Jarvis OS
PYQ papersPricingSign inGet started
  1. Home
  2. /JEE Main PYQs
  3. /2023
  4. /15 Apr Shift 1

JEE Main 15 April 2023 Shift 1 Question Paper with Answers

15 April 2023 · April session · 90 questions

The complete JEE Main 15 April 2023 Shift 1 paper — all 90 questions with the correct answer for each, tagged to the chapter it tests. Free to read, no account needed.

Physics
30
Chemistry
30
Mathematics
30

Physics — JEE Main 15 April 2023 Shift 1

Q1·PhysicsSingle correct
The electric field due to a short electric dipole at a large distance (r)(r)(r) from center of dipole on the equatorial plane varies with distance as :
  1. (A)rrr
  2. (B)1r\frac{1}{r}r1​
  3. (C)1r3\frac{1}{r^{3}}r31​
  4. (D)1r2\frac{1}{r^{2}}r21​

Correct answer: (C)

Step-by-step solution →
Q2·PhysicsSingle correct
In a linear simple harmonic motion (SHM) (A) Restoring force is directly proportional to the displacement. (B) The acceleration and displacement are opposite in direction. (C) The velocity is maximum at mean position. (D) The acceleration is minimum at extreme points. Choose the correct answer from the options given below :
  1. (A)(A), (B) and (C) only
  2. (B)(C) and (D) only
  3. (C)(A), (B) and (D) only
  4. (D)(A), (C) and (D) only

Correct answer: (A)

Step-by-step solution →
Q3·PhysicsSingle correct
Two identical particles each of mass 'm' go round a circle of radius aaa under the action of their mutual gravitational attraction. The angular speed of each particle will be :
  1. (A)Gm2a3\sqrt{\frac{Gm}{2a^{3}}}2a3Gm​​
  2. (B)Gm8a3\sqrt{\frac{Gm}{8a^{3}}}8a3Gm​​
  3. (C)Gm4a3\sqrt{\frac{Gm}{4a^{3}}}4a3Gm​​
  4. (D)Gma3\sqrt{\frac{Gm}{a^{3}}}a3Gm​​

Correct answer: (C)

Step-by-step solution →
Q4·PhysicsSingle correct
The height of transmitting antenna is 180 m and the height of the receiving antenna is 245 m. The maximum distance between them for satisfactory communication in line of sight will be : (given R=6400R = 6400R=6400 km)
  1. (A)48 km
  2. (B)56 km
  3. (C)96 km
  4. (D)104 km

Correct answer: (D)

Step-by-step solution →
Q5·PhysicsSingle correct
The half-life of a radioactive nucleus is 5 years, The fraction of the original sample that would decay in 15 years is :
  1. (A)18\frac{1}{8}81​
  2. (B)14\frac{1}{4}41​
  3. (C)78\frac{7}{8}87​
  4. (D)34\frac{3}{4}43​

Correct answer: (C)

Step-by-step solution →
Q6·PhysicsSingle correct
The de Broglie wavelength of an electron having kinetic energy EEE is λ\lambdaλ. If the kinetic energy of electron becomes E4\frac{E}{4}4E​, then its de-Broglie wavelength will be :
  1. (A)λ2\frac{\lambda}{\sqrt{2}}2​λ​
  2. (B)λ2\frac{\lambda}{2}2λ​
  3. (C)2λ2\lambda2λ
  4. (D)2λ\sqrt{2}\lambda2​λ

Correct answer: (C)

Step-by-step solution →
Q7·Physics·Magnetic Field of CurrentSingle correct
For designing a voltmeter of range 50 V and an ammeter of range 10 mA using a galvanometer which has a coil of resistance 54 Ω\OmegaΩ showing a full scale deflection for 1 mA as in figure. (A) for voltmeter R≈50R \approx 50R≈50 kΩ\OmegaΩ (B) for ammeter r≈0.2r \approx 0.2r≈0.2 Ω\OmegaΩ (C) for ammeter r≈6r \approx 6r≈6 Ω\OmegaΩ (D) for voltmeter R≈5R \approx 5R≈5 kΩ\OmegaΩ (E) for voltmeter R≈500R \approx 500R≈500 Ω\OmegaΩ Choose the correct answer from the options given below :
  1. (A)(C) and (E)
  2. (B)(C) and (D)
  3. (C)(A) and (C)
  4. (D)(A) and (B)

Correct answer: (C)

Step-by-step solution →
Q8·PhysicsSingle correct
A flask contains Hydrogen and Argon in the ratio 2:1 by mass. The temperature of the mixture is 30∘^{\circ}∘C. The ratio of average kinetic energy per molecule of the two gases (K argon/K hydrogen) is: (Given: Atomic Weight of Ar = 39.9)
  1. (A)1
  2. (B)2
  3. (C)39.92\frac{39.9}{2}239.9​
  4. (D)39.9

Correct answer: (A)

Step-by-step solution →
Q9·PhysicsSingle correct
Given below are two statements: Statement I : The equivalent resistance of resistors in a series combination is smaller than least resistance used in the combination. Statement II : The resistivity of the material is independent of temperature. In the light of the above statements, choose the correct answer from the options given below :
  1. (A)Statement I is false but Statement II is true
  2. (B)Both Statement I and Statement II are false
  3. (C)Statement I is true but Statement II is false
  4. (D)Both Statement I and Statement II are true

Correct answer: (B)

Step-by-step solution →
Q10·PhysicsSingle correct
A body is released from a height equal to the radius (R)(R)(R) of the earth. The velocity of the body when it strikes the surface of the earth will be : (Given ggg = acceleration due to gravity on the earth.)
  1. (A)gR\sqrt{gR}gR​
  2. (B)4gR\sqrt{4gR}4gR​
  3. (C)2gR\sqrt{2gR}2gR​
  4. (D)gR2\sqrt{\frac{gR}{2}}2gR​​

Correct answer: (A)

Step-by-step solution →
Q11·PhysicsSingle correct
A 12 V battery connected to a coil of resistance 6 Ω\OmegaΩ through a switch, drives a constant current in the circuit. The switch is opened in 1 ms. The emf induced across the coil is 20 V. The inductance of the coil is :
  1. (A)5 mH
  2. (B)12 mH
  3. (C)8 mH
  4. (D)10 mH

Correct answer: (D)

