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JEE Main 1 February 2023 Shift 1 Question Paper with Answers

1 February 2023 · January session · 90 questions

The complete JEE Main 1 February 2023 Shift 1 paper — all 90 questions with the correct answer for each, tagged to the chapter it tests. Free to read, no account needed.

Physics
30
Chemistry
30
Mathematics
30

Physics — JEE Main 1 February 2023 Shift 1

Q1·PhysicsSingle correct
A child stands on the edge of the cliff 101010 m above the ground and throws a stone horizontally with an initial speed of 555 ms−1^{-1}−1. Neglecting the air resistance, the speed with which the stone hits the ground will be _______ ms−1^{-1}−1 (given, g=10g = 10g=10 ms−2^{-2}−2).
  1. (A)151515
  2. (B)202020
  3. (C)303030
  4. (D)252525

Correct answer: (A)

Step-by-step solution →
Q2·PhysicsSingle correct
Let σ\sigmaσ be the uniform surface charge density of two infinite thin plane sheets shown in the figure. Then the electric fields in three different regions EIE_IEI​, EIIE_{II}EII​ and EIIIE_{III}EIII​ are:
  1. (A)E⃗I=2σε0n^, E⃗II=0, E⃗III=2σε0n^\vec{E}_I=\tfrac{2\sigma}{\varepsilon_0}\hat{n},\ \vec{E}_{II}=0,\ \vec{E}_{III}=\tfrac{2\sigma}{\varepsilon_0}\hat{n}EI​=ε0​2σ​n^, EII​=0, EIII​=ε0​2σ​n^
  2. (B)E⃗I=σ2ε0n^, E⃗II=0, E⃗III=σ2ε0n^\vec{E}_I=\tfrac{\sigma}{2\varepsilon_0}\hat{n},\ \vec{E}_{II}=0,\ \vec{E}_{III}=\tfrac{\sigma}{2\varepsilon_0}\hat{n}EI​=2ε0​σ​n^, EII​=0, EIII​=2ε0​σ​n^
  3. (C)E⃗I=−σε0n^, E⃗II=0, E⃗III=σε0n^\vec{E}_I=-\tfrac{\sigma}{\varepsilon_0}\hat{n},\ \vec{E}_{II}=0,\ \vec{E}_{III}=\tfrac{\sigma}{\varepsilon_0}\hat{n}EI​=−ε0​σ​n^, EII​=0, EIII​=ε0​σ​n^
  4. (D)E⃗I=0, E⃗II=σε0n^, E⃗III=0\vec{E}_I=0,\ \vec{E}_{II}=\tfrac{\sigma}{\varepsilon_0}\hat{n},\ \vec{E}_{III}=0EI​=0, EII​=ε0​σ​n^, EIII​=0

Correct answer: (C)

Step-by-step solution →
Q3·PhysicsSingle correct
A mercury drop of radius 10−310^{-3}10−3 m is broken into 125125125 equal size droplets. Surface tension of mercury is 0.450.450.45 Nm−1^{-1}−1. The gain in surface energy is:
  1. (A)28×10−528\times10^{-5}28×10−5 J
  2. (B)17.5×10−517.5\times10^{-5}17.5×10−5 J
  3. (C)5×10−55\times10^{-5}5×10−5 J
  4. (D)2.26×10−52.26\times10^{-5}2.26×10−5 J

Correct answer: (D)

Step-by-step solution →
Q4·PhysicsSingle correct
If earth has a mass nine times and radius twice to that of a planet PPP, then ve3x\tfrac{v_e}{3}\sqrt{x}3ve​​x​ ms−1^{-1}−1 will be the minimum velocity required by a rocket to pull out of gravitational force of PPP, where vev_eve​ is escape velocity on earth. The value of xxx is:
  1. (A)111
  2. (B)333
  3. (C)181818
  4. (D)222

Correct answer: (D)

Step-by-step solution →
Q5·PhysicsSingle correct
A sample of gas at temperature TTT is adiabatically expanded to double its volume. The work done by the gas in the process is (given, γ=32)\left(\text{given},\ \gamma=\tfrac{3}{2}\right)(given, γ=23​):
  1. (A)W=TR[2−2]W=\tfrac{T}{R}[\sqrt{2}-2]W=RT​[2​−2]
  2. (B)W=RT[2−2]W=RT[2-\sqrt{2}]W=RT[2−2​]
  3. (C)W=TR[2−2]W=TR[\sqrt{2}-2]W=TR[2​−2]
  4. (D)W=RT[2−2]W=\tfrac{R}{T}[2-\sqrt{2}]W=TR​[2−2​]

Correct answer: (B)

Step-by-step solution →
Q6·PhysicsSingle correct
(P+aV2)(V−b)=RT\left(P+\tfrac{a}{V^2}\right)(V-b)=RT(P+V2a​)(V−b)=RT represents the equation of state of some gases, where PPP is the pressure, VVV is the volume, TTT is the temperature and a,b,Ra, b, Ra,b,R are the constants. The physical quantity, which has dimensional formula as that of b2a\tfrac{b^2}{a}ab2​, will be:
  1. (A)Compressibility
  2. (B)Energy density
  3. (C)Modulus of rigidity
  4. (D)Bulk modulus

Correct answer: (A)

Step-by-step solution →
Q7·PhysicsSingle correct
The equivalent resistance between AAA and BBB of the network shown in the figure is:
  1. (A)83R\tfrac{8}{3}R38​R
  2. (B)21R21R21R
  3. (C)14R14R14R
  4. (D)1123R11\tfrac{2}{3}R1132​R

Correct answer: (A)

Step-by-step solution →
Q8·PhysicsSingle correct
Match List I (electrical machines and resonance phenomena) with List II (the underlying principle or condition). Choose the correct answer from the options given below:
List IList II
A.AC generatorI.Presence of both L and C
B.TransformerII.Electromagnetic Induction
C.Resonance phenomenon to occurIII.Quality factor
D.Sharpness of resonanceIV.Mutual Induction
  1. (A)A-IV, B-III, C-I, D-II
  2. (B)A-IV, B-II, C-I, D-III
  3. (C)A-II, B-IV, C-I, D-III
  4. (D)A-II, B-I, C-III, D-IV

Correct answer: (C)

Step-by-step solution →
Q9·PhysicsSingle correct
An object moves with speed v1v_1v1​, v2v_2v2​ and v3v_3v3​ along a line segment ABABAB, BCBCBC and CDCDCD respectively, where AB=BCAB=BCAB=BC and AD=3ABAD=3ABAD=3AB. Then the average speed of the object will be:
  1. (A)(v1+v2+v3)3v1v2v3\tfrac{(v_1+v_2+v_3)}{3v_1v_2v_3}3v1​v2​v3​(v1​+v2​+v3​)​
  2. (B)(v1+v2+v3)3\tfrac{(v_1+v_2+v_3)}{3}3(v1​+v2​+v3​)​
  3. (C)3v1v2v3(v1v2+v2v3+v3v1)\tfrac{3v_1v_2v_3}{(v_1v_2+v_2v_3+v_3v_1)}(v1​v2​+v2​v3​+v3​v1​)3v1​v2​v3​​
  4. (D)v1v2v33(v1v2+v2v3+v3v1)\tfrac{v_1v_2v_3}{3(v_1v_2+v_2v_3+v_3v_1)}3(v1​v2​+v2​v3​+v3​v1​)v1​v2​v3​​

