Jarvis OS
PYQ papersPricingSign inGet started
  1. Home
  2. /JEE Main PYQs
  3. /2021
  4. /27 Aug Shift 2

JEE Main 27 August 2021 Shift 2 Question Paper with Answers

27 August 2021 · August session · 88 questions

88 of the 90 questions from the JEE Main 27 August 2021 Shift 2 paper, each with its correct answer and tagged to the chapter it tests. Free to read, no account needed.

2 questions are held back from this paper while we re-check the transcription or the answer key. We would rather show you nothing than show you an answer we are not confident is right.

Physics
30
Chemistry
29
Mathematics
29

Physics — JEE Main 27 August 2021 Shift 2

Q1·PhysicsSingle correct
Curved surfaces of a plano-convex lens of refractive index μ1\mu_{1}μ1​ and a plano-concave lens of refractive index μ2\mu_{2}μ2​ have equal radius of curvature as shown in figure. Find the ratio of radius of curvature to the focal length of the combined lenses.
  1. (A)1μ2−μ1\frac{1}{\mu_{2}-\mu_{1}}μ2​−μ1​1​
  2. (B)μ1−μ2\mu_{1}-\mu_{2}μ1​−μ2​
  3. (C)1μ1−μ2\frac{1}{\mu_{1}-\mu_{2}}μ1​−μ2​1​
  4. (D)μ2−μ1\mu_{2}-\mu_{1}μ2​−μ1​

Correct answer: (B)

Step-by-step solution →
Q2·PhysicsSingle correct
The boxes of masses 2 kg and 8 kg are connected by a massless string passing over smooth pulleys. Calculate the time taken by box of mass 8 kg to strike the ground starting from rest. (use g = 10 m/s2^{2}2)
  1. (A)0.34 s
  2. (B)0.2 s
  3. (C)0.25 s
  4. (D)0.4 s

Correct answer: (D)

Step-by-step solution →
Q3·PhysicsSingle correct
For a transistor α and β are given as α=ICIE\alpha = \frac{I_{C}}{I_{E}}α=IE​IC​​ and β=ICIB\beta = \frac{I_{C}}{I_{B}}β=IB​IC​​. Then the correct relation between α and β will be :
  1. (A)α=1−ββ\alpha = \frac{1-\beta}{\beta}α=β1−β​
  2. (B)β=α1−α\beta = \frac{\alpha}{1-\alpha}β=1−αα​
  3. (C)αβ=1\alpha\beta = 1αβ=1
  4. (D)α=β1−β\alpha = \frac{\beta}{1-\beta}α=1−ββ​

Correct answer: (B)

Step-by-step solution →
Q4·PhysicsSingle correct
Water drops are falling from a nozzle of a shower onto the floor, from a height of 9.8 m. The drops fall at a regular interval of time. When the first drop strikes the floor, at that instant, the third drop begins to fall. Locate the position of second drop from the floor when the first drop strikes the floor.
  1. (A)4.18 m
  2. (B)2.94 m
  3. (C)2.45 m
  4. (D)7.35 m

Correct answer: (D)

Step-by-step solution →
Q5·PhysicsSingle correct
Two discs have moments of intertia I1I_{1}I1​ and I2I_{2}I2​ about their respective axes perpendicular to the plane and passing through the centre. They are rotating with angular speeds, ω1\omega_{1}ω1​ and ω2\omega_{2}ω2​ respectively and are brought into contact face to face with their axes of rotation coaxial. The loss in kinetic energy of the system in the process is given by :
  1. (A)I1I2(I1+I2)(ω1−ω2)2\frac{I_{1}I_{2}}{(I_{1}+I_{2})}\left(\omega_{1}-\omega_{2}\right)^{2}(I1​+I2​)I1​I2​​(ω1​−ω2​)2
  2. (B)(I1−I2)2 ω1ω22(I1+I2)\frac{(I_{1}-I_{2})^{2}\,\omega_{1}\omega_{2}}{2(I_{1}+I_{2})}2(I1​+I2​)(I1​−I2​)2ω1​ω2​​
  3. (C)I1I22(I1+I2)(ω1−ω2)2\frac{I_{1}I_{2}}{2(I_{1}+I_{2})}\left(\omega_{1}-\omega_{2}\right)^{2}2(I1​+I2​)I1​I2​​(ω1​−ω2​)2
  4. (D)(ω1−ω2)22(I1+I2)\frac{(\omega_{1}-\omega_{2})^{2}}{2(I_{1}+I_{2})}2(I1​+I2​)(ω1​−ω2​)2​

Correct answer: (C)

Step-by-step solution →
Q6·PhysicsSingle correct
Three capacitors C1C_{1}C1​ = 2μF, C2C_{2}C2​ = 6 μF and C3C_{3}C3​ = 12 μF are connected as shown in figure. Find the ratio of the charges on capacitors C1C_{1}C1​, C2C_{2}C2​ and C3C_{3}C3​ respectively :
  1. (A)2 : 1 : 1
  2. (B)2 : 3 : 3
  3. (C)1 : 2 : 2
  4. (D)3 : 4 : 4

Correct answer: (C)

Step-by-step solution →
Q7·PhysicsSingle correct
The colour coding on a carbon resistor is shown in the given figure. The resistance value of the given resistor is :
  1. (A)(5700 ± 285) Ω
  2. (B)(7500 ± 750) Ω
  3. (C)(5700 ± 375) Ω
  4. (D)(7500 ± 375) Ω

Correct answer: (D)

Step-by-step solution →
Q8·PhysicsSingle correct
An antenna is mounted on a 400 m tall building. What will be the wavelength of signal of signal that can be radiated effectively by the transmission tower upto a range of 44 km?
  1. (A)37.8 m
  2. (B)605 m
  3. (C)75.6 m
  4. (D)302 m

Correct answer: (B)

Step-by-step solution →
Q9·PhysicsSingle correct
If the rms speed of oxygen molecules at 0°C is 160 m/s, find the rms speed of hydrogen molecules at 0°C.
  1. (A)640 m/s
  2. (B)40 m/s
  3. (C)80 m/s
  4. (D)332 m/s

Correct answer: (A)

Step-by-step solution →
Q10·PhysicsSingle correct
A constant magnetic field of 1 T is applied in the x > 0 region. A metallic circular ring of radius 1m is moving with a constant velocity of 1 m/s along the x-axis. At t = 0s, the centre of O of the ring is at x = − 1m. What will be the value of the induced emf in the ring at t = 1s? (Assume the velocity of the ring does not change.)
  1. (A)1 V
  2. (B)2π V
  3. (C)2 V
  4. (D)0 V

