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JEE Main 27 January 2024 Shift 1 Question Paper with Answers

27 January 2024 · January session · 90 questions

The complete JEE Main 27 January 2024 Shift 1 paper — all 90 questions with the correct answer for each, tagged to the chapter it tests. Free to read, no account needed.

Physics
30
Chemistry
30
Mathematics
30

Physics — JEE Main 27 January 2024 Shift 1

Q1·Physics·KinematicsSingle correct
Position of an ant (S in metres) moving in Y-Z plane is given by S=2t2j^+5k^S=2t^2\hat j+5\hat kS=2t2j^​+5k^ (where ttt is in second). The magnitude and direction of velocity of the ant at t=1t=1t=1 s will be:
  1. (A)16 m/s in y-direction
  2. (B)4 m/s in x-direction
  3. (C)9 m/s in z-direction
  4. (D)4 m/s in y-direction

Correct answer: (D)

Step-by-step solution →
Q2·Physics·Properties of Solids and LiquidsSingle correct
Statement (I): Viscosity of gases is greater than that of liquids. Statement (II): Surface tension of a liquid decreases due to the presence of insoluble impurities. In the light of the above statements, choose the most appropriate answer from the options given below:
  1. (A)Statement I is correct but statement II is incorrect
  2. (B)Statement I is incorrect but Statement II is correct
  3. (C)Both Statement I and Statement II are incorrect
  4. (D)Both Statement I and Statement II are correct

Correct answer: (B)

Step-by-step solution →
Q3·Physics·Geometrical OpticsSingle correct
If the refractive index of the material of a prism is cot⁡ ⁣(A2)\cot\!\left(\dfrac{A}{2}\right)cot(2A​), where AAA is the angle of prism then the angle of minimum deviation will be:
  1. (A)π−2A\pi-2Aπ−2A
  2. (B)π2−2A\dfrac{\pi}{2}-2A2π​−2A
  3. (C)π−A\pi-Aπ−A
  4. (D)π2−A\dfrac{\pi}{2}-A2π​−A

Correct answer: (A)

Step-by-step solution →
Q4·Physics·Magnetic Field of CurrentSingle correct
A proton moving with a constant velocity passes through a region of space without any change in its velocity. If E⃗\vec EE and B⃗\vec BB represent the electric and magnetic fields respectively, then the region of space may have: (A) E=0E=0E=0, B=0B=0B=0 (B) E≠0E\neq 0E=0, B≠0B\neq 0B=0 (C) E≠0E\neq 0E=0, B=0B=0B=0 (D) E=0E=0E=0, B≠0B\neq 0B=0. Choose the most appropriate answer from the options given below:
  1. (A)(A), (B) and (C) only
  2. (B)(A), (C) and (D) only
  3. (C)(A), (B) and (D) only
  4. (D)(B), (C) and (D) only

Correct answer: (C)

Step-by-step solution →
Q5·Physics·GravitationSingle correct
The acceleration due to gravity on the surface of earth is ggg. If the diameter of earth reduces to half of its original value and mass remains constant, then acceleration due to gravity on the surface of earth would be:
  1. (A)g/4g/4g/4
  2. (B)2g2g2g
  3. (C)g/2g/2g/2
  4. (D)4g4g4g

Correct answer: (D)

Step-by-step solution →
Q6·Physics·Laws of MotionSingle correct
A train is moving with a speed of 12 m/s on rails which are 1.5 m apart. To negotiate a curve radius 400 m, the height by which the outer rail should be raised with respect to the inner rail is (Given, g=10 m/s2g=10\,\text{m/s}^2g=10m/s2):
  1. (A)6.0 cm
  2. (B)5.4 cm
  3. (C)4.8 cm
  4. (D)4.2 cm

Correct answer: (B)

Step-by-step solution →
Q7·Physics·Electronic DevicesSingle correct
Which of the following circuits is reverse-biased?
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (D)

Step-by-step solution →
Q8·Physics·Experimental SkillsSingle correct
Identify the physical quantity that cannot be measured using spherometer:
  1. (A)Radius of curvature of concave surface
  2. (B)Specific rotation of liquids
  3. (C)Thickness of thin plates
  4. (D)Radius of curvature of convex surface

Correct answer: (B)

Step-by-step solution →
Q9·Physics·Work, Energy and PowerSingle correct
Two bodies of mass 4 g and 25 g are moving with equal kinetic energies. The ratio of magnitude of their linear momentum is:
  1. (A)3:5
  2. (B)5:4
  3. (C)2:5
  4. (D)4:5

Correct answer: (C)

Step-by-step solution →
Q10·Physics·ThermodynamicsSingle correct
0.08 kg air is heated at constant volume through 5∘5^{\circ}5∘C. The specific heat of air at constant volume is 0.17 kcal/kg·∘^{\circ}∘C and J=4.18J=4.18J=4.18 joule/cal. The change in its internal energy is approximately:
  1. (A)318 J
  2. (B)298 J
  3. (C)284 J
  4. (D)142 J

Correct answer: (C)

Step-by-step solution →
Q11·Physics·Atoms and NucleiSingle correct
The radius of third stationary orbit of electron for Bohr’s atom is RRR. The radius of fourth stationary orbit will be:
  1. (A)43R\dfrac{4}{3}R34​R
  2. (B)169R\dfrac{16}{9}R916​R
  3. (C)34R\dfrac{3}{4}R43​R
  4. (D)916R\dfrac{9}{16}R169​R

Correct answer: (B)

Step-by-step solution →
Q12·Physics·Electromagnetic InductionSingle correct
A rectangular loop of length 2.5 m and width 2 m is placed at 60∘60^{\circ}60∘ to a magnetic field of 4 T. The loop is removed from the field in 10 sec. The average emf induced in the loop during this time is:
  1. (A)−2-2−2 V
  2. (B)+2+2+2 V
  3. (C)+1+1+1 V
  4. (D)−1-1−1 V

Correct answer: (C)

Step-by-step solution →
Q13·Physics·Electric PotentialSingle correct
An electric charge 10−6 μ10^{-6}\,\mu10−6μC is placed at origin (0, 0) m of X–Y co-ordinate system. Two points P and Q are situated at (3,3)(\sqrt3,\sqrt3)(3​,3​) m and (6,0)(\sqrt6,0)(6​,0) m respectively. The potential difference between the points P and Q will be:
  1. (A)3\sqrt33​ V
  2. (B)6\sqrt66​ V
  3. (C)0 V
  4. (D)3 V