Correct answer: (C)

Step-by-step solution →
Q10·PhysicsSingle correct
'nnn' polarizing sheets are arranged such that each makes an angle 45∘45^\circ45∘ with the preceeding sheet. An unpolarized light of intensity III is incident into this arrangement. The output intensity is found to be I64\tfrac{I}{64}64I​. The value of nnn will be:
  1. (A)444
  2. (B)333
  3. (C)555
  4. (D)666

Correct answer: (D)

Step-by-step solution →
Q11·PhysicsSingle correct
Match List I (regions of the electromagnetic spectrum) with List II (their sources). Choose the correct answer from the options given below:
List IList II
A.MicrowavesI.Radio active decay of the nucleus
B.Gamma raysII.Rapid acceleration and deceleration of electron in aerials
C.Radio wavesIII.Inner shell electrons
D.X-raysIV.Klystron valve
  1. (A)A-I, B-III, C-IV, D-II
  2. (B)A-IV, B-I, C-II, D-III
  3. (C)A-IV, B-III, C-II, D-I
  4. (D)A-I, B-II, C-III, D-IV

Correct answer: (B)

Step-by-step solution →
Q12·PhysicsSingle correct
A proton moving with one tenth of velocity of light has a certain de Broglie wavelength of λ\lambdaλ. An alpha particle having certain kinetic energy has the same de-Broglie wavelength λ\lambdaλ. The ratio of kinetic energy of proton and that of alpha particle is:
  1. (A)2:12:12:1
  2. (B)1:21:21:2
  3. (C)1:41:41:4
  4. (D)4:14:14:1

Correct answer: (D)

Step-by-step solution →
Q13·PhysicsSingle correct
A block of mass 555 kg is placed at rest on a table of rough surface. Now, if a force of 303030 N is applied in the direction parallel to surface of the table, the block slides through a distance of 505050 m in an interval of time 101010 s. Coefficient of kinetic friction is (given, g=10g=10g=10 ms−2^{-2}−2):
  1. (A)0.600.600.60
  2. (B)0.250.250.25
  3. (C)0.750.750.75
  4. (D)0.500.500.50

Correct answer: (D)

Step-by-step solution →
Q14·PhysicsSingle correct
Given below are two statements: Statement I: Acceleration due to gravity is different at different places on the surface of earth. Statement II: Acceleration due to gravity increases as we go down below the earth's surface. In the light of the above statements, choose the correct answer from the options given below:
  1. (A)Statement I is false but Statement II is true
  2. (B)Statement I is true but Statement II is false
  3. (C)Both Statement I and Statement II are false
  4. (D)Both Statement I and Statement II are true

Correct answer: (B)

Step-by-step solution →
Q15·PhysicsSingle correct
Which of the following frequencies does not belong to FM broadcast?
  1. (A)646464 MHz
  2. (B)898989 MHz
  3. (C)999999 MHz
  4. (D)106106106 MHz

Correct answer: (A)

Step-by-step solution →
Q16·PhysicsSingle correct
The mass of proton, neutron and helium nucleus are respectively 1.0073u1.0073u1.0073u, 1.0087u1.0087u1.0087u and 4.0015u4.0015u4.0015u. The binding energy of helium nucleus is:
  1. (A)28.428.428.4 MeV
  2. (B)56.856.856.8 MeV
  3. (C)14.214.214.2 MeV
  4. (D)7.17.17.1 MeV

Correct answer: (A)

Step-by-step solution →
Q17·PhysicsSingle correct
A steel wire with mass per unit length 7.0×10−37.0\times10^{-3}7.0×10−3 kg m−1^{-1}−1 is under tension of 707070 N. The speed of transverse waves in the wire will be:
  1. (A)100100100 m/s
  2. (B)101010 m/s
  3. (C)505050 m/s
  4. (D)200π200\pi200π m/s

Correct answer: (A)

Step-by-step solution →
Q18·PhysicsSingle correct
Match List I (type of semiconductor/conductor) with List II (position of the Fermi-level). Choose the correct answer from the options given below:
List IList II
A.Intrinsic semiconductorI.Fermi-level near the valence band
B.n-type semiconductorII.Fermi-level in the middle of valence and conduction band
C.p-type semiconductorIII.Fermi-level near the conduction band
D.MetalsIV.Fermi-level inside the conduction band
  1. (A)A-II, B-III, C-I, D-IV
  2. (B)A-I, B-II, C-III, D-IV
  3. (C)A-II, B-I, C-III, D-IV
  4. (D)A-III, B-I, C-II, D-IV

Correct answer: (A)

Step-by-step solution →
Q19·PhysicsSingle correct
Find the magnetic field at the point PPP in the figure. The curved portion is a semicircle of radius rrr connected to two long straight wires.
  1. (A)μ0i2r(1+2π)\tfrac{\mu_0 i}{2r}\left(1+\tfrac{2}{\pi}\right)2rμ0​i​(1+π2​)
  2. (B)μ0i2r(12+12π)\tfrac{\mu_0 i}{2r}\left(\tfrac{1}{2}+\tfrac{1}{2\pi}\right)2rμ0​i​(21​+2π1​)
  3. (C)μ0i2r(1+1π)\tfrac{\mu_0 i}{2r}\left(1+\tfrac{1}{\pi}\right)2rμ0​i​(1+π1​)
  4. (D)μ0i2r(12+1π)\tfrac{\mu_0 i}{2r}\left(\tfrac{1}{2}+\tfrac{1}{\pi}\right)2rμ0​i​(21​+π1​)

Correct answer: (B)

Step-by-step solution →
Q20·PhysicsSingle correct
The average kinetic energy of a molecule of the gas is:
  1. (A)proportional to absolute temperature
  2. (B)proportional to pressure
  3. (C)proportional to volume
  4. (D)dependent on the nature of gas

Correct answer: (A)

Step-by-step solution →
Q21·PhysicsNumerical
A small particle moves to position 5i^−2j^+k^5\hat{i}-2\hat{j}+\hat{k}5i^−2j^​+k^ from its initial position 2i^+3j^−4k^2\hat{i}+3\hat{j}-4\hat{k}2i^+3j^​−4k^ under the action of force 5i^+2j^+7k^5\hat{i}+2\hat{j}+7\hat{k}5i^+2j^​+7k^ N. The value of work done will be _______ J.

Correct answer: 40

Step-by-step solution →
Q22·PhysicsNumerical
A certain pressure 'PPP' is applied to 111 litre of water and 222 litre of a liquid separately. Water gets compressed to 0.01%0.01\%0.01% whereas the liquid gets compressed to 0.03%0.03\%0.03%. The ratio of Bulk modulus of water to that of the liquid is 3x\tfrac{3}{x}x3​. The value of xxx is _______ .

Correct answer: 1

Step-by-step solution →
Q23·PhysicsNumerical
A light of energy 12.7512.7512.75 eV is incident on a hydrogen atom in its ground state. The atom absorbs the radiation and reaches to one of its excited states. The angular momentum of the atom in the excited state is xπ×10−17\tfrac{x}{\pi}\times10^{-17}πx​×10−17 eVs. The value of xxx is _______ (use h=4.14×10−15h=4.14\times10^{-15}h=4.14×10−15 eVs, c=3×108c=3\times10^8c=3×108 ms−1^{-1}−1).

