. (C)30
  4. (D)75

Correct answer: (B)

Step-by-step solution →
Q5·PhysicsSingle correct
The height in terms of radius of the earth (R)(R)(R), at which the acceleration due to gravity becomes g9\frac{g}{9}9g​, where ggg is acceleration due to gravity on earth's surface, is ______.
  1. (A)3R\sqrt{3}R3​R
  2. (B)22R2\sqrt{2}R22​R
  3. (C)2R2R2R
  4. (D)49R\frac{4}{9}R94​R

Correct answer: (C)

Step-by-step solution →
Q6·PhysicsSingle correct
A metal string AAA is suspended from a rigid support and its free end is attached to a block of mass MMM. Second block having mass 2M2M2M is suspended at the bottom of the first block using a string BBB. The area of cross sections of strings AAA and BBB are same. The ratio of lengths of strings of AAA to BBB is 2 and the ratio of their Young's moduli (YA/YB)(Y_{A}/Y_{B})(YA​/YB​) is 0.5. The ratio of elongations in AAA to BBB is ______.
  1. (A)1
  2. (B)4
  3. (C)8
  4. (D)6

Correct answer: (D)

Step-by-step solution →
Q7·PhysicsSingle correct
A water spray gun is attached to a hose of cross sectional area 30 cm2^{2}2. The gun comprises of 10 perforations each of cross sectional area 15 mm2^{2}2. If the water flows in the hose with the speed of 50 cm/s, calculate the speed at which the water flows out from each perforation. (Neglect any edge effects)
  1. (A)100 m/s
  2. (B)10 m/s
  3. (C)1000 m/s
  4. (D)15×10215 \times 10^{2}15×102 m/s

Correct answer: (B)

Step-by-step solution →
Q8·PhysicsSingle correct
Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R Assertion A: If the average kinetic energy of H2H_{2}H2​ and O2O_{2}O2​ molecules, kept in two different sized containers are same, then their temperatures will be same. Reason R: The r.m.s. speed of H2H_{2}H2​ and O2O_{2}O2​ molecules are same at same temperature. Choose the correct answer from the options given below
  1. (A)Both A and R are true and R is the correct explanation of A
  2. (B)Both A and R are true but R is NOT the correct explanation of A
  3. (C)A is true but R is false
  4. (D)A is false but R is true

Correct answer: (C)

Step-by-step solution →
Q9·PhysicsSingle correct
The temperature of a metal strip having coefficient of linear expansion α\alphaα is increased from T1T_{1}T1​ to T2T_{2}T2​ resulting in increase of its length by ΔL1\Delta L_{1}ΔL1​. The temperature is further increased from T2T_{2}T2​ to T3T_{3}T3​ such that the increase in its length is ΔL2\Delta L_{2}ΔL2​. Given T3+T1=2T2T_{3} + T_{1} = 2T_{2}T3​+T1​=2T2​ and T2−T1=ΔTT_{2} - T_{1} = \Delta TT2​−T1​=ΔT, the value of ΔL2\Delta L_{2}ΔL2​ is ______.
  1. (A)ΔL1[1+2α2(ΔT)2]\Delta L_{1}[1 + 2\alpha^{2}(\Delta T)^{2}]ΔL1​[1+2α2(ΔT)2]
  2. (B)ΔL1[1+α2(ΔT)2]\Delta L_{1}[1 + \alpha^{2}(\Delta T)^{2}]ΔL1​[1+α2(ΔT)2]
  3. (C)ΔL1[1+2αΔT]\Delta L_{1}[1 + 2\alpha\Delta T]ΔL1​[1+2αΔT]
  4. (D)ΔL1[1+αΔT]\Delta L_{1}[1 + \alpha\Delta T]ΔL1​[1+αΔT]

Correct answer: (D)

Step-by-step solution →
Q10·PhysicsSingle correct
A uniform disc of radius RRR and mass MMM is free to oscillate about the axis AAA as shown in the figure. For small oscillations the time period is ______. (ggg is acceleration due to gravity)
  1. (A)2π5R4g2\pi\sqrt{\frac{5R}{4g}}2π4g5R​​
  2. (B)2π2R3g2\pi\sqrt{\frac{2R}{3g}}2π3g2R​​
  3. (C)2π3R2g2\pi\sqrt{\frac{3R}{2g}}2π2g3R​​
  4. (D)2π3Rg2\pi\sqrt{\frac{3R}{g}}2πg3R​​

Correct answer: (A)

Step-by-step solution →
Q11·PhysicsSingle correct
A rigid dipole undergoes a simple harmonic motion about its centre in the presence of an electric field E⃗1=E0x^\vec{E}_{1} = E_{0}\hat{x}E1​=E0​x^. If another electric field E⃗2=2E0(y^+z^)\vec{E}_{2} = 2E_{0}(\hat{y} + \hat{z})E2​=2E0​(y^​+z^) is introduced to the system, what will be the percentage change in the frequency of the oscillation (approximate)?
  1. (A)73%
  2. (B)63%
  3. (C)83%
  4. (D)53%

Correct answer: (A)

Step-by-step solution →
Q12·PhysicsSingle correct
From the circuit given below, the capacitance between terminals AAA and BBB shown in the circuit is ______ μF. (take C1=C2=C3=1C_{1} = C_{2} = C_{3} = 1C1​=C2​=C3​=1 μF and C4=2C_{4} = 2C4​=2 μF.)
  1. (A)2
  2. (B)7/2
  3. (C)7/3
  4. (D)5/2

Correct answer: (A)

Step-by-step solution →
Q13·Physics·Electric Field and Coulomb's LawSingle correct
Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R Assertion A: In electrostatics, a conductor does not store any net charge inside. Reason R: Inside the capacitor (with no dielectric medium), the free charge carriers, if placed between the plates of capacitor, experience force and drift. Choose the correct answer from the options given below
  1. (A)Both A and R are true and R is the correct explanation of A
  2. (B)Both A and R are true but R is NOT the correct explanation of A
  3. (C)A is true but R is false
  4. (D)A is false but R is true

Correct answer: (B)

