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JEE Main 25 February 2021 Shift 1 Question Paper with Answers

25 February 2021 · February session · 90 questions

The complete JEE Main 25 February 2021 Shift 1 paper — all 90 questions with the correct answer for each, tagged to the chapter it tests. Free to read, no account needed.

Physics
30
Chemistry
30
Mathematics
30

Physics — JEE Main 25 February 2021 Shift 1

Q1·PhysicsSingle correct
A 5V battery is connected across the points X and Y. Assume D1D_1D1​ and D2D_2D2​ to be normal silicon diodes. Find the current supplied by the battery if the +ve terminal of the battery is connected to point X.
  1. (A)~0.86 A
  2. (B)~0.5 A
  3. (C)~ 0.43 A
  4. (D)~ 1.5 A

Correct answer: (C)

Step-by-step solution →
Q2·PhysicsSingle correct
A solid sphere of radius R gravitationally attracts a particle placed at 3R from its centre with a force F1F_1F1​. Now a spherical cavity of radius (R2)\left(\dfrac{R}{2}\right)(2R​) is made in the sphere (as shown in figure) and the force becomes F2F_2F2​. The value of F1:F2F_1 : F_2F1​:F2​ is :
  1. (A)41 : 50
  2. (B)36 : 25
  3. (C)50 : 41
  4. (D)25 : 36

Correct answer: (A)

Step-by-step solution →
Q3·PhysicsSingle correct
A student is performing the experiment of resonance column. The diameter of the column tube is 6 cm. The frequency of the tuning fork is 504 Hz. Speed of the sound at the given temperature is 336 m/s. The zero of the metre scale coincides with the top end of the resonance column tube. The reading of the water level in the column when the first resonance occurs is :
  1. (A)13 cm
  2. (B)14.8 cm
  3. (C)16.6 cm
  4. (D)18.4 cm

Correct answer: (B)

Step-by-step solution →
Q4·PhysicsSingle correct
A diatomic gas, having Cp=72RC_p = \dfrac{7}{2}RCp​=27​R and Cv=52RC_v = \dfrac{5}{2}RCv​=25​R, is heated at constant pressure. The ratio dU : dQ : dW
  1. (A)3 : 7 : 2
  2. (B)5 : 7 : 2
  3. (C)5 : 7 : 3
  4. (D)3 : 5 : 2

Correct answer: (B)

Step-by-step solution →
Q5·PhysicsSingle correct
Given below are two statements : Statement I : A speech signal of 2 kHz is used to modulate a carrier signal of 1 MHz. The bandwidth requirement for the signal is 4 kHz. Statement II : The side band frequencies are 1002 kHz and 998 kHz. In the light of the above statements, choose the correct answer from the options given below :
  1. (A)Both statement I and statement II are false
  2. (B)Statement I is false but statement II is true
  3. (C)Statement I is true but statement II is false
  4. (D)Both statement I and statement II are true

Correct answer: (D)

Step-by-step solution →
Q6·PhysicsSingle correct
The current (i) at time t=0 and t=∞t = \inftyt=∞ respectively for the given circuit is :
  1. (A)18E55,5E18\dfrac{18E}{55}, \dfrac{5E}{18}5518E​,185E​
  2. (B)5E18,18E55\dfrac{5E}{18}, \dfrac{18E}{55}185E​,5518E​
  3. (C)5E18,10E33\dfrac{5E}{18}, \dfrac{10E}{33}185E​,3310E​
  4. (D)10E33,5E18\dfrac{10E}{33}, \dfrac{5E}{18}3310E​,185E​

Correct answer: (C)

Step-by-step solution →
Q7·PhysicsSingle correct
Two satellites A and B of masses 200 kg and 400 kg are revolving round the earth at height of 600 km and 1600 km respectively. If TAT_ATA​ and TBT_BTB​ are the time periods of A and B respectively then the value of TB−TAT_B - T_ATB​−TA​ : [Given : radius of earth = 6400 km, mass of earth = 6×10246 \times 10^{24}6×1024 kg]
  1. (A)4.24×1024.24 \times 10^24.24×102 s
  2. (B)3.33×1023.33 \times 10^23.33×102 s
  3. (C)1.33×1031.33 \times 10^31.33×103 s
  4. (D)4.24×1034.24 \times 10^34.24×103 s

Correct answer: (C)

Step-by-step solution →
Q8·PhysicsSingle correct
An engine of a train, moving with uniform acceleration, passes the signal post with velocity u and the last compartment with velocity v. The velocity with which middle point of the train passes the signal post is :
  1. (A)v2−u22\sqrt{\dfrac{v^2 - u^2}{2}}2v2−u2​​
  2. (B)v−u2\dfrac{v - u}{2}2v−u​
  3. (C)v2+u22\sqrt{\dfrac{v^2 + u^2}{2}}2v2+u2​​
  4. (D)u+v2\dfrac{u + v}{2}2u+v​

Correct answer: (C)

Step-by-step solution →
Q9·PhysicsSingle correct
A proton, a deuteron and an α particle are moving with same momentum in a uniform magnetic field. The ratio of magnetic forces action on them is ________ and their speed is ______, in the ratio.
  1. (A)2 : 1 : 1 and 4 : 2 : 1
  2. (B)1 : 2 : 4 and 2 : 1 :1
  3. (C)1 : 2 : 4 and 1 : 1 : 2
  4. (D)4 : 2 : 1 and 2 : 1 : 1

Correct answer: (A)

Step-by-step solution →
Q10·PhysicsSingle correct
Given below are two statements : one is labelled as Assertion A and the other is labelled as Reason R. Assertion A : When a rod lying freely is heated, no thermal stress is developed in it. Reason R : On heating, the length of the rod increases. In the light of the above statements, choose the corect answer from the options given below :
  1. (A)A is true but R is false
  2. (B)Both A and R are true and R is the correct explanation of A
  3. (C)Both A and R are true but R is NOT the correct explanation of A
  4. (D)A is false but R is true

Correct answer: (C)

Step-by-step solution →
Q11·PhysicsSingle correct
In an octagon ABCDEFGH of equal side, what is the sum of AB→+AC→+AD→+AE→+AF→+AG→+AH→\overrightarrow{AB} + \overrightarrow{AC} + \overrightarrow{AD} + \overrightarrow{AE} + \overrightarrow{AF} + \overrightarrow{AG} + \overrightarrow{AH}AB+AC+AD+AE+AF+AG+AH If, AO→=2i^+3j^−4k^\overrightarrow{AO} = 2\hat{i} + 3\hat{j} - 4\hat{k}AO=2i^+3j^​−4k^
  1. (A)16i^+24j^−32k^16\hat{i} + 24\hat{j} - 32\hat{k}16i^+24j^​−32k^
  2. (B)−16i^−24j^−32k^-16\hat{i} - 24\hat{j} - 32\hat{k}−16i^−24j^​−32k^
  3. (C)−16i^−24j^+32k^-16\hat{i} - 24\hat{j} + 32\hat{k}−16i^−24j^​+32k^
  4. (D)−16i^+24j^+32k^-16\hat{i} + 24\hat{j} + 32\hat{k}−16i^+24j^​+32k^

