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JEE Main 26 June 2022 Shift 2 Question Paper with Answers

26 June 2022 · June session · 90 questions

The complete JEE Main 26 June 2022 Shift 2 paper — all 90 questions with the correct answer for each, tagged to the chapter it tests. Free to read, no account needed.

Physics
30
Chemistry
30
Mathematics
30

Physics — JEE Main 26 June 2022 Shift 2

Q1·PhysicsSingle correct
The dimension of mutual inductance is :
  1. (A)[ML2T−2A−1][ML^2 T^{-2} A^{-1}][ML2T−2A−1]
  2. (B)[ML2T−3A−1][ML^2T^{-3}A^{-1}][ML2T−3A−1]
  3. (C)[ML2T−2A−2][ML^2T^{-2}A^{-2}][ML2T−2A−2]
  4. (D)[ML2T−3A−2][ML^2T^{-3}A^{-2}][ML2T−3A−2]

Correct answer: (C)

Step-by-step solution →
Q2·PhysicsSingle correct
In the arrangement shown in figure a1a_1a1​,a2a_2a2​, a3a_3a3​ and a4a_4a4​ are the accelerations of masses m1m_1m1​,m2m_2m2​,m3m_3m3​ and m4m_4m4​ respectively. Which of the following relation is true for this arrangement?
  1. (A)4a1+2a2+a3+a4=04a_1 + 2a_2 + a_3 + a_4 = 04a1​+2a2​+a3​+a4​=0
  2. (B)a1+4a2+3a3+a4=0a_1 + 4a_2 + 3a_3 + a_4 = 0a1​+4a2​+3a3​+a4​=0
  3. (C)a1+4a2+3a3+2a4=0a_1 + 4a_2 + 3a_3 + 2a_4 = 0a1​+4a2​+3a3​+2a4​=0
  4. (D)2a1+2a2+3a3+a4=02a_1 + 2a_2 + 3a_3 + a_4 = 02a1​+2a2​+3a3​+a4​=0

Correct answer: (A)

Step-by-step solution →
Q3·PhysicsSingle correct
Arrange the four graphs in descending order of total work done; where W1W_1W1​, W2W_2W2​, W3W_3W3​ and W4W_4W4​ are the work done corresponding to figure a, b, c and d respectively.
  1. (A)W3>W2>W1>W4W_3 > W_2 > W_1 > W_4W3​>W2​>W1​>W4​
  2. (B)W3>W2>W4>W1W_3 > W_2 > W_4 > W_1W3​>W2​>W4​>W1​
  3. (C)W2>W3>W4>W1W_2 > W_3 > W_4 > W_1W2​>W3​>W4​>W1​
  4. (D)W2>W3>W1>W4W_2 > W_3 > W_1 > W_4W2​>W3​>W1​>W4​

Correct answer: (A)

Step-by-step solution →
Q4·PhysicsSingle correct
Solid spherical ball is rolling on a frictionless horizontal plane surface about its axis of symmetry. The ratio of rotational kinetic energy of the ball to its total kinetic energy is :-
  1. (A)25\frac{2}{5}52​
  2. (B)27\frac{2}{7}72​
  3. (C)15\frac{1}{5}51​
  4. (D)710\frac{7}{10}107​

Correct answer: (B)

Step-by-step solution →
Q5·PhysicsSingle correct
Given below are two statements : One is labelled as Assertion A and the other is labelled as Reason R. Assertion A : If we move from poles to equator, the direction of acceleration due to gravity of earth always points towards the center of earth without any variation in its magnitude. Reason R : At equator, the direction of acceleration due to the gravity is towards the center of earth. In the light of above statements, choose the correct answer from the options given below :
  1. (A)Both A and R are true and R is the correct explanation of A.
  2. (B)Both A and R are true but R is NOT the correct explanation of A.
  3. (C)A is true but R is false
  4. (D)A is false but R is true

Correct answer: (D)

Step-by-step solution →
Q6·PhysicsSingle correct
If ρ is the density and η is coefficient of viscosity of fluid which flows with a speed v in the pipe of diameter d, the correct formula for Reynolds number ReR_eRe​ is :
  1. (A)Re=ηdρvR_e = \frac{\eta d}{\rho v}Re​=ρvηd​
  2. (B)Re=ρvηdR_e = \frac{\rho v}{\eta d}Re​=ηdρv​
  3. (C)Re=ρvdηR_e = \frac{\rho v d}{\eta}Re​=ηρvd​
  4. (D)Re=ηρvdR_e = \frac{\eta}{\rho v d}Re​=ρvdη​

Correct answer: (C)

Step-by-step solution →
Q7·PhysicsSingle correct
A flask contains argon and oxygen in the ratio of 3:2 in mass and the mixture is kept at 27°C. The ratio of their average kinetic energy per molecule respectively will be :
  1. (A)3 : 2
  2. (B)9 : 4
  3. (C)2 : 3
  4. (D)1 : 1

Correct answer: (D)

Step-by-step solution →
Q8·PhysicsSingle correct
The charge on capacitor of capacitance 15μF in the figure given below is :
  1. (A)60μc
  2. (B)130μc
  3. (C)260 μc
  4. (D)585 μc

Correct answer: (A)

Step-by-step solution →
Q9·PhysicsSingle correct
A parallel plate capacitor with plate area A and plate separation d=2 m has a capacitance of 4 μF. The new capacitance of the system if half of the space between them is filled with a dielectric material of dielectric constant K=3 (as shown in figure) will be :
  1. (A)2μF
  2. (B)32μF
  3. (C)6μF
  4. (D)8μF

Correct answer: (C)

Step-by-step solution →
Q10·Physics·Electric Field and Coulomb's LawSingle correct
Sixty four conducting drops each of radius 0.02 m and each carrying a charge of 5 μC are combined to form a bigger drop. The ratio of surface density of bigger drop to the smaller drop will be :
  1. (A)1 : 4
  2. (B)4 : 1
  3. (C)1 : 8
  4. (D)8 : 1

Correct answer: (B)

Step-by-step solution →
Q11·PhysicsSingle correct
The equivalent resistance between points A and B in the given network is :
  1. (A)65Ω
  2. (B)20Ω
  3. (C)5Ω
  4. (D)2Ω