Correct answer: (C)

Step-by-step solution →
Q11·PhysicsSingle correct
A mass of 50 kg is placed at the centre of a uniform spherical shell of mass 100 kg and radius 50 m. If the gravitational potential at a point, 25 m from the centre is V kg/m. The value of V is :
  1. (A)− 60 G
  2. (B)+ 2 G
  3. (C)− 20 G
  4. (D)− 4 G

Correct answer: (D)

Step-by-step solution →
Q12·PhysicsSingle correct
For full scale deflection of total 50 divisions, 50 mV voltage is required in galvanometer. The resistance of galvanometer if its current sensitivity is 2 div/mA will be :
  1. (A)1 Ω
  2. (B)5 Ω
  3. (C)4 Ω
  4. (D)2 Ω

Correct answer: (D)

Step-by-step solution →
Q13·PhysicsSingle correct
A monochromatic neon lamp with wavelength of 670.5 nm illuminates a photo-sensitive material which has a stopping voltage of 0.48 V. What will be the stopping voltage if the source light is changed with another source of wavelength of 474.6 nm?
  1. (A)0.96 V
  2. (B)1.25 V
  3. (C)0.24 V
  4. (D)1.5 V

Correct answer: (B)

Step-by-step solution →
Q14·PhysicsSingle correct
Match List-I (physical quantity) with List-II (SI unit). Choose the most appropriate answer from the options given below :
List-IList-II
a.RHR_{H}RH​ (Rydberg constant)i.kg m−1^{-1}−1 s−1^{-1}−1
b.h (Planck's constant)ii.kg m2^{2}2 s−1^{-1}−1
c.μB\mu_{B}μB​ (Magnetic field energy density)iii.m−1^{-1}−1
d.η (coefficient of viscocity)iv.kg m−1^{-1}−1 s−2^{-2}−2
  1. (A)(a)–(ii), (b)–(iii), (c)–(iv), (d)–(i)
  2. (B)(a)–(iii), (b)–(ii), (c)–(iv), (d)–(i)
  3. (C)(a)–(iv), (b)–(ii), (c)–(i), (d)–(iii)
  4. (D)(a)–(iii), (b)–(ii), (c)–(i), (d)–(iv)

Correct answer: (B)

Step-by-step solution →
Q15·PhysicsSingle correct
If force (F), length (L) and time (T) are taken as the fundamental quantities. Then what will be the dimension of density :
  1. (A)[FL−4^{-4}−4 T2^{2}2]
  2. (B)[FL−3^{-3}−3 T2^{2}2]
  3. (C)[FL−5^{-5}−5 T2^{2}2]
  4. (D)[FL−3^{-3}−3 T3^{3}3]

Correct answer: (A)

Step-by-step solution →
Q16·PhysicsSingle correct
A coaxial cable consists of an inner wire of radius 'a' surrounded by an outer shell of inner and outer radii 'b' and 'c' respectively. The inner wire carries an electric current i0i_{0}i0​, which is distributed uniformly across cross-sectional area. The outer shell carries an equal current in opposite direction and distributed uniformly. What will be the ratio of the magnetic field at a distance x from the axis when (i) x < a and (ii) a < x < b ?
  1. (A)x2a2\frac{x^{2}}{a^{2}}a2x2​
  2. (B)a2x2\frac{a^{2}}{x^{2}}x2a2​
  3. (C)x2b2−a2\frac{x^{2}}{b^{2}-a^{2}}b2−a2x2​
  4. (D)b2−a2x2\frac{b^{2}-a^{2}}{x^{2}}x2b2−a2​

Correct answer: (A)

Step-by-step solution →
Q17·PhysicsSingle correct
The height of victoria falls is 63 m. What is the difference in temperature of water at the top and at the bottom of fall ? [Given 1 cal = 4.2 J and specific heat of water = 1 cal g−1^{-1}−1 °C−1^{-1}−1]
  1. (A)0.147° C
  2. (B)14.76° C
  3. (C)1.476°
  4. (D)0.014° C

Correct answer: (A)

Step-by-step solution →
Q18·PhysicsSingle correct
A player kicks a football with an initial speed of 25 ms−1^{-1}−1 at an angle of 45° from the ground. What are the maximum height and the time taken by the football to reach at the highest point during motion ? (Take g = 10 ms−2^{-2}−2)
  1. (A)hmax_{max}max​ = 10 m, T = 2.5 s
  2. (B)hmax_{max}max​ = 15.625 m, T = 3.54 s
  3. (C)hmax_{max}max​ = 15.625 m, T = 1.77 s
  4. (D)hmax_{max}max​ = 3.54 m, T = 0.125 s

Correct answer: (C)

Step-by-step solution →
Q19·PhysicsSingle correct
The light waves from two coherent sources have same intensity I1I_{1}I1​ = I2I_{2}I2​ = I0I_{0}I0​. In interference pattern the intensity of light at minima is zero. What will be the intensity of light at maxima ?
  1. (A)I0I_{0}I0​
  2. (B)2 I0I_{0}I0​
  3. (C)5 I0I_{0}I0​
  4. (D)4 I0I_{0}I0​

Correct answer: (D)

Step-by-step solution →
Q20·PhysicsSingle correct
Figure shows a rod AB, which is bent in a 120° circular arc of radius R. A charge (−Q) is uniformly distributed over rod AB. What is the electric field E⃗\vec{E}E at the centre of curvature O ?
  1. (A)33 Q8πε0R2(i^)\frac{3\sqrt{3}\,Q}{8\pi\varepsilon_{0}R^{2}}(\hat{i})8πε0​R233​Q​(i^)
  2. (B)33 Q8π2ε0R2(i^)\frac{3\sqrt{3}\,Q}{8\pi^{2}\varepsilon_{0}R^{2}}(\hat{i})8π2ε0​R233​Q​(i^)
  3. (C)33 Q16π2ε0R2(i^)\frac{3\sqrt{3}\,Q}{16\pi^{2}\varepsilon_{0}R^{2}}(\hat{i})16π2ε0​R233​Q​(i^)
  4. (D)33 Q8π2ε0R2(−i^)\frac{3\sqrt{3}\,Q}{8\pi^{2}\varepsilon_{0}R^{2}}(-\hat{i})8π2ε0​R233​Q​(−i^)

Correct answer: (B)

Step-by-step solution →
Q21·PhysicsNumerical
A heat engine operates between a cold reservoir at temperature T2T_2T2​ = 400 K and a hot reservoir at temperature T1T_1T1​. It takes 300 J of heat from the hot reservoir and delivers 240 J of heat to the cold reservoir in a cycle. The minimum temperature of the hot reservoir has to be __________ K.