Step-by-step solution →
Q12·PhysicsSingle correct
A wire of length 'L' and radius 'r' is clamped rigidly at one end. When the other end of the wire is pulled by a force f, its length increases by 'ℓ\ellℓ'. Another wire of same material of length '2L' and radius '2r' is pulled by a force '2f'. Then the increase in its length will be :
  1. (A)2ℓ2\ell2ℓ
  2. (B)ℓ\ellℓ
  3. (C)4ℓ4\ell4ℓ
  4. (D)ℓ/2\ell/2ℓ/2

Correct answer: (B)

Step-by-step solution →
Q13·PhysicsSingle correct
The position of a particle related to time is given by x=(5t2−4t+5)x = (5t^{2} - 4t + 5)x=(5t2−4t+5) m. The magnitude of velocity of the particle at t=2t = 2t=2 s will be :
  1. (A)10 ms−1^{-1}−1
  2. (B)14 ms−1^{-1}−1
  3. (C)16 ms−1^{-1}−1
  4. (D)06 ms−1^{-1}−1

Correct answer: (C)

Step-by-step solution →
Q14·PhysicsSingle correct
The position vector of a particle related to time t is given by r⃗=(10ti^+15t2j^+7k^)\vec{r} = \left(10t\hat{i} + 15t^{2}\hat{j} + 7\hat{k}\right)r=(10ti^+15t2j^​+7k^) m. The direction of net force experienced by the particle is :
  1. (A)Positive y-axis
  2. (B)Positive x-axis
  3. (C)Positive z-axis
  4. (D)In x-y plane

Correct answer: (A)

Step-by-step solution →
Q15·PhysicsSingle correct
Match List I (Electromagnetic waves) with List II (corresponding wavelength range). List I: (A) Microwave, (B) Ultraviolet, (C) X-Ray, (D) Infra-red. List II: (I) 400 nm to 1 nm, (II) 1 nm to 10−310^{-3}10−3 nm, (III) 1 mm to 700 nm, (IV) 0.1 m to 1mm. Choose the correct answer from the options given below :
List-IList-II
A.MicrowaveI.400 nm to 1 nm
B.UltravioletII.1 nm to 10−310^{-3}10−3 nm
C.X-RayIV.0.1 m to 1mm
D.Infra-redIII.1 mm to 700 nm
  1. (A)(A)-(I), (B)-(IV), (C)-(II), (D)-(III)
  2. (B)(A)-(IV), (B)-(I), (C)-(II), (D)-(III)
  3. (C)(A)-(IV), (B)-(II), (C)-(I), (D)-(III)
  4. (D)(A)-(IV), (B)-(I), (C)-(III), (D)-(II)

Correct answer: (B)

Step-by-step solution →
Q16·PhysicsSingle correct
A vector in x-y plane makes an angle of 30∘30^\circ30∘ with y-axis. The magnitude of y-component of vector is 232\sqrt{3}23​. The magnitude of x-component of the vector will be :
  1. (A)13\frac{1}{\sqrt{3}}3​1​
  2. (B)666
  3. (C)3\sqrt{3}3​
  4. (D)222

Correct answer: (D)

Step-by-step solution →
Q17·PhysicsSingle correct
The speed of a wave produced in water is given by v=λagbρcv = \lambda^a g^b \rho^cv=λagbρc. Where λ\lambdaλ, ggg and ρ\rhoρ are wavelength of wave, acceleration due to gravity and density of water respectively. The values of a, b and c respectively, are :
  1. (A)12,12,0\frac{1}{2}, \frac{1}{2}, 021​,21​,0
  2. (B)1,1,01, 1, 01,1,0
  3. (C)1,−1,01, -1, 01,−1,0
  4. (D)12,0,12\frac{1}{2}, 0, \frac{1}{2}21​,0,21​

Correct answer: (A)

Step-by-step solution →
Q18·PhysicsSingle correct
A thermodynamic system is taken through cyclic process. The total work done in the process is :
  1. (A)100100100 J
  2. (B)300300300 J
  3. (C)Zero
  4. (D)200200200 J

Correct answer: (B)

Step-by-step solution →
Q19·PhysicsSingle correct
A single slit of width aaa is illuminated by a monochromatic light of wavelength 600600600 nm. The value of 'a' for which first minimum appears at θ=30∘\theta = 30^\circθ=30∘ on the screen will be :
  1. (A)0.6 μ0.6\ \mu0.6 μm
  2. (B)1.2 μ1.2\ \mu1.2 μm
  3. (C)1.8 μ1.8\ \mu1.8 μm
  4. (D)3 μ3\ \mu3 μm

Correct answer: (B)

Step-by-step solution →
Q20·PhysicsSingle correct
In the given circuit, the current (I) through the battery will be :
  1. (A)1.51.51.5 A
  2. (B)111 A
  3. (C)2.52.52.5 A
  4. (D)222 A

Correct answer: (A)

Step-by-step solution →
Q21·PhysicsNumerical
A 202020 cm long metallic rod is rotated with 210210210 rpm about an axis normal to the rod passing through its one end. The other end of the rod is in contact with a circular metallic ring. A constant and uniform magnetic field 0.20.20.2 T parallel to the axis exists everywhere. The emf developed between the centre and the ring is __________ mV. Take π=227\pi = \frac{22}{7}π=722​.

Correct answer: 88

Step-by-step solution →
Q22·PhysicsNumerical
A network of four resistances is connected to 999 V battery, as shown in figure. The magnitude of voltage difference between the points A and B is __________ V.

Correct answer: 3

Step-by-step solution →
Q23·PhysicsNumerical
The fundamental frequency of vibration of a string stretched between two rigid support is 505050 Hz. The mass of the string is 181818 g and its linear mass density is 202020 g/m. The speed of the transverse waves so produced in the string is __________ ms−1^{-1}−1.

Correct answer: 90

Step-by-step solution →
Q24·PhysicsNumerical
As per given figure A, B and C are the first, second and third excited energy level of hydrogen atom respectively. If the ratio of the two wavelengths (i.e. λ1λ2\frac{\lambda_1}{\lambda_2}λ2​λ1​​) is 74n\frac{7}{4n}4n7​, then the value of n will be __________.

Correct answer: 5

Step-by-step solution →
Q25·PhysicsNumerical
A solid sphere and a solid cylinder of same mass and radius are rolling on a horizontal surface without slipping. The ratio of their radius of gyrations respectively (ksph:kcylk_{sph} : k_{cyl}ksph​:kcyl​) is 2:x2 : \sqrt{x}2:x​, then value of x is __________.

Correct answer: 5

Step-by-step solution →
Q26·PhysicsNumerical
The refractive index of a transparent liquid filled in an equilateral hollow prism is 2\sqrt{2}2​. The angle of minimum deviation for the liquid will be __________ ∘^\circ∘.