Correct answer: (C)

Step-by-step solution →
Q12·PhysicsSingle correct
A bar magnet having a magnetic moment of 2.0×1052.0 \times 10^52.0×105 JT−1^{-1}−1, is placed along the direction of uniform magnetic field of magnitude B= 14×10−514 \times 10^{-5}14×10−5 T. The work done in rotating the magnet slowly through 60° from the direction of field is :
  1. (A)14 J
  2. (B)8.4 J
  3. (C)4 J
  4. (D)1.4 J

Correct answer: (A)

Step-by-step solution →
Q13·PhysicsSingle correct
Two coils of self inductance L1L_1L1​ and L2L_2L2​ are connected in series combination having mutual inductance of the coils as M. The equivalent self inductance of the combination will be :
  1. (A)1L1+1L2+1M\frac{1}{L_1} + \frac{1}{L_2} + \frac{1}{M}L1​1​+L2​1​+M1​
  2. (B)L1+L2+ML_1 + L_2 + ML1​+L2​+M
  3. (C)L1+L2+2ML_1 + L_2 + 2ML1​+L2​+2M
  4. (D)L1+L2−2ML_1 + L_2 - 2ML1​+L2​−2M

Correct answer: (D)

Step-by-step solution →
Q14·PhysicsSingle correct
A metallic conductor of length 1m rotates in a vertical plane parallel to east-west direction about one of its end with angular velocity 5 rad/s. If the horizontal component of earth's magnetic field is 0.2×10−40.2 \times 10^{-4}0.2×10−4 T, then emf induced between the two ends of the conductor is :
  1. (A)5μV
  2. (B)50μV
  3. (C)5mV
  4. (D)50mV

Correct answer: (B)

Step-by-step solution →
Q15·PhysicsSingle correct
Which is the correct ascending order of wavelengths?
  1. (A)λvisible<λX−ray<λgamma−ray<λmicrowave\lambda_{visible} < \lambda_{X-ray} < \lambda_{gamma-ray} < \lambda_{microwave}λvisible​<λX−ray​<λgamma−ray​<λmicrowave​
  2. (B)λgamma−ray<λX−ray<λvisible<λmicrowave\lambda_{gamma-ray} < \lambda_{X-ray} < \lambda_{visible} < \lambda_{microwave}λgamma−ray​<λX−ray​<λvisible​<λmicrowave​
  3. (C)λX−ray<λgamma−ray<λvisible<λmicrowave\lambda_{X-ray} < \lambda_{gamma-ray} < \lambda_{visible} < \lambda_{microwave}λX−ray​<λgamma−ray​<λvisible​<λmicrowave​
  4. (D)λmicrowave<λvisible<λgamma−ray<λX−ray\lambda_{microwave} < \lambda_{visible} < \lambda_{gamma-ray} < \lambda_{X-ray}λmicrowave​<λvisible​<λgamma−ray​<λX−ray​

Correct answer: (B)

Step-by-step solution →
Q16·PhysicsSingle correct
For a specific wavelength 670 nm of light coming from a galaxy moving with velocity v, the observed wavelength is 670.7 nm. The value of v is :
  1. (A)3 × 10810^{8}108 ms−1^{-1}−1
  2. (B)3 × 101010^{10}1010 ms−1^{-1}−1
  3. (C)3.13 × 10510^{5}105 ms−1^{-1}−1
  4. (D)4.48 × 10510^{5}105 ms−1^{-1}−1

Correct answer: (C)

Step-by-step solution →
Q17·PhysicsSingle correct
A metal surface is illuminated by a radiation of wavelength 4500 Å. The ejected photo-electron enters a constant magnetic field of 2 mT making an angle of 90° with the magnetic field. If it starts revolving in a circular path of radius 2 mm, the work function of the metal is approximately :
  1. (A)1.36 eV
  2. (B)1.69 eV
  3. (C)2.78 eV
  4. (D)2.23 eV

Correct answer: (A)

Step-by-step solution →
Q18·PhysicsSingle correct
A radioactive nucleus can decay by two different processes. Half-life for the first process is 3.0 hours while it is 4.5 hours for the second process. The effective half- life of the nucleus will be :
  1. (A)3.75 hours
  2. (B)0.56 hours
  3. (C)0.26 hours
  4. (D)1.80 hours

Correct answer: (D)

Step-by-step solution →
Q19·PhysicsSingle correct
The positive feedback is required by an amplifier to act an oscillator. The feedback here means :
  1. (A)External input is necessary to sustain ac signal in output.
  2. (B)A portion of the output power is returned back to the input.
  3. (C)Feedback can be achieved by LR network.
  4. (D)The base-collector junction must be forward biased.

Correct answer: (B)

Step-by-step solution →
Q20·PhysicsSingle correct
A sinusoidal wave y(t) = 40sin(10 x 10610^{6}106 πt) is amplitude modulated by another sinusoidal wave x(t) = 20sin (1000πt). The amplitude of minimum frequency component of modulated signal is :
  1. (A)0.5
  2. (B)0.25
  3. (C)20
  4. (D)10

Correct answer: (D)

Step-by-step solution →
Q21·PhysicsNumerical
A ball is projected vertically upward with an initial velocity of 50 ms−1^{-1}−1 at t = 0s. At t = 2s. another ball is projected vertically upward with same velocity. At t =________s, second ball will meet the first ball (g =10 ms−2^{-2}−2).

Correct answer: 6

Step-by-step solution →
Q22·PhysicsNumerical
A batsman hits back a ball of mass 0.4 kg straight in the direction of the bowler without changing its initial speed of 15 ms−1^{-1}−1. The impulse imparted to the ball is ________________Ns.

Correct answer: 12

Step-by-step solution →
Q23·PhysicsNumerical
A system to 10 balls each of mass 2 kg are connected via massless and unstretchable string. The system is allowed to slip over the edge of a smooth table as shown in figure. Tension on the string between the 7th7^{th}7th and 8th8^{th}8th ball is______________N when 6th6^{th}6th ball just leaves the table.