Correct answer: 500

Step-by-step solution →
Q22·PhysicsNumerical
Two simple harmonic motion, are represented by the equations y1=10sin⁡(3πt+π3)y_1 = 10 \sin\left(3\pi t + \frac{\pi}{3}\right)y1​=10sin(3πt+3π​) y2=5(sin⁡3πt+3cos⁡3πt)y_2 = 5(\sin 3\pi t + \sqrt{3}\cos 3\pi t)y2​=5(sin3πt+3​cos3πt) Ratio of amplitude of y1y_1y1​ to y2y_2y2​ = x : 1. The value of x is _________ .

Correct answer: 1

Step-by-step solution →
Q23·PhysicsNumerical
X different wavelengths may be observed in the spectrum from a hydrogen sample if the atoms are exited to states with principal quantum number n = 6 ? The value of X is ________ .

Correct answer: 15

Step-by-step solution →
Q24·PhysicsNumerical
A zener diode of power rating 2W is to be used as a voltage regulator. If the zener diode has a breakdown of 10 V and it has to regulate voltage fluctuated between 6 V and 14 V, the value of RsR_sRs​ for safe operation should be ________ Ω.

Correct answer: 20

Step-by-step solution →
Q25·PhysicsNumerical
Wires W1W_1W1​ and W2W_2W2​ are made of same material having the breaking stress of 1.25 × 109^{9}9 N/m2^{2}2. W1W_1W1​ and W2W_2W2​ have cross-sectional area of 8 × 10−7^{-7}−7 m2^{2}2 and 4 × 10−7^{-7}−7 m2^{2}2, respectively. Masses of 20 kg and 10 kg hang from them as shown in the figure. The maximum mass that can be placed in the pan without breaking the wires is _____ kg. (Use g = 10 m/s2^{2}2)

Correct answer: 40

Step-by-step solution →
Q26·PhysicsNumerical
A bullet of 10 g, moving with velocity v, collides head-on with the stationary bob of a pendulum and recoils with velocity 100 m/s. The length of the pendulum is 0.5 m and mass of the bob is 1 kg. The minimum value of v = _____ m/s so that the pendulum describes a circle. (Assume the string to be inextensible and g = 10 m/s2^{2}2)

Correct answer: 400

Step-by-step solution →
Q27·PhysicsNumerical
An ac circuit has an inductor and a resistor of resistance R in series, such that XLX_LXL​ = 3R. Now, a capacitor is added in series such that XCX_CXC​ = 2R. The ratio of new power factor with the old power factor of the circuit is 5\sqrt{5}5​ : x . The value of x is _____ .

Correct answer: 1

Step-by-step solution →
Q28·PhysicsNumerical
The ratio of the equivalent resistance of the network (shown in figure) between the points a and b when switch is open and switch is closed is x : 8. The value of x is ________ .

Correct answer: 9

Step-by-step solution →
Q29·PhysicsNumerical
A plane electromagnetic wave with frequency of 30 MHz travels in free space. At particular point in space and time, electric field is 6 V/m. The magnetic field at this point will be x × 10−8^{-8}−8 T. The value of x is _____ .

Correct answer: 2

Step-by-step solution →
Q30·PhysicsNumerical
A tuning fork is vibrating at 250 Hz. The length of the shortest closed organ pipe that will resonate with the tuning fork will be _____ cm. (Take speed of sound in air as 340 ms−1^{-1}−1)

Correct answer: 34

Step-by-step solution →

Chemistry — JEE Main 27 August 2021 Shift 2

Q31·ChemistrySingle correct
Choose the correct statement from the following :
  1. (A)The standard enthalpy of formation for alkali metal bromides becomes less negative on descending the group.
  2. (B)The low solubility of CsI in water is due to its high lattice enthalpy.
  3. (C)Among the alkali metal halides, LiF is least soluble in water.
  4. (D)LiF has least negative standard enthalpy of formation among alkali metal fluorides.

Correct answer: (C)

Step-by-step solution →
Q32·ChemistrySingle correct
The addition of dilute NaOH to Cr3+^{3+}3+ salt solution will give :
  1. (A)a solution of [Cr(OH)4_{4}4​]−^{-}−
  2. (B)precipitate of Cr2_{2}2​O3_{3}3​(H2_{2}2​O)n_{n}n​
  3. (C)precipitate of [Cr(OH)6_{6}6​]3−^{3-}3−
  4. (D)precipitate of Cr(OH)3_{3}3​

Correct answer: (B)

Step-by-step solution →
Q33·ChemistrySingle correct
Given below are two statements : Statement I : Ethyl pent–4–yn–oate on reaction with CH3_{3}3​MgBr gives a 3°–alcohol. Statement II : In this reaction one mole of ethyl pent–4–yn–oate utilizes two moles of CH3_{3}3​MgBr. In the light of the above statements, choose the most appropriate answer from the options given below :
  1. (A)Both Statement I and Statement II are false.
  2. (B)Statement I is false but Statement II is true.
  3. (C)Statement I is true but Statement II is false.
  4. (D)Both Statement I and Statement II are true.

Correct answer: (C)

Step-by-step solution →
Q34·ChemistrySingle correct
In stratosphere most of the ozone formation is assisted by :
  1. (A)cosmic rays.
  2. (B)γ–rays.
  3. (C)ultraviolet radiation.
  4. (D)visible radiations.

