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JEE Main 4 April 2026 Shift 1 Question Paper with Answers

4 April 2026 · April session · 74 questions

74 of the 75 questions from the JEE Main 4 April 2026 Shift 1 paper, each with its correct answer and tagged to the chapter it tests. Free to read, no account needed.

1 question is held back from this paper while we re-check the transcription or the answer key. We would rather show you nothing than show you an answer we are not confident is right.

Physics
25
Chemistry
24
Mathematics
25

Physics — JEE Main 4 April 2026 Shift 1

Q1·PhysicsSingle correct
In a screw gauge when the circular scale is given five complete rotations it moves linearly by 2.5 mm. If the circular scale has 100 divisions, the least count of screw gauge is _____ mm.
  1. (A)1×10−21 \times 10^{-2}1×10−2
  2. (B)1×10−31 \times 10^{-3}1×10−3
  3. (C)5×10−25 \times 10^{-2}5×10−2
  4. (D)5×10−35 \times 10^{-3}5×10−3

Correct answer: (D)

Step-by-step solution →
Q2·PhysicsSingle correct
The increase in the pressure required to decrease the volume (ΔV)(\Delta V)(ΔV) of water is 6.3×1076.3 \times 10^{7}6.3×107 N/m2^22. The percentage decrease in the volume is _____. (Bulk modulus of water =2.1×109= 2.1 \times 10^{9}=2.1×109 N/m2^22.)
  1. (A)2%2\%2%
  2. (B)3%3\%3%
  3. (C)6%6\%6%
  4. (D)4%4\%4%

Correct answer: (B)

Step-by-step solution →
Q3·PhysicsSingle correct
The time taken by a block of mass mmm to slide down from the highest point to the lowest point on a rough inclined plane is 50% more compared to the time taken by the same block on identical inclined smooth plane. Both inclined planes are at 45∘45^\circ45∘ with the horizontal. The coefficient of kinetic friction between the rough inclined surface and block is _____.
  1. (A)3/43/43/4
  2. (B)2/32/32/3
  3. (C)5/95/95/9
  4. (D)4/94/94/9

Correct answer: (C)

Step-by-step solution →
Q4·PhysicsSingle correct
Two nuclei of mass number 3 combine with another nucleus of mass number 4 to yield a nucleus of mass number 10 . If the binding energy per nucleon for the mass numbers 3, 4 and 10 are 5.6 MeV, 7.4 MeV and 6.1 MeV, respectively, then in the process, ΔMc2=\Delta Mc^2 =ΔMc2= _____ MeV.
  1. (A)6.9
  2. (B)7.9
  3. (C)2.2
  4. (D)4.3

Correct answer: (C)

Step-by-step solution →
Q5·PhysicsSingle correct
A solid sphere of mass MMM and radius RRR is divided into two unequal parts. The smaller part having mass M/8M/8M/8 is converted into a sphere of radius rrr and the larger part is converted into a circular disc of thickness ttt and radius 2R2R2R. If I1I_1I1​ is moment of inertia of a sphere having radius rrr about an axis through its centre and I2I_2I2​ is the moment of inertia of a disc about its diameter, the ratio of their moment of inertia I2/I1=I_2/I_1 =I2​/I1​= _____.
  1. (A)35
  2. (B)70
  3. (C)140
  4. (D)210

Correct answer: (B)

Step-by-step solution →
Q6·PhysicsSingle correct
Two projectiles are projected with the same initial velocities at the 15∘15^\circ15∘ and 30∘30^\circ30∘ with respect to the horizontal. The ratio of their ranges is 1:x1 : x1:x. The value of xxx is:
  1. (A)2\sqrt{2}2​
  2. (B)3\sqrt{3}3​
  3. (C)232\sqrt{3}23​
  4. (D)12\frac{1}{\sqrt{2}}2​1​

Correct answer: (B)

Step-by-step solution →
Q7·PhysicsSingle correct
The graph shows variation of stopping potential VoV_oVo​ with the frequency ν\nuν of the incident radiation for three photosensitive metals X1X_1X1​, X2X_2X2​ and X3X_3X3​. Which metal will give out electrons with greater kinetic energy, for the same wavelength of incident radiation?
  1. (A)X1X_1X1​
  2. (B)X2X_2X2​
  3. (C)X3X_3X3​
  4. (D)All the metals will give out photo electrons with same kinetic energies.

Correct answer: (A)

Step-by-step solution →
Q8·PhysicsSingle correct
A slit of width aaa is illuminated by light of wavelength λ\lambdaλ. The linear separation between 1st1^{st}1st and 3rd3^{rd}3rd minima in the diffraction pattern produced on a screen placed at a distance DDD from the slit system is _____.
  1. (A)Dλa\frac{D\lambda}{a}aDλ​
  2. (B)1.5Dλa1.5\frac{D\lambda}{a}1.5aDλ​
  3. (C)2Dλa2\frac{D\lambda}{a}2aDλ​
  4. (D)3Dλa3\frac{D\lambda}{a}3aDλ​

Correct answer: (C)

Step-by-step solution →
Q9·PhysicsSingle correct
A string AAA of length 0.314 m and Young's modulus 2×10102 \times 10^{10}2×1010 N/m2^22 is connected to another string BBB of length and Young's modulus both twice of those of AAA. This series combination of strings is then suspended from a rigid support and its free end is fixed to a load of mass 0.8 kg. The net change in length of the combination is _____ mm. (radius of both the strings is 0.2 mm and acceleration due to gravity =10= 10=10 m/s2^22) (Mass of both strings is to be neglected as compared to the mass of load)
  1. (A)3
  2. (B)2
  3. (C)1.9
  4. (D)1

Correct answer: (B)