Correct answer: 36

Step-by-step solution →
Q24·PhysicsNumerical
A geyser heats water flowing at a rate of 2.0 kg per minute from 30°C to 70°C. If geyser operates on a gas burner, the rate of combustion of fuel will be _____________g min−1^{-1}−1 [Heat of combustion = 8 × 10310^{3}103 Jg−1^{-1}−1 Specific heat of water = 4.2 Jg−1^{-1}−1 °C−1^{-1}−1]

Correct answer: 42

Step-by-step solution →
Q25·PhysicsNumerical
A heat engine operates with the cold reservoir at temperature 324 K. The minimum temperature of the hot reservoir, if the heat engine takes 300 J heat from the hot reservoir and delivers 180 J heat to the cold reservoir per cycle, is ____________K.

Correct answer: 540

Step-by-step solution →
Q26·PhysicsNumerical
A set of 20 tuning forks is arranged in a series of increasing frequencies. If each fork gives 4 beats with respect to the preceding fork and the frequency of the last fork is twice the frequency of the first, then the frequency of last fork is______Hz.

Correct answer: 152

Step-by-step solution →
Q27·PhysicsNumerical
Two 10 cm long, straight wires, each carrying a current of 5A are kept parallel to each other. If each wire experienced a force of 10−510^{-5}10−5 N, then separation between the wires is _________ cm.

Correct answer: 5

Step-by-step solution →
Q28·PhysicsNumerical
A small bulb is placed at the bottom of a tank containing water to a depth of 7\sqrt{7}7​ m. The refractive index of water is 43\frac{4}{3}34​. The area of the surface of water through which light from the bulb can emerge out is xπ m2^{2}2. The value of x is________.

Correct answer: 9

Step-by-step solution →
Q29·PhysicsNumerical
A travelling microscope is used to determine the refractive index of a glass slab. If 40 divisions are there in 1 cm on main scale and 50 Vernier scale divisions are equal to 49 main scale divisions, then least count of the travelling microscope is ______×10−610^{-6}10−6 m.

Correct answer: 5

Step-by-step solution →
Q30·PhysicsNumerical
The stopping potential for photoelectrons emitted from a surface illuminated by light of wavelength 6630 Å is 0.42 V. If the threshold frequency is x × 101310^{13}1013/s, where x is _______ (nearest integer). (Given, speed light = 3 × 10810^{8}108 m/s, Planck's constant = 6.63 × 10−3410^{-34}10−34 Js)

Correct answer: 35

Step-by-step solution →

Chemistry — JEE Main 26 June 2022 Shift 2

Q31·ChemistrySingle correct
The number of radial and angular nodes in 4d orbital are, respectively
  1. (A)1 and 2
  2. (B)3 and 2
  3. (C)1 and 0
  4. (D)2 and 1

Correct answer: (A)

Step-by-step solution →
Q32·ChemistrySingle correct
Match List I with List II. Choose the most appropriate answer from the options given below :
List I (Enzyme)List II (Conversion of)
A.InvertaseI.Starch into maltose
B.ZymaseII.Maltose into glucose
C.DiastaseIII.Glucose into ethanol
D.MaltaseIV.Cane sugar into glucose
  1. (A)A-III, B-IV, C-II, D-I
  2. (B)A-III, B-II, C-I, D-IV
  3. (C)A-IV, B-III, C-I, D-II
  4. (D)A-IV, B-II, C-III, D-I

Correct answer: (C)

Step-by-step solution →
Q33·ChemistrySingle correct
Which of the following elements in considered as a metalloid?
  1. (A)Sc
  2. (B)Pb
  3. (C)Bi
  4. (D)Te

Correct answer: (D)

Step-by-step solution →
Q34·ChemistrySingle correct
The role of depressants in Froth Flotation method is to
  1. (A)selectively prevent one component of the ore from coming to the froth.
  2. (B)reduce the consumption of oil for froth formation.
  3. (C)stabilize the froth.
  4. (D)enhance non-wettability of the mineral particles.

Correct answer: (A)

Step-by-step solution →
Q35·ChemistrySingle correct
Boiling of hard water is helpful in removing the temporary hardness by converting calcium hydrogen carbonate and magnesium hydrogen carbonate to
  1. (A)CaCO3CaCO_3CaCO3​ and Mg(OH)2Mg(OH)_2Mg(OH)2​
  2. (B)CaCO3CaCO_3CaCO3​ and M2CO3M_2CO_3M2​CO3​
  3. (C)Ca(OH)2Ca(OH)_2Ca(OH)2​ and MgCO3MgCO_3MgCO3​
  4. (D)Ca(OH)2Ca(OH)_2Ca(OH)2​ and Mg(OH)2Mg(OH)_2Mg(OH)2​

Correct answer: (A)

Step-by-step solution →
Q36·ChemistrySingle correct
s-block element which cannot be qualitatively confirmed by the flame test is
  1. (A)Li
  2. (B)Na
  3. (C)Rb
  4. (D)Be

Correct answer: (D)

Step-by-step solution →
Q37·ChemistrySingle correct
The oxide which contains an odd electron at the nitrogen atom is
  1. (A)N2ON_2ON2​O
  2. (B)NO2NO_2NO2​
  3. (C)N2O3N_2O_3N2​O3​
  4. (D)N2O5N_2O_5N2​O5​

Correct answer: (B)

Step-by-step solution →
Q38·ChemistrySingle correct
Which one of the following is an example of disproportionation reaction?
  1. (A)3MnO42−+4H+→2MnO4−+MnO2+2H2O3MnO_4^{2-} + 4H^+ \rightarrow 2MnO_4^- + MnO_2 + 2H_2O3MnO42−​+4H+→2MnO4−​+MnO2​+2H2​O
  2. (B)MnO42−+4H++4e−→MnO2+2H2OMnO_4^{2-} + 4H^+ + 4e^- \rightarrow MnO_2 + 2H_2OMnO42−​+4H++4e−→MnO2​+2H2​O
  3. (C)10I−+2MnO4−+16H+→2Mn2++8H2O+5I210I^- + 2MnO_4^- + 16H^+ \rightarrow 2Mn^{2+} + 8H_2O + 5I_210I−+2MnO4−​+16H+→2Mn2++8H2​O+5I2​
  4. (D)8MnO4−+3S2O32−+H2O→8MnO2+6SO42−+2OH−8MnO_4^- + 3S_2O_3^{2-} + H_2O \rightarrow 8MnO_2 + 6SO_4^{2-} + 2OH^-8MnO4−​+3S2​O32−​+H2​O→8MnO2​+6SO42−​+2OH−