Correct answer: 828

Step-by-step solution →
Q24·PhysicsNumerical
A charge particle of 2 μC2\,\mu C2μC accelerated by a potential difference of 100100100 V enters a region of uniform magnetic field of magnitude 444 mT at right angle to the direction of field. The charge particle completes semicircle of radius 333 cm inside magnetic field. The mass of the charge particle is _______ ×10−18\times10^{-18}×10−18 kg.

Correct answer: 144

Step-by-step solution →
Q25·PhysicsNumerical
The amplitude of a particle executing SHM is 333 cm. The displacement at which its kinetic energy will be 25%25\%25% more than the potential energy is _______ cm.

Correct answer: 2

Step-by-step solution →
Q26·PhysicsNumerical
In an experiment to find emf of a cell using potentiometer, the length of null point for a cell of emf 1.51.51.5 V is found to be 606060 cm. If this cell is replaced by another cell of emf EEE, the length of null point increases by 404040 cm. The value of EEE is x10\tfrac{x}{10}10x​ V. The value of xxx is _______ .

Correct answer: 25

Step-by-step solution →
Q27·PhysicsNumerical
A thin cylindrical rod of length 101010 cm is placed horizontally on the principal axis of a concave mirror of focal length 202020 cm. The rod is placed in such a way that mid point of the rod is at 404040 cm from the pole of mirror. The length of the image formed by the mirror will be x3\tfrac{x}{3}3x​ cm. The value of xxx is _______ .

Correct answer: 32

Step-by-step solution →
Q28·PhysicsNumerical
A solid cylinder is released from rest from the top of an inclined plane of inclination 30∘30^\circ30∘ and length 606060 cm. If the cylinder rolls without slipping, its speed upon reaching the bottom of the inclined plane is _______ ms−1^{-1}−1 (given g=10g=10g=10 ms−2^{-2}−2).

Correct answer: 2

Step-by-step solution →
Q29·PhysicsNumerical
A series LCR circuit is connected to an ac source of 220220220 V, 505050 Hz. The circuit contains a resistance R=100 ΩR=100\,\OmegaR=100Ω and an inductor of inductive reactance XL=79.6 ΩX_L=79.6\,\OmegaXL​=79.6Ω. The capacitance of the capacitor needed to maximize the average rate at which energy is supplied will be _______ μ\muμF.

Correct answer: 40

Step-by-step solution →
Q30·PhysicsNumerical
Two equal positive point charges are separated by a distance 2a2a2a. The distance of a point from the centre of the line joining two charges on the equatorial line (perpendicular bisector) at which force experienced by a test charge q0q_0q0​ becomes maximum is ax\tfrac{a}{\sqrt{x}}x​a​. The value of xxx is _______ .

Correct answer: 2

Step-by-step solution →

Chemistry — JEE Main 1 February 2023 Shift 1

Q31·ChemistrySingle correct
A solution of FeCl3\text{FeCl}_3FeCl3​ when treated with K4[Fe(CN)6]\text{K}_4[\text{Fe(CN)}_6]K4​[Fe(CN)6​] gives a prussian blue precipitate due to the formation of:
  1. (A)K[Fe2(CN)6]\text{K[Fe}_2(\text{CN})_6]K[Fe2​(CN)6​]
  2. (B)Fe4[Fe(CN)6]3\text{Fe}_4[\text{Fe(CN)}_6]_3Fe4​[Fe(CN)6​]3​
  3. (C)Fe[Fe(CN)6]\text{Fe[Fe(CN)}_6]Fe[Fe(CN)6​]
  4. (D)Fe3[Fe(CN)6]2\text{Fe}_3[\text{Fe(CN)}_6]_2Fe3​[Fe(CN)6​]2​

Correct answer: (B)

Step-by-step solution →
Q32·ChemistryAssertion & Reason
Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R. Assertion A: Hydrogen is an environment friendly fuel. Reason R: Atomic number of hydrogen is 1 and it is a very light element. In the light of the above statements, choose the correct answer from the options given below:
  1. (A)A is true but R is false
  2. (B)A is false but R is true
  3. (C)Both A and R are true and R is the correct explanation of A
  4. (D)Both A and R are true but R is NOT the correct explanation of A

Correct answer: (D)

Step-by-step solution →
Q33·ChemistrySingle correct
Resonance structures of the carbonate ion (CO32−)(\text{CO}_3^{2-})(CO32−​) are shown in the figure. Which of the following is true?
  1. (A)All these structures are in dynamic equilibrium with each other.
  2. (B)It is possible to identify each structure individually by some physical or chemical method.
  3. (C)Each structure exists for equal amount of time.
  4. (D)CO32−\text{CO}_3^{2-}CO32−​ has a single structure i.e., resonance hybrid of the above three structures.

Correct answer: (D)

Step-by-step solution →
Q34·ChemistrySingle correct
Match List I (class of drug) with List II (its example or action). Choose the correct answer from the options given below:
List IList II
A.TranquilizersI.Anti blood clotting
B.AspirinII.Salvarsan
C.AntibioticIII.antidepressant drugs
D.AntisepticIV.soframicine
  1. (A)(A)-IV, (B)-II, (C)-I, (D)-III
  2. (B)(A)-II, (B)-I, (C)-III, (D)-IV
  3. (C)(A)-III, (B)-I, (C)-II, (D)-IV
  4. (D)(A)-II, (B)-IV, (C)-I, (D)-III

Correct answer: (C)

Step-by-step solution →
Q35·ChemistrySingle correct
Identify the incorrect option from the following:
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (D)

Step-by-step solution →
Q36·ChemistrySingle correct
But-2-yne CH3−C≡C−CH3\text{CH}_3-\text{C}\equiv\text{C}-\text{CH}_3CH3​−C≡C−CH3​ is reacted separately with one mole of hydrogen to give A (using Na in liquid NH3\text{NH}_3NH3​) and B (using Pd/C\text{Pd}/\text{C}Pd/C). (A) A is more soluble than B. (B) The boiling point and melting point of A are higher and lower than B respectively. (C) A is more polar than B because dipole moment of A is zero. (D) Br2\text{Br}_2Br2​ adds easily to B than A. Identify the incorrect statements from the options given below:
  1. (A)B, C and D only
  2. (B)A and B only
  3. (C)A, C and D only
  4. (D)B and C only

Correct answer: (B)

Step-by-step solution →
Q37·ChemistrySingle correct
In the reaction shown in the figure, 'AAA' is:
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (C)

Step-by-step solution →
Q38·ChemistrySingle correct
Highest oxidation state of Mn is exhibited in Mn2O7\text{Mn}_2\text{O}_7Mn2​O7​. The correct statements about Mn2O7\text{Mn}_2\text{O}_7Mn2​O7​ are: (A) Mn is tetrahedrally surrounded by oxygen atoms. (B) Mn is octahedrally surrounded by oxygen atoms. (C) Contains Mn-O-Mn bridge. (D) Contains Mn-Mn bond. Choose the correct answer from the options given below:
  1. (A)A and C only
  2. (B)A and D only
  3. (C)B and C only
  4. (D)B and D only

Correct answer: (A)