Correct answer: 30

Step-by-step solution →
Q27·PhysicsNumerical
An electron in a hydrogen atom revolves around its nucleus with a speed of 6.76×1066.76 \times 10^66.76×106 ms−1^{-1}−1 in an orbit of radius 0.520.520.52 A∘^\circ∘. The magnetic field produced at the nucleus of the hydrogen atom is __________ T.

Correct answer: 40

Step-by-step solution →
Q28·PhysicsNumerical
There is an air bubble of radius 1.01.01.0 mm in a liquid of surface tension 0.0750.0750.075 Nm−1^{-1}−1 and density 100010001000 kg m−3^{-3}−3 at a depth of 101010 cm below the free surface. The amount by which the pressure inside the bubble is greater than the atmospheric pressure is __________ Pa (g=10g = 10g=10 ms−2^{-2}−2).

Correct answer: 1150

Step-by-step solution →
Q29·PhysicsNumerical
A block of mass 101010 kg is moving along x-axis under the action of force F=5xF = 5xF=5x N. The work done by the force in moving the block from x=2x = 2x=2m to 444m will be __________ J.

Correct answer: 30

Step-by-step solution →
Q30·PhysicsNumerical
In the given figure the total charge stored in the combination of capacitors is 100 μ100\ \mu100 μC. The value of 'x' is __________.

Correct answer: 5

Step-by-step solution →

Chemistry — JEE Main 15 April 2023 Shift 1

Q31·ChemistrySingle correct
Match List I with List II:
List I-(Monomer)List II-(Polymer)
A.TetrafluoroetheneI.Orlon
B.AcrylonitrileII.Natural rubber
C.CaprolactamIII.Teflon
D.IsopreneIV.Nylon-6
  1. (A)(A)-(III), (B)-(I), (C)-(IV), (D)-(II)
  2. (B)(A)-(III), (B)-(IV), (C)-(II), (D)-(I)
  3. (C)(A)-(IV), (B)-(I), (C)-(II), (D)-(III)
  4. (D)(A)-(II), (B)-(III), (C)-(IV), (D)-(I)

Correct answer: (A)

Step-by-step solution →
Q32·ChemistrySingle correct
The product formed in the following multistep reaction is: CH3−CH=CH2CH_3-CH=CH_2CH3​−CH=CH2​ with i) B2H6B_2H_6B2​H6​ ii) H2O2,NaOHH_2O_2, NaOHH2​O2​,NaOH iii) PCC iv) CH3MgBrCH_3MgBrCH3​MgBr
  1. (A)CH3−CH2−CH(OH)−CH3CH_3-CH_2-CH(OH)-CH_3CH3​−CH2​−CH(OH)−CH3​
  2. (B)CH3−CH2−CH2−CH2−OHCH_3-CH_2-CH_2-CH_2-OHCH3​−CH2​−CH2​−CH2​−OH
  3. (C)CH3−CH2−C(=O)−OCH3CH_3-CH_2-C(=O)-OCH_3CH3​−CH2​−C(=O)−OCH3​
  4. (D)CH3−C(OH)(CH3)−CH3CH_3-C(OH)(CH_3)-CH_3CH3​−C(OH)(CH3​)−CH3​

Correct answer: (A)

Step-by-step solution →
Q33·ChemistrySingle correct
The possibility of photochemical smog formation will be minimum at
  1. (A)Kolkata in October
  2. (B)Mumbai in May
  3. (C)New-Delhi in August (Summer)
  4. (D)Srinagar, Jammu and Kashmir in January

Correct answer: (D)

Step-by-step solution →
Q34·ChemistrySingle correct
Which one of the following is not an example of calcination?
  1. (A)Fe2O3⋅xH2O→ΔFe2O3+xH2OFe_2O_3 \cdot xH_2O \xrightarrow{\Delta} Fe_2O_3 + xH_2OFe2​O3​⋅xH2​OΔ​Fe2​O3​+xH2​O
  2. (B)CaCO3→ΔCaO+CO2CaCO_3 \xrightarrow{\Delta} CaO + CO_2CaCO3​Δ​CaO+CO2​
  3. (C)CaCO3⋅MgCO3→ΔCaO+MgO+2CO2CaCO_3 \cdot MgCO_3 \xrightarrow{\Delta} CaO + MgO + 2CO_2CaCO3​⋅MgCO3​Δ​CaO+MgO+2CO2​
  4. (D)2PbS+3O2→Δ2PbO+2SO22PbS + 3O_2 \xrightarrow{\Delta} 2PbO + 2SO_22PbS+3O2​Δ​2PbO+2SO2​

Correct answer: (D)

Step-by-step solution →
Q35·ChemistrySingle correct
Consider the following statements: (A) NF3NF_3NF3​ molecule has a trigonal planar structure. (B) Bond length of N2N_2N2​ is shorter than O2O_2O2​. (C) Isoelectronic molecules or ions have identical bond order. (D) Dipole moment of H2SH_2SH2​S is higher than that of water molecule. Choose the correct answer from the option below:
  1. (A)(A) and (D) are correct
  2. (B)(C) and (D) are correct
  3. (C)(A) and (B) are correct
  4. (D)(B) and (C) are correct

Correct answer: (D)

Step-by-step solution →
Q36·ChemistrySingle correct
Consider the following sequence of reactions: aniline (C6H5NH2C_6H_5NH_2C6​H5​NH2​) with NaNO2NaNO_2NaNO2​ at 0−5 ∘C0-5\,^{\circ}C0−5∘C gives 'A', then 'A' with N,N-Dimethylaniline gives 'B'. The product 'B' is
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (B)

Step-by-step solution →
Q37·ChemistrySingle correct
The number of P-O-P bonds in H4P2O7H_4P_2O_7H4​P2​O7​, (HPO3)3(HPO_3)_3(HPO3​)3​ and P4O10P_4O_{10}P4​O10​ are respectively.
  1. (A)1, 3, 6
  2. (B)0, 3, 6
  3. (C)0, 3, 4
  4. (D)1, 2, 4

Correct answer: (A)

Step-by-step solution →
Q38·ChemistrySingle correct
Given below are two statements: Statement I: According to Bohr's model of hydrogen atom, the angular momentum of an electron in a given stationary state is quantised. Statement II: The concept of electron in Bohr's orbit, violates the Heisenberg uncertainty principle. In the light of the above statements, choose the most appropriate answer from the options given below:
  1. (A)Both Statement I and Statement II are correct.
  2. (B)Statement I is correct but Statement II is incorrect.
  3. (C)Statement I is incorrect but Statement II is correct
  4. (D)Both Statement I and Statement II are incorrect.

