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JEE Main 12 April 2023 Shift 1 Question Paper with Answers

12 April 2023 · April session · 90 questions

The complete JEE Main 12 April 2023 Shift 1 paper — all 90 questions with the correct answer for each, tagged to the chapter it tests. Free to read, no account needed.

Physics
30
Chemistry
30
Mathematics
30

Physics — JEE Main 12 April 2023 Shift 1

Q1·Physics·Geometrical OpticsSingle correct
An ice cube has a bubble inside. When viewed from one side the apparent distance of the bubble is 12 cm. When viewed from the opposite side, the apparent distance of the bubble is observed as 4 cm. If the side of the ice cube is 24 cm, the refractive index of the ice cube is
  1. (A)43\dfrac4334​
  2. (B)32\dfrac3223​
  3. (C)23\dfrac2332​
  4. (D)65\dfrac6556​

Correct answer: (B)

Step-by-step solution →
Q2·PhysicsSingle correct
Two satellites A and B move round the earth in the same orbit. The mass of A is twice the mass of B. The quantity which is same for the two satellites will be:
  1. (A)Potential energy
  2. (B)Total energy
  3. (C)Kinetic energy
  4. (D)Speed

Correct answer: (D)

Step-by-step solution →
Q3·PhysicsSingle correct
The amplitude of 15 sin(1000π\piπt) signal is modulated by 10 sin(4π\piπt) signal. The amplitude modulated signal contains frequencies of 1. 500 Hz 2. 2 Hz 3. 250 Hz 4. 498 Hz 5. 502 Hz. Choose the correct answer from the options given below:
  1. (A)(1) and (3) only
  2. (B)(2) and (4) only
  3. (C)(3) and (2) only
  4. (D)(1), (4) and (5) only

Correct answer: (D)

Step-by-step solution →
Q4·PhysicsSingle correct
In an n-p-n common emitter (CE) transistor the collector current changes from 5 mA to 16 mA for the change in base current from 100 μ\muμA and 200 μ\muμA, respectively. The current gain of transistor is _________.
  1. (A)110
  2. (B)0.9
  3. (C)210
  4. (D)9

Correct answer: (A)

Step-by-step solution →
Q5·PhysicsSingle correct
If the r.m.s. speed of chlorine molecule is 490 m/s at 27°C, the r.m.s. speed of argon molecules at the same temperature will be (Atomic mass of argon = 39.9u, molecular mass of chlorine = 70.9u)
  1. (A)751.7 m/s
  2. (B)451.7 m/s
  3. (C)651.7 m/s
  4. (D)551.7 m/s

Correct answer: (C)

Step-by-step solution →
Q6·PhysicsSingle correct
A proton and an α\alphaα-particle are accelerated from rest by 2V and 4V potentials, respectively. The ratio of their de-Broglie wavelength is:
  1. (A)4:1
  2. (B)2:1
  3. (C)8:1
  4. (D)16:1

Correct answer: (A)

Step-by-step solution →
Q7·Physics·Magnetism and MatterSingle correct
Given below are two statements: Statement I: The diamagnetic property depends on temperature. Statement II: The induced magnetic dipole moment in a diamagnetic sample is always opposite to the magnetizing field. In the light of given statement, choose the correct answer from the options given below:
  1. (A)Statement I is incorrect but Statement II is true
  2. (B)Both Statement I and Statement II are true.
  3. (C)Both Statement I and Statement II are false.
  4. (D)Statement I is correct but Statement II is false.

Correct answer: (A)

Step-by-step solution →
Q8·PhysicsSingle correct
A wire of resistance 160 Ω\OmegaΩ is melted and drawn in wire of one-fourth of its length. The new resistance of the wire will be
  1. (A)10 Ω\OmegaΩ
  2. (B)640 Ω\OmegaΩ
  3. (C)40 Ω\OmegaΩ
  4. (D)16 Ω\OmegaΩ

Correct answer: (A)

Step-by-step solution →
Q9·PhysicsSingle correct
Match List I (physical quantities: spring constant, angular speed, angular momentum, moment of inertia) with List II (dimensional formulae). Choose the correct answer from the options given below:
List IList II
A.Spring constantI.[T−1][T^{-1}][T−1]
B.Angular speedII.[MT−2][MT^{-2}][MT−2]
C.Angular momentumIII.[ML2][ML^2][ML2]
D.Moment of InertiaIV.[ML2T−1][ML^2T^{-1}][ML2T−1]
  1. (A)A-II, B-I, C-IV, D-III
  2. (B)A-IV, B-I, C-III, D-II
  3. (C)A-II, B-III, C-I, D-IV
  4. (D)A-II, B-III, C-II, D-IV

Correct answer: (A)

Step-by-step solution →
Q10·PhysicsSingle correct
Three forces F1=10F_1=10F1​=10 N, F2=8F_2=8F2​=8 N, F3=6F_3=6F3​=6 N are acting on a particle of mass 5 kg. The forces F2F_2F2​ and F3F_3F3​ are applied perpendicular so that particle remains at rest. If the force F1F_1F1​ is removed, then the acceleration of the particle is:
  1. (A)2 ms−2^{-2}−2
  2. (B)0.5 ms−2^{-2}−2
  3. (C)4.8 ms−2^{-2}−2
  4. (D)7 ms−2^{-2}−2

Correct answer: (A)

Step-by-step solution →
Q11·PhysicsSingle correct
A body cools from 80°C to 60°C in 5 minutes. The temperature of the surrounding is 20°C. The time it takes to cool from 60°C to 40°C is:
  1. (A)500 s
  2. (B)253\dfrac{25}{3}325​ s
  3. (C)450 s
  4. (D)420 s

Correct answer: (A)

Step-by-step solution →
Q12·PhysicsSingle correct
An engine operating between the boiling and freezing points of water will have 1. efficiency more than 27% 2. efficiency less than the efficiency of a Carnot engine operating between the same two temperatures 3. efficiency equal to 27% 4. efficiency less than 27%. Choose the correct answer from the options given below:
  1. (A)2, 3 and 4 only
  2. (B)2 and 3 only
  3. (C)2 and 4 only
  4. (D)1 and 2 only

