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JEE Main 13 April 2023 Shift 1 Question Paper with Answers

13 April 2023 · April session · 90 questions

The complete JEE Main 13 April 2023 Shift 1 paper — all 90 questions with the correct answer for each, tagged to the chapter it tests. Free to read, no account needed.

Physics
30
Chemistry
30
Mathematics
30

Physics — JEE Main 13 April 2023 Shift 1

Q1·PhysicsSingle correct
Which of the following Maxwell's equations is valid for time varying conditions but not valid for static conditions:
  1. (A)∮B⃗⋅dl⃗=μ0I\displaystyle\oint\vec B\cdot d\vec l=\mu_{0}I∮B⋅dl=μ0​I
  2. (B)∮E⃗⋅dl⃗=0\displaystyle\oint\vec E\cdot d\vec l=0∮E⋅dl=0
  3. (C)∮E⃗⋅dl⃗=−∂ΦB∂t\displaystyle\oint\vec E\cdot d\vec l=-\dfrac{\partial\Phi_{B}}{\partial t}∮E⋅dl=−∂t∂ΦB​​
  4. (D)∮D⃗⋅dA⃗=Q\displaystyle\oint\vec D\cdot d\vec A=Q∮D⋅dA=Q

Correct answer: (C)

Step-by-step solution →
Q2·PhysicsSingle correct
Different combinations of 333 resistors of equal resistance RRR are shown in the figures. The increasing order for power dissipation is:
  1. (A)PA<PB<PC<PDP_{A}<P_{B}<P_{C}<P_{D}PA​<PB​<PC​<PD​
  2. (B)PC<PD<PA<PBP_{C}<P_{D}<P_{A}<P_{B}PC​<PD​<PA​<PB​
  3. (C)PB<PD<PC<PAP_{B}<P_{D}<P_{C}<P_{A}PB​<PD​<PC​<PA​
  4. (D)PA<PC<PD<PBP_{A}<P_{C}<P_{D}<P_{B}PA​<PC​<PD​<PB​

Correct answer: (D)

Step-by-step solution →
Q3·PhysicsSingle correct
A vessel of depth ′d′'d'′d′ is half filled with oil of refractive index n1n_{1}n1​ and the other half is filled with water of refractive index n2n_{2}n2​. The apparent depth of this vessel when viewed from above will be:
  1. (A)d n1n2(n1+n2)\dfrac{d\,n_{1}n_{2}}{(n_{1}+n_{2})}(n1​+n2​)dn1​n2​​
  2. (B)d(n1+n2)2n1n2\dfrac{d(n_{1}+n_{2})}{2n_{1}n_{2}}2n1​n2​d(n1​+n2​)​
  3. (C)d n1n22(n1+n2)\dfrac{d\,n_{1}n_{2}}{2(n_{1}+n_{2})}2(n1​+n2​)dn1​n2​​
  4. (D)2d(n1+n2)n1n2\dfrac{2d(n_{1}+n_{2})}{n_{1}n_{2}}n1​n2​2d(n1​+n2​)​

Correct answer: (B)

Step-by-step solution →
Q4·PhysicsSingle correct
The source of time varying magnetic field may be: (A) A permanent magnet (B) An electric field changing linearly with time (C) Direct current (D) A decelerating charge particle (E) An antenna fed with a digital signal Choose the correct answer from the options given below:
  1. (A)(D) only
  2. (B)(C) and (E) only
  3. (C)(A) only
  4. (D)(B) and (D) only

Correct answer: (A)

Step-by-step solution →
Q5·PhysicsSingle correct
Two trains 'A' and 'B' of length ′l′'l'′l′ and ′4l′'4l'′4l′ are travelling into a tunnel of length ′L′'L'′L′ in parallel tracks from opposite directions with velocities 108 km/h108\,km/h108km/h and 72 km/h72\,km/h72km/h respectively. If train 'A' takes 35 s35\,s35s less time than train 'B' to cross the tunnel, then length 'L' of the tunnel is: (Given L=60 lL=60\,lL=60l)
  1. (A)1200 m1200\,m1200m
  2. (B)2200 m2200\,m2200m
  3. (C)1800 m1800\,m1800m
  4. (D)900 m900\,m900m

Correct answer: (C)

Step-by-step solution →
Q6·PhysicsSingle correct
The ratio of powers of two motors is 3xx+1\dfrac{3\sqrt x}{\sqrt x+1}x​+13x​​, that are capable of raising 300 kg300\,kg300kg of water in 555 minutes and 50 kg50\,kg50kg of water in 222 minutes respectively from a well of 100 m100\,m100m deep. The value of xxx will be:
  1. (A)222
  2. (B)444
  3. (C)2.42.42.4
  4. (D)161616

Correct answer: (D)

Step-by-step solution →
Q7·PhysicsSingle correct
A planet having mass 9 Me9\,M_{e}9Me​ and radius 4 Re4\,R_{e}4Re​, where MeM_{e}Me​ and ReR_{e}Re​ are mass and radius of earth respectively, has escape velocity in km/skm/skm/s given by: (Given escape velocity on earth Ve=11.2×103 m/sV_{e}=11.2\times10^{3}\,m/sVe​=11.2×103m/s)
  1. (A)67.267.267.2
  2. (B)16.816.816.8
  3. (C)33.633.633.6
  4. (D)11.211.211.2

Correct answer: (B)

Step-by-step solution →
Q8·PhysicsSingle correct
The difference between threshold wavelengths for two metal surfaces AAA and BBB having work function φA=9 eV\varphi_{A}=9\,eVφA​=9eV and φB=4.5 eV\varphi_{B}=4.5\,eVφB​=4.5eV in nm is: (Given, hc=1242 eV nmhc=1242\,eV\,nmhc=1242eVnm)
  1. (A)264264264
  2. (B)138138138
  3. (C)276276276
  4. (D)540540540

Correct answer: (B)

Step-by-step solution →
Q9·PhysicsSingle correct
A bullet 10 g10\,g10g leaves the barrel of gun with a velocity of 600 m/s600\,m/s600m/s. If the barrel of gun is 50 cm50\,cm50cm long and mass of gun is 3 kg3\,kg3kg, then value of impulse supplied to the gun will be:
  1. (A)12 Ns12\,Ns12Ns
  2. (B)6 Ns6\,Ns6Ns
  3. (C)36 Ns36\,Ns36Ns
  4. (D)3 Ns3\,Ns3Ns

Correct answer: (B)

Step-by-step solution →
Q10·PhysicsSingle correct
Two charges each of magnitude 0.01 C0.01\,C0.01C and separated by a distance of 0.4 m0.4\,m0.4m constitute an electric dipole. If the dipole is placed in an uniform electric field E⃗\vec EE of 10 dyne/C10\,dyne/C10dyne/C making 30∘30^\circ30∘ angle with E⃗\vec EE, the magnitude of torque acting on the dipole is:
  1. (A)4.0×10−5 Nm4.0\times10^{-5}\,Nm4.0×10−5Nm
  2. (B)2.0×10−5 Nm2.0\times10^{-5}\,Nm2.0×10−5Nm
  3. (C)4.0×10−8 Nm4.0\times10^{-8}\,Nm4.0×10−8Nm
  4. (D)1.5×10−5 Nm1.5\times10^{-5}\,Nm1.5×10−5Nm