Correct answer: (A)

Step-by-step solution →
Q39·ChemistrySingle correct
The most common oxidation state of Lanthanoid elements is +3. Which of the following is likely to deviate easily from +3 oxidation state?
  1. (A)Ce (At. No. 58)
  2. (B)La (At. No. 57)
  3. (C)Lu (At. No. 71)
  4. (D)Gd (At. No. 64)

Correct answer: (A)

Step-by-step solution →
Q40·ChemistrySingle correct
The measured BOD values for four different water samples (A-D) are as follows: A = 3 ppm; B = 18 ppm; C = 21 ppm; D = 4 ppm. The water samples which can be called as highly polluted with organic wastes, are
  1. (A)A and B
  2. (B)A and D
  3. (C)B and C
  4. (D)B and D

Correct answer: (C)

Step-by-step solution →
Q41·Chemistry·Reaction MechanismSingle correct
The correct order of nucleophilicity is
  1. (A)F−>OH−F^- > OH^-F−>OH−
  2. (B)H2O⋅⋅⋅⋅>OH−H_2\overset{\cdot\cdot}{\underset{\cdot\cdot}{O}} > OH^-H2​⋅⋅O​⋅⋅​>OH−
  3. (C)RO⋅⋅⋅⋅H>RO−R\overset{\cdot\cdot}{\underset{\cdot\cdot}{O}}H > RO^-R⋅⋅O​⋅⋅​H>RO−
  4. (D)NH2−>NH3NH_2^- > NH_3NH2−​>NH3​

Correct answer: (D)

Step-by-step solution →
Q42·ChemistrySingle correct
Oxidation of toluene to Benzaldehyde can be easily carried out with which of the following reagents?
  1. (A)CrO3CrO_3CrO3​/acetic acid, H3O+H_3O^+H3​O+
  2. (B)CrO3CrO_3CrO3​/acetic anhydride, H3O+H_3O^+H3​O+
  3. (C)KMnO4KMnO_4KMnO4​/HCl, H3O+H_3O^+H3​O+
  4. (D)CO/HCl, anhydrous AlCl3AlCl_3AlCl3​

Correct answer: (B)

Step-by-step solution →
Q43·ChemistrySingle correct
The major product in the following reaction (i) Hg(OAc)2Hg(OAc)_2Hg(OAc)2​, H2OH_2OH2​O (ii) NaBH4NaBH_4NaBH4​
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (A)

Step-by-step solution →
Q44·ChemistrySingle correct
Halogenation of which one of the following will yield m-substituted product with respect to methyl group as a major product?
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (C)

Step-by-step solution →
Q45·ChemistrySingle correct
The reagent, from the following, which converts benzoic acid to benzaldehyde in one step is
  1. (A)LiAlH4LiAlH_4LiAlH4​
  2. (B)KMnO4KMnO_4KMnO4​
  3. (C)MnO
  4. (D)NaBH4NaBH_4NaBH4​

Correct answer: (C)

Step-by-step solution →
Q46·ChemistrySingle correct
The final product 'A' in the following reaction sequence CH3CH2−CO−CH3CH_3CH_2-CO-CH_3CH3​CH2​−CO−CH3​ →(HCN) ? →(95% H2SO4H_2SO_4H2​SO4​, Heat) A
  1. (A)CH3−CH=C(CH3)−COOHCH_3-CH=C(CH_3)-COOHCH3​−CH=C(CH3​)−COOH
  2. (B)CH3−CH=C(CH3)−CNCH_3-CH=C(CH_3)-CNCH3​−CH=C(CH3​)−CN
  3. (C)CH3−CH−C(OH)(CH3)−COOHCH_3-CH-C(OH)(CH_3)-COOHCH3​−CH−C(OH)(CH3​)−COOH
  4. (D)CH3−CH=C(CH3)−CONH2CH_3-CH=C(CH_3)-CONH_2CH3​−CH=C(CH3​)−CONH2​

Correct answer: (A)

Step-by-step solution →
Q47·ChemistrySingle correct
Which statement is NOT correct for p-toluenesulphonyl chloride?
  1. (A)It is known as Hinsberg's reagent.
  2. (B)It is used to distinguish primary and secondary amines.
  3. (C)On treatment with secondary amine, it leads to a product, that is soluble in alkali.
  4. (D)It doesn't react with tertiary amines.

Correct answer: (C)

Step-by-step solution →
Q48·ChemistrySingle correct
The final product 'C' is the following series series of reactions
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (C)

Step-by-step solution →
Q49·ChemistrySingle correct
Which of the following is NOT an example of synthetic detergent?
  1. (A)CH3−(CH2)11−C6H4−SO3−Na+CH_3-(CH_2)_{11}-C_6H_4-SO_3^-Na^+CH3​−(CH2​)11​−C6​H4​−SO3−​Na+
  2. (B)CH3−(CH2)16−COO−Na+CH_3-(CH_2)_{16}-COO^-Na^+CH3​−(CH2​)16​−COO−Na+
  3. (C)[CH3−(CH2)15−N(CH3)3]+Br−[CH_3-(CH_2)_{15}-N(CH_3)_3]^+Br^-[CH3​−(CH2​)15​−N(CH3​)3​]+Br−
  4. (D)CH3(CH2)16COO(CH2CH2O)nCH2CH2OHCH_3(CH_2)_{16}COO(CH_2CH_2O)_nCH_2CH_2OHCH3​(CH2​)16​COO(CH2​CH2​O)n​CH2​CH2​OH

Correct answer: (B)

Step-by-step solution →
Q50·ChemistrySingle correct
Which one of the following is a water soluble vitamin, that is not excreted easily?
  1. (A)Vitamin B2B_2B2​
  2. (B)Vitamin B1B_1B1​
  3. (C)Vitamin B6B_6B6​
  4. (D)Vitamin B12B_{12}B12​

Correct answer: (D)

Step-by-step solution →
Q51·ChemistryNumerical
CNG is an important transportation fuel. When 100 g CNG is mixed with 208 oxygen in vehicles, it leads to the formation of CO2CO_2CO2​ and H2OH_2OH2​O and produces large quantity of heat during this combustion, then the amount of carbon dioxide, produced in grams is_________. [nearest integer] [Assume CNG to be methane]

Correct answer: 143

Step-by-step solution →
Q52·ChemistryNumerical
In a solid AB. A atoms are in ccp arrangement and B atoms occupy all the octahedral sites. If two atoms from the opposite faces are removed, then the resultant stoichiometry of the compound is AxByA_xB_yAx​By​. The value of x is________. [nearest integer]

Correct answer: 3

Step-by-step solution →
Q53·ChemistryNumerical
Amongst SF4SF_4SF4​, XeF4XeF_4XeF4​, CF4CF_4CF4​ and H2OH_2OH2​O, the number of species with two lone pairs of electrons _______ .