Step-by-step solution →
Q14·PhysicsSingle correct
A solenoid has a core made of material with relative permeability 400. The magnetic field produced in the interior of solenoid is 1.0 T. The magnetic intensity in SI units is α × 10510^{5}105. The value of α is ______. (Free space permeability μ0=4π×10−7\mu_{0} = 4\pi \times 10^{-7}μ0​=4π×10−7 SI units.)
  1. (A)25π\frac{25}{\pi}π25​
  2. (B)116π\frac{1}{16\pi}16π1​
  3. (C)1π\frac{1}{\pi}π1​
  4. (D)14π\frac{1}{4\pi}4π1​

Correct answer: (B)

Step-by-step solution →
Q15·PhysicsSingle correct
A magnetic field vector in an electromagnetic wave is represented by B⃗=B0sin⁡(2πvt−2πxλ)j^\vec{B} = B_{0}\sin\left(2\pi vt - \frac{2\pi x}{\lambda}\right)\hat{j}B=B0​sin(2πvt−λ2πx​)j^​. Its associated electric field vector is ______.
  1. (A)E⃗=−vλB0sin⁡(2πvt−2πxλ)k^\vec{E} = -v\lambda B_{0}\sin\left(2\pi vt - \frac{2\pi x}{\lambda}\right)\hat{k}E=−vλB0​sin(2πvt−λ2πx​)k^
  2. (B)E⃗=−vλB0sin⁡(2πvt−2πxλ)i^\vec{E} = -v\lambda B_{0}\sin\left(2\pi vt - \frac{2\pi x}{\lambda}\right)\hat{i}E=−vλB0​sin(2πvt−λ2πx​)i^
  3. (C)E⃗=vλB0sin⁡(2πvt−2πxλ)k^\vec{E} = v\lambda B_{0}\sin\left(2\pi vt - \frac{2\pi x}{\lambda}\right)\hat{k}E=vλB0​sin(2πvt−λ2πx​)k^
  4. (D)E⃗=vλB0sin⁡(2πvt−2πxλ)i^\vec{E} = v\lambda B_{0}\sin\left(2\pi vt - \frac{2\pi x}{\lambda}\right)\hat{i}E=vλB0​sin(2πvt−λ2πx​)i^

Correct answer: (A)

Step-by-step solution →
Q16·PhysicsSingle correct
A convex lens is made from glass material having refractive index of 1.4 with same radius of curvature on both sides. The ratio of its focal length and radius of curvature is ______.
  1. (A)0.5
  2. (B)2.5
  3. (C)0.8
  4. (D)1.25

Correct answer: (D)

Step-by-step solution →
Q17·PhysicsSingle correct
An unpolarized light of certain intensity passes through a combination of two polarizers whose transmission axes are at 30° and 90°, respectively, with respect to the horizontal axis. A third polarizer with its transmission axis at 60° with the horizontal axis is placed between the two existing polarizers. The ratio of the output intensities with and without the third polarizer is ______.
  1. (A)3/4
  2. (B)4/3
  3. (C)9/4
  4. (D)4/9

Correct answer: (C)

Step-by-step solution →
Q18·PhysicsSingle correct
In Rutherford's alpha-particle scattering experiment, only a few alpha particles rebound back because A. The size of gold nucleus is very small as compared to the size of gold atom. B. Alpha particle and gold nucleus have equal charge. C. The impact parameter is minimum for a few alpha particles. D. A few alpha particles have very high kinetic energy. E. Only a few alpha particles undergo head-on collision with the nuclei. Choose the correct answer from the options given below:
  1. (A)A, B Only
  2. (B)B, E Only
  3. (C)C, D Only
  4. (D)A, C, E Only

Correct answer: (D)

Step-by-step solution →
Q19·PhysicsSingle correct
The de Broglie wavelength associated with an electron accelerated through a potential difference V is λe\lambda_{e}λe​ and the de Broglie wavelength associated with a proton accelerated through the same potential difference is λp\lambda_{p}λp​. If their corresponding masses are mem_{e}me​ and mpm_{p}mp​, respectively, then the ratio of their de Broglie wavelengths (λeλp)\left(\frac{\lambda_{e}}{\lambda_{p}}\right)(λp​λe​​) is ______.
  1. (A)mpme\sqrt{\frac{m_{p}}{m_{e}}}me​mp​​​
  2. (B)memp\sqrt{\frac{m_{e}}{m_{p}}}mp​me​​​
  3. (C)mpme\frac{m_{p}}{m_{e}}me​mp​​
  4. (D)(mpme)2\left(\frac{m_{p}}{m_{e}}\right)^{2}(me​mp​​)2

Correct answer: (A)

Step-by-step solution →
Q20·PhysicsSingle correct
Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R Assertion A: A diode under reverse-biased condition provides very small current which is nearly independent of voltage until a critical limit at which the current increases drastically. Reason R: Below the critical voltage limit, only majority charge carriers flow which increases drastically above critical voltage. Choose the correct answer from the options given below
  1. (A)Both A and R are true and R is the correct explanation of A
  2. (B)Both A and R are true but R is NOT the correct explanation of A
  3. (C)A is true but R is false
  4. (D)A is false but R is true

Correct answer: (C)

Step-by-step solution →
Q21·PhysicsNumerical
A diode has Zener voltage of 10 V and maximum power dissipation of 0.5 W, then the minimum resistance to be used in series with this diode for safety when it is connected to a 25 V power supply is ______ Ω.

