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JEE Main 31 January 2024 Shift 1 Question Paper with Answers

31 January 2024 · January session · 90 questions

The complete JEE Main 31 January 2024 Shift 1 paper — all 90 questions with the correct answer for each, tagged to the chapter it tests. Free to read, no account needed.

Physics
30
Chemistry
30
Mathematics
30

Physics — JEE Main 31 January 2024 Shift 1

Q1·Physics·Kinetic Theory of GasesSingle correct
The parameter that remains the same for molecules of all gases at a given temperature is :
  1. (A)kinetic energy
  2. (B)momentum
  3. (C)mass
  4. (D)speed

Correct answer: (A)

Step-by-step solution →
Q2·Physics·Electronic DevicesSingle correct
Identify the logic operation performed by the given circuit.
  1. (A)NAND
  2. (B)NOR
  3. (C)OR
  4. (D)AND

Correct answer: (C)

Step-by-step solution →
Q3·Physics·KinematicsSingle correct
The relation between time 't' and distance 'x' is t=αx2+βxt=\alpha x^2+\beta xt=αx2+βx, where α\alphaα and β\betaβ are constants. The relation between acceleration (a) and velocity (v) is :
  1. (A)a=−2αv3a=-2\alpha v^3a=−2αv3
  2. (B)a=−5αv5a=-5\alpha v^5a=−5αv5
  3. (C)a=−3αv2a=-3\alpha v^2a=−3αv2
  4. (D)a=−4αv4a=-4\alpha v^4a=−4αv4

Correct answer: (A)

Step-by-step solution →
Q4·Physics·Geometrical OpticsSingle correct
The refractive index of a prism with apex angle A is cot⁡A2\cot\dfrac{A}{2}cot2A​. The angle of minimum deviation is :
  1. (A)δm=180∘−A\delta_m=180^\circ-Aδm​=180∘−A
  2. (B)δm=180∘−3A\delta_m=180^\circ-3Aδm​=180∘−3A
  3. (C)δm=180∘−4A\delta_m=180^\circ-4Aδm​=180∘−4A
  4. (D)δm=180∘−2A\delta_m=180^\circ-2Aδm​=180∘−2A

Correct answer: (D)

Step-by-step solution →
Q5·Physics·Magnetic Field of CurrentSingle correct
A rigid wire consists of a semicircular portion of radius R and two straight sections. The wire is partially immersed in a perpendicular magnetic field B=B0j^B=B_0\hat{j}B=B0​j^​ as shown in figure. The magnetic force on the wire if it has a current i is :
  1. (A)−iBRj^-iBR\hat{j}−iBRj^​
  2. (B)2iBRj^2iBR\hat{j}2iBRj^​
  3. (C)iBRj^iBR\hat{j}iBRj^​
  4. (D)−2iBRj^-2iBR\hat{j}−2iBRj^​

Correct answer: (D)

Step-by-step solution →
Q6·Physics·Atoms and NucleiSingle correct
If the wavelength of the first member of Lyman series of hydrogen is λ\lambdaλ. The wavelength of the second member will be :
  1. (A)2732λ\dfrac{27}{32}\lambda3227​λ
  2. (B)3227λ\dfrac{32}{27}\lambda2732​λ
  3. (C)275λ\dfrac{27}{5}\lambda527​λ
  4. (D)527λ\dfrac{5}{27}\lambda275​λ

Correct answer: (A)

Step-by-step solution →
Q7·Physics·GravitationSingle correct
Four identical particles of mass m are kept at the four corners of a square. If the gravitational force exerted on one of the masses by the other masses is (22+132)Gm2L2\left(\dfrac{2\sqrt{2}+1}{32}\right)\dfrac{Gm^2}{L^2}(3222​+1​)L2Gm2​, the length of the sides of the square is :
  1. (A)L2\dfrac{L}{2}2L​
  2. (B)4L4L4L
  3. (C)3L3L3L
  4. (D)2L2L2L

Correct answer: (B)

