Jarvis OS
PYQ papersPricingSign inGet started
  1. Home
  2. /JEE Main PYQs
  3. /2023
  4. /13 Apr Shift 2

JEE Main 13 April 2023 Shift 2 Question Paper with Answers

13 April 2023 · April session · 90 questions

The complete JEE Main 13 April 2023 Shift 2 paper — all 90 questions with the correct answer for each, tagged to the chapter it tests. Free to read, no account needed.

Physics
30
Chemistry
30
Mathematics
30

Physics — JEE Main 13 April 2023 Shift 2

Q1·PhysicsSingle correct
Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R. Assertion A: The binding energy per nucleon is practically independent of the atomic number for nuclei of mass number in the range 30 to 170. Reason R: Nuclear force is short ranged. In the light of the above statements, choose the correct answer from the options given below
  1. (A)Both A and R are true but R is NOT the correct explanation of A
  2. (B)A is true but R is false
  3. (C)A is false but R is true
  4. (D)Both A and R are true and R is the correct explanation of A

Correct answer: (D)

Step-by-step solution →
Q2·PhysicsSingle correct
The output from a NAND gate having inputs A and B given below will be:
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (A)

Step-by-step solution →
Q3·PhysicsSingle correct
In the network shown below, the charge accumulated in the capacitor in steady state will be:
  1. (A)7.2 μ\muμC
  2. (B)4.8 μ\muμC
  3. (C)10.3 μ\muμC
  4. (D)12 μ\muμC

Correct answer: (A)

Step-by-step solution →
Q4·PhysicsSingle correct
Given below are two statements: Statement I: For a planet, if the ratio of mass of the planet to its radius increases, the escape velocity from the planet also increases. Statement II: Escape velocity is independent of the radius of the planet. In the light of above statements, choose the most appropriate answer from the options given below
  1. (A)Both Statement I and Statement II are incorrect
  2. (B)Statement I is correct but Statement II is incorrect
  3. (C)Statement I is incorrect but Statement II is correct
  4. (D)Both Statement I and Statement II are correct

Correct answer: (B)

Step-by-step solution →
Q5·PhysicsSingle correct
A particle executes SHM of amplitude A. The distance from the mean position when its kinetic energy becomes equal to its potential energy is:
  1. (A)2A\sqrt{2}A2​A
  2. (B)2A2A2A
  3. (C)12A\dfrac{1}{\sqrt{2}}A2​1​A
  4. (D)12A\dfrac{1}{2}A21​A

Correct answer: (C)

Step-by-step solution →
Q6·PhysicsSingle correct
A passenger sitting in a train A moving at 90 km/h observes another train B moving in the opposite direction for 8 s. If the velocity of the train B is 54 km/h, then length of train B is:
  1. (A)80 m
  2. (B)200 m
  3. (C)120 m
  4. (D)320 m

Correct answer: (D)

Step-by-step solution →
Q7·PhysicsSingle correct
The initial pressure and volume of an ideal gas are P0P_0P0​ and V0V_0V0​. The final pressure of the gas when the gas is suddenly compressed to volume V04\dfrac{V_0}{4}4V0​​ will be: (Given γ\gammaγ = ratio of specific heats at constant pressure and at constant volume)
  1. (A)P0(4)1−γP_0(4)^{1-\gamma}P0​(4)1−γ
  2. (B)P0(4)γP_0(4)^{\gamma}P0​(4)γ
  3. (C)P0P_0P0​
  4. (D)4P04P_04P0​

Correct answer: (B)

Step-by-step solution →
Q8·PhysicsSingle correct
Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R. Assertion A: A spherical body of radius (5±0.1)(5 \pm 0.1)(5±0.1) mm having a particular density is falling through a liquid of constant density. The percentage error in the calculation of its terminal velocity is 4%. Reason R: The terminal velocity of the spherical body falling through the liquid is inversely proportional to its radius. In the light of the above statements, choose the correct answer from the options given below
  1. (A)Both A and R are true but R is NOT the correct explanation of A
  2. (B)Both A and R are true and R is the correct explanation of A
  3. (C)A is false but R is true
  4. (D)A is true but R is false

Correct answer: (D)

Step-by-step solution →
Q9·PhysicsSingle correct
In an electromagnetic wave, at an instant and at a particular position, the electric field is along the negative z-axis and magnetic field is along the positive x-axis. Then the direction of propagation of electromagnetic wave is:
  1. (A)at 45∘^\circ∘ angle from positive y-axis
  2. (B)negative y-axis
  3. (C)positive z-axis
  4. (D)positive y-axis

Correct answer: (B)

Step-by-step solution →
Q10·PhysicsSingle correct
The distance travelled by an object in time t is given by s=(2.5)t2s = (2.5)t^2s=(2.5)t2. The instantaneous speed of the object at t=5t = 5t=5 s will be:
  1. (A)12.5 m s−1^{-1}−1
  2. (B)62.5 m s−1^{-1}−1
  3. (C)5 m s−1^{-1}−1
  4. (D)25 m s−1^{-1}−1

Correct answer: (D)

Step-by-step solution →
Q11·PhysicsSingle correct
An electron is moving along the positive x-axis. If the uniform magnetic field is applied parallel to the negative z-axis, then A. The electron will experience magnetic force along positive y-axis B. The electron will experience magnetic force along negative y-axis C. The electron will not experience any force in magnetic field D. The electron will continue to move along the positive x-axis E. The electron will move along circular path in magnetic field. Choose the correct answer from the options given below:
  1. (A)B and E only
  2. (B)A and E only
  3. (C)C and D only
  4. (D)B and D only

Correct answer: (A)

Step-by-step solution →
Q12·PhysicsSingle correct
Two planets A and B of radii R and 1.5 R have densities ρ\rhoρ and ρ/2\rho/2ρ/2 respectively. The ratio of acceleration due to gravity at the surface of B to A is:
  1. (A)2 : 3
  2. (B)2 : 1
  3. (C)3 : 4
  4. (D)4 : 3

Correct answer: (C)