Correct answer: 300

Step-by-step solution →
Q22·PhysicsNumerical
A gun mounted on the ground fires bullets in all directions with same speed. The farthest distance the bullets could reach is 6.4 m. The speed of the bullets from the gun is ______ m/s. (take g=10g = 10g=10 m/s2s^{2}s2)

Correct answer: 8

Step-by-step solution →
Q23·PhysicsNumerical
Two identical small bar magnets each of dipole moment 353\sqrt{5}35​ J/T are placed at a center to center separation of 10 cm, with their axes perpendicular to each other as shown in figure. The value of magnetic field at the point P midway between the magnets is α × 10−310^{-3}10−3 T. The value of α is ______. (μ0=4π×10−7\mu_{0} = 4\pi \times 10^{-7}μ0​=4π×10−7 Tm/A)

Correct answer: 12

Step-by-step solution →
Q24·Physics·Magnetic Field of CurrentNumerical
A circular coil of radius 2 cm and 125 turns carries a current of 1 A. The coil is placed in a uniform magnetic field of magnitude 0.4 T. The axis of the coil makes an angle of 30° with the direction of the magnetic field. The torque acting on the coil is α × 10−410^{-4}10−4 N.m. The value of α is ______. (π=3.14\pi = 3.14π=3.14)

Correct answer: 314

Step-by-step solution →
Q25·PhysicsNumerical
In a double slit experiment, when one of the slits is covered by a transparent mica sheet of refractive index 1.56, the central fringe shifts to the position of 7th7^{th}7th bright fringe, obtained with both slits uncovered. If the light source wavelength is 450 nm, the thickness of mica sheet is α × 10−910^{-9}10−9 m. The value of α is ______.

Correct answer: 5625

Step-by-step solution →

Chemistry — JEE Main 4 April 2026 Shift 2

Q26·ChemistrySingle correct
The correct order of total number of atoms present in (A) 2 moles of cyclohexane (B) 684 g of sucrose (C) 90.8 L of dihydrogen at STP is:
  1. (A)C>A>BC > A > BC>A>B
  2. (B)C>B>AC > B > AC>B>A
  3. (C)B>C>AB > C > AB>C>A
  4. (D)B>A>CB > A > CB>A>C

Correct answer: (D)

Step-by-step solution →
Q27·ChemistrySingle correct
The species having identical radii according to the Bohr's theory are: A. HHH (first orbit) B. He+He^{+}He+ (first orbit) C. He+He^{+}He+ (Second orbit) D. Li2+Li^{2+}Li2+ (first orbit) E. Be3+Be^{3+}Be3+ (Second orbit) Choose the correct answer from the options given below:
  1. (A)A and C Only
  2. (B)A and E Only
  3. (C)B and E Only
  4. (D)C and D Only

Correct answer: (B)

Step-by-step solution →
Q28·ChemistrySingle correct
Which of the following pictorial diagram most correctly represents the π* (π-antibonding) molecular orbital between two atoms if the internuclear axis is taken to be in the z-direction (→z-axis\xrightarrow{\text{z-axis}}z-axis​)?
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (C)

Step-by-step solution →
Q29·ChemistrySingle correct
At 27°C, 0.1 M, 1 L K4[Fe(CN)6]\mathrm{K_{4}[Fe(CN)_{6}]}K4​[Fe(CN)6​] aqueous solution and 0.1 M, 1 L FeCl3\mathrm{FeCl_{3}}FeCl3​ aqueous solution are placed in a container separated by a semi permeable membrane AB. Assume complete dissociation of both the solutes. Which of the following statement is correct?
  1. (A)Blue color is formed on both sides.
  2. (B)Ionic solutes in aqueous solution can pass through semi-permeable membrane.
  3. (C)Solution on side 'y' is hypotonic.
  4. (D)To cause the reverse flow of solvent during osmosis, external pressure (any value) should be applied to side 'x'.

Correct answer: (C)

Step-by-step solution →
Q30·ChemistrySingle correct
20 mL of a solution of acetic acid required 28.4 mL of 0.1 M NaOH for its neutralization. A solution (X) was prepared by mixing 20 mL of the above acetic acid and 14.2 mL of 0.1 M NaOH solution. What is the pH of the solution (X)? (pKapK_{a}pKa​ value of acetic acid is 4.75).
  1. (A)7.0
  2. (B)4.75
  3. (C)3.5
  4. (D)4.82

Correct answer: (B)

Step-by-step solution →
Q31·Chemistry·Reaction MechanismSingle correct
Match the LIST-I (Reaction) with LIST-II (Mechanism). Choose the correct answer from the options given below:
List-I (Reaction)List-II (Mechanism)
A.Williamson SynthesisI.Electrophilic addition
B.Friedel Craft ReactionII.Free radical substitution
C.Bromination of vinyl benzeneIII.Nucleophilic substitution
D.Chlorination of toluene in lightIV.Electrophilic substitution
  1. (A)A-III, B-I, C-II, D-IV
  2. (B)A-III, B-IV, C-II, D-I
  3. (C)A-III, B-IV, C-I, D-II
  4. (D)A-I, B-III, C-IV, D-II

Correct answer: (C)

Step-by-step solution →
Q32·ChemistrySingle correct
The 1st1^{st}1st ionization enthalpy for Mg is +737 kJ/mol. The most probable estimated value of the 2nd2^{nd}2nd ionization enthalpy of Mg is ______.
  1. (A)−906 kJ/mol
  2. (B)−856 kJ/mol
  3. (C)+1450 kJ/mol
  4. (D)+590 kJ/mol

Correct answer: (C)

Step-by-step solution →
Q33·ChemistrySingle correct
The electronegativity of a group 13 element 'E' is same as that of Ge (on Pauling scale and upto one decimal point). The CORRECT statements about E3+E^{3+}E3+ are A. It can act as a reducing agent. B. It can act as an oxidizing agent. C. E3+E^{3+}E3+ is more stable than E+E^{+}E+. D. The standard electrode potential value for E3+/EE^{3+}/EE3+/E is positive. Choose the correct answer from the options given below:
  1. (A)A and C Only
  2. (B)B and C Only
  3. (C)B and D Only
  4. (D)A and D Only

Correct answer: (C)

Step-by-step solution →
Q34·ChemistrySingle correct
Pairs of elements with the same number of electrons in their respective 4f orbital are [Atomic number. Eu-63, Gd-64, Dy-66, Ho-67, Tm-69, Yb-70, Lu-71, Hf-72] A. (Eu and Gd) B. (Dy and Ho) C. (Yb and Hf) D. (Lu and Tm) Choose the correct answer from the options given below:
  1. (A)B and C Only
  2. (B)A and B Only
  3. (C)A and D Only
  4. (D)A and C Only

Correct answer: (D)