Correct answer: (C)

Step-by-step solution →
Q13·PhysicsSingle correct
Given below are two statements: Statement I: A truck and a car moving with same kinetic energy are brought to rest by applying brakes which provide equal retarding forces. Both come to rest in equal distance. Statement II: A car moving towards east takes a turn and moves towards north, the speed remains unchanged. The acceleration of the car is zero. In the light of given statements, choose the most appropriate answer from the options given below:
  1. (A)Statement I is correct but Statement II is incorrect
  2. (B)Statement I is incorrect but Statement II is correct
  3. (C)Both Statement I and Statement II are correct but II not explanation of I
  4. (D)Both Statement I and Statement II are correct

Correct answer: (A)

Step-by-step solution →
Q14·Physics·OscillationsSingle correct
A particle is executing Simple Harmonic Motion (SHM). The ratio of potential energy and kinetic energy of the particle when its displacement is half of its amplitude will be:
  1. (A)1 : 1
  2. (B)2 : 1
  3. (C)1 : 4
  4. (D)1 : 3

Correct answer: (D)

Step-by-step solution →
Q15·PhysicsSingle correct
A ball is thrown vertically upward with an initial velocity of 150 m/s. The ratio of velocity after 3 s and 5 s is x+1x\dfrac{x+1}{x}xx+1​. The value of x is _________. (Take g=10g=10g=10 m/s2^22)
  1. (A)6
  2. (B)5
  3. (C)-5
  4. (D)10

Correct answer: (B)

Step-by-step solution →
Q16·PhysicsSingle correct
Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R. Assertion A: If we move from poles to equator, the direction of acceleration due to gravity of earth always points downward. Reason R: Electric dipole consists of two equal and opposite charges. In the light of above statements, choose the correct answer from the options given below:
  1. (A)Both A and R are true and R is the correct explanation of A
  2. (B)A is true but R is false
  3. (C)Both A and R true but R is NOT the correct explanation of A
  4. (D)A is false but R is true

Correct answer: (A)

Step-by-step solution →
Q17·PhysicsSingle correct
Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R. Assertion A: EM waves used for optical communication have longer wavelengths than that of microwave, employed in Radar technology. Reason R: Infrared EM waves are more energetic than microwaves (used in Radar). In the light of given statements, choose the correct answer from the options given below:
  1. (A)A is false but R is true
  2. (B)A is true but R is false
  3. (C)Both A and R true but R is NOT the correct explanation of A
  4. (D)Both A and R true and R is the correct explanation of A

Correct answer: (A)

Step-by-step solution →
Q18·PhysicsSingle correct
A 12.5 eV electron beam is used to bombard gaseous hydrogen at room temperature. The number of spectral lines emitted will be:
  1. (A)2
  2. (B)1
  3. (C)3
  4. (D)4

Correct answer: (C)

Step-by-step solution →
Q19·PhysicsSingle correct
The ratio of escape velocity of a planet to the escape velocity of earth will be: Given: Mass of the planet is 16 times mass of the earth and 4 times the radius of earth.
  1. (A)4 : 1
  2. (B)2 : 1
  3. (C)1 : 2\sqrt22​
  4. (D)1 : 4

Correct answer: (B)

Step-by-step solution →
Q20·Physics·Alternating CurrentsSingle correct
Given below are two statements: Statement I: When the frequency of an a.c. source in a series LCR circuit increases, the current in the circuit first increases, attains a maximum value and then decreases. Statement II: In a series LCR circuit, the value of power factor at resonance is one. In the light of given statements, choose the most appropriate answer from the options given below:
  1. (A)Statement I is false but Statement II is true.
  2. (B)Both Statement I and Statement II are false.
  3. (C)Statement I is correct but Statement II is false.
  4. (D)Both Statement I and Statement II are true.

Correct answer: (D)

Step-by-step solution →
Q21·Physics·WavesNumerical
For a certain organ pipe, the first three resonance frequencies are in the ratio of 1:3:5 respectively. If the frequency of fifth harmonic is 405 Hz and the speed of sound in air is 324 m s−1^{-1}−1, the length of the organ pipe is _________ m.

Correct answer: 1

Step-by-step solution →
Q22·PhysicsNumerical
For a rolling spherical shell, the ratio of rotational kinetic energy and total kinetic energy is x5\dfrac{x}{5}5x​. The value of x is _________.

Correct answer: 2

Step-by-step solution →
Q23·Physics·Magnetism and MatterNumerical
A compass needle oscillates 20 times per minute at a place where the dip is 30° and 30 times per minute where the dip is 60°. The ratio of total magnetic field due to the earth at the two places respectively is 4x\dfrac{4}{\sqrt{x}}x​4​. The value of x is _________.

Correct answer: 243

Step-by-step solution →
Q24·Physics·Electromagnetic InductionNumerical
A conducting circular loop is placed in a uniform magnetic field of 0.4 T with its plane perpendicular to the field. Somehow, the radius of the loop starts expanding at a constant rate of 1 mm/s. The magnitude of induced emf in the loop at an instant when the radius of the loop is 1 cm will be _________ μ\muμV.

Correct answer: 50

Step-by-step solution →
Q25·PhysicsNumerical
To maintain a speed of 80 km/h by a bus of mass 500 kg on a plane rough road for 4 km distance, the work done by the engine of the bus will be _________ kJ. [The coefficient of friction between tyre of bus and road is 0.04]

Correct answer: 784

Step-by-step solution →
Q26·PhysicsNumerical
Consider an example of alpha decay 92238U→90234Th+24He+Q_{92}^{238}U\rightarrow{}_{90}^{234}Th+{}_2^4He+Q92238​U→90234​Th+24​He+Q. Given: 92238U=238.05060u_{92}^{238}U=238.05060u92238​U=238.05060u, 90234Th=234.04360u_{90}^{234}Th=234.04360u90234​Th=234.04360u, 24He=4.00260u_2^4He=4.00260u24​He=4.00260u, and 1u=931.5 MeVc21u=931.5\,\dfrac{MeV}{c^2}1u=931.5c2MeV​. The energy released (Q) during the alpha decay of 92238U_{92}^{238}U92238​U is _________ MeV.

