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JEE Main 31 January 2024 Shift 2 Question Paper with Answers

31 January 2024 · January session · 88 questions

88 of the 90 questions from the JEE Main 31 January 2024 Shift 2 paper, each with its correct answer and tagged to the chapter it tests. Free to read, no account needed.

2 questions are held back from this paper while we re-check the transcription or the answer key. We would rather show you nothing than show you an answer we are not confident is right.

Physics
29
Chemistry
30
Mathematics
29

Physics — JEE Main 31 January 2024 Shift 2

Q1·Physics·Laws of MotionSingle correct
A light string passing over a smooth light fixed pulley connects two blocks of masses m1m_1m1​ and m2m_2m2​. If the acceleration of the system is g8\dfrac{g}{8}8g​, then the ratio of masses is
  1. (A)97\dfrac{9}{7}79​
  2. (B)81\dfrac{8}{1}18​
  3. (C)43\dfrac{4}{3}34​
  4. (D)53\dfrac{5}{3}35​

Correct answer: (A)

Step-by-step solution →
Q2·Physics·Magnetic Field of CurrentSingle correct
A uniform magnetic field of 2×10−32\times10^{-3}2×10−3 T acts along positive Y-direction. A rectangular loop of sides 20 cm and 10 cm with current of 5 A is in Y-Z plane. The current is in anticlockwise sense with reference to negative X axis. Magnitude and direction of the torque is
  1. (A)2×10−42\times10^{-4}2×10−4 N–m along positive Z-direction
  2. (B)2×10−42\times10^{-4}2×10−4 N–m along negative Z-direction
  3. (C)2×10−42\times10^{-4}2×10−4 N–m along positive X-direction
  4. (D)2×10−42\times10^{-4}2×10−4 N–m along positive Y-direction

Correct answer: (B)

Step-by-step solution →
Q3·Physics·Units and MeasurementsSingle correct
The measured value of the length of a simple pendulum is 20 cm with 2 mm accuracy. The time for 50 oscillations was measured to be 40 seconds with 1 second resolution. From these measurements, the accuracy in the measurement of acceleration due to gravity is N%. The value of N is:
  1. (A)4
  2. (B)8
  3. (C)6
  4. (D)5

Correct answer: (C)

Step-by-step solution →
Q4·Physics·Capacitors and DielectricsSingle correct
Force between two point charges q1q_1q1​ and q2q_2q2​ placed in vacuum at 'rrr' cm apart is F. Force between them when placed in a medium having dielectric K=5K=5K=5 at 'r/5r/5r/5' cm apart will be:
  1. (A)F25\dfrac{F}{25}25F​
  2. (B)5F
  3. (C)F5\dfrac{F}{5}5F​
  4. (D)25F

Correct answer: (B)

Step-by-step solution →
Q5·Physics·Alternating CurrentsSingle correct
An AC voltage V=20sin⁡200πtV=20\sin 200\pi tV=20sin200πt is applied to a series LCR circuit which drives a current I=10sin⁡(200πt+π3)I=10\sin\left(200\pi t+\dfrac{\pi}{3}\right)I=10sin(200πt+3π​). The average power dissipated is:
  1. (A)21.6 W
  2. (B)200 W
  3. (C)173.2 W
  4. (D)50 W

Correct answer: (D)

Step-by-step solution →
Q6·Physics·Geometrical OpticsSingle correct
When unpolarized light is incident at an angle of 60∘60^\circ60∘ on a transparent medium from air. The reflected ray is completely polarized. The angle of refraction in the medium is
  1. (A)30∘30^\circ30∘
  2. (B)60∘60^\circ60∘
  3. (C)90∘90^\circ90∘
  4. (D)45∘45^\circ45∘

Correct answer: (A)

Step-by-step solution →
Q7·Physics·WavesSingle correct
The speed of sound in oxygen at S.T.P. will be approximately: (Given, R=8.3 JK−1R=8.3\ \text{JK}^{-1}R=8.3 JK−1, γ=1.4\gamma=1.4γ=1.4)
  1. (A)310 m/s
  2. (B)333 m/s
  3. (C)341 m/s
  4. (D)325 m/s

Correct answer: (A)

Step-by-step solution →
Q8·Physics·Kinetic Theory of GasesSingle correct
A gas mixture consists of 8 moles of argon and 6 moles of oxygen at temperature T. Neglecting all vibrational modes, the total internal energy of the system is
  1. (A)29 RT
  2. (B)20 RT
  3. (C)27 RT
  4. (D)21 RT

Correct answer: (C)

Step-by-step solution →
Q9·Physics·Current ElectricitySingle correct
The resistance per centimeter of a meter bridge wire is rrr, with X ΩX\,\OmegaXΩ resistance in left gap. Balancing length from left end is at 40 cm with 25 Ω25\,\Omega25Ω resistance in right gap. If the wire is replaced by another wire of double the resistance per centimeter, the new balancing length from same settings will be at
  1. (A)20 cm
  2. (B)10 cm
  3. (C)80 cm
  4. (D)40 cm

Correct answer: (D)

Step-by-step solution →
Q10·Physics·Electromagnetic WavesSingle correct
Given below are two statements: Statement-I: Electromagnetic waves carry energy as they travel through space and this energy is equally shared by the electric and magnetic fields. Statement-II: When electromagnetic waves strike a surface, a pressure is exerted on the surface. In the light of the above statements, choose the most appropriate answer from the options given below:
  1. (A)Statement I is incorrect but Statement II is correct
  2. (B)Both Statement I and Statement II are correct.
  3. (C)Both Statement I and Statement II are incorrect.
  4. (D)Statement I is correct but Statement II is incorrect.