Step-by-step solution →
Q13·PhysicsSingle correct
Given below are two statements: Statement I: An AC circuit undergoes electrical resonance if it contains either a capacitor or an inductor. Statement II: An AC circuit containing a pure capacitor or a pure inductor consumes high power due to its non-zero power factor. In the light of above statements, choose the correct answer from the options given below
  1. (A)Both Statement I and Statement II are false
  2. (B)Statement I is true but Statement II is false
  3. (C)Both Statement I and Statement II are true
  4. (D)Statement I is false but Statement II is true

Correct answer: (A)

Step-by-step solution →
Q14·PhysicsSingle correct
A vehicle of mass 200 kg is moving along a levelled curved road of radius 70 m with angular velocity of 0.2 rad/s. The centripetal force acting on the vehicle is:
  1. (A)560 N
  2. (B)2800 N
  3. (C)14 N
  4. (D)2240 N

Correct answer: (A)

Step-by-step solution →
Q15·PhysicsSingle correct
To radiate EM signal of wavelength λ\lambdaλ with high efficiency, the antennas should have a minimum size equal to:
  1. (A)λ2\dfrac{\lambda}{2}2λ​
  2. (B)λ4\dfrac{\lambda}{4}4λ​
  3. (C)2λ2\lambda2λ
  4. (D)4λ4\lambda4λ

Correct answer: (B)

Step-by-step solution →
Q16·PhysicsSingle correct
Given below are two statements: Statement I: Out of microwaves, infrared rays and ultraviolet rays, ultraviolet rays are the most effective for the emission of electrons from a metallic surface. Statement II: Above the threshold frequency, the maximum kinetic energy of photoelectrons is inversely proportional to the frequency of the incident light. In the light of above statements, choose the correct answer from the options given below
  1. (A)Statement I is true but Statement II is false
  2. (B)Both Statement I and Statement II are true
  3. (C)Statement I is false but Statement II is true
  4. (D)Both Statement I and Statement II are false

Correct answer: (A)

Step-by-step solution →
Q17·PhysicsSingle correct
A 10 μ\muμC charge is divided into two parts and placed at 1 cm distance so that the repulsive force between them is maximum. The charges of the two parts are:
  1. (A)9 μ\muμC, 1 μ\muμC
  2. (B)5 μ\muμC, 5 μ\muμC
  3. (C)7 μ\muμC, 3 μ\muμC
  4. (D)8 μ\muμC, 2 μ\muμC

Correct answer: (B)

Step-by-step solution →
Q18·PhysicsSingle correct
In the equation [X+aY2][Y−b]=RT\left[X + \dfrac{a}{Y^2}\right][Y - b] = RT[X+Y2a​][Y−b]=RT, XXX is pressure, YYY is volume, R is universal gas constant and TTT is temperature. The physical quantity equivalent to the ratio ab\dfrac{a}{b}ba​ is:
  1. (A)Energy
  2. (B)Impulse
  3. (C)Pressure gradient
  4. (D)Coefficient of viscosity

Correct answer: (A)

Step-by-step solution →
Q19·PhysicsSingle correct
In a Young's double slit experiment, the ratio of amplitude of light coming from slits is 2:1. The ratio of the maximum to minimum intensity in the interference pattern is:
  1. (A)9 : 4
  2. (B)9 : 1
  3. (C)2 : 1
  4. (D)25 : 9

Correct answer: (B)

Step-by-step solution →
Q20·PhysicsSingle correct
The mean free path of molecules of a certain gas at STP is 1500d, where d is the diameter of the gas molecules. While maintaining the standard pressure, the mean free path of the molecules at 373 K is approximately:
  1. (A)1098d
  2. (B)2049d
  3. (C)750d
  4. (D)1500d

Correct answer: (B)

Step-by-step solution →
Q21·PhysicsNumerical
A biconvex lens of focal length 10 cm is cut in two identical parts along a plane perpendicular to the principal axis. The power of each lens after cut is ____ D.

Correct answer: 5

Step-by-step solution →
Q22·PhysicsNumerical
An atom absorbs a photon of wavelength 500 nm and emits another photon of wavelength 600 nm. The net energy absorbed by the atom in this process is n×10−4n \times 10^{-4}n×10−4 eV. The value of n is ____. [Assume the atom to be stationary during the absorption and emission process] (Take h=6.6×10−34h = 6.6 \times 10^{-34}h=6.6×10−34 Js and c=3×108c = 3 \times 10^8c=3×108 m/s)

Correct answer: 4125

Step-by-step solution →
Q23·PhysicsNumerical
Three point charges qqq, −2q-2q−2q and 2q2q2q are placed on x-axis at a distance x=0x = 0x=0, x=34Rx = \dfrac{3}{4}Rx=43​R and x=Rx = Rx=R respectively from origin as shown. If q=2×10−6q = 2 \times 10^{-6}q=2×10−6 C and R = 2 cm, the magnitude of net force experienced by the charge −2q-2q−2q is ____ N.

Correct answer: 5440

Step-by-step solution →
Q24·PhysicsNumerical
In the circuit shown, the energy stored in the capacitor is nnn μ\muμJ. The value of n is ____.

Correct answer: 75

Step-by-step solution →
Q25·PhysicsNumerical
An insulated copper wire of 100 turns is wrapped around a wooden cylindrical core of the cross-sectional area 24 cm2^22. The two ends of the wire are connected to a resistor. The total resistance in the circuit is 12 Ω\OmegaΩ. If an externally applied uniform magnetic field in the core along its axis changes from 1.5 T in one direction to 1.5 T in the opposite direction, the charge flowing through a point in the circuit during the change of magnetic field will be ____ mC.

Correct answer: 60

Step-by-step solution →
Q26·PhysicsNumerical
In an experiment with sonometer when a mass of 180 g is attached to the string, it vibrates with fundamental frequency of 30 Hz. When a mass m is attached, the string vibrates with fundamental frequency of 50 Hz. The value of m is ____ g.

Correct answer: 500

Step-by-step solution →
Q27·PhysicsNumerical
A light rope is wound around a hollow cylinder of mass 5 kg and radius 70 cm. The rope is pulled with a force of 52.5 N. The angular acceleration of the cylinder will be ____ rad s−2^{-2}−2.

Correct answer: 15

Step-by-step solution →
Q28·PhysicsNumerical
A car accelerates from rest to u m/s. The energy spent in this process is E J. The energy required to accelerate the car from u m/s to 2u m/s is nE J. The value of n is ____.