Step-by-step solution →
Q35·ChemistrySingle correct
Consider the metal complexes [Ni(en)3]2+[Ni(en)_{3}]^{2+}[Ni(en)3​]2+ (A), [NiCl4]2−[NiCl_{4}]^{2-}[NiCl4​]2− (B) and [Ni(NH3)6]2+[Ni(NH_{3})_{6}]^{2+}[Ni(NH3​)6​]2+ (C). Choose the CORRECT option by considering the number of unpaired electrons present in (A), (B) and (C) respectively and the order of frequency of absorption.
  1. (A)2,2,22, 2, 22,2,2 and (A)>(C)>(B)(A) > (C) > (B)(A)>(C)>(B)
  2. (B)0,2,00, 2, 00,2,0 and (A)>(C)>(B)(A) > (C) > (B)(A)>(C)>(B)
  3. (C)2,2,02, 2, 02,2,0 and (B)>(C)>(A)(B) > (C) > (A)(B)>(C)>(A)
  4. (D)2,2,22, 2, 22,2,2 and (C)>(A)>(B)(C) > (A) > (B)(C)>(A)>(B)

Correct answer: (A)

Step-by-step solution →
Q36·Chemistry·Electronic Effects and StabilitySingle correct
Consider the following molecules/species: (x)(x)(x) tropone, (y)(y)(y) acetone, (z)(z)(z) acetate ion The correct order of carbon – oxygen double bond length is:
  1. (A)x>y>zx > y > zx>y>z
  2. (B)y>z>xy > z > xy>z>x
  3. (C)z>x>yz > x > yz>x>y
  4. (D)x>z>yx > z > yx>z>y

Correct answer: (C)

Step-by-step solution →
Q37·ChemistrySingle correct
Consider ∣x∣|x|∣x∣ is the difference in oxidation states of Mn in highest manganese fluoride and highest manganese oxide. The ions with ∣x∣|x|∣x∣ number of unpaired electrons from the following are: A. Sc3+Sc^{3+}Sc3+ B. Zn2+Zn^{2+}Zn2+ C. V2+V^{2+}V2+ D. Fe2+Fe^{2+}Fe2+ E. Co2+Co^{2+}Co2+ Choose the correct answer from the options given below:
  1. (A)A and B Only
  2. (B)C, D and E Only
  3. (C)C and E Only
  4. (D)B and E Only

Correct answer: (C)

Step-by-step solution →
Q38·ChemistrySingle correct
Consider the given graph showing variation of reactant concentration with time. Three different reactions were started with identical initial concentration of reactants. Which of the following statement is correct?
  1. (A)The order of all the three reactions is same.
  2. (B)The rate constant of reaction 3 is larger than the rate constant of reaction 2 if the order of reaction is same for both.
  3. (C)The SI unit of rate constant of reaction 1 is s−1\mathrm{s^{-1}}s−1.
  4. (D)Thermal decomposition of HI on gold surface is an example of reaction 2.

Correct answer: (B)

Step-by-step solution →
Q39·ChemistrySingle correct
Compound (X) [styrene] is subjected to the sequence of reactions as shown above: (i) Br2/CHCl3\mathrm{Br_{2}/CHCl_{3}}Br2​/CHCl3​ (ii) NaNH2\mathrm{NaNH_{2}}NaNH2​ excess (iii) CH3I\mathrm{CH_{3}I}CH3​I (iv) H2\mathrm{H_{2}}H2​, Na/NH3\mathrm{Na/NH_{3}}Na/NH3​ (l), giving Major Product (Y). Molar mass of the major product (Y) formed is ______ g mol−1^{-1}−1. (Given molar mass in g mol−1^{-1}−1 C:12, H: 1, O: 16)
  1. (A)90
  2. (B)118
  3. (C)160
  4. (D)125

Correct answer: (B)

Step-by-step solution →
Q40·Chemistry·Electronic Effects and StabilitySingle correct
The following structures are
  1. (A)enantiomers.
  2. (B)identical molecules.
  3. (C)diastereomers.
  4. (D)meso compounds.

Correct answer: (B)

Step-by-step solution →
Q41·Chemistry·Alcohols and EthersSingle correct
The descending order of acidity among the following compounds is: A. Phenol B. 4-nitrophenol C. 4-methoxyphenol D. 4-nitrobenzoic acid E. Benzoic acid Choose the correct answer from the options given below:
  1. (A)B > D > E > A > C
  2. (B)D > B > E > A > C
  3. (C)C > A > B > D > E
  4. (D)D > E > B > A > C

Correct answer: (D)

Step-by-step solution →
Q42·ChemistrySingle correct
The strongest conjugate acid will result from:
  1. (A)aniline
  2. (B)4-methoxyaniline
  3. (C)4-nitroaniline
  4. (D)4-methylaniline (p-toluidine)

Correct answer: (C)

Step-by-step solution →
Q43·ChemistrySingle correct
A D-aldotetrose on oxidation with concentrated HNO3\mathrm{HNO_{3}}HNO3​ resulted in optically inactive dicarboxylic acid. The structure of the D-aldotetrose is:
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (C)

Step-by-step solution →
Q44·ChemistrySingle correct
Among Fe3+\mathrm{Fe^{3+}}Fe3+, Pb2+\mathrm{Pb^{2+}}Pb2+, Cu2+\mathrm{Cu^{2+}}Cu2+ and Mn2+\mathrm{Mn^{2+}}Mn2+, identify the one that gets precipitated out while passing H2S\mathrm{H_{2}S}H2​S in presence of NH4OH\mathrm{NH_{4}OH}NH4​OH as group reagent. The highest possible oxidation state of the corresponding metal is
  1. (A)+3
  2. (B)+4
  3. (C)+2
  4. (D)+7

Correct answer: (D)

Step-by-step solution →
Q45·ChemistrySingle correct
Match the LIST-I (Compound) with LIST-II (Test). Choose the correct answer from the options given below:
List-I (Compound)List-II (Test)
A.CyclohexanolI.Hinsberg's reagent test
B.CyclohexylamineII.Phthalein dye test
C.CyclohexanecarbaldehydeIII.Lucas test
D.PhenolIV.Tollen's test
  1. (A)A-III, B-I, C-IV, D-II
  2. (B)A-III, B-IV, C-I, D-II
  3. (C)A-I, B-III, C-II, D-IV
  4. (D)A-I, B-II, C-III, D-IV