Correct answer: (B)

Step-by-step solution →
Q11·PhysicsSingle correct
A disc is rolling without slipping on a surface. The radius of the disc is RRR. At t=0t=0t=0, the top most point on the disc is AAA as shown in figure. When the disc completes half of its rotation, the displacement of point AAA from its initial position is:
  1. (A)Rπ2+4R\sqrt{\pi^{2}+4}Rπ2+4​
  2. (B)Rπ2+1R\sqrt{\pi^{2}+1}Rπ2+1​
  3. (C)2R2R2R
  4. (D)2R1+4π22R\sqrt{1+4\pi^{2}}2R1+4π2​

Correct answer: (A)

Step-by-step solution →
Q12·PhysicsSingle correct
Match List I with List II. Choose the correct answer from the options given below:
List I (Layer of atmosphere)List II (Approximate height over earth's surface)
A.F1F_{1}F1​ LayerI.10 km10\,km10km
B.D LayerII.170−190 km170-190\,km170−190km
C.TroposphereIII.100 km100\,km100km
D.E LayerIV.65−75 km65-75\,km65−75km
  1. (A)A-III, B-IV, C-I, D-II
  2. (B)A-II, B-IV, C-III, D-I
  3. (C)A-II, B-I, C-IV, D-III
  4. (D)A-II, B-IV, C-I, D-III

Correct answer: (D)

Step-by-step solution →
Q13·PhysicsSingle correct
The rmsrmsrms speed of oxygen molecules in a vessel at particular temperature is (1+5x)1/2 v\left(1+\dfrac{5}{x}\right)^{1/2}\,v(1+x5​)1/2v, where vvv is the average speed of the molecule. The value of xxx will be: (Take π=227\pi=\dfrac{22}{7}π=722​)
  1. (A)282828
  2. (B)272727
  3. (C)888
  4. (D)444

Correct answer: (A)

Step-by-step solution →
Q14·PhysicsSingle correct
A body of mass (5±0.5) kg(5\pm 0.5)\,kg(5±0.5)kg is moving with a velocity of (20±0.4) m/s(20\pm 0.4)\,m/s(20±0.4)m/s. Its kinetic energy will be:
  1. (A)(1000±140) J(1000\pm 140)\,J(1000±140)J
  2. (B)(1000±0.14) J(1000\pm 0.14)\,J(1000±0.14)J
  3. (C)(500±0.14) J(500\pm 0.14)\,J(500±0.14)J
  4. (D)(500±140) J(500\pm 140)\,J(500±140)J

Correct answer: (A)

Step-by-step solution →
Q15·PhysicsSingle correct
Two bodies are having kinetic energies in the ratio 16:916:916:9. If they have same linear momentum, the ratio of their masses respectively is:
  1. (A)4:34:34:3
  2. (B)3:43:43:4
  3. (C)16:916:916:9
  4. (D)9:169:169:16

Correct answer: (D)

Step-by-step solution →
Q16·PhysicsSingle correct
The figure shows a liquid of given density flowing steadily in a horizontal tube of varying cross-section. Cross sectional areas at AAA is 1.5 cm21.5\,cm^{2}1.5cm2 and at BBB is 25 mm225\,mm^{2}25mm2. If the speed of the liquid at BBB is 60 cm/s60\,cm/s60cm/s then (PA−PB)(P_{A}-P_{B})(PA​−PB​) is: (Given PAP_{A}PA​ and PBP_{B}PB​ are liquid pressures at AAA and BBB points. Density ρ=1000 kg m−3\rho=1000\,kg\,m^{-3}ρ=1000kgm−3)
  1. (A)175 Pa175\,Pa175Pa
  2. (B)27 Pa27\,Pa27Pa
  3. (C)135 Pa135\,Pa135Pa
  4. (D)36 Pa36\,Pa36Pa

Correct answer: (A)

Step-by-step solution →
Q17·PhysicsSingle correct
Under isothermal condition, the pressure of a gas is given by P=aV−3P=aV^{-3}P=aV−3, where aaa is a constant and VVV is the volume of the gas. The bulk modulus at constant temperature is equal to:
  1. (A)P2\dfrac{P}{2}2P​
  2. (B)3P3P3P
  3. (C)2P2P2P
  4. (D)PPP

Correct answer: (B)

Step-by-step solution →
Q18·PhysicsSingle correct
For the following circuit and given inputs AAA and BBB, choose the correct option for output ′Y′'Y'′Y′:
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (D)

Step-by-step solution →
Q19·PhysicsSingle correct
Which graph represents the difference between total energy and potential energy of a particle executing SHM Vs its distance from mean position:
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (D)

Step-by-step solution →
Q20·PhysicsSingle correct
92238U→90234 ⁣Th+24 ⁣D+Q^{238}_{92}U\to ^{234}_{90}\!Th+^{4}_{2}\!D+Q92238​U→90234​Th+24​D+Q. In the above nuclear reaction, the approximate amount of energy released will be: [Given, mass of 92238U=238.05079×931.5 MeV/c2^{238}_{92}U=238.05079\times 931.5\,MeV/c^{2}92238​U=238.05079×931.5MeV/c2, mass of 90234Th=234.04363×931.5 MeV/c2^{234}_{90}Th=234.04363\times 931.5\,MeV/c^{2}90234​Th=234.04363×931.5MeV/c2, mass of 24D=4.00260×931.5 MeV/c2^{4}_{2}D=4.00260\times 931.5\,MeV/c^{2}24​D=4.00260×931.5MeV/c2]
  1. (A)3.82 MeV3.82\,MeV3.82MeV
  2. (B)5.9 MeV5.9\,MeV5.9MeV
  3. (C)2.12 MeV2.12\,MeV2.12MeV
  4. (D)4.25 MeV4.25\,MeV4.25MeV

Correct answer: (D)

Step-by-step solution →
Q21·PhysicsNumerical
The elastic potential energy stored in a steel wire of length 20 m20\,m20m stretched through 2 cm2\,cm2cm is 80 J80\,J80J. The cross sectional area of the wire is _____ mm2mm^{2}mm2. (Given, y=2.0×1011 Nm−2y=2.0\times10^{11}\,Nm^{-2}y=2.0×1011Nm−2)

Correct answer: 40

Step-by-step solution →
Q22·PhysicsNumerical
A potential V0V_{0}V0​ is applied across a uniform wire of resistance RRR. The power dissipation is P1P_{1}P1​. The wire is then cut into two equal parts and a potential of V0V_{0}V0​ is applied across the length of each half. The total power dissipation across two wires is P2P_{2}P2​. The ratio P2:P1P_{2}:P_{1}P2​:P1​ is x:1\sqrt x:1x​:1. The value of xxx is _____.