Correct answer: 3

Step-by-step solution →
Q29·PhysicsNumerical
Two plates A and B have thermal conductivities 84 Wm−1^{-1}−1K−1^{-1}−1 and 126 Wm−1^{-1}−1K−1^{-1}−1 respectively. They have same surface area and same thickness. They are placed in contact along their surfaces. If the temperatures of the outer surfaces of A and B are kept at 100 °C and 0 °C respectively, then the temperature of the surface of contact in steady state is ____ °C.

Correct answer: 40

Step-by-step solution →
Q30·PhysicsNumerical
A straight wire AB of mass 40 g and length 50 cm is suspended by a pair of flexible leads in uniform magnetic field of magnitude 0.40 T as shown in the figure. The magnitude of the current required in the wire to remove the tension in the supporting leads is ____ A. (Take g=10g = 10g=10 ms−2^{-2}−2)

Correct answer: 2

Step-by-step solution →

Chemistry — JEE Main 13 April 2023 Shift 2

Q31·ChemistrySingle correct
In the wet tests for detection of various cations by precipitation, Ba2+Ba^{2+}Ba2+ cations are detected by obtaining precipitate of
  1. (A)Ba(ox)Ba(ox)Ba(ox): Barium oxalate
  2. (B)BaCO3BaCO_3BaCO3​
  3. (C)Ba(OAc)2Ba(OAc)_2Ba(OAc)2​
  4. (D)BaSO4BaSO_4BaSO4​

Correct answer: (B)

Step-by-step solution →
Q32·ChemistrySingle correct
The naturally occurring amino acid that contains only one basic functional group in its chemical structure is
  1. (A)arginine
  2. (B)lysine
  3. (C)asparagine
  4. (D)histidine

Correct answer: (C)

Step-by-step solution →
Q33·ChemistrySingle correct
Given below are two statements related to Ellingham diagram. Statement-I: Ellingham diagrams can be constructed for formation of oxides, sulphides and halides of metals. Statement-II: It consists of plots of ΔH0\Delta H^0ΔH0 vs T for formation of oxides of elements. In the light of the above statements, choose the most appropriate answer from the options given below:
  1. (A)Both Statement I and Statement II are correct
  2. (B)Statement I is incorrect but Statement II is correct
  3. (C)Both Statement I and Statement II are incorrect
  4. (D)Statement I is correct but Statement II is incorrect

Correct answer: (D)

Step-by-step solution →
Q34·ChemistrySingle correct
Given below are two statements, one is labelled as Assertion A and the other is labelled as Reason R. Assertion A: The diameter of colloidal particles in solution should not be much smaller than wavelength of light to show Tyndall effect. Reason R: The light scatters in all directions when the size of particles is large enough. In the light of the above statements, choose the correct answer from the options given below:
  1. (A)A is true but R is false
  2. (B)A is false but R is true
  3. (C)Both A and R are correct and R is the correct explanation of A
  4. (D)Both A and R are correct but R is NOT the correct explanation of A

Correct answer: (C)

Step-by-step solution →
Q35·ChemistrySingle correct
The total number of stereoisomers for the complex [Cr(ox)2ClBr]3−[Cr(ox)_2ClBr]^{3-}[Cr(ox)2​ClBr]3− (where ox = oxalate) is:
  1. (A)2
  2. (B)3
  3. (C)1
  4. (D)4

Correct answer: (A)

Step-by-step solution →
Q36·ChemistrySingle correct
Better method for preparation of BeF2BeF_2BeF2​, among the following is
  1. (A)(NH4)2BeF4→ΔBeF2(NH_4)_2BeF_4 \xrightarrow{\Delta} BeF_2(NH4​)2​BeF4​Δ​BeF2​
  2. (B)BeH2+F2→ΔBeF2BeH_2 + F_2 \xrightarrow{\Delta} BeF_2BeH2​+F2​Δ​BeF2​
  3. (C)Be+F2→ΔBeF2Be + F_2 \xrightarrow{\Delta} BeF_2Be+F2​Δ​BeF2​
  4. (D)BeO+C+F2→ΔBeF2BeO + C + F_2 \xrightarrow{\Delta} BeF_2BeO+C+F2​Δ​BeF2​

Correct answer: (A)

Step-by-step solution →
Q37·ChemistrySingle correct
Given below are two statements, one is labelled as Assertion A and the other is labelled as Reason R. Assertion A: Isotopes of hydrogen have almost same chemical properties, but difference in their rates of reaction. Reason R: Isotopes of hydrogen have different enthalpy of bond dissociation. In the light of the above statements, choose the most appropriate answer from the options given below:
  1. (A)Both A and R are correct but R is NOT the correct explanation of A
  2. (B)Both A and R are correct and R is the correct explanation of A
  3. (C)A is not correct but R is correct
  4. (D)A is correct but R is not correct

Correct answer: (B)

Step-by-step solution →
Q38·Chemistry·AromaticitySingle correct
Given below are two statements: Statement I: Tropolone is an aromatic compound and has 8π8\pi8π electrons. Statement II: π\piπ electrons of >C=O>C=O>C=O group in tropolone is involved in aromaticity. In the light of the above statements, choose the correct answer from the options given below:
  1. (A)Both Statement I and Statement II are true
  2. (B)Statement I is true but Statement II is false
  3. (C)Statement I is false but Statement II is true
  4. (D)Both Statement I and Statement II are false

Correct answer: (B)

Step-by-step solution →
Q39·ChemistrySingle correct
Compound A from the following reaction sequence is:
  1. (A)Benzoic Acid
  2. (B)Phenol
  3. (C)Salicylic Acid
  4. (D)Aniline

Correct answer: (D)

Step-by-step solution →
Q40·Chemistry·Reaction MechanismSingle correct
The major product for the following reaction is:
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (A)

Step-by-step solution →
Q41·ChemistrySingle correct
Which of the following are the Green house gases? A. Water vapour B. Ozone C. I2I_2I2​ D. Molecular hydrogen. Choose the most appropriate answer from the options given below:
  1. (A)B and C only
  2. (B)C and D only
  3. (C)A and D only
  4. (D)A and B only