Step-by-step solution →
Q8·Physics·ThermodynamicsSingle correct
The given figure represents two isobaric processes for the same mass of an ideal gas, then
  1. (A)P2≥P1P_2\ge P_1P2​≥P1​
  2. (B)P2>P1P_2>P_1P2​>P1​
  3. (C)P1=P2P_1=P_2P1​=P2​
  4. (D)P1>P2P_1>P_2P1​>P2​

Correct answer: (D)

Step-by-step solution →
Q9·Physics·Units and MeasurementsSingle correct
If the percentage errors in measuring the length and the diameter of a wire are 0.1% each. The percentage error in measuring its resistance will be :
  1. (A)0.2%0.2\%0.2%
  2. (B)0.3%0.3\%0.3%
  3. (C)0.1%0.1\%0.1%
  4. (D)0.144%0.144\%0.144%

Correct answer: (B)

Step-by-step solution →
Q10·Physics·Electromagnetic WavesSingle correct
In a plane EM wave, the electric field oscillates sinusoidally at a frequency of 5×10105\times10^{10}5×1010 Hz and an amplitude of 50 Vm−1^{-1}−1. The total average energy density of the electromagnetic field of the wave is : [Use ϵ0=8.85×10−12\epsilon_0=8.85\times10^{-12}ϵ0​=8.85×10−12 C2^22/Nm2^22]
  1. (A)1.106×10−81.106\times10^{-8}1.106×10−8 Jm−3^{-3}−3
  2. (B)4.425×10−84.425\times10^{-8}4.425×10−8 Jm−3^{-3}−3
  3. (C)2.212×10−82.212\times10^{-8}2.212×10−8 Jm−3^{-3}−3
  4. (D)2.212×10−102.212\times10^{-10}2.212×10−10 Jm−3^{-3}−3

Correct answer: (A)

Step-by-step solution →
Q11·Physics·Units and MeasurementsSingle correct
A force is represented by F=ax2+bt1/2F=ax^2+bt^{1/2}F=ax2+bt1/2 where x = distance and t = time. The dimensions of b2a\dfrac{b^2}{a}ab2​ are :
  1. (A)[ML3T−3][ML^3T^{-3}][ML3T−3]
  2. (B)[MLT−2][MLT^{-2}][MLT−2]
  3. (C)[ML−1T−1][ML^{-1}T^{-1}][ML−1T−1]
  4. (D)[ML2T−3][ML^2T^{-3}][ML2T−3]

Correct answer: (A)

Step-by-step solution →
Q12·Physics·Electric Field and Coulomb's LawSingle correct
Two charges q and 3q are separated by a distance 'r' in air. At a distance x from charge q, the resultant electric field is zero. The value of x is :
  1. (A)(1+3)r\dfrac{(1+\sqrt{3})}{r}r(1+3​)​
  2. (B)r3(1+3)\dfrac{r}{3(1+\sqrt{3})}3(1+3​)r​
  3. (C)r(1+3)\dfrac{r}{(1+\sqrt{3})}(1+3​)r​
  4. (D)r(1+3)r(1+\sqrt{3})r(1+3​)

Correct answer: (C)

Step-by-step solution →
Q13·Physics·Laws of MotionSingle correct
In the given arrangement of a doubly inclined plane two blocks of masses M and m are placed. The blocks are connected by a light string passing over an ideal pulley as shown. The coefficient of friction between the surface of the plane and the blocks is 0.25. The value of m, for which M = 10 kg will move down with an acceleration of 2 m/s2^22, is : (take g=10g=10g=10 m/s2^22 and tan⁡37∘=3/4\tan 37^\circ=3/4tan37∘=3/4)
  1. (A)9 kg
  2. (B)4.5 kg
  3. (C)6.5 kg
  4. (D)2.25 kg

Correct answer: (B)