Correct answer: (C)

Step-by-step solution →
Q14·Physics·Dual Nature of Matter and RadiationSingle correct
A convex lens of focal length 40 cm forms an image of an extended source of light on a photo-electric cell. A current III is produced. The lens is replaced by another convex lens having the same diameter but focal length 20 cm. The photoelectric current now is:
  1. (A)I/2I/2I/2
  2. (B)4I4I4I
  3. (C)2I2I2I
  4. (D)III

Correct answer: (D)

Step-by-step solution →
Q15·Physics·Laws of MotionSingle correct
A body of mass 1000 kg is moving horizontally with a velocity 6 m/s. If 200 kg extra mass is added, the final velocity (in m/s) is:
  1. (A)6
  2. (B)2
  3. (C)3
  4. (D)5

Correct answer: (D)

Step-by-step solution →
Q16·Physics·Electromagnetic WavesSingle correct
A plane electromagnetic wave propagating in x-direction is described by Ey=(200 Vm−1)sin⁡[1.5×107t−0.05 x]E_y=(200\,\text{Vm}^{-1})\sin[1.5\times 10^7 t-0.05\,x]Ey​=(200Vm−1)sin[1.5×107t−0.05x]. The intensity of the wave is (Use ϵ0=8.85×10−12 C2N−1m−2\epsilon_0=8.85\times 10^{-12}\,\text{C}^2\text{N}^{-1}\text{m}^{-2}ϵ0​=8.85×10−12C2N−1m−2):
  1. (A)35.4 Wm−235.4\,\text{Wm}^{-2}35.4Wm−2
  2. (B)53.1 Wm−253.1\,\text{Wm}^{-2}53.1Wm−2
  3. (C)26.6 Wm−226.6\,\text{Wm}^{-2}26.6Wm−2
  4. (D)106.2 Wm−2106.2\,\text{Wm}^{-2}106.2Wm−2

Correct answer: (B)

Step-by-step solution →
Q17·Physics·Units and MeasurementsSingle correct
Statement (I): Planck’s constant and angular momentum have same dimensions. Statement (II): Linear momentum and moment of force have same dimensions. In the light of the above statements, choose the correct answer from the options given below:
  1. (A)Statement I is true but Statement II is false
  2. (B)Both Statement I and Statement II are false
  3. (C)Both Statement I and Statement II are true
  4. (D)Statement I is false but Statement II is true

Correct answer: (A)

Step-by-step solution →
Q18·Physics·Current ElectricitySingle correct
A wire of length 10 cm and radius 7×10−4\sqrt7\times 10^{-4}7​×10−4 m connected across the right gap of a meter bridge. When a resistance of 4.5 Ω\OmegaΩ is connected on the left gap by using a resistance box, the balance length is found to be at 60 cm from the left end. If the resistivity of the wire is R×10−7 ΩR\times 10^{-7}\,\OmegaR×10−7Ωm, then value of RRR is:
  1. (A)63
  2. (B)70
  3. (C)66
  4. (D)35

Correct answer: (C)

Step-by-step solution →
Q19·Physics·Current ElectricitySingle correct
A wire of resistance RRR and length LLL is cut into 5 equal parts. If these parts are joined parallely, then resultant resistance will be:
  1. (A)125R\dfrac{1}{25}R251​R
  2. (B)15R\dfrac{1}{5}R51​R
  3. (C)25R25R25R
  4. (D)5R5R5R

Correct answer: (A)

Step-by-step solution →
Q20·Physics·Kinetic Theory of GasesSingle correct
The average kinetic energy of a monatomic molecule is 0.414 eV at temperature (Use KB=1.38×10−23K_B=1.38\times 10^{-23}KB​=1.38×10−23 J/mol-K):
  1. (A)3000 K
  2. (B)3200 K
  3. (C)1600 K
  4. (D)1500 K

Correct answer: (B)

Step-by-step solution →
Q21·Physics·KinematicsNumerical
A particle starts from origin at t=0t=0t=0 with a velocity 5i^5\hat i5i^ m/s and moves in x\textendash y plane under action of a force which produces a constant acceleration of (3i^+2j^)(3\hat i+2\hat j)(3i^+2j^​) m/s2^22. If the x-coordinate of the particle at that instant is 84 m, then the speed of the particle at this time is α\sqrt{\alpha}α​ m/s. The value of α\alphaα is __________.

Correct answer: 673

Step-by-step solution →
Q22·Physics·Electric Field and Coulomb's LawNumerical
A thin metallic wire having cross sectional area of 10−410^{-4}10−4 m2^22 is used to make a ring of radius 30 cm. A positive charge of 2π2\pi2π C is uniformly distributed over the ring, while another positive charge of 30 pC is kept at the centre of the ring. The tension in the ring is __________ N; provided that the ring does not get deformed (neglect the influence of gravity). (given, 14πϵ0=9×109\dfrac{1}{4\pi\epsilon_0}=9\times 10^94πϵ0​1​=9×109 SI units).

Correct answer: 3

Step-by-step solution →
Q23·Physics·Electromagnetic InductionNumerical
Two coils have mutual inductance 0.002 H. The current changes in the first coil according to the relation i=i0sin⁡ωti=i_0\sin\omega ti=i0​sinωt, where i0=5i_0=5i0​=5 A and ω=50π\omega=50\piω=50π rad/s. The maximum value of emf in the second coil is πα\dfrac{\pi}{\alpha}απ​ V. The value of α\alphaα is __________.

Correct answer: 2

Step-by-step solution →
Q24·Physics·Geometrical OpticsNumerical
Two immiscible liquids of refractive indices 85\dfrac{8}{5}58​ and 32\dfrac{3}{2}23​ respectively are put in a beaker as shown in the figure. The height of each column is 6 cm. A coin is placed at the bottom of the beaker. For near normal vision, the apparent depth of the coin is α4\dfrac{\alpha}{4}4α​ cm. The value of α\alphaα is __________.

Correct answer: 31

Step-by-step solution →
Q25·Physics·Atoms and NucleiNumerical
In a nuclear fission process, a high mass nuclide (A≈236A\approx 236A≈236) with binding energy 7.6 MeV/Nucleon dissociated into middle mass nuclides (A≈118A\approx 118A≈118), having binding energy of 8.6 MeV/Nucleon. The energy released in the process would be __________ MeV.

Correct answer: 236

Step-by-step solution →
Q26·Physics·Rotational MotionNumerical
Four particles each of mass 1 kg are placed at four corners of a square of side 2 m. Moment of inertia of system about an axis perpendicular to its plane and passing through one of its vertex is __________ kgm2^22.