Step-by-step solution →
Q39·ChemistrySingle correct
Match List I (common name of an s-block compound) with List II (its chemical formula). Choose the correct answer from the options given below:
List IList II
A.Slaked limeI.NaOH\text{NaOH}NaOH
B.Dead burnt plasterII.Ca(OH)2\text{Ca(OH)}_2Ca(OH)2​
C.Caustic sodaIII.Na2CO3⋅10H2O\text{Na}_2\text{CO}_3\cdot 10\text{H}_2\text{O}Na2​CO3​⋅10H2​O
D.Washing sodaIV.CaSO4\text{CaSO}_4CaSO4​
  1. (A)(A)-III, (B)-IV, (C)-II, (D)-I
  2. (B)(A)-III, (B)-II, (C)-IV, (D)-I
  3. (C)(A)-I, (B)-IV, (C)-II, (D)-III
  4. (D)(A)-II, (B)-IV, (C)-I, (D)-III

Correct answer: (D)

Step-by-step solution →
Q40·ChemistrySingle correct
The correct representation in six membered pyranose form for the sugar [X][X][X] shown in the figure is:
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (B)

Step-by-step solution →
Q41·ChemistrySingle correct
Which of the following complex will show largest splitting of d-orbitals?
  1. (A)[CoF6]3−[\text{CoF}_6]^{3-}[CoF6​]3−
  2. (B)[Co(C2O4)3]3−[\text{Co}(\text{C}_2\text{O}_4)_3]^{3-}[Co(C2​O4​)3​]3−
  3. (C)[Co(CN)6]3−[\text{Co}(\text{CN})_6]^{3-}[Co(CN)6​]3−
  4. (D)[Co(NH3)6]3+[\text{Co}(\text{NH}_3)_6]^{3+}[Co(NH3​)6​]3+

Correct answer: (C)

Step-by-step solution →
Q42·ChemistrySingle correct
Which of the following are the examples of double salt? (A) FeSO4⋅(NH4)2SO4⋅6H2O\text{FeSO}_4\cdot(\text{NH}_4)_2\text{SO}_4\cdot 6\text{H}_2\text{O}FeSO4​⋅(NH4​)2​SO4​⋅6H2​O (B) CuSO4⋅4NH3⋅H2O\text{CuSO}_4\cdot 4\text{NH}_3\cdot\text{H}_2\text{O}CuSO4​⋅4NH3​⋅H2​O (C) K2SO4⋅Al2(SO4)3⋅24H2O\text{K}_2\text{SO}_4\cdot\text{Al}_2(\text{SO}_4)_3\cdot 24\text{H}_2\text{O}K2​SO4​⋅Al2​(SO4​)3​⋅24H2​O (D) Fe(CN)2⋅4KCN\text{Fe(CN)}_2\cdot 4\text{KCN}Fe(CN)2​⋅4KCN. Choose the correct answer:
  1. (A)B and D only
  2. (B)A and C only
  3. (C)A and B only
  4. (D)A, B and D only

Correct answer: (B)

Step-by-step solution →
Q43·ChemistrySingle correct
Decreasing order of dehydration of the alcohols (a), (b), (c) and (d) shown in the figure is:
  1. (A)b > a > d > c
  2. (B)a > d > b > c
  3. (C)d > b > c > a
  4. (D)b > d > c > a

Correct answer: (D)

Step-by-step solution →
Q44·ChemistrySingle correct
Given below are two statements: Statement I: Chlorine can easily combine with oxygen to form oxides; and the product has a tendency to explode. Statement II: Chemical reactivity of an element can be determined by its reaction with oxygen and halogens. In the light of the above statements, choose the correct answer from the options given below:
  1. (A)Both the Statements I and II are true
  2. (B)Both the Statements I and II are false
  3. (C)Statement I is false but Statement II is true
  4. (D)Statement I is true but Statement II is false

Correct answer: (A)

Step-by-step solution →
Q45·ChemistrySingle correct
Choose the correct statement(s): A. Beryllium oxide is purely acidic in nature. B. Beryllium carbonate is kept in the atmosphere of CO2\text{CO}_2CO2​. C. Beryllium sulphate is readily soluble in water. D. Beryllium shows anomalous behaviour. Choose the correct answer from the options given below:
  1. (A)B, C and D only
  2. (B)A only
  3. (C)A, B and C only
  4. (D)A and B only

Correct answer: (A)

Step-by-step solution →
Q46·ChemistrySingle correct
Which of the following represents the lattice structure of A0.95O\text{A}_{0.95}\text{O}A0.95​O containing A2+\text{A}^{2+}A2+, A3+\text{A}^{3+}A3+ and O2−\text{O}^{2-}O2− ions (structures A, B and C shown in the figure)?
  1. (A)A only
  2. (B)B and C only
  3. (C)A and B only
  4. (D)B only

Correct answer: (A)

Step-by-step solution →
Q47·ChemistryAssertion & Reason
Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R. Assertion A: In an Ellingham diagram, the oxidation of carbon to carbon monoxide shows a negative slope with respect to temperature. Reason R: CO tends to get decomposed at higher temperature. In the light of the above statements, choose the correct answer from the options given below:
  1. (A)Both A and R are correct but R is NOT the correct explanation of A
  2. (B)Both A and R are correct and R is the correct explanation of A
  3. (C)A is not correct but R is correct
  4. (D)A is correct but R is not correct

Correct answer: (D)

Step-by-step solution →
Q48·ChemistryAssertion & Reason
Given below are two statements: One is labelled as Assertion A and the other is labelled as Reason R. Assertion A: Amongst He, Ne, Ar and Kr; 1 g of activated charcoal adsorbs more of Kr. Reason R: The critical volume VcV_cVc​ (cm3 mol−1\text{cm}^3\,\text{mol}^{-1}cm3mol−1) and critical pressure PcP_cPc​ (atm) is highest for Krypton but the compressibility factor at critical point ZcZ_cZc​ is lowest for Krypton. In the light of the above statements, choose the correct answer from the options given below:
  1. (A)A is true but R is false
  2. (B)Both A and R are true and R is the correct explanation of A
  3. (C)A is false but R is true
  4. (D)Both A and R are true but R is NOT the correct explanation of A

Correct answer: (A)

Step-by-step solution →
Q49·Chemistry·Purification and Characterisation of Organic CompoundsSingle correct
Match List I (qualitative test) with List II (class of compound it detects). Choose the correct answer from the options given below:
List IList II
A.Molisch's TestI.Peptide
B.Biuret TestII.Carbohydrate
C.Carbylamine TestIII.Primary amine
D.Schiff's TestIV.Aldehyde
  1. (A)(A)-III, (B)-IV, (C)-I, (D)-II
  2. (B)(A)-II, (B)-I, (C)-III, (D)-IV
  3. (C)(A)-III, (B)-IV, (C)-II, (D)-I
  4. (D)(A)-I, (B)-II, (C)-III, (D)-IV

Correct answer: (B)

Step-by-step solution →
Q50·ChemistrySingle correct
How can photochemical smog be controlled?
  1. (A)By using catalytic convertors in the automobiles/industry.
  2. (B)By complete combustion of fuel.
  3. (C)By using tall chimneys.
  4. (D)By using catalyst.