Step-by-step solution →
Q10·PhysicsSingle correct
One gas of n1n_1n1​ mole of molecules at temperature T1T_1T1​, volume V1V_1V1​, and pressure P1P_1P1​, and another gas of n2n_2n2​ mole of molecules at temperature T2T_2T2​, volume V2V_2V2​, and pressure P2P_2P2​, are mixed resulting in pressure PPP and volume VVV of the mixture. The temperature of the mixture is _____.
  1. (A)(T1+T2)/2(T_1 + T_2)/2(T1​+T2​)/2
  2. (B)T1T2PV/(T2P1V1+T1P2V2)T_1T_2PV/(T_2P_1V_1 + T_1P_2V_2)T1​T2​PV/(T2​P1​V1​+T1​P2​V2​)
  3. (C)(T2P1V1+T1P2V2)/(T1T2PV)(T_2P_1V_1 + T_1P_2V_2)/(T_1T_2PV)(T2​P1​V1​+T1​P2​V2​)/(T1​T2​PV)
  4. (D)∣T1−T2∣/2|T_1 - T_2|/2∣T1​−T2​∣/2

Correct answer: (B)

Step-by-step solution →
Q11·PhysicsSingle correct
An ideal gas undergoes a process maintaining relation between pressure (P)(P)(P) and volume (V)(V)(V) as P=Po(1+(VoV)2)−1P = P_o\left(1 + \left(\frac{V_o}{V}\right)^2\right)^{-1}P=Po​(1+(VVo​​)2)−1 , where PoP_oPo​ and VoV_oVo​ are constants. If two samples AAA and BBB (two moles each) with initial volumes VoV_oVo​ and 3Vo3V_o3Vo​ respectively undergo above mentioned process and attain same pressure, then the difference at the temperatures of these samples, TB−TAT_B - T_ATB​−TA​ is _____. (R=R =R= gas constant)
  1. (A)9PoVo8R\frac{9P_oV_o}{8R}8R9Po​Vo​​
  2. (B)11PoVo10R\frac{11P_oV_o}{10R}10R11Po​Vo​​
  3. (C)7PoVo6R\frac{7P_oV_o}{6R}6R7Po​Vo​​
  4. (D)13PoVo11R\frac{13P_oV_o}{11R}11R13Po​Vo​​

Correct answer: (B)

Step-by-step solution →
Q12·PhysicsSingle correct
A voltmeter with internal resistance of xxx Ω\OmegaΩ can be used to measure upto 20 V. In order to increase its measuring range to 30 V, the required modification is to _____.
  1. (A)connect resistor of x2\frac{x}{2}2x​ Ω\OmegaΩ, in series with voltmeter.
  2. (B)connect resistor of x2\frac{x}{2}2x​ Ω\OmegaΩ, in parallel to voltmeter.
  3. (C)connect a resistor of xxx Ω\OmegaΩ in series with voltmeter.
  4. (D)connect resistor of 2x2x2x Ω\OmegaΩ in parallel to voltmeter.

Correct answer: (A)

Step-by-step solution →
Q13·PhysicsSingle correct
Two 4 bits binary numbers, A=1101A = 1101A=1101 and B=1010B = 1010B=1010 are given in the inputs of a logic circuit shown in figure below. The output (Y)(Y)(Y) will be:
  1. (A)Y=1101Y = 1101Y=1101
  2. (B)Y=0010Y = 0010Y=0010
  3. (C)Y=0111Y = 0111Y=0111
  4. (D)Y=1000Y = 1000Y=1000

Correct answer: (A)

Step-by-step solution →
Q14·PhysicsSingle correct
A rod of length 10 cm lies along the principle axis of a concave mirror of focal length 10 cm as shown in figure. The length of the image is ______ cm.
  1. (A)2.5
  2. (B)5
  3. (C)7.5
  4. (D)7

Correct answer: (B)

Step-by-step solution →
Q15·PhysicsSingle correct
A parallel plate air capacitor is connected to a battery. The plates are pulled apart at uniform speed vvv. If xxx is the separation between the plates at any instant, then the time rate of change of electrostatic energy of the capacitor is proportional to xαx^{\alpha}xα, where α\alphaα is ______.
  1. (A)−2-2−2
  2. (B)111
  3. (C)−1-1−1
  4. (D)222

Correct answer: (A)

Step-by-step solution →
Q16·PhysicsSingle correct
An insulated wire is wound so that it forms a flat coil with N=200N = 200N=200 turns. The radius of the innermost turn is r1=3r_1 = 3r1​=3 cm, and of the outermost turn r2=6r_2 = 6r2​=6 cm. If 20 mA current flows in it then the magnetic moment will be α×10−2\alpha \times 10^{-2}α×10−2 A.m2^22. The value of α\alphaα is ______.
  1. (A)4.4
  2. (B)2.64
  3. (C)3.25
  4. (D)1.2

Correct answer: (B)

Step-by-step solution →
Q17·PhysicsSingle correct
Consider a circuit consisting of a capacitor (20 μ20\ \mu20 μF), resistor (100 Ω100\ \Omega100 Ω) and two identical diodes as shown in figure. The resistance of diode under forward biasing condition is 10 Ω10\ \Omega10 Ω. The time constant of the circuit is α×10−3\alpha \times 10^{-3}α×10−3 s. The value of α\alphaα is ______
  1. (A)2.2
  2. (B)2.0
  3. (C)2.1
  4. (D)2.4

Correct answer: (A)

Step-by-step solution →
Q18·PhysicsSingle correct
The voltage and the current between AAA and BBB points shown in the circuit are ______.
  1. (A)24 V, 12 A
  2. (B)24 V, 4 A
  3. (C)18 V, 12 A
  4. (D)27 V, 4 A

Correct answer: (B)

Step-by-step solution →
Q19·PhysicsSingle correct
A telescope with objective diameter RRR is used to observe a distant star emitting light of wavelength 500 nm, at a resolution of 5×10−75 \times 10^{-7}5×10−7 radian. The value of RRR is ______ cm.
  1. (A)61
  2. (B)122
  3. (C)244
  4. (D)305

Correct answer: (B)