Correct answer: 4

Step-by-step solution →
Q27·PhysicsNumerical
The current flowing through a conductor connected across a source is 2A and 1.2 A at 0°C and 50°C respectively. The current flowing through the conductor at 50°C will be _________ ×102^22 mA.

Correct answer: 15

Step-by-step solution →
Q28·Physics·Geometrical OpticsNumerical
Two convex lenses of focal length 20 cm each are placed coaxially with a separation of 60 cm between them. The image of the distant object formed by the combination is at _________ cm from the first lens.

Correct answer: 100

Step-by-step solution →
Q29·PhysicsNumerical
10 resistors each of resistance 10 Ω\OmegaΩ can be connected in such as to get maximum and minimum equivalent resistance. The ratio of maximum and minimum equivalent resistance will be _________.

Correct answer: 100

Step-by-step solution →
Q30·Physics·Electric PotentialNumerical
64 identical drops each charged upto potential of 10 mV are combined to form a bigger drop. The potential of the bigger drop will be _________ mV.

Correct answer: 160

Step-by-step solution →

Chemistry — JEE Main 12 April 2023 Shift 1

Q31·Chemistry·Alcohols and EthersSingle correct
In the reaction shown, a Grignard reagent is formed with Mg and then treated with H2_22​O to give the major product 'A'. 'A' is
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (D)

Step-by-step solution →
Q32·ChemistrySingle correct
Four gases A, B, C and D have critical temperatures 5.3, 33.2, 126.0 and 154.3K respectively. For their adsorption on fixed amount of charcoal, the correct order is:
  1. (A)C > B > D > A
  2. (B)C > D > B > A
  3. (C)D > C > A > B
  4. (D)D > C > B > A

Correct answer: (D)

Step-by-step solution →
Q33·ChemistrySingle correct
Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R. Assertion A: 5f electrons can participate in bonding to a far greater extent than 4f electrons. Reason R: 5f orbitals are not as buried as 4f orbitals. In the light of the above statements, choose the correct answer from the options given below:
  1. (A)Both A and R are true but R is NOT the correct explanation of A
  2. (B)Both A and R are true and R is the correct explanation of A
  3. (C)A is false but R is true
  4. (D)A is true but R is false

Correct answer: (B)

Step-by-step solution →
Q34·Chemistry·AminesSingle correct
The incorrect statement regarding the reaction of the given secondary amine 'A' (shown) with NaNO2NaNO_2NaNO2​ and HX to give 'B' is
  1. (A)The electrophile involved in the reaction is NO+^++
  2. (B)‘B’ is N-nitroso ammonium compound
  3. (C)The reaction occurs at low temperature
  4. (D)The product ‘B’ formed in the above reaction is p-nitroso compound at low temperature

Correct answer: (B)

Step-by-step solution →
Q35·ChemistrySingle correct
Match List I (complex) with List II (CFSE in units of Δ0\Delta_0Δ0​). Choose the correct answer from the options given below:
List I (Complex)List II (CFSE/$\Delta_0$)
A.[Cu(NH3)4]2+[Cu(NH_3)_4]^{2+}[Cu(NH3​)4​]2+I.−0.6-0.6−0.6
B.[Ti(H2O)6]3+[Ti(H_2O)_6]^{3+}[Ti(H2​O)6​]3+II.−2.0-2.0−2.0
C.[Fe(CN)6]3−[Fe(CN)_6]^{3-}[Fe(CN)6​]3−III.−1.2-1.2−1.2
D.[NiF6]2−[NiF_6]^{2-}[NiF6​]2−IV.−0.4-0.4−0.4
  1. (A)A-I, B-IV, C-II, D-III
  2. (B)A-II, B-III, C-IV, D-I
  3. (C)A-I, B-II, C-IV, D-III
  4. (D)A-IV, B-I, C-II, D-III

Correct answer: (A)

Step-by-step solution →
Q36·ChemistrySingle correct
Match List I (polymer) with List II (class). Choose the correct answer from the options given below:
List I (Examples)List II (Examples)
A.2-Chloro-1,3-butadieneI.Biodegradable polymer
B.Nylon 2-nylon 6II.Synthetic Rubber
C.PolyacrylonitrileIII.Polyester
D.DacronIV.Addition Polymer
  1. (A)A-IV, B-I, C-III, D-II
  2. (B)A-II, B-III, C-I, D-IV
  3. (C)A-II, B-I, C-IV, D-III
  4. (D)A-IV, B-I, C-IV, D-III

Correct answer: (C)

Step-by-step solution →
Q37·ChemistrySingle correct
The density of alkali metals is in the order
  1. (A)K < Cs < Na < Rb
  2. (B)Li < K < Na < Rb < Cs
  3. (C)K < Na < Cs < Rb
  4. (D)Na < Rb < K < Cs

Correct answer: (B)

Step-by-step solution →
Q38·ChemistrySingle correct
Given below are two statements: Statement I: SbCl5_55​ is more covalent than SbCl3_33​. Statement II: The higher oxides of halogens also tend to be more stable than the lower ones. In the light of the above statements, choose the most appropriate answer from the options given below:
  1. (A)Both Statement I and Statement II are correct
  2. (B)Both Statement I and Statement II are incorrect
  3. (C)Statement I is correct but Statement II is incorrect
  4. (D)Statement I is incorrect but Statement II is correct

Correct answer: (A)

Step-by-step solution →
Q39·ChemistrySingle correct
A metal chloride contains 55.0% of chlorine by weight. 100 mL vapours of the metal chloride at STP weigh 0.57 g. The molecular formula of the metal chloride is (Given: Atomic mass of chlorine is 35.5u)
  1. (A)MCl2_22​
  2. (B)MCl4_44​
  3. (C)MCl3_33​
  4. (D)MCl

Correct answer: (A)