Correct answer: (A)

Step-by-step solution →
Q51·ChemistryNumerical
For the equilibria (i) X(g)⇌Y(g)+Z(g)\text{X(g)}\rightleftharpoons \text{Y(g)}+\text{Z(g)}X(g)⇌Y(g)+Z(g), Kp1=3K_{p_1}=3Kp1​​=3 and (ii) A(g)⇌2B(g)\text{A(g)}\rightleftharpoons 2\text{B(g)}A(g)⇌2B(g), Kp2=1K_{p_2}=1Kp2​​=1. If the degree of dissociation and initial concentration of both the reactants X(g)\text{X(g)}X(g) and A(g)\text{A(g)}A(g) are equal, then the ratio of the total pressure at equilibrium (p1p2)\left(\tfrac{p_1}{p_2}\right)(p2​p1​​) is equal to x:1x:1x:1. The value of xxx is _______ (Nearest integer).

Correct answer: 12

Step-by-step solution →
Q52·ChemistryNumerical
Electrons in a cathode ray tube have been emitted with a velocity of 100010001000 m s−1^{-1}−1. The number of following statements which is/are true about the emitted radiation is _______ . (Given: h=6×10−34h=6\times10^{-34}h=6×10−34 Js, me=9×10−31m_e=9\times10^{-31}me​=9×10−31 kg) (A) The deBroglie wavelength of the electron is 666.67666.67666.67 nm. (B) The characteristic of electrons emitted depend upon the material of the electrodes of the cathode ray tube. (C) The cathode rays start from cathode and move towards anode. (D) The nature of the emitted electrons depends on the nature of the gas present in cathode ray tube.

Correct answer: 2

Step-by-step solution →
Q53·ChemistryNumerical
A and B are two substances undergoing radioactive decay in a container. The half life of A is 15 min and that of B is 5 min. If the initial concentration of B is 4 times that of A and they both start decaying at the same time, how much time will it take for the concentration of both of them to be same? _______ min.

Correct answer: 15

Step-by-step solution →
Q54·ChemistryNumerical
Sum of oxidation states of bromine in bromic acid and perbromic acid is _______ .

Correct answer: 12

Step-by-step solution →
Q55·ChemistryNumerical
25 mL of an aqueous solution of KCl was found to require 20 mL of 1 M AgNO3\text{AgNO}_3AgNO3​ solution when titrated using K2CrO4\text{K}_2\text{CrO}_4K2​CrO4​ as an indicator. What is the depression in freezing point of KCl solution of the given concentration? _______ (Nearest integer). (Given: Kf=2.0K_f=2.0Kf​=2.0 K kg mol−1^{-1}−1) Assume (1) 100% ionization and (2) density of the aqueous solution as 111 g mL−1^{-1}−1.

Correct answer: 3

Step-by-step solution →
Q56·ChemistryNumerical
At 25∘^\circ∘C, the enthalpies of the following processes are given: H2(g)+O2(g)→2OH(g)\text{H}_2(g)+\text{O}_2(g)\rightarrow 2\text{OH}(g)H2​(g)+O2​(g)→2OH(g), ΔH∘=78\Delta H^\circ=78ΔH∘=78 kJ mol−1^{-1}−1; H2(g)+12O2(g)→H2O(g)\text{H}_2(g)+\tfrac{1}{2}\text{O}_2(g)\rightarrow \text{H}_2\text{O}(g)H2​(g)+21​O2​(g)→H2​O(g), ΔH∘=−242\Delta H^\circ=-242ΔH∘=−242 kJ mol−1^{-1}−1; H2(g)→2H(g)\text{H}_2(g)\rightarrow 2\text{H}(g)H2​(g)→2H(g), ΔH∘=436\Delta H^\circ=436ΔH∘=436 kJ mol−1^{-1}−1; 12O2(g)→O(g)\tfrac{1}{2}\text{O}_2(g)\rightarrow \text{O}(g)21​O2​(g)→O(g), ΔH∘=249\Delta H^\circ=249ΔH∘=249 kJ mol−1^{-1}−1. What would be the value of X for the reaction H2O(g)→H(g)+OH(g)\text{H}_2\text{O}(g)\rightarrow \text{H}(g)+\text{OH}(g)H2​O(g)→H(g)+OH(g), ΔH∘=X kJ mol−1\Delta H^\circ=\text{X kJ mol}^{-1}ΔH∘=X kJ mol−1? _______ (Nearest integer).

Correct answer: 499

Step-by-step solution →
Q57·ChemistryNumerical
At what pH, the given half cell MnO4−(0.1 M) ∣ Mn2+(0.001 M)\text{MnO}_4^-(0.1\,\text{M})\,|\,\text{Mn}^{2+}(0.001\,\text{M})MnO4−​(0.1M)∣Mn2+(0.001M) will have electrode potential of 1.2821.2821.282 V? _______ (Nearest Integer). (Given EMnO4−∣Mn2+∘=1.54E^\circ_{\text{MnO}_4^-|\text{Mn}^{2+}}=1.54EMnO4−​∣Mn2+∘​=1.54 V, 2.303RTF=0.059\tfrac{2.303RT}{F}=0.059F2.303RT​=0.059 V).

Correct answer: 3

Step-by-step solution →
Q58·ChemistryNumerical
The density of 3 M solution of NaCl\text{NaCl}NaCl is 1.01.01.0 g mL−1^{-1}−1. Molality of the solution is _______ ×10−2\times10^{-2}×10−2 m (Nearest integer). (Given: molar mass of Na\text{Na}Na and Cl\text{Cl}Cl is 23 and 35.535.535.5 g mol−1^{-1}−1 respectively).

Correct answer: 364

Step-by-step solution →
Q59·ChemistryNumerical
The number of isomeric compounds with molecular formula C9H10O\text{C}_9\text{H}_{10}\text{O}C9​H10​O which (i) do not dissolve in NaOH (ii) do not dissolve in HCl (iii) do not give orange precipitate with 2,4-DNP (iv) on hydrogenation give identical compound with molecular formula C9H12O\text{C}_9\text{H}_{12}\text{O}C9​H12​O is _______ .

Correct answer: 2

Step-by-step solution →
Q60·Chemistry·IsomerismNumerical
The total number of chiral compound/s from the compounds shown in the figure is _______ .

Correct answer: 3

Step-by-step solution →

Mathematics — JEE Main 1 February 2023 Shift 1

Q61·MathematicsSingle correct
If y=y(x)y=y(x)y=y(x) is the solution curve of the differential equation dydx+ytan⁡x=xsec⁡x\frac{dy}{dx}+y\tan x=x\sec xdxdy​+ytanx=xsecx, 0≤x≤π30\le x\le\frac{\pi}{3}0≤x≤3π​, y(0)=1y(0)=1y(0)=1, then y ⁣(π6)y\!\left(\frac{\pi}{6}\right)y(6π​) is equal to
  1. (A)π12−32log⁡e ⁣(23e)\frac{\pi}{12}-\frac{\sqrt{3}}{2}\log_e\!\left(\frac{2\sqrt{3}}{e}\right)12π​−23​​loge​(e23​​)
  2. (B)π12−32log⁡e ⁣(2e3)\frac{\pi}{12}-\frac{\sqrt{3}}{2}\log_e\!\left(\frac{2}{e\sqrt{3}}\right)12π​−23​​loge​(e3​2​)
  3. (C)π12+32log⁡e ⁣(2e3)\frac{\pi}{12}+\frac{\sqrt{3}}{2}\log_e\!\left(\frac{2}{e\sqrt{3}}\right)12π​+23​​loge​(e3​2​)
  4. (D)π12+32log⁡e ⁣(23e)\frac{\pi}{12}+\frac{\sqrt{3}}{2}\log_e\!\left(\frac{2\sqrt{3}}{e}\right)12π​+23​​loge​(e23​​)