Correct answer: 16

Step-by-step solution →
Q27·Physics·OscillationsNumerical
A particle executes simple harmonic motion with an amplitude of 4 cm. At the mean position, velocity of the particle is 10 cm/s. The distance of the particle from the mean position when its speed becomes 5 cm/s is α\sqrt{\alpha}α​ cm, where α=\alpha=α= __________.

Correct answer: 12

Step-by-step solution →
Q28·Physics·Magnetic Field of CurrentNumerical
Two long, straight wires carry equal currents in opposite directions as shown in figure. The separation between the wires is 5.0 cm. The magnitude of the magnetic field at a point P midway between the wires is __________ μ\muμT. (Given: μ0=4π×10−7\mu_0=4\pi\times 10^{-7}μ0​=4π×10−7 TmA−1^{-1}−1)

Correct answer: 160

Step-by-step solution →
Q29·Physics·Current ElectricityNumerical
The charge accumulated on the capacitor connected in the following circuit is __________ μ\muμC (Given C=150 μC=150\,\muC=150μF).

Correct answer: 400

Step-by-step solution →
Q30·Physics·Properties of Solids and LiquidsNumerical
If average depth of an ocean is 4000 m and the bulk modulus of water is 2×1092\times 10^92×109 Nm−2^{-2}−2, then fractional compression ΔVV\dfrac{\Delta V}{V}VΔV​ of water at the bottom of ocean is α×10−2\alpha\times 10^{-2}α×10−2. The value of α\alphaα is __________ (Given, g=10g=10g=10 ms−2^{-2}−2, ρ=1000\rho=1000ρ=1000 kg m−3^{-3}−3).

Correct answer: 2

Step-by-step solution →

Chemistry — JEE Main 27 January 2024 Shift 1

Q31·Chemistry·BiomoleculesSingle correct
Two nucleotides are joined together by a linkage known as:
  1. (A)Phosphodiester linkage
  2. (B)Glycosidic linkage
  3. (C)Disulphide linkage
  4. (D)Peptide linkage

Correct answer: (A)

Step-by-step solution →
Q32·Chemistry·IsomerismSingle correct
Highest enol content will be shown by:
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (B)

Step-by-step solution →
Q33·Chemistry·p-Block ElementsSingle correct
Element not showing variable oxidation state is:
  1. (A)Bromine
  2. (B)Iodine
  3. (C)Chlorine
  4. (D)Fluorine

Correct answer: (D)

Step-by-step solution →
Q34·Chemistry·AminesSingle correct
Which of the following is strongest Bronsted base?
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (D)

Step-by-step solution →
Q35·Chemistry·d- and f-Block ElementsSingle correct
Which of the following electronic configuration would be associated with the highest magnetic moment?
  1. (A)[Ar] 3d7[\text{Ar}]\,3d^7[Ar]3d7
  2. (B)[Ar] 3d8[\text{Ar}]\,3d^8[Ar]3d8
  3. (C)[Ar] 3d3[\text{Ar}]\,3d^3[Ar]3d3
  4. (D)[Ar] 3d6[\text{Ar}]\,3d^6[Ar]3d6

Correct answer: (D)

Step-by-step solution →
Q36·Chemistry·Electronic Effects and StabilitySingle correct
Which of the following has highly acidic hydrogen?
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (D)

Step-by-step solution →
Q37·Chemistry·SolutionsSingle correct
A solution of two miscible liquids showing negative deviation from Raoult's law will have:
  1. (A)increased vapour pressure, increased boiling point
  2. (B)increased vapour pressure, decreased boiling point
  3. (C)decreased vapour pressure, decreased boiling point
  4. (D)decreased vapour pressure, increased boiling point

Correct answer: (D)

Step-by-step solution →
Q38·Chemistry·d- and f-Block ElementsSingle correct
Consider the following complex ions P=[FeF6]3−P=[\text{FeF}_6]^{3-}P=[FeF6​]3−, Q=[V(H2O)6]2+Q=[\text{V}(\text{H}_2\text{O})_6]^{2+}Q=[V(H2​O)6​]2+, R=[Fe(H2O)6]2+R=[\text{Fe}(\text{H}_2\text{O})_6]^{2+}R=[Fe(H2​O)6​]2+. The correct order of the complex ions, according to their spin only magnetic moment values (in B.M.) is:
  1. (A)R<Q<PR<Q<PR<Q<P
  2. (B)R<P<QR<P<QR<P<Q
  3. (C)Q<R<PQ<R<PQ<R<P
  4. (D)Q<P<RQ<P<RQ<P<R

Correct answer: (C)

Step-by-step solution →
Q39·Chemistry·Chemical Bonding and Molecular StructureSingle correct
Choose the polar molecule from the following:
  1. (A)CCl4\text{CCl}_4CCl4​
  2. (B)CO2\text{CO}_2CO2​
  3. (C)CH2=CH2\text{CH}_2=\text{CH}_2CH2​=CH2​
  4. (D)CHCl3\text{CHCl}_3CHCl3​

Correct answer: (D)

Step-by-step solution →
Q40·Chemistry·Classification of Elements and Periodicity in PropertiesSingle correct
Statement (I): The 4f-series and 5f-series of elements are placed separately in the Periodic table to preserve the principle of classification. Statement (II): S-block elements can be found in pure form in nature. In the light of the above statements, choose the most appropriate answer from the options given below:
  1. (A)Statement I is false but Statement II is true
  2. (B)Both Statement I and Statement II are true
  3. (C)Statement I is true but Statement II is false
  4. (D)Both Statement I and Statement II are false

Correct answer: (C)

Step-by-step solution →
Q41·Chemistry·Alcohols and EthersSingle correct
Statement (I): p-nitrophenol is more acidic than m-nitrophenol and o-nitrophenol. Statement (II): Ethanol will give immediate turbidity with Lucas reagent. In the light of the above statements, choose the correct answer from the options given below:
  1. (A)Statement I is true but Statement II is false
  2. (B)Both Statement I and Statement II are true
  3. (C)Both Statement I and Statement II are false
  4. (D)Statement I is false but Statement II is true

Correct answer: (A)