Correct answer: (A)

Step-by-step solution →
Q12·PhysicsSingle correct
Two radioactive substances X and Y originally have N1N_1N1​ and N2N_2N2​nuclei respectively. Half life of X is half of the half life of Y. After there half lives of Y, number of nuclei of both are equal. The ratio N1N2\dfrac{N_1}{N_2}N2​N1​​ will be equal to :
  1. (A)81\dfrac{8}{1}18​
  2. (B)18\dfrac{1}{8}81​
  3. (C)31\dfrac{3}{1}13​
  4. (D)13\dfrac{1}{3}31​

Correct answer: (A)

Step-by-step solution →
Q13·PhysicsSingle correct
Match List –I with List- II : List-I (a)h (Planck's constant) (b)E (kinetic energy) (c)V (electric potential) (d)P (linear momentum) List-II (i) [M L T−1][M\,L\,T^{-1}][MLT−1] (ii) [M L2 T−1][M\,L^2\,T^{-1}][ML2T−1] (iii) [M L2 T−2][M\,L^2\,T^{-2}][ML2T−2] (iv) [ML2I−1 T−3][ML^2I^{-1}\,T^{-3}][ML2I−1T−3] Choose the correct answer from the options given below :
  1. (A)(a) → (ii), (b) → (iii), (c) → (iv), (d) → (i)
  2. (B)(a) → (i), (b) → (ii), (c) → (iv), (d) → (iii)
  3. (C)(a) → (iii), (b) → (ii), (c) → (iv), (d) → (i)
  4. (D)(a) → (iii), (b) → (iv), (c) → (ii), (d) → (i)

Correct answer: (A)

Step-by-step solution →
Q14·PhysicsSingle correct
The pitch of the screw guage is 1 mm and there are 100 divisions on the circular scale. When nothing is put in between the jaws, the zero of the circular scale lines 8 divisions below the reference line. When a wire is placed between the jaws, the first linear scale division is clearly visible while 72nd72^{nd}72nd division on circular scale coincides with the reference line. The radius of the wire is :
  1. (A)1.64 mm
  2. (B)1.80 mm
  3. (C)0.82 mm
  4. (D)0.90 mm

Correct answer: (C)

Step-by-step solution →
Q15·PhysicsSingle correct
If the time period of a two meter long simple pendulum is 2 s, the acceleration due to gravity at the place where pendulum is executing S.H.M. is :
  1. (A)2π2ms−22\pi^2 \mathrm{ms}^{-2}2π2ms−2
  2. (B)16m/s216 \mathrm{m/s}^216m/s2
  3. (C)9.8ms−29.8 \mathrm{ms}^{-2}9.8ms−2
  4. (D)π2ms−2\pi^2 \mathrm{ms}^{-2}π2ms−2

Correct answer: (A)

Step-by-step solution →
Q16·PhysicsSingle correct
An α\alphaα particle and a proton are accelerated from rest by a potential difference of 200 V. After this, their de Broglie wavelengths are λα\lambda_\alphaλα​ and λp\lambda_pλp​ respectively. The ratio λpλα\dfrac{\lambda_p}{\lambda_\alpha}λα​λp​​ is :
  1. (A)8
  2. (B)2.8
  3. (C)3.8
  4. (D)7.8

Correct answer: (B)

Step-by-step solution →
Q17·PhysicsSingle correct
Given below are two statements : one is labelled as Assertion A and the other is labelled as reason R. Assertion A : The escape velocities of planet A and B are same. But A and B are of unequal mass. Reason R : The product of their mass and radius must be same. M1R1=M2R2M_1R_1 = M_2R_2M1​R1​=M2​R2​ In the light of the above statements, choose the most appropriate answer from the options given below:
  1. (A)Both A and R are correct but R is NOT the correct explanation of A
  2. (B)A is correct but R is not correct
  3. (C)Both A and R are correct and R is the correct explanation of A
  4. (D)A is not correct but R is correct

Correct answer: (B)

Step-by-step solution →
Q18·PhysicsSingle correct
The angular frequency of alterlating current in a L-C-R circuit is 100 rad/s. The components connected are shown in the figure. Find the value of inductance of the coil and capacity of condenser.
  1. (A)0.8 H and 250 μ\muμF
  2. (B)0.8 H and 150 μ\muμF
  3. (C)1.33 H and 250 μ\muμF
  4. (D)1.33 H and 150 μ\muμF

Correct answer: (A)

Step-by-step solution →
Q19·PhysicsSingle correct
Two coherent light sources having intensity in the ratio 2x produce an interference pattern. The ratio Imax−IminImax+Imin\dfrac{I_{max} - I_{min}}{I_{max} + I_{min}}Imax​+Imin​Imax​−Imin​​ will be :
  1. (A)22xx+1\dfrac{2\sqrt{2x}}{x + 1}x+122x​​
  2. (B)2x2x+1\dfrac{\sqrt{2x}}{2x + 1}2x+12x​​
  3. (C)22x2x+1\dfrac{2\sqrt{2x}}{2x + 1}2x+122x​​
  4. (D)2xx+1\dfrac{\sqrt{2x}}{x + 1}x+12x​​

Correct answer: (C)

Step-by-step solution →
Q20·PhysicsSingle correct
Magnetic fields at two points on the axis of a circular coil at a distance of 0.05 m and 02 m from the centre are in the rato 8 : 1. The radius of coil is ________
  1. (A)0.15 m
  2. (B)0.2 m
  3. (C)0.1 m
  4. (D)1.0 m

Correct answer: (C)

Step-by-step solution →
Q21·PhysicsNumerical
The same size images are formed by a convex lens when the object is placed at 20 cm or at 10 cm from the lens. The focal length of convex lens is ________ cm.

Correct answer: 15

Step-by-step solution →
Q22·PhysicsNumerical
The electric field in a region is given by E⃗=(35E0i^+45E0j^)NC\vec{E} = \left(\dfrac{3}{5}E_0\hat{i} + \dfrac{4}{5}E_0\hat{j}\right)\dfrac{N}{C}E=(53​E0​i^+54​E0​j^​)CN​. The ratio of flux of reported field through the rectangular surface of area 0.2 m2m^2m2 (parallel to y-z plane) to that of the surface of area 0.3 m2m^2m2 (parallel to x-z plane) is a : b, where a = __________ [Here i^\hat{i}i^, j^\hat{j}j^​ and k^\hat{k}k^ are unit vectors along x, y and z-axes respectively]

Correct answer: 1

Step-by-step solution →
Q23·PhysicsNumerical
512 identical drops of mercury are charged to a potential of 2 V each. The drops are joined to form a single drop. The potential of this drop is _____ V.