Correct answer: (A)

Step-by-step solution →
Q46·ChemistryNumerical
If 3.365 g of ethanol (l) is burnt completely in a bomb calorimeter at 298.15 K, the heat produced is 99.472 kJ. The ∣ΔHf∘∣|\Delta H_{f}^{\circ}|∣ΔHf∘​∣ of ethanol at 298.15 K is ______ ×102^{2}2 kJ mol−1^{-1}−1. (Nearest integer) Given: Standard enthalpy for combustion of graphite = −393.5 kJ mol−1^{-1}−1 Standard enthalpy of formation of water (l) = −285.8 kJ mol−1^{-1}−1 Molar mass in g mol−1^{-1}−1 of C, H, O are 12, 1 and 16 respectively

Correct answer: 3

Step-by-step solution →
Q47·ChemistryNumerical
For the following reaction at 50 °C and at 2 atm pressure, 2N2O5(g)⇌2N2O4(g)+O2(g)2\mathrm{N_{2}O_{5}}(g) \rightleftharpoons 2\mathrm{N_{2}O_{4}}(g) + \mathrm{O_{2}}(g)2N2​O5​(g)⇌2N2​O4​(g)+O2​(g) N2O5\mathrm{N_{2}O_{5}}N2​O5​ is 50% dissociated. The magnitude of standard free energy change at this temperature is xxx. xxx = ______ J mol−1^{-1}−1 [Nearest integer]. Given: RRR = 8.314 J mol−1^{-1}−1 K−1^{-1}−1, log 2 = 0.30, log 3 = 0.48, ln 10 = 2.303, °C + 273 = K

Correct answer: 2474

Step-by-step solution →
Q48·ChemistryNumerical
An electrochemical cell, consist of the following two redox couples, Mx+(aq)/M(s)M^{x+}(aq)/M(s)Mx+(aq)/M(s) [Ered⊖[E^{\ominus}_{red}[Ered⊖​ = +0.15 V] and Fe3+(aq)/Fe(s)\mathrm{Fe^{3+}}(aq)/\mathrm{Fe}(s)Fe3+(aq)/Fe(s) [Ered⊖[E^{\ominus}_{red}[Ered⊖​ = −0.036 V]. The cell EMF (EcellE_{cell}Ecell​) is recorded to be 0.2057 V. If the reaction quotient of the electrochemical reaction is found to be 10−2^{-2}−2, then the value of xxx is ______. (Nearest integer) [Given: M is a p-block metal and 2.303RTF\frac{2.303RT}{F}F2.303RT​ = 0.059 V]

Correct answer: 2

Step-by-step solution →
Q49·ChemistryNumerical
For a first order reaction A→BA \rightarrow BA→B xxx = ______ min. (Nearest integer)
ttt/min[A][A][A]/M
00.6500
xxx0.0650
200.00065

Correct answer: 7

Step-by-step solution →
Q50·ChemistryNumerical
In sulphur estimation, 2.0 × 10−3^{-3}−3 mol of an organic compound (X) (molar mass 76 g mol−1^{-1}−1) gave 0.4813 g of barium sulphate (molar mass 233 g mol−1^{-1}−1). The percentage of sulphur in the compound (X) is ______ ×10−1^{-1}−1 % (Nearest integer)

Correct answer: 435

Step-by-step solution →

Mathematics — JEE Main 4 April 2026 Shift 2

Q51·MathematicsSingle correct
For the function f:[1,∞)→[1,∞)f : [1, \infty) \to [1, \infty)f:[1,∞)→[1,∞) defined by f(x)=(x−1)4+1f(x) = (x-1)^{4} + 1f(x)=(x−1)4+1, among the two statements: (I) The set S={x∈[1,∞):f(x)=f−1(x)}S = \{x \in [1, \infty) : f(x) = f^{-1}(x)\}S={x∈[1,∞):f(x)=f−1(x)} contains exactly two elements, and (II) The set S={x∈[1,∞):f(x)=f−1(x+1)}S = \{x \in [1, \infty) : f(x) = f^{-1}(x+1)\}S={x∈[1,∞):f(x)=f−1(x+1)} is an empty set,
  1. (A)only (I) is TRUE
  2. (B)only (II) is TRUE
  3. (C)both (I) and (II) are TRUE
  4. (D)neither (I) nor (II) is TRUE

Correct answer: (A)

Step-by-step solution →
Q52·MathematicsSingle correct
Let S={z∈C:z2+4z+16=0}S = \{z \in \mathbb{C} : z^{2} + 4z + 16 = 0\}S={z∈C:z2+4z+16=0}. Then ∑z∈S∣z+3i∣2\sum_{z \in S} |z + \sqrt{3}i|^{2}∑z∈S​∣z+3​i∣2 is equal to:
  1. (A)42
  2. (B)23
  3. (C)27
  4. (D)38

Correct answer: (D)

Step-by-step solution →
Q53·MathematicsSingle correct
If the system of equations: x+y+z=5x + y + z = 5x+y+z=5 x+2y+3z=9x + 2y + 3z = 9x+2y+3z=9 x+3y+λz=μx + 3y + \lambda z = \mux+3y+λz=μ has infinitely many solutions, then the value of λ+μ\lambda + \muλ+μ is:
  1. (A)16
  2. (B)18
  3. (C)19
  4. (D)21

Correct answer: (B)

Step-by-step solution →
Q54·MathematicsSingle correct
If α=1\alpha = 1α=1 and β=1+i2\beta = 1 + i\sqrt{2}β=1+i2​, where i=−1i = \sqrt{-1}i=−1​ are two roots of the equation x3+ax2+bx+c=0x^{3} + ax^{2} + bx + c = 0x3+ax2+bx+c=0, a,b,c∈Ra, b, c \in \mathbb{R}a,b,c∈R, then ∫−11(x3+ax2+bx+c)dx\int_{-1}^{1}(x^{3} + ax^{2} + bx + c)dx∫−11​(x3+ax2+bx+c)dx is equal to:
  1. (A)−2
  2. (B)−4
  3. (C)−8
  4. (D)−10