Correct answer: (B)

Step-by-step solution →
Q11·Physics·Dual Nature of Matter and RadiationSingle correct
In a photoelectric effect experiment a light of frequency 1.5 times the threshold frequency is made to fall on the surface of photosensitive material. Now if the frequency is halved and intensity is doubled, the number of photo electrons emitted will be:
  1. (A)Doubled
  2. (B)Quadrupled
  3. (C)Zero
  4. (D)Halved

Correct answer: (C)

Step-by-step solution →
Q12·Physics·Current ElectricitySingle correct
By what percentage will the illumination of the lamp decrease if the current drops by 20%?
  1. (A)46%
  2. (B)26%
  3. (C)36%
  4. (D)56%

Correct answer: (C)

Step-by-step solution →
Q13·Physics·KinematicsSingle correct
If two vectors A⃗\vec{A}A and B⃗\vec{B}B having equal magnitude R are inclined at an angle θ\thetaθ, then
  1. (A)∣A⃗−B⃗∣=2 Rsin⁡(θ2)\left|\vec{A}-\vec{B}\right|=\sqrt{2}\,R\sin\left(\dfrac{\theta}{2}\right)​A−B​=2​Rsin(2θ​)
  2. (B)∣A⃗+B⃗∣=2Rsin⁡(θ2)\left|\vec{A}+\vec{B}\right|=2R\sin\left(\dfrac{\theta}{2}\right)​A+B​=2Rsin(2θ​)
  3. (C)∣A⃗+B⃗∣=2Rcos⁡(θ2)\left|\vec{A}+\vec{B}\right|=2R\cos\left(\dfrac{\theta}{2}\right)​A+B​=2Rcos(2θ​)
  4. (D)∣A⃗−B⃗∣=2Rcos⁡(θ2)\left|\vec{A}-\vec{B}\right|=2R\cos\left(\dfrac{\theta}{2}\right)​A−B​=2Rcos(2θ​)

Correct answer: (C)

Step-by-step solution →
Q14·Physics·Atoms and NucleiSingle correct
The mass number of nucleus having radius equal to half of the radius of nucleus with mass number 192 is:
  1. (A)24
  2. (B)32
  3. (C)40
  4. (D)20

Correct answer: (A)

Step-by-step solution →
Q15·Physics·GravitationSingle correct
The mass of the moon is 1144\dfrac{1}{144}1441​ times the mass of a planet and its diameter is 116\dfrac{1}{16}161​ times the diameter of a planet. If the escape velocity on the planet is vvv, the escape velocity on the moon will be:
  1. (A)v4\dfrac{v}{4}4v​
  2. (B)v3\dfrac{v}{3}3v​
  3. (C)v12\dfrac{v}{12}12v​
  4. (D)v6\dfrac{v}{6}6v​

Correct answer: (B)

Step-by-step solution →
Q16·Physics·Properties of Solids and LiquidsSingle correct
A small spherical ball of radius rrr, falling through a viscous medium of negligible density has terminal velocity vvv. Another ball of the same mass but of radius 2r2r2r, falling through the same viscous medium will have terminal velocity:
  1. (A)v2\dfrac{v}{2}2v​
  2. (B)v4\dfrac{v}{4}4v​
  3. (C)4v4v4v
  4. (D)2v2v2v

Correct answer: (A)

Step-by-step solution →
Q17·Physics·Work, Energy and PowerSingle correct
A body of mass 2 kg begins to move under the action of a time dependent force given by F⃗=(6t i^+6t2 j^)\vec{F}=\left(6t\,\hat{i}+6t^2\,\hat{j}\right)F=(6ti^+6t2j^​) N. The power developed by the force at the time ttt is given by
  1. (A)(6t4+9t5)\left(6t^4+9t^5\right)(6t4+9t5) W
  2. (B)(3t3+6t5)\left(3t^3+6t^5\right)(3t3+6t5) W
  3. (C)(9t5+6t3)\left(9t^5+6t^3\right)(9t5+6t3) W
  4. (D)(9t3+6t5)\left(9t^3+6t^5\right)(9t3+6t5) W

Correct answer: (D)

Step-by-step solution →
Q18·Physics·Electronic DevicesSingle correct
The output of the given circuit diagram (shown in the figure) is
  1. (A)A,B,Y: (0,0)→0, (1,0)→0, (0,1)→0, (1,1)→1
  2. (B)A,B,Y: (0,0)→0, (1,0)→1, (0,1)→1, (1,1)→0
  3. (C)A,B,Y: (0,0)→0, (1,0)→0, (0,1)→0, (1,1)→0
  4. (D)A,B,Y: (0,0)→0, (1,0)→0, (0,1)→1, (1,1)→0

Correct answer: (C)

Step-by-step solution →
Q19·Physics·Units and MeasurementsSingle correct
Consider two physical quantities A and B related to each other as E=B−x2AtE=\dfrac{B-x^2}{At}E=AtB−x2​ where E, xxx and ttt have dimensions of energy, length and time respectively. The dimension of AB is
  1. (A)L−2M1T0L^{-2}M^1T^0L−2M1T0
  2. (B)L2M−1T1L^2M^{-1}T^1L2M−1T1
  3. (C)L−2M−1T1L^{-2}M^{-1}T^1L−2M−1T1
  4. (D)L0M1T−1L^0M^1T^{-1}L0M1T−1

Correct answer: (B)

Step-by-step solution →
Q20·Physics·Current ElectricityNumerical
In the following circuit, the battery has an emf of 2 V and an internal resistance of 23 Ω\dfrac{2}{3}\,\Omega32​Ω. The power consumption in the entire circuit is ______ W.

Correct answer: 3

Step-by-step solution →
Q21·Physics·Geometrical OpticsNumerical
Light from a point source in air falls on a convex curved surface of radius 20 cm and refractive index 1.5. If the source is located at 100 cm from the convex surface, the image will be formed at ______ cm from the object.

Correct answer: 200

Step-by-step solution →
Q22·Physics·Electromagnetic InductionNumerical
The magnetic flux ϕ\phiϕ (in weber) linked with a closed circuit of resistance 8 Ω8\,\Omega8Ω varies with time (in seconds) as ϕ=5t2−36t+1\phi=5t^2-36t+1ϕ=5t2−36t+1. The induced current in the circuit at t=2t=2t=2 s is ______ A.

Correct answer: 2

Step-by-step solution →
Q23·Physics·Properties of Solids and LiquidsNumerical
Two blocks of mass 2 kg and 4 kg are connected by a metal wire going over a smooth pulley as shown in figure. The radius of wire is 4.0×10−54.0\times10^{-5}4.0×10−5 m and Young's modulus of the metal 2.0×10112.0\times10^{11}2.0×1011 N/m2^22. The longitudinal strain developed in the wire is 1απ\dfrac{1}{\alpha\pi}απ1​. The value of α\alphaα is ______. [Use g=10 m/s2g=10\ \text{m/s}^2g=10 m/s2]

Correct answer: 12

Step-by-step solution →
Q24·Physics·Rotational MotionNumerical
A body of mass 'mmm' is projected with a speed 'uuu' making an angle of 45∘45^\circ45∘ with the ground. The angular momentum of the body about the point of projection, at the highest point is expressed as 2 mu3Xg\dfrac{\sqrt{2}\,mu^3}{Xg}Xg2​mu3​. The value of 'XXX' is ______.