Step-by-step solution →
Q42·Chemistry·Alcohols and EthersSingle correct
The ascending order of acidity of —OH group in the following compounds is: (A) Bu—OH; (B) 4-nitrophenol; (C) 4-methoxyphenol; (D) phenol; (E) 2,4-dinitrophenol. Choose the correct answer from the options given below:
  1. (A)(A)<(D)<(C)<(B)<(E)(A)<(D)<(C)<(B)<(E)(A)<(D)<(C)<(B)<(E)
  2. (B)(C)<(A)<(D)<(B)<(E)(C)<(A)<(D)<(B)<(E)(C)<(A)<(D)<(B)<(E)
  3. (C)(C)<(D)<(B)<(A)<(E)(C)<(D)<(B)<(A)<(E)(C)<(D)<(B)<(A)<(E)
  4. (D)(A)<(C)<(D)<(B)<(E)(A)<(C)<(D)<(B)<(E)(A)<(C)<(D)<(B)<(E)

Correct answer: (D)

Step-by-step solution →
Q43·Chemistry·p-Block ElementsSingle correct
Given below are two statements: one is labelled as Assertion (A) and the other is labelled as Reason (R). Assertion (A): Melting point of Boron (2453 K) is unusually high in group 13 elements. Reason (R): Solid Boron has very strong crystalline lattice. In the light of the above statements, choose the most appropriate answer from the options given below:
  1. (A)Both (A) and (R) are correct but (R) is Not the correct explanation of (A)
  2. (B)Both (A) and (R) are correct and (R) is the correct explanation of (A)
  3. (C)(A) is true but (R) is false
  4. (D)(A) is false but (R) is true

Correct answer: (B)

Step-by-step solution →
Q44·Chemistry·Some Basic Concepts in ChemistrySingle correct
Cyclohexene is __________ type of an organic compound.
  1. (A)Benzenoid aromatic
  2. (B)Benzenoid non-aromatic
  3. (C)Acyclic
  4. (D)Alicyclic

Correct answer: (D)

Step-by-step solution →
Q45·Chemistry·p-Block ElementsSingle correct
Yellow compound of lead chromate gets dissolved on treatment with hot NaOH solution. The product of lead formed is a:
  1. (A)Tetraanionic complex with coordination number six
  2. (B)Neutral complex with coordination number four
  3. (C)Dianionic complex with coordination number six
  4. (D)Dianionic complex with coordination number four

Correct answer: (D)

Step-by-step solution →
Q46·Chemistry·EquilibriumSingle correct
Given below are two statements: Statement (I): Aqueous solution of ammonium carbonate is basic. Statement (II): Acidic/basic nature of salt solution of a salt of weak acid and weak base depends on KaK_aKa​ and KbK_bKb​ value of acid and the base forming it. In the light of the above statements, choose the most appropriate answer from the options given below:
  1. (A)Both Statement I and Statement II are correct
  2. (B)Statement I is correct but Statement II is incorrect
  3. (C)Both Statement I and Statement II are incorrect
  4. (D)Statement I is incorrect but Statement II is correct

Correct answer: (A)

Step-by-step solution →
Q47·Chemistry·Some Basic Concepts in ChemistrySingle correct
IUPAC name of following compound (P) is:
  1. (A)1-Ethyl-5,5-dimethylcyclohexane
  2. (B)3-Ethyl-1,1-dimethylcyclohexane
  3. (C)1-Ethyl-3,3-dimethylcyclohexane
  4. (D)1,1-Dimethyl-3-ethylcyclohexane

Correct answer: (B)

Step-by-step solution →
Q48·Chemistry·d- and f-Block ElementsSingle correct
NaCl reacts with conc. H2SO4\text{H}_2\text{SO}_4H2​SO4​ and K2Cr2O7\text{K}_2\text{Cr}_2\text{O}_7K2​Cr2​O7​ to give reddish fumes (B), which react with NaOH to give yellow solution (C). (B) and (C) respectively are:
  1. (A)CrO2Cl2,  Na2CrO4\text{CrO}_2\text{Cl}_2,\;\text{Na}_2\text{CrO}_4CrO2​Cl2​,Na2​CrO4​
  2. (B)Na2CrO4,  CrO2Cl2\text{Na}_2\text{CrO}_4,\;\text{CrO}_2\text{Cl}_2Na2​CrO4​,CrO2​Cl2​
  3. (C)CrO2Cl2,  KHSO4\text{CrO}_2\text{Cl}_2,\;\text{KHSO}_4CrO2​Cl2​,KHSO4​
  4. (D)CrO2Cl2,  Na2Cr2O7\text{CrO}_2\text{Cl}_2,\;\text{Na}_2\text{Cr}_2\text{O}_7CrO2​Cl2​,Na2​Cr2​O7​

Correct answer: (A)

Step-by-step solution →
Q49·Chemistry·HydrocarbonsSingle correct
The correct statement regarding nucleophilic substitution reaction in a chiral alkyl halide is:
  1. (A)Retention occurs in SN1S_N1SN​1 reaction and inversion occurs in SN2S_N2SN​2 reaction.
  2. (B)Racemisation occurs in SN1S_N1SN​1 reaction and retention occurs in SN2S_N2SN​2 reaction.
  3. (C)Racemisation occurs in both SN1S_N1SN​1 and SN2S_N2SN​2 reactions.
  4. (D)Racemisation occurs in SN1S_N1SN​1 reaction and inversion occurs in SN2S_N2SN​2 reaction.

Correct answer: (D)

Step-by-step solution →
Q50·Chemistry·Atomic StructureSingle correct
The electronic configuration for Neodymium is: [Atomic Number for Neodymium 60]
  1. (A)[Xe] 4f4 6s2[\text{Xe}]\,4f^4\,6s^2[Xe]4f46s2
  2. (B)[Xe] 5f4 7s2[\text{Xe}]\,5f^4\,7s^2[Xe]5f47s2
  3. (C)[Xe] 6f4 6s2[\text{Xe}]\,6f^4\,6s^2[Xe]6f46s2
  4. (D)[Xe] 4f5 5d1 6s2[\text{Xe}]\,4f^5\,5d^1\,6s^2[Xe]4f55d16s2

Correct answer: (A)

Step-by-step solution →
Q51·Chemistry·Redox Reactions and ElectrochemistryNumerical
The mass of silver (Molar mass of Ag : 108 g\,mol−1^{-1}−1) displaced by a quantity of electricity which displaces 5600 mL of O2\text{O}_2O2​ at S.T.P. will be __________ g.