Correct answer: (A)

Step-by-step solution →
Q39·Chemistry·Electronic Effects and StabilitySingle correct
Decreasing order of reactivity towards electrophilic substitution for the following compounds is: (a) toluene, (b) benzene, (c) 1-(trifluoromethyl)... (a benzene ring with CF3), (d) anisole (benzene with OCH3), (e) N,N-dimethylaniline (benzene with NMe2).
  1. (A)c > b > a > d > e
  2. (B)e > d > a > b > c
  3. (C)a > d > e > b > c
  4. (D)d > a > e > c > b

Correct answer: (B)

Step-by-step solution →
Q40·ChemistrySingle correct
Which of the following statement(s) is/are correct? (A) The pH of 1×10−81 \times 10^{-8}1×10−8 M HCl solution is 8. (B) The conjugate base H2PO4−H_2PO_4^-H2​PO4−​ is HPO42−HPO_4^{2-}HPO42−​. (C) KwK_wKw​ increases with increase in temperature. (D) When a solution of weak monoprotic acid is titrated against a strong base at half neutralisation point, pH=12pKapH = \frac{1}{2}pK_apH=21​pKa​. Choose the correct answer from the option given below.
  1. (A)(B), (C), (D)
  2. (B)(A), (D)
  3. (C)(A), (B), (C)
  4. (D)(B), (C)

Correct answer: (D)

Step-by-step solution →
Q41·ChemistrySingle correct
Given below are two statements: One is labelled as Assertion A and the other is labelled as Reason R: Assertion (A): BeCl2BeCl_2BeCl2​ and MgCl2MgCl_2MgCl2​ produce characteristic flame. Reason (R): The excitation energy is high in BeCl2BeCl_2BeCl2​ and MgCl2MgCl_2MgCl2​. In the light of the above statements, choose the correct answer from the option given below:
  1. (A)Both (A) and (R) are true but (R) is NOT the correct explanation of (A)
  2. (B)(A) is false but (R) is true
  3. (C)Both (A) and (R) are true and (R) is the correct explanation of (A)
  4. (D)(A) is true but (R) is false.

Correct answer: (B)

Step-by-step solution →
Q42·ChemistrySingle correct
In the above conversion the correct sequence of reagents to be added is (the conversion shown is 4-nitrotoluene to 2-bromo-4-chlorobenzoic acid).
  1. (A)(i) Fe/H+Fe/H^+Fe/H+, (ii) HONO, (iii) CuCl, (iv) KMnO4KMnO_4KMnO4​, (v) Br2Br_2Br2​
  2. (B)(i) KMnO4KMnO_4KMnO4​, (ii) Br2/FeBr_2/FeBr2​/Fe, (iii) Fe/H+Fe/H^+Fe/H+, (iv) Cl2Cl_2Cl2​
  3. (C)(i) Br2/FeBr_2/FeBr2​/Fe, (ii) Fe/H+Fe/H^+Fe/H+, (iii) HONO, (iv) CuCl, (v) KMnO4KMnO_4KMnO4​
  4. (D)Br2/FeBr_2/FeBr2​/Fe, (ii) Fe/H+Fe/H^+Fe/H+, (iii) KMnO4KMnO_4KMnO4​, (iv) Cl2Cl_2Cl2​

Correct answer: (C)

Step-by-step solution →
Q43·ChemistrySingle correct
For the drawn 1,2,3-indantrione (ninhydrin-type triketone of indane) reacting with H2OH_2OH2​O to give major product 'A', the major product 'A' formed in the above reaction is
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (D)

Step-by-step solution →
Q44·ChemistrySingle correct
Which is not true for arginine?
  1. (A)It is a crystalline solid.
  2. (B)It is associated with more than one pKapK_apKa​ values.
  3. (C)It has a fairly high melting point.
  4. (D)It has high solubility in benzene.

Correct answer: (D)

Step-by-step solution →
Q45·ChemistrySingle correct
During water-gas shift reaction
  1. (A)carbon monoxide is oxidized to carbon dioxide.
  2. (B)carbon is oxidized to carbon monoxide.
  3. (C)carbon dioxide is reduced to carbon monoxide.
  4. (D)water is evaporated in presence of catalyst.

Correct answer: (A)

Step-by-step solution →
Q46·ChemistrySingle correct
For a good quality cement, the ratio of silica to alumina is found to be
  1. (A)3
  2. (B)4.5
  3. (C)2
  4. (D)1.5

Correct answer: (A)

Step-by-step solution →
Q47·ChemistrySingle correct
Which the following statement is correct for paper chromatography?
  1. (A)Water present in the mobile phase gets absorbed by the paper which then forms the stationary phase.
  2. (B)Water present in the pores of the paper forms the stationary phase.
  3. (C)Paper sheet forms the stationary phase.
  4. (D)Paper and water present in its pores together form the stationary phase.

Correct answer: (B)

Step-by-step solution →
Q48·ChemistrySingle correct
The major product formed in the Friedel-Craft acylation of chlorobenzene is.
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (A)

Step-by-step solution →
Q49·ChemistrySingle correct
The complex with highest magnitude of crystal field splitting energy (Δo)(\Delta_o)(Δo​) is
  1. (A)[Cr(OH2)6]3+[Cr(OH_2)_6]^{3+}[Cr(OH2​)6​]3+
  2. (B)[Ti(OH2)6]3+[Ti(OH_2)_6]^{3+}[Ti(OH2​)6​]3+
  3. (C)[Fe(OH2)6]3+[Fe(OH_2)_6]^{3+}[Fe(OH2​)6​]3+
  4. (D)[Mn(OH2)6]3+[Mn(OH_2)_6]^{3+}[Mn(OH2​)6​]3+

Correct answer: (A)

Step-by-step solution →
Q50·ChemistrySingle correct
Which of the following expressions is correct in case of a CsCl unit cell (edge length 'a')?
  1. (A)rCs++rCl−=a2r_{Cs^+} + r_{Cl^-} = \dfrac{a}{\sqrt{2}}rCs+​+rCl−​=2​a​
  2. (B)rCs++rCl−=ar_{Cs^+} + r_{Cl^-} = arCs+​+rCl−​=a
  3. (C)rCs++rCl−=32ar_{Cs^+} + r_{Cl^-} = \dfrac{\sqrt{3}}{2}arCs+​+rCl−​=23​​a
  4. (D)rCs++rCl−=a2r_{Cs^+} + r_{Cl^-} = \dfrac{a}{2}rCs+​+rCl−​=2a​

Correct answer: (C)

Step-by-step solution →
Q51·ChemistryNumerical
The homoleptic and octahedral complex of Co2+Co^{2+}Co2+ and H2OH_2OH2​O has _______ unpaired electron(s) in the t2gt_{2g}t2g​ set of orbitals.