Step-by-step solution →
Q14·Physics·Electromagnetic InductionSingle correct
A coil is placed perpendicular to a magnetic field of 5000 T. When the field is changed to 3000 T in 2s, an induced emf of 22 V is produced in the coil. If the diameter of the coil is 0.02 m, then the number of turns in the coil is :
  1. (A)7
  2. (B)70
  3. (C)35
  4. (D)140

Correct answer: (B)

Step-by-step solution →
Q15·Physics·WavesSingle correct
The fundamental frequency of a closed organ pipe is equal to the first overtone frequency of an open organ pipe. If length of the open pipe is 60 cm, the length of the closed pipe will be :
  1. (A)60 cm
  2. (B)45 cm
  3. (C)30 cm
  4. (D)15 cm

Correct answer: (D)

Step-by-step solution →
Q16·Physics·Properties of Solids and LiquidsSingle correct
A small steel ball is dropped into a long cylinder containing glycerine. Which one of the following is the correct representation of the velocity time graph for the transit of the ball?
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (B)

Step-by-step solution →
Q17·Physics·Laws of MotionSingle correct
A coin is placed on a disc. The coefficient of friction between the coin and the disc is μ\muμ. If the distance of the coin from the center of the disc is r, the maximum angular velocity which can be given to the disc, so that the coin does not slip away, is :
  1. (A)μgr\dfrac{\mu g}{r}rμg​
  2. (B)rμg\sqrt{\dfrac{r}{\mu g}}μgr​​
  3. (C)μgr\sqrt{\dfrac{\mu g}{r}}rμg​​
  4. (D)μrg\dfrac{\mu}{\sqrt{rg}}rg​μ​

Correct answer: (C)

Step-by-step solution →
Q18·Physics·Current ElectricitySingle correct
Two conductors have the same resistances at 0∘^\circ∘C but their temperature coefficients of resistance are α1\alpha_1α1​ and α2\alpha_2α2​. The respective temperature coefficients for their series and parallel combinations are :
  1. (A)α1+α2, α1+α22\alpha_1+\alpha_2,\ \dfrac{\alpha_1+\alpha_2}{2}α1​+α2​, 2α1​+α2​​
  2. (B)α1+α22, α1+α22\dfrac{\alpha_1+\alpha_2}{2},\ \dfrac{\alpha_1+\alpha_2}{2}2α1​+α2​​, 2α1​+α2​​
  3. (C)α1+α2, α1α2α1+α2\alpha_1+\alpha_2,\ \dfrac{\alpha_1\alpha_2}{\alpha_1+\alpha_2}α1​+α2​, α1​+α2​α1​α2​​
  4. (D)α1+α22, α1+α2\dfrac{\alpha_1+\alpha_2}{2},\ \alpha_1+\alpha_22α1​+α2​​, α1​+α2​

Correct answer: (B)

Step-by-step solution →
Q19·Physics·Work, Energy and PowerSingle correct
An artillery piece of mass M1M_1M1​ fires a shell of mass M2M_2M2​ horizontally. Instantaneously after the firing, the ratio of kinetic energy of the artillery and that of the shell is :
  1. (A)M1(M1+M2)\dfrac{M_1}{(M_1+M_2)}(M1​+M2​)M1​​
  2. (B)M2M1\dfrac{M_2}{M_1}M1​M2​​
  3. (C)M2(M1+M2)\dfrac{M_2}{(M_1+M_2)}(M1​+M2​)M2​​
  4. (D)M1M2\dfrac{M_1}{M_2}M2​M1​​

Correct answer: (B)

Step-by-step solution →
Q20·Physics·Dual Nature of Matter and RadiationSingle correct
When a metal surface is illuminated by light of wavelength λ\lambdaλ, the stopping potential is 8V. When the same surface is illuminated by light of wavelength 3λ3\lambda3λ, stopping potential is 2V. The threshold wavelength for this surface is :
  1. (A)5λ5\lambda5λ
  2. (B)3λ3\lambda3λ
  3. (C)9λ9\lambda9λ
  4. (D)4.5λ4.5\lambda4.5λ

Correct answer: (C)