Correct answer: 108

Step-by-step solution →
Q52·Chemistry·Chemical KineticsNumerical
Consider the following data for the given reaction 2HI(g)→H2(g)+I2(g)2\text{HI}_{(g)}\to\text{H}_{2(g)}+\text{I}_{2(g)}2HI(g)​→H2(g)​+I2(g)​. Experiment 1, 2, 3 — [HI] (mol L−1^{-1}−1) = 0.005, 0.01, 0.02; Rate (mol L−1^{-1}−1 s−1^{-1}−1) = 7.5×10−47.5\times 10^{-4}7.5×10−4, 3.0×10−33.0\times 10^{-3}3.0×10−3, 1.2×10−21.2\times 10^{-2}1.2×10−2. The order of the reaction is __________.

Correct answer: 2

Step-by-step solution →
Q53·Chemistry·Some Basic Concepts in ChemistryNumerical
Mass of methane required to produce 22 g of CO2\text{CO}_2CO2​ after complete combustion is __________ g. (Given Molar mass in g mol−1^{-1}−1: C=12.0C=12.0C=12.0; H=1.0H=1.0H=1.0; O=16.0O=16.0O=16.0)

Correct answer: 8

Step-by-step solution →
Q54·Chemistry·Chemical ThermodynamicsNumerical
If three moles of an ideal gas at 300 K expand isothermally from 30 dm3^33 to 45 dm3^33 against a constant opposing pressure of 80 kPa, then the amount of heat transferred is __________ J.

Correct answer: 1200

Step-by-step solution →
Q55·Chemistry·HydrocarbonsNumerical
3-Methylhex-2-ene on reaction with HBr in presence of peroxide forms an addition product (A). The number of possible stereoisomers for 'A' is __________.

Correct answer: 4

Step-by-step solution →
Q56·Chemistry·AromaticityNumerical
Among the given organic compounds, the total number of aromatic compounds is __________.

Correct answer: 3

Step-by-step solution →
Q57·Chemistry·Electronic Effects and StabilityNumerical
Among the following, total number of meta directing functional groups is (Integer based): −OCH3-\text{OCH}_3−OCH3​, −NO2-\text{NO}_2−NO2​, −CN-\text{CN}−CN, −CH3-\text{CH}_3−CH3​, −NHCOCH3-\text{NHCOCH}_3−NHCOCH3​, −COR-\text{COR}−COR, −OH-\text{OH}−OH, −COOH-\text{COOH}−COOH, −Cl-\text{Cl}−Cl.

Correct answer: 4

Step-by-step solution →
Q58·Chemistry·Atomic StructureNumerical
The number of electrons present in all the completely filled subshells having n=4n=4n=4 and s=+12s=+\dfrac{1}{2}s=+21​ is __________. (Where n=n=n= principal quantum number and s=s=s= spin quantum number)

Correct answer: 16

Step-by-step solution →
Q59·Chemistry·Chemical Bonding and Molecular StructureNumerical
Sum of bond order of CO and NO+^++ is __________.

Correct answer: 6

Step-by-step solution →
Q60·Chemistry·p-Block ElementsNumerical
From the given list, the number of compounds with +4 oxidation state of Sulphur __________: SO3,  H2SO3,  SOCl2,  SF4,  BaSO4,  H2S2O7\text{SO}_3,\;\text{H}_2\text{SO}_3,\;\text{SOCl}_2,\;\text{SF}_4,\;\text{BaSO}_4,\;\text{H}_2\text{S}_2\text{O}_7SO3​,H2​SO3​,SOCl2​,SF4​,BaSO4​,H2​S2​O7​.

Correct answer: 3

Step-by-step solution →

Mathematics — JEE Main 27 January 2024 Shift 1

Q61·Mathematics·Permutations and CombinationsSingle correct
n−1Cr=(k2−8)⋅nCr+1^{n-1}C_r=(k^2-8)\cdot{}^{n}C_{r+1}n−1Cr​=(k2−8)⋅nCr+1​ if and only if:
  1. (A)22<k≤32\sqrt2<k\le 322​<k≤3
  2. (B)23<k≤322\sqrt3<k\le 3\sqrt223​<k≤32​
  3. (C)23<k<332\sqrt3<k<3\sqrt323​<k<33​
  4. (D)22<k<232\sqrt2<k<2\sqrt322​<k<23​

Correct answer: (A)

Step-by-step solution →
Q62·Mathematics·Three Dimensional GeometrySingle correct
The distance of the point (7,−2,11)(7,-2,11)(7,−2,11) from the line x−61=y−40=z−83\dfrac{x-6}{1}=\dfrac{y-4}{0}=\dfrac{z-8}{3}1x−6​=0y−4​=3z−8​ along the line x−52=y−1−3=z−56\dfrac{x-5}{2}=\dfrac{y-1}{-3}=\dfrac{z-5}{6}2x−5​=−3y−1​=6z−5​, is:
  1. (A)12
  2. (B)14
  3. (C)18
  4. (D)21

Correct answer: (B)

Step-by-step solution →
Q63·Mathematics·Differential EquationsSingle correct
Let x=x(t)x=x(t)x=x(t) and y=y(t)y=y(t)y=y(t) be solutions of the differential equations dxdt+ax=0\dfrac{dx}{dt}+ax=0dtdx​+ax=0 and dydt+by=0\dfrac{dy}{dt}+by=0dtdy​+by=0 respectively, a,b∈Ra,b\in\mathbb Ra,b∈R. Given that x(0)=2x(0)=2x(0)=2, y(0)=1y(0)=1y(0)=1 and 3y(1)=2x(1)3y(1)=2x(1)3y(1)=2x(1), the value of ttt, for which x(t)=y(t)x(t)=y(t)x(t)=y(t), is:
  1. (A)log⁡2/32\log_{2/3} 2log2/3​2
  2. (B)log⁡43\log_4 3log4​3
  3. (C)log⁡34\log_3 4log3​4
  4. (D)log⁡4/32\log_{4/3} 2log4/3​2

Correct answer: (D)

Step-by-step solution →
Q64·Mathematics·Definite IntegrationSingle correct
If (a,b)(a,b)(a,b) be the orthocentre of the triangle whose vertices are (1,2)(1,2)(1,2), (2,3)(2,3)(2,3) and (3,1)(3,1)(3,1) and I1=∫abxsin⁡(4x−x2) dxI_1=\displaystyle\int_a^b x\sin(4x-x^2)\,dxI1​=∫ab​xsin(4x−x2)dx, I2=∫absin⁡(4x−x2) dxI_2=\displaystyle\int_a^b \sin(4x-x^2)\,dxI2​=∫ab​sin(4x−x2)dx, then 36 I1I236\,\dfrac{I_1}{I_2}36I2​I1​​ is equal to:
  1. (A)72
  2. (B)88
  3. (C)80
  4. (D)66