Correct answer: (C)

Step-by-step solution →
Q55·MathematicsSingle correct
If the quadratic equation (λ+2)x2−3λx+4λ=0(\lambda + 2)x^{2} - 3\lambda x + 4\lambda = 0(λ+2)x2−3λx+4λ=0, λ≠−2\lambda \neq -2λ=−2, has two positive roots, then the number of possible integral values of λ\lambdaλ is:
  1. (A)1
  2. (B)2
  3. (C)3
  4. (D)4

Correct answer: (B)

Step-by-step solution →
Q56·MathematicsSingle correct
Let A=[1274−2838−7]A = \begin{bmatrix} 1 & 2 & 7 \\ 4 & -2 & 8 \\ 3 & 8 & -7 \end{bmatrix}A=​143​2−28​78−7​​ and det⁡(A−αI)=0\det(A - \alpha I) = 0det(A−αI)=0, where α\alphaα is a real number. If the largest possible value of α\alphaα is ppp, then the circle (x−p)2+(y−2p)2=320(x - p)^{2} + (y - 2p)^{2} = 320(x−p)2+(y−2p)2=320, intersects the co-ordinate axes at
  1. (A)1 point
  2. (B)2 points
  3. (C)3 points
  4. (D)4 points

Correct answer: (C)

Step-by-step solution →
Q57·MathematicsSingle correct
Let α=14+18+116+…∞\alpha = \frac{1}{4} + \frac{1}{8} + \frac{1}{16} + \ldots \inftyα=41​+81​+161​+…∞ and β=13+19+127+…∞\beta = \frac{1}{3} + \frac{1}{9} + \frac{1}{27} + \ldots \inftyβ=31​+91​+271​+…∞. Then the value of (0.2)log⁡5(α)+(0.04)log⁡5(β)(0.2)^{\log_{\sqrt{5}}(\alpha)} + (0.04)^{\log_{5}(\beta)}(0.2)log5​​(α)+(0.04)log5​(β) is equal to:
  1. (A)4
  2. (B)5
  3. (C)8
  4. (D)25

Correct answer: (C)

Step-by-step solution →
Q58·MathematicsSingle correct
For 10 observations x1,x2,…,x10x_{1}, x_{2}, \ldots, x_{10}x1​,x2​,…,x10​, if ∑i=110(xi+2)2=180\sum_{i=1}^{10}(x_{i} + 2)^{2} = 180∑i=110​(xi​+2)2=180 and ∑i=110(xi−1)2=90\sum_{i=1}^{10}(x_{i} - 1)^{2} = 90∑i=110​(xi​−1)2=90, then their standard deviation is:
  1. (A)2
  2. (B)3\sqrt{3}3​
  3. (C)222\sqrt{2}22​
  4. (D)3

Correct answer: (D)

Step-by-step solution →
Q59·MathematicsSingle correct
In the expansion of (9x−13x)18\left(9x - \frac{1}{3\sqrt{x}}\right)^{18}(9x−3x​1​)18, x>0x > 0x>0, if the term independent of xxx is (221)k(221)k(221)k, then kkk is equal to:
  1. (A)84
  2. (B)78
  3. (C)168
  4. (D)198

Correct answer: (A)

Step-by-step solution →
Q60·MathematicsSingle correct
Let P(3cos⁡α,2sin⁡α)P(3\cos\alpha, 2\sin\alpha)P(3cosα,2sinα), α≠0\alpha \neq 0α=0, be a point on the ellipse x29+y24=1\frac{x^{2}}{9} + \frac{y^{2}}{4} = 19x2​+4y2​=1, QQQ be a point on the circle x2+y2−14x−14y+82=0x^{2} + y^{2} - 14x - 14y + 82 = 0x2+y2−14x−14y+82=0 and RRR be a point on the line x+y=5x + y = 5x+y=5 such that the centroid of the triangle PQRPQRPQR is (2+cos⁡α,3+23sin⁡α)\left(2 + \cos\alpha, 3 + \frac{2}{3}\sin\alpha\right)(2+cosα,3+32​sinα). Then the sum of the ordinates of all possible points RRR is:
  1. (A)6
  2. (B)2
  3. (C)4
  4. (D)8

Correct answer: (D)

Step-by-step solution →
Q61·MathematicsSingle correct
Let H:x2a2−y2b2=1H : \frac{x^{2}}{a^{2}} - \frac{y^{2}}{b^{2}} = 1H:a2x2​−b2y2​=1 be a hyperbola such that the distance between its foci is 6 and the distance between its directrices is 83\frac{8}{3}38​. If the line x=αx = \alphax=α intersects the hyperbola HHH at the points AAA and BBB such that the area of the triangle AOBAOBAOB is 4154\sqrt{15}415​, where OOO is the origin, then α2\alpha^{2}α2 equals
  1. (A)12
  2. (B)16
  3. (C)24
  4. (D)25

Correct answer: (B)

Step-by-step solution →
Q62·MathematicsSingle correct
max⁡0≤x≤π(16sin⁡(x2)cos⁡3(x2))\max_{0 \leq x \leq \pi}\left(16\sin\left(\frac{x}{2}\right)\cos^{3}\left(\frac{x}{2}\right)\right)max0≤x≤π​(16sin(2x​)cos3(2x​)) is equal to:
  1. (A)332\frac{3\sqrt{3}}{2}233​​
  2. (B)333\sqrt{3}33​
  3. (C)434\sqrt{3}43​
  4. (D)636\sqrt{3}63​

Correct answer: (B)