Step-by-step solution →
Q20·PhysicsSingle correct
An unpolarized light is incident on the plane interface of air-dielectric medium shown in figure. If the incident angle is equal to Brewster angle, identify the expression representing reflected wave.
  1. (A)(Exi^+Eyj^)sin⁡(kx−kz−ωt)(E_x\hat{i} + E_y\hat{j}) \sin(kx - kz - \omega t)(Ex​i^+Ey​j^​)sin(kx−kz−ωt)
  2. (B)(Exi^+Ezk^)sin⁡(kx+ky−ωt)(E_x\hat{i} + E_z\hat{k}) \sin(kx + ky - \omega t)(Ex​i^+Ez​k^)sin(kx+ky−ωt)
  3. (C)(Exj^+Eyk^)sin⁡(ky+kz−ωt)(E_x\hat{j} + E_y\hat{k}) \sin(ky + kz - \omega t)(Ex​j^​+Ey​k^)sin(ky+kz−ωt)
  4. (D)(Exi^+Eyj^+Ezk^)sin⁡(kx+ky−kz−ωt)(E_x\hat{i} + E_y\hat{j} + E_z\hat{k}) \sin(kx + ky - kz - \omega t)(Ex​i^+Ey​j^​+Ez​k^)sin(kx+ky−kz−ωt)

Correct answer: (A)

Step-by-step solution →
Q21·PhysicsNumerical
A 1 kg block subjected to two simultaneous forces (2i^+3j^+4k^)(2\hat{i} + 3\hat{j} + 4\hat{k})(2i^+3j^​+4k^) N and (3i^−j^−2k^)(3\hat{i} - \hat{j} - 2\hat{k})(3i^−j^​−2k^) N is moved a distance of 25 m along (3i^−4j^)(3\hat{i} - 4\hat{j})(3i^−4j^​) direction. The work done in this process is ______ J.

Correct answer: 35

Step-by-step solution →
Q22·PhysicsNumerical
The surface tension of a soap solution is 3.5×10−23.5 \times 10^{-2}3.5×10−2 N/m. The work required to increase the radius of a soap bubble from 1 cm to 2 cm is α×10−6\alpha \times 10^{-6}α×10−6 J. The value of α\alphaα is ______. (π=22/7)(\pi = 22/7)(π=22/7)

Correct answer: 264

Step-by-step solution →
Q23·PhysicsNumerical
The velocity of a particle executing simple harmonic motion along xxx-axis is described as v2=50−x2v^2 = 50 - x^2v2=50−x2, where xxx represents displacement. If the time period of motion is x7\frac{x}{7}7x​ s, the value of xxx is ______.

Correct answer: 44

Step-by-step solution →
Q24·PhysicsNumerical
A body of mass 2 kg begins to move under the influence of time dependent force F⃗=(2ti^+6t2j^)\vec{F} = (2t\hat{i} + 6t^2\hat{j})F=(2ti^+6t2j^​) N, where i^\hat{i}i^ and j^\hat{j}j^​ are unit vectors along xxx and yyy-axis respectively. The power produced by the force at t=2t = 2t=2 s is ______ W.

Correct answer: 200

Step-by-step solution →
Q25·PhysicsNumerical
An inductor of 10 mH, capacitor of 0.1 μ0.1\ \mu0.1 μF and a resistor of 100 Ω100\ \Omega100 Ω are connected in series across an a.ca.ca.c power supply 220 V, 70 Hz. The power factor of the given circuit is 0.5. The difference in the inductive reactance and capacitance reactance is 3α Ω\sqrt{3}\alpha\ \Omega3​α Ω. The value of α\alphaα is ______.

Correct answer: 100

Step-by-step solution →

Chemistry — JEE Main 4 April 2026 Shift 1

Q26·ChemistrySingle correct
Number of moles and number of molecules in 1.41871.41871.4187 L of SO2SO_2SO2​ at STP respectively are:
  1. (A)0.1266;3.812×10220.1266; 3.812 \times 10^{22}0.1266;3.812×1022
  2. (B)0.0633;3.812×10220.0633; 3.812 \times 10^{22}0.0633;3.812×1022
  3. (C)0.1266;7.6238×10220.1266; 7.6238 \times 10^{22}0.1266;7.6238×1022
  4. (D)0.0633;7.6238×10220.0633; 7.6238 \times 10^{22}0.0633;7.6238×1022

Correct answer: (B)

Step-by-step solution →
Q27·ChemistrySingle correct
What is the ratio of wave number of first line (lowest energy line) of Balmer series of H atomic spectrum to first line of its Brackett series?
  1. (A)5:15 : 15:1
  2. (B)5:0.815 : 0.815:0.81
  3. (C)5:1.755 : 1.755:1.75
  4. (D)5:275 : 275:27

Correct answer: (B)

Step-by-step solution →
Q28·ChemistrySingle correct
Which of the following is correct set of 4 quantum numbers of 19th19^{th}19th electron in Chromium (Atomic number =24= 24=24) in accordance with Aufbau principle?
  1. (A)n=3,l=2,m=+2,s=+12n = 3, l = 2, m = +2, s = +\frac{1}{2}n=3,l=2,m=+2,s=+21​
  2. (B)n=3,l=2,m=−2,s=+12n = 3, l = 2, m = -2, s = +\frac{1}{2}n=3,l=2,m=−2,s=+21​
  3. (C)n=4,l=1,m=0,s=+12n = 4, l = 1, m = 0, s = +\frac{1}{2}n=4,l=1,m=0,s=+21​
  4. (D)n=4,l=0,m=0,s=+12n = 4, l = 0, m = 0, s = +\frac{1}{2}n=4,l=0,m=0,s=+21​

Correct answer: (D)

Step-by-step solution →
Q29·ChemistrySingle correct
Given below are two statements: Statement I: For an ideal gas, heat capacity at constant volume is always greater than the heat capacity at constant pressure. Statement II: In a constant volume process, no work is produced and all the heat withdrawn goes into the chaotic motion and is reflected by a temperature increase of the ideal gas. In the light of the above statements, choose the correct answer from the options given below
  1. (A)Both Statement I and Statement II are true
  2. (B)Both Statement I and Statement II are false
  3. (C)Statement I is true but Statement II is false
  4. (D)Statement I is false but Statement II is true

Correct answer: (D)