Correct answer: (C)

Step-by-step solution →
Q35·ChemistrySingle correct
The compound/s which will show significant intermolecular H–bonding is/are :
  1. (A)(b) only
  2. (B)(c) only
  3. (C)(a) and (b) only
  4. (D)(a), (b) and (c)

Correct answer: (A)

Step-by-step solution →
Q36·ChemistrySingle correct
Which one of the following chemicals is responsible for the production of HCl in the stomach leading to irritation and pain?
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (B)

Step-by-step solution →
Q37·ChemistrySingle correct
The oxide that gives H2_{2}2​O2_{2}2​ most readily on treatment with H2_{2}2​O is :
  1. (A)PbO2_{2}2​
  2. (B)Na2_{2}2​O2_{2}2​
  3. (C)SnO2_{2}2​
  4. (D)BaO2_{2}2​·8H2_{2}2​O

Correct answer: (B)

Step-by-step solution →
Q38·ChemistrySingle correct
The correct order of ionic radii for the ions, P3−^{3-}3−, S2−^{2-}2−, Ca2+^{2+}2+, K+^{+}+, Cl−^{-}− is :
  1. (A)P3−^{3-}3− > S2−^{2-}2− > Cl−^{-}− > K+^{+}+ > Ca2+^{2+}2+
  2. (B)Cl−^{-}− > S2−^{2-}2− > P3−^{3-}3− > Ca2+^{2+}2+ > K+^{+}+
  3. (C)P3−^{3-}3− > S2−^{2-}2− > Cl−^{-}− > Ca2+^{2+}2+ > K+^{+}+
  4. (D)K+^{+}+ > Ca2+^{2+}2+ > P3−^{3-}3− > S2−^{2-}2− > Cl−^{-}−

Correct answer: (A)

Step-by-step solution →
Q39·ChemistrySingle correct
Which one of the following is the major product of the given reaction?
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (A)

Step-by-step solution →
Q40·ChemistrySingle correct
The major product (A) formed in the reaction given below is :
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (B)

Step-by-step solution →
Q41·ChemistrySingle correct
Which one of the following is used to remove most of plutonium from spent nuclear fuel?
  1. (A)ClF3_{3}3​
  2. (B)O2_{2}2​F2_{2}2​
  3. (C)I2_{2}2​O5_{5}5​
  4. (D)BrO3_{3}3​

Correct answer: (B)

Step-by-step solution →
Q42·ChemistrySingle correct
Lyophilic sols are more stable than lyophobic sols because :
  1. (A)there is a strong electrostatic repulsion between the negatively charged colloidal particles.
  2. (B)the colloidal particles have positive charge.
  3. (C)the colloidal particles have no charge.
  4. (D)the colloidal particles are solvated.

Correct answer: (D)

Step-by-step solution →
Q43·ChemistrySingle correct
The major product of the following reaction, if it occurs by SN_{N}N​2 mechanism is :
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (D)

Step-by-step solution →
Q44·ChemistrySingle correct
Potassium permanganate on heating at 513 K gives a product which is :
  1. (A)paramagnetic and colourless
  2. (B)diamagnetic and green
  3. (C)diamagnetic and colourless
  4. (D)paramagnetic and green

Correct answer: (D)

Step-by-step solution →
Q45·ChemistrySingle correct
Which one of the following tests used for the identification of functional groups in organic compounds does not use copper reagent ?
  1. (A)Barfoed's test
  2. (B)Seliwanoff's test
  3. (C)Benedict's test
  4. (D)Biuret test for peptide bond

Correct answer: (B)

Step-by-step solution →
Q46·ChemistrySingle correct
Hydrolysis of sucrose gives :
  1. (A)α-D-(–)-Glucose and β-D-(–)-Fructose
  2. (B)α-D-(+)-Glucose and α-D-(–)-Fructose
  3. (C)α-D-(–)-Glucose and α-D-(+)-Fructose
  4. (D)α-D-(+)-Glucose and β-D-(–)-Fructose

Correct answer: (D)

Step-by-step solution →
Q47·ChemistrySingle correct
Match List-I (Name of ore/mineral) with List – II (Chemical formula) : Choose the most appropriate answer from the options given below :
List-I (Name of ore/mineral)List-II (Chemical formula)
a.Calaminei.Zns
b.Malachiteii.FeCO3_{3}3​
c.Sideriteiii.ZnCO3_{3}3​
d.Sphaleriteiv.CuCO3_{3}3​ · Cu(OH)2_{2}2​
  1. (A)(a)-(iii), (b)-(iv), (c)-(ii), (d)-(i)
  2. (B)(a)-(iii), (b)-(iv), (c)-(i), (d)-(ii)
  3. (C)(a)-(iv), (b)-(iii), (c)-(i), (d)-(ii)
  4. (D)(a)-(iii), (b)-(ii), (c)-(iv), (d)-(i)

Correct answer: (A)

Step-by-step solution →
Q48·ChemistrySingle correct
Which one of the following is formed (mainly) when red phosphorus is heated in a sealed tube at 803 K ?
  1. (A)White phosphorus
  2. (B)Yellow phosphorus
  3. (C)β-Black phosphorus
  4. (D)α-Black phosphorus

Correct answer: (D)

Step-by-step solution →
Q49·ChemistrySingle correct
The correct structures of A and B formed in the following reactions are :
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (D)

Step-by-step solution →
Q50·ChemistryNumerical
The first order rate constant for the decomposition of CaCO3_{3}3​ at 700 K is 6.36 × 10−3^{-3}−3s−1^{-1}−1 and activation energy is 209 kJ mol−1^{-1}−1. Its rate constant (in s−1^{-1}−1) at 600 K is x × 10−6^{-6}−6. The value of x is _____ . (Nearest integer) [Given R = 8.31 J K−1^{-1}−1 mol−1^{-1}−1; log 6.36 × 10−3^{-3}−3 = −2.19, 10−4.79^{-4.79}−4.79 = 1.62 × 10−5^{-5}−5]

Correct answer: 16

Step-by-step solution →
Q51·ChemistryNumerical
The number of optical isomers possible for [Cr(C2_{2}2​O4_{4}4​)3_{3}3​]3−^{3-}3− is _____ .