Correct answer: 128

Step-by-step solution →
Q24·PhysicsNumerical
The potential energy (U) of a diatomic molecule is a function dependent on r (interatomic distance) as U=αr10−βr5−3U = \dfrac{\alpha}{r^{10}} - \dfrac{\beta}{r^5} - 3U=r10α​−r5β​−3 Where, a and b are positive constants. The equilibrium distance between two atoms will (2αβ)ab\left(\dfrac{2\alpha}{\beta}\right)^{\frac{a}{b}}(β2α​)ba​. Where a = ________

Correct answer: 1

Step-by-step solution →
Q25·PhysicsNumerical
A small bob tied at one end of a thin string of length 1m is describing a vertical circle so that the maximum and minimum tension in the string are in the rato 5 : 1. The velocity of the bob at the highest position is ________ m/s. (take g=10 m/s2m/s^2m/s2)

Correct answer: 5

Step-by-step solution →
Q26·PhysicsNumerical
In a certain themodynamical process, the pressure ofa gas depends on its volume as kV3kV^3kV3 . The work done when the temperature changes from 100ºC to 300ºC will be _____ nR, where n denotes number of moles of a gas.

Correct answer: 50

Step-by-step solution →
Q27·PhysicsNumerical
In the given circuit of potentiometer, the potentital difference E across AB (10 m length) is larger than E1E_1E1​ and E2E_2E2​ as well. For key K1K_1K1​ (closed), the jockey is adjusted to touch the wire at point J1J_1J1​ so that there is no deflection in the galvanometer. Now the first battery (E1E_1E1​) is replaced by second battery (E2E_2E2​) for working by making K1K_1K1​ open and E2E_2E2​ closed. The galvanometer gives then null deflection at J2J_2J2​. The value of E1E2\dfrac{E_1}{E_2}E2​E1​​ is ab\dfrac{a}{b}ba​, where a = _____.

Correct answer: 1

Step-by-step solution →
Q28·PhysicsNumerical
A monoatomic gas of mass 4.0 u is kept in an insulated container. Container is moving with velocity 30 m/s. If container is suddenly stopped then change in temperature of the gas (R=gas constant) is x3R\dfrac{x}{3R}3Rx​. Value of x is ________ .

Correct answer: 3600

Step-by-step solution →
Q29·PhysicsNumerical
A coil of inductance 2 H having negligible resistance is connected to a source of supply whose voltage is given by V =3t volt. (where t is in second). If the voltage is applied when t = 0, then the energy stored in the coil after 4 s is ________ J.

Correct answer: 144

Step-by-step solution →
Q30·PhysicsNumerical
A transmitting station releases waves of wavelength 960 m. A capacitor of 256 μ\muμF is used in the resonant circuit. The self inductance of coil necessary for resonance is ______ ×10−8\times 10^{-8}×10−8H.

Correct answer: 10

Step-by-step solution →

Chemistry — JEE Main 25 February 2021 Shift 1

Q31·ChemistrySingle correct
Ellingham diagram is a graphical representation of:
  1. (A)ΔG vs T
  2. (B)(ΔG − TΔS) vs T
  3. (C)ΔH vs T
  4. (D)ΔG vs P

Correct answer: (A)

Step-by-step solution →
Q32·ChemistrySingle correct
Which of the following equation depicts the oxidizing nature of H2_{2}2​O2_{2}2​?
  1. (A)Cl2_{2}2​ + H2_{2}2​O2_{2}2​ → 2HCl + O2_{2}2​
  2. (B)KIO4_{4}4​ + H2_{2}2​O2_{2}2​ → KIO3_{3}3​ + H2_{2}2​O + O2_{2}2​
  3. (C)2I−^{-}− + H2_{2}2​O2_{2}2​ + 2H+^{+}+ → I2_{2}2​ + 2H2_{2}2​O
  4. (D)I2_{2}2​ + H2_{2}2​O2_{2}2​ + 2OH−^{-}− → 2I−^{-}− + 2H2O + O2_{2}2​

Correct answer: (C)

Step-by-step solution →
Q33·ChemistrySingle correct
In Freundlich adsorption isotherm at moderate pressure, the extent of adsorption (xm)\left(\dfrac{x}{m}\right)(mx​) is directly proportional to Px^{x}x. The value of x is:
  1. (A)∞
  2. (B)1
  3. (C)zero
  4. (D)1n\dfrac{1}{n}n1​

Correct answer: (D)

Step-by-step solution →
Q34·ChemistrySingle correct
According to molecular orbital theory, the species among the following that does not exist is:
  1. (A)He2−_{2}^{-}2−​
  2. (B)He2+_{2}^{+}2+​
  3. (C)O22−_{2}^{2-}22−​
  4. (D)Be2_{2}2​

Correct answer: (D)

Step-by-step solution →
Q35·ChemistrySingle correct
Identify A in the given chemical reaction.
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (D)

Step-by-step solution →
Q36·ChemistrySingle correct
Given below are two statements: Statement-I : CeO2_{2}2​ can be used for oxidation of aldehydes and ketones. Statement-II : Aqueous solution of EuSO4_{4}4​ is a strong reducing agent.
  1. (A)Statement I is true, statement II is false
  2. (B)Statement I is false, statement II is true
  3. (C)Both Statement I and Statement II are false
  4. (D)Both Statement I and Statement II are true

Correct answer: (D)

Step-by-step solution →
Q37·ChemistrySingle correct
The major product of the following chemical reaction is: CH3_{3}3​CH2_{2}2​CN →3) Pd/BaSO4, H21) H3O+, Δ2) SOCl2\xrightarrow[\text{3) Pd/BaSO}_{4}\text{, H}_{2}]{\substack{\text{1) H}_{3}\text{O}^{+}\text{, }\Delta \\ \text{2) SOCl}_{2}}}1) H3​O+, Δ2) SOCl2​​3) Pd/BaSO4​, H2​​ ?
  1. (A)(CH3_{3}3​CH2_{2}2​CO)2_{2}2​O
  2. (B)CH3_{3}3​CH2_{2}2​CHO
  3. (C)CH3_{3}3​CH2_{2}2​CH3_{3}3​
  4. (D)CH3_{3}3​CH2_{2}2​CH2_{2}2​OH

Correct answer: (B)

Step-by-step solution →
Q38·ChemistrySingle correct
Complete combustion of 1.80 g of an oxygen containing compound (Cx_{x}x​Hy_{y}y​Oz_{z}z​) gave 2.64 g of CO2_{2}2​ and 1.08 g of H2_{2}2​O. The percentage of oxygen in the organic compound is:
  1. (A)63.53
  2. (B)53.33
  3. (C)51.63
  4. (D)50.33

Correct answer: (B)

Step-by-step solution →
Q39·ChemistrySingle correct
The correct statement about B2_{2}2​H6_{6}6​ is:
  1. (A)All B−H−B angles are of 120°.
  2. (B)Its fragment, BH3_{3}3​, behaves as a Lewis base.
  3. (C)Terminal B−H bonds have less p-character when compared to bridging bonds.
  4. (D)The two B−H−B bonds are not of same length.