Correct answer: (D)

Step-by-step solution →
Q42·ChemistrySingle correct
Match List I with List II (Polymers). Choose the correct answer from the options given below:
List IList II
A.Weak intermolecular forces of attractionI.Hexamethylenediamine + adipic acid
B.Hydrogen bondingII.AlEt3+TiCl4AlEt_3 + TiCl_4AlEt3​+TiCl4​
C.Heavily branched polymerIII.2-chloro-1,3-butadiene
D.High density polymerIV.Phenol + formaldehyde
  1. (A)A-III, B-I, C-I, D-III
  2. (B)A-III, B-I, C-IV, D-II
  3. (C)A-IV, B-I, C-III, D-II
  4. (D)A-IV, B-II, C-III, D-I

Correct answer: (B)

Step-by-step solution →
Q43·ChemistrySingle correct
Given below are two statements: Statement I: SO2SO_2SO2​ and H2OH_2OH2​O both possess V-shaped structure. Statement II: The bond angle of SO2SO_2SO2​ is less than that of H2OH_2OH2​O. In the light of the above statements, choose the most appropriate answer from the options given below:
  1. (A)Both Statement I and Statement II are correct
  2. (B)Statement I is correct but Statement II is incorrect
  3. (C)Both Statement I and Statement II are incorrect
  4. (D)Statement I is incorrect but Statement II is correct

Correct answer: (B)

Step-by-step solution →
Q44·ChemistrySingle correct
The correct group of halide ions which can be oxidised by oxygen in acidic medium is
  1. (A)Br−Br^-Br− only
  2. (B)Cl−,Br−Cl^-, Br^-Cl−,Br− and I−I^-I− only
  3. (C)Br−Br^-Br− and I−I^-I− only
  4. (D)I−I^-I− only

Correct answer: (D)

Step-by-step solution →
Q45·ChemistrySingle correct
What happens when methane undergoes combustion in systems A and B respectively? (System A is an adiabatic system; System B is a diathermic container)
  1. (A)System A: Temperature rises; System B: Temperature remains same
  2. (B)System A: Temperature falls; System B: Temperature rises
  3. (C)System A: Temperature falls; System B: Temperature remains same
  4. (D)System A: Temperature remains same; System B: Temperature rises

Correct answer: (A)

Step-by-step solution →
Q46·Chemistry·Electronic Effects and StabilitySingle correct
Given below are two statements, one is labelled as Assertion A and the other is labelled as Reason R. Assertion A: Order of acidic nature of the following compounds is A > B > C. Reason R: Fluoro is a stronger electron withdrawing group than Chloro group. In the light of the above statements, choose the correct answer from the options given below:
  1. (A)A is false but R is true
  2. (B)Both A and R are correct and R is the correct explanation of A
  3. (C)Both A and R are correct but R is NOT the correct explanation of A
  4. (D)A is true but R is false

Correct answer: (C)

Step-by-step solution →
Q47·ChemistrySingle correct
Identify the correct order of standard enthalpy of formation of sodium halides.
  1. (A)NaF<NaBr<NaCl<NaINaF < NaBr < NaCl < NaINaF<NaBr<NaCl<NaI
  2. (B)NaF<NaCl<NaBr<NaINaF < NaCl < NaBr < NaINaF<NaCl<NaBr<NaI
  3. (C)NaCl<NaF<NaBr<NaINaCl < NaF < NaBr < NaINaCl<NaF<NaBr<NaI
  4. (D)NaI<NaBr<NaF<NaClNaI < NaBr < NaF < NaClNaI<NaBr<NaF<NaCl

Correct answer: (D)

Step-by-step solution →
Q48·ChemistrySingle correct
Match List I (Reagent) with List II (Product). Choose the correct answer from the options given below:
List I (Reagent)List II (Product)
A.KOHKOHKOH (alc)I.Nitrile
B.KCNKCNKCN (alc)II.Ester
C.AgNO2AgNO_2AgNO2​III.Alkene
D.H3CCOOAgH_3CCOOAgH3​CCOOAgIV.Nitroalkane
  1. (A)A-IV, B-III, C-II, D-I
  2. (B)A-III, B-I, C-IV, D-II
  3. (C)A-I, B-II, C-III, D-IV
  4. (D)A-I, B-III, C-IV, D-II

Correct answer: (B)

Step-by-step solution →
Q49·ChemistrySingle correct
The covalency and oxidation state respectively of boron in [BF4]−[BF_4]^-[BF4​]− are
  1. (A)4 and 3
  2. (B)4 and 4
  3. (C)3 and 4
  4. (D)3 and 5

Correct answer: (A)

Step-by-step solution →
Q50·ChemistrySingle correct
Which of the following complexes will exhibit maximum attraction to an applied magnetic field?
  1. (A)[Zn(H2O)6]2+[Zn(H_2O)_6]^{2+}[Zn(H2​O)6​]2+
  2. (B)[Co(H2O)6]2+[Co(H_2O)_6]^{2+}[Co(H2​O)6​]2+
  3. (C)[Co(en)3]3+[Co(en)_3]^{3+}[Co(en)3​]3+
  4. (D)[Ni(H2O)6]2+[Ni(H_2O)_6]^{2+}[Ni(H2​O)6​]2+

Correct answer: (B)

Step-by-step solution →
Q51·ChemistryNumerical
0.400 g of an organic compound (X) gave 0.376 g of AgBr in Carius method for estimation of bromine. % of bromine in the compound (X) is ____. (Given: Molar mass AgBr = 188 g mol−1^{-1}−1, Br = 80 g mol−1^{-1}−1)

Correct answer: 40

Step-by-step solution →
Q52·ChemistryNumerical
1 g of a carbonate (M2CO3M_2CO_3M2​CO3​) on treatment with excess HCl produces 0.01 mol of CO2CO_2CO2​. The molar mass of M2CO3M_2CO_3M2​CO3​ is ____ g mol−1^{-1}−1. (Nearest integer)

Correct answer: 100

Step-by-step solution →
Q53·ChemistryNumerical
See the following chemical reaction: Cr2O72−+XH++6Fe2+→YCr3++6Fe3++ZH2OCr_2O_7^{2-} + XH^+ + 6Fe^{2+} \rightarrow YCr^{3+} + 6Fe^{3+} + ZH_2OCr2​O72−​+XH++6Fe2+→YCr3++6Fe3++ZH2​O. The sum of X, Y and Z is ____.