Correct answer: 2

Step-by-step solution →
Q54·ChemistryNumerical
A fish swimming in water body when taken out from the water body is covered with a film of water of weight 36 g. When it is subjected to cooking at 100°C, then the internal energy for vaporization in kJ mol−1mol^{-1}mol−1 is _________. [nearest integer] [Assume steam to be an ideal gas. Given AvapH⊖A_{vap}H^{\ominus}Avap​H⊖ for water at 373 K and 1 bar is 41.1 kJ mol−1mol^{-1}mol−1 ; R = 8.31 JK−1mol−1JK^{-1}mol^{-1}JK−1mol−1]

Correct answer: 38

Step-by-step solution →
Q55·ChemistryNumerical
The osmotic pressure exerted by a solution prepared by dissolving 2.0 g of protein of molar mass 60 kg mol−1mol^{-1}mol−1 in 200 mL of water at 27°C is ________ Pa. [integer value] (use R = 0.083 L bar mol−1mol^{-1}mol−1 K−1K^{-1}K−1)

Correct answer: 415

Step-by-step solution →
Q56·ChemistryNumerical
40° of HI undergoes decomposition to H2H_2H2​ and I2I_2I2​ at 300 K. ΔG⊖\Delta G^{\ominus}ΔG⊖ for this decompostion reaction at one atmosphere pressure is_________ J mol−1mol^{-1}mol−1. [nearest integer] (Use R = 8.31 J K−1K^{-1}K−1 mol−1mol^{-1}mol−1; log 2 = 0.3010. In 10 = 2.3, log 3 = 0.477)

Correct answer: 2735

Step-by-step solution →
Q57·ChemistryNumerical
Cu(s) + Sn2+Sn^{2+}Sn2+ (0.001M) → Cu2+Cu^{2+}Cu2+ (0.01M) + Sn(s) The Gibbs free energy change for the above reaction at 298 K is x × 10−110^{-1}10−1 kJ mol−1mol^{-1}mol−1; The value of x is_______. [nearest integer] [Given : ECu2+/Cu⊖E^{\ominus}_{Cu^{2+}/Cu}ECu2+/Cu⊖​ = 0.34 V; ESn2+/Sn⊖E^{\ominus}_{Sn^{2+}/Sn}ESn2+/Sn⊖​ = −0.14 V; F = 96500 C mol−1mol^{-1}mol−1]

Correct answer: 983

Step-by-step solution →
Q58·ChemistryNumerical
Catalyst A reduces the activation energy for a reaction by 10 kJ mol−1mol^{-1}mol−1 at 300 K. The ratio of rate constants, kT,CatalysedkT,Uncatalysed\frac{k_{T,Catalysed}}{k_{T,Uncatalysed}}kT,Uncatalysed​kT,Catalysed​​ is exe^xex. The value of x is ________. [nearest integer] [Assume theat the pre-exponential factor is same in both the cases. Given R = 8.31 J K−1K^{-1}K−1 mol−1mol^{-1}mol−1]

Correct answer: 4

Step-by-step solution →
Q59·ChemistryNumerical
Reaction of [Co(H2O)6]2+[Co(H_2O)_6]^{2+}[Co(H2​O)6​]2+ with excess ammonia and in the presence of oxygen results into a diamagnetic product. Number of electrons present in t2gt_{2g}t2g​–orbitals of the product is ________ .

Correct answer: 6

Step-by-step solution →
Q60·ChemistryNumerical
The moles of methane required to produce 81 g of water after complete combustion is ______ × 10−210^{-2}10−2 mol. [nearest integer]

Correct answer: 225

Step-by-step solution →

Mathematics — JEE Main 26 June 2022 Shift 2

Q61·MathematicsSingle correct
Let f : ℝ → ℝ be defined as f(x) = x-1 and g : ℝ − {1, −1} → ℝ be defined as g(x)=x2x2−1g(x)=\frac{x^2}{x^2-1}g(x)=x2−1x2​. Then the function fog is :
  1. (A)one-one but not onto function
  2. (B)onto but not one-one function
  3. (C)both one-one and onto function
  4. (D)neither one-one nor onto function

Correct answer: (D)

Step-by-step solution →
Q62·MathematicsSingle correct
If the system of equations αx + y + z = 5, x + 2y + 3z = 4, x + 3y + 5z = β, has infinitely many solutions, then the ordered pair (α, β) is equal to :
  1. (A)(1,–3)
  2. (B)(–1, 3)
  3. (C)(1, 3)
  4. (D)(–1, –3)

Correct answer: (C)

Step-by-step solution →
Q63·MathematicsSingle correct
If A=∑n=1∞1(3+(−1)n)nA=\sum_{n=1}^{\infty}\frac{1}{\left(3+(-1)^n\right)^n}A=∑n=1∞​(3+(−1)n)n1​ and B=∑n=1∞(−1)n(3+(−1)n)nB=\sum_{n=1}^{\infty}\frac{(-1)^n}{\left(3+(-1)^n\right)^n}B=∑n=1∞​(3+(−1)n)n(−1)n​, then AB\frac{A}{B}BA​ is equal to :
  1. (A)119\frac{11}{9}911​
  2. (B)1
  3. (C)−119-\frac{11}{9}−911​
  4. (D)−113-\frac{11}{3}−311​

Correct answer: (C)