Correct answer: 2

Step-by-step solution →
Q52·ChemistryNumerical
Two flasks I and II shown below are connected by a valve of negligible volume. When the valve is opened, the final pressure of the system in bar is x × 10−2^{-2}−2. The value of x is _____ . (Integer answer) [Assume–Ideal gas; 1 bar = 105^{5}5 Pa; Molar mass of N2_{2}2​ = 28.0 g mol−1^{-1}−1 ; R = 8.31 J mol−1^{-1}−1K−1^{-1}−1]

Correct answer: 84

Step-by-step solution →
Q53·ChemistryNumerical
100 g of propane is completely reacted with 1000 g of oxygen. The mole fraction of carbon dioxide in the resulting mixture is x × 10−2^{-2}−2. The value of x is _____ . (Nearest integer) [Atomic weight : H = 1.008; C = 12.00; O = 16.00]

Correct answer: 19

Step-by-step solution →
Q54·ChemistryNumerical
40 g of glucose (Molar mass = 180) is mixed with 200 mL of water. The freezing point of solution is _____ K. (Nearest integer) [Given : Kf_{f}f​ = 1.86 K kg mol−1^{-1}−1 ; Density of water = 1.00 g cm−3^{-3}−3; Freezing point of water = 273.15 K]

Correct answer: 271

Step-by-step solution →
Q55·ChemistryNumerical
The resistance of a conductivity cell with cell constant 1.14 cm−1^{-1}−1, containing 0.001 M KCl at 298 K is 1500 Ω. The molar conductivity of 0.001 M KCl solution at 298 K in S cm2^{2}2 mol−1^{-1}−1 is _____ . (Integer answer)

Correct answer: 760

Step-by-step solution →
Q56·ChemistryNumerical
The number of photons emitted by a monochromatic (single frequency) infrared range finder of power 1 mW and wavelength of 1000 nm, in 0.1 second is x × 1013^{13}13. The value of x is _____ . (Nearest integer) (h = 6.63 × 10−34^{-34}−34 Js, c = 3.00 × 108^{8}8 ms−1^{-1}−1)

Correct answer: 50

Step-by-step solution →
Q57·ChemistryNumerical
When 5.1 g of solid NH4_{4}4​HS is introduced into a two litre evacuated flask at 27°C, 20% of the solid decomposes into gaseous ammonia and hydrogen sulphide. The Kp_{p}p​ for the reaction at 27°C is x × 10−2^{-2}−2. The value of x is _____ . (Integer answer) [Given R = 0.082 L atm K−1^{-1}−1 mol−1^{-1}−1]

Correct answer: 6

Step-by-step solution →
Q58·ChemistryNumerical
The number of species having non–pyramidal shape among the following is _____ . (A) SO3_{3}3​ (B) NO3−_{3}^{-}3−​ (C) PCl3_{3}3​ (D) CO32−_{3}^{2-}32−​

Correct answer: 3

Step-by-step solution →
Q59·ChemistryNumerical
Data given for the following reaction is as follows: FeO(s)_{(s)}(s)​ + C(graphite)_{(graphite)}(graphite)​ → Fe(s)_{(s)}(s)​ + CO(g)_{(g)}(g)​ Substance | ΔH° (kJ mol−1^{-1}−1) | ΔS° (J mol−1^{-1}−1K−1^{-1}−1) FeO(s)_{(s)}(s)​ | −266.3 | 57.49 C(graphite)_{(graphite)}(graphite)​ | 0 | 5.74 Fe(s)_{(s)}(s)​ | 0 | 27.28 CO(g)_{(g)}(g)​ | −110.5 | 197.6 The minimum temperature in K at which the reaction becomes spontaneous is _____ . (Integer answer)

Correct answer: 964

Step-by-step solution →

Mathematics — JEE Main 27 August 2021 Shift 2

Q60·MathematicsSingle correct
The angle between the straight lines, whose direction cosines are given by the equations 2l + 2m − n = 0 and mn + nl + lm = 0, is :
  1. (A)π2\frac{\pi}{2}2π​
  2. (B)π−cos⁡−1(49)\pi - \cos^{-1}\left(\frac{4}{9}\right)π−cos−1(94​)
  3. (C)cos⁡−1(89)\cos^{-1}\left(\frac{8}{9}\right)cos−1(98​)
  4. (D)π3\frac{\pi}{3}3π​

Correct answer: (A)

Step-by-step solution →
Q61·MathematicsSingle correct
Let A=([x+1][x+2][x+3][x][x+3][x+3][x][x+2][x+4])A = \begin{pmatrix} [x+1] & [x+2] & [x+3] \\ [x] & [x+3] & [x+3] \\ [x] & [x+2] & [x+4] \end{pmatrix}A=​[x+1][x][x]​[x+2][x+3][x+2]​[x+3][x+3][x+4]​​, where [t] denotes the greatest integer less than or equal to t. If det(A) = 192, then the set of values of x is the interval:
  1. (A)[68, 69)
  2. (B)[62, 63)
  3. (C)[65, 66)
  4. (D)[60, 61)

Correct answer: (B)

Step-by-step solution →
Q62·MathematicsSingle correct
Let M and m respectively be the maximum and minimum values of the function f(x)=tan⁡−1(sin⁡x+cos⁡x)f(x) = \tan^{-1}(\sin x + \cos x)f(x)=tan−1(sinx+cosx) in [0,π2]\left[0, \frac{\pi}{2}\right][0,2π​], Then the value of tan(M − m) is equal to:
  1. (A)2+32 + \sqrt{3}2+3​
  2. (B)2−32 - \sqrt{3}2−3​
  3. (C)3+223 + 2\sqrt{2}3+22​
  4. (D)3−223 - 2\sqrt{2}3−22​

Correct answer: (D)

Step-by-step solution →
Q63·MathematicsSingle correct
Each of the persons A and B independently tosses three fair coins. The probability that both of them get the same number of heads is :
  1. (A)18\frac{1}{8}81​
  2. (B)58\frac{5}{8}85​
  3. (C)516\frac{5}{16}165​
  4. (D)1

Correct answer: (C)

Step-by-step solution →
Q64·MathematicsSingle correct
A differential equation representing the family of parabolas with axis parallel to y-axis and whose length of latus rectum is the distance of the point (2, −3) form the line 3x + 4y = 5, is given by :
  1. (A)10d2ydx2=1110\frac{d^{2}y}{dx^{2}} = 1110dx2d2y​=11
  2. (B)11d2xdy2=1011\frac{d^{2}x}{dy^{2}} = 1011dy2d2x​=10
  3. (C)10d2xdy2=1110\frac{d^{2}x}{dy^{2}} = 1110dy2d2x​=11
  4. (D)11d2ydx2=1011\frac{d^{2}y}{dx^{2}} = 1011dx2d2y​=10

Correct answer: (D)

Step-by-step solution →
Q65·MathematicsSingle correct
If two tangents drawn from a point P to the parabola y2=16(x−3)y^{2} = 16(x - 3)y2=16(x−3) are at right angles, then the locus of point P is :
  1. (A)x + 3 = 0
  2. (B)x + 1 = 0
  3. (C)x + 2 = 0
  4. (D)x + 4 = 0

Correct answer: (B)