Correct answer: (B)

Step-by-step solution →
Q62·MathematicsSingle correct
Let RRR be a relation on R\mathbb{R}R, given by R={(a,b):3a−3b+7 is an irrational number}R=\{(a,b):3a-3b+\sqrt{7}\text{ is an irrational number}\}R={(a,b):3a−3b+7​ is an irrational number}. Then RRR is
  1. (A)an equivalence relation
  2. (B)reflexive and symmetric but not transitive
  3. (C)reflexive but neither symmetric nor transitive
  4. (D)reflexive and transitive but not symmetric

Correct answer: (C)

Step-by-step solution →
Q63·MathematicsSingle correct
For a triangle ABCABCABC, the value of cos⁡2A+cos⁡2B+cos⁡2C\cos 2A+\cos 2B+\cos 2Ccos2A+cos2B+cos2C is least. If its inradius is 333 and incentre is MMM, then which of the following is NOT correct?
  1. (A)perimeter of △ABC\triangle ABC△ABC is 18318\sqrt{3}183​
  2. (B)sin⁡2A+sin⁡2B+sin⁡2C=sin⁡A+sin⁡B+sin⁡C\sin 2A+\sin 2B+\sin 2C=\sin A+\sin B+\sin Csin2A+sin2B+sin2C=sinA+sinB+sinC
  3. (C)MA→⋅MB→=−18\overrightarrow{MA}\cdot\overrightarrow{MB}=-18MA⋅MB=−18
  4. (D)area of △ABC\triangle ABC△ABC is 2732\frac{27\sqrt{3}}{2}2273​​

Correct answer: (D)

Step-by-step solution →
Q64·MathematicsSingle correct
Let SSS be the set of all solutions of the equation cos⁡−1(2x)−2cos⁡−1 ⁣(1−x2)=π\cos^{-1}(2x)-2\cos^{-1}\!\left(\sqrt{1-x^2}\right)=\picos−1(2x)−2cos−1(1−x2​)=π, x∈[−12,12]x\in\left[-\tfrac{1}{2},\tfrac{1}{2}\right]x∈[−21​,21​]. Then ∑x∈S2sin⁡−1 ⁣(x2−1)\sum_{x\in S}2\sin^{-1}\!\left(x^2-1\right)∑x∈S​2sin−1(x2−1) is equal to
  1. (A)π−2sin⁡−1 ⁣(34)\pi-2\sin^{-1}\!\left(\frac{\sqrt{3}}{4}\right)π−2sin−1(43​​)
  2. (B)π−sin⁡−1 ⁣(34)\pi-\sin^{-1}\!\left(\frac{\sqrt{3}}{4}\right)π−sin−1(43​​)
  3. (C)−2π3\frac{-2\pi}{3}3−2π​
  4. (D)000

Correct answer: (A)

Step-by-step solution →
Q65·MathematicsSingle correct
Let SSS denote the set of all real values of λ\lambdaλ such that the system of equations λx+y+z=1\lambda x+y+z=1λx+y+z=1, x+λy+z=1x+\lambda y+z=1x+λy+z=1, x+y+λz=1x+y+\lambda z=1x+y+λz=1 is inconsistent, then ∑λ∈S(∣λ∣2+∣λ∣)\sum_{\lambda\in S}\left(|\lambda|^2+|\lambda|\right)∑λ∈S​(∣λ∣2+∣λ∣) is equal to
  1. (A)444
  2. (B)121212
  3. (C)666
  4. (D)222

Correct answer: (C)

Step-by-step solution →
Q66·MathematicsSingle correct
In a binomial distribution B(n,p)B(n,p)B(n,p), the sum and the product of the mean and the variance are 555 and 666 respectively, then 6(n+p−q)6(n+p-q)6(n+p−q) is equal to
  1. (A)525252
  2. (B)505050
  3. (C)515151
  4. (D)535353

Correct answer: (A)

Step-by-step solution →
Q67·MathematicsSingle correct
The combined equation of the two lines ax+by+c=0ax+by+c=0ax+by+c=0 and a′x+b′y+c′=0a'x+b'y+c'=0a′x+b′y+c′=0 can be written as (ax+by+c)(a′x+b′y+c′)=0(ax+by+c)(a'x+b'y+c')=0(ax+by+c)(a′x+b′y+c′)=0. The equation of the angle bisectors of the lines represented by the equation 2x2+xy−3y2=02x^2+xy-3y^2=02x2+xy−3y2=0 is
  1. (A)x2−y2−10xy=0x^2-y^2-10xy=0x2−y2−10xy=0
  2. (B)x2−y2+10xy=0x^2-y^2+10xy=0x2−y2+10xy=0
  3. (C)3x2+5xy+2y2=03x^2+5xy+2y^2=03x2+5xy+2y2=0
  4. (D)3x2+xy−2y2=03x^2+xy-2y^2=03x2+xy−2y2=0

Correct answer: (A)

Step-by-step solution →
Q68·MathematicsSingle correct
The area enclosed by the closed curve CCC given by the differential equation dydx+x+ay−2=0\frac{dy}{dx}+\frac{x+a}{y-2}=0dxdy​+y−2x+a​=0, y(1)=0y(1)=0y(1)=0 is 4π4\pi4π. Let PPP and QQQ be the points of intersection of the curve CCC and the yyy-axis. If normals at PPP and QQQ on the curve CCC intersect xxx-axis at points RRR and SSS respectively, then the length of the line segment RSRSRS is
  1. (A)222
  2. (B)433\frac{4\sqrt{3}}{3}343​​
  3. (C)232\sqrt{3}23​
  4. (D)233\frac{2\sqrt{3}}{3}323​​

Correct answer: (B)

Step-by-step solution →
Q69·MathematicsSingle correct
The value of 11! 50!+13! 48!+15! 46!+⋯+149! 2!+151! 1!\frac{1}{1!\,50!}+\frac{1}{3!\,48!}+\frac{1}{5!\,46!}+\cdots+\frac{1}{49!\,2!}+\frac{1}{51!\,1!}1!50!1​+3!48!1​+5!46!1​+⋯+49!2!1​+51!1!1​ is
  1. (A)25051!\frac{2^{50}}{51!}51!250​
  2. (B)25150!\frac{2^{51}}{50!}50!251​
  3. (C)25050!\frac{2^{50}}{50!}50!250​
  4. (D)25151!\frac{2^{51}}{51!}51!251​

Correct answer: (A)

Step-by-step solution →
Q70·MathematicsSingle correct
The mean and variance of 555 observations are 555 and 888 respectively. If 333 observations are 1,3,51, 3, 51,3,5 then the sum of cubes of the remaining two observations is
  1. (A)121612161216
  2. (B)107210721072
  3. (C)145614561456
  4. (D)179217921792

Correct answer: (B)