Correct answer: 8

Step-by-step solution →
Q25·Physics·Magnetic Field of CurrentNumerical
Two circular coils P and Q of 100 turns each have same radius of π\piπ cm. The currents in P and Q are 1 A and 2 A respectively. P and Q are placed with their planes mutually perpendicular with their centers coincide. The resultant magnetic field induction at the center of the coils is x\sqrt{x}x​ mT, where x=x=x= ______. [Use μ0=4π×10−7\mu_0=4\pi\times10^{-7}μ0​=4π×10−7 T A m−1^{-1}−1]

Correct answer: 20

Step-by-step solution →
Q26·Physics·Electric PotentialNumerical
The distance between charges +q+q+q and −q-q−q is 2ℓ2\ell2ℓ and between +2q+2q+2q and −2q-2q−2q is 4ℓ4\ell4ℓ. The electrostatic potential at point P at a distance rrr from centre O is −αqℓr2×109-\alpha\dfrac{q\ell}{r^2}\times10^9−αr2qℓ​×109 V, where the value of α\alphaα is ______. (Use 14πε0=9×109\dfrac{1}{4\pi\varepsilon_0}=9\times10^94πε0​1​=9×109 Nm2^22C−2^{-2}−2)

Correct answer: 27

Step-by-step solution →
Q27·Physics·Rotational MotionNumerical
Two identical spheres each of mass 2 kg and radius 50 cm are fixed at the ends of a light rod so that the separation between the centers is 150 cm. Then, moment of inertia of the system about an axis perpendicular to the rod and passing through its middle point is x20\dfrac{x}{20}20x​ kg m2^22, where the value of xxx is ______.

Correct answer: 53

Step-by-step solution →
Q28·Physics·OscillationsNumerical
The time period of simple harmonic motion of mass M in the given figure is παM5K\pi\sqrt{\dfrac{\alpha M}{5K}}π5KαM​​, where the value of α\alphaα is ______.

Correct answer: 12

Step-by-step solution →
Q29·Physics·Atoms and NucleiNumerical
A nucleus has mass number A1A_1A1​ and volume V1V_1V1​. Another nucleus has mass number A2A_2A2​ and volume V2V_2V2​. If relation between mass number is A2=4A1A_2=4A_1A2​=4A1​, then V2V1=\dfrac{V_2}{V_1}=V1​V2​​= ______.

Correct answer: 4

Step-by-step solution →

Chemistry — JEE Main 31 January 2024 Shift 2

Q30·Chemistry·Coordination CompoundsSingle correct
Match List I with List II. Choose the correct answer from the options given below:
List-I (Complex ion)List-II (Electronic Configuration)
A.[Cr(H2O)6]3+[Cr(H_2O)_6]^{3+}[Cr(H2​O)6​]3+I.t2g2eg0t_{2g}^{2}e_g^{0}t2g2​eg0​
B.[Fe(H2O)6]3+[Fe(H_2O)_6]^{3+}[Fe(H2​O)6​]3+II.t2g3eg0t_{2g}^{3}e_g^{0}t2g3​eg0​
C.[Ni(H2O)6]2+[Ni(H_2O)_6]^{2+}[Ni(H2​O)6​]2+III.t2g3eg2t_{2g}^{3}e_g^{2}t2g3​eg2​
D.[V(H2O)6]3+[V(H_2O)_6]^{3+}[V(H2​O)6​]3+IV.t2g6eg2t_{2g}^{6}e_g^{2}t2g6​eg2​
  1. (A)A-III, B-II, C-IV, D-I
  2. (B)A-IV, B-I, C-II, D-III
  3. (C)A-IV, B-III, C-II, D-I
  4. (D)A-II, B-III, C-IV, D-I

Correct answer: (D)

Step-by-step solution →
Q31·Chemistry·Some Basic Concepts in ChemistrySingle correct
A sample of CaCO3_33​ and MgCO3_33​ weighed 2.21 g is ignited to constant weight of 1.152 g. The composition of mixture is: (Given molar mass in g mol−1^{-1}−1 CaCO3_33​:100, MgCO3_33​:84)
  1. (A)1.187 g CaCO3_33​ + 1.023 g MgCO3_33​
  2. (B)1.023 g CaCO3_33​ + 1.023 g MgCO3_33​
  3. (C)1.187 g CaCO3_33​ + 1.187 g MgCO3_33​
  4. (D)1.023 g CaCO3_33​ + 1.187 g MgCO3_33​

Correct answer: (A)

Step-by-step solution →
Q32·Chemistry·AminesSingle correct
Identify A and B in the following reaction sequence (shown in the figure).
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (A)

Step-by-step solution →
Q33·Chemistry·Redox Reactions and ElectrochemistrySingle correct
Given below are two statements: Statement-I: S8S_8S8​ solid undergoes disproportionation reaction under alkaline conditions to form S2−S^{2-}S2− and S2O32−S_2O_3^{2-}S2​O32−​. Statement-II: ClO4−ClO_4^-ClO4−​ can undergo disproportionation reaction under acidic condition. In the light of the above statements, choose the most appropriate answer from the options given below:
  1. (A)Statement I is correct but statement II is incorrect.
  2. (B)Statement I is incorrect but statement II is correct
  3. (C)Both Statement I and Statement II are incorrect
  4. (D)Both Statement I and statement II are correct

Correct answer: (A)

Step-by-step solution →
Q34·Chemistry·Aldehydes and KetonesSingle correct
Identify major product 'P' formed in the following reaction (shown in the figure).
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (D)

Step-by-step solution →
Q35·Chemistry·HydrocarbonsMultiple correct
Major product of the following reaction is (shown in the figure).
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (C), (D)

Step-by-step solution →
Q36·Chemistry·IUPAC NomenclatureSingle correct
Identify structure of 2,3-dibromo-1-phenylpentane (from the structures shown in the figure).
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (C)

Step-by-step solution →
Q37·Chemistry·Coordination CompoundsSingle correct
Select the option with correct property -
  1. (A)[Ni(CO)4][Ni(CO)_4][Ni(CO)4​] and [NiCl4]2−[NiCl_4]^{2-}[NiCl4​]2− both diamagnetic
  2. (B)[Ni(CO)4][Ni(CO)_4][Ni(CO)4​] and [NiCl4]2−[NiCl_4]^{2-}[NiCl4​]2− both paramagnetic
  3. (C)[NiCl4]2−[NiCl_4]^{2-}[NiCl4​]2− diamagnetic, [Ni(CO)4][Ni(CO)_4][Ni(CO)4​] paramagnetic
  4. (D)[Ni(CO)4][Ni(CO)_4][Ni(CO)4​] diamagnetic, [NiCl4]2−[NiCl_4]^{2-}[NiCl4​]2− paramagnetic

Correct answer: (D)