Step-by-step solution →
Q40·ChemistrySingle correct
Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R. Assertion A: In the Ellingham diagram, a sharp change in slope of the line is observed for Mg→MgOMg\rightarrow MgOMg→MgO at ∼1120°C\sim1120°C∼1120°C. Reason R: There is a large change of entropy associated with the change of state. In the light of the above statements, choose the correct answer from the options given below:
  1. (A)Both A and R are true but R is NOT the correct explanation of A
  2. (B)Both A and R are true and R is the correct explanation of A
  3. (C)A is false but R is true
  4. (D)A is true but R is false

Correct answer: (B)

Step-by-step solution →
Q41·ChemistrySingle correct
Match List I (pollutant source) with List II (environmental effect). Choose the correct answer from the options given below:
List IList II
A.Nitrogen oxides in airI.Eutrophication
B.Methane in airII.pH of rain water becomes 5.6
C.Carbon dioxideIII.Global warming
D.Phosphate fertilisers in waterIV.Acid rain
  1. (A)A-IV, B-III, C-II, D-I
  2. (B)A-II, B-III, C-IV, D-I
  3. (C)A-I, B-III, C-II, D-IV
  4. (D)A-IV, B-II, C-III, D-I

Correct answer: (A)

Step-by-step solution →
Q42·ChemistrySingle correct
For lead storage battery, pick the correct statement. A. During charging of battery, PbSO4_44​ on anode is converted into PbO2_22​. B. During discharging of battery, PbSO4_44​ on cathode is converted into PbO2_22​. C. Lead storage battery consists of grid of lead packed with PbO2_22​ as anode. D. Lead storage battery has ~38% solution of sulphuric acid as an electrolyte. Choose the correct answer from the options given below:
  1. (A)A, D only
  2. (B)B, C, D only
  3. (C)A, B, D only
  4. (D)B, C only

Correct answer: (A)

Step-by-step solution →
Q43·ChemistrySingle correct
222-hexene →(i) O3; (ii) H2O2\xrightarrow{(i)\,O_3;\ (ii)\,H_2O_2}(i)O3​; (ii)H2​O2​​ Products. The two products formed in above reaction are:
  1. (A)Butanoic acid and acetic acid
  2. (B)Butanal and acetic acid
  3. (C)Butanal and acetaldehyde
  4. (D)Butanoic acid and acetaldehyde

Correct answer: (A)

Step-by-step solution →
Q44·Chemistry·Reaction MechanismSingle correct
Correct statements for the given reaction 'A' →OH−, 2eq\xrightarrow{OH^-,\ 2eq}OH−, 2eq​ 'B' (where 'A' is the structure shown) are: A. Compound 'B' is aromatic. B. The completion of above reaction is very slow. C. 'A' shows tautomerism. D. The bond lengths C-C in compound B are found to be same. Choose the correct answer from the options given below:
  1. (A)A, B and D only
  2. (B)A, B and C only
  3. (C)B, C and D only
  4. (D)A, C and D only

Correct answer: (D)

Step-by-step solution →
Q45·ChemistrySingle correct
The bond order and magnetic property of acetylide ion are same as that of
  1. (A)NO+^++
  2. (B)O2+_2^+2+​
  3. (C)O2−_2^-2−​
  4. (D)N2+_2^+2+​

Correct answer: (A)

Step-by-step solution →
Q46·ChemistrySingle correct
The number of molecules and moles in 2.8375 litres of O2_22​ at STP are respectively
  1. (A)1.752 ×\times× 1022^{22}22 and 0.250 mol
  2. (B)1.505 ×\times× 1023^{23}23 and 0.250 mol
  3. (C)7.527 ×\times× 1022^{22}22 and 0.125 mol
  4. (D)7.527 ×\times× 1023^{23}23 and 0.125 mol

Correct answer: (C)

Step-by-step solution →
Q47·ChemistrySingle correct
Given below are two statements: Statement I: Boron is extremely hard indicating its high lattice energy. Statement II: Boron has highest melting and boiling point compared to its other group members. In the light of the above statements, choose the most appropriate answer from the options given below:
  1. (A)Statement I is incorrect but Statement II is correct
  2. (B)Both Statement I and Statement II are correct
  3. (C)Statement I is correct but Statement II is incorrect
  4. (D)Both Statement I and Statement II are incorrect

Correct answer: (B)

Step-by-step solution →
Q48·ChemistrySingle correct
'A' →OH−, Δ\xrightarrow{OH^-,\ \Delta}OH−, Δ​ major product. 'A' (shown) and its major product are:
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (C)

Step-by-step solution →
Q49·ChemistrySingle correct
Match List I (type of hydride) with List II (example). Choose the correct answer from the options given below:
List I (Type of hydride)List II (Example)
A.Electron deficient hydrideI.MgH2_22​
B.Electron rich hydrideII.HF
C.Electron precise hydrideIII.B2_22​H6_66​
D.Saline hydrideIV.CH4_44​
  1. (A)A-III, B-II, C-IV, D-I
  2. (B)A-II, B-III, C-IV, D-I
  3. (C)A-II, B-III, C-I, D-IV
  4. (D)A-III, B-II, C-I, D-IV

Correct answer: (A)

Step-by-step solution →
Q50·Chemistry·Carboxylic Acids and DerivativesSingle correct
The major product 'P' formed in the following sequence of reactions (on the substrate shown) is: (i) SOCl2_22​; (ii) Benzene/AlCl3_33​; (iii) LiAlH4_44​; (iv) H3_33​O+^++
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (D)

Step-by-step solution →
Q51·ChemistryNumerical
One mole of an ideal gas at 350K is in a 2.0 L vessel of thermally conducting walls, which are in contact with the surroundings. It undergoes isothermal reversible expansion from 2.0L to 3.0L against a constant pressure of 4 atm. The change in entropy of the surroundings (ΔS)(\Delta S)(ΔS) is _________ J K−1^{-1}−1 (Nearest integer). Given: R = 8.314 J K−1^{-1}−1 mol−1^{-1}−1.

Correct answer: 3

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Q52·Chemistry·Aldehydes and KetonesNumerical
The mass of NH3_33​ produced when 131.8 kg of cyclohexanecarbaldehyde undergoes Tollen's test is _________ kg. (Nearest integer) Molar Mass of C = 12 g/mol, N = 14 g/mol, O = 16 g/mol.