Step-by-step solution →
Q21·Physics·Magnetic Field of CurrentNumerical
An electron moves through a uniform magnetic field B⃗=B0i^+2B0j^\vec{B}=B_0\hat{i}+2B_0\hat{j}B=B0​i^+2B0​j^​ T. At a particular instant of time, the velocity of electron is u⃗=3i^+5j^\vec{u}=3\hat{i}+5\hat{j}u=3i^+5j^​ m/s. If the magnetic force acting on electron is F⃗=5ek^\vec{F}=5e\hat{k}F=5ek^ N, where e is the charge of electron, then the value of B0B_0B0​ is ______ T.

Correct answer: 5

Step-by-step solution →
Q22·Physics·Capacitors and DielectricsNumerical
A parallel plate capacitor with plate separation 5 mm is charged up by a battery. It is found that on introducing a dielectric sheet of thickness 2 mm, while keeping the battery connections intact, the capacitor draws 25% more charge from the battery than before. The dielectric constant of the sheet is ______.

Correct answer: 2

Step-by-step solution →
Q23·Physics·Current ElectricityNumerical
Equivalent resistance of the following network is ______ Ω\OmegaΩ.

Correct answer: 1

Step-by-step solution →
Q24·Physics·Rotational MotionNumerical
A solid circular disc of mass 50 kg rolls along a horizontal floor so that its center of mass has a speed of 0.4 m/s. The absolute value of work done on the disc to stop it is ______ J.

Correct answer: 6

Step-by-step solution →
Q25·Physics·KinematicsNumerical
A body starts falling freely from height H hits an inclined plane in its path at height h. As a result of this perfectly elastic impact, the direction of the velocity of the body becomes horizontal. The value of Hh\dfrac{H}{h}hH​ for which the body will take the maximum time to reach the ground is ______.

Correct answer: 2

Step-by-step solution →
Q26·Physics·Wave OpticsNumerical
Two waves of intensity ratio 1 : 9 cross each other at a point. The resultant intensities at the point, when (a) Waves are incoherent is I1I_1I1​ (b) Waves are coherent and differ in phase by 60∘60^\circ60∘ is I2I_2I2​. If I1I2=10x\dfrac{I_1}{I_2}=\dfrac{10}{x}I2​I1​​=x10​ then x=x=x= ______.

Correct answer: 13

Step-by-step solution →
Q27·Physics·Electromagnetic InductionNumerical
A small square loop of wire of side ℓ\ellℓ is placed inside a large square loop of wire of side L (L=ℓ2)(L=\ell^2)(L=ℓ2). The loops are coplanar and their centers coincide. The value of the mutual inductance of the system is x×10−7\sqrt{x}\times10^{-7}x​×10−7 H, where x=x=x= ______.

Correct answer: 128

Step-by-step solution →
Q28·Physics·Properties of Solids and LiquidsNumerical
The depth below the surface of sea to which a rubber ball be taken so as to decrease its volume by 0.02% is ______ m. (Take density of sea water = 10310^3103 kgm−3^{-3}−3, Bulk modulus of rubber = 9×1089\times10^89×108 Nm−2^{-2}−2, and g=10g=10g=10 ms−2^{-2}−2)

Correct answer: 18

Step-by-step solution →
Q29·Physics·OscillationsNumerical
A particle performs simple harmonic motion with amplitude A. Its speed is increased to three times at an instant when its displacement is 2A3\dfrac{2A}{3}32A​. The new amplitude of motion is nA3\dfrac{nA}{3}3nA​. The value of n is ______.