Step-by-step solution →
Q30·ChemistrySingle correct
At T(K)T(K)T(K), the equilibrium constant of A2(g)+B2(g)⇌C(g)A_2(g) + B_2(g) \rightleftharpoons C(g)A2​(g)+B2​(g)⇌C(g) is 2.7×10−52.7 \times 10^{-5}2.7×10−5. What is the equilibrium constant for 13A2(g)+13B2(g)⇌13C(g)\frac{1}{3}A_2(g) + \frac{1}{3}B_2(g) \rightleftharpoons \frac{1}{3}C(g)31​A2​(g)+31​B2​(g)⇌31​C(g) at the same temperature?
  1. (A)(2.7×10−5)3(2.7 \times 10^{-5})^3(2.7×10−5)3
  2. (B)6×10−26 \times 10^{-2}6×10−2
  3. (C)2.7×10−5\sqrt{2.7 \times 10^{-5}}2.7×10−5​
  4. (D)3×10−23 \times 10^{-2}3×10−2

Correct answer: (D)

Step-by-step solution →
Q31·ChemistrySingle correct
In order to oxidise a mixture of 1 mole each of FeC2O4FeC_2O_4FeC2​O4​, Fe2(C2O4)3Fe_2(C_2O_4)_3Fe2​(C2​O4​)3​, FeSO4FeSO_4FeSO4​ and Fe2(SO4)3Fe_2(SO_4)_3Fe2​(SO4​)3​ in acidic medium, the number of moles of KMnO4KMnO_4KMnO4​ required is
  1. (A)3
  2. (B)2
  3. (C)5
  4. (D)7

Correct answer: (B)

Step-by-step solution →
Q32·ChemistrySingle correct
Consider the first order reaction R→PR \rightarrow PR→P. The fraction of molecules decomposed in the given first order reaction can be expressed as
  1. (A)1−ek1t1 - e^{k_1 t}1−ek1​t
  2. (B)1+ek1t1 + e^{k_1 t}1+ek1​t
  3. (C)1+e−k1t1 + e^{-k_1 t}1+e−k1​t
  4. (D)1−e−k1t1 - e^{-k_1 t}1−e−k1​t

Correct answer: (D)

Step-by-step solution →
Q33·ChemistrySingle correct
A monoatomic anion (A−)(A^-)(A−) has 45 neutrons and 36 electrons. Atomic mass, group in the periodic table and physical state at room temperature of the element (A)(A)(A) respectively are
  1. (A)80,1780, 1780,17, liquid
  2. (B)81,1681, 1681,16, solid
  3. (C)80,1680, 1680,16, gas
  4. (D)81,1581, 1581,15, gas

Correct answer: (A)

Step-by-step solution →
Q34·ChemistrySingle correct
Given below are two statements: Statement I: The covalency of oxygen is generally two but it can exceed upto four. The oxidation state of oxygen in SO2SO_2SO2​ is −2-2−2 and in OF2OF_2OF2​ it is +2+2+2. Statement II: The anomalous behaviour of oxygen when compared to the other elements of group 16 is due to its small size and high electronegativity. In the light of the above statements, choose the correct answer from the options given below
  1. (A)Both Statement I and Statement II are true
  2. (B)Both Statement I and Statement II are false
  3. (C)Statement I is true but Statement II is false
  4. (D)Statement I is false but Statement II is true

Correct answer: (A)

Step-by-step solution →
Q35·ChemistrySingle correct
The correct statements among the following are, A. Mo(VI)Mo(VI)Mo(VI) and W(VI)W(VI)W(VI) are less stable than Cr(VI)Cr(VI)Cr(VI). B. Ce4+Ce^{4+}Ce4+ and Tb4+Tb^{4+}Tb4+ are oxidant while Eu2+Eu^{2+}Eu2+ and Yb2+Yb^{2+}Yb2+ are reductant. C. CmCmCm and AmAmAm have seven unpaired electrons. D. Actinoid contraction is greater from element to element than lanthanoid contraction. Choose the correct answer from the options given below:
  1. (A)A and B Only
  2. (B)C and D Only
  3. (C)B and D Only
  4. (D)A and C Only

Correct answer: (C)

Step-by-step solution →
Q36·ChemistrySingle correct
Correct statements from the following are A. Potassium dichromate is an oxidising agent and it oxidises FeSO4FeSO_4FeSO4​ to Fe2(SO4)3Fe_2(SO_4)_3Fe2​(SO4​)3​ in acidic medium. B. Sodium dichromate can be used as primary standard in volumetric estimation. C. CrO42−CrO_4^{2-}CrO42−​ and Cr2O72−Cr_2O_7^{2-}Cr2​O72−​ are interconvertible in aqueous solution by varying the pHpHpH of the solution. D. Cr-O-CrCr\text{-}O\text{-}CrCr-O-Cr bond angle in Cr2O72−Cr_2O_7^{2-}Cr2​O72−​ is 126∘126^{\circ}126∘. Choose the correct answer from the options given below:
  1. (A)A, B and C Only
  2. (B)A, C and D Only
  3. (C)A and C Only
  4. (D)B and D Only

Correct answer: (B)

Step-by-step solution →
Q37·ChemistrySingle correct
Match List-I (Complex ion) with List-II (Calculated spin only magnetic moment (BM)). Choose the correct answer from the options given below:
List-I (Complex ion)List-II (Calculated spin only magnetic moment (BM))
A.[Cr(H2O)6]2+[Cr(H_2O)_6]^{2+}[Cr(H2​O)6​]2+I.3.873.873.87
B.[Co(H2O)6]2+[Co(H_2O)_6]^{2+}[Co(H2​O)6​]2+II.5.925.925.92
C.[Cu(H2O)6]2+[Cu(H_2O)_6]^{2+}[Cu(H2​O)6​]2+III.4.904.904.90
D.[Mn(H2O)6]2+[Mn(H_2O)_6]^{2+}[Mn(H2​O)6​]2+IV.1.731.731.73
  1. (A)A-I, B-III, C-IV, D-II
  2. (B)A-II, B-I, C-III, D-IV
  3. (C)A-IV, B-II, C-I, D-III
  4. (D)A-III, B-I, C-IV, D-II

Correct answer: (D)