Correct answer: (C)

Step-by-step solution →
Q40·ChemistrySingle correct
In which of the following pairs, the outer most electronic configuration will be the same?
  1. (A)Fe2+^{2+}2+ and Co+^{+}+
  2. (B)Cr+^{+}+ and Mn2+^{2+}2+
  3. (C)Ni2+^{2+}2+ and Cu+^{+}+
  4. (D)V2+^{2+}2+ and Cr+^{+}+

Correct answer: (B)

Step-by-step solution →
Q41·ChemistrySingle correct
Which statement is correct?
  1. (A)Buna-S is a synthetic and linear thermosetting polymer
  2. (B)Neoprene is addition copolymer used in plastic bucket manufacturing
  3. (C)Synthesis of Buna-S needs nascent oxygen
  4. (D)Buna-N is a natural polymer

Correct answer: (C)

Step-by-step solution →
Q42·ChemistrySingle correct
Given below are two statements: Statement-I : An allotrope of oxygen is an important intermediate in the formation of reducing smog. Statement-II : Gases such as oxides of nitrogen and sulphur present in troposphere contribute to the formation of photochemical smog. In the light of the above statements, choose the correct answer from the options given below:
  1. (A)Statement I and Statement II are true
  2. (B)Statement I is true about Statement II is false
  3. (C)Both Statement I and Statement II are false
  4. (D)Statement I is false but Statement II is true

Correct answer: (C)

Step-by-step solution →
Q43·ChemistrySingle correct
The plots of radial distribution functions for various orbitals of hydrogen atom against 'r' are given below: The correct plot for 3s orbital is:
  1. (A)D
  2. (B)B
  3. (C)A
  4. (D)C

Correct answer: (A)

Step-by-step solution →
Q44·ChemistrySingle correct
Which of the glycosidic linkage galactose and glucose is present in lactose?
  1. (A)C-1 of glucose and C-6 of galactose
  2. (B)C-1 of galactose and C-4 of glucose
  3. (C)C-1 of glucose and C-4 of galactose
  4. (D)C-1 of galactose and C-6 of glucose

Correct answer: (B)

Step-by-step solution →
Q45·ChemistrySingle correct
Which one of the following reactions will not form acetaldehyde?
  1. (A)CH3_{3}3​CH2_{2}2​OH →CrO3−H2SO4\xrightarrow{\text{CrO}_{3} - \text{H}_{2}\text{SO}_{4}}CrO3​−H2​SO4​​
  2. (B)CH3_{3}3​CN →ii) H2Oi) DIBAL-H\xrightarrow[\text{ii) H}_{2}\text{O}]{\text{i) DIBAL-H}}i) DIBAL-Hii) H2​O​
  3. (C)CH2_{2}2​ = CH2_{2}2​ + O2_{2}2​ →H2OPd(II)/Cu(II)\xrightarrow[\text{H}_{2}\text{O}]{\text{Pd(II)/Cu(II)}}Pd(II)/Cu(II)H2​O​
  4. (D)CH3_{3}3​CH2_{2}2​OH →573 KCu\xrightarrow[\text{573 K}]{\text{Cu}}Cu573 K​

Correct answer: (A)

Step-by-step solution →
Q46·ChemistrySingle correct
Which of the following reaction/s will not give p-aminoazobenzene?
  1. (A)B only
  2. (B)A and B
  3. (C)C only
  4. (D)A only

Correct answer: (A)

Step-by-step solution →
Q47·ChemistrySingle correct
The hybridization and magnetic nature of [Mn(CN)6_{6}6​]4−^{4-}4− and [Fe(CN)6_{6}6​]3−^{3-}3−, respectively are:
  1. (A)d2^{2}2sp3^{3}3 and paramagnetic
  2. (B)sp3^{3}3d2^{2}2 and paramagnetic
  3. (C)d2^{2}2sp3^{3}3 and diamagnetic
  4. (D)sp3^{3}3d2^{2}2 and diamagnetic

Correct answer: (A)

Step-by-step solution →
Q48·ChemistrySingle correct
Identify A and B in the chemical reaction.
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (D)

Step-by-step solution →
Q49·ChemistrySingle correct
Compound(s) which will liberate carbon dioxide with sodium bicarbonate solution is/are:
  1. (A)B and C only
  2. (B)B only
  3. (C)A and B only
  4. (D)C only

Correct answer: (A)

Step-by-step solution →
Q50·ChemistrySingle correct
The solubility of AgCN in a buffer solution of pH = 3 is x. The value of x is: [Assume: No cyano complex is formed; Ksp_{sp}sp​(AgCN) = 2.2 × 10−16^{-16}−16 and Ka_{a}a​ (HCN) = 6.2 × 10−10^{-10}−10]
  1. (A)0.625 × 10−6^{-6}−6
  2. (B)1.6 × 10−6^{-6}−6
  3. (C)2.2 × 10−16^{-16}−16
  4. (D)1.9 × 10−5^{-5}−5

Correct answer: (D)

Step-by-step solution →
Q51·ChemistryNumerical
The reaction of cyanamide, NH2_{2}2​CN(s)_{(s)}(s)​ with oxygen was run in a bomb calorimeter and ΔU was found to be −742.24 kJ mol−1^{-1}−1. The magnitude of ΔH298_{298}298​ for the reaction NH2_{2}2​CN(s)_{(s)}(s)​ + 32\frac{3}{2}23​O2_{2}2​(g) → N2(g)_{2(g)}2(g)​ + O2(g)_{2(g)}2(g)​ + H2_{2}2​O(l)_{(l)}(l)​ is _______ kJ. (Rounded off to the nearest integer) [Assume ideal gases and R = 8.314 J mol−1^{-1}−1 K−1^{-1}−1]

Correct answer: 741

Step-by-step solution →
Q52·ChemistryNumerical
In basic medium CrO42−_{4}^{2-}42−​ oxidizes S2_{2}2​O32−_{3}^{2-}32−​ to form SO42−_{4}^{2-}42−​ and itself changes into Cr(OH)4−_{4}^{-}4−​. The volume of 0.154 M CrO42−_{4}^{2-}42−​ required to react with 40 mL of 0.25 M S2_{2}2​O32−_{3}^{2-}32−​ is _______ mL. (Rounded-off to the nearest integer)