Correct answer: 60

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Q53·ChemistryNumerical
In an oligopeptide named Alanylglycylphenyl alanyl isoleucine, the number of sp2^22 hybridised carbons is _________.

Correct answer: 10

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Q54·ChemistryNumerical
An analyst wants to convert 1L HCl of pH = 1 to a solution of HCl at pH 2. The volume of water needed to do this dilution is _________ mL. (Nearest Integer)

Correct answer: 9000

Step-by-step solution →
Q55·ChemistryNumerical
Three organic compounds A, B and C were allowed to run in thin layer chromatography using hexane and gave the result shown (see figure). The Rf value of the most polar compound is _________ × 10−2^{-2}−2

Correct answer: 25

Step-by-step solution →
Q56·ChemistryNumerical
80 mole percent of MgCl2_22​ is dissociated in aqueous solution. The vapour pressure of 1.0 molal aqueous solution of MgCl2_22​ at 38°C is _________ mm Hg. (Nearest integer) Given: Vapour pressure of water at 38°C is 50 mm Hg.

Correct answer: 48

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Q57·Chemistry·AminesNumerical
For the substrate shown undergoing the reaction sequence (i) HBr(2eq)/H2_22​O2_22​; (ii) H2_22​/Pd, Δ\DeltaΔ to give 'A', then a further multi-step sequence to give 'D' = C13_{13}13​H19_{19}19​NO4_44​Ix_xx​, the value of x in compound 'D' is _________.

Correct answer: 15

Step-by-step solution →
Q58·ChemistryNumerical
At 600K, the root mean square (rms) speed of gas X (molar mass = 40) is equal to the most probable speed of gas Y at 90K. The molar mass of the gas Y is _________ g mol−1^{-1}−1. (Nearest integer)

Correct answer: 4

Step-by-step solution →
Q59·ChemistryNumerical
The reaction 2NO+Br2→2NOBr2NO+Br_2\rightarrow2NOBr2NO+Br2​→2NOBr takes place through the mechanism given below: NO+Br2⇌NOBr2NO+Br_2\rightleftharpoons NOBr_2NO+Br2​⇌NOBr2​ (fast); NOBr2+NO→2NOBrNOBr_2+NO\rightarrow2NOBrNOBr2​+NO→2NOBr (slow). The overall order of the reaction is _________.

Correct answer: 3

Step-by-step solution →
Q60·ChemistryNumerical
Values of work function (W0W_0W0​) for a few metals are given below — Metal: Li, Na, K, Mg, Cu, Ag; W0W_0W0​/eV: 2.42, 2.3, 2.25, 3.7, 4.8, 4.3. The number of metals which will show photoelectric effect when light of wavelength 400nm falls on it is _________. Given: h = 6.6 × 10−34^{-34}−34 J s; c = 3 × 108^88 m s−1^{-1}−1; e = 1.6 × 10−19^{-19}−19 C.

Correct answer: 3

Step-by-step solution →

Mathematics — JEE Main 12 April 2023 Shift 1

Q61·MathematicsSingle correct
The number of five digit numbers, greater than 40000 and divisible by 5, which can be formed using the digits 0, 1, 3, 5, 7 and 9 without repetition, is equal to
  1. (A)120
  2. (B)132
  3. (C)72
  4. (D)96

Correct answer: (A)

Step-by-step solution →
Q62·MathematicsSingle correct
Let α,β\alpha,\betaα,β be the roots of the quadratic equation x2+6 x+3=0x^2+\sqrt6\,x+3=0x2+6​x+3=0. Then α23+β23+α14+β14α15+β15+α10+β10\dfrac{\alpha^{23}+\beta^{23}+\alpha^{14}+\beta^{14}}{\alpha^{15}+\beta^{15}+\alpha^{10}+\beta^{10}}α15+β15+α10+β10α23+β23+α14+β14​ is equal to
  1. (A)729
  2. (B)72
  3. (C)81
  4. (D)9

Correct answer: (C)

Step-by-step solution →
Q63·MathematicsSingle correct
Let ⟨an⟩\langle a_n\rangle⟨an​⟩ be a sequence such that a1+a2+⋯+an=n2+3n(n+1)(n+2)a_1+a_2+\cdots+a_n=\dfrac{n^2+3n}{(n+1)(n+2)}a1​+a2​+⋯+an​=(n+1)(n+2)n2+3n​. If 28∑k=1101ak=p1p2p3⋯pm28\sum_{k=1}^{10}\dfrac{1}{a_k}=p_1 p_2 p_3\cdots p_m28∑k=110​ak​1​=p1​p2​p3​⋯pm​, where p1,p2,…,pmp_1,p_2,\ldots,p_mp1​,p2​,…,pm​ are the first m prime numbers, then m is equal to
  1. (A)7
  2. (B)6
  3. (C)5
  4. (D)8

Correct answer: (B)

Step-by-step solution →
Q64·MathematicsSingle correct
Let the lines l1:x+53=y+41=z−α−2l_1:\dfrac{x+5}{3}=\dfrac{y+4}{1}=\dfrac{z-\alpha}{-2}l1​:3x+5​=1y+4​=−2z−α​ and l2:3x+2y+z−2=0=x−3y+2z−13l_2:3x+2y+z-2=0=x-3y+2z-13l2​:3x+2y+z−2=0=x−3y+2z−13 be coplanar. If the point P(a,b,c)(a,b,c)(a,b,c) on l1l_1l1​ is nearest to the point Q(−4,−3,2)(-4,-3,2)(−4,−3,2), then ∣a∣+∣b∣+∣c∣|a|+|b|+|c|∣a∣+∣b∣+∣c∣ is equal to
  1. (A)12
  2. (B)14
  3. (C)10
  4. (D)8

Correct answer: (C)