Step-by-step solution →
Q38·Chemistry·Diazonium Salts and ReactionsSingle correct
The azo-dye (Y) formed in the following reactions is (shown in the figure).
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (D)

Step-by-step solution →
Q39·Chemistry·AminesSingle correct
Given below are two statements: Statement-I: Aniline reacts with conc. H2_22​SO4_44​ followed by heating at 453-473 K gives p-aminobenzene sulphonic acid, which gives blood red colour in the 'Lassaigne's test'. Statement-II: In Friedel-Crafts alkylation and acylation reactions, aniline forms salt with the AlCl3_33​ catalyst. Due to this, nitrogen of aniline acquires a positive charge and acts as deactivating group. In the light of the above statements, choose the correct answer from the options given below:
  1. (A)Statement I is false but statement II is true
  2. (B)Both statement I and statement II are false
  3. (C)Statement I is true but statement II is false
  4. (D)Both statement I and statement II are true

Correct answer: (D)

Step-by-step solution →
Q40·Chemistry·EquilibriumSingle correct
A(g)⇌B(g)+C2(g)A_{(g)}\rightleftharpoons B_{(g)}+\dfrac{C}{2}_{(g)}A(g)​⇌B(g)​+2C​(g)​. The correct relationship between KPK_PKP​ and equilibrium pressure P is
  1. (A)KP=α3/2P1/2(2+α)1/2K_P=\dfrac{\alpha^{3/2}P^{1/2}}{(2+\alpha)^{1/2}}KP​=(2+α)1/2α3/2P1/2​
  2. (B)KP=α3/2P1/2(2+α)1/2(1−α)K_P=\dfrac{\alpha^{3/2}P^{1/2}}{(2+\alpha)^{1/2}(1-\alpha)}KP​=(2+α)1/2(1−α)α3/2P1/2​
  3. (C)KP=α1/2P3/2(2+α)3/2K_P=\dfrac{\alpha^{1/2}P^{3/2}}{(2+\alpha)^{3/2}}KP​=(2+α)3/2α1/2P3/2​
  4. (D)KP=α1/2P1/2(2+α)3/2K_P=\dfrac{\alpha^{1/2}P^{1/2}}{(2+\alpha)^{3/2}}KP​=(2+α)3/2α1/2P1/2​

Correct answer: (B)

Step-by-step solution →
Q41·Chemistry·p-Block ElementsSingle correct
Choose the correct statements from the following A. All group 16 elements form oxides of general formula EO2EO_2EO2​ and EO3EO_3EO3​ where E = S, Se, Te and Po. Both the types of oxides are acidic in nature. B. TeO2TeO_2TeO2​ is an oxidising agent while SO2SO_2SO2​ is reducing in nature. C. The reducing property decreases from H2SH_2SH2​S to H2TeH_2TeH2​Te down the group. D. The ozone molecule contains five lone pairs of electrons. Choose the correct answer from the options given below:
  1. (A)A and D only
  2. (B)B and C only
  3. (C)C and D only
  4. (D)A and B only

Correct answer: (D)

Step-by-step solution →
Q42·Chemistry·Aldehydes and KetonesSingle correct
Identify the name of the following reaction (shown in the figure).
  1. (A)Stephen reaction
  2. (B)Etard reaction
  3. (C)Gatterman-Koch reaction
  4. (D)Rosenmund reaction

Correct answer: (C)

Step-by-step solution →
Q43·Chemistry·Chemical Bonding and Molecular StructureSingle correct
Which of the following is least ionic?
  1. (A)BaCl2BaCl_2BaCl2​
  2. (B)AgClAgClAgCl
  3. (C)KClKClKCl
  4. (D)CoCl2CoCl_2CoCl2​

Correct answer: (B)

Step-by-step solution →
Q44·Chemistry·Purification and Characterisation of Organic CompoundsSingle correct
The fragrance of flowers is due to the presence of some volatile organic compounds called essential oils. These are generally insoluble in water at room temperature but are miscible with water vapour in vapour phase. A suitable method for the extraction of these oils from the flowers is:
  1. (A)crystallisation
  2. (B)distillation under reduced pressure
  3. (C)distillation
  4. (D)steam distillation

Correct answer: (D)

Step-by-step solution →
Q45·Chemistry·p-Block ElementsSingle correct
Given below are two statements: Statement-I: Group 13 trivalent halides easily get hydrolyzed by water due to their covalent nature. Statement-II: AlCl3AlCl_3AlCl3​ upon hydrolysis in acidified aqueous solution forms octahedral [Al(H2O)6]3+[Al(H_2O)_6]^{3+}[Al(H2​O)6​]3+ ion. In the light of the above statements, choose the correct answer from the options given below:
  1. (A)Statement I is true but Statement II is false
  2. (B)Statement I is false but Statement II is true
  3. (C)Both statement I and statement II are false
  4. (D)Both statement I and statement II are true

Correct answer: (D)

Step-by-step solution →
Q46·Chemistry·Atomic StructureSingle correct
The four quantum numbers for the electron in the outer most orbital of potassium (atomic no. 19) are
  1. (A)n=4, ℓ=2, m=−1, s=+12n=4,\ \ell=2,\ m=-1,\ s=+\dfrac{1}{2}n=4, ℓ=2, m=−1, s=+21​
  2. (B)n=4, ℓ=0, m=0, s=+12n=4,\ \ell=0,\ m=0,\ s=+\dfrac{1}{2}n=4, ℓ=0, m=0, s=+21​
  3. (C)n=3, ℓ=0, m=0, s=+12n=3,\ \ell=0,\ m=0,\ s=+\dfrac{1}{2}n=3, ℓ=0, m=0, s=+21​
  4. (D)n=2, ℓ=0, m=0, s=+12n=2,\ \ell=0,\ m=0,\ s=+\dfrac{1}{2}n=2, ℓ=0, m=0, s=+21​

Correct answer: (B)

Step-by-step solution →
Q47·Chemistry·d- and f-Block ElementsSingle correct
Choose the correct statements from the following A. Mn2O7Mn_2O_7Mn2​O7​ is an oil at room temperature B. V2O4V_2O_4V2​O4​ reacts with acid to give VO2+VO_2^+VO2+​ C. CrOCrOCrO is a basic oxide D. V2O5V_2O_5V2​O5​ does not react with acid Choose the correct answer from the options given below:
  1. (A)A, B and D only
  2. (B)A and C only
  3. (C)A, B and C only
  4. (D)B and C only

Correct answer: (B)