Correct answer: 173

Step-by-step solution →
Q53·ChemistryNumerical
For the reaction, aA + bB → cC + dD, the plot of log k vs 1T\frac{1}{T}T1​ is given below: The temperature at which the rate constant of the reaction is 10−4^{-4}−4s−1^{-1}−1 is _______ K. [Rounded off to the nearest integer) [Given: The rate constant of the reaction is 10−5^{-5}−5 s−1^{-1}−1 at 500 K]

Correct answer: 526

Step-by-step solution →
Q54·ChemistryNumerical
0.4g mixture of NaOH, Na2_{2}2​CO3_{3}3​ and some inert impurities was first titrated with N10\frac{N}{10}10N​ HCl using phenolphthalein as an indicator, 17.5 mL of HCl was required at the end point. After this methyl orange was added and titrated. 1.5 mL of same HCl was required for the next end point. The weight percentage of Na2_{2}2​CO3_{3}3​ in the mixture is _______. (Rounded-off to the nearest integer)

Correct answer: 4

Step-by-step solution →
Q55·ChemistryNumerical
The ionization enthalpy of Na+^{+}+ formation from Na(g)_{(g)}(g)​ is 495.8 kJ mol−1^{-1}−1, while the electron gain enthalpy of Br is −325.0 kJ mol−1^{-1}−1. Given the lattice enthalpy of NaBr is −728.4 kJ mol−1^{-1}−1. The energy for the formation of NaBr ionic solid is (−)_______ × 10−1^{-1}−1 kJ mol−1^{-1}−1.

Correct answer: 5576

Step-by-step solution →
Q56·ChemistryNumerical
Consider the following chemical reaction. HC ≡ CH →(2) CO+HCl/AlCl3(1) Red hot Fe tube, 873 K\xrightarrow[\text{(2) CO+HCl/AlCl}_{3}]{\text{(1) Red hot Fe tube, 873 K}}(1) Red hot Fe tube, 873 K(2) CO+HCl/AlCl3​​ Product The number of sp2^{2}2 hybridized carbon atom(s) present in the product is _______.

Correct answer: 7

Step-by-step solution →
Q57·ChemistryNumerical
A car tyre is filled with nitrogen gas at 35 psi at 27°C. It will burst if pressure exceeds 40 psi. The temperature in °C at which the car tyre will burst is _______. (Rounded-off to the nearest integer)

Correct answer: 70

Step-by-step solution →
Q58·ChemistryNumerical
Among the following, the number of halide(s) which is/are inert to hydrolysis is _______. (A) BF3_{3}3​ (B) SiCl4_{4}4​ (C) PCl5_{5}5​ (D) SF6_{6}6​

Correct answer: 1

Step-by-step solution →
Q59·ChemistryNumerical
1 molal aqueous solution of an electrolyte A2_{2}2​B3_{3}3​ is 60% ionised. The boiling point of the solution at 1 atm is _______ K. (Rounded-off to the nearest integer) [Given Kb_{b}b​ for (H2_{2}2​O) = 0.52 K kg mol−1^{-1}−1]

Correct answer: 375

Step-by-step solution →
Q60·ChemistryNumerical
Using the provided information in the following paper chromatogram: Fig: Paper chromatography for compounds A and B the calculated Rf_{f}f​ value of A _______ × 10−1^{-1}−1.

Correct answer: 4

Step-by-step solution →

Mathematics — JEE Main 25 February 2021 Shift 1

Q61·MathematicsSingle correct
The coefficients a, b and c of the quadratic equation, ax2+bx+c=0ax^{2} + bx + c = 0ax2+bx+c=0 are obtained by throwing a dice three times. The probability that this equation has equal roots is :
  1. (A)154\frac{1}{54}541​
  2. (B)172\frac{1}{72}721​
  3. (C)136\frac{1}{36}361​
  4. (D)5216\frac{5}{216}2165​

Correct answer: (D)

Step-by-step solution →
Q62·MathematicsSingle correct
Let α\alphaα be the angle between the lines whose direction cosines satisfy the equations l+m−n=0l + m - n = 0l+m−n=0 and l2+m2−n2=0l^{2} + m^{2} - n^{2} = 0l2+m2−n2=0. Then the value of sin⁡4α+cos⁡4α\sin^{4}\alpha + \cos^{4}\alphasin4α+cos4α is :
  1. (A)34\frac{3}{4}43​
  2. (B)12\frac{1}{2}21​
  3. (C)58\frac{5}{8}85​
  4. (D)38\frac{3}{8}83​

Correct answer: (C)

Step-by-step solution →
Q63·MathematicsSingle correct
The value of the integral ∫sin⁡θ⋅sin⁡2θ(sin⁡6θ+sin⁡4θ+sin⁡2θ)2sin⁡4θ+3sin⁡2θ+61−cos⁡2θ dθ\int \frac{\sin\theta \cdot \sin 2\theta (\sin^{6}\theta + \sin^{4}\theta + \sin^{2}\theta)\sqrt{2\sin^{4}\theta + 3\sin^{2}\theta + 6}}{1 - \cos 2\theta}\, d\theta∫1−cos2θsinθ⋅sin2θ(sin6θ+sin4θ+sin2θ)2sin4θ+3sin2θ+6​​dθ is (where c is a constant of integration)
  1. (A)118[9−2sin⁡6θ−3sin⁡4θ−6sin⁡2θ]32+c\frac{1}{18}\left[9 - 2\sin^{6}\theta - 3\sin^{4}\theta - 6\sin^{2}\theta\right]^{\frac{3}{2}} + c181​[9−2sin6θ−3sin4θ−6sin2θ]23​+c
  2. (B)118[11−18sin⁡2θ+9sin⁡4θ−2sin⁡6θ]32+c\frac{1}{18}\left[11 - 18\sin^{2}\theta + 9\sin^{4}\theta - 2\sin^{6}\theta\right]^{\frac{3}{2}} + c181​[11−18sin2θ+9sin4θ−2sin6θ]23​+c
  3. (C)118[11−18cos⁡2θ+9cos⁡4θ−2cos⁡6θ]32+c\frac{1}{18}\left[11 - 18\cos^{2}\theta + 9\cos^{4}\theta - 2\cos^{6}\theta\right]^{\frac{3}{2}} + c181​[11−18cos2θ+9cos4θ−2cos6θ]23​+c
  4. (D)118[9−2cos⁡6θ−3cos⁡4θ−6cos⁡2θ]32+c\frac{1}{18}\left[9 - 2\cos^{6}\theta - 3\cos^{4}\theta - 6\cos^{2}\theta\right]^{\frac{3}{2}} + c181​[9−2cos6θ−3cos4θ−6cos2θ]23​+c