Correct answer: 23

Step-by-step solution →
Q54·ChemistryNumerical
If the formula of Borax is Na2B4Ox(OH)y⋅zH2ONa_2B_4O_x(OH)_y \cdot zH_2ONa2​B4​Ox​(OH)y​⋅zH2​O, then x+y+z=x + y + z =x+y+z= ____.

Correct answer: 17

Step-by-step solution →
Q55·ChemistryNumerical
At 298 K, the standard reduction potential for Cu2+/CuCu^{2+}/CuCu2+/Cu electrode is 0.34 V. Given: KspK_{sp}Ksp​ of Cu(OH)2=1×10−20Cu(OH)_2 = 1 \times 10^{-20}Cu(OH)2​=1×10−20. Take 2.303RTF=0.059\dfrac{2.303RT}{F} = 0.059F2.303RT​=0.059 V. The reduction potential at pH = 14 for the above couple is (−)x×10−2(-)x \times 10^{-2}(−)x×10−2 V. The value of x is ____.

Correct answer: 25

Step-by-step solution →
Q56·ChemistryNumerical
20 mL of 0.1 M NaOH is added to 50 mL of 0.1 M acetic acid solution. The pH of the resulting solution is ____ ×10−2\times 10^{-2}×10−2 (Nearest integer). Given: pKa (CH3COOH)=4.76(CH_3COOH) = 4.76(CH3​COOH)=4.76.

Correct answer: 448

Step-by-step solution →
Q57·ChemistryNumerical
A(g)→2B(g)+C(g)A(g) \rightarrow 2B(g) + C(g)A(g)→2B(g)+C(g) is a first order reaction. The initial pressure of the system was found to be 800 mm Hg which increased to 1600 mm Hg after 10 min. The total pressure of the system after 30 min will be ____ mm Hg. (Nearest integer)

Correct answer: 2200

Step-by-step solution →
Q58·ChemistryNumerical
The orbital angular momentum of an electron in 3s orbital is xh2π\dfrac{xh}{2\pi}2πxh​. The value of x is

Correct answer: 0

Step-by-step solution →
Q59·ChemistryNumerical
Sodium metal crystallizes in a body centred cubic lattice with unit cell edge length of 4 Å. The radius of sodium atom is ____ ×10−1\times 10^{-1}×10−1 Å (Nearest integer)

Correct answer: 17

Step-by-step solution →
Q60·ChemistryNumerical
Sea water contains 29.25% NaCl and 19% MgCl2MgCl_2MgCl2​ by weight of solution. The normal boiling point of the sea water is ____ °C (Nearest integer). Assume 100% ionization for both NaCl and MgCl2MgCl_2MgCl2​. Given: Kb(H2O)=0.52K_b(H_2O) = 0.52Kb​(H2​O)=0.52 K kg mol−1^{-1}−1. Molar mass of NaCl and MgCl2MgCl_2MgCl2​ is 58.5 and 95 g mol−1^{-1}−1 respectively.

Correct answer: 116

Step-by-step solution →

Mathematics — JEE Main 13 April 2023 Shift 2

Q61·MathematicsSingle correct
If the system of equations 2x+y−z=52x + y - z = 52x+y−z=5, 2x−5y+λz=μ2x - 5y + \lambda z = \mu2x−5y+λz=μ, x+2y−5z=7x + 2y - 5z = 7x+2y−5z=7 has infinitely many solutions, then (λ+μ)2+(λ−μ)2(\lambda + \mu)^2 + (\lambda - \mu)^2(λ+μ)2+(λ−μ)2 is equal to
  1. (A)916
  2. (B)912
  3. (C)920
  4. (D)904

Correct answer: (A)

Step-by-step solution →
Q62·MathematicsSingle correct
The coefficient of x5x^5x5 in the expansion of (2x3−13x2)5\left(2x^3 - \dfrac{1}{3x^2}\right)^5(2x3−3x21​)5 is
  1. (A)8
  2. (B)9
  3. (C)809\dfrac{80}{9}980​
  4. (D)263\dfrac{26}{3}326​

Correct answer: (C)

Step-by-step solution →
Q63·MathematicsSingle correct
The plane, passing through the points (0,−1,2)(0, -1, 2)(0,−1,2) and (−1,2,1)(-1, 2, 1)(−1,2,1) and parallel to the line passing through (5,1,−7)(5, 1, -7)(5,1,−7) and (1,−1,−1)(1, -1, -1)(1,−1,−1), also passes through the point
  1. (A)(1,−2,1)(1, -2, 1)(1,−2,1)
  2. (B)(0,5,−2)(0, 5, -2)(0,5,−2)
  3. (C)(−2,5,0)(-2, 5, 0)(−2,5,0)
  4. (D)(2,0,1)(2, 0, 1)(2,0,1)

Correct answer: (C)

Step-by-step solution →
Q64·MathematicsSingle correct
Let α,β\alpha, \betaα,β be the roots of the equation x2−2x+2=0x^2 - \sqrt{2}x + 2 = 0x2−2​x+2=0. Then α14+β14\alpha^{14} + \beta^{14}α14+β14 is equal to
  1. (A)−642-64\sqrt{2}−642​
  2. (B)−1282-128\sqrt{2}−1282​
  3. (C)−64-64−64
  4. (D)−128-128−128

Correct answer: (D)

Step-by-step solution →
Q65·MathematicsSingle correct
Let a1,a2,a3,…a_1, a_2, a_3, \ldotsa1​,a2​,a3​,… be a G.P. of increasing positive numbers. Let the sum of its 6th6^{th}6th and 8th8^{th}8th terms be 2 and the product of its 3rd3^{rd}3rd and 5th5^{th}5th terms be 19\dfrac{1}{9}91​. Then 6(a2+a4)(a4+a6)6(a_2 + a_4)(a_4 + a_6)6(a2​+a4​)(a4​+a6​) is equal to
  1. (A)222\sqrt{2}22​
  2. (B)222
  3. (C)333\sqrt{3}33​
  4. (D)333