Step-by-step solution →
Q64·MathematicsSingle correct
lim⁡x→0cos⁡(sin⁡x)−cos⁡xx4\lim_{x\to 0}\frac{\cos(\sin x)-\cos x}{x^4}limx→0​x4cos(sinx)−cosx​ is equal to :
  1. (A)13\frac{1}{3}31​
  2. (B)14\frac{1}{4}41​
  3. (C)16\frac{1}{6}61​
  4. (D)112\frac{1}{12}121​

Correct answer: (C)

Step-by-step solution →
Q65·MathematicsSingle correct
Let f (x) = min {1, 1 + x sin x}, 0 ≤ x ≤ 2π. If m is the number of points, where f is not differentiable and n is the number of points, where f is not continuous, then the ordered pair (m, n) is equal to
  1. (A)(2, 0)
  2. (B)(1, 0)
  3. (C)(1, 1)
  4. (D)(2, 1)

Correct answer: (B)

Step-by-step solution →
Q66·MathematicsSingle correct
Consider a cuboid of sides 2x, 4x and 5x and a closed hemisphere of radius r. If the sum of their surface areas is a constant k, then the ratio x : r, for which the sum of their volumes is maximum, is :
  1. (A)2 : 5
  2. (B)19:45
  3. (C)3 : 8
  4. (D)19 : 15

Correct answer: (B)

Step-by-step solution →
Q67·MathematicsSingle correct
The area of the region bounded by y2=8xy^2=8xy2=8x and y2=16(3−x)y^2=16(3-x)y2=16(3−x) is equal to :-
  1. (A)323\frac{32}{3}332​
  2. (B)403\frac{40}{3}340​
  3. (C)16
  4. (D)19

Correct answer: (C)

Step-by-step solution →
Q68·MathematicsSingle correct
If ∫1x1−x1+x dx=g(x)+c\int \frac{1}{x}\sqrt{\frac{1-x}{1+x}}\,dx = g\left(x\right) + c∫x1​1+x1−x​​dx=g(x)+c, g(1)=0g\left(1\right) = 0g(1)=0, then g(12)g\left(\frac{1}{2}\right)g(21​) is equal to :
  1. (A)log⁡e(3−13+1)+π3\log_{e}\left(\frac{\sqrt{3}-1}{\sqrt{3}+1}\right) + \frac{\pi}{3}loge​(3​+13​−1​)+3π​
  2. (B)log⁡e(3+13−1)+π3\log_{e}\left(\frac{\sqrt{3}+1}{\sqrt{3}-1}\right) + \frac{\pi}{3}loge​(3​−13​+1​)+3π​
  3. (C)log⁡e(3+13−1)−π3\log_{e}\left(\frac{\sqrt{3}+1}{\sqrt{3}-1}\right) - \frac{\pi}{3}loge​(3​−13​+1​)−3π​
  4. (D)12log⁡e(3−13+1)−π6\frac{1}{2}\log_{e}\left(\frac{\sqrt{3}-1}{\sqrt{3}+1}\right) - \frac{\pi}{6}21​loge​(3​+13​−1​)−6π​

Correct answer: (A)

Step-by-step solution →
Q69·MathematicsSingle correct
If y = y(x) is the solution of the differential equation xdydx+2y=xex, y(1)=0x\frac{dy}{dx}+2y=xe^x,\ y(1)=0xdxdy​+2y=xex, y(1)=0, then the local maximum value of the function z(x)=x2y(x)−exz(x)=x^2y(x)-e^xz(x)=x2y(x)−ex, x∈R is :
  1. (A)1 – e
  2. (B)0
  3. (C)12\frac{1}{2}21​
  4. (D)4e−e\frac{4}{e}-ee4​−e

Correct answer: (D)

Step-by-step solution →
Q70·MathematicsSingle correct
If the solution of the differential equation dydx+ex(x2−2)y=(x2−2x)(x2−2)e2x\frac{dy}{dx}+e^x\left(x^2-2\right)y=\left(x^2-2x\right)\left(x^2-2\right)e^{2x}dxdy​+ex(x2−2)y=(x2−2x)(x2−2)e2x satisfies y(0) = 0, then the value of y(2) is ________ .
  1. (A)–1
  2. (B)1
  3. (C)0
  4. (D)e

Correct answer: (C)

Step-by-step solution →
Q71·MathematicsSingle correct
If m is the slope of a common tangent to the curves x216+y29=1\frac{x^2}{16}+\frac{y^2}{9}=116x2​+9y2​=1 and x2+y2=12x^2+y^2=12x2+y2=12, then 12m212m^212m2 is equal to :
  1. (A)6
  2. (B)9
  3. (C)10
  4. (D)12

Correct answer: (B)

Step-by-step solution →
Q72·MathematicsSingle correct
The locus of the mid point of the line segment joining the point (4, 3) and the points on the ellipse x2+2y2=4x^2+2y^2=4x2+2y2=4 is an ellipse with eccentricity :
  1. (A)32\frac{\sqrt{3}}{2}23​​
  2. (B)122\frac{1}{2\sqrt{2}}22​1​
  3. (C)12\frac{1}{\sqrt{2}}2​1​
  4. (D)12\frac{1}{2}21​

Correct answer: (C)

Step-by-step solution →
Q73·MathematicsSingle correct
The normal to the hyperbola x2a2−y29=1\frac{x^2}{a^2}-\frac{y^2}{9}=1a2x2​−9y2​=1 at the point (8,33)\left(8,3\sqrt{3}\right)(8,33​) on it passes through the point :
  1. (A)(15,−23)\left(15,-2\sqrt{3}\right)(15,−23​)
  2. (B)(9,23)\left(9,2\sqrt{3}\right)(9,23​)
  3. (C)(−1,93)\left(-1,9\sqrt{3}\right)(−1,93​)
  4. (D)(−1,63)\left(-1,6\sqrt{3}\right)(−1,63​)

Correct answer: (C)

Step-by-step solution →
Q74·MathematicsSingle correct
If the plane 2x + y – 5z = 0 is rotated about its line of intersection with the plane 3x – y + 4z – 7 = 0 by an angle of π2\frac{\pi}{2}2π​, then the plane after the rotation passes through the point :
  1. (A)(2, –2, 0)
  2. (B)(–2, 2, 0)
  3. (C)(1, 0, 2)
  4. (D)(–1, 0, –2)