Step-by-step solution →
Q38·Chemistry·Electronic Effects and StabilitySingle correct
Increasing order of electron withdrawing power of following functional groups is: a. −CN-CN−CN b. −COOH-COOH−COOH c. −NO2-NO_2−NO2​ d. −I-I−I
  1. (A)c<b<d<ac < b < d < ac<b<d<a
  2. (B)c<a<b<dc < a < b < dc<a<b<d
  3. (C)d<b<a<cd < b < a < cd<b<a<c
  4. (D)a<b<c<da < b < c < da<b<c<d

Correct answer: (C)

Step-by-step solution →
Q39·ChemistrySingle correct
Match List-I (Name of reaction) with List-II (Reagent or catalyst used). Choose the correct answer from the options given below:
List-I (Name of reaction)List-II (Reagent or catalyst used)
A.Finkelstein reactionI.SbF3SbF_3SbF3​
B.Swarts reactionII.NaNaNa, dry ether
C.Sandmeyer's reactionIII.NaINaINaI
D.Fittig reactionIV.Cu2Cl2Cu_2Cl_2Cu2​Cl2​
  1. (A)A-I, B-IV, C-III, D-II
  2. (B)A-III, B-I, C-IV, D-II
  3. (C)A-IV, B-II, C-I, D-III
  4. (D)A-I, B-III, C-II, D-IV

Correct answer: (B)

Step-by-step solution →
Q40·ChemistrySingle correct
Amongst the following, the total number of compounds soluble in aqueous NaOHNaOHNaOH at room temperature is:
  1. (A)5
  2. (B)4
  3. (C)6
  4. (D)3

Correct answer: (A)

Step-by-step solution →
Q41·ChemistrySingle correct
Product CCC of the following reaction sequence will be
  1. (A)1-Bromo-4-nitrobenzene
  2. (B)1, 3, 5-Tribromo-2-nitrobenzene
  3. (C)4-Bromo-1-nitrobenzene
  4. (D)1, 3, 5-Tribromobenzene

Correct answer: (B)

Step-by-step solution →
Q42·ChemistrySingle correct
Given below are two statements: Statement I: The structure of Maltose is given below: Maltose is a non-reducing sugar. Statement II: The structure of Lactose is given below: Lactose is a reducing sugar. In the light of the above statements, choose the correct answer from the options given below
  1. (A)Both Statement I and Statement II are true
  2. (B)Both Statement I and Statement II are false
  3. (C)Statement I is true but Statement II is false
  4. (D)Statement I is false but Statement II is true

Correct answer: (D)

Step-by-step solution →
Q43·ChemistrySingle correct
Match List-I (Name of amino acid) with List-II (One letter symbol/type). Choose the correct answer from the options given below:
List-I (Name of amino acid)List-II (One letter symbol/type)
A.ArginineI.D/Non-essential
B.Aspartic acidII.R/Essential
C.LysineIII.E/Non-essential
D.Glutamic acidIV.K/Essential
  1. (A)A-II, B-I, C-IV, D-III
  2. (B)A-IV, B-III, C-II, D-I
  3. (C)A-III, B-IV, C-I, D-II
  4. (D)A-II, B-IV, C-I, D-III

Correct answer: (A)

Step-by-step solution →
Q44·ChemistrySingle correct
Identify the colour of compound ′X′'X'′X′ in the sequence of the reaction.
  1. (A)Violet
  2. (B)Green
  3. (C)Red
  4. (D)Colourless

Correct answer: (D)

Step-by-step solution →
Q45·ChemistryNumerical
According to Lewis theory, the total number of σ\sigmaσ bond-pairs and lone pair of electrons around the central atom of XeO64−XeO_6^{4-}XeO64−​ ion is _______.

Correct answer: 6

Step-by-step solution →
Q46·ChemistryNumerical
Consider the following sequence of reactions to give the major product (X)(X)(X) PPP g of the major product (X)(X)(X) formed is reacted with NaHCO3NaHCO_3NaHCO3​ solution to liberate a gas which occupied 11.2 dm3dm^3dm3 at STP. P=P =P= _______ g. (Given molar mass in g mol−1mol^{-1}mol−1 H:1, C:12, O:16, Cl:35.5)

Correct answer: 78.25

Step-by-step solution →
Q47·ChemistryNumerical
2.0 g of a bromo hydrocarbon (X)(X)(X) was subjected to Carius analysis, gave 3.36 g of AgBrAgBrAgBr. The percentage of carbon in the compound (X)(X)(X) is 26.7%. Total number of carbon atoms in the empirical formula for compound (X)(X)(X) is _______. (Given molar mass in g mol−1mol^{-1}mol−1 H:1, C:12, Br:80, Ag:108)

Correct answer: 5

Step-by-step solution →
Q48·ChemistryNumerical
The pH of a solution obtained by mixing 5 mL of 0.1 M NH4OHNH_4OHNH4​OH solution with 250 mL of 0.1 M NH4ClNH_4ClNH4​Cl solution is _______ ×10−2\times 10^{-2}×10−2. (Nearest integer) Given: pKb(NH4OH)=4.74pK_b(NH_4OH) = 4.74pKb​(NH4​OH)=4.74 log⁡2=0.30\log 2 = 0.30log2=0.30 log⁡3=0.48\log 3 = 0.48log3=0.48 log⁡5=0.70\log 5 = 0.70log5=0.70

Correct answer: 756

Step-by-step solution →
Q49·ChemistryNumerical
A non-volatile, non-electrolyte solid solute when dissolved in 40 g of a solvent, the vapour pressure of the solvent decreased from 760 mm Hg to 750 mm Hg. If the same solution boils at 320 K, then the number of moles of the solvent present in the solution is _______. (Nearest integer) [Given: boiling point of the pure solvent =319.5= 319.5=319.5 K, KbK_bKb​ of the solvent =0.3= 0.3=0.3 K kg mol−1mol^{-1}mol−1]