Step-by-step solution →
Q66·MathematicsSingle correct
The equation of the plane passing through the line of intersection of the planes r⃗⋅(i^+j^+k^)=1\vec{r}\cdot\left(\hat{i} + \hat{j} + \hat{k}\right) = 1r⋅(i^+j^​+k^)=1 and r⃗⋅(2i^+3j^−k^)+4=0\vec{r}\cdot\left(2\hat{i} + 3\hat{j} - \hat{k}\right) + 4 = 0r⋅(2i^+3j^​−k^)+4=0 and parallel to the x-axis is:
  1. (A)r⃗⋅(j^−3k^)+6=0\vec{r}\cdot\left(\hat{j} - 3\hat{k}\right) + 6 = 0r⋅(j^​−3k^)+6=0
  2. (B)r⃗⋅(i^+3k^)+6=0\vec{r}\cdot\left(\hat{i} + 3\hat{k}\right) + 6 = 0r⋅(i^+3k^)+6=0
  3. (C)r⃗⋅(i^−3k^)+6=0\vec{r}\cdot\left(\hat{i} - 3\hat{k}\right) + 6 = 0r⋅(i^−3k^)+6=0
  4. (D)r⃗⋅(j^−3k^)−6=0\vec{r}\cdot\left(\hat{j} - 3\hat{k}\right) - 6 = 0r⋅(j^​−3k^)−6=0

Correct answer: (A)

Step-by-step solution →
Q67·MathematicsSingle correct
If the solution curve of the differential equation (2x−10y3) dy+y dx=0(2x - 10y^{3})\,dy + y\,dx = 0(2x−10y3)dy+ydx=0, passes through the points (0, 1) and (2, β), then β is a root of the equation:
  1. (A)y5−2y−2=0y^{5} - 2y - 2 = 0y5−2y−2=0
  2. (B)2y5−2y−1=02y^{5} - 2y - 1 = 02y5−2y−1=0
  3. (C)2y5−y2−2=02y^{5} - y^{2} - 2 = 02y5−y2−2=0
  4. (D)y5−y2−1=0y^{5} - y^{2} - 1 = 0y5−y2−1=0

Correct answer: (D)

Step-by-step solution →
Q68·MathematicsSingle correct
Let A(a, 0), B(b, 2b +1) and C(0, b), b ≠ 0, |b| ≠ 1, be points such that the area of triangle ABC is 1 sq. unit, then the sum of all possible values of a is :
  1. (A)−2bb+1\frac{-2b}{b+1}b+1−2b​
  2. (B)2bb+1\frac{2b}{b+1}b+12b​
  3. (C)2b2b+1\frac{2b^{2}}{b+1}b+12b2​
  4. (D)−2b2b+1\frac{-2b^{2}}{b+1}b+1−2b2​

Correct answer: (D)

Step-by-step solution →
Q69·MathematicsSingle correct
Let [λ] be the greatest integer less than or equal to λ. The set of all values of λ for which the system of linear equations x + y + z = 4, 3x + 2y+ 5z = 3, 9x + 4y + (28+ [λ])z = [λ] has a solution is:
  1. (A)ℝ
  2. (B)(−∞,−9)∪(−9,∞)(-\infty, -9) \cup (-9, \infty)(−∞,−9)∪(−9,∞)
  3. (C)[−9, −8)
  4. (D)(−∞,−9)∪[−8,∞)(-\infty, -9) \cup [-8, \infty)(−∞,−9)∪[−8,∞)

Correct answer: (A)

Step-by-step solution →
Q70·MathematicsSingle correct
The set of all values of k > −1, for which the equation (3x2+4x+3)2−(k+1)(3x2+4x+3)(3x2+4x+2)+k(3x2+4x+2)2=0(3x^{2} + 4x + 3)^{2} - (k+1)(3x^{2} + 4x + 3)(3x^{2} + 4x + 2) + k(3x^{2} + 4x + 2)^{2} = 0(3x2+4x+3)2−(k+1)(3x2+4x+3)(3x2+4x+2)+k(3x2+4x+2)2=0 has real roots, is :
  1. (A)(1,52]\left(1, \frac{5}{2}\right](1,25​]
  2. (B)[2, 3)
  3. (C)[−12,1)\left[-\frac{1}{2}, 1\right)[−21​,1)
  4. (D)(12,32]−{1}\left(\frac{1}{2}, \frac{3}{2}\right] - \{1\}(21​,23​]−{1}

Correct answer: (A)

Step-by-step solution →
Q71·MathematicsSingle correct
A box open from top is made from a rectangular sheet of dimension a × b by cutting squares each of side x from each of the four corners and folding up the flaps. If the volume of the box is maximum, then x is equal to :
  1. (A)a+b−a2+b2−ab12\frac{a + b - \sqrt{a^{2} + b^{2} - ab}}{12}12a+b−a2+b2−ab​​
  2. (B)a+b−a2+b2+ab6\frac{a + b - \sqrt{a^{2} + b^{2} + ab}}{6}6a+b−a2+b2+ab​​
  3. (C)a+b−a2+b2−ab6\frac{a + b - \sqrt{a^{2} + b^{2} - ab}}{6}6a+b−a2+b2−ab​​
  4. (D)a+b+a2+b2−ab6\frac{a + b + \sqrt{a^{2} + b^{2} - ab}}{6}6a+b+a2+b2−ab​​

Correct answer: (C)

Step-by-step solution →
Q72·MathematicsSingle correct
The Boolean expression (p∧q)⇒((r∧q)∧p)(p \wedge q) \Rightarrow ((r \wedge q) \wedge p)(p∧q)⇒((r∧q)∧p) is equivalent to :
  1. (A)(p∧q)⇒(r∧q)(p \wedge q) \Rightarrow (r \wedge q)(p∧q)⇒(r∧q)
  2. (B)(q∧r)⇒(p∧q)(q \wedge r) \Rightarrow (p \wedge q)(q∧r)⇒(p∧q)
  3. (C)(p∧q)⇒(r∨q)(p \wedge q) \Rightarrow (r \vee q)(p∧q)⇒(r∨q)
  4. (D)(p∧r)⇒(p∧q)(p \wedge r) \Rightarrow (p \wedge q)(p∧r)⇒(p∧q)

Correct answer: (A)