Correct answer: (C)

Step-by-step solution →
Q75·MathematicsSingle correct
If the lines r⃗=(i^−j^+k^)+λ(3j^−k^)\vec{r}=\left(\hat{i}-\hat{j}+\hat{k}\right)+\lambda\left(3\hat{j}-\hat{k}\right)r=(i^−j^​+k^)+λ(3j^​−k^) and r⃗=(αi^−j^)+μ(2i^−3k^)\vec{r}=\left(\alpha\hat{i}-\hat{j}\right)+\mu\left(2\hat{i}-3\hat{k}\right)r=(αi^−j^​)+μ(2i^−3k^) are co-planar, then distance of the plane containing these two lines from the point (α, 0, 0) is :
  1. (A)29\frac{2}{9}92​
  2. (B)211\frac{2}{11}112​
  3. (C)411\frac{4}{11}114​
  4. (D)2

Correct answer: (B)

Step-by-step solution →
Q76·MathematicsSingle correct
Let a⃗=i^+j^+2k^\vec{a}=\hat{i}+\hat{j}+2\hat{k}a=i^+j^​+2k^, b⃗=2i^−3j^+k^\vec{b}=2\hat{i}-3\hat{j}+\hat{k}b=2i^−3j^​+k^ and c⃗=i^−j^+k^\vec{c}=\hat{i}-\hat{j}+\hat{k}c=i^−j^​+k^ be three given vectors. Let v⃗\vec{v}v be a vector in the plane of a⃗\vec{a}a and b⃗\vec{b}b whose projection on c⃗\vec{c}c is 23\frac{2}{\sqrt{3}}3​2​. If v⃗⋅j^=7\vec{v}\cdot\hat{j}=7v⋅j^​=7, then v⃗⋅(i^+k^)\vec{v}\cdot\left(\hat{i}+\hat{k}\right)v⋅(i^+k^) is equal to :
  1. (A)6
  2. (B)7
  3. (C)8
  4. (D)9

Correct answer: (D)

Step-by-step solution →
Q77·MathematicsSingle correct
The mean and standard deviation of 50 observations are 15 and 2 respectively. It was found that one incorrect observation was taken such that the sum of correct and incorrect observations is 70. If the correct mean is 16, then the correct variance is equal to :
  1. (A)10
  2. (B)36
  3. (C)43
  4. (D)60

Correct answer: (C)

Step-by-step solution →
Q78·MathematicsSingle correct
16sin⁡(20∘) sin⁡(40∘) sin⁡(80∘)16\sin(20^\circ)\,\sin(40^\circ)\,\sin(80^\circ)16sin(20∘)sin(40∘)sin(80∘) is equal to :
  1. (A)3\sqrt{3}3​
  2. (B)232\sqrt{3}23​
  3. (C)3
  4. (D)434\sqrt{3}43​

Correct answer: (B)

Step-by-step solution →
Q79·MathematicsSingle correct
If the inverse trigonometric functions take principal values, then cos⁡−1(310cos⁡(tan⁡−1(43))+25sin⁡(tan⁡−1(43)))\cos^{-1}\left(\frac{3}{10}\cos\left(\tan^{-1}\left(\frac{4}{3}\right)\right)+\frac{2}{5}\sin\left(\tan^{-1}\left(\frac{4}{3}\right)\right)\right)cos−1(103​cos(tan−1(34​))+52​sin(tan−1(34​))) is equal to :
  1. (A)0
  2. (B)π4\frac{\pi}{4}4π​
  3. (C)π3\frac{\pi}{3}3π​
  4. (D)π6\frac{\pi}{6}6π​

Correct answer: (C)

Step-by-step solution →
Q80·MathematicsSingle correct
Let r ∈ {p, q, ~p, ~q} be such that the logical statement r∨(∼p)⇒(p∧q)∨rr\vee(\sim p)\Rightarrow(p\wedge q)\vee rr∨(∼p)⇒(p∧q)∨r is a tautology. Then 'r' is equal to :
  1. (A)p
  2. (B)q
  3. (C)~p
  4. (D)~q

Correct answer: (C)

Step-by-step solution →
Q81·MathematicsNumerical
Let f:R→Rf:\mathbb{R}\to\mathbb{R}f:R→R satisfy f(x+y)=2xf(y)+4yf(x)f(x+y)=2^{x}f(y)+4^{y}f(x)f(x+y)=2xf(y)+4yf(x), ∀x, y ∈ R\mathbb{R}R. If f(2)=3f(2)=3f(2)=3, then 14⋅f′(4)f′(2)14\cdot\frac{f'(4)}{f'(2)}14⋅f′(2)f′(4)​ is equal to ______.

Correct answer: 248

Step-by-step solution →
Q82·MathematicsNumerical
Let p and q be two real numbers such that p+q=3p+q=3p+q=3 and p4+q4=369p^{4}+q^{4}=369p4+q4=369. Then (1p+1q)−2\left(\frac{1}{p}+\frac{1}{q}\right)^{-2}(p1​+q1​)−2 is equal to ________.

Correct answer: 4

Step-by-step solution →
Q83·MathematicsNumerical
If z2+z+1=0z^{2} + z + 1 = 0z2+z+1=0, z∈Cz \in \mathbb{C}z∈C, then ∣∑n=115(Zn+(−1)n1Zn)2∣\left|\sum_{n=1}^{15}\left(Z^{n} + \left(-1\right)^{n}\frac{1}{Z^{n}}\right)^{2}\right|​∑n=115​(Zn+(−1)nZn1​)2​ is equal to ______ .