Correct answer: (C)

Step-by-step solution →
Q64·MathematicsSingle correct
A man is observing, from the top of a tower, a boat speeding towards the tower from a certain point A, with uniform speed. At that point, angle of depression of the boat with the man's eye is 30∘30^{\circ}30∘ (Ignore man's height). After sailing for 20 seconds towards the base of the tower (which is at the level of water), the boat has reached a point B, where the angle of depression is 45∘45^{\circ}45∘. Then the time taken (in seconds) by the boat from B to reach the base of the tower is :
  1. (A)10(3−1)10(\sqrt{3} - 1)10(3​−1)
  2. (B)10310\sqrt{3}103​
  3. (C)101010
  4. (D)10(3+1)10(\sqrt{3} + 1)10(3​+1)

Correct answer: (D)

Step-by-step solution →
Q65·MathematicsSingle correct
If 0<θ,ϕ<π20 < \theta, \phi < \frac{\pi}{2}0<θ,ϕ<2π​, x=∑n=0∞cos⁡2nθx = \sum_{n=0}^{\infty} \cos^{2n}\thetax=∑n=0∞​cos2nθ, y=∑n=0∞sin⁡2nϕy = \sum_{n=0}^{\infty} \sin^{2n}\phiy=∑n=0∞​sin2nϕ and z=∑n=0∞cos⁡2nθ⋅sin⁡2nϕz = \sum_{n=0}^{\infty} \cos^{2n}\theta \cdot \sin^{2n}\phiz=∑n=0∞​cos2nθ⋅sin2nϕ then :
  1. (A)xyz=4xyz = 4xyz=4
  2. (B)xy−z=(x+y)zxy - z = (x + y)zxy−z=(x+y)z
  3. (C)xy+yz+zx=zxy + yz + zx = zxy+yz+zx=z
  4. (D)xy+z=(x+y)zxy + z = (x + y)zxy+z=(x+y)z

Correct answer: (D)

Step-by-step solution →
Q66·MathematicsSingle correct
The equation of the line through the point (0, 1, 2) and perpendicular to the line x−12=y+13=z−1−2\frac{x-1}{2} = \frac{y+1}{3} = \frac{z-1}{-2}2x−1​=3y+1​=−2z−1​ is :
  1. (A)x−3=y−14=z−23\frac{x}{-3} = \frac{y-1}{4} = \frac{z-2}{3}−3x​=4y−1​=3z−2​
  2. (B)x3=y−14=z−23\frac{x}{3} = \frac{y-1}{4} = \frac{z-2}{3}3x​=4y−1​=3z−2​
  3. (C)x3=y−1−4=z−23\frac{x}{3} = \frac{y-1}{-4} = \frac{z-2}{3}3x​=−4y−1​=3z−2​
  4. (D)x3=y−14=z−2−3\frac{x}{3} = \frac{y-1}{4} = \frac{z-2}{-3}3x​=4y−1​=−3z−2​

Correct answer: (A)

Step-by-step solution →
Q67·MathematicsSingle correct
The statement A→(B→A)A \rightarrow (B \rightarrow A)A→(B→A) is equivalent to:
  1. (A)A→(A∧B)A \rightarrow (A \wedge B)A→(A∧B)
  2. (B)A→(A∨B)A \rightarrow (A \vee B)A→(A∨B)
  3. (C)A→(A→B)A \rightarrow (A \rightarrow B)A→(A→B)
  4. (D)A→(A↔B)A \rightarrow (A \leftrightarrow B)A→(A↔B)

Correct answer: (B)

Step-by-step solution →
Q68·MathematicsSingle correct
The integer 'k', for which the inequality x2−2(3k−1)x+8k2−7>0x^{2} - 2(3k - 1)x + 8k^{2} - 7 > 0x2−2(3k−1)x+8k2−7>0 is valid for every x in R is :
  1. (A)333
  2. (B)222
  3. (C)444
  4. (D)000

Correct answer: (A)

Step-by-step solution →
Q69·MathematicsSingle correct
A tangent is drawn to the parabola y2=6xy^{2} = 6xy2=6x which is perpendicular to the line 2x+y=12x + y = 12x+y=1. Which of the following points does NOT lie on it ?
  1. (A)(0,3)(0, 3)(0,3)
  2. (B)(−6,0)(-6, 0)(−6,0)
  3. (C)(4,5)(4, 5)(4,5)
  4. (D)(5,4)(5, 4)(5,4)

Correct answer: (D)

Step-by-step solution →
Q70·MathematicsSingle correct
Let f, g: N→NN \rightarrow NN→N such that f(n+1)=f(n)+f(1)f(n + 1) = f(n) + f(1)f(n+1)=f(n)+f(1) ∀n∈N\forall n \in N∀n∈N and g be any arbitrary function. Which of the following statements is NOT true ?
  1. (A)f is one-one
  2. (B)If fog is one-one, then g is one-one
  3. (C)If g is onto, then fog is one-one
  4. (D)If f is onto, then f(n)=n ∀n∈Nf(n) = n\ \forall n \in Nf(n)=n ∀n∈N

Correct answer: (C)

Step-by-step solution →
Q71·MathematicsSingle correct
Let the lines (2−i)z=(2+i)zˉ(2 - i)z = (2 + i)\bar{z}(2−i)z=(2+i)zˉ and (2+i)z+(i−2)zˉ−4i=0(2 + i)z + (i - 2)\bar{z} - 4i = 0(2+i)z+(i−2)zˉ−4i=0, (here i2=−1i^{2} = -1i2=−1) be normal to a circle C. If the line iz+zˉ+1+i=0iz + \bar{z} + 1 + i = 0iz+zˉ+1+i=0 is tangent to this circle C, then its radius is :
  1. (A)32\frac{3}{\sqrt{2}}2​3​
  2. (B)323\sqrt{2}32​
  3. (C)322\frac{3}{2\sqrt{2}}22​3​
  4. (D)122\frac{1}{2\sqrt{2}}22​1​

Correct answer: (C)