Step-by-step solution →
Q48·Chemistry·Electronic Effects and StabilitySingle correct
The correct order of reactivity in electrophilic substitution reaction of the following compounds (A: benzene, B: methylbenzene, C: chlorobenzene, D: nitrobenzene, shown in the figure) is:
  1. (A)B > C > A > D
  2. (B)D > C > B > A
  3. (C)A > B > C > D
  4. (D)B > A > C > D

Correct answer: (D)

Step-by-step solution →
Q49·Chemistry·Classification of Elements and Periodicity in PropertiesSingle correct
Consider the following elements: A′A'A′ and B′B'B′ are adjacent elements in the same period (with A′A'A′ to the left of B′B'B′), and C′C'C′ and D′D'D′ lie directly below A′A'A′ and B′B'B′ respectively in the next period. Which of the following is/are true about A′A'A′, B′B'B′, C′C'C′ and D′D'D′? A. Order of atomic radii: B′<A′<D′<C′B'<A'<D'<C'B′<A′<D′<C′ B. Order of metallic character: B′<A′<D′<C′B'<A'<D'<C'B′<A′<D′<C′ C. Size of the element: D′<C′<B′<A′D'<C'<B'<A'D′<C′<B′<A′ D. Order of ionic radii: B′+<A′+<D′+<C′+B'^+<A'^+<D'^+<C'^+B′+<A′+<D′+<C′+ Choose the correct answer from the options given below:
  1. (A)A only
  2. (B)A, B and D only
  3. (C)A and B only
  4. (D)B, C and D only

Correct answer: (B)

Step-by-step solution →
Q50·Chemistry·Chemical Bonding and Molecular StructureNumerical
A diatomic molecule has a dipole moment of 1.2 D. If the bond distance is 1 A˚1\,\text{\AA}1A˚, then fractional charge on each atom is ______ ×10−1\times10^{-1}×10−1 esu. (Given 1 D=10−181\,D=10^{-18}1D=10−18 esu cm)

Correct answer: 0

Step-by-step solution →
Q51·Chemistry·Chemical KineticsNumerical
r=k[A]r=k[A]r=k[A] for a reaction, 50% of A is decomposed in 120 minutes. The time taken for 90% decomposition of A is ______ minutes.

Correct answer: 399

Step-by-step solution →
Q52·Chemistry·AminesNumerical
A compound (x) with molar mass 108 g mol−1^{-1}−1 undergoes acetylation to give product with molar mass 192 g mol−1^{-1}−1. The number of amino groups in the compound (x) is ______.

Correct answer: 2

Step-by-step solution →
Q53·Chemistry·Organic Compounds Containing HalogensNumerical
Number of isomeric products formed by mono-chlorination of 2-methylbutane in presence of sunlight is ______.

Correct answer: 6

Step-by-step solution →
Q54·Chemistry·Redox Reactions and ElectrochemistryNumerical
Number of moles of H+H^+H+ ions required by 1 mole of MnO4−MnO_4^-MnO4−​ to oxidise oxalate ion to CO2CO_2CO2​ is ______.

Correct answer: 8

Step-by-step solution →
Q55·Chemistry·d- and f-Block ElementsNumerical
In the reaction of potassium dichromate, potassium chloride and sulfuric acid (conc.), the oxidation state of the chromium in the product is (+)(+)(+) ______.

Correct answer: 6

Step-by-step solution →
Q56·Chemistry·Some Basic Concepts in ChemistryNumerical
The molarity of 1 L orthophosphoric acid (H3PO4H_3PO_4H3​PO4​) having 70% purity by weight (specific gravity 1.54 g cm−3^{-3}−3) is ______ M. (Molar mass of H3PO4=98H_3PO_4=98H3​PO4​=98 g mol−1^{-1}−1)

Correct answer: 11

Step-by-step solution →
Q57·Chemistry·Solid StateNumerical
The values of conductivity of some materials at 298.15 K in S m−1^{-1}−1 are 2.1×1032.1\times10^32.1×103, 1.2×101.2\times101.2×10, 3.91, 1.5×10−21.5\times10^{-2}1.5×10−2, 1×10−71\times10^{-7}1×10−7, 1.0×1031.0\times10^31.0×103. The number of conductors among the materials is ______.

Correct answer: 4

Step-by-step solution →
Q58·Chemistry·BiomoleculesNumerical
From the vitamins A, B1B_1B1​, B6B_6B6​, B12B_{12}B12​, C, D, E and K, the number of vitamins that can be stored in our body is ______.

Correct answer: 5

Step-by-step solution →
Q59·Chemistry·Chemical ThermodynamicsNumerical
If 5 moles of an ideal gas expands from 10 L to a volume of 100 L at 300 K under isothermal and reversible condition then work, www, is −x-x−x J. The value of xxx is ______. (Given R=8.314R=8.314R=8.314 J K−1^{-1}−1mol−1^{-1}−1)

Correct answer: 28721

Step-by-step solution →

Mathematics — JEE Main 31 January 2024 Shift 2

Q60·Mathematics·Permutations and CombinationsSingle correct
The number of ways in which 21 identical apples can be distributed among three children such that each child gets at least 2 apples, is
  1. (A)406
  2. (B)130
  3. (C)142
  4. (D)136

Correct answer: (D)

Step-by-step solution →
Q61·Mathematics·Straight LinesSingle correct
Let A(aaa, bbb), B(3, 4) and C(−6-6−6, −8-8−8) respectively denote the centroid, circumcentre and orthocentre of a triangle. Then, the distance of the point P(2a+32a+32a+3, 7b+57b+57b+5) from the line 2x+3y−4=02x+3y-4=02x+3y−4=0 measured parallel to the line x−2y−1=0x-2y-1=0x−2y−1=0 is
  1. (A)1557\dfrac{15\sqrt{5}}{7}7155​​
  2. (B)1756\dfrac{17\sqrt{5}}{6}6175​​
  3. (C)1757\dfrac{17\sqrt{5}}{7}7175​​
  4. (D)4517\dfrac{4\sqrt{5}}{17}1745​​

Correct answer: (C)

Step-by-step solution →
Q62·Mathematics·Complex NumbersSingle correct
Let z1z_1z1​ and z2z_2z2​ be two complex numbers such that z1+z2=5z_1+z_2=5z1​+z2​=5 and z13+z23=20+15iz_1^3+z_2^3=20+15iz13​+z23​=20+15i. Then ∣z14+z24∣\left|z_1^4+z_2^4\right|​z14​+z24​​ equals
  1. (A)30330\sqrt{3}303​
  2. (B)757575
  3. (C)151515\sqrt{15}1515​
  4. (D)25325\sqrt{3}253​

Correct answer: (B)