Correct answer: 1

Step-by-step solution →
Q52·ChemistryNumerical
The volume (in mL) of 0.1 M AgNO3AgNO_3AgNO3​ required for complete precipitation of chloride ions present in 20 mL of 0.01 M solution of [Cr(H2O)5Cl]Cl2[Cr(H_2O)_5Cl]Cl_2[Cr(H2​O)5​Cl]Cl2​ as silver chloride is _______

Correct answer: 4

Step-by-step solution →
Q53·ChemistryNumerical
The total change in the oxidation state of manganese involved in the reaction of KMnO4KMnO_4KMnO4​ and potassium iodide in the acidic medium is _______

Correct answer: 5

Step-by-step solution →
Q54·ChemistryNumerical
In Chromyl chloride, the oxidation state of chromium is (+)_______

Correct answer: 6

Step-by-step solution →
Q55·ChemistryNumerical
The total number of isoelectronic species from the given set is _______ O2−,F−,Al,Mg2+,Na+,O+,Mg,Al3+,FO^{2-}, F^-, Al, Mg^{2+}, Na^+, O^+, Mg, Al^{3+}, FO2−,F−,Al,Mg2+,Na+,O+,Mg,Al3+,F

Correct answer: 5

Step-by-step solution →
Q56·ChemistryNumerical
The vapour pressure of 30% (w/v) aqueous solution of glucose is _______ mm Hg at 25 C. [Given : The density of 30% (w/v), aqueous solution of glucose is 1.2 g cm−3cm^{-3}cm−3 and vapour pressure of pure water is 24 mm Hg.] (Molar mass of glucose is 180 g mol−1mol^{-1}mol−1.)

Correct answer: 23

Step-by-step solution →
Q57·ChemistryNumerical
20 mL of 0.5 M NaCl is required to coagulate 200 mL of As2S3As_2S_3As2​S3​ solution in 2 hours. The coagulating value of NaCl is _______

Correct answer: 50

Step-by-step solution →
Q58·ChemistryNumerical
For a reversible reaction A⇌BA \rightleftharpoons BA⇌B, the ΔHforward reaction=20\Delta H_{forward\ reaction} = 20ΔHforward reaction​=20 kJ mol−1mol^{-1}mol−1. The activation energy of the uncatalysed forward reaction is 300 kJ mol−1mol^{-1}mol−1. When the reaction is catalysed keeping the reactant concentration same, the rate of the catalysed forward reaction at 27 C is found to be same as that of the uncatalysed reaction at 327 C. The activation energy of the catalysed backward reaction is _______ kJ mol−1mol^{-1}mol−1.

Correct answer: 130

Step-by-step solution →
Q59·ChemistryNumerical
The number of correct statements from the following is _______ (A) Conductivity always decreases with decrease in concentration for both strong and weak electrolytes. (B) The number of ions per unit volume that carry current in a solution increases on dilution. (C) Molar conductivity increases with decrease in concentration. (D) The variation in molar conductivity is different for strong and weak electrolytes. (E) For weak electrolytes, the change in molar conductivity with dilution is due to decrease in degree of dissociation.

Correct answer: 3

Step-by-step solution →
Q60·ChemistryNumerical
30.4 kJ of heat is required to melt one mole of sodium chloride and the entropy change at the melting point is 28.4 J K−1K^{-1}K−1 mol−1mol^{-1}mol−1 at 1 atm. The melting point of sodium chloride is _______ K (Nearest Integer)

Correct answer: 1070

Step-by-step solution →

Mathematics — JEE Main 15 April 2023 Shift 1

Q61·MathematicsSingle correct
The total number of three-digit numbers, divisible by 3, which can be formed using the digits 1, 3, 5, 8, if repetition of digits is allowed, is:
  1. (A)22
  2. (B)18
  3. (C)21
  4. (D)20

Correct answer: (A)

Step-by-step solution →
Q62·MathematicsSingle correct
Let SSS be the set of all values of λ\lambdaλ, for which the shortest distance between the lines x−λ0=y−34=z+61\frac{x-\lambda}{0}=\frac{y-3}{4}=\frac{z+6}{1}0x−λ​=4y−3​=1z+6​ and x+λ3=y−4=z−60\frac{x+\lambda}{3}=\frac{y}{-4}=\frac{z-6}{0}3x+λ​=−4y​=0z−6​ is 131313. Then 8∣∑λ∈Sλ∣8\left|\sum_{\lambda\in S}\lambda\right|8​∑λ∈S​λ​ is equal to
  1. (A)304
  2. (B)308
  3. (C)306
  4. (D)302

Correct answer: (C)

Step-by-step solution →
Q63·MathematicsSingle correct
The mean and standard deviation of 10 observations are 20 and 8 respectively. Later on, it was observed that one observation was recorded as 50 instead of 40. Then the correct variance is:
  1. (A)14
  2. (B)13
  3. (C)12
  4. (D)11

Correct answer: (B)

Step-by-step solution →
Q64·MathematicsSingle correct
Let ABCD be a quadrilateral. If E and F are the mid points of the diagonals AC and BD respectively and (AB⃗−BC⃗)+(AD⃗−DC⃗)=k FE⃗\left(\vec{AB}-\vec{BC}\right)+\left(\vec{AD}-\vec{DC}\right)=k\,\vec{FE}(AB−BC)+(AD−DC)=kFE, then k is equal to
  1. (A)2
  2. (B)−2-2−2
  3. (C)−4-4−4
  4. (D)4

Correct answer: (C)

Step-by-step solution →
Q65·MathematicsSingle correct
Let x=x(y)x=x(y)x=x(y) be the solution of the differential equation 2(y+2)log⁡e(y+2) dx+(x+4−2log⁡e(y+2)) dy=02(y+2)\log_e(y+2)\,dx+(x+4-2\log_e(y+2))\,dy=02(y+2)loge​(y+2)dx+(x+4−2loge​(y+2))dy=0, y>−1y>-1y>−1 with x(e4−2)=1x(e^4-2)=1x(e4−2)=1. Then x(e9−2)x(e^9-2)x(e9−2) is equal to
  1. (A)49\frac{4}{9}94​
  2. (B)103\frac{10}{3}310​
  3. (C)329\frac{32}{9}932​
  4. (D)3