Step-by-step solution →
Q72·MathematicsSingle correct
All possible values of θ∈[0,2π]\theta \in [0, 2\pi]θ∈[0,2π] for which sin⁡2θ+tan⁡2θ>0\sin 2\theta + \tan 2\theta > 0sin2θ+tan2θ>0 lie in:
  1. (A)(0,π2)∪(π,3π2)\left(0, \frac{\pi}{2}\right) \cup \left(\pi, \frac{3\pi}{2}\right)(0,2π​)∪(π,23π​)
  2. (B)(0,π4)∪(π2,3π4)∪(π,5π4)∪(3π2,7π4)\left(0, \frac{\pi}{4}\right) \cup \left(\frac{\pi}{2}, \frac{3\pi}{4}\right) \cup \left(\pi, \frac{5\pi}{4}\right) \cup \left(\frac{3\pi}{2}, \frac{7\pi}{4}\right)(0,4π​)∪(2π​,43π​)∪(π,45π​)∪(23π​,47π​)
  3. (C)(0,π2)∪(π2,3π4)∪(π,7π6)\left(0, \frac{\pi}{2}\right) \cup \left(\frac{\pi}{2}, \frac{3\pi}{4}\right) \cup \left(\pi, \frac{7\pi}{6}\right)(0,2π​)∪(2π​,43π​)∪(π,67π​)
  4. (D)(0,π4)∪(π2,3π4)∪(3π2,11π6)\left(0, \frac{\pi}{4}\right) \cup \left(\frac{\pi}{2}, \frac{3\pi}{4}\right) \cup \left(\frac{3\pi}{2}, \frac{11\pi}{6}\right)(0,4π​)∪(2π​,43π​)∪(23π​,611π​)

Correct answer: (B)

Step-by-step solution →
Q73·MathematicsSingle correct
The image of the point (3,5) in the line x−y+1=0x - y + 1 = 0x−y+1=0, lies on :
  1. (A)(x−2)2+(y−4)2=4(x - 2)^{2} + (y - 4)^{2} = 4(x−2)2+(y−4)2=4
  2. (B)(x−4)2+(y+2)2=16(x - 4)^{2} + (y + 2)^{2} = 16(x−4)2+(y+2)2=16
  3. (C)(x−4)2+(y−4)2=8(x - 4)^{2} + (y - 4)^{2} = 8(x−4)2+(y−4)2=8
  4. (D)(x−2)2+(y−2)2=12(x - 2)^{2} + (y - 2)^{2} = 12(x−2)2+(y−2)2=12

Correct answer: (A)

Step-by-step solution →
Q74·Mathematics·Application of DerivativesSingle correct
If Rolle's theorem holds for the function f(x)=x3−ax2+bx−4f(x) = x^{3} - ax^{2} + bx - 4f(x)=x3−ax2+bx−4, x∈[1,2]x \in [1, 2]x∈[1,2] with f′(43)=0f'\left(\frac{4}{3}\right) = 0f′(34​)=0, then ordered pair (a, b) is equal to :
  1. (A)(−5,8)(-5, 8)(−5,8)
  2. (B)(5,8)(5, 8)(5,8)
  3. (C)(5,−8)(5, -8)(5,−8)
  4. (D)(−5,−8)(-5, -8)(−5,−8)

Correct answer: (B)

Step-by-step solution →
Q75·MathematicsSingle correct
If the curves, x2a+y2b=1\frac{x^{2}}{a} + \frac{y^{2}}{b} = 1ax2​+by2​=1 and x2c+y2d=1\frac{x^{2}}{c} + \frac{y^{2}}{d} = 1cx2​+dy2​=1 intersect each other at an angle of 90∘90^{\circ}90∘, then which of the following relations is true ?
  1. (A)a+b=c+da + b = c + da+b=c+d
  2. (B)a−b=c−da - b = c - da−b=c−d
  3. (C)ab=c+da+bab = \frac{c+d}{a+b}ab=a+bc+d​
  4. (D)a−c=b+da - c = b + da−c=b+d

Correct answer: (B)

Step-by-step solution →
Q76·Mathematics·Limits and ContinuitySingle correct
lim⁡n→∞(1+1+12+⋯+1nn2)n\lim\limits_{n \to \infty} \left( 1 + \dfrac{1 + \frac{1}{2} + \dots + \frac{1}{n}}{n^2} \right)^{n}n→∞lim​(1+n21+21​+⋯+n1​​)n is equal to :
  1. (A)12\frac{1}{2}21​
  2. (B)1e\frac{1}{e}e1​
  3. (C)111
  4. (D)000

Correct answer: (C)

Step-by-step solution →
Q77·MathematicsSingle correct
The total number of positive integral solutions (x, y, z) such that xyz=24xyz = 24xyz=24 is
  1. (A)363636
  2. (B)454545
  3. (C)242424
  4. (D)303030

Correct answer: (D)

Step-by-step solution →
Q78·MathematicsSingle correct
If a curve passes through the origin and the slope of the tangent to it at any point (x,y)(x, y)(x,y) is x2−4x+y+8x−2\dfrac{x^2 - 4x + y + 8}{x - 2}x−2x2−4x+y+8​, then this curve also passes through the point :
  1. (A)(4,5)(4, 5)(4,5)
  2. (B)(5,4)(5, 4)(5,4)
  3. (C)(4,4)(4, 4)(4,4)
  4. (D)(5,5)(5, 5)(5,5)

Correct answer: (D)

Step-by-step solution →
Q79·MathematicsSingle correct
The value of ∫−11x2e[x3]dx\int\limits_{-1}^{1} x^2 e^{[x^3]} dx−1∫1​x2e[x3]dx, where [t][t][t] denotes the greatest integer ≤t\le t≤t, is :
  1. (A)e+13\frac{e+1}{3}3e+1​
  2. (B)e−13e\frac{e-1}{3e}3ee−1​
  3. (C)e+13e\frac{e+1}{3e}3ee+1​
  4. (D)13e\frac{1}{3e}3e1​

Correct answer: (C)

Step-by-step solution →
Q80·MathematicsSingle correct
When a missile is fired from a ship, the probability that it is intercepted is 13\frac{1}{3}31​ and the probability that the missile hits the target, given that it is not intercepted, is 34\frac{3}{4}43​. If three missiles are fired independently from the ship, then the probability that all three hit the target, is:
  1. (A)18\frac{1}{8}81​
  2. (B)127\frac{1}{27}271​
  3. (C)34\frac{3}{4}43​
  4. (D)38\frac{3}{8}83​

Correct answer: (A)

Step-by-step solution →
Q81·MathematicsNumerical
Let A1,A2,A3,…A_1, A_2, A_3, \dotsA1​,A2​,A3​,… be squares such that for each n≥1n \ge 1n≥1, the length of the side of AnA_nAn​ equals the length of diagonal of An+1A_{n+1}An+1​. If the length of A1A_1A1​ is 12 cm, then the smallest value of nnn for which area of AnA_nAn​ is less than one, is __________.

Correct answer: 9

Step-by-step solution →
Q82·MathematicsNumerical
The graphs of sine and cosine functions, intersect each other at a number of points and between two consecutive points of intersection, the two graphs enclose the same area A. Then A4A^4A4 is equal to __________

Correct answer: 64

Step-by-step solution →
Q83·MathematicsNumerical
The locus of the point of intersection of the lines (3)kx+ky−43=0(\sqrt{3})kx + ky - 4\sqrt{3} = 0(3​)kx+ky−43​=0 and 3x−y−4(3)k=0\sqrt{3}x - y - 4(\sqrt{3})k = 03​x−y−4(3​)k=0 is a conic, whose eccentricity is __________.