Correct answer: (D)

Step-by-step solution →
Q66·MathematicsSingle correct
Let (α,β)(\alpha, \beta)(α,β) be the centroid of the triangle formed by the lines 15x−y=8215x - y = 8215x−y=82, 6x−5y=−46x - 5y = -46x−5y=−4 and 9x+4y=179x + 4y = 179x+4y=17. Then α+β\alpha + \betaα+β and 9α−β9\alpha - \beta9α−β are the roots of the equation
  1. (A)x2−7x+12=0x^2 - 7x + 12 = 0x2−7x+12=0
  2. (B)x2−13x+42=0x^2 - 13x + 42 = 0x2−13x+42=0
  3. (C)x2−14x+48=0x^2 - 14x + 48 = 0x2−14x+48=0
  4. (D)x2−10x+25=0x^2 - 10x + 25 = 0x2−10x+25=0

Correct answer: (B)

Step-by-step solution →
Q67·MathematicsSingle correct
Let ∣a⃗∣=2|\vec{a}| = 2∣a∣=2, ∣b⃗∣=3|\vec{b}| = 3∣b∣=3 and the angle between the vectors a⃗\vec{a}a and b⃗\vec{b}b be π4\dfrac{\pi}{4}4π​. Then ∣(a⃗+2b⃗)×(2a⃗−3b⃗)∣2\left|(\vec{a} + 2\vec{b}) \times (2\vec{a} - 3\vec{b})\right|^2​(a+2b)×(2a−3b)​2 is equal to
  1. (A)482
  2. (B)441
  3. (C)841
  4. (D)882

Correct answer: (D)

Step-by-step solution →
Q68·MathematicsSingle correct
Let N be the foot of perpendicular from the point P(1,−2,3)P(1, -2, 3)P(1,−2,3) on the line passing through the points (4,5,8)(4, 5, 8)(4,5,8) and (1,−7,5)(1, -7, 5)(1,−7,5). Then the distance of N from the plane 2x−2y+z+5=02x - 2y + z + 5 = 02x−2y+z+5=0 is
  1. (A)6
  2. (B)9
  3. (C)7
  4. (D)8

Correct answer: (C)

Step-by-step solution →
Q69·MathematicsSingle correct
If lim⁡x→0eax−cos⁡(bx)−cxe−cx21−cos⁡(2x)=17\lim\limits_{x \to 0} \dfrac{e^{ax} - \cos(bx) - \dfrac{cxe^{-cx}}{2}}{1 - \cos(2x)} = 17x→0lim​1−cos(2x)eax−cos(bx)−2cxe−cx​​=17, then 5a2+b25a^2 + b^25a2+b2 is
  1. (A)72
  2. (B)76
  3. (C)68
  4. (D)64

Correct answer: (C)

Step-by-step solution →
Q70·MathematicsSingle correct
Let the centre of a circle C be (α,β)(\alpha, \beta)(α,β) and its radius r<8r < 8r<8. Let 3x+4y=243x + 4y = 243x+4y=24 and 3x−4y=323x - 4y = 323x−4y=32 be two tangents and 4x+3y=14x + 3y = 14x+3y=1 be a normal to C. Then (α−β+r)(\alpha - \beta + r)(α−β+r) is equal to
  1. (A)7
  2. (B)9
  3. (C)5
  4. (D)6

Correct answer: (A)

Step-by-step solution →
Q71·MathematicsSingle correct
All words, with or without meaning, are made using all the letters of the word MONDAY. These words are written as in a dictionary with serial numbers. The serial number of the word MONDAY is
  1. (A)327
  2. (B)326
  3. (C)328
  4. (D)324

Correct answer: (A)

Step-by-step solution →
Q72·MathematicsSingle correct
The range of f(x)=4sin⁡−1(x2x2+1)f(x) = 4\sin^{-1}\left(\dfrac{x^2}{x^2+1}\right)f(x)=4sin−1(x2+1x2​) is
  1. (A)[0,π][0, \pi][0,π]
  2. (B)[0,2π)[0, 2\pi)[0,2π)
  3. (C)[0,π)[0, \pi)[0,π)
  4. (D)[0,2π][0, 2\pi][0,2π]

Correct answer: (B)

Step-by-step solution →
Q73·MathematicsSingle correct
The statement (∼(p⇔∼q))∧q(\sim(p \Leftrightarrow \sim q)) \wedge q(∼(p⇔∼q))∧q is equivalent to
  1. (A)(∼p)∧(∼q)(\sim p) \wedge (\sim q)(∼p)∧(∼q)
  2. (B)p∧(∼q)p \wedge (\sim q)p∧(∼q)
  3. (C)(∼p)∨q(\sim p) \vee q(∼p)∨q
  4. (D)p∨qp \vee qp∨q

Correct answer: (A)

Step-by-step solution →
Q74·MathematicsSingle correct
The random variable X follows binomial distribution B(n,p)B(n, p)B(n,p) for which the difference of the mean and the variance is 1. If 2P(X=2)=3P(X=1)2P(X = 2) = 3P(X = 1)2P(X=2)=3P(X=1), then n2P(X>1)n^2 P(X > 1)n2P(X>1) is equal to
  1. (A)12
  2. (B)15
  3. (C)11
  4. (D)16

Correct answer: (C)

Step-by-step solution →
Q75·MathematicsSingle correct
Let for A=[123α31112]A = \begin{bmatrix} 1 & 2 & 3 \\ \alpha & 3 & 1 \\ 1 & 1 & 2 \end{bmatrix}A=​1α1​231​312​​, ∣A∣=2|A| = 2∣A∣=2. If ∣2 adj (2 adj (2A))∣=32n\left|2\,\text{adj}\,(2\,\text{adj}\,(2A))\right| = 32^n∣2adj(2adj(2A))∣=32n, then 3n+α3n + \alpha3n+α is equal to
  1. (A)10
  2. (B)9
  3. (C)12
  4. (D)11

Correct answer: (D)