Correct answer: 5

Step-by-step solution →

Mathematics — JEE Main 4 April 2026 Shift 1

Q50·MathematicsSingle correct
Let [⋅][\cdot][⋅] denote the greatest integer function. If the domain of the function f(x)=cos⁡−1(4x+2[x]3)f(x) = \cos^{-1}\left(\frac{4x + 2[x]}{3}\right)f(x)=cos−1(34x+2[x]​) is [α,β][\alpha, \beta][α,β], then 12(α+β)12(\alpha + \beta)12(α+β) is equal to:
  1. (A)666
  2. (B)888
  3. (C)999
  4. (D)444

Correct answer: (A)

Step-by-step solution →
Q51·MathematicsSingle correct
If the set of all solutions of ∣x2+x−9∣=∣x∣+∣x2−9∣|x^2 + x - 9| = |x| + |x^2 - 9|∣x2+x−9∣=∣x∣+∣x2−9∣ is [α,β]∪[γ,∞)[\alpha, \beta] \cup [\gamma, \infty)[α,β]∪[γ,∞), then (α2+β2+γ2)(\alpha^2 + \beta^2 + \gamma^2)(α2+β2+γ2) is equal to:
  1. (A)999
  2. (B)181818
  3. (C)363636
  4. (D)727272

Correct answer: (B)

Step-by-step solution →
Q52·MathematicsSingle correct
Let zzz be a complex number such that ∣z+2∣=∣z−2∣|z + 2| = |z - 2|∣z+2∣=∣z−2∣ and arg⁡(z+3z−i)=π4\arg\left(\frac{z + 3}{z - i}\right) = \frac{\pi}{4}arg(z−iz+3​)=4π​. Then ∣z∣2|z|^2∣z∣2 is equal to:
  1. (A)999
  2. (B)444
  3. (C)555
  4. (D)111

Correct answer: (A)

Step-by-step solution →
Q53·MathematicsSingle correct
The number of functions f:{1,2,3,4}→{a,b,c}f : \{1, 2, 3, 4\} \to \{a, b, c\}f:{1,2,3,4}→{a,b,c}, which are not onto, is:
  1. (A)484848
  2. (B)454545
  3. (C)515151
  4. (D)353535

Correct answer: (B)

Step-by-step solution →
Q54·MathematicsSingle correct
Let S={A=[abcd]:a,b,c,d∈{0,1,2,3,4} and A2−4A+3I=0}S = \left\{ A = \begin{bmatrix} a & b \\ c & d \end{bmatrix} : a, b, c, d \in \{0, 1, 2, 3, 4\} \text{ and } A^2 - 4A + 3I = 0 \right\}S={A=[ac​bd​]:a,b,c,d∈{0,1,2,3,4} and A2−4A+3I=0} be a set of 2×22 \times 22×2 matrices. Then the number of matrices in SSS, for which the sum of the diagonal elements is equal to 4, is:
  1. (A)202020
  2. (B)171717
  3. (C)212121
  4. (D)191919

Correct answer: (D)

Step-by-step solution →
Q55·MathematicsSingle correct
Let A=[112−201135]A = \begin{bmatrix} 1 & 1 & 2 \\ -2 & 0 & 1 \\ 1 & 3 & 5 \end{bmatrix}A=​1−21​103​215​​. Then the sum of all elements of the matrix adj(adj(2(adjA)−1))\mathrm{adj}(\mathrm{adj}(2(\mathrm{adj}A)^{-1}))adj(adj(2(adjA)−1)) is equal to:
  1. (A)333
  2. (B)444
  3. (C)−4-4−4
  4. (D)−3-3−3

Correct answer: (D)

Step-by-step solution →
Q56·MathematicsSingle correct
The first term of an A.P. of 30 non-negative terms is 103\frac{10}{3}310​. If the sum of this A.P. is the cube of its last term, then its common difference is:
  1. (A)587\frac{5}{87}875​
  2. (B)2583\frac{25}{83}8325​
  3. (C)1529\frac{15}{29}2915​
  4. (D)529\frac{5}{29}295​

Correct answer: (A)

Step-by-step solution →
Q57·MathematicsSingle correct
The number of ways of forming a queue of 4 boys and 3 girls such that all the girls are not together, is:
  1. (A)504050405040
  2. (B)305030503050
  3. (C)341034103410
  4. (D)432043204320

Correct answer: (D)

Step-by-step solution →
Q58·MathematicsSingle correct
Let the smallest value of k∈Nk \in \mathbb{N}k∈N, for which the coefficient of x3x^3x3 in (1+x)3+(1+x)4+(1+x)5+…+(1+x)99+(1+kx)100(1 + x)^3 + (1 + x)^4 + (1 + x)^5 + \ldots + (1 + x)^{99} + (1 + kx)^{100}(1+x)3+(1+x)4+(1+x)5+…+(1+x)99+(1+kx)100, x≠0x \neq 0x=0, is (43n+1014)(100C3)\left(43n + \frac{101}{4}\right)\left({}^{100}C_3\right)(43n+4101​)(100C3​) for some n∈Nn \in \mathbb{N}n∈N, be ppp. Then the value of p+np + np+n is:
  1. (A)101010
  2. (B)111111
  3. (C)121212
  4. (D)131313

Correct answer: (B)

Step-by-step solution →
Q59·MathematicsSingle correct
Suppose that the mean and median of the non-negative numbers 21,8,17,a,51,103,b,13,67,(a>b)21, 8, 17, a, 51, 103, b, 13, 67, (a > b)21,8,17,a,51,103,b,13,67,(a>b), are 40 and 21, respectively. If the mean deviation about the median is 26, then 2a2a2a is equal to:
  1. (A)109109109
  2. (B)117117117
  3. (C)161161161
  4. (D)131131131

Correct answer: (D)

Step-by-step solution →
Q60·MathematicsSingle correct
Let the line L1:x+3=0L_1 : x + 3 = 0L1​:x+3=0 intersect the lines L2:x−y=0L_2 : x - y = 0L2​:x−y=0 and L3:3x+y=0L_3 : 3x + y = 0L3​:3x+y=0 at the points AAA and BBB, respectively. Let the bisector of the obtuse angle between the lines L2L_2L2​ and L3L_3L3​ intersect the line L1L_1L1​ at the point CCC. Then BC2:AC2BC^2 : AC^2BC2:AC2 is equal to:
  1. (A)5:15 : 15:1
  2. (B)1:51 : 51:5
  3. (C)2:32 : 32:3
  4. (D)3:23 : 23:2