Correct answer: 7

Step-by-step solution →
Q30·Physics·Atoms and NucleiNumerical
The mass defect in a particular reaction is 0.4 g. The amount of energy liberated is n×107n\times10^7n×107 kWh, where n=n=n= ______. (speed of light = 3×1083\times10^83×108 m/s)

Correct answer: 1

Step-by-step solution →

Chemistry — JEE Main 31 January 2024 Shift 1

Q31·Chemistry·p-Block ElementsSingle correct
Given below are two statements: Statement-I : Noble gases have very high boiling points. Statement-II : Noble gases are monoatomic gases. They are held together by strong dispersion forces. Because of this they are liquefied at very low temperature. Hence, they have very high boiling points. In the light of the above statements, choose the correct answer from the options given below:
  1. (A)Statement I is false but Statement II is true.
  2. (B)Both Statement I and Statement II are true.
  3. (C)Statement I is true but Statement II is false.
  4. (D)Both Statement I and Statement II are false.

Correct answer: (D)

Step-by-step solution →
Q32·Chemistry·EquilibriumSingle correct
For the given reaction, choose the correct expression of KCK_CKC​ from the following :- Fe(aq)3++SCN(aq)−⇌(FeSCN)(aq)2+Fe^{3+}_{(aq)}+SCN^-_{(aq)}\rightleftharpoons (FeSCN)^{2+}_{(aq)}Fe(aq)3+​+SCN(aq)−​⇌(FeSCN)(aq)2+​
  1. (A)KC=[FeSCN2+][Fe3+][SCN−]K_C=\dfrac{[FeSCN^{2+}]}{[Fe^{3+}][SCN^-]}KC​=[Fe3+][SCN−][FeSCN2+]​
  2. (B)KC=[Fe3+][SCN−][FeSCN2+]K_C=\dfrac{[Fe^{3+}][SCN^-]}{[FeSCN^{2+}]}KC​=[FeSCN2+][Fe3+][SCN−]​
  3. (C)KC=[FeSCN2+][Fe3+]2[SCN−]2K_C=\dfrac{[FeSCN^{2+}]}{[Fe^{3+}]^2[SCN^-]^2}KC​=[Fe3+]2[SCN−]2[FeSCN2+]​
  4. (D)KC=[FeSCN2+]2[Fe3+][SCN−]K_C=\dfrac{[FeSCN^{2+}]^2}{[Fe^{3+}][SCN^-]}KC​=[Fe3+][SCN−][FeSCN2+]2​

Correct answer: (A)

Step-by-step solution →
Q33·Chemistry·SolutionsSingle correct
Identify the mixture that shows positive deviations from Raoult's Law
  1. (A)(CH3)2CO+C6H5NH2(CH_3)_2CO+C_6H_5NH_2(CH3​)2​CO+C6​H5​NH2​
  2. (B)CHCl3+C6H6CHCl_3+C_6H_6CHCl3​+C6​H6​
  3. (C)CHCl3+(CH3)2COCHCl_3+(CH_3)_2COCHCl3​+(CH3​)2​CO
  4. (D)(CH3)2CO+CS2(CH_3)_2CO+CS_2(CH3​)2​CO+CS2​

Correct answer: (D)

Step-by-step solution →
Q34·Chemistry·Principles of Qualitative AnalysisSingle correct
The compound that is white in color is
  1. (A)ammonium sulphide
  2. (B)lead sulphate
  3. (C)lead iodide
  4. (D)ammonium arsinomolybdate

Correct answer: (B)

Step-by-step solution →
Q35·Chemistry·Redox Reactions and ElectrochemistrySingle correct
The metals that are employed in the battery industries are A. Fe B. Mn C. Ni D. Cr E. Cd Choose the correct answer from the options given below:
  1. (A)B, C and E only
  2. (B)A, B, C, D and E
  3. (C)A, B, C and D only
  4. (D)B, D and E only

Correct answer: (A)

Step-by-step solution →
Q36·Chemistry·Reaction MechanismSingle correct
A species having carbon with sextet of electrons and can act as electrophile is called
  1. (A)carbon free radical
  2. (B)carbanion
  3. (C)carbocation
  4. (D)pentavalent carbon

Correct answer: (C)

Step-by-step solution →
Q37·Chemistry·Redox Reactions and ElectrochemistrySingle correct
Identify the factor from the following that does not affect electrolytic conductance of a solution.
  1. (A)The nature of the electrolyte added.
  2. (B)The nature of the electrode used.
  3. (C)Concentration of the electrolyte.
  4. (D)The nature of solvent used.