Correct answer: (A)

Step-by-step solution →
Q65·Mathematics·Binomial Theorem and Its Simple ApplicationsSingle correct
If AAA denotes the sum of all the coefficients in the expansion of (1−3x+10x2)n(1-3x+10x^2)^n(1−3x+10x2)n and BBB denotes the sum of all the coefficients in the expansion of (1+x2)n(1+x^2)^n(1+x2)n, then:
  1. (A)A=B3A=B^3A=B3
  2. (B)3A=B3A=B3A=B
  3. (C)B=A3B=A^3B=A3
  4. (D)A=3BA=3BA=3B

Correct answer: (A)

Step-by-step solution →
Q66·Mathematics·Sequence and SeriesSingle correct
The number of common terms in the progressions 4,9,14,19,…4,9,14,19,\ldots4,9,14,19,…, up to 25th25^{\text{th}}25th term and 3,6,9,12,…3,6,9,12,\ldots3,6,9,12,…, up to 37th37^{\text{th}}37th term is:
  1. (A)9
  2. (B)5
  3. (C)7
  4. (D)8

Correct answer: (C)

Step-by-step solution →
Q67·Mathematics·CirclesSingle correct
If the shortest distance of the parabola y2=4xy^2=4xy2=4x from the centre of the circle x2+y2−4x−16y+64=0x^2+y^2-4x-16y+64=0x2+y2−4x−16y+64=0 is ddd, then d2d^2d2 is equal to:
  1. (A)16
  2. (B)24
  3. (C)20
  4. (D)36

Correct answer: (C)

Step-by-step solution →
Q68·Mathematics·Three Dimensional GeometrySingle correct
If the shortest distance between the lines x−41=y+12=z−3\dfrac{x-4}{1}=\dfrac{y+1}{2}=\dfrac{z}{-3}1x−4​=2y+1​=−3z​ and x−λ2=y+14=z−2−5\dfrac{x-\lambda}{2}=\dfrac{y+1}{4}=\dfrac{z-2}{-5}2x−λ​=4y+1​=−5z−2​ is 65\dfrac{6}{\sqrt5}5​6​, then the sum of all possible values of λ\lambdaλ is:
  1. (A)5
  2. (B)8
  3. (C)7
  4. (D)10

Correct answer: (B)

Step-by-step solution →
Q69·Mathematics·Definite IntegrationSingle correct
If ∫0113+x+1+x dx=a+b2+c3\displaystyle\int_0^1\dfrac{1}{\sqrt{3+x}+\sqrt{1+x}}\,dx=a+b\sqrt2+c\sqrt3∫01​3+x​+1+x​1​dx=a+b2​+c3​, where aaa, bbb, ccc are rational numbers, then 2a+3b−4c2a+3b-4c2a+3b−4c is equal to:
  1. (A)4
  2. (B)10
  3. (C)7
  4. (D)8

Correct answer: (D)

Step-by-step solution →
Q70·Mathematics·Sets, Relations and FunctionsSingle correct
Let S={1,2,3,…,10}S=\{1,2,3,\ldots,10\}S={1,2,3,…,10}. Suppose MMM is the set of all the subsets of SSS, then the relation R={(A,B):A∩B≠φ; A,B∈M}R=\{(A,B):A\cap B\neq\varphi;\,A,B\in M\}R={(A,B):A∩B=φ;A,B∈M} is:
  1. (A)symmetric and reflexive only
  2. (B)reflexive only
  3. (C)symmetric and transitive only
  4. (D)symmetric only

Correct answer: (D)

Step-by-step solution →
Q71·Mathematics·Complex NumbersSingle correct
If S={z∈C:∣z−i∣=∣z+i∣=∣z−1∣}S=\{z\in\mathbb C:|z-i|=|z+i|=|z-1|\}S={z∈C:∣z−i∣=∣z+i∣=∣z−1∣}, then n(S)n(S)n(S) is:
  1. (A)1
  2. (B)0
  3. (C)3
  4. (D)2

Correct answer: (A)

Step-by-step solution →
Q72·Mathematics·CirclesSingle correct
Four distinct points (2k,3k)(2k,3k)(2k,3k), (1,0)(1,0)(1,0), (0,1)(0,1)(0,1) and (0,0)(0,0)(0,0) lie on a circle for kkk equal to:
  1. (A)213\dfrac{2}{13}132​
  2. (B)313\dfrac{3}{13}133​
  3. (C)513\dfrac{5}{13}135​
  4. (D)113\dfrac{1}{13}131​

Correct answer: (C)

Step-by-step solution →
Q73·Mathematics·Limits and ContinuitySingle correct
Consider the function f(x)={a(7x−12−x2)b ∣x2−7x+12∣,x<32sin⁡(x−3)/(x−[x]),x>3b,x=3f(x)=\begin{cases}\dfrac{a(7x-12-x^2)}{b\,|x^2-7x+12|}, & x<3\\ 2^{\sin(x-3)/(x-[x])}, & x>3\\ b, & x=3\end{cases}f(x)=⎩⎨⎧​b∣x2−7x+12∣a(7x−12−x2)​,2sin(x−3)/(x−[x]),b,​x<3x>3x=3​, where [x][x][x] denotes the greatest integer less than or equal to xxx. If SSS denotes the set of all ordered pairs (a,b)(a,b)(a,b) such that f(x)f(x)f(x) is continuous at x=3x=3x=3, then the number of elements in SSS is:
  1. (A)2
  2. (B)Infinitely many
  3. (C)4
  4. (D)1

Correct answer: (D)

Step-by-step solution →
Q74·Mathematics·Statistics and ProbabilitySingle correct
Let a1,a2,…,a10a_1,a_2,\ldots,a_{10}a1​,a2​,…,a10​ be 10 observations such that ∑k=110ak=50\displaystyle\sum_{k=1}^{10}a_k=50k=1∑10​ak​=50 and ∑∀k<jak aj=1100\displaystyle\sum_{\forall k<j}a_k\,a_j=1100∀k<j∑​ak​aj​=1100. Then the standard deviation of a1,a2,…,a10a_1,a_2,\ldots,a_{10}a1​,a2​,…,a10​ is equal to:
  1. (A)5
  2. (B)5\sqrt55​
  3. (C)10
  4. (D)115\sqrt{115}115​