Step-by-step solution →
Q63·MathematicsSingle correct
The shortest distance between the lines r⃗=(13i^+2j^+83k^)+λ(2i^−5j^+6k^)\vec{r} = \left(\frac{1}{3}\hat{i} + 2\hat{j} + \frac{8}{3}\hat{k}\right) + \lambda(2\hat{i} - 5\hat{j} + 6\hat{k})r=(31​i^+2j^​+38​k^)+λ(2i^−5j^​+6k^) and r⃗=(−23i^−13k^)+μ(j^−k^)\vec{r} = \left(-\frac{2}{3}\hat{i} - \frac{1}{3}\hat{k}\right) + \mu(\hat{j} - \hat{k})r=(−32​i^−31​k^)+μ(j^​−k^), λ,μ∈R\lambda, \mu \in \mathbb{R}λ,μ∈R, is:
  1. (A)5\sqrt{5}5​
  2. (B)3
  3. (C)232\sqrt{3}23​
  4. (D)15\sqrt{15}15​

Correct answer: (B)

Step-by-step solution →
Q64·MathematicsSingle correct
If (2α+1,α2−3α,α−12)\left(2\alpha + 1, \alpha^{2} - 3\alpha, \frac{\alpha - 1}{2}\right)(2α+1,α2−3α,2α−1​) is the image of (α,2α,1)(\alpha, 2\alpha, 1)(α,2α,1) in the line x−23=y−12=z1\frac{x - 2}{3} = \frac{y - 1}{2} = \frac{z}{1}3x−2​=2y−1​=1z​, then the possible value(s) of α is (are)
  1. (A)Only 3
  2. (B)Only 3 and −1
  3. (C)Only 3, 14\frac{1}{4}41​ and −1
  4. (D)Only 3 and 14\frac{1}{4}41​

Correct answer: (A)

Step-by-step solution →
Q65·MathematicsSingle correct
Let u^\hat{u}u^ and v^\hat{v}v^ be unit vectors inclined at an acute angle such that ∣u^×v^∣=32|\hat{u} \times \hat{v}| = \frac{\sqrt{3}}{2}∣u^×v^∣=23​​. If A⃗=λu^+v^+(u^×v^)\vec{A} = \lambda\hat{u} + \hat{v} + (\hat{u} \times \hat{v})A=λu^+v^+(u^×v^), then λ is equal to:
  1. (A)43(A⃗⋅u^)−23(A⃗⋅v^)\frac{4}{3}(\vec{A} \cdot \hat{u}) - \frac{2}{3}(\vec{A} \cdot \hat{v})34​(A⋅u^)−32​(A⋅v^)
  2. (B)23(A⃗⋅u^)−13(A⃗⋅v^)\frac{2}{3}(\vec{A} \cdot \hat{u}) - \frac{1}{3}(\vec{A} \cdot \hat{v})32​(A⋅u^)−31​(A⋅v^)
  3. (C)43(A⃗⋅u^)+23(A⃗⋅v^)\frac{4}{3}(\vec{A} \cdot \hat{u}) + \frac{2}{3}(\vec{A} \cdot \hat{v})34​(A⋅u^)+32​(A⋅v^)
  4. (D)(A⃗⋅u^)−12(A⃗⋅v^)(\vec{A} \cdot \hat{u}) - \frac{1}{2}(\vec{A} \cdot \hat{v})(A⋅u^)−21​(A⋅v^)

Correct answer: (A)

Step-by-step solution →
Q66·MathematicsSingle correct
Let for some α ∈ R\mathbb{R}R, f:R→Rf : \mathbb{R} \to \mathbb{R}f:R→R be a function satisfying f(x+y)=f(x)+2y2+y+αxyf(x + y) = f(x) + 2y^{2} + y + \alpha xyf(x+y)=f(x)+2y2+y+αxy for all x,y∈Rx, y \in \mathbb{R}x,y∈R. If f(0)=−1f(0) = -1f(0)=−1 and f(1)=2f(1) = 2f(1)=2, then the value of ∑n=15(α+f(n))\sum_{n=1}^{5}(\alpha + f(n))∑n=15​(α+f(n)) is:
  1. (A)110
  2. (B)140
  3. (C)150
  4. (D)170

Correct answer: (B)

Step-by-step solution →
Q67·MathematicsSingle correct
Let A={(a,b,c):a,b,c are non-negative integers and a+b+2c=22}A = \{(a, b, c) : a, b, c \text{ are non-negative integers and } a + b + 2c = 22\}A={(a,b,c):a,b,c are non-negative integers and a+b+2c=22}. Then n(A)n(A)n(A) is equal to:
  1. (A)121
  2. (B)124
  3. (C)144
  4. (D)169

Correct answer: (C)

Step-by-step solution →
Q68·MathematicsSingle correct
The area of the region bounded by the curves x+3y2=0x + 3y^{2} = 0x+3y2=0 and x+4y2=1x + 4y^{2} = 1x+4y2=1 is equal to:
  1. (A)13\frac{1}{3}31​
  2. (B)23\frac{2}{3}32​
  3. (C)43\frac{4}{3}34​
  4. (D)53\frac{5}{3}35​

Correct answer: (C)

Step-by-step solution →
Q69·MathematicsSingle correct
Let y=y(x)y = y(x)y=y(x) be the solution of the differential equation: dydx+(6x2+(3x2+2x3+4)e−2x(x3+2)(2+e−2x))y=2+e−2x\frac{dy}{dx} + \left(\frac{6x^{2} + (3x^{2} + 2x^{3} + 4)e^{-2x}}{(x^{3} + 2)(2 + e^{-2x})}\right)y = 2 + e^{-2x}dxdy​+((x3+2)(2+e−2x)6x2+(3x2+2x3+4)e−2x​)y=2+e−2x, x∈(−1,2)x \in (-1, 2)x∈(−1,2), satisfying y(0)=32y(0) = \frac{3}{2}y(0)=23​. If y(1)=α(2+e−2)y(1) = \alpha(2 + e^{-2})y(1)=α(2+e−2), then α is equal to:
  1. (A)138\frac{13}{8}813​
  2. (B)613\frac{6}{13}136​
  3. (C)1213\frac{12}{13}1312​
  4. (D)1312\frac{13}{12}1213​

Correct answer: (D)