Correct answer: (C)

Step-by-step solution →
Q66·MathematicsSingle correct
Let [x][x][x] denote the greatest integer function and f(x)=max⁡{1+x+[x], 2+x, x+2[x]}f(x)=\max\{1+x+[x],\,2+x,\,x+2[x]\}f(x)=max{1+x+[x],2+x,x+2[x]}, 0≤x≤20\le x\le 20≤x≤2. Let mmm be the number of points in [0,2][0,2][0,2], where fff is not continuous and nnn be the number of points in (0,2)(0,2)(0,2), where fff is not differentiable. Then (m+n)2+2(m+n)^2+2(m+n)2+2 is equal to:
  1. (A)11
  2. (B)2
  3. (C)6
  4. (D)3

Correct answer: (D)

Step-by-step solution →
Q67·MathematicsSingle correct
The number of real roots of the equation x∣x∣−5∣x+2∣+6=0x|x|-5|x+2|+6=0x∣x∣−5∣x+2∣+6=0, is
  1. (A)5
  2. (B)3
  3. (C)6
  4. (D)4

Correct answer: (B)

Step-by-step solution →
Q68·MathematicsSingle correct
Let (a+bx+cx2)10=∑i=020pixi(a+bx+cx^2)^{10}=\sum_{i=0}^{20}p_i x^i(a+bx+cx2)10=∑i=020​pi​xi, a,b,c∈Na,b,c\in\mathbb{N}a,b,c∈N. If p1=20p_1=20p1​=20 and p2=210p_2=210p2​=210, then 2(a+b+c)2(a+b+c)2(a+b+c) is equal to
  1. (A)8
  2. (B)12
  3. (C)15
  4. (D)6

Correct answer: (B)

Step-by-step solution →
Q69·MathematicsSingle correct
Let the determinant of a square matrix A of order m be m−nm-nm−n, where m and n satisfy 4m+n=224m+n=224m+n=22 and 17m+4n=9317m+4n=9317m+4n=93. If det⁡(n adj(adj(mA)))=3a5b6c\det(n\,\mathrm{adj}(\mathrm{adj}(mA)))=3^a 5^b 6^cdet(nadj(adj(mA)))=3a5b6c, then a+b+ca+b+ca+b+c is equal to:
  1. (A)96
  2. (B)101
  3. (C)109
  4. (D)84

Correct answer: (A)

Step-by-step solution →
Q70·MathematicsSingle correct
Let A1A_1A1​ and A2A_2A2​ be two arithmetic means and G1,G2,G3G_1, G_2, G_3G1​,G2​,G3​ be three geometric means of two distinct positive numbers. The G14+G24+G34+G12G32G_1^4+G_2^4+G_3^4+G_1^2 G_3^2G14​+G24​+G34​+G12​G32​ is equal to
  1. (A)2(A1+A2)G1G32(A_1+A_2)G_1 G_32(A1​+A2​)G1​G3​
  2. (B)(A1+A2)2G1G3(A_1+A_2)^2 G_1 G_3(A1​+A2​)2G1​G3​
  3. (C)(A1+A2)G12G32(A_1+A_2)G_1^2 G_3^2(A1​+A2​)G12​G32​
  4. (D)2(A1+A2)G12G322(A_1+A_2)G_1^2 G_3^22(A1​+A2​)G12​G32​

Correct answer: (B)

Step-by-step solution →
Q71·MathematicsSingle correct
If the set {Re(z−zˉ+zzˉ2−3z+5zˉ):z∈C,Re(z)=3}\left\{\mathrm{Re}\left(\frac{z-\bar{z}+z\bar{z}}{2-3z+5\bar{z}}\right):z\in\mathbb{C},\mathrm{Re}(z)=3\right\}{Re(2−3z+5zˉz−zˉ+zzˉ​):z∈C,Re(z)=3} is equal to the interval (α,β](\alpha,\beta](α,β], then 24(β−α)24(\beta-\alpha)24(β−α) is equal to
  1. (A)36
  2. (B)42
  3. (C)27
  4. (D)30

Correct answer: (D)

Step-by-step solution →
Q72·MathematicsSingle correct
The number of common tangents, to the circles x2+y2−18x−15y+131=0x^2+y^2-18x-15y+131=0x2+y2−18x−15y+131=0 and x2+y2−6x−6y−7=0x^2+y^2-6x-6y-7=0x2+y2−6x−6y−7=0, is :
  1. (A)3
  2. (B)2
  3. (C)1
  4. (D)4

Correct answer: (A)

Step-by-step solution →
Q73·MathematicsSingle correct
Negation of p∧(q∧∼(p∧q))p\wedge(q\wedge\sim(p\wedge q))p∧(q∧∼(p∧q)) is
  1. (A)∼(p∨q)\sim(p\vee q)∼(p∨q)
  2. (B)p∨qp\vee qp∨q
  3. (C)(∼(p∧q))∧q(\sim(p\wedge q))\wedge q(∼(p∧q))∧q
  4. (D)(∼(p∧q))∨p(\sim(p\wedge q))\vee p(∼(p∧q))∨p

Correct answer: (D)

Step-by-step solution →
Q74·MathematicsSingle correct
Let the system of linear equations −x+2y−9z=7-x+2y-9z=7−x+2y−9z=7, −x+3y+7z=9-x+3y+7z=9−x+3y+7z=9, −2x+y+5z=8-2x+y+5z=8−2x+y+5z=8, −3x+y+13z=λ-3x+y+13z=\lambda−3x+y+13z=λ has a unique solution x=α,y=β,z=γx=\alpha, y=\beta, z=\gammax=α,y=β,z=γ. Then the distance of the point (α,β,γ)(\alpha,\beta,\gamma)(α,β,γ) from the plane 2x−2y+z=λ2x-2y+z=\lambda2x−2y+z=λ is
  1. (A)9
  2. (B)11
  3. (C)13
  4. (D)7

Correct answer: (D)

Step-by-step solution →
Q75·MathematicsSingle correct
If (α,β)(\alpha,\beta)(α,β) is the orthocentre of the triangle ABC with vertices A(3,−7)A(3,-7)A(3,−7), B(−1,2)B(-1,2)B(−1,2) and C(4,5)C(4,5)C(4,5), then 9α−6β+609\alpha-6\beta+609α−6β+60 is equal to:
  1. (A)30
  2. (B)25
  3. (C)40
  4. (D)35

Correct answer: (B)