Step-by-step solution →
Q76·MathematicsSingle correct
Let S={z∈C:zˉ=i(z2+Re(zˉ))}S = \left\{ z \in \mathbb{C} : \bar{z} = i(z^2 + \text{Re}(\bar{z})) \right\}S={z∈C:zˉ=i(z2+Re(zˉ))}. Then ∑z∈S∣z∣2\sum\limits_{z \in S} |z|^2z∈S∑​∣z∣2 is equal to
  1. (A)72\dfrac{7}{2}27​
  2. (B)444
  3. (C)52\dfrac{5}{2}25​
  4. (D)333

Correct answer: (B)

Step-by-step solution →
Q77·MathematicsSingle correct
The area of the region {(x,y):x2≤y≤∣x2−4∣, y≥1}\left\{(x, y) : x^2 \le y \le \left|x^2 - 4\right|,\ y \ge 1\right\}{(x,y):x2≤y≤​x2−4​, y≥1} is
  1. (A)34(42−1)\dfrac{3}{4}\left(4\sqrt{2} - 1\right)43​(42​−1)
  2. (B)43(42−1)\dfrac{4}{3}\left(4\sqrt{2} - 1\right)34​(42​−1)
  3. (C)43(42+1)\dfrac{4}{3}\left(4\sqrt{2} + 1\right)34​(42​+1)
  4. (D)34(42+1)\dfrac{3}{4}\left(4\sqrt{2} + 1\right)43​(42​+1)

Correct answer: (B)

Step-by-step solution →
Q78·MathematicsSingle correct
Let for a triangle ABC, AB→=−2i^+j^+3k^\overrightarrow{AB} = -2\hat{i} + \hat{j} + 3\hat{k}AB=−2i^+j^​+3k^, CB→=αi^+βj^+γk^\overrightarrow{CB} = \alpha\hat{i} + \beta\hat{j} + \gamma\hat{k}CB=αi^+βj^​+γk^, CA→=4i^+3j^+δk^\overrightarrow{CA} = 4\hat{i} + 3\hat{j} + \delta\hat{k}CA=4i^+3j^​+δk^. If δ>0\delta > 0δ>0 and the area of the triangle ABC is 565\sqrt{6}56​, then CB→⋅CA→\overrightarrow{CB} \cdot \overrightarrow{CA}CB⋅CA is equal to
  1. (A)60
  2. (B)120
  3. (C)108
  4. (D)54

Correct answer: (A)

Step-by-step solution →
Q79·MathematicsSingle correct
The line, that is coplanar to the line x+3−3=y−11=z−55\dfrac{x+3}{-3} = \dfrac{y-1}{1} = \dfrac{z-5}{5}−3x+3​=1y−1​=5z−5​, is
  1. (A)x+11=y−22=z−55\dfrac{x+1}{1} = \dfrac{y-2}{2} = \dfrac{z-5}{5}1x+1​=2y−2​=5z−5​
  2. (B)x+1−1=y−22=z−55\dfrac{x+1}{-1} = \dfrac{y-2}{2} = \dfrac{z-5}{5}−1x+1​=2y−2​=5z−5​
  3. (C)x+1−1=y−22=z−54\dfrac{x+1}{-1} = \dfrac{y-2}{2} = \dfrac{z-5}{4}−1x+1​=2y−2​=4z−5​
  4. (D)x−1−1=y−22=z−55\dfrac{x-1}{-1} = \dfrac{y-2}{2} = \dfrac{z-5}{5}−1x−1​=2y−2​=5z−5​

Correct answer: (B)

Step-by-step solution →
Q80·MathematicsSingle correct
The value of ∫0π4e−x+∫0π4e−xtan⁡50x dx∫0π4e−x(tan⁡49x+tan⁡51x)dx\dfrac{\displaystyle\int_{0}^{\frac{\pi}{4}} e^{-x} + \int_{0}^{\frac{\pi}{4}} e^{-x}\tan^{50}x\,dx}{\displaystyle\int_{0}^{\frac{\pi}{4}} e^{-x}\left(\tan^{49}x + \tan^{51}x\right)dx}∫04π​​e−x(tan49x+tan51x)dx∫04π​​e−x+∫04π​​e−xtan50xdx​ is
  1. (A)50
  2. (B)49
  3. (C)51
  4. (D)52

Correct answer: (A)

Step-by-step solution →
Q81·MathematicsNumerical
The mean and standard deviation of the marks of 10 students were found to be 50 and 12 respectively. Later, it was observed that two marks 20 and 25 were wrongly read as 45 and 50 respectively. Then the correct variance is

Correct answer: 269

Step-by-step solution →
Q82·MathematicsNumerical
Let A={−4,−3,−2,0,1,3,4}A = \{-4, -3, -2, 0, 1, 3, 4\}A={−4,−3,−2,0,1,3,4} and R={(a,b)∈A×A:b=∣a∣ or b2=a+1}R = \{(a, b) \in A \times A : b = |a| \text{ or } b^2 = a + 1\}R={(a,b)∈A×A:b=∣a∣ or b2=a+1} be a relation on A. Then the minimum number of elements, that must be added to the relation R so that it becomes reflexive and symmetric, is

Correct answer: 7

Step-by-step solution →
Q83·MathematicsNumerical
Let f(x)=∑k=110kxkf(x) = \sum\limits_{k=1}^{10} k x^kf(x)=k=1∑10​kxk, x∈Rx \in \mathbb{R}x∈R. If 2f(2)+f′(2)=119(2)k+12f(2) + f'(2) = 119(2)^k + 12f(2)+f′(2)=119(2)k+1 then kkk is equal to

Correct answer: 10

Step-by-step solution →
Q84·MathematicsNumerical
Total number of 3-digit numbers that are divisible by 6 and can be formed by using the digits 1, 2, 3, 4, 5 with repetition, is

Correct answer: 16

Step-by-step solution →
Q85·MathematicsNumerical
Let [α][\alpha][α] denote the greatest integer ≤α\le \alpha≤α. Then [1]+[2]+[3]+…+[120]\left[\sqrt{1}\right] + \left[\sqrt{2}\right] + \left[\sqrt{3}\right] + \ldots + \left[\sqrt{120}\right][1​]+[2​]+[3​]+…+[120​] is equal to

Correct answer: 825

Step-by-step solution →
Q86·MathematicsNumerical
For x∈(−1,1]x \in (-1, 1]x∈(−1,1], the number of solutions of the equation sin⁡−1x=2tan⁡−1x\sin^{-1}x = 2\tan^{-1}xsin−1x=2tan−1x is equal to