Step-by-step solution →
Q70·MathematicsSingle correct
The integral ∫01cot⁡−1(1+x+x2)dx\int_{0}^{1}\cot^{-1}(1 + x + x^{2})dx∫01​cot−1(1+x+x2)dx is equal to:
  1. (A)2tan⁡−12+12log⁡e(54)+π22\tan^{-1}2 + \frac{1}{2}\log_{e}\left(\frac{5}{4}\right) + \frac{\pi}{2}2tan−12+21​loge​(45​)+2π​
  2. (B)2tan⁡−12+12log⁡e(54)−π22\tan^{-1}2 + \frac{1}{2}\log_{e}\left(\frac{5}{4}\right) - \frac{\pi}{2}2tan−12+21​loge​(45​)−2π​
  3. (C)2tan⁡−12−12log⁡e(54)+π22\tan^{-1}2 - \frac{1}{2}\log_{e}\left(\frac{5}{4}\right) + \frac{\pi}{2}2tan−12−21​loge​(45​)+2π​
  4. (D)2tan⁡−12−12log⁡e(54)−π22\tan^{-1}2 - \frac{1}{2}\log_{e}\left(\frac{5}{4}\right) - \frac{\pi}{2}2tan−12−21​loge​(45​)−2π​

Correct answer: (D)

Step-by-step solution →
Q71·MathematicsNumerical
From a month of 31 days, 3 different dates are selected at random. If the probability that these dates are in an increasing A.P. is equal to ab\frac{a}{b}ba​, where a,b∈Na, b \in \mathbb{N}a,b∈N and gcd⁡(a,b)=1\gcd(a, b) = 1gcd(a,b)=1, then a+ba + ba+b is equal to ______

Correct answer: 944

Step-by-step solution →
Q72·Mathematics·DifferentiabilityNumerical
Let f(x)={ex−1,x<0x2−5x+6,x≥0f(x) = \begin{cases} e^{x-1}, & x < 0 \\ x^{2} - 5x + 6, & x \geq 0 \end{cases}f(x)={ex−1,x2−5x+6,​x<0x≥0​ and g(x)=f(∣x∣)+∣f(x)∣g(x) = f(|x|) + |f(x)|g(x)=f(∣x∣)+∣f(x)∣. If the number of points where ggg is not continuous and is not differentiable are α and β respectively, then α+β\alpha + \betaα+β is equal to ______

Correct answer: 4

Step-by-step solution →
Q73·MathematicsNumerical
Let A,BA, BA,B be points on the two half-lines x−3∣y∣=αx - \sqrt{3}|y| = \alphax−3​∣y∣=α, α>0\alpha > 0α>0 at a distance of α from their point of intersection PPP. The line segment ABABAB meets the angle bisector of the given half-lines at the point QQQ. If PQ=92PQ = \frac{9}{2}PQ=29​ and RRR is the radius of the circumcircle of △PAB\triangle PAB△PAB, then α2R\frac{\alpha^{2}}{R}Rα2​ is equal to ______

Correct answer: 9

Step-by-step solution →
Q74·MathematicsNumerical
Let A,BA, BA,B and CCC be the vertices of a variable right angled triangle inscribed in the parabola y2=16xy^{2} = 16xy2=16x. Let the vertex BBB containing the right angle be (4,8)(4, 8)(4,8) and the locus of the centroid of △ABC\triangle ABC△ABC be a conic CoC_{o}Co​. Then three times the length of latus rectum of CoC_{o}Co​ is ______

Correct answer: 16

Step-by-step solution →
Q75·MathematicsNumerical
Let fff be a twice differentiable function such that f(x)=∫0xtan⁡(t−x)dt−∫0xf(t)tan⁡t dtf(x) = \int_{0}^{x}\tan(t - x)dt - \int_{0}^{x}f(t)\tan t\,dtf(x)=∫0x​tan(t−x)dt−∫0x​f(t)tantdt, x∈(−π2,π2)x \in \left(-\frac{\pi}{2}, \frac{\pi}{2}\right)x∈(−2π​,2π​). Then f′′(π6)+12f′(−π6)+f(π6)f''\left(\frac{\pi}{6}\right) + 12f'\left(-\frac{\pi}{6}\right) + f\left(\frac{\pi}{6}\right)f′′(6π​)+12f′(−6π​)+f(6π​) is equal to ______

Correct answer: 5

Step-by-step solution →

Chapters tested in this paper

Open any chapter to practise every past-year question on that topic across all papers, and see how often it has actually appeared.

  • Properties of Solids and Liquids 172/186
  • Three Dimensional Geometry 176/186
  • Matrices and Determinants 180/186
  • Coordination Compounds 176/186
  • Sets, Relations and Functions 165/186
  • Sequence and Series 164/186
  • p-Block Elements 164/186
  • Definite Integration 168/186
  • Redox Reactions and Electrochemistry 177/186
  • Geometrical Optics 172/186
  • Kinematics 156/186
  • Vector Algebra 173/186
  • Differential Equations 167/186
  • Probability 176/186
  • Permutations and Combinations 162/186
  • Magnetic Field of Current 147/186
  • Binomial Theorem and Its Simple Applications 158/186
  • Electromagnetic Waves 144/186
  • Chemical Bonding and Molecular Structure 151/186
  • Application of Derivatives 139/186
  • d- and f-Block Elements 126/186
  • Equilibrium 163/186
  • Solutions 158/186
  • Laws of Motion 130/186
  • Chemical Thermodynamics 165/186
  • Units and Measurements 149/186
  • Hydrocarbons 126/186
  • Complex Numbers 165/186
  • Biomolecules 162/186
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  • Gravitation 152/186
  • Electric Field and Coulomb's Law 133/186
  • Atomic Structure 161/186
  • Electronic Devices 145/186
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  • Dual Nature of Matter and Radiation 155/186
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  • Quadratic Equations 148/186
  • Some Basic Concepts in Chemistry 129/186
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  • Area Under Curves 139/186
  • Kinetic Theory of Gases 135/186
  • Alcohols and Ethers 106/186
  • Purification and Characterisation of Organic Compounds 116/186
  • Oscillations 117/186
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  • Atoms 112/186
  • Classification of Elements and Periodicity in Properties 113/186
  • Parabola 101/186
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  • Principles of Qualitative Analysis 58/186
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