Step-by-step solution →
Q76·MathematicsSingle correct
Let the foot of perpendicular of the point P(3,−2,−9)P(3, -2, -9)P(3,−2,−9) on the plane passing through the points (−1,−2,−3)(-1, -2, -3)(−1,−2,−3), (9,3,4)(9, 3, 4)(9,3,4), (9,−2,1)(9, -2, 1)(9,−2,1) be Q(α,β,γ)Q(\alpha, \beta, \gamma)Q(α,β,γ). Then the distance of QQQ from the origin is:
  1. (A)29\sqrt{29}29​
  2. (B)35\sqrt{35}35​
  3. (C)42\sqrt{42}42​
  4. (D)38\sqrt{38}38​

Correct answer: (C)

Step-by-step solution →
Q77·MathematicsSingle correct
A bag contains 6 white and 4 black balls. A die is rolled once and the number of balls equal to the number obtained on the die are drawn from the bag at random. The probability that all the balls drawn are white is:
  1. (A)14\frac{1}{4}41​
  2. (B)950\frac{9}{50}509​
  3. (C)15\frac{1}{5}51​
  4. (D)1150\frac{11}{50}5011​

Correct answer: (C)

Step-by-step solution →
Q78·MathematicsSingle correct
If ∫011(5+2x−2x2)(1+e(2−4x)) dx=1αlog⁡e(α+1β)\int_0^1 \frac{1}{\left(5 + 2x - 2x^2\right)\left(1 + e^{(2-4x)}\right)}\,dx = \frac{1}{\alpha}\log_e\left(\frac{\alpha + 1}{\beta}\right)∫01​(5+2x−2x2)(1+e(2−4x))1​dx=α1​loge​(βα+1​), α,β>0\alpha, \beta > 0α,β>0, then α4−β4\alpha^4 - \beta^4α4−β4 is equal to:
  1. (A)212121
  2. (B)000
  3. (C)191919
  4. (D)−21-21−21

Correct answer: (A)

Step-by-step solution →
Q79·MathematicsSingle correct
Let SSS be the set of all (λ,μ)(\lambda, \mu)(λ,μ) for which the vectors λi^−j^+k^\lambda\hat{i} - \hat{j} + \hat{k}λi^−j^​+k^, i^+2j^+μk^\hat{i} + 2\hat{j} + \mu\hat{k}i^+2j^​+μk^ and 3i^−4j^+5k^3\hat{i} - 4\hat{j} + 5\hat{k}3i^−4j^​+5k^, where λ−μ=5\lambda - \mu = 5λ−μ=5, are coplanar, then ∑(λ,μ)∈S80(λ2+μ2)\sum_{(\lambda,\mu)\in S} 80(\lambda^2 + \mu^2)∑(λ,μ)∈S​80(λ2+μ2) is equal to:
  1. (A)237023702370
  2. (B)213021302130
  3. (C)229022902290
  4. (D)221022102210

Correct answer: (C)

Step-by-step solution →
Q80·MathematicsSingle correct
If the domain of the function f(x)=log⁡e(4x2+11x+6)+sin⁡−1(4x+3)+cos⁡−1(10x+63)f(x) = \log_e\left(4x^2 + 11x + 6\right) + \sin^{-1}(4x + 3) + \cos^{-1}\left(\frac{10x + 6}{3}\right)f(x)=loge​(4x2+11x+6)+sin−1(4x+3)+cos−1(310x+6​) is (α,β](\alpha, \beta](α,β], then 36 ∣α+β∣36\,|\alpha + \beta|36∣α+β∣ is equal to:
  1. (A)636363
  2. (B)454545
  3. (C)727272
  4. (D)545454

Correct answer: (B)

Step-by-step solution →
Q81·MathematicsNumerical
If the sum of the series (12−13)+(122−12⋅3+132)+(123−122⋅3+12⋅32−133)+(124−123⋅3+122⋅32−12⋅33+134)+⋯\left(\frac{1}{2} - \frac{1}{3}\right) + \left(\frac{1}{2^2} - \frac{1}{2 \cdot 3} + \frac{1}{3^2}\right) + \left(\frac{1}{2^3} - \frac{1}{2^2 \cdot 3} + \frac{1}{2 \cdot 3^2} - \frac{1}{3^3}\right) + \left(\frac{1}{2^4} - \frac{1}{2^3 \cdot 3} + \frac{1}{2^2 \cdot 3^2} - \frac{1}{2 \cdot 3^3} + \frac{1}{3^4}\right) + \cdots(21​−31​)+(221​−2⋅31​+321​)+(231​−22⋅31​+2⋅321​−331​)+(241​−23⋅31​+22⋅321​−2⋅331​+341​)+⋯ is αβ\frac{\alpha}{\beta}βα​, where α\alphaα and β\betaβ are co-prime, then α+3β\alpha + 3\betaα+3β is equal to....

Correct answer: 7

Step-by-step solution →
Q82·MathematicsNumerical
A person forgets his 4-digit ATM pin code. But he remembers that in the code all the digits are different, the greatest digit is 7 and the sum of the first two digits is equal to the sum of the last two digits. Then the maximum number of trials necessary to obtain the correct code is____

Correct answer: 72

Step-by-step solution →
Q83·MathematicsNumerical
Let the plane PPP contain the line 2x+y−z−3=0=5x−3y+4z+92x + y - z - 3 = 0 = 5x - 3y + 4z + 92x+y−z−3=0=5x−3y+4z+9 and be parallel to the line x+22=3−y−4=z−75\frac{x + 2}{2} = \frac{3 - y}{-4} = \frac{z - 7}{5}2x+2​=−43−y​=5z−7​. Then the distance of the point A(8,−1,−19)A(8, -1, -19)A(8,−1,−19) from the plane PPP measured parallel to the line x−3=y−54=2−z−12\frac{x}{-3} = \frac{y - 5}{4} = \frac{2 - z}{-12}−3x​=4y−5​=−122−z​ is equal to____

Correct answer: 26

Step-by-step solution →
Q84·MathematicsNumerical
Let an ellipse with centre (1,0)(1, 0)(1,0) and latus rectum of length 12\frac{1}{2}21​ have its major axis along xxx-axis. If its minor axis subtends an angle 60∘60^\circ60∘ at the foci, then the square of the sum of the lengths of its minor and major axes is equal to____

Correct answer: 9

Step-by-step solution →
Q85·MathematicsNumerical
Let A={1,2,3,4}A = \{1, 2, 3, 4\}A={1,2,3,4} and RRR be a relation on the set A×AA \times AA×A defined by R={((a,b),(c,d)):2a+3b=4c+5d}R = \{((a, b), (c, d)) : 2a + 3b = 4c + 5d\}R={((a,b),(c,d)):2a+3b=4c+5d}. Then the number of elements in RRR is:

Correct answer: 6

Step-by-step solution →
Q86·MathematicsNumerical
The number of elements in the set {n∈N:10≤n≤100 and 3n−3 is a multiple of 7}\{n \in \mathbb{N} : 10 \le n \le 100 \text{ and } 3^n - 3 \text{ is a multiple of } 7\}{n∈N:10≤n≤100 and 3n−3 is a multiple of 7} is____

Correct answer: 15

Step-by-step solution →
Q87·MathematicsNumerical
If the line x=y=zx = y = zx=y=z intersects the line xsin⁡A+ysin⁡B+zsin⁡C−18=0=xsin⁡2A+ysin⁡2B+zsin⁡2C−9x\sin A + y\sin B + z\sin C - 18 = 0 = x\sin 2A + y\sin 2B + z\sin 2C - 9xsinA+ysinB+zsinC−18=0=xsin2A+ysin2B+zsin2C−9, where A,B,CA, B, CA,B,C are the angles of a triangle ABCABCABC, then 80(sin⁡A2sin⁡B2sin⁡C2)80\left(\sin\frac{A}{2}\sin\frac{B}{2}\sin\frac{C}{2}\right)80(sin2A​sin2B​sin2C​) is equal to____

Correct answer: 5

Step-by-step solution →
Q88·MathematicsNumerical
If the area bounded by the curve 2y2=3x2y^2 = 3x2y2=3x, lines x+y=3x + y = 3x+y=3, y=0y = 0y=0 and outside the circle (x−3)2+y2=2(x - 3)^2 + y^2 = 2(x−3)2+y2=2 is AAA, then 4(π+4A)4(\pi + 4A)4(π+4A) is equal to____

Correct answer: 42

Step-by-step solution →
Q89·MathematicsNumerical
Consider the triangles with vertices A(2,1)A(2, 1)A(2,1), B(0,0)B(0, 0)B(0,0) and C(t,4)C(t, 4)C(t,4), t∈[0,4]t \in [0, 4]t∈[0,4]. If the maximum and the minimum perimeters of such triangles are obtained at t=αt = \alphat=α and t=βt = \betat=β respectively, then 6α+21β6\alpha + 21\beta6α+21β is equal to____

Correct answer: 48

Step-by-step solution →
Q90·MathematicsNumerical
Let f(x)=∫dx(3+4x2)4−3x2f(x) = \int \frac{dx}{\left(3 + 4x^2\right)\sqrt{4 - 3x^2}}f(x)=∫(3+4x2)4−3x2​dx​, ∣x∣<23|x| < \frac{2}{\sqrt{3}}∣x∣<3​2​. If f(0)=0f(0) = 0f(0)=0 and f(1)=1αβtan⁡−1(αβ)f(1) = \frac{1}{\alpha\beta}\tan^{-1}\left(\frac{\alpha}{\beta}\right)f(1)=αβ1​tan−1(βα​), α,β>0\alpha, \beta > 0α,β>0, then α2+β2\alpha^2 + \beta^2α2+β2 is equal to____

Correct answer: 28

Step-by-step solution →

Chapters tested in this paper

Open any chapter to practise every past-year question on that topic across all papers, and see how often it has actually appeared.

  • Properties of Solids and Liquids 172/186
  • Three Dimensional Geometry 176/186
  • Matrices and Determinants 180/186
  • Coordination Compounds 176/186
  • Sets, Relations and Functions 165/186
  • Current Electricity 160/186
  • Sequence and Series 164/186
  • p-Block Elements 164/186
  • Definite Integration 168/186
  • Rotational Motion 172/186
  • Redox Reactions and Electrochemistry 177/186
  • Geometrical Optics 172/186
  • Kinematics 156/186
  • Vector Algebra 173/186
  • Differential Equations 167/186
  • Probability 176/186
  • Permutations and Combinations 162/186
  • Magnetic Field of Current 147/186
  • Binomial Theorem and Its Simple Applications 158/186
  • Electromagnetic Waves 144/186
  • Chemical Bonding and Molecular Structure 151/186
  • d- and f-Block Elements 126/186
  • Thermodynamics 154/186
  • Aldehydes and Ketones 135/186
  • Equilibrium 163/186
  • Solutions 158/186
  • Chemical Thermodynamics 165/186
  • Units and Measurements 149/186
  • Hydrocarbons 126/186
  • Complex Numbers 165/186
  • Biomolecules 162/186
  • Chemical Kinetics 169/186
  • Gravitation 152/186
  • Electric Field and Coulomb's Law 133/186
  • Atomic Structure 161/186
  • Circles 142/186
  • Dual Nature of Matter and Radiation 155/186
  • Quadratic Equations 148/186
  • Work, Energy and Power 132/186
  • Electromagnetic Induction 120/186
  • Wave Optics 130/186
  • Area Under Curves 139/186
  • Kinetic Theory of Gases 135/186
  • Purification and Characterisation of Organic Compounds 116/186
  • Oscillations 117/186
  • Nuclei 116/186
  • Straight Lines 114/186
  • Waves 109/186
  • Capacitors and Dielectrics 115/186
  • Atoms 112/186
  • Statistics 118/186
  • Ellipse 103/186
  • Isolation of Metals 106/186
  • s-Block Elements 88/186
  • Surface Chemistry 98/186
  • Environmental Chemistry 83/186
  • Hydrogen 81/186
  • Electronic Effects and Stability 74/186
  • Indefinite Integration 66/186
  • Polymers 64/186
  • Solid State 63/186
  • Diazonium Salts and Reactions 53/186
← 13 Apr Shift 2 2023All papers27 Jan Shift 1 2024 →

Attempt this paper under exam timing.

Take the 15 April 2023 Shift 1 paper as a timed mock and Jarvis marks it, then tells you which errors were conceptual gaps, which were silly mistakes, and which pattern you have now repeated. Step-by-step solutions for every question included.

Attempt this paper freeSee pricing

Free plan, no time limit · No credit card needed

Jarvis OS

AI-powered JEE preparation.

Question papers

JEE Main PYQsJEE Advanced PYQsPhysics PYQsChemistry PYQsMaths PYQs

Product

TourPricingSign inCreate account

Legal

Privacy PolicyTerms of ServiceRefund & CancellationShipping & DeliveryContact Us

Operated by

Venyou Craft Private Limited

info@jarvisos.net

© 2026 Jarvis OS