Correct answer: 2

Step-by-step solution →
Q87·MathematicsNumerical
If y=y(x)y = y(x)y=y(x) is the solution of the differential equation dydx+4x(x2−1)y=x+2(x2−1)52\dfrac{dy}{dx} + \dfrac{4x}{(x^2-1)}y = \dfrac{x+2}{(x^2-1)^{\frac{5}{2}}}dxdy​+(x2−1)4x​y=(x2−1)25​x+2​, x>1x > 1x>1 such that y(2)=29log⁡e(2+3)y(2) = \dfrac{2}{9}\log_e\left(2 + \sqrt{3}\right)y(2)=92​loge​(2+3​) and y(2)=αlog⁡e(α+β)+β−γy\left(\sqrt{2}\right) = \alpha\log_e\left(\sqrt{\alpha} + \beta\right) + \beta - \sqrt{\gamma}y(2​)=αloge​(α​+β)+β−γ​, α,β,γ∈N\alpha, \beta, \gamma \in \mathbb{N}α,β,γ∈N, then αβγ\alpha\beta\gammaαβγ is equal to

Correct answer: 6

Step-by-step solution →
Q88·MathematicsNumerical
The foci of a hyperbola are (±2,0)(\pm 2, 0)(±2,0) and its eccentricity is 32\dfrac{3}{2}23​. A tangent, perpendicular to the line 2x+3y=62x + 3y = 62x+3y=6, is drawn at a point in the first quadrant on the hyperbola. If the intercepts made by the tangent on the x- and y-axes are aaa and bbb respectively, then ∣6a∣+∣5b∣|6a| + |5b|∣6a∣+∣5b∣ is equal to

Correct answer: 12

Step-by-step solution →
Q89·MathematicsNumerical
Let fn=∫0π2(∑k=1nsin⁡k−1x)(∑k=1n(2k−1)sin⁡k−1x)cos⁡x dxf_n = \int_{0}^{\frac{\pi}{2}} \left(\sum\limits_{k=1}^{n} \sin^{k-1}x\right)\left(\sum\limits_{k=1}^{n} (2k-1)\sin^{k-1}x\right)\cos x\, dxfn​=∫02π​​(k=1∑n​sink−1x)(k=1∑n​(2k−1)sink−1x)cosxdx, n∈Nn \in \mathbb{N}n∈N. Then f21−f20f_{21} - f_{20}f21​−f20​ is equal to

Correct answer: 41

Step-by-step solution →
Q90·MathematicsNumerical
The remainder, when 71037^{103}7103 is divided by 17, is

Correct answer: 12

Step-by-step solution →

Chapters tested in this paper

Open any chapter to practise every past-year question on that topic across all papers, and see how often it has actually appeared.

  • Properties of Solids and Liquids 172/186
  • Three Dimensional Geometry 176/186
  • Matrices and Determinants 180/186
  • Coordination Compounds 176/186
  • Sets, Relations and Functions 165/186
  • Sequence and Series 164/186
  • p-Block Elements 164/186
  • Definite Integration 168/186
  • Rotational Motion 172/186
  • Redox Reactions and Electrochemistry 177/186
  • Geometrical Optics 172/186
  • Kinematics 156/186
  • Vector Algebra 173/186
  • Differential Equations 167/186
  • Probability 176/186
  • Permutations and Combinations 162/186
  • Magnetic Field of Current 147/186
  • Binomial Theorem and Its Simple Applications 158/186
  • Electromagnetic Waves 144/186
  • Chemical Bonding and Molecular Structure 151/186
  • Limits and Continuity 149/186
  • Thermodynamics 154/186
  • Equilibrium 163/186
  • Solutions 158/186
  • Laws of Motion 130/186
  • Chemical Thermodynamics 165/186
  • Units and Measurements 149/186
  • Complex Numbers 165/186
  • Biomolecules 162/186
  • Chemical Kinetics 169/186
  • Gravitation 152/186
  • Electric Field and Coulomb's Law 133/186
  • Atomic Structure 161/186
  • Electronic Devices 145/186
  • Circles 142/186
  • Dual Nature of Matter and Radiation 155/186
  • Work, Energy and Power 132/186
  • Some Basic Concepts in Chemistry 129/186
  • Electromagnetic Induction 120/186
  • Wave Optics 130/186
  • Area Under Curves 139/186
  • Kinetic Theory of Gases 135/186
  • Purification and Characterisation of Organic Compounds 116/186
  • Oscillations 117/186
  • Alternating Currents 108/186
  • Nuclei 116/186
  • Organic Compounds Containing Halogens 109/186
  • Straight Lines 114/186
  • Waves 109/186
  • Capacitors and Dielectrics 115/186
  • Atoms 112/186
  • Statistics 118/186
  • Isolation of Metals 106/186
  • s-Block Elements 88/186
  • Surface Chemistry 98/186
  • Inverse Trigonometric Functions 93/186
  • Environmental Chemistry 83/186
  • Hydrogen 81/186
  • Electronic Effects and Stability 74/186
  • Hyperbola 77/186
  • Polymers 64/186
  • Solid State 63/186
  • Principles of Qualitative Analysis 58/186
  • Diazonium Salts and Reactions 53/186
  • Reaction Mechanism 29/186
  • Aromaticity 22/186
← 13 Apr Shift 1 2023All papers15 Apr Shift 1 2023 →

Attempt this paper under exam timing.

Take the 13 April 2023 Shift 2 paper as a timed mock and Jarvis marks it, then tells you which errors were conceptual gaps, which were silly mistakes, and which pattern you have now repeated. Step-by-step solutions for every question included.

Attempt this paper freeSee pricing

Free plan, no time limit · No credit card needed

Jarvis OS

AI-powered JEE preparation.

Question papers

JEE Main PYQsJEE Advanced PYQsPhysics PYQsChemistry PYQsMaths PYQs

Product

TourPricingSign inCreate account

Legal

Privacy PolicyTerms of ServiceRefund & CancellationShipping & DeliveryContact Us

Operated by

Venyou Craft Private Limited

info@jarvisos.net

© 2026 Jarvis OS