Correct answer: (A)

Step-by-step solution →
Q61·MathematicsSingle correct
Let the vertex AAA of a triangle ABCABCABC be (1,2)(1, 2)(1,2), and the mid-point of the side ABABAB be (5,−1)(5, -1)(5,−1). If the centroid of this triangle is (3,4)(3, 4)(3,4) and its circumcenter is (α,β)(\alpha, \beta)(α,β), then 21(α+β)21(\alpha + \beta)21(α+β) is equal to:
  1. (A)309309309
  2. (B)403403403
  3. (C)497497497
  4. (D)524524524

Correct answer: (C)

Step-by-step solution →
Q62·MathematicsSingle correct
Suppose that two chords, drawn from the point (1,2)(1, 2)(1,2) on the circle x2+y2+x−3y=0x^2 + y^2 + x - 3y = 0x2+y2+x−3y=0 are bisected by the yyy-axis. If the other ends of these chords are RRR and SSS, and the mid point of the line segment RSRSRS is (α,β)(\alpha, \beta)(α,β), then 6(α+β)6(\alpha + \beta)6(α+β) is equal to:
  1. (A)111
  2. (B)333
  3. (C)444
  4. (D)666

Correct answer: (B)

Step-by-step solution →
Q63·MathematicsSingle correct
A line with direction ratios 1,−1,21, -1, 21,−1,2 intersects the lines x2=y3=z+13\frac{x}{2} = \frac{y}{3} = \frac{z+1}{3}2x​=3y​=3z+1​ and x+1−1=y−21=z4\frac{x+1}{-1} = \frac{y-2}{1} = \frac{z}{4}−1x+1​=1y−2​=4z​ at the points PPP and QQQ, respectively. If the length of the line segment PQPQPQ is α\alphaα, then 225α2225\alpha^2225α2 is equal to:
  1. (A)102410241024
  2. (B)101410141014
  3. (C)110411041104
  4. (D)120412041204

Correct answer: (B)

Step-by-step solution →
Q64·MathematicsSingle correct
The square of the distance of the point (−2,−8,6)(-2, -8, 6)(−2,−8,6) from the line x−11=y−12=z−1\frac{x-1}{1} = \frac{y-1}{2} = \frac{z}{-1}1x−1​=2y−1​=−1z​ along the line x+51=y+5−1=z2\frac{x+5}{1} = \frac{y+5}{-1} = \frac{z}{2}1x+5​=−1y+5​=2z​ is equal to:
  1. (A)333
  2. (B)666
  3. (C)888
  4. (D)121212

Correct answer: (B)

Step-by-step solution →
Q65·MathematicsSingle correct
If y=tan⁡−1(3cos⁡x−4sin⁡x4cos⁡x+3sin⁡x)+2tan⁡−1(x1+1−x2)y = \tan^{-1}\left(\frac{3\cos x - 4\sin x}{4\cos x + 3\sin x}\right) + 2\tan^{-1}\left(\frac{x}{1+\sqrt{1-x^2}}\right)y=tan−1(4cosx+3sinx3cosx−4sinx​)+2tan−1(1+1−x2​x​), then dydx\frac{dy}{dx}dxdy​ at x=32x = \frac{\sqrt{3}}{2}x=23​​ is equal to:
  1. (A)333
  2. (B)−1-1−1
  3. (C)111
  4. (D)222

Correct answer: (C)

Step-by-step solution →
Q66·MathematicsSingle correct
Let fff be a real polynomial of degree nnn such that f(x)=f′(x)f′′(x)f(x) = f'(x)f''(x)f(x)=f′(x)f′′(x), for all x∈Rx \in \mathbb{R}x∈R. If f(0)=0f(0) = 0f(0)=0, then 36(f′(2)+f′′(2)+∫02f(x) dx)36\left(f'(2) + f''(2) + \int_0^2 f(x)\, dx\right)36(f′(2)+f′′(2)+∫02​f(x)dx) is equal to:
  1. (A)424242
  2. (B)464646
  3. (C)565656
  4. (D)666666

Correct answer: (C)

Step-by-step solution →
Q67·MathematicsSingle correct
The area of the region {(x,y):y≤π−∣x∣, y≤∣xsin⁡x∣, y≥0}\{(x, y) : y \leq \pi - |x|,\ y \leq |x \sin x|,\ y \geq 0\}{(x,y):y≤π−∣x∣, y≤∣xsinx∣, y≥0} is:
  1. (A)1+π281 + \frac{\pi^2}{8}1+8π2​
  2. (B)2+π242 + \frac{\pi^2}{4}2+4π2​
  3. (C)π28−1\frac{\pi^2}{8} - 18π2​−1
  4. (D)4+π224 + \frac{\pi^2}{2}4+2π2​

Correct answer: (B)

Step-by-step solution →
Q68·MathematicsSingle correct
Let ∫−22(∣sin⁡x∣+[xsin⁡x])dx=2(3−cos⁡2)+β\int_{-2}^{2}\left(|\sin x| + [x \sin x]\right) dx = 2(3 - \cos 2) + \beta∫−22​(∣sinx∣+[xsinx])dx=2(3−cos2)+β, where [⋅][\cdot][⋅] is the greatest integer function. Then βsin⁡(β2)\beta \sin\left(\frac{\beta}{2}\right)βsin(2β​) equals:
  1. (A)111
  2. (B)222
  3. (C)444
  4. (D)888

Correct answer: (B)