Step-by-step solution →
Q63·Mathematics·CirclesSingle correct
Let a variable line passing through the centre of the circle x2+y2−16x−4y=0x^2+y^2-16x-4y=0x2+y2−16x−4y=0, meet the positive co-ordinate axes at the points A and B. Then the minimum value of OA+OBOA+OBOA+OB, where O is the origin, is equal to
  1. (A)12
  2. (B)18
  3. (C)20
  4. (D)24

Correct answer: (B)

Step-by-step solution →
Q64·Mathematics·Three Dimensional GeometrySingle correct
Let (α,β,γ)(\alpha,\beta,\gamma)(α,β,γ) be the mirror image of the point (2,3,5)(2,3,5)(2,3,5) in the line x−12=y−23=z−34\dfrac{x-1}{2}=\dfrac{y-2}{3}=\dfrac{z-3}{4}2x−1​=3y−2​=4z−3​. Then 2α+3β+4γ2\alpha+3\beta+4\gamma2α+3β+4γ is equal to
  1. (A)32
  2. (B)33
  3. (C)31
  4. (D)34

Correct answer: (B)

Step-by-step solution →
Q65·Mathematics·ParabolaSingle correct
Let P be a parabola with vertex (2,3)(2,3)(2,3) and directrix 2x+y=62x+y=62x+y=6. Let an ellipse E:x2a2+y2b2=1E:\dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}=1E:a2x2​+b2y2​=1, a>ba>ba>b, of eccentricity 12\dfrac{1}{\sqrt{2}}2​1​ pass through the focus of the parabola P. Then the square of the length of the latus rectum of E, is
  1. (A)3858\dfrac{385}{8}8385​
  2. (B)3478\dfrac{347}{8}8347​
  3. (C)51225\dfrac{512}{25}25512​
  4. (D)65625\dfrac{656}{25}25656​

Correct answer: (D)

Step-by-step solution →
Q66·Mathematics·Differential EquationsSingle correct
The temperature T(t)T(t)T(t) of a body at time t=0t=0t=0 is 160∘160^\circ160∘F and it decreases continuously as per the differential equation dTdt=−K(T−80)\dfrac{dT}{dt}=-K(T-80)dtdT​=−K(T−80), where K is a positive constant. If T(15)=120∘T(15)=120^\circT(15)=120∘F, then T(45)T(45)T(45) is equal to
  1. (A)85∘85^\circ85∘F
  2. (B)95∘95^\circ95∘F
  3. (C)90∘90^\circ90∘F
  4. (D)80∘80^\circ80∘F

Correct answer: (C)

Step-by-step solution →
Q67·Mathematics·Sequence and SeriesSingle correct
Let 2nd2^{\text{nd}}2nd, 8th8^{\text{th}}8th and 44th44^{\text{th}}44th terms of a non-constant A.P. be respectively the 1st1^{\text{st}}1st, 2nd2^{\text{nd}}2nd and 3rd3^{\text{rd}}3rd terms of G.P. If the first term of A.P. is 1, then the sum of first 20 terms is equal to
  1. (A)980
  2. (B)960
  3. (C)990
  4. (D)970

Correct answer: (D)

Step-by-step solution →
Q68·Mathematics·Limits and ContinuitySingle correct
Let f:R→(0,∞)f:R\to(0,\infty)f:R→(0,∞) be strictly increasing function such that lim⁡x→∞f(7x)f(x)=1\displaystyle\lim_{x\to\infty}\dfrac{f(7x)}{f(x)}=1x→∞lim​f(x)f(7x)​=1. Then the value of lim⁡x→∞[f(5x)f(x)−1]\displaystyle\lim_{x\to\infty}\left[\dfrac{f(5x)}{f(x)}-1\right]x→∞lim​[f(x)f(5x)​−1] is equal to
  1. (A)4
  2. (B)0
  3. (C)75\dfrac{7}{5}57​
  4. (D)1

Correct answer: (B)

Step-by-step solution →
Q69·Mathematics·Area Under CurvesSingle correct
The area of the region enclosed by the parabola y=4x−x2y=4x-x^2y=4x−x2 and 3y=(x−4)23y=(x-4)^23y=(x−4)2 is equal to
  1. (A)329\dfrac{32}{9}932​
  2. (B)4
  3. (C)6
  4. (D)143\dfrac{14}{3}314​

Correct answer: (C)

Step-by-step solution →
Q70·Mathematics·Statistics and ProbabilitySingle correct
Let the mean and the variance of 6 observations aaa, bbb, 68, 44, 48, 60 be 55 and 194, respectively. If a>ba>ba>b, then a+3ba+3ba+3b is
  1. (A)200
  2. (B)190
  3. (C)180
  4. (D)210

Correct answer: (C)

Step-by-step solution →
Q71·Mathematics·Limits and ContinuitySingle correct
If the function f:(−∞,−1]→(a,b]f:(-\infty,-1]\to(a,b]f:(−∞,−1]→(a,b] defined by f(x)=ex3−3x+1f(x)=e^{x^3-3x+1}f(x)=ex3−3x+1 is one-one and onto, then the distance of the point P(2b+4, a+2)P(2b+4,\ a+2)P(2b+4, a+2) from the line x+e−3y=4x+e^{-3}y=4x+e−3y=4 is
  1. (A)21+e62\sqrt{1+e^6}21+e6​
  2. (B)41+e64\sqrt{1+e^6}41+e6​
  3. (C)31+e63\sqrt{1+e^6}31+e6​
  4. (D)1+e6\sqrt{1+e^6}1+e6​

Correct answer: (A)

Step-by-step solution →
Q72·Mathematics·Limits and ContinuitySingle correct
Consider the function f:(0,∞)→Rf:(0,\infty)\to Rf:(0,∞)→R defined by f(x)=e−∣log⁡ex∣f(x)=e^{-\left|\log_e x\right|}f(x)=e−∣loge​x∣. If mmm and nnn be respectively the number of points at which fff is not continuous and fff is not differentiable, then m+nm+nm+n is
  1. (A)0
  2. (B)3
  3. (C)1
  4. (D)2

Correct answer: (C)

Step-by-step solution →
Q73·Mathematics·Trigonometric FunctionsSingle correct
The number of solutions, of the equation esin⁡x−2e−sin⁡x=2e^{\sin x}-2e^{-\sin x}=2esinx−2e−sinx=2 is
  1. (A)2
  2. (B)more than 2
  3. (C)1
  4. (D)0

Correct answer: (D)