Correct answer: (B)

Step-by-step solution →
Q38·Chemistry·Organic Compounds Containing HalogensSingle correct
The product (C) in the below mentioned reaction is: CH3−CH2−CH2−Br→ΔKOH(alc)A→HBrB→ΔKOH(aq)CCH_3-CH_2-CH_2-Br\xrightarrow[\Delta]{KOH(alc)}A\xrightarrow{HBr}B\xrightarrow[\Delta]{KOH(aq)}CCH3​−CH2​−CH2​−BrKOH(alc)Δ​AHBr​BKOH(aq)Δ​C
  1. (A)Propan-1-ol
  2. (B)Propene
  3. (C)Propyne
  4. (D)Propan-2-ol

Correct answer: (D)

Step-by-step solution →
Q39·Chemistry·Alcohols and EthersSingle correct
Given below are two statements: One is labelled as Assertion A and the other is labelled as Reason R: Assertion A : Alcohols react both as nucleophiles and electrophiles. Reason R : Alcohols react with active metals such as sodium, potassium and aluminum to yield corresponding alkoxides and liberate hydrogen. In the light of the above statements, choose the correct answer from the options given below:
  1. (A)A is false but R is true.
  2. (B)A is true but R is false.
  3. (C)Both A and R are true and R is the correct explanation of A.
  4. (D)Both A and R are true but R is NOT the correct explanation of A

Correct answer: (D)

Step-by-step solution →
Q40·Chemistry·Classification of Elements and Periodicity in PropertiesSingle correct
The correct sequence of electron gain enthalpy of the elements listed below is A. Ar B. Br C. F D. S Choose the most appropriate from the options given below:
  1. (A)C > B > D > A
  2. (B)A > D > B > C
  3. (C)A > D > C > B
  4. (D)D > C > B > A

Correct answer: (B)

Step-by-step solution →
Q41·Chemistry·d- and f-Block ElementsSingle correct
Identify correct statements from below: A. The chromate ion is square planar. B. Dichromates are generally prepared from chromates. C. The green manganate ion is diamagnetic. D. Dark green coloured K2MnO4K_2MnO_4K2​MnO4​ disproportionates in a neutral or acidic medium to give permanganate. E. With increasing oxidation number of transition metal, ionic character of the oxides decreases. Choose the correct answer from the options given below:
  1. (A)B, C, D only
  2. (B)A, D, E only
  3. (C)A, B, C only
  4. (D)B, D, E only

Correct answer: (D)

Step-by-step solution →
Q42·Chemistry·Purification and Characterisation of Organic CompoundsSingle correct
'Adsorption' principle is used for which of the following purification method?
  1. (A)Extraction
  2. (B)Chromatography
  3. (C)Distillation
  4. (D)Sublimation

Correct answer: (B)

Step-by-step solution →
Q43·Chemistry·Chemical KineticsSingle correct
Integrated rate law equation for a first order gas phase reaction is given by (where PiP_iPi​ is initial pressure and PtP_tPt​ is total pressure at time t)
  1. (A)k=2.303t×log⁡Pi(2Pi−Pt)k=\dfrac{2.303}{t}\times\log\dfrac{P_i}{(2P_i-P_t)}k=t2.303​×log(2Pi​−Pt​)Pi​​
  2. (B)k=2.303t×log⁡2Pi(2Pi−Pt)k=\dfrac{2.303}{t}\times\log\dfrac{2P_i}{(2P_i-P_t)}k=t2.303​×log(2Pi​−Pt​)2Pi​​
  3. (C)k=2.303t×log⁡(2Pi−Pt)Pik=\dfrac{2.303}{t}\times\log\dfrac{(2P_i-P_t)}{P_i}k=t2.303​×logPi​(2Pi​−Pt​)​
  4. (D)k=2.303t×Pi(2Pi−Pt)k=\dfrac{2.303}{t}\times\dfrac{P_i}{(2P_i-P_t)}k=t2.303​×(2Pi​−Pt​)Pi​​