Correct answer: 16

Step-by-step solution →
Q23·PhysicsNumerical
At a given point of time the value of displacement of a simple harmonic oscillator is given as y=Acos⁡(30∘)y=A\cos(30^\circ)y=Acos(30∘). If amplitude is 40 cm40\,cm40cm and kinetic energy at that time is 200 J200\,J200J, the value of force constant is 1.0×10x Nm−11.0\times 10^{x}\,Nm^{-1}1.0×10xNm−1. The value of xxx is _____.

Correct answer: 4

Step-by-step solution →
Q24·PhysicsNumerical
When a resistance of 5 Ω5\,\Omega5Ω is shunted with a moving coil galvanometer, it shows a full scale deflection for a current of 250 mA250\,mA250mA, however when 1050 Ω1050\,\Omega1050Ω resistance is connected with it in series, it gives full scale deflection for 252525 volt. The resistance of galvanometer is _____ Ω\OmegaΩ.

Correct answer: 50

Step-by-step solution →
Q25·PhysicsNumerical
The radius of 2nd2^{nd}2nd orbit of He+He^{+}He+ of Bohr's model is r1r_{1}r1​ and that of fourth orbit of Be+3Be^{+3}Be+3 is represented as r2r_{2}r2​. Now the ratio r2r1\dfrac{r_{2}}{r_{1}}r1​r2​​ is x:1x:1x:1. The value of xxx is _____.

Correct answer: 2

Step-by-step solution →
Q26·PhysicsNumerical
A thin infinite sheet charge and an infinite line charge of respective charge densities +σ+\sigma+σ and +λ+\lambda+λ are placed parallel at 5 m5\,m5m distance from each other. Points 'P' and 'Q' are at 3π m\dfrac{3}{\pi}\,mπ3​m and 4π m\dfrac{4}{\pi}\,mπ4​m perpendicular distance from line charge towards sheet charge, respectively. ′EP′'E_{P}'′EP′​ and ′EQ′'E_{Q}'′EQ′​ are the magnitudes of resultant electric field intensities at point 'P' and 'Q', respectively. If EPEQ=4a\dfrac{E_{P}}{E_{Q}}=\dfrac{4}{a}EQ​EP​​=a4​ for 2∣σ∣=∣λ∣2|\sigma|=|\lambda|2∣σ∣=∣λ∣. Then the value of aaa is _____.

Correct answer: 6

Step-by-step solution →
Q27·PhysicsNumerical
In the given figure, an inductor and a resistor are connected in series with a battery of emf EEE volt. E22b J/s\dfrac{E^{2}}{2b}\,J/s2bE2​J/s represents the maximum rate at which the energy is stored in the magnetic field (inductor). The numerical value of ba\dfrac{b}{a}ab​ will be _____.

Correct answer: 25

Step-by-step solution →
Q28·PhysicsNumerical
A fish rising vertically upward with a uniform velocity of 8 ms−18\,ms^{-1}8ms−1, observes that a bird is diving vertically downward towards the fish with the velocity of 12 ms−112\,ms^{-1}12ms−1. If the refractive index of water is 43\dfrac{4}{3}34​, then the actual velocity of the diving bird to pick the fish, will be _____ ms−1ms^{-1}ms−1.

Correct answer: 3

Step-by-step solution →
Q29·PhysicsNumerical
A solid sphere is rolling on a horizontal plane without slipping. If the ratio of angular momentum about axis of rotation of the sphere to the total energy of moving sphere is π:22\pi:22π:22 then, the value of its angular speed will be _____ rad/s.

Correct answer: 4

Step-by-step solution →
Q30·PhysicsNumerical
From the given transfer characteristic of a transistor in CE configuration, the value of power gain of this configuration is 10x10^{x}10x, for RB=10 kΩR_{B}=10\,k\OmegaRB​=10kΩ and RC=1 kΩR_{C}=1\,k\OmegaRC​=1kΩ. The value of xxx is _____.

Correct answer: 3

Step-by-step solution →

Chemistry — JEE Main 13 April 2023 Shift 1

Q31·ChemistrySingle correct
In the reaction given below, ′A′'A'′A′ is:
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (A)

Step-by-step solution →
Q32·ChemistrySingle correct
Given below are two statements: Statement-I: Permutit process is more efficient compared to the synthetic resin method for the softening of water. Statement-II: Synthetic resin method results in the formation of soluble sodium salts. In the light of the above statements, choose the most appropriate answer from the options given below:
  1. (A)Both the Statements I and II are correct
  2. (B)Statement I is correct but Statement II is incorrect
  3. (C)Statement I is incorrect but Statement II is correct
  4. (D)Both the Statements I and II are incorrect

Correct answer: (D)

Step-by-step solution →
Q33·ChemistrySingle correct
The mismatched combinations are: A. Chlorophyll - Co B. Water hardness - EDTA C. Photography - [Ag(CN)2]−[Ag(CN)_{2}]^{-}[Ag(CN)2​]− D. Wilkinson catalyst - [(Ph3P)3 RhCl][(Ph_{3}P)_{3}\,RhCl][(Ph3​P)3​RhCl] E. Chelating ligand - D-Penicillamine Choose the correct answer from the options given below:
  1. (A)A and C Only
  2. (B)A and E Only
  3. (C)D and E Only
  4. (D)A, C and E Only

Correct answer: (A)

Step-by-step solution →
Q34·ChemistrySingle correct
In which of the following processes, the bond order increases and paramagnetic character changes to diamagnetic one?
  1. (A)O2→O2+O_{2}\to O_{2}^{+}O2​→O2+​
  2. (B)NO→NO+NO\to NO^{+}NO→NO+
  3. (C)N2→N2+N_{2}\to N_{2}^{+}N2​→N2+​
  4. (D)O2→O2−O_{2}\to O_{2}^{-}O2​→O2−​

Correct answer: (B)

Step-by-step solution →
Q35·ChemistrySingle correct
The incorrect statement from the following for borazine is:
  1. (A)It has electronic delocalization
  2. (B)It contains banana bonds
  3. (C)It can react with water
  4. (D)It is a cyclic compound

Correct answer: (C)

Step-by-step solution →
Q36·Chemistry·Electronic Effects and StabilitySingle correct
Among the following compounds, the one which shows highest dipole moment is:
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (A)

Step-by-step solution →
Q37·ChemistrySingle correct
Match Column-A with Column-B. Column-A: a. Nylon 6; b. Vulcanized Rubber; c. cis-1,4-polyisoprene; d. Polychloroprene Column-B: I. Natural Rubber; II. Cross Linked; III. Caprolactam; IV. Neoprene Choose the correct answer from option given below:
  1. (A)a → IV, b → III, c → II, d → I
  2. (B)a → III, b → IV, c → I, d → II
  3. (C)a → II, b → III, c → I, d → IV
  4. (D)a → III, b → II, c → I, d → IV

Correct answer: (D)

Step-by-step solution →
Q38·ChemistrySingle correct
In the above reaction, the left hand side and right hand side rings are named as ′A′'A'′A′ and ′B′'B'′B′ respectively. They undergo ring expansion. The correct statement for this reaction is:
  1. (A)Finally both rings will become six membered each
  2. (B)Finally both rings will become five membered each
  3. (C)Only ′A′'A'′A′ will become 666 membered
  4. (D)Ring expansion can go upto seven membered rings