Correct answer: 2

Step-by-step solution →
Q84·MathematicsNumerical
If A=[0−tan⁡(θ2)tan⁡(θ2)0]A = \begin{bmatrix} 0 & -\tan\left(\frac{\theta}{2}\right) \\ \tan\left(\frac{\theta}{2}\right) & 0 \end{bmatrix}A=[0tan(2θ​)​−tan(2θ​)0​] and (I2+A)(I2−A)−1=[a−bba](I_2 + A)(I_2 - A)^{-1} = \begin{bmatrix} a & -b \\ b & a \end{bmatrix}(I2​+A)(I2​−A)−1=[ab​−ba​], then 13(a2+b2)13(a^2 + b^2)13(a2+b2) is equal to _______.

Correct answer: 13

Step-by-step solution →
Q85·MathematicsNumerical
Let f(x)f(x)f(x) be a polynomial of degree 6 in xxx, in which the coefficient of x6x^6x6 is unity and it has extrema at x=−1x = -1x=−1 and x=1x = 1x=1. If lim⁡x→0f(x)x3=1\lim\limits_{x \to 0} \dfrac{f(x)}{x^3} = 1x→0lim​x3f(x)​=1, then 5⋅f(2)5 \cdot f(2)5⋅f(2) is equal to __________

Correct answer: 144

Step-by-step solution →
Q86·Mathematics·DifferentiabilityNumerical
The number of points, at which the function f(x)=∣2x+1∣−3∣x+2∣+∣x2+x−2∣f(x) = |2x + 1| - 3|x + 2| + |x^2 + x - 2|f(x)=∣2x+1∣−3∣x+2∣+∣x2+x−2∣, x∈Rx \in Rx∈R is not differentiable, is __________.

Correct answer: 2

Step-by-step solution →
Q87·MathematicsNumerical
If the system of equations kx+y+2z=1kx + y + 2z = 1kx+y+2z=1 3x−y−2z=23x - y - 2z = 23x−y−2z=2 −2x−2y−4z=3-2x - 2y - 4z = 3−2x−2y−4z=3 has infinitely many solutions, then kkk is equal to ___________.

Correct answer: 21

Step-by-step solution →
Q88·MathematicsNumerical
Let a⃗=i^+2j^−k^\vec{a} = \hat{i} + 2\hat{j} - \hat{k}a=i^+2j^​−k^, b⃗=i^−j^\vec{b} = \hat{i} - \hat{j}b=i^−j^​ and c⃗=i^−j^−k^\vec{c} = \hat{i} - \hat{j} - \hat{k}c=i^−j^​−k^ be three given vectors. If r⃗\vec{r}r is a vector such that r⃗×a⃗=c⃗×a⃗\vec{r} \times \vec{a} = \vec{c} \times \vec{a}r×a=c×a and r⃗⋅b⃗=0\vec{r} \cdot \vec{b} = 0r⋅b=0, then r⃗⋅a⃗\vec{r} \cdot \vec{a}r⋅a is equal to ________

Correct answer: 12

Step-by-step solution →
Q89·MathematicsNumerical
Let A=[xyzyzxzxy]A = \begin{bmatrix} x & y & z \\ y & z & x \\ z & x & y \end{bmatrix}A=​xyz​yzx​zxy​​, where xxx, yyy and zzz are real numbers such that x+y+z>0x + y + z > 0x+y+z>0 and xyz=2xyz = 2xyz=2. If A2=I3A^2 = I_3A2=I3​, then the value of x3+y3+z3x^3 + y^3 + z^3x3+y3+z3 is ________.

Correct answer: 7

Step-by-step solution →
Q90·MathematicsNumerical
The total number of numbers, lying between 100 and 1000 that can be formed with the digits 1, 2, 3, 4, 5, if the repetition of digits is not allowed and numbers are divisible by either 3 or 5 is _________.

Correct answer: 32

Step-by-step solution →

Chapters tested in this paper

Open any chapter to practise every past-year question on that topic across all papers, and see how often it has actually appeared.

  • Properties of Solids and Liquids 172/186
  • Three Dimensional Geometry 176/186
  • Matrices and Determinants 180/186
  • Coordination Compounds 176/186
  • Sets, Relations and Functions 165/186
  • Current Electricity 160/186
  • Sequence and Series 164/186
  • p-Block Elements 164/186
  • Definite Integration 168/186
  • Redox Reactions and Electrochemistry 177/186
  • Geometrical Optics 172/186
  • Kinematics 156/186
  • Vector Algebra 173/186
  • Differential Equations 167/186
  • Probability 176/186
  • Permutations and Combinations 162/186
  • Magnetic Field of Current 147/186
  • Electromagnetic Waves 144/186
  • Chemical Bonding and Molecular Structure 151/186
  • Application of Derivatives 139/186
  • Limits and Continuity 149/186
  • d- and f-Block Elements 126/186
  • Thermodynamics 154/186
  • Aldehydes and Ketones 135/186
  • Equilibrium 163/186
  • Solutions 158/186
  • Laws of Motion 130/186
  • Chemical Thermodynamics 165/186
  • Units and Measurements 149/186
  • Hydrocarbons 126/186
  • Complex Numbers 165/186
  • Trigonometric Functions 144/186
  • Biomolecules 162/186
  • Chemical Kinetics 169/186
  • Gravitation 152/186
  • Electric Field and Coulomb's Law 133/186
  • Atomic Structure 161/186
  • Electronic Devices 145/186
  • Dual Nature of Matter and Radiation 155/186
  • Amines 133/186
  • Quadratic Equations 148/186
  • Work, Energy and Power 132/186
  • Some Basic Concepts in Chemistry 129/186
  • Electromagnetic Induction 120/186
  • Wave Optics 130/186
  • Area Under Curves 139/186
  • Kinetic Theory of Gases 135/186
  • Alcohols and Ethers 106/186
  • Purification and Characterisation of Organic Compounds 116/186
  • Oscillations 117/186
  • Alternating Currents 108/186
  • Nuclei 116/186
  • Organic Compounds Containing Halogens 109/186
  • Straight Lines 114/186
  • Waves 109/186
  • Parabola 101/186
  • Isolation of Metals 106/186
  • Differentiability 91/186
  • Surface Chemistry 98/186
  • Environmental Chemistry 83/186
  • Hydrogen 81/186
  • Hyperbola 77/186
  • Experimental Skills 68/186
  • Electric Potential 63/186
  • Indefinite Integration 66/186
  • Polymers 64/186
  • States of Matter: Gases and Liquids 52/186
← 24 Feb Shift 2 2021All papers25 Feb Shift 2 2021 →

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