Step-by-step solution →
Q65·MathematicsSingle correct
Let P(237,67)\left(\dfrac{2\sqrt3}{\sqrt7},\dfrac{6}{\sqrt7}\right)(7​23​​,7​6​), Q, R and S be four points on the ellipse 9x2+4y2=369x^2+4y^2=369x2+4y2=36. Let PQ and RS be mutually perpendicular and pass through the origin. If 1(PQ)2+1(RS)2=pq\dfrac{1}{(PQ)^2}+\dfrac{1}{(RS)^2}=\dfrac{p}{q}(PQ)21​+(RS)21​=qp​, where p and q are coprime, then p+qp+qp+q is equal to
  1. (A)143
  2. (B)157
  3. (C)137
  4. (D)147

Correct answer: (B)

Step-by-step solution →
Q66·MathematicsSingle correct
Let a, b, c be three distinct real numbers, none equal to one. If the vectors ai^+j^+k^a\hat i+\hat j+\hat kai^+j^​+k^, i^+bj^+k^\hat i+b\hat j+\hat ki^+bj^​+k^ and i^+j^+ck^\hat i+\hat j+c\hat ki^+j^​+ck^ are coplanar, then 11−a+11−b+11−c\dfrac{1}{1-a}+\dfrac{1}{1-b}+\dfrac{1}{1-c}1−a1​+1−b1​+1−c1​ is equal to
  1. (A)1
  2. (B)-1
  3. (C)3
  4. (D)-2

Correct answer: (A)

Step-by-step solution →
Q67·MathematicsSingle correct
If the local maximum value of the function f(x)=(3e2sin⁡x)sin⁡2xf(x)=\left(\dfrac{\sqrt{3e}}{2\sin x}\right)^{\sin^2 x}f(x)=(2sinx3e​​)sin2x, x∈(0,π2)x\in\left(0,\dfrac{\pi}{2}\right)x∈(0,2π​), is ke\dfrac{k}{e}ek​, then (ke)8+k8e5+k5\left(\dfrac{k}{e}\right)^8+\dfrac{k^8}{e^5}+k^5(ek​)8+e5k8​+k5 is equal to
  1. (A)e5+e6+e11e^5+e^6+e^{11}e5+e6+e11
  2. (B)e3+e6+e11e^3+e^6+e^{11}e3+e6+e11
  3. (C)e3+e5+e11e^3+e^5+e^{11}e3+e5+e11
  4. (D)e5+e6+e10e^5+e^6+e^{10}e5+e6+e10

Correct answer: (C)

Step-by-step solution →
Q68·MathematicsSingle correct
Let D be the domain of the function f(x)=sin⁡−1(log⁡3x(6+2log⁡3x−5x))f(x)=\sin^{-1}\left(\log_{3x}\left(\dfrac{6+2\log_3 x}{-5x}\right)\right)f(x)=sin−1(log3x​(−5x6+2log3​x​)). If the range of the function g:D→Rg:D\to\mathbb{R}g:D→R defined by g(x)=x−[x]g(x)=x-[x]g(x)=x−[x] ([x][x][x] is the greatest integer function) is (α,β)(\alpha,\beta)(α,β), then α2+5β\alpha^2+\dfrac{5}{\beta}α2+β5​ is equal to
  1. (A)46
  2. (B)135
  3. (C)136
  4. (D)45

Correct answer: (B)

Step-by-step solution →
Q69·MathematicsSingle correct
Let y=y(x)y=y(x)y=y(x), y>0y>0y>0, be a solution curve of the differential equation (1+x2) dy=y(x−y) dx(1+x^2)\,dy=y(x-y)\,dx(1+x2)dy=y(x−y)dx. If y(0)=1y(0)=1y(0)=1 and y(22)=βy(2\sqrt2)=\betay(22​)=β, then
  1. (A)e1/β=e(3+22)e^{1/\beta}=e(3+2\sqrt2)e1/β=e(3+22​)
  2. (B)e1/β=e−2(5+42)e^{1/\beta}=e^{-2}(5+4\sqrt2)e1/β=e−2(5+42​)
  3. (C)e1/β=e−2(3+22)e^{1/\beta}=e^{-2}(3+2\sqrt2)e1/β=e−2(3+22​)
  4. (D)e1/β=e(5+42)e^{1/\beta}=e(5+4\sqrt2)e1/β=e(5+42​)

Correct answer: (A)

Step-by-step solution →
Q70·MathematicsSingle correct
Among the two statements (S1): (p⇒q)∧(q∧(∼q))(p\Rightarrow q)\wedge(q\wedge(\sim q))(p⇒q)∧(q∧(∼q)) is a contradiction and (S2): (p∧q)∨((∼p)∧q)∨(p∧(∼q))∨((∼p)∧(∼q))(p\wedge q)\vee((\sim p)\wedge q)\vee(p\wedge(\sim q))\vee((\sim p)\wedge(\sim q))(p∧q)∨((∼p)∧q)∨(p∧(∼q))∨((∼p)∧(∼q)) is a tautology
  1. (A)only (S2) is true
  2. (B)only (S1) is true
  3. (C)both are false
  4. (D)both are true

Correct answer: (D)

Step-by-step solution →
Q71·MathematicsSingle correct
Let λ∈Z\lambda\in\mathbb{Z}λ∈Z, a⃗=2λi^+j^−k^\vec a=2\lambda\hat i+\hat j-\hat ka=2λi^+j^​−k^ and b⃗=3i^−j^+2k^\vec b=3\hat i-\hat j+2\hat kb=3i^−j^​+2k^. Let c⃗\vec cc be a vector such that (a⃗+b⃗+c⃗)×c⃗=0⃗(\vec a+\vec b+\vec c)\times\vec c=\vec 0(a+b+c)×c=0, a⃗⋅c⃗=−17\vec a\cdot\vec c=-17a⋅c=−17 and b⃗⋅c⃗=−20\vec b\cdot\vec c=-20b⋅c=−20. Then ∣c⃗×(λi^+j^+k^)∣2|\vec c\times(\lambda\hat i+\hat j+\hat k)|^2∣c×(λi^+j^​+k^)∣2 is equal to
  1. (A)62
  2. (B)46
  3. (C)53
  4. (D)49