Correct answer: (A)

Step-by-step solution →
Q39·ChemistrySingle correct
The radical which mainly causes ozone depletion in the presence of UV radiations is:
  1. (A)CH3∙CH_{3}^{\bullet}CH3∙​
  2. (B)NO∙NO^{\bullet}NO∙
  3. (C)Cl∙Cl^{\bullet}Cl∙
  4. (D)O˙H\dot{O}HO˙H

Correct answer: (C)

Step-by-step solution →
Q40·ChemistrySingle correct
In the following reaction ′X′'X'′X′ is: CH3−(CH2)2−CH3→Anhy. AlCl3/HCl, ΔXCH_3-(CH_2)_2-CH_3\xrightarrow{\text{Anhy. }AlCl_3/HCl,\,\Delta}XCH3​−(CH2​)2​−CH3​Anhy. AlCl3​/HCl,Δ​X (major product)
  1. (A)CH3−(CH2)3−CH3CH_3-(CH_2)_3-CH_3CH3​−(CH2​)3​−CH3​
  2. (B)Cl−CH2−(CH2)3−ClCl-CH_2-(CH_2)_3-ClCl−CH2​−(CH2​)3​−Cl
  3. (C)(CH3)2CH−(CH2)2−CH3(CH_3)_2CH-(CH_2)_2-CH_3(CH3​)2​CH−(CH2​)2​−CH3​
  4. (D)cyclohexane

Correct answer: (C)

Step-by-step solution →
Q41·ChemistrySingle correct
222-Methyl propyl bromide reacts with C2H5O−C_{2}H_{5}O^{-}C2​H5​O− and gives ′A′'A'′A′ whereas on reaction with C2H5OHC_{2}H_{5}OHC2​H5​OH it gives ′B′'B'′B′. The mechanism followed in these reactions and the products ′A′'A'′A′ and ′B′'B'′B′ respectively are:
  1. (A)SN2S_N 2SN​2; A = iso-butyl ethyl ether; SN1S_N 1SN​1; B = tert-butyl ethyl ether
  2. (B)SN1S_N 1SN​1; A = tert-butyl ethyl ether; SN2S_N 2SN​2; B = 2-butyl ethyl ether
  3. (C)SN1S_N 1SN​1; A = tert-butyl ethyl ether; SN2S_N 2SN​2; B = iso-butyl ethyl ether
  4. (D)SN2S_N 2SN​2; A = 222-butyl ethyl ether; SN1S_N 1SN​1; B = iso-butyl ethyl ether

Correct answer: (A)

Step-by-step solution →
Q42·ChemistrySingle correct
D-(+)(+)(+)-Glyceraldehyde →(iii) HNO3(i) HCN, (ii) H2O/H+\xrightarrow[\text{(iii) }HNO_3]{\text{(i) }HCN,\,\text{(ii) }H_2O/H^+}(i) HCN,(ii) H2​O/H+(iii) HNO3​​. The products formed in the above reaction are:
  1. (A)Two optically active products
  2. (B)One optically active and one meso product
  3. (C)One optically inactive and one meso product
  4. (D)Two optically inactive products

Correct answer: (B)

Step-by-step solution →
Q43·ChemistrySingle correct
Which one of the following is most likely a mismatch?
  1. (A)Zinc - Liquation
  2. (B)Titanium - van Arkel method
  3. (C)Nickel - Mond process
  4. (D)Copper - Electrolysis

Correct answer: (A)

Step-by-step solution →
Q44·ChemistrySingle correct
ClF5ClF_{5}ClF5​ at room temperature is a:
  1. (A)Colourless gas with trigonal bipyramidal geometry
  2. (B)Colourless gas with square pyramidal geometry
  3. (C)Colourless liquid with square pyramidal geometry
  4. (D)Colourless liquid with trigonal bipyramidal geometry

Correct answer: (C)

Step-by-step solution →
Q45·ChemistrySingle correct
Be(OH)2Be(OH)_{2}Be(OH)2​ reacts with Sr(OH)2Sr(OH)_{2}Sr(OH)2​ to yield an ionic salt. Choose the incorrect option related to this reaction from the following:
  1. (A)Be is tetrahedrally coordinated in the ionic salt.
  2. (B)The reaction is an example of acid - base neutralization reaction.
  3. (C)Both Sr and Be elements are present in the ionic salt.
  4. (D)The elements Be is present in the cationic part of the ionic salt.

Correct answer: (D)

Step-by-step solution →
Q46·ChemistrySingle correct
In the reaction given below, ′B′'B'′B′ is:
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (C)

Step-by-step solution →
Q47·ChemistrySingle correct
Which of the following statements are not correct? A. The electron gain enthalpy of FFF is more negative than that of ClClCl B. Ionization enthalpy decreases in a group of periodic table C. The electronegativity of an atom depends upon the atoms bonded to it D. Al2O3Al_{2}O_{3}Al2​O3​ and NONONO are examples of amphoteric oxides. Choose the most appropriate answer from the options given below:
  1. (A)A, B, C and D
  2. (B)A, C and D Only
  3. (C)B and D Only
  4. (D)A, B and D Only

Correct answer: (B)

Step-by-step solution →
Q48·ChemistrySingle correct
The energy of an electron in the first Bohr orbit of hydrogen atom is −2.18×10−18 J-2.18\times10^{-18}\,J−2.18×10−18J. Its energy in the third Bohr orbit is:
  1. (A)127\dfrac{1}{27}271​ of this value
  2. (B)One third of this value
  3. (C)Three times of this value
  4. (D)19\dfrac{1}{9}91​ th of this value

Correct answer: (D)

Step-by-step solution →
Q49·ChemistrySingle correct
What happens when a lyophilic sol is added to a lyophobic sol?
  1. (A)Lyophilic sol is dispersed in lyophobic sol
  2. (B)Film of lyophilic sol is formed over lyophobic sol
  3. (C)Lyophobic sol is coagulated
  4. (D)Film of lyophobic sol is formed over lyophilic sol

Correct answer: (B)

Step-by-step solution →
Q50·ChemistrySingle correct
The pair of lanthanides in which both elements have high third-ionization energy is:
  1. (A)Eu, Gd
  2. (B)Eu, Yb
  3. (C)Lu, Yb
  4. (D)Dy, Gd

Correct answer: (B)

Step-by-step solution →
Q51·ChemistryNumerical
For the given reaction  CH3−C(CH3)H3C−CH=CH−C(CH3)H3C−CH3 →H+ ′A′\,CH_3-\underset{H_3C}{C(CH_3)}-CH=CH-\underset{H_3C}{C(CH_3)}-CH_3\,\xrightarrow{H^+}\,'A'CH3​−H3​CC(CH3​)​−CH=CH−H3​CC(CH3​)​−CH3​H+​′A′. The total number of possible products formed by tertiary carbocation of A is _____.