Step-by-step solution →
Q71·MathematicsSingle correct
The sum to 101010 terms of the series 11+12+14+21+22+24+31+32+34+⋯\frac{1}{1+1^2+1^4}+\frac{2}{1+2^2+2^4}+\frac{3}{1+3^2+3^4}+\cdots1+12+141​+1+22+242​+1+32+343​+⋯ is
  1. (A)55111\frac{55}{111}11155​
  2. (B)56111\frac{56}{111}11156​
  3. (C)58111\frac{58}{111}11158​
  4. (D)59111\frac{59}{111}11159​

Correct answer: (A)

Step-by-step solution →
Q72·MathematicsSingle correct
The shortest distance between the lines x−51=y−22=z−4−3\frac{x-5}{1}=\frac{y-2}{2}=\frac{z-4}{-3}1x−5​=2y−2​=−3z−4​ and x+31=y+54=z−1−5\frac{x+3}{1}=\frac{y+5}{4}=\frac{z-1}{-5}1x+3​=4y+5​=−5z−1​ is
  1. (A)535\sqrt{3}53​
  2. (B)737\sqrt{3}73​
  3. (C)636\sqrt{3}63​
  4. (D)434\sqrt{3}43​

Correct answer: (C)

Step-by-step solution →
Q73·MathematicsSingle correct
lim⁡n→∞[11+n+12+n+13+n+⋯+12n]\lim_{n\to\infty}\left[\frac{1}{1+n}+\frac{1}{2+n}+\frac{1}{3+n}+\cdots+\frac{1}{2n}\right]limn→∞​[1+n1​+2+n1​+3+n1​+⋯+2n1​] is equal to
  1. (A)log⁡e2\log_e 2loge​2
  2. (B)log⁡e ⁣(23)\log_e\!\left(\frac{2}{3}\right)loge​(32​)
  3. (C)log⁡e ⁣(32)\log_e\!\left(\frac{3}{2}\right)loge​(23​)
  4. (D)000

Correct answer: (A)

Step-by-step solution →
Q74·MathematicsSingle correct
Let the image of the point P(2,−1,3)P(2,-1,3)P(2,−1,3) in the plane x+2y−z=0x+2y-z=0x+2y−z=0 be QQQ. Then the distance of the plane 3x+2y+z+29=03x+2y+z+29=03x+2y+z+29=0 from the point QQQ is
  1. (A)2427\frac{24\sqrt{2}}{7}7242​​
  2. (B)2142\sqrt{14}214​
  3. (C)3143\sqrt{14}314​
  4. (D)2227\frac{22\sqrt{2}}{7}7222​​

Correct answer: (C)

Step-by-step solution →
Q75·MathematicsSingle correct
Let f(x)=2x+tan⁡−1xf(x)=2x+\tan^{-1}xf(x)=2x+tan−1x and g(x)=log⁡e ⁣(1+x2+x)g(x)=\log_e\!\left(\sqrt{1+x^2}+x\right)g(x)=loge​(1+x2​+x), x∈[0,3]x\in[0,3]x∈[0,3]. Then
  1. (A)min⁡f′(x)=1+max⁡g′(x)\min f'(x)=1+\max g'(x)minf′(x)=1+maxg′(x)
  2. (B)max⁡f′(x)>max⁡g′(x)\max f'(x)>\max g'(x)maxf′(x)>maxg′(x)
  3. (C)there exist 0<x1<x2<30<x_1<x_2<30<x1​<x2​<3 such that f(x)<g(x), ∀x∈(x1,x2)f(x)<g(x),\ \forall x\in(x_1,x_2)f(x)<g(x), ∀x∈(x1​,x2​)
  4. (D)there exists x^∈[0,3]\hat{x}\in[0,3]x^∈[0,3] such that f′(x^)<g′(x^)f'(\hat{x})<g'(\hat{x})f′(x^)<g′(x^)

Correct answer: (B)

Step-by-step solution →
Q76·MathematicsSingle correct
If the orthocentre of the triangle, whose vertices are (1,2)(1,2)(1,2), (2,3)(2,3)(2,3) and (3,1)(3,1)(3,1) is (α,β)(\alpha,\beta)(α,β), then the quadratic equation whose roots are α+4β\alpha+4\betaα+4β and 4α+β4\alpha+\beta4α+β, is
  1. (A)x2−20x+99=0x^2-20x+99=0x2−20x+99=0
  2. (B)x2−19x+90=0x^2-19x+90=0x2−19x+90=0
  3. (C)x2−22x+120=0x^2-22x+120=0x2−22x+120=0
  4. (D)x2−18x+80=0x^2-18x+80=0x2−18x+80=0

Correct answer: (A)

Step-by-step solution →
Q77·MathematicsSingle correct
Let S={x:x∈R and (3+2)x2−4+(3−2)x2−4=10}S=\{x:x\in\mathbb{R}\text{ and }(\sqrt{3}+\sqrt{2})^{x^2-4}+(\sqrt{3}-\sqrt{2})^{x^2-4}=10\}S={x:x∈R and (3​+2​)x2−4+(3​−2​)x2−4=10}. Then n(S)n(S)n(S) is equal to
  1. (A)444
  2. (B)000
  3. (C)666
  4. (D)222

Correct answer: (A)

Step-by-step solution →
Q78·MathematicsSingle correct
If the center and radius of the circle ∣z−2z−3∣=2\left|\frac{z-2}{z-3}\right|=2​z−3z−2​​=2 are respectively (α,β)(\alpha,\beta)(α,β) and γ\gammaγ, then 3(α+β+γ)3(\alpha+\beta+\gamma)3(α+β+γ) is equal to
  1. (A)111111
  2. (B)121212
  3. (C)999
  4. (D)101010

Correct answer: (B)

Step-by-step solution →
Q79·MathematicsSingle correct
Let f(x)=∣1+sin⁡2xcos⁡2xsin⁡2xsin⁡2x1+cos⁡2xsin⁡2xsin⁡2xcos⁡2x1+sin⁡2x∣f(x)=\begin{vmatrix}1+\sin^2 x & \cos^2 x & \sin 2x\\ \sin^2 x & 1+\cos^2 x & \sin 2x\\ \sin^2 x & \cos^2 x & 1+\sin 2x\end{vmatrix}f(x)=​1+sin2xsin2xsin2x​cos2x1+cos2xcos2x​sin2xsin2x1+sin2x​​, x∈[π6,π3]x\in\left[\frac{\pi}{6},\frac{\pi}{3}\right]x∈[6π​,3π​]. If α\alphaα and β\betaβ respectively are the maximum and the minimum values of fff, then
  1. (A)α2+β2=92\alpha^2+\beta^2=\frac{9}{2}α2+β2=29​
  2. (B)β2−2α=194\beta^2-2\sqrt{\alpha}=\frac{19}{4}β2−2α​=419​
  3. (C)α2−β2=43\alpha^2-\beta^2=4\sqrt{3}α2−β2=43​
  4. (D)β2+2α=194\beta^2+2\sqrt{\alpha}=\frac{19}{4}β2+2α​=419​

Correct answer: (B)

Step-by-step solution →
Q80·MathematicsSingle correct
The negation of the expression q∨((∼q)∧p)q\vee((\sim q)\wedge p)q∨((∼q)∧p) is equivalent to
  1. (A)(∼p)∨(∼q)(\sim p)\vee(\sim q)(∼p)∨(∼q)
  2. (B)p∧(∼q)p\wedge(\sim q)p∧(∼q)
  3. (C)(∼p)∨q(\sim p)\vee q(∼p)∨q
  4. (D)(∼p)∧(∼q)(\sim p)\wedge(\sim q)(∼p)∧(∼q)