Correct answer: (A)

Step-by-step solution →
Q44·Chemistry·Alcohols and EthersSingle correct
Given below are two statements: One is labelled as Assertion A and the other is labelled as Reason R: Assertion A : pKapK_apKa​ value of phenol is 10.0 while that of ethanol is 15.9. Reason R : Ethanol is stronger acid than phenol. In the light of the above statements, choose the correct answer from the options given below:
  1. (A)A is true but R is false.
  2. (B)A is false but R is true.
  3. (C)Both A and R are true and R is the correct explanation of A.
  4. (D)Both A and R are true but R is NOT the correct explanation of A.

Correct answer: (A)

Step-by-step solution →
Q45·Chemistry·IUPAC NomenclatureSingle correct
Given below are two statements: Statement I : IUPAC name of HO−CH2−(CH2)3−CH2−COCH3HO-CH_2-(CH_2)_3-CH_2-COCH_3HO−CH2​−(CH2​)3​−CH2​−COCH3​ is 7-hydroxyheptan-2-one. Statement II : 2-oxoheptan-7-ol is the correct IUPAC name for above compound. In the light of the above statements, choose the most appropriate answer from the options given below:
  1. (A)Statement I is correct but Statement II is incorrect.
  2. (B)Both Statement I and Statement II are incorrect.
  3. (C)Both Statement I and Statement II are correct.
  4. (D)Statement I is incorrect but Statement II is correct.

Correct answer: (A)

Step-by-step solution →
Q46·Chemistry·Coordination CompoundsSingle correct
The correct statements from following are: A. The strength of anionic ligands can be explained by crystal field theory. B. Valence bond theory does not give a quantitative interpretation of kinetic stability of coordination compounds. C. The hybridization involved in formation of [Ni(CN)4]2−[Ni(CN)_4]^{2-}[Ni(CN)4​]2− complex is dsp2dsp^2dsp2. D. The number of possible isomer(s) of cis-[PtCl2(en)2]2+[PtCl_2(en)_2]^{2+}[PtCl2​(en)2​]2+ is one. Choose the correct answer from the options given below:
  1. (A)A, D only
  2. (B)A, C only
  3. (C)B, D only
  4. (D)B, C only

Correct answer: (D)

Step-by-step solution →
Q47·Chemistry·Chemical Bonding and Molecular StructureSingle correct
The linear combination of atomic orbitals to form molecular orbitals takes place only when the combining atomic orbitals A. have the same energy B. have the minimum overlap C. have same symmetry about the molecular axis D. have different symmetry about the molecular axis Choose the most appropriate from the options given below:
  1. (A)A, B, C only
  2. (B)A and C only
  3. (C)B, C, D only
  4. (D)B and D only

Correct answer: (B)

Step-by-step solution →
Q48·Chemistry·BiomoleculesSingle correct
Match List-I (reactions of glucose) with List-II. Choose the correct answer from the options given below:
List-IList-II
A.Glucose/NaHCO3/ΔNaHCO_3/\DeltaNaHCO3​/ΔI.Gluconic acid
B.Glucose/HNO3HNO_3HNO3​II.No reaction
C.Glucose/HI/Δ\DeltaΔIII.n-hexane
D.Glucose/Bromine waterIV.Saccharic acid
  1. (A)A-IV, B-I, C-III, D-II
  2. (B)A-II, B-IV, C-III, D-I
  3. (C)A-III, B-II, C-I, D-IV
  4. (D)A-I, B-IV, C-III, D-II

Correct answer: (B)