Step-by-step solution →
Q73·MathematicsSingle correct
Let ℤ be the set of all integers, A = {(x, y) ∈ ℤ × ℤ : (x−2)2+y2≤4(x - 2)^{2} + y^{2} \le 4(x−2)2+y2≤4}, B = {(x, y) ∈ ℤ × ℤ : x2+y2≤4x^{2} + y^{2} \le 4x2+y2≤4} and C = {(x, y) ∈ ℤ × ℤ : (x−2)2+(y−2)2≤4(x - 2)^{2} + (y - 2)^{2} \le 4(x−2)2+(y−2)2≤4} If the total number of relation from A ∩ B to A ∩ C is 2p2^{p}2p, then the value of p is :
  1. (A)16
  2. (B)25
  3. (C)49
  4. (D)9

Correct answer: (B)

Step-by-step solution →
Q74·MathematicsSingle correct
The area of the region bounded by the parabola (y−2)2=(x−1)(y - 2)^{2} = (x - 1)(y−2)2=(x−1), the tangent to it at the point whose ordinate is 3 and the x-axis is :
  1. (A)9
  2. (B)10
  3. (C)4
  4. (D)6

Correct answer: (A)

Step-by-step solution →
Q75·MathematicsSingle correct
If y(x)=cot⁡−1(1+sin⁡x+1−sin⁡x1+sin⁡x−1−sin⁡x)y(x) = \cot^{-1}\left(\frac{\sqrt{1 + \sin x} + \sqrt{1 - \sin x}}{\sqrt{1 + \sin x} - \sqrt{1 - \sin x}}\right)y(x)=cot−1(1+sinx​−1−sinx​1+sinx​+1−sinx​​), x ∈ (π2,π)\left(\frac{\pi}{2}, \pi\right)(2π​,π), then dydx\frac{dy}{dx}dxdy​ at x=5π6x = \frac{5\pi}{6}x=65π​ is:
  1. (A)−12-\frac{1}{2}−21​
  2. (B)−1
  3. (C)12\frac{1}{2}21​
  4. (D)0

Correct answer: (A)

Step-by-step solution →
Q76·MathematicsSingle correct
Two poles, AB of length a metres and CD of length a + b (b ≠ a) metres are erected at the same horizontal level with bases at B and D. If BD = x and tan⁡∠ACB=12\tan \angle ACB = \frac{1}{2}tan∠ACB=21​, then:
  1. (A)x2+2(a+2b)x−b(a+b)=0x^{2} + 2(a + 2b)x - b(a + b) = 0x2+2(a+2b)x−b(a+b)=0
  2. (B)x2+2(a+2b)x+a(a+b)=0x^{2} + 2(a + 2b)x + a(a + b) = 0x2+2(a+2b)x+a(a+b)=0
  3. (C)x2−2ax+b(a+b)=0x^{2} - 2ax + b(a + b) = 0x2−2ax+b(a+b)=0
  4. (D)x2−2ax+a(a+b)=0x^{2} - 2ax + a(a + b) = 0x2−2ax+a(a+b)=0

Correct answer: (C)

Step-by-step solution →
Q77·MathematicsSingle correct
If 0 < x < 1 and y=12x2+23x3+34x4+…y = \frac{1}{2}x^{2} + \frac{2}{3}x^{3} + \frac{3}{4}x^{4} + \ldotsy=21​x2+32​x3+43​x4+…, then the value of e1+ye^{1+y}e1+y at x=12x = \frac{1}{2}x=21​ is:
  1. (A)12e2\frac{1}{2}e^{2}21​e2
  2. (B)2e
  3. (C)12e\frac{1}{2}\sqrt{e}21​e​
  4. (D)2e22e^{2}2e2

Correct answer: (A)

Step-by-step solution →
Q78·MathematicsSingle correct
The value of the integral ∫01x dx(1+x)(1+3x)(3+x)\int_{0}^{1} \frac{\sqrt{x}\,dx}{(1+x)(1+3x)(3+x)}∫01​(1+x)(1+3x)(3+x)x​dx​ is:
  1. (A)π8(1−32)\frac{\pi}{8}\left(1 - \frac{\sqrt{3}}{2}\right)8π​(1−23​​)
  2. (B)π4(1−36)\frac{\pi}{4}\left(1 - \frac{\sqrt{3}}{6}\right)4π​(1−63​​)
  3. (C)π8(1−36)\frac{\pi}{8}\left(1 - \frac{\sqrt{3}}{6}\right)8π​(1−63​​)
  4. (D)π4(1−32)\frac{\pi}{4}\left(1 - \frac{\sqrt{3}}{2}\right)4π​(1−23​​)

Correct answer: (A)

Step-by-step solution →
Q79·MathematicsSingle correct
If lim⁡x→∞(x2−x+1−ax)=b\lim_{x \to \infty}\left(\sqrt{x^{2} - x + 1} - ax\right) = blimx→∞​(x2−x+1​−ax)=b, then the ordered pair (a, b) is:
  1. (A)(1,12)\left(1, \frac{1}{2}\right)(1,21​)
  2. (B)(1,−12)\left(1, -\frac{1}{2}\right)(1,−21​)
  3. (C)(−1,12)\left(-1, \frac{1}{2}\right)(−1,21​)
  4. (D)(−1,−12)\left(-1, -\frac{1}{2}\right)(−1,−21​)

Correct answer: (B)

Step-by-step solution →
Q80·MathematicsNumerical
Let S be the sum of all solutions (in radians) of the equation sin⁡4θ+cos⁡4θ−sin⁡θ cos⁡θ=0\sin^{4}\theta + \cos^{4}\theta - \sin\theta\,\cos\theta = 0sin4θ+cos4θ−sinθcosθ=0 in [0, 4π][0,\ 4\pi][0, 4π]. Then 8Sπ\frac{8S}{\pi}π8S​ is equal to _________ .

Correct answer: 56

Step-by-step solution →
Q81·MathematicsNumerical
Let S be the mirror image of the point Q(1, 3, 4) with respect to the plane 2x − y + z + 3 = 0 and let R (3, 5, γ) be a point of this plane. Then the square of the length of the line segment SR is ___________ .

Correct answer: 72

Step-by-step solution →
Q82·MathematicsNumerical
The probability distribution of random variable X is given by: X | 1 | 2 | 3 | 4 | 5 P(X) | K | 2K | 2K | 3K | K Let p = P(1 < X < 4 | X < 3). If 5p = λK, then λ equal to _________ .