Correct answer: (B)

Step-by-step solution →
Q72·MathematicsSingle correct
The sum of the coefficients of the first 50 terms in the binomial expansion of (1−x)100(1-x)^{100}(1−x)100, is equal to
  1. (A)−100C50-{}^{100}C_{50}−100C50​
  2. (B)99C49{}^{99}C_{49}99C49​
  3. (C)−99C49-{}^{99}C_{49}−99C49​
  4. (D)100C50{}^{100}C_{50}100C50​

Correct answer: (C)

Step-by-step solution →
Q73·MathematicsSingle correct
The area of the region enclosed by the curve y=x3y=x^3y=x3 and its tangent at the point (−1,−1)(-1,-1)(−1,−1) is
  1. (A)274\dfrac{27}{4}427​
  2. (B)194\dfrac{19}{4}419​
  3. (C)234\dfrac{23}{4}423​
  4. (D)314\dfrac{31}{4}431​

Correct answer: (A)

Step-by-step solution →
Q74·MathematicsSingle correct
Let A=[115101]A=\begin{bmatrix}1&\frac{1}{51}\\0&1\end{bmatrix}A=[10​511​1​]. If B=[12−1−1]A[−1−211]B=\begin{bmatrix}1&2\\-1&-1\end{bmatrix}A\begin{bmatrix}-1&-2\\1&1\end{bmatrix}B=[1−1​2−1​]A[−11​−21​], then the sum of all the elements of the matrix ∑n=150Bn\sum_{n=1}^{50}B^n∑n=150​Bn is equal to
  1. (A)100
  2. (B)50
  3. (C)75
  4. (D)125

Correct answer: (A)

Step-by-step solution →
Q75·MathematicsSingle correct
Let the plane P: 4x−y+z=104x-y+z=104x−y+z=10 be rotated by an angle π2\dfrac{\pi}{2}2π​ about its line of intersection with the plane x+y−z=4x+y-z=4x+y−z=4. If α\alphaα is the distance of the point (2,3,−4)(2,3,-4)(2,3,−4) from the new position of the plane P, then 35α35\alpha35α is equal to
  1. (A)90
  2. (B)85
  3. (C)126
  4. (D)170

Correct answer: (C)

Step-by-step solution →
Q76·MathematicsSingle correct
If 1n+1 nCn+1n nCn−1+⋯+12 nC1+nC0=102310\dfrac{1}{n+1}\,{}^nC_n+\dfrac{1}{n}\,{}^nC_{n-1}+\cdots+\dfrac{1}{2}\,{}^nC_1+{}^nC_0=\dfrac{1023}{10}n+11​nCn​+n1​nCn−1​+⋯+21​nC1​+nC0​=101023​ then n is equal to
  1. (A)6
  2. (B)9
  3. (C)8
  4. (D)7

Correct answer: (B)

Step-by-step solution →
Q77·MathematicsSingle correct
Let C be the circle in the complex plane with centre z0=12(1+3i)z_0=\dfrac12(1+3i)z0​=21​(1+3i) and radius r=1r=1r=1. Let z1=1+iz_1=1+iz1​=1+i and the complex number z2z_2z2​ be outside the circle C such that ∣z1−z0∣ ∣z2−z0∣=1|z_1-z_0|\,|z_2-z_0|=1∣z1​−z0​∣∣z2​−z0​∣=1. If z0z_0z0​, z1z_1z1​ and z2z_2z2​ are collinear, then the smaller value of ∣z2∣2|z_2|^2∣z2​∣2 is equal to
  1. (A)132\dfrac{13}{2}213​
  2. (B)52\dfrac5225​
  3. (C)32\dfrac3223​
  4. (D)72\dfrac7227​

Correct answer: (B)

Step-by-step solution →
Q78·MathematicsSingle correct
If the point (α,733)\left(\alpha,\dfrac{7\sqrt3}{3}\right)(α,373​​) lies on the curve traced by the mid-points of the line segments of the lines xcos⁡θ+ysin⁡θ=7x\cos\theta+y\sin\theta=7xcosθ+ysinθ=7, θ∈(0,π2)\theta\in\left(0,\dfrac{\pi}{2}\right)θ∈(0,2π​) between the co-ordinate axes, then α\alphaα is equal to
  1. (A)7
  2. (B)-7
  3. (C)−73-7\sqrt3−73​
  4. (D)737\sqrt373​

Correct answer: (A)

Step-by-step solution →
Q79·MathematicsSingle correct
Two dice A and B are rolled. Let the numbers obtained on A and B be α\alphaα and β\betaβ respectively. If the variance of α−β\alpha-\betaα−β is pq\dfrac{p}{q}qp​, where p and q are co-prime, then the sum of the positive divisors of p is equal to
  1. (A)36
  2. (B)48
  3. (C)31
  4. (D)72

Correct answer: (B)

Step-by-step solution →
Q80·MathematicsSingle correct
In a triangle ABC, if cos⁡A+2cos⁡B+cos⁡C=2\cos A+2\cos B+\cos C=2cosA+2cosB+cosC=2 and the lengths of the sides opposite to the angles A and C are 3 and 7 respectively, then cos⁡A−cos⁡C\cos A-\cos CcosA−cosC is equal to
  1. (A)37\dfrac3773​
  2. (B)97\dfrac9779​
  3. (C)107\dfrac{10}{7}710​
  4. (D)57\dfrac5775​

Correct answer: (C)

Step-by-step solution →
Q81·MathematicsNumerical
A fair die with faces marked 111 to nnn (n>1n>1n>1) is tossed repeatedly until a number less than n appears. If the mean of the number of tosses required is n9\dfrac{n}{9}9n​, then n is equal to

Correct answer: 10

Step-by-step solution →
Q82·MathematicsNumerical
Let the digits a, b, c be in A.P. Nine-digit numbers are to be formed using each of these three digits thrice such that three consecutive digits are in A.P. at least once. How many such numbers can be formed?