Correct answer: 4

Step-by-step solution →
Q52·ChemistryNumerical
Solution of 12 g12\,g12g of non-electrolyte (A) prepared by dissolving it in 1000 mL1000\,mL1000mL of water exerts the same osmotic pressure as that of 0.05 M0.05\,M0.05M glucose solution at the same temperature. The empirical formula of AAA is CH2OCH_{2}OCH2​O. The molecular mass of A is _____ ggg. (Nearest integer)

Correct answer: 240

Step-by-step solution →
Q53·ChemistryNumerical
25.0 mL25.0\,mL25.0mL of 0.050 M Ba(NO3)20.050\,M\,Ba(NO_{3})_{2}0.050MBa(NO3​)2​ is mixed with 25.0 mL25.0\,mL25.0mL of 0.020 M NaF0.020\,M\,NaF0.020MNaF. KspK_{sp}Ksp​ of BaF2BaF_{2}BaF2​ is 0.5×10−60.5\times10^{-6}0.5×10−6 at 298 K298\,K298K. The ratio of [Ba2+][F−]2[Ba^{2+}][F^{-}]^{2}[Ba2+][F−]2 and KspK_{sp}Ksp​ is _____ (Nearest integer).

Correct answer: 5

Step-by-step solution →
Q54·ChemistryNumerical
A2+B2→2AB, ΔH∘=−200 kJ mol−1A_{2}+B_{2}\to 2AB,\,\Delta H^{\circ}=-200\,kJ\,mol^{-1}A2​+B2​→2AB,ΔH∘=−200kJmol−1. AB, A2A_{2}A2​ and B2B_{2}B2​ are diatomic molecule. If the bond enthalpies of A2, B2A_{2},\,B_{2}A2​,B2​ and AB are in the ratio 1:0.5:11:0.5:11:0.5:1, then the bond enthalpy of A2A_{2}A2​ is _____ kJ mol−1kJ\,mol^{-1}kJmol−1 (Nearest integer).

Correct answer: 400

Step-by-step solution →
Q55·ChemistryNumerical
An organic compound gives 0.220 g0.220\,g0.220g of CO2CO_{2}CO2​ and 0.126 g0.126\,g0.126g of H2OH_{2}OH2​O on complete combustion. If the %\%% of carbon is 242424 then the %\%% of hydrogen is _____ ×10−1\times 10^{-1}×10−1. (Nearest integer)

Correct answer: 56

Step-by-step solution →
Q56·ChemistryNumerical
20 mL20\,mL20mL of calcium hydroxide was consumed when it was reacted with 10 mL10\,mL10mL of unknown solution of H2SO4H_{2}SO_{4}H2​SO4​. Also 20 mL20\,mL20mL standard solution of 0.5 M HCl0.5\,M\,HCl0.5MHCl containing 222 drops of phenolphthalein was titrated with calcium hydroxide the mixture showed pink colour when burette displayed the value of 35.5 mL35.5\,mL35.5mL, whereas the burette showed 25.5 mL25.5\,mL25.5mL initially. The concentration of H2SO4H_{2}SO_{4}H2​SO4​ is _____ MMM (Nearest integer).

Correct answer: 1

Step-by-step solution →
Q57·ChemistryNumerical
A certain quantity of real gas occupies a volume of 0.15 dm30.15\,dm^{3}0.15dm3 at 100 atm100\,atm100atm and 500 K500\,K500K when its compressibility factor is 1.871.871.87. Its volume at 300 atm300\,atm300atm and 300 K300\,K300K (When its compressibility factor is 1.41.41.4) is _____ ×10−4 dm3\times10^{-4}\,dm^{3}×10−4dm3 (Nearest integer).

Correct answer: 392

Step-by-step solution →
Q58·ChemistryNumerical
t87.5t_{87.5}t87.5​ is the time required for the reaction to undergo 87.5%87.5\%87.5% completion and t50t_{50}t50​ is the time required for the reaction to undergo 50%50\%50% completion. The relation between t87.5t_{87.5}t87.5​ and t50t_{50}t50​ for a first order reaction is t87.5=x×t50t_{87.5}=x\times t_{50}t87.5​=x×t50​. The value of xxx is _____. (Nearest integer)

Correct answer: 3

Step-by-step solution →
Q59·Chemistry·Redox Reactions and ElectrochemistryNumerical
KMnO4KMnO_{4}KMnO4​ is titrated with ferrous ammonium sulphate hexahydrate in presence of dilute H2SO4H_{2}SO_{4}H2​SO4​. Number of water molecules produced for 222 molecules of KMnO4KMnO_{4}KMnO4​ is _____.

Correct answer: 68

Step-by-step solution →
Q60·Chemistry·Redox Reactions and ElectrochemistryNumerical
A metal surface of 100 cm2100\,cm^{2}100cm2 area has to be coated with nickel layer of thickness 0.001 mm0.001\,mm0.001mm. A current of 2 A2\,A2A was passed through a solution of Ni(NO3)2Ni(NO_{3})_{2}Ni(NO3​)2​ for ′x′'x'′x′ seconds to coat the desired layer. The value of xxx is _____ (Nearest integer). (ρNi(\rho_{Ni}(ρNi​ (density of Nickel) is 10 g mL−110\,g\,mL^{-1}10gmL−1. Molar mass of Nickel is 60 g mol−1, F=96500 C mol−1)60\,g\,mol^{-1},\,F=96500\,C\,mol^{-1})60gmol−1,F=96500Cmol−1)

Correct answer: 161

Step-by-step solution →

Mathematics — JEE Main 13 April 2023 Shift 1

Q61·MathematicsSingle correct
∫026e3x+6e2x+11ex+6 dx\displaystyle\int_{0}^{2}\dfrac{6}{e^{3x}+6e^{2x}+11e^{x}+6}\,dx∫02​e3x+6e2x+11ex+66​dx is equal to:
  1. (A)log⁡e51281\log_e\dfrac{512}{81}loge​81512​
  2. (B)log⁡e3227\log_e\dfrac{32}{27}loge​2732​
  3. (C)log⁡e25681\log_e\dfrac{256}{81}loge​81256​
  4. (D)log⁡e6427\log_e\dfrac{64}{27}loge​2764​

Correct answer: (B)

Step-by-step solution →
Q62·MathematicsSingle correct
max⁡0≤x≤π/2{x−2sin⁡xcos⁡x+13sin⁡3x}=\displaystyle\max_{0\le x\le\pi/2}\left\{x-2\sin x\cos x+\dfrac13\sin 3x\right\}=0≤x≤π/2max​{x−2sinxcosx+31​sin3x}=
  1. (A)5π+2+336\dfrac{5\pi+2+3\sqrt3}{6}65π+2+33​​
  2. (B)5π+2−336\dfrac{5\pi+2-3\sqrt3}{6}65π+2−33​​
  3. (C)π\piπ
  4. (D)000

Correct answer: (A)

Step-by-step solution →
Q63·MathematicsSingle correct
The set of all a∈Ra\in\mathbb{R}a∈R for which the equation x∣x−1∣+∣x+2∣+a=0x|x-1|+|x+2|+a=0x∣x−1∣+∣x+2∣+a=0 has exactly one real root is:
  1. (A)(−6,−3)(-6,-3)(−6,−3)
  2. (B)(−∞,∞)(-\infty,\infty)(−∞,∞)
  3. (C)(−6,∞)(-6,\infty)(−6,∞)
  4. (D)(−∞,−3)(-\infty,-3)(−∞,−3)