Correct answer: (D)

Step-by-step solution →
Q81·MathematicsNumerical
Let v⃗=αi^+2j^−3k^\vec{v}=\alpha\hat{i}+2\hat{j}-3\hat{k}v=αi^+2j^​−3k^, w⃗=2αi^+j^−k^\vec{w}=2\alpha\hat{i}+\hat{j}-\hat{k}w=2αi^+j^​−k^ and u⃗\vec{u}u be a vector such that ∣u⃗∣=α>0|\vec{u}|=\alpha>0∣u∣=α>0. If the minimum value of the scalar triple product [u⃗ v⃗ w⃗][\vec{u}\ \vec{v}\ \vec{w}][u v w] is −α3401-\alpha\sqrt{3401}−α3401​, and ∣u⃗⋅i^∣2=mn|\vec{u}\cdot\hat{i}|^2=\frac{m}{n}∣u⋅i^∣2=nm​ where mmm and nnn are coprime natural numbers, then m+nm+nm+n is equal to _______ .

Correct answer: 3501

Step-by-step solution →
Q82·MathematicsNumerical
The number of words, with or without meaning, that can be formed using all the letters of the word ASSASSINATION so that the vowels occur together, is _______ .

Correct answer: 50400

Step-by-step solution →
Q83·MathematicsNumerical
The remainder, when 19200+2320019^{200}+23^{200}19200+23200 is divided by 494949, is _______ .

Correct answer: 29

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Q84·MathematicsNumerical
The number of 333-digit numbers, that are divisible by either 222 or 333 but not divisible by 777, is _______ .

Correct answer: 514

Step-by-step solution →
Q85·MathematicsNumerical
Let f:R→Rf:\mathbb{R}\to\mathbb{R}f:R→R be a differentiable function such that f′(x)+f(x)=∫02f(t) dtf'(x)+f(x)=\int_0^2 f(t)\,dtf′(x)+f(x)=∫02​f(t)dt. If f(0)=e−2f(0)=e^{-2}f(0)=e−2, then 2f(0)−f(2)2f(0)-f(2)2f(0)−f(2) is equal to _______ .

Correct answer: 1

Step-by-step solution →
Q86·MathematicsNumerical
If f(x)=x2+g′(1)x+g′′(2)f(x)=x^2+g'(1)x+g''(2)f(x)=x2+g′(1)x+g′′(2) and g(x)=f(1)x2+xf′(x)+f′′(x)g(x)=f(1)x^2+xf'(x)+f''(x)g(x)=f(1)x2+xf′(x)+f′′(x), then the value of f(4)−g(4)f(4)-g(4)f(4)−g(4) is equal to _______ .

Correct answer: 14

Step-by-step solution →
Q87·MathematicsNumerical
Let AAA be the area bounded by the curve y=x∣x−3∣y=x|x-3|y=x∣x−3∣, the xxx-axis and the ordinates x=−1x=-1x=−1 and x=2x=2x=2. Then 12A12A12A is equal to _______ .

Correct answer: 62

Step-by-step solution →
Q88·MathematicsNumerical
If ∫01(x21+x14+x7)(2x14+3x7+6)1/7 dx=1l(11)m/n\int_0^1 (x^{21}+x^{14}+x^7)(2x^{14}+3x^7+6)^{1/7}\,dx=\frac{1}{l}(11)^{m/n}∫01​(x21+x14+x7)(2x14+3x7+6)1/7dx=l1​(11)m/n where l,m,n∈Nl,m,n\in\mathbb{N}l,m,n∈N, mmm and nnn are coprime, then l+m+nl+m+nl+m+n is equal to _______ .

Correct answer: 63

Step-by-step solution →
Q89·MathematicsNumerical
Let a1,a2,a3,…,ana_1, a_2, a_3, \ldots, a_na1​,a2​,a3​,…,an​ be in A.P. If the sum of its first four terms is 505050 and the sum of its last four terms is 170170170, then the product of its middle two terms is _______ .

Correct answer: 754

Step-by-step solution →
Q90·MathematicsNumerical
A(2,6,2)A(2,6,2)A(2,6,2), B(−4,0,λ)B(-4,0,\lambda)B(−4,0,λ), C(2,3,−1)C(2,3,-1)C(2,3,−1) and D(4,5,0)D(4,5,0)D(4,5,0), ∣λ∣≤5|\lambda|\le 5∣λ∣≤5 are the vertices of a quadrilateral ABCDABCDABCD. If its area is 181818 square units, then 5−6λ5-6\lambda5−6λ is equal to _______ .

Correct answer: 11

Step-by-step solution →

Chapters tested in this paper

Open any chapter to practise every past-year question on that topic across all papers, and see how often it has actually appeared.

  • Properties of Solids and Liquids 172/186
  • Three Dimensional Geometry 176/186
  • Matrices and Determinants 180/186
  • Coordination Compounds 176/186
  • Sets, Relations and Functions 165/186
  • Current Electricity 160/186
  • Sequence and Series 164/186
  • p-Block Elements 164/186
  • Definite Integration 168/186
  • Rotational Motion 172/186
  • Redox Reactions and Electrochemistry 177/186
  • Geometrical Optics 172/186
  • Kinematics 156/186
  • Vector Algebra 173/186
  • Differential Equations 167/186
  • Probability 176/186
  • Permutations and Combinations 162/186
  • Magnetic Field of Current 147/186
  • Binomial Theorem and Its Simple Applications 158/186
  • Electromagnetic Waves 144/186
  • Chemical Bonding and Molecular Structure 151/186
  • Application of Derivatives 139/186
  • d- and f-Block Elements 126/186
  • Thermodynamics 154/186
  • Aldehydes and Ketones 135/186
  • Equilibrium 163/186
  • Solutions 158/186
  • Laws of Motion 130/186
  • Chemical Thermodynamics 165/186
  • Units and Measurements 149/186
  • Hydrocarbons 126/186
  • Complex Numbers 165/186
  • Trigonometric Functions 144/186
  • Biomolecules 162/186
  • Chemical Kinetics 169/186
  • Gravitation 152/186
  • Electric Field and Coulomb's Law 133/186
  • Atomic Structure 161/186
  • Electronic Devices 145/186
  • Dual Nature of Matter and Radiation 155/186
  • Amines 133/186
  • Quadratic Equations 148/186
  • Work, Energy and Power 132/186
  • Electromagnetic Induction 120/186
  • Wave Optics 130/186
  • Area Under Curves 139/186
  • Kinetic Theory of Gases 135/186
  • Alcohols and Ethers 106/186
  • Purification and Characterisation of Organic Compounds 116/186
  • Oscillations 117/186
  • Alternating Currents 108/186
  • Nuclei 116/186
  • Organic Compounds Containing Halogens 109/186
  • Straight Lines 114/186
  • Waves 109/186
  • Atoms 112/186
  • Statistics 118/186
  • Isolation of Metals 106/186
  • s-Block Elements 88/186
  • Inverse Trigonometric Functions 93/186
  • Environmental Chemistry 83/186
  • Hydrogen 81/186
  • Solid State 63/186
  • Chemistry in Everyday Life 60/186
  • Isomerism 51/186
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