Correct answer: (B)

Step-by-step solution →
Q75·Mathematics·EllipseSingle correct
The length of the chord of the ellipse x225+y216=1\dfrac{x^2}{25}+\dfrac{y^2}{16}=125x2​+16y2​=1, whose mid point is (1,25)\left(1,\dfrac{2}{5}\right)(1,52​), is equal to:
  1. (A)16915\dfrac{\sqrt{1691}}{5}51691​​
  2. (B)20095\dfrac{\sqrt{2009}}{5}52009​​
  3. (C)17415\dfrac{\sqrt{1741}}{5}51741​​
  4. (D)15415\dfrac{\sqrt{1541}}{5}51541​​

Correct answer: (A)

Step-by-step solution →
Q76·Mathematics·Straight LinesSingle correct
The portion of the line 4x+5y=204x+5y=204x+5y=20 in the first quadrant is trisected by the lines L1L_1L1​ and L2L_2L2​ passing through the origin. The tangent of an angle between the lines L1L_1L1​ and L2L_2L2​ is:
  1. (A)85\dfrac{8}{5}58​
  2. (B)2541\dfrac{25}{41}4125​
  3. (C)25\dfrac{2}{5}52​
  4. (D)3041\dfrac{30}{41}4130​

Correct answer: (D)

Step-by-step solution →
Q77·Mathematics·Vector AlgebraSingle correct
Let a⃗=i^+2j^+k^\vec a=\hat i+2\hat j+\hat ka=i^+2j^​+k^, b⃗=3(i^−j^+k^)\vec b=3(\hat i-\hat j+\hat k)b=3(i^−j^​+k^). Let c⃗\vec cc be the vector such that a⃗×c⃗=b⃗\vec a\times\vec c=\vec ba×c=b and a⃗⋅c⃗=3\vec a\cdot\vec c=3a⋅c=3. Then a⃗⋅((c⃗×b⃗)−b⃗−c⃗)\vec a\cdot\big((\vec c\times\vec b)-\vec b-\vec c\big)a⋅((c×b)−b−c) is equal to:
  1. (A)32
  2. (B)24
  3. (C)20
  4. (D)36

Correct answer: (B)

Step-by-step solution →
Q78·Mathematics·Limits and ContinuitySingle correct
If a=lim⁡x→01+1+x4−2x4a=\displaystyle\lim_{x\to 0}\dfrac{\sqrt{1+\sqrt{1+x^4}}-\sqrt2}{x^4}a=x→0lim​x41+1+x4​​−2​​ and b=lim⁡x→0sin⁡2x2−1+cos⁡xb=\displaystyle\lim_{x\to 0}\dfrac{\sin^2 x}{\sqrt2-\sqrt{1+\cos x}}b=x→0lim​2​−1+cosx​sin2x​, then the value of ab3ab^3ab3 is:
  1. (A)36
  2. (B)32
  3. (C)25
  4. (D)30

Correct answer: (B)

Step-by-step solution →
Q79·Mathematics·Matrices and DeterminantsSingle correct
Consider the matrix f(x)=[cos⁡x−sin⁡x0sin⁡xcos⁡x0001]f(x)=\begin{bmatrix}\cos x & -\sin x & 0\\ \sin x & \cos x & 0\\ 0 & 0 & 1\end{bmatrix}f(x)=​cosxsinx0​−sinxcosx0​001​​. Given below are two statements: Statement I: f(−x)f(-x)f(−x) is the inverse of the matrix f(x)f(x)f(x). Statement II: f(x)⋅f(y)=f(x+y)f(x)\cdot f(y)=f(x+y)f(x)⋅f(y)=f(x+y). In the light of the above statements, choose the correct answer from the options given below:
  1. (A)Statement I is false but Statement II is true
  2. (B)Both Statement I and Statement II are false
  3. (C)Statement I is true but Statement II is false
  4. (D)Both Statement I and Statement II are true

Correct answer: (D)

Step-by-step solution →
Q80·Mathematics·Sets, Relations and FunctionsSingle correct
The function f:N−{1}→Nf:\mathbb N-\{1\}\to\mathbb Nf:N−{1}→N defined by f(n)=f(n)=f(n)= the highest prime factor of nnn, is:
  1. (A)both one-one and onto
  2. (B)one-one only
  3. (C)onto only
  4. (D)neither one-one nor onto

Correct answer: (D)

Step-by-step solution →
Q81·Mathematics·Vector AlgebraNumerical
The least positive integral value of α\alphaα, for which the angle between the vectors αi^−2j^+2k^\alpha\hat i-2\hat j+2\hat kαi^−2j^​+2k^ and αi^+2αj^−2k^\alpha\hat i+2\alpha\hat j-2\hat kαi^+2αj^​−2k^ is acute, is __________.

Correct answer: 5

Step-by-step solution →
Q82·Mathematics·Differential EquationsNumerical
Let for a differentiable function f:(0,∞)→Rf:(0,\infty)\to\mathbb Rf:(0,∞)→R, f(x)−f(y)≥log⁡e(x/y)+x−yf(x)-f(y)\ge\log_e(x/y)+x-yf(x)−f(y)≥loge​(x/y)+x−y, ∀ x,y∈(0,∞)\forall\,x,y\in(0,\infty)∀x,y∈(0,∞). Then ∑n=120f′ ⁣(1n2)\displaystyle\sum_{n=1}^{20}f'\!\left(\dfrac{1}{n^2}\right)n=1∑20​f′(n21​) is equal to __________.

Correct answer: 2890

Step-by-step solution →
Q83·Mathematics·Differential EquationsNumerical
If the solution of the differential equation (2x+3y−2) dx+(4x+6y−7) dy=0(2x+3y-2)\,dx+(4x+6y-7)\,dy=0(2x+3y−2)dx+(4x+6y−7)dy=0, y(0)=3y(0)=3y(0)=3, is αx+βy+3log⁡e∣2x+3y−γ∣=6\alpha x+\beta y+3\log_e|2x+3y-\gamma|=6αx+βy+3loge​∣2x+3y−γ∣=6, then α+2β+3γ\alpha+2\beta+3\gammaα+2β+3γ is equal to __________.

Correct answer: 29

Step-by-step solution →
Q84·Mathematics·Area Under CurvesNumerical
Let the area of the region {(x,y):x−2y+4≥0, x+2y2≥0, x+4y2≤8, y≥0}\{(x,y):x-2y+4\ge 0,\,x+2y^2\ge 0,\,x+4y^2\le 8,\,y\ge 0\}{(x,y):x−2y+4≥0,x+2y2≥0,x+4y2≤8,y≥0} be mn\dfrac{m}{n}nm​, where mmm and nnn are coprime numbers. Then m+nm+nm+n is equal to __________.