Correct answer: (B)

Step-by-step solution →
Q64·MathematicsSingle correct
The negation of the statement ((A∧(B∨C))⇒(A∨B))⇒A((A\wedge(B\vee C))\Rightarrow(A\vee B))\Rightarrow A((A∧(B∨C))⇒(A∨B))⇒A is:
  1. (A)equivalent to ∼A\sim A∼A
  2. (B)equivalent to ∼C\sim C∼C
  3. (C)equivalent to B∨∼CB\vee\sim CB∨∼C
  4. (D)a fallacy

Correct answer: (A)

Step-by-step solution →
Q65·MathematicsSingle correct
The distance of the point (−1,2,3)(-1,2,3)(−1,2,3) from the plane r⃗⋅(i^−2j^+3k^)=10\vec r\cdot(\hat i-2\hat j+3\hat k)=10r⋅(i^−2j^​+3k^)=10 parallel to the line of the shortest distance between the lines r⃗=(i^−j^)+λ(2i^+k^)\vec r=(\hat i-\hat j)+\lambda(2\hat i+\hat k)r=(i^−j^​)+λ(2i^+k^) and r⃗=(2i^−j^)+μ(i^−j^+k^)\vec r=(2\hat i-\hat j)+\mu(\hat i-\hat j+\hat k)r=(2i^−j^​)+μ(i^−j^​+k^) is:
  1. (A)363\sqrt636​
  2. (B)353\sqrt535​
  3. (C)262\sqrt626​
  4. (D)252\sqrt525​

Correct answer: (C)

Step-by-step solution →
Q66·MathematicsSingle correct
A coin is biased so that a head is 333 times as likely to occur as a tail. This coin is tossed until a head or three tails occur. If XXX denotes the number of tosses of the coin, then the mean of XXX is:
  1. (A)2116\dfrac{21}{16}1621​
  2. (B)8164\dfrac{81}{64}6481​
  3. (C)1516\dfrac{15}{16}1615​
  4. (D)3716\dfrac{37}{16}1637​

Correct answer: (A)

Step-by-step solution →
Q67·Mathematics·Matrices and DeterminantsSingle correct
For the system of linear equations 2x+4y+2az=b, x+2y+3z=4, 2x−5y+2z=82x+4y+2az=b,\,x+2y+3z=4,\,2x-5y+2z=82x+4y+2az=b,x+2y+3z=4,2x−5y+2z=8, which of the following is NOT correct?
  1. (A)It has infinitely many solutions if a=3, b=6a=3,\,b=6a=3,b=6
  2. (B)It has unique solution if a=b=6a=b=6a=b=6
  3. (C)It has unique solution if a=b=8a=b=8a=b=8
  4. (D)It has infinitely many solution if a=3, b=8a=3,\,b=8a=3,b=8

Correct answer: (A)

Step-by-step solution →
Q68·Mathematics·DifferentiabilitySingle correct
For the differentiable function f:R∖{0}→Rf:\mathbb{R}\setminus\{0\}\to\mathbb{R}f:R∖{0}→R, if 3f(x)+2f(1x)=1x−103f(x)+2f\left(\dfrac{1}{x}\right)=\dfrac{1}{x}-103f(x)+2f(x1​)=x1​−10, then ∣f(3)+f ′ ⁣(14)∣\left|f(3)+f\,'\!\left(\dfrac14\right)\right|​f(3)+f′(41​)​ is equal to:
  1. (A)777
  2. (B)335\dfrac{33}{5}533​
  3. (C)295\dfrac{29}{5}529​
  4. (D)131313

Correct answer: (D)

Step-by-step solution →
Q69·MathematicsSingle correct
Let the tangent and normal at the point (33,1)(3\sqrt3,1)(33​,1) on the ellipse x236+y24=1\dfrac{x^2}{36}+\dfrac{y^2}{4}=136x2​+4y2​=1 meet the yyy-axis at the points AAA and BBB respectively. Let the circle CCC be drawn taking ABABAB as a diameter and the line x=25x=2\sqrt5x=25​ intersect CCC at the points PPP and QQQ. If the tangents at the points PPP and QQQ on the circle intersect at the point (α,0)(\alpha,0)(α,0) and (β,0)(\beta,0)(β,0), then α2−β2\alpha^2-\beta^2α2−β2 is equal to:
  1. (A)3145\dfrac{314}{5}5314​
  2. (B)3045\dfrac{304}{5}5304​
  3. (C)606060
  4. (D)616161

Correct answer: (B)

Step-by-step solution →
Q70·MathematicsSingle correct
The area of the region enclosed by the curve f(x)=max⁡{sin⁡x,cos⁡x}, −π≤x≤πf(x)=\max\{\sin x,\cos x\},\,-\pi\le x\le\pif(x)=max{sinx,cosx},−π≤x≤π and the xxx-axis is:
  1. (A)2(2+1)2(\sqrt2+1)2(2​+1)
  2. (B)22(2+1)2\sqrt2(\sqrt2+1)22​(2​+1)
  3. (C)4(2)4(\sqrt2)4(2​)
  4. (D)444

Correct answer: (D)

Step-by-step solution →
Q71·Mathematics·Matrices and DeterminantsSingle correct
The number of symmetric matrices of order 333, with all the entries from the set {0,1,2,3,4,5,6,7,8,9}\{0,1,2,3,4,5,6,7,8,9\}{0,1,2,3,4,5,6,7,8,9} is:
  1. (A)6106^{10}610
  2. (B)9109^{10}910
  3. (C)10310^{3}103
  4. (D)10610^{6}106

Correct answer: (D)

Step-by-step solution →
Q72·MathematicsSingle correct
Among: (S1): lim⁡n→∞1n2(2+4+6+⋯+2n)=1\displaystyle\lim_{n\to\infty}\dfrac{1}{n^{2}}(2+4+6+\dots+2n)=1n→∞lim​n21​(2+4+6+⋯+2n)=1 (S2): lim⁡n→∞1n16(115+215+315+⋯+n15)=116\displaystyle\lim_{n\to\infty}\dfrac{1}{n^{16}}(1^{15}+2^{15}+3^{15}+\dots+n^{15})=\dfrac{1}{16}n→∞lim​n161​(115+215+315+⋯+n15)=161​
  1. (A)Both (S1) and (S2) are false
  2. (B)Both (S1) and (S2) are true
  3. (C)Only (S2) is true
  4. (D)Only (S1) is true

Correct answer: (A)

Step-by-step solution →
Q73·MathematicsSingle correct
Let PQPQPQ be a focal chord of the parabola y2=36xy^{2}=36xy2=36x of length 100100100, making an acute angle with the positive xxx-axis. Let the ordinate of PPP be positive and MMM be the point on the line segment PQPQPQ such that PM:MQ=3:1PM:MQ=3:1PM:MQ=3:1. Then which of the following points does NOT lie on the line passing through MMM and perpendicular to the line PQPQPQ?
  1. (A)(−3,43)(-3,43)(−3,43)
  2. (B)(−6,45)(-6,45)(−6,45)
  3. (C)(3,33)(3,33)(3,33)
  4. (D)(6,29)(6,29)(6,29)