Correct answer: 30

Step-by-step solution →
Q83·MathematicsNumerical
Let z1z_{1}z1​ and z2z_{2}z2​ be two complex numbers such that arg⁡ (z1−z2)=π4\arg\,(z_{1} - z_{2}) = \frac{\pi}{4}arg(z1​−z2​)=4π​ and z1z_{1}z1​, z2z_{2}z2​ satisfy the equation ∣z−3∣=Re(z)|z - 3| = \mathrm{Re}(z)∣z−3∣=Re(z). Then the imaginary part of z1+z2z_{1} + z_{2}z1​+z2​ is equal to ___________ .

Correct answer: 6

Step-by-step solution →
Q84·MathematicsNumerical
Let S = {1, 2, 3, 4, 5, 6, 9}. Then the number of elements in the set T = {A ⊆ S : A ≠ φ and the sum of all the elements of A is not a multiple of 3} is ___________ .

Correct answer: 80

Step-by-step solution →
Q85·MathematicsNumerical
Two circles each of radius 5 units touch each other at the point (1, 2). If the equation of their common tangent is 4x + 3y = 10, and C1(α, β)C_{1}(\alpha,\ \beta)C1​(α, β) and C2 (γ, δ)C_{2}\,(\gamma,\ \delta)C2​(γ, δ), C1≠C2C_{1} \neq C_{2}C1​=C2​ are their centres, then ∣(α+β) (γ+δ)∣|(\alpha + \beta)\,(\gamma + \delta)|∣(α+β)(γ+δ)∣ is equal to ____________ .

Correct answer: 40

Step-by-step solution →
Q86·MathematicsNumerical
3×722+2×1022−443 \times 7^{22} + 2 \times 10^{22} - 443×722+2×1022−44 when divided by 18 leaves the remainder __________ .

Correct answer: 15

Step-by-step solution →
Q87·MathematicsNumerical
An online exam is attempted by 50 candidates out of which 20 are boys. The average marks obtained by boys is 12 with a variance 2. The variance of marks obtained by 30 girls is also 2. The average marks of all 50 candidates is 15. If μ is the average marks of girls and σ2\sigma^{2}σ2 is the variance of marks of 50 candidates, then μ+σ2\mu + \sigma^{2}μ+σ2 is equal to _________ .

Correct answer: 25

Step-by-step solution →
Q88·MathematicsNumerical
If ∫2ex+3e−x4ex+7e−x dx=114(ux+v log⁡e(4ex+7e−x))+C\int \frac{2e^{x} + 3e^{-x}}{4e^{x} + 7e^{-x}}\,dx = \frac{1}{14}\left(ux + v\,\log_{e}(4e^{x} + 7e^{-x})\right) + C∫4ex+7e−x2ex+3e−x​dx=141​(ux+vloge​(4ex+7e−x))+C, where C is a constant of integration, then u + v is equal to ___________ .

Correct answer: 7

Step-by-step solution →

Chapters tested in this paper

Open any chapter to practise every past-year question on that topic across all papers, and see how often it has actually appeared.

  • Properties of Solids and Liquids 172/186
  • Three Dimensional Geometry 176/186
  • Matrices and Determinants 180/186
  • Coordination Compounds 176/186
  • Sets, Relations and Functions 165/186
  • Current Electricity 160/186
  • Sequence and Series 164/186
  • p-Block Elements 164/186
  • Definite Integration 168/186
  • Rotational Motion 172/186
  • Redox Reactions and Electrochemistry 177/186
  • Geometrical Optics 172/186
  • Kinematics 156/186
  • Differential Equations 167/186
  • Probability 176/186
  • Permutations and Combinations 162/186
  • Magnetic Field of Current 147/186
  • Binomial Theorem and Its Simple Applications 158/186
  • Electromagnetic Waves 144/186
  • Chemical Bonding and Molecular Structure 151/186
  • Application of Derivatives 139/186
  • Limits and Continuity 149/186
  • d- and f-Block Elements 126/186
  • Thermodynamics 154/186
  • Aldehydes and Ketones 135/186
  • Equilibrium 163/186
  • Solutions 158/186
  • Laws of Motion 130/186
  • Chemical Thermodynamics 165/186
  • Units and Measurements 149/186
  • Complex Numbers 165/186
  • Trigonometric Functions 144/186
  • Biomolecules 162/186
  • Chemical Kinetics 169/186
  • Gravitation 152/186
  • Electric Field and Coulomb's Law 133/186
  • Atomic Structure 161/186
  • Electronic Devices 145/186
  • Circles 142/186
  • Dual Nature of Matter and Radiation 155/186
  • Amines 133/186
  • Quadratic Equations 148/186
  • Work, Energy and Power 132/186
  • Some Basic Concepts in Chemistry 129/186
  • Electromagnetic Induction 120/186
  • Wave Optics 130/186
  • Area Under Curves 139/186
  • Kinetic Theory of Gases 135/186
  • Alcohols and Ethers 106/186
  • Oscillations 117/186
  • Alternating Currents 108/186
  • Organic Compounds Containing Halogens 109/186
  • Straight Lines 114/186
  • Waves 109/186
  • Capacitors and Dielectrics 115/186
  • Atoms 112/186
  • Classification of Elements and Periodicity in Properties 113/186
  • Parabola 101/186
  • Statistics 118/186
  • Isolation of Metals 106/186
  • s-Block Elements 88/186
  • Surface Chemistry 98/186
  • Inverse Trigonometric Functions 93/186
  • Environmental Chemistry 83/186
  • Hydrogen 81/186
  • Indefinite Integration 66/186
  • Carboxylic Acids and Derivatives 54/186
  • Chemistry in Everyday Life 60/186
  • States of Matter: Gases and Liquids 52/186
← 27 Aug Shift 1 2021All papers31 Aug Shift 1 2021 →

Attempt this paper under exam timing.

Take the 27 August 2021 Shift 2 paper as a timed mock and Jarvis marks it, then tells you which errors were conceptual gaps, which were silly mistakes, and which pattern you have now repeated. Step-by-step solutions for every question included.

Attempt this paper freeSee pricing

Free plan, no time limit · No credit card needed

Jarvis OS

AI-powered JEE preparation.

Question papers

JEE Main PYQsJEE Advanced PYQsPhysics PYQsChemistry PYQsMaths PYQs

Product

TourPricingSign inCreate account

Legal

Privacy PolicyTerms of ServiceRefund & CancellationShipping & DeliveryContact Us

Operated by

Venyou Craft Private Limited

info@jarvisos.net

© 2026 Jarvis OS