Step-by-step solution →
Q69·MathematicsSingle correct
Let y=y(x)y = y(x)y=y(x) be the solution of the differential equation dydx=(1+x+x2)(1−y+y2)\frac{dy}{dx} = (1 + x + x^2)(1 - y + y^2)dxdy​=(1+x+x2)(1−y+y2), y(0)=12y(0) = \frac{1}{2}y(0)=21​. Then (2y(1)−1)(2y(1) - 1)(2y(1)−1) is equal to:
  1. (A)3tan⁡(1136)\sqrt{3} \tan\left(\frac{11\sqrt{3}}{6}\right)3​tan(6113​​)
  2. (B)32tan⁡(11312)\frac{\sqrt{3}}{2} \tan\left(\frac{11\sqrt{3}}{12}\right)23​​tan(12113​​)
  3. (C)3tan⁡(11312)\sqrt{3} \tan\left(\frac{11\sqrt{3}}{12}\right)3​tan(12113​​)
  4. (D)32tan⁡(1136)\frac{\sqrt{3}}{2} \tan\left(\frac{11\sqrt{3}}{6}\right)23​​tan(6113​​)

Correct answer: (C)

Step-by-step solution →
Q70·MathematicsNumerical
A coin is tossed 8 times. If the probability that exactly 4 heads appear in the first six tosses and exactly 3 heads appear in the last five tosses is ppp, then 96p96p96p is equal to _______.

Correct answer: 9

Step-by-step solution →
Q71·MathematicsNumerical
Consider the parabola P:y2=4kxP : y^2 = 4kxP:y2=4kx and the ellipse E:x2a2+y2b2=1E : \frac{x^2}{a^2} + \frac{y^2}{b^2} = 1E:a2x2​+b2y2​=1. Let the line segment joining the points of intersection of PPP and EEE, be their latus rectums. If the eccentricity of EEE is eee, then e2+22e^2 + 2\sqrt{2}e2+22​ is equal to _______.

Correct answer: 3

Step-by-step solution →
Q72·MathematicsNumerical
If A=sin⁡3∘cos⁡9∘+sin⁡9∘cos⁡27∘+sin⁡27∘cos⁡81∘A = \frac{\sin 3^\circ}{\cos 9^\circ} + \frac{\sin 9^\circ}{\cos 27^\circ} + \frac{\sin 27^\circ}{\cos 81^\circ}A=cos9∘sin3∘​+cos27∘sin9∘​+cos81∘sin27∘​ and B=tan⁡81∘−tan⁡3∘B = \tan 81^\circ - \tan 3^\circB=tan81∘−tan3∘, then BA\frac{B}{A}AB​ is equal to _______.

Correct answer: 2

Step-by-step solution →
Q73·MathematicsNumerical
Let a⃗k=(tan⁡θk)i^+j^\vec{a}_k = (\tan\theta_k)\hat{i} + \hat{j}ak​=(tanθk​)i^+j^​ and b⃗k=i^−(cot⁡θk)j^\vec{b}_k = \hat{i} - (\cot\theta_k)\hat{j}bk​=i^−(cotθk​)j^​, where θk=2k−1π2n+1\theta_k = \frac{2^{k-1}\pi}{2^n + 1}θk​=2n+12k−1π​, for some n∈Nn \in \mathbb{N}n∈N, n>5n > 5n>5. Then the value of ∑k=1n∣a⃗k∣2∑k=1n∣b⃗k∣2\frac{\sum_{k=1}^{n} |\vec{a}_k|^2}{\sum_{k=1}^{n} |\vec{b}_k|^2}∑k=1n​∣bk​∣2∑k=1n​∣ak​∣2​ is _______.

Correct answer: 3

Step-by-step solution →
Q74·MathematicsNumerical
The number of points, at which the function f(x)=max⁡{6x,2+3x2}+∣x−1∣∣cos⁡∣x2−14∣∣f(x) = \max\{6x, 2 + 3x^2\} + |x - 1|\left|\cos\left|x^2 - \frac{1}{4}\right|\right|f(x)=max{6x,2+3x2}+∣x−1∣​cos​x2−41​​​, x∈(−π,π)x \in (-\pi, \pi)x∈(−π,π), is not differentiable, is _______.

Correct answer: 9

Step-by-step solution →

Chapters tested in this paper

Open any chapter to practise every past-year question on that topic across all papers, and see how often it has actually appeared.

  • Properties of Solids and Liquids 172/186
  • Three Dimensional Geometry 176/186
  • Matrices and Determinants 180/186
  • Coordination Compounds 176/186
  • Current Electricity 160/186
  • Sequence and Series 164/186
  • p-Block Elements 164/186
  • Definite Integration 168/186
  • Rotational Motion 172/186
  • Redox Reactions and Electrochemistry 177/186
  • Geometrical Optics 172/186
  • Kinematics 156/186
  • Differential Equations 167/186
  • Probability 176/186
  • Permutations and Combinations 162/186
  • Magnetic Field of Current 147/186
  • Binomial Theorem and Its Simple Applications 158/186
  • d- and f-Block Elements 126/186
  • Thermodynamics 154/186
  • Equilibrium 163/186
  • Solutions 158/186
  • Laws of Motion 130/186
  • Chemical Thermodynamics 165/186
  • Hydrocarbons 126/186
  • Complex Numbers 165/186
  • Trigonometric Functions 144/186
  • Biomolecules 162/186
  • Chemical Kinetics 169/186
  • Atomic Structure 161/186
  • Electronic Devices 145/186
  • Circles 142/186
  • Dual Nature of Matter and Radiation 155/186
  • Quadratic Equations 148/186
  • Work, Energy and Power 132/186
  • Some Basic Concepts in Chemistry 129/186
  • Wave Optics 130/186
  • Area Under Curves 139/186
  • Kinetic Theory of Gases 135/186
  • Alcohols and Ethers 106/186
  • Purification and Characterisation of Organic Compounds 116/186
  • Oscillations 117/186
  • Alternating Currents 108/186
  • Nuclei 116/186
  • Organic Compounds Containing Halogens 109/186
  • Straight Lines 114/186
  • Capacitors and Dielectrics 115/186
  • Classification of Elements and Periodicity in Properties 113/186
  • Statistics 118/186
  • Ellipse 103/186
  • Differentiability 91/186
  • Inverse Trigonometric Functions 93/186
  • Electronic Effects and Stability 74/186
  • Experimental Skills 68/186
  • Diazonium Salts and Reactions 53/186
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