Correct answer: (A)

Step-by-step solution →
Q74·MathematicsSingle correct
For x∈Rx\in\mathbb{R}x∈R, two real valued functions f(x)f(x)f(x) and g(x)g(x)g(x) are such that g(x)=x+1g(x)=\sqrt x+1g(x)=x​+1 and f(g(x))=x+3−xf(g(x))=x+3-\sqrt xf(g(x))=x+3−x​. Then f(0)f(0)f(0) is equal to:
  1. (A)111
  2. (B)−3-3−3
  3. (C)555
  4. (D)000

Correct answer: (C)

Step-by-step solution →
Q75·MathematicsSingle correct
Fractional part of the number 4202215\dfrac{4^{2022}}{15}1542022​ is equal to:
  1. (A)415\dfrac{4}{15}154​
  2. (B)115\dfrac{1}{15}151​
  3. (C)1415\dfrac{14}{15}1514​
  4. (D)815\dfrac{8}{15}158​

Correct answer: (B)

Step-by-step solution →
Q76·MathematicsSingle correct
Let a⃗=i^+4j^+2k^, b⃗=3i^−2j^+7k^\vec a=\hat i+4\hat j+2\hat k,\,\vec b=3\hat i-2\hat j+7\hat ka=i^+4j^​+2k^,b=3i^−2j^​+7k^ and c⃗=2i^−j^+4k^\vec c=2\hat i-\hat j+4\hat kc=2i^−j^​+4k^. If a vector d⃗\vec dd satisfies d⃗×b⃗=c⃗×b⃗\vec d\times\vec b=\vec c\times\vec bd×b=c×b and a⃗⋅d⃗=24\vec a\cdot\vec d=24a⋅d=24, then ∣d⃗∣2|\vec d|^{2}∣d∣2 is equal to:
  1. (A)413413413
  2. (B)423423423
  3. (C)323323323
  4. (D)313313313

Correct answer: (A)

Step-by-step solution →
Q77·Mathematics·Matrices and DeterminantsSingle correct
Let B=[13α123αα4], α>2B=\begin{bmatrix} 1 & 3 & \alpha \\ 1 & 2 & 3 \\ \alpha & \alpha & 4 \end{bmatrix},\,\alpha>2B=​11α​32α​α34​​,α>2 be the adjoint of a matrix AAA and ∣A∣=2|A|=2∣A∣=2, then [α −2α α][α−2αα][\alpha\,-2\alpha\,\alpha]\begin{bmatrix} \alpha \\ -2\alpha \\ \alpha \end{bmatrix}[α−2αα]​α−2αα​​ is equal to:
  1. (A)161616
  2. (B)323232
  3. (C)−16-16−16
  4. (D)000

Correct answer: (C)

Step-by-step solution →
Q78·MathematicsSingle correct
Let s1,s2,s3,…,s10s_{1},s_{2},s_{3},\dots,s_{10}s1​,s2​,s3​,…,s10​ respectively be the sum to 121212 terms of 101010 A.P.'s whose first terms are 1,2,3,…,101,2,3,\dots,101,2,3,…,10 and the common differences are 1,3,5,…,191,3,5,\dots,191,3,5,…,19 respectively. Then ∑i=110si\displaystyle\sum_{i=1}^{10}s_{i}i=1∑10​si​ is equal to:
  1. (A)738073807380
  2. (B)722072207220
  3. (C)736073607360
  4. (D)726072607260

Correct answer: (D)

Step-by-step solution →
Q79·MathematicsSingle correct
Let y=y1(x)y=y_{1}(x)y=y1​(x) and y=y2(x)y=y_{2}(x)y=y2​(x) be the solution curves of the differential equation dydx=y+7\dfrac{dy}{dx}=y+7dxdy​=y+7 with initial conditions y1(0)=0, y2(0)=1y_{1}(0)=0,\,y_{2}(0)=1y1​(0)=0,y2​(0)=1 respectively. Then the curves y=y1(x)y=y_{1}(x)y=y1​(x) and y=y2(x)y=y_{2}(x)y=y2​(x) intersect at:
  1. (A)Two points
  2. (B)no point
  3. (C)infinite number of points
  4. (D)one point

Correct answer: (B)

Step-by-step solution →
Q80·MathematicsSingle correct
Let the equation of the plane passing through the line of intersection of the planes x+2y+az=2x+2y+az=2x+2y+az=2 and x−y+z=3x-y+z=3x−y+z=3 be 5x−11y+bz=6a−15x-11y+bz=6a-15x−11y+bz=6a−1. For c∈Zc\in\mathbb{Z}c∈Z, if the distance of this plane from the point (a,−c,c)(a,-c,c)(a,−c,c) is 2a\dfrac{2}{\sqrt a}a​2​, then a+bc\dfrac{a+b}{c}ca+b​ is equal to:
  1. (A)−2-2−2
  2. (B)222
  3. (C)−4-4−4
  4. (D)444

Correct answer: (C)

Step-by-step solution →
Q81·MathematicsNumerical
Let α\alphaα be the constant term in the binomial expansion of (x−6x3/2)n, n≤15\left(\sqrt x-\dfrac{6}{x^{3/2}}\right)^{n},\,n\le 15(x​−x3/26​)n,n≤15. If the sum of the coefficients of the remaining terms in the expansion is 649649649 and the coefficient of x−nx^{-n}x−n is λα\lambda\alphaλα, then λ\lambdaλ is equal to _____.

Correct answer: 36

Step-by-step solution →
Q82·MathematicsNumerical
Let S={x∈R:sin⁡−1(x+1x2+2x+2)−sin⁡−1(xx2+1)=π4}S=\left\{x\in\mathbb{R}:\sin^{-1}\left(\dfrac{x+1}{\sqrt{x^{2}+2x+2}}\right)-\sin^{-1}\left(\dfrac{x}{\sqrt{x^{2}+1}}\right)=\dfrac{\pi}{4}\right\}S={x∈R:sin−1(x2+2x+2​x+1​)−sin−1(x2+1​x​)=4π​}. Then ∑x∈S(sin⁡ ⁣((x2+x+5)π2)−cos⁡ ⁣((x2+x+5)π))\displaystyle\sum_{x\in S}\left(\sin\!\left((x^{2}+x+5)\dfrac{\pi}{2}\right)-\cos\!\left((x^{2}+x+5)\pi\right)\right)x∈S∑​(sin((x2+x+5)2π​)−cos((x2+x+5)π)) is equal to _____.

Correct answer: 4

Step-by-step solution →
Q83·MathematicsNumerical
Let ω=zzˉ+k1z+kˉ1zˉ+λ(1+i), k1∈C\omega=z\bar z+k_{1}z+\bar k_{1}\bar z+\lambda(1+i),\,k_{1}\in\mathbb{C}ω=zzˉ+k1​z+kˉ1​zˉ+λ(1+i),k1​∈C. Re⁡(ω)=0\operatorname{Re}(\omega)=0Re(ω)=0 be the circle CCC of radius 111 in the first quadrant touching the line y=1y=1y=1 and the yyy-axis. If the curve Im⁡(ω)=0\operatorname{Im}(\omega)=0Im(ω)=0 intersects CCC at AAA and BBB, then 30(AB)230(AB)^{2}30(AB)2 is equal to _____.