Correct answer: 2

Step-by-step solution →
Q84·MathematicsNumerical
Let X=[010001000]X=\begin{bmatrix} 0 & 1 & 0 \\ 0 & 0 & 1 \\ 0 & 0 & 0 \end{bmatrix}X=​000​100​010​​, Y=αI+βX+γX2Y=\alpha I+\beta X+\gamma X^{2}Y=αI+βX+γX2 and Z=α2I−αβX+(β2−αγ)X2Z=\alpha^{2}I-\alpha\beta X+\left(\beta^{2}-\alpha\gamma\right)X^{2}Z=α2I−αβX+(β2−αγ)X2, α,β,γ∈R\alpha,\beta,\gamma\in\mathbb{R}α,β,γ∈R. If Y−1=[15−2515015−250015]Y^{-1}=\begin{bmatrix} \frac{1}{5} & \frac{-2}{5} & \frac{1}{5} \\ 0 & \frac{1}{5} & \frac{-2}{5} \\ 0 & 0 & \frac{1}{5} \end{bmatrix}Y−1=​51​00​5−2​51​0​51​5−2​51​​​, then (α−β+γ)2(\alpha-\beta+\gamma)^{2}(α−β+γ)2 is equal to ______ .

Correct answer: 100

Step-by-step solution →
Q85·MathematicsNumerical
The total number of 3−digit numbers, whose greatest common divisor with 36 is 2, is ______ .

Correct answer: 150

Step-by-step solution →
Q86·MathematicsNumerical
If (40C0)+(41C1)+(42C2)+...+(60C20)=mn 60C20\left(^{40}C_{0}\right)+\left(^{41}C_{1}\right)+\left(^{42}C_{2}\right)+...+\left(^{60}C_{20}\right)=\frac{m}{n}\,^{60}C_{20}(40C0​)+(41C1​)+(42C2​)+...+(60C20​)=nm​60C20​, m and n are coprime, then m+nm+nm+n is equal to _____ .

Correct answer: 102

Step-by-step solution →
Q87·MathematicsNumerical
If a1(>0)a_{1}(>0)a1​(>0), a2a_{2}a2​, a3a_{3}a3​, a4a_{4}a4​, a5a_{5}a5​ are in a G.P., a2+a4=2a3+1a_{2}+a_{4}=2a_{3}+1a2​+a4​=2a3​+1 and 3a2+a3=2a43a_{2}+a_{3}=2a_{4}3a2​+a3​=2a4​, then a2+a4+2a5a_{2}+a_{4}+2a_{5}a2​+a4​+2a5​ is equal to ____.

Correct answer: 40

Step-by-step solution →
Q88·MathematicsNumerical
The integral 24π∫02(2−x2)dx(2+x2)4+x4\frac{24}{\pi}\int_{0}^{\sqrt{2}}\frac{\left(2-x^{2}\right)dx}{\left(2+x^{2}\right)\sqrt{4+x^{4}}}π24​∫02​​(2+x2)4+x4​(2−x2)dx​ is equal to ____.

Correct answer: 3

Step-by-step solution →
Q89·MathematicsNumerical
Let a line L1L_{1}L1​ be tangent to the hyperbola x216−y24=1\frac{x^{2}}{16}-\frac{y^{2}}{4}=116x2​−4y2​=1 and let L2L_{2}L2​ be the line passing through the origin and perpendicular to L1L_{1}L1​. If the locus of the point of intersection of L1L_{1}L1​ and L2L_{2}L2​ is (x2+y2)2=αx2+βy2(x^{2}+y^{2})^{2}=\alpha x^{2}+\beta y^{2}(x2+y2)2=αx2+βy2, then α+β\alpha+\betaα+β is equal to ______ .

Correct answer: 12

Step-by-step solution →
Q90·MathematicsNumerical
If the probability that a randomly chosen 6-digit number formed by using digits 1 and 8 only is a multiple of 21 is p, then 96 p is equal to ______ .

Correct answer: 33

Step-by-step solution →

Chapters tested in this paper

Open any chapter to practise every past-year question on that topic across all papers, and see how often it has actually appeared.

  • Properties of Solids and Liquids 172/186
  • Three Dimensional Geometry 176/186
  • Matrices and Determinants 180/186
  • Coordination Compounds 176/186
  • Sets, Relations and Functions 165/186
  • Current Electricity 160/186
  • Sequence and Series 164/186
  • p-Block Elements 164/186
  • Definite Integration 168/186
  • Rotational Motion 172/186
  • Redox Reactions and Electrochemistry 177/186
  • Geometrical Optics 172/186
  • Kinematics 156/186
  • Vector Algebra 173/186
  • Differential Equations 167/186
  • Probability 176/186
  • Permutations and Combinations 162/186
  • Magnetic Field of Current 147/186
  • Binomial Theorem and Its Simple Applications 158/186
  • Electromagnetic Waves 144/186
  • Chemical Bonding and Molecular Structure 151/186
  • Application of Derivatives 139/186
  • Limits and Continuity 149/186
  • d- and f-Block Elements 126/186
  • Thermodynamics 154/186
  • Aldehydes and Ketones 135/186
  • Equilibrium 163/186
  • Solutions 158/186
  • Laws of Motion 130/186
  • Chemical Thermodynamics 165/186
  • Units and Measurements 149/186
  • Hydrocarbons 126/186
  • Complex Numbers 165/186
  • Trigonometric Functions 144/186
  • Biomolecules 162/186
  • Chemical Kinetics 169/186
  • Gravitation 152/186
  • Electric Field and Coulomb's Law 133/186
  • Atomic Structure 161/186
  • Electronic Devices 145/186
  • Dual Nature of Matter and Radiation 155/186
  • Amines 133/186
  • Quadratic Equations 148/186
  • Work, Energy and Power 132/186
  • Some Basic Concepts in Chemistry 129/186
  • Electromagnetic Induction 120/186
  • Wave Optics 130/186
  • Area Under Curves 139/186
  • Kinetic Theory of Gases 135/186
  • Alcohols and Ethers 106/186
  • Nuclei 116/186
  • Waves 109/186
  • Capacitors and Dielectrics 115/186
  • Classification of Elements and Periodicity in Properties 113/186
  • Statistics 118/186
  • Ellipse 103/186
  • Isolation of Metals 106/186
  • s-Block Elements 88/186
  • Inverse Trigonometric Functions 93/186
  • Environmental Chemistry 83/186
  • Hyperbola 77/186
  • Experimental Skills 68/186
  • Indefinite Integration 66/186
  • Solid State 63/186
  • Chemistry in Everyday Life 60/186
  • Diazonium Salts and Reactions 53/186
  • Magnetism and Matter 50/186
  • Reaction Mechanism 29/186
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