Step-by-step solution →
Q74·Mathematics·Inverse Trigonometric FunctionsSingle correct
If a=sin⁡−1(sin⁡(5))a=\sin^{-1}(\sin(5))a=sin−1(sin(5)) and b=cos⁡−1(cos⁡(5))b=\cos^{-1}(\cos(5))b=cos−1(cos(5)), then a2+b2a^2+b^2a2+b2 is equal to
  1. (A)4π2+254\pi^2+254π2+25
  2. (B)8π2−40π+508\pi^2-40\pi+508π2−40π+50
  3. (C)4π2−20π+504\pi^2-20\pi+504π2−20π+50
  4. (D)25

Correct answer: (B)

Step-by-step solution →
Q75·Mathematics·Permutations and CombinationsSingle correct
If for some mmm, nnn;  6Cm+2(6Cm+1)+ 6Cm+2> 8C3\ ^6C_m+2\left(^6C_{m+1}\right)+\ ^6C_{m+2}>\ ^8C_3 6Cm​+2(6Cm+1​)+ 6Cm+2​> 8C3​ and  n−1P3: nP4=1:8\ ^{n-1}P_3:\ ^nP_4=1:8 n−1P3​: nP4​=1:8, then  nPm+1+ n+1Cm\ ^nP_{m+1}+\ ^{n+1}C_m nPm+1​+ n+1Cm​ is equal to
  1. (A)380
  2. (B)376
  3. (C)384
  4. (D)372

Correct answer: (D)

Step-by-step solution →
Q76·Mathematics·Statistics and ProbabilitySingle correct
A coin is biased so that a head is twice as likely to occur as a tail. If the coin is tossed 3 times, then the probability of getting two tails and one head is
  1. (A)29\dfrac{2}{9}92​
  2. (B)19\dfrac{1}{9}91​
  3. (C)227\dfrac{2}{27}272​
  4. (D)127\dfrac{1}{27}271​

Correct answer: (A)

Step-by-step solution →
Q77·Mathematics·Matrices and DeterminantsSingle correct
Let A be a 3×33\times33×3 real matrix such that A(101)=2(101)A\begin{pmatrix}1\\0\\1\end{pmatrix}=2\begin{pmatrix}1\\0\\1\end{pmatrix}A​101​​=2​101​​, A(−101)=4(−101)A\begin{pmatrix}-1\\0\\1\end{pmatrix}=4\begin{pmatrix}-1\\0\\1\end{pmatrix}A​−101​​=4​−101​​, A(010)=2(010)A\begin{pmatrix}0\\1\\0\end{pmatrix}=2\begin{pmatrix}0\\1\\0\end{pmatrix}A​010​​=2​010​​. Then, the system (A−3I)(xyz)=(123)(A-3I)\begin{pmatrix}x\\y\\z\end{pmatrix}=\begin{pmatrix}1\\2\\3\end{pmatrix}(A−3I)​xyz​​=​123​​ has
  1. (A)unique solution
  2. (B)exactly two solutions
  3. (C)no solution
  4. (D)infinitely many solutions

Correct answer: (A)

Step-by-step solution →
Q78·Mathematics·Three Dimensional GeometrySingle correct
The shortest distance between lines L1L_1L1​ and L2L_2L2​, where L1:x−12=y+1−3=z+42L_1:\dfrac{x-1}{2}=\dfrac{y+1}{-3}=\dfrac{z+4}{2}L1​:2x−1​=−3y+1​=2z+4​ and L2L_2L2​ is the line passing through the points A(−4,4,3)A(-4,4,3)A(−4,4,3), B(−1,6,3)B(-1,6,3)B(−1,6,3) and perpendicular to the line x−3−2=y3=z−11\dfrac{x-3}{-2}=\dfrac{y}{3}=\dfrac{z-1}{1}−2x−3​=3y​=1z−1​, is
  1. (A)121221\dfrac{121}{\sqrt{221}}221​121​
  2. (B)24117\dfrac{24}{\sqrt{117}}117​24​
  3. (C)141221\dfrac{141}{\sqrt{221}}221​141​
  4. (D)42117\dfrac{42}{\sqrt{117}}117​42​

Correct answer: (C)

Step-by-step solution →
Q79·Mathematics·Definite IntegrationNumerical
∣120π3∫0πx2sin⁡xcos⁡xsin⁡4x+cos⁡4x dx∣\left|\dfrac{120}{\pi^3}\displaystyle\int_0^{\pi}\dfrac{x^2\sin x\cos x}{\sin^4 x+\cos^4 x}\,dx\right|​π3120​∫0π​sin4x+cos4xx2sinxcosx​dx​ is equal to ______.

Correct answer: 15

Step-by-step solution →
Q80·Mathematics·Quadratic EquationsNumerical
Let aaa, bbb, ccc be the length of three sides of a triangle satisfying the condition (a2+b2)x2−2b(a+c)x+(b2+c2)=0(a^2+b^2)x^2-2b(a+c)x+(b^2+c^2)=0(a2+b2)x2−2b(a+c)x+(b2+c2)=0. If the set of all possible values of xxx is the interval (α,β)(\alpha,\beta)(α,β), then 12(α2+β2)12(\alpha^2+\beta^2)12(α2+β2) is equal to ______.

Correct answer: 36

Step-by-step solution →
Q81·Mathematics·Straight LinesNumerical
Let A(−2,−1)A(-2,-1)A(−2,−1), B(1,0)B(1,0)B(1,0), C(α,β)C(\alpha,\beta)C(α,β) and D(γ,δ)D(\gamma,\delta)D(γ,δ) be the vertices of a parallelogram ABCD. If the point C lies on 2x−y=52x-y=52x−y=5 and the point D lies on 3x−2y=63x-2y=63x−2y=6, then the value of ∣α+β+γ+δ∣|\alpha+\beta+\gamma+\delta|∣α+β+γ+δ∣ is equal to ______.

Correct answer: 32

Step-by-step solution →
Q82·Mathematics·Binomial Theorem and Its Simple ApplicationsNumerical
Let the coefficient of xrx^rxr in the expansion of (x+3)n−1+(x+3)n−2(x+2)+(x+3)n−3(x+2)2+…+(x+2)n−1(x+3)^{n-1}+(x+3)^{n-2}(x+2)+(x+3)^{n-3}(x+2)^2+\ldots+(x+2)^{n-1}(x+3)n−1+(x+3)n−2(x+2)+(x+3)n−3(x+2)2+…+(x+2)n−1 be ara_rar​. If ∑r=0nar=βn−αn\displaystyle\sum_{r=0}^{n}a_r=\beta^n-\alpha^nr=0∑n​ar​=βn−αn, β,α∈N\beta,\alpha\in Nβ,α∈N, then the value of β2+α2\beta^2+\alpha^2β2+α2 equals ______.