Correct answer: 24

Step-by-step solution →
Q84·MathematicsNumerical
Let for x∈R, S0(x)=x, Sk(x)=Ck+k∫0xSk−1(t)dtx\in\mathbb{R},\,S_{0}(x)=x,\,S_{k}(x)=C_{k}+k\displaystyle\int_{0}^{x}S_{k-1}(t)dtx∈R,S0​(x)=x,Sk​(x)=Ck​+k∫0x​Sk−1​(t)dt, where Ck=1−∫01Sk−1(x)dx, k=1,2,3,…C_{k}=1-\displaystyle\int_{0}^{1}S_{k-1}(x)dx,\,k=1,2,3,\dotsCk​=1−∫01​Sk−1​(x)dx,k=1,2,3,…. Then S2(3)+6C3S_{2}(3)+6C_{3}S2​(3)+6C3​ is equal to _____.

Correct answer: 18

Step-by-step solution →
Q85·MathematicsNumerical
The sum to 202020 terms of the series 2⋅22−32+2⋅42−52+2⋅62−…2\cdot 2^{2}-3^{2}+2\cdot 4^{2}-5^{2}+2\cdot 6^{2}-\dots2⋅22−32+2⋅42−52+2⋅62−… is equal to _____.

Correct answer: 1310

Step-by-step solution →
Q86·MathematicsNumerical
The number of seven digit positive integers formed using the digits 1, 2, 31,\,2,\,31,2,3 and 444 only and sum of the digits equal to 121212 is _____.

Correct answer: 413

Step-by-step solution →
Q87·MathematicsNumerical
Let m1m_{1}m1​ and m2m_{2}m2​ be the slopes of the tangents drawn from the point P(4,1)P(4,1)P(4,1) to the hyperbola H:y225−x216=1H:\dfrac{y^{2}}{25}-\dfrac{x^{2}}{16}=1H:25y2​−16x2​=1. If QQQ is the point from which the tangents drawn to HHH have slopes ∣m1∣|m_{1}|∣m1​∣ and ∣m2∣|m_{2}|∣m2​∣ and they make positive intercepts α\alphaα and β\betaβ on the xxx-axis, then (PQ)2αβ\dfrac{(PQ)^{2}}{\alpha\beta}αβ(PQ)2​ is equal to _____.

Correct answer: 8

Step-by-step solution →
Q88·MathematicsNumerical
Let the image of the point (53,53,83)\left(\dfrac{5}{3},\dfrac{5}{3},\dfrac{8}{3}\right)(35​,35​,38​) in the plane x−2y+z−2=0x-2y+z-2=0x−2y+z−2=0 be PPP. If the distance of point Q(6,−2,α), α>0Q(6,-2,\alpha),\,\alpha>0Q(6,−2,α),α>0 from PPP is 131313, then α\alphaα is equal to _____.

Correct answer: 15

Step-by-step solution →
Q89·MathematicsNumerical
Let a⃗=3i^+j^−k^\vec a=3\hat i+\hat j-\hat ka=3i^+j^​−k^ and c⃗=2i^−3j^+3k^\vec c=2\hat i-3\hat j+3\hat kc=2i^−3j^​+3k^. If b⃗\vec bb is a vector such that a⃗=b⃗×c⃗\vec a=\vec b\times\vec ca=b×c and ∣b⃗∣=50|\vec b|=\sqrt{50}∣b∣=50​, then ∣72−∣b⃗+c⃗∣2∣\left|72-|\vec b+\vec c|^{2}\right|​72−∣b+c∣2​ is equal to _____.

Correct answer: 66

Step-by-step solution →
Q90·MathematicsNumerical
Let the mean of the data: x13579Frequency (f)42428α8\begin{array}{|c|c|c|c|c|c|}\hline x & 1 & 3 & 5 & 7 & 9 \\\hline \text{Frequency }(f) & 4 & 24 & 28 & \alpha & 8 \\\hline\end{array}xFrequency (f)​14​324​528​7α​98​​ be 555. If mmm and σ2\sigma^{2}σ2 are respectively the mean deviation about the mean and the variance of the data, then 3αm+σ2\dfrac{3\alpha}{m+\sigma^{2}}m+σ23α​ is equal to _____.

Correct answer: 8

Step-by-step solution →

Chapters tested in this paper

Open any chapter to practise every past-year question on that topic across all papers, and see how often it has actually appeared.

  • Properties of Solids and Liquids 172/186
  • Three Dimensional Geometry 176/186
  • Matrices and Determinants 180/186
  • Coordination Compounds 176/186
  • Sets, Relations and Functions 165/186
  • Current Electricity 160/186
  • Sequence and Series 164/186
  • p-Block Elements 164/186
  • Definite Integration 168/186
  • Rotational Motion 172/186
  • Redox Reactions and Electrochemistry 177/186
  • Geometrical Optics 172/186
  • Kinematics 156/186
  • Vector Algebra 173/186
  • Differential Equations 167/186
  • Probability 176/186
  • Permutations and Combinations 162/186
  • Binomial Theorem and Its Simple Applications 158/186
  • Electromagnetic Waves 144/186
  • Chemical Bonding and Molecular Structure 151/186
  • Application of Derivatives 139/186
  • d- and f-Block Elements 126/186
  • Equilibrium 163/186
  • Solutions 158/186
  • Laws of Motion 130/186
  • Chemical Thermodynamics 165/186
  • Hydrocarbons 126/186
  • Complex Numbers 165/186
  • Biomolecules 162/186
  • Chemical Kinetics 169/186
  • Gravitation 152/186
  • Electric Field and Coulomb's Law 133/186
  • Atomic Structure 161/186
  • Electronic Devices 145/186
  • Dual Nature of Matter and Radiation 155/186
  • Amines 133/186
  • Quadratic Equations 148/186
  • Work, Energy and Power 132/186
  • Some Basic Concepts in Chemistry 129/186
  • Electromagnetic Induction 120/186
  • Area Under Curves 139/186
  • Kinetic Theory of Gases 135/186
  • Purification and Characterisation of Organic Compounds 116/186
  • Oscillations 117/186
  • Nuclei 116/186
  • Organic Compounds Containing Halogens 109/186
  • Atoms 112/186
  • Classification of Elements and Periodicity in Properties 113/186
  • Parabola 101/186
  • Statistics 118/186
  • Ellipse 103/186
  • Isolation of Metals 106/186
  • Differentiability 91/186
  • s-Block Elements 88/186
  • Surface Chemistry 98/186
  • Inverse Trigonometric Functions 93/186
  • Environmental Chemistry 83/186
  • Hydrogen 81/186
  • Electronic Effects and Stability 74/186
  • Hyperbola 77/186
  • Experimental Skills 68/186
  • Polymers 64/186
  • States of Matter: Gases and Liquids 52/186
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