Correct answer: 1260

Step-by-step solution →
Q83·Mathematics·Limits and ContinuityNumerical
Let [x][x][x] be the greatest integer ≤x\le x≤x. Then the number of points in the interval (−2,1)(-2,1)(−2,1), where the function f(x)=∣[x]∣+x−[x]f(x)=|[x]|+\sqrt{x-[x]}f(x)=∣[x]∣+x−[x]​ is discontinuous is _________.

Correct answer: 2

Step-by-step solution →
Q84·MathematicsNumerical
Let the plane x+3y−2z+6=0x+3y-2z+6=0x+3y−2z+6=0 meet the co-ordinate axes at the points A, B, C. If the orthocentre of the triangle ABC is (α,β,67)\left(\alpha,\beta,\dfrac67\right)(α,β,76​), then 98(α+β)298(\alpha+\beta)^298(α+β)2 is equal to _________.

Correct answer: 288

Step-by-step solution →
Q85·MathematicsNumerical
Let I=∫x+7x dxI=\int\sqrt{\dfrac{x+7}{x}}\,dxI=∫xx+7​​dx and I(1)=α+7log⁡e(1+22)I(1)=\alpha+7\log_e(1+2\sqrt2)I(1)=α+7loge​(1+22​), then α4\alpha^4α4 is equal to _________.

Correct answer: 64

Step-by-step solution →
Q86·MathematicsNumerical
Let Dk=∣12k2k−1nn2+n+2n2nn2+nn2+n+2∣D_k=\begin{vmatrix}1&2k&2k-1\\n&n^2+n+2&n^2\\n&n^2+n&n^2+n+2\end{vmatrix}Dk​=​1nn​2kn2+n+2n2+n​2k−1n2n2+n+2​​. If ∑k=1nDk=96\sum_{k=1}^{n}D_k=96∑k=1n​Dk​=96, then n is equal to

Correct answer: 6

Step-by-step solution →
Q87·MathematicsNumerical
Let the positive numbers a1,a2,a3,a4a_1,a_2,a_3,a_4a1​,a2​,a3​,a4​ and a5a_5a5​ be in a G.P. Let their mean and variance be 3110\dfrac{31}{10}1031​ and mn\dfrac{m}{n}nm​ respectively, where m and n are co-prime. If the mean of their reciprocals is 3140\dfrac{31}{40}4031​ and a3+a4+a5=14a_3+a_4+a_5=14a3​+a4​+a5​=14, then m+nm+nm+n is equal to _________.

Correct answer: 211

Step-by-step solution →
Q88·MathematicsNumerical
The number of relations, on the set {1,2,3}\{1,2,3\}{1,2,3} containing (1,2)(1,2)(1,2) and (2,3)(2,3)(2,3), which are reflexive and transitive but not symmetric, is _________.

Correct answer: 4

Step-by-step solution →
Q89·MathematicsNumerical
If ∫−0.150.15∣100x2−1∣ dx=k3000\int_{-0.15}^{0.15}\left|100x^2-1\right|\,dx=\dfrac{k}{3000}∫−0.150.15​​100x2−1​dx=3000k​, then k is equal to _________.

Correct answer: 575

Step-by-step solution →
Q90·MathematicsNumerical
Two circles in the first quadrant of radii r1r_1r1​ and r2r_2r2​ touch the coordinate axes. Each of them cuts off an intercept of 2 units with the line x+y=2x+y=2x+y=2. Then r12+r22−r1r2r_1^2+r_2^2-r_1 r_2r12​+r22​−r1​r2​ is equal to _________.

Correct answer: 7

Step-by-step solution →

Chapters tested in this paper

Open any chapter to practise every past-year question on that topic across all papers, and see how often it has actually appeared.

  • Three Dimensional Geometry 176/186
  • Matrices and Determinants 180/186
  • Coordination Compounds 176/186
  • Sets, Relations and Functions 165/186
  • Current Electricity 160/186
  • Sequence and Series 164/186
  • p-Block Elements 164/186
  • Definite Integration 168/186
  • Rotational Motion 172/186
  • Redox Reactions and Electrochemistry 177/186
  • Geometrical Optics 172/186
  • Kinematics 156/186
  • Vector Algebra 173/186
  • Differential Equations 167/186
  • Probability 176/186
  • Permutations and Combinations 162/186
  • Binomial Theorem and Its Simple Applications 158/186
  • Electromagnetic Waves 144/186
  • Chemical Bonding and Molecular Structure 151/186
  • Application of Derivatives 139/186
  • Limits and Continuity 149/186
  • d- and f-Block Elements 126/186
  • Thermodynamics 154/186
  • Aldehydes and Ketones 135/186
  • Equilibrium 163/186
  • Solutions 158/186
  • Laws of Motion 130/186
  • Units and Measurements 149/186
  • Hydrocarbons 126/186
  • Complex Numbers 165/186
  • Trigonometric Functions 144/186
  • Biomolecules 162/186
  • Chemical Kinetics 169/186
  • Gravitation 152/186
  • Atomic Structure 161/186
  • Electronic Devices 145/186
  • Circles 142/186
  • Dual Nature of Matter and Radiation 155/186
  • Amines 133/186
  • Quadratic Equations 148/186
  • Work, Energy and Power 132/186
  • Some Basic Concepts in Chemistry 129/186
  • Electromagnetic Induction 120/186
  • Area Under Curves 139/186
  • Kinetic Theory of Gases 135/186
  • Alcohols and Ethers 106/186
  • Purification and Characterisation of Organic Compounds 116/186
  • Oscillations 117/186
  • Alternating Currents 108/186
  • Nuclei 116/186
  • Straight Lines 114/186
  • Waves 109/186
  • Atoms 112/186
  • Statistics 118/186
  • Ellipse 103/186
  • Isolation of Metals 106/186
  • s-Block Elements 88/186
  • Surface Chemistry 98/186
  • Environmental Chemistry 83/186
  • Hydrogen 81/186
  • Electric Potential 63/186
  • Indefinite Integration 66/186
  • Polymers 64/186
  • Carboxylic Acids and Derivatives 54/186
  • States of Matter: Gases and Liquids 52/186
  • Magnetism and Matter 50/186
  • Reaction Mechanism 29/186
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