Correct answer: 25

Step-by-step solution →
Q83·Mathematics·Matrices and DeterminantsNumerical
Let A be a 3×33\times33×3 matrix and det⁡(A)=2\det(A)=2det(A)=2. If n=det⁡(adj(adj(…(adjA))))n=\det\left(\text{adj}\left(\text{adj}\left(\ldots\left(\text{adj}A\right)\right)\right)\right)n=det(adj(adj(…(adjA)))) (adj applied 2024 times). Then the remainder when nnn is divided by 9 is equal to ______.

Correct answer: 7

Step-by-step solution →
Q84·Mathematics·Vector AlgebraNumerical
Let a⃗=3i^+2j^+k^\vec{a}=3\hat{i}+2\hat{j}+\hat{k}a=3i^+2j^​+k^, b⃗=2i^−j^+3k^\vec{b}=2\hat{i}-\hat{j}+3\hat{k}b=2i^−j^​+3k^ and c⃗\vec{c}c be a vector such that (a⃗+b⃗)×c⃗=2(a⃗×b⃗)+24j^−6k^(\vec{a}+\vec{b})\times\vec{c}=2(\vec{a}\times\vec{b})+24\hat{j}-6\hat{k}(a+b)×c=2(a×b)+24j^​−6k^ and (a⃗−b⃗+i^)⋅c⃗=−3(\vec{a}-\vec{b}+\hat{i})\cdot\vec{c}=-3(a−b+i^)⋅c=−3. Then ∣c⃗∣2|\vec{c}|^2∣c∣2 is equal to ______.

Correct answer: 38

Step-by-step solution →
Q85·Mathematics·Limits and ContinuityNumerical
If lim⁡x→0ax2ex−blog⁡e(1+x)+cxe−xx2sin⁡x=1\displaystyle\lim_{x\to0}\dfrac{ax^2e^x-b\log_e(1+x)+cxe^{-x}}{x^2\sin x}=1x→0lim​x2sinxax2ex−bloge​(1+x)+cxe−x​=1, then 16(a2+b2+c2)16(a^2+b^2+c^2)16(a2+b2+c2) is equal to ______.

Correct answer: 81

Step-by-step solution →
Q86·Mathematics·Three Dimensional GeometryNumerical
A line passes through A(4,−6,−2)A(4,-6,-2)A(4,−6,−2) and B(16,−2,4)B(16,-2,4)B(16,−2,4). The point P(a,b,c)P(a,b,c)P(a,b,c) where a,b,ca,b,ca,b,c are non-negative integers, on the line AB lies at a distance of 21 units, from the point A. The distance between the points P(a,b,c)P(a,b,c)P(a,b,c) and Q(4,−12,3)Q(4,-12,3)Q(4,−12,3) is equal to ______.

Correct answer: 22

Step-by-step solution →
Q87·Mathematics·Differential EquationsNumerical
Let y=y(x)y=y(x)y=y(x) be the solution of the differential equation sec⁡2x dx+(e2ytan⁡2x+tan⁡x)dy=0\sec^2 x\,dx+\left(e^{2y}\tan^2 x+\tan x\right)dy=0sec2xdx+(e2ytan2x+tanx)dy=0, 0<x<π20<x<\dfrac{\pi}{2}0<x<2π​, y(π4)=0y\left(\dfrac{\pi}{4}\right)=0y(4π​)=0. If y(π6)=αy\left(\dfrac{\pi}{6}\right)=\alphay(6π​)=α, Then e8αe^{8\alpha}e8α is equal to ______.

Correct answer: 9

Step-by-step solution →
Q88·Mathematics·Sets, Relations and FunctionsNumerical
Let A={1,2,3,……100}A=\{1,2,3,\ldots\ldots100\}A={1,2,3,……100}. Let R be a relation on A defined by (x,y)∈R(x,y)\in R(x,y)∈R if and only if 2x=3y2x=3y2x=3y. Let R1R_1R1​ be a symmetric relation on A such that R⊂R1R\subset R_1R⊂R1​ and the number of elements in R1R_1R1​ is nnn. Then the minimum value of nnn is ______.

Correct answer: 66

Step-by-step solution →

Chapters tested in this paper

Open any chapter to practise every past-year question on that topic across all papers, and see how often it has actually appeared.

  • Properties of Solids and Liquids 172/186
  • Three Dimensional Geometry 176/186
  • Matrices and Determinants 180/186
  • Coordination Compounds 176/186
  • Sets, Relations and Functions 165/186
  • Current Electricity 160/186
  • Sequence and Series 164/186
  • p-Block Elements 164/186
  • Definite Integration 168/186
  • Rotational Motion 172/186
  • Redox Reactions and Electrochemistry 177/186
  • Geometrical Optics 172/186
  • Kinematics 156/186
  • Vector Algebra 173/186
  • Differential Equations 167/186
  • Probability 176/186
  • Permutations and Combinations 162/186
  • Magnetic Field of Current 147/186
  • Binomial Theorem and Its Simple Applications 158/186
  • Electromagnetic Waves 144/186
  • Chemical Bonding and Molecular Structure 151/186
  • Limits and Continuity 149/186
  • d- and f-Block Elements 126/186
  • Aldehydes and Ketones 135/186
  • Equilibrium 163/186
  • Laws of Motion 130/186
  • Chemical Thermodynamics 165/186
  • Units and Measurements 149/186
  • Hydrocarbons 126/186
  • Complex Numbers 165/186
  • Trigonometric Functions 144/186
  • Biomolecules 162/186
  • Chemical Kinetics 169/186
  • Gravitation 152/186
  • Atomic Structure 161/186
  • Electronic Devices 145/186
  • Circles 142/186
  • Dual Nature of Matter and Radiation 155/186
  • Amines 133/186
  • Quadratic Equations 148/186
  • Work, Energy and Power 132/186
  • Some Basic Concepts in Chemistry 129/186
  • Electromagnetic Induction 120/186
  • Area Under Curves 139/186
  • Kinetic Theory of Gases 135/186
  • Purification and Characterisation of Organic Compounds 116/186
  • Oscillations 117/186
  • Alternating Currents 108/186
  • Nuclei 116/186
  • Organic Compounds Containing Halogens 109/186
  • Straight Lines 114/186
  • Waves 109/186
  • Capacitors and Dielectrics 115/186
  • Classification of Elements and Periodicity in Properties 113/186
  • Parabola 101/186
  • Statistics 118/186
  • Inverse Trigonometric Functions 93/186
  • Electronic Effects and Stability 74/186
  • Electric Potential 63/186
  • Solid State 63/186
  • Diazonium Salts and Reactions 53/186
  • IUPAC Nomenclature 37/186
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