Correct answer: 119

Step-by-step solution →
Q85·Mathematics·Sequence and SeriesNumerical
If 8=3+14(3+p)+142(3+2p)+143(3+3p)+…∞8=3+\dfrac{1}{4}(3+p)+\dfrac{1}{4^2}(3+2p)+\dfrac{1}{4^3}(3+3p)+\ldots\infty8=3+41​(3+p)+421​(3+2p)+431​(3+3p)+…∞, then the value of ppp is __________.

Correct answer: 9

Step-by-step solution →
Q86·Mathematics·Statistics and ProbabilityNumerical
A fair die is tossed repeatedly until a six is obtained. Let XXX denote the number of tosses required and let a=P(X=3)a=P(X=3)a=P(X=3), b=P(X≥3)b=P(X\ge 3)b=P(X≥3) and c=P(X≥6∣X>3)c=P(X\ge 6\mid X>3)c=P(X≥6∣X>3). Then b+ca\dfrac{b+c}{a}ab+c​ is equal to __________.

Correct answer: 12

Step-by-step solution →
Q87·Mathematics·Trigonometric FunctionsNumerical
Let the set of all a∈Ra\in\mathbb Ra∈R such that the equation cos⁡2x+asin⁡x=2a−7\cos 2x+a\sin x=2a-7cos2x+asinx=2a−7 has a solution be [p,q][p,q][p,q] and r=tan⁡9∘−tan⁡27∘−1cot⁡63∘+tan⁡81∘r=\tan 9^{\circ}-\tan 27^{\circ}-\dfrac{1}{\cot 63^{\circ}}+\tan 81^{\circ}r=tan9∘−tan27∘−cot63∘1​+tan81∘, then pqrpqrpqr is equal to __________.

Correct answer: 48

Step-by-step solution →
Q88·Mathematics·Limits and ContinuityNumerical
Let f(x)=x3+x2f′(1)+x f′′(2)+f′′′(3)f(x)=x^3+x^2 f'(1)+x\,f''(2)+f'''(3)f(x)=x3+x2f′(1)+xf′′(2)+f′′′(3), x∈Rx\in\mathbb Rx∈R. Then f′(10)f'(10)f′(10) is equal to __________.

Correct answer: 202

Step-by-step solution →
Q89·Mathematics·Matrices and DeterminantsNumerical
Let A=[201110101]A=\begin{bmatrix}2 & 0 & 1\\ 1 & 1 & 0\\ 1 & 0 & 1\end{bmatrix}A=​211​010​101​​, B=[B1,B2,B3]B=[B_1,B_2,B_3]B=[B1​,B2​,B3​], where B1,B2,B3B_1,B_2,B_3B1​,B2​,B3​ are column matrices, and AB1=[100]AB_1=\begin{bmatrix}1\\ 0\\ 0\end{bmatrix}AB1​=​100​​, AB2=[230]AB_2=\begin{bmatrix}2\\ 3\\ 0\end{bmatrix}AB2​=​230​​, AB3=[321]AB_3=\begin{bmatrix}3\\ 2\\ 1\end{bmatrix}AB3​=​321​​. If α=∣B∣\alpha=|B|α=∣B∣ and β\betaβ is the sum of all the diagonal elements of BBB, then α3+β3\alpha^3+\beta^3α3+β3 is equal to __________.

Correct answer: 28

Step-by-step solution →
Q90·Mathematics·Complex NumbersNumerical
If α\alphaα satisfies the equation x2+x+1=0x^2+x+1=0x2+x+1=0 and (1+α)7=A+Bα+Cα2(1+\alpha)^7=A+B\alpha+C\alpha^2(1+α)7=A+Bα+Cα2, A,B,C≥0A,B,C\ge 0A,B,C≥0, then 5(3A−2B−C)5(3A-2B-C)5(3A−2B−C) is equal to __________.

Correct answer: 5

Step-by-step solution →

Chapters tested in this paper

Open any chapter to practise every past-year question on that topic across all papers, and see how often it has actually appeared.

  • Properties of Solids and Liquids 172/186
  • Three Dimensional Geometry 176/186
  • Matrices and Determinants 180/186
  • Sets, Relations and Functions 165/186
  • Current Electricity 160/186
  • Sequence and Series 164/186
  • p-Block Elements 164/186
  • Definite Integration 168/186
  • Rotational Motion 172/186
  • Redox Reactions and Electrochemistry 177/186
  • Geometrical Optics 172/186
  • Kinematics 156/186
  • Vector Algebra 173/186
  • Differential Equations 167/186
  • Probability 176/186
  • Permutations and Combinations 162/186
  • Magnetic Field of Current 147/186
  • Binomial Theorem and Its Simple Applications 158/186
  • Electromagnetic Waves 144/186
  • Chemical Bonding and Molecular Structure 151/186
  • Limits and Continuity 149/186
  • d- and f-Block Elements 126/186
  • Thermodynamics 154/186
  • Equilibrium 163/186
  • Solutions 158/186
  • Laws of Motion 130/186
  • Chemical Thermodynamics 165/186
  • Units and Measurements 149/186
  • Hydrocarbons 126/186
  • Complex Numbers 165/186
  • Trigonometric Functions 144/186
  • Biomolecules 162/186
  • Chemical Kinetics 169/186
  • Gravitation 152/186
  • Electric Field and Coulomb's Law 133/186
  • Atomic Structure 161/186
  • Electronic Devices 145/186
  • Circles 142/186
  • Dual Nature of Matter and Radiation 155/186
  • Amines 133/186
  • Work, Energy and Power 132/186
  • Some Basic Concepts in Chemistry 129/186
  • Electromagnetic Induction 120/186
  • Area Under Curves 139/186
  • Kinetic Theory of Gases 135/186
  • Alcohols and Ethers 106/186
  • Oscillations 117/186
  • Nuclei 116/186
  • Straight Lines 114/186
  • Atoms 112/186
  • Classification of Elements and Periodicity in Properties 113/186
  • Statistics 118/186
  • Ellipse 103/186
  • Electronic Effects and Stability 74/186
  • Experimental Skills 68/186
  • Electric Potential 63/186
  • Isomerism 51/186
  • Aromaticity 22/186
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