Step-by-step solution →
Q49·Chemistry·p-Block ElementsSingle correct
Consider the oxides of group 14 elements SiO2SiO_2SiO2​, GeO2GeO_2GeO2​, SnO2SnO_2SnO2​, PbO2PbO_2PbO2​, CO and GeO. The amphoteric oxides are
  1. (A)GeO,GeO2GeO, GeO_2GeO,GeO2​
  2. (B)SiO2,GeO2SiO_2, GeO_2SiO2​,GeO2​
  3. (C)SnO2,PbO2SnO_2, PbO_2SnO2​,PbO2​
  4. (D)SnO2,COSnO_2, COSnO2​,CO

Correct answer: (C)

Step-by-step solution →
Q50·Chemistry·Purification and Characterisation of Organic CompoundsSingle correct
Match List-I (separation technique) with List-II (application). Choose the correct answer from the options given below:
List-I (Technique)List-II (Application)
A.DistillationI.Separation of glycerol from spent-lye
B.Fractional distillationII.Aniline - Water mixture
C.Steam distillationIII.Separation of crude oil fractions
D.Distillation under reduced pressureIV.Chloroform-Aniline
  1. (A)A-IV, B-I, C-II, D-III
  2. (B)A-IV, B-III, C-II, D-I
  3. (C)A-I, B-II, C-IV, D-III
  4. (D)A-II, B-III, C-I, D-IV

Correct answer: (B)

Step-by-step solution →
Q51·Chemistry·p-Block ElementsNumerical
Molar mass of the salt from NaBr, NaNO3NaNO_3NaNO3​, KI and CaF2CaF_2CaF2​ which does not evolve coloured vapours on heating with concentrated H2SO4H_2SO_4H2​SO4​ is ______ g mol−1^{-1}−1. (Molar mass in g mol−1^{-1}−1 : Na : 23, N : 14, K : 39, O : 16, Br : 80, I : 127, F : 19, Ca : 40)

Correct answer: 78

Step-by-step solution →
Q52·Chemistry·Coordination CompoundsNumerical
The 'Spin only' Magnetic moment for [Ni(NH3)6]2+[Ni(NH_3)_6]^{2+}[Ni(NH3​)6​]2+ is ______ ×10−1\times10^{-1}×10−1 BM. (given : Atomic number of Ni : 28)

Correct answer: 28

Step-by-step solution →
Q53·Chemistry·Some Basic Concepts in ChemistryNumerical
Number of moles of methane required to produce 22 g CO2(g)CO_{2(g)}CO2(g)​ after combustion is x×10−2x\times10^{-2}x×10−2 moles. The value of x is ______.

Correct answer: 50

Step-by-step solution →
Q54·Chemistry·Aldehydes and KetonesNumerical
The product of the following reaction is P. The compound shown (a benzene ring bearing a –CHO group and a –OH group at the para position) is treated with (i) PhMgBr (1 equiv.), (ii) aq. NH4ClNH_4ClNH4​Cl. The number of hydroxyl groups present in the product P is ______.

Correct answer: 1

Step-by-step solution →
Q55·Chemistry·Chemical Bonding and Molecular StructureNumerical
The number of species from the following in which the central atom uses sp3sp^3sp3 hybrid orbitals in its bonding is ______. NH3NH_3NH3​, SO2SO_2SO2​, SiO2SiO_2SiO2​, BeCl2BeCl_2BeCl2​, CO2CO_2CO2​, H2OH_2OH2​O, CH4CH_4CH4​, BF3BF_3BF3​

Correct answer: 4

Step-by-step solution →
Q56·Chemistry·Organic Compounds Containing HalogensNumerical
In the reaction CH3CH2Br+NaOHCH_3CH_2Br+NaOHCH3​CH2​Br+NaOH, with ethanol (C2H5OHC_2H_5OHC2​H5​OH) as medium giving Product A and with water (H2OH_2OH2​O) as medium giving Product B, the total number of hydrogen atoms in product A and product B is ______.

Correct answer: 10

Step-by-step solution →
Q57·Chemistry·HydrocarbonsNumerical
Number of alkanes obtained on electrolysis of a mixture of CH3COONaCH_3COONaCH3​COONa and C2H5COONaC_2H_5COONaC2​H5​COONa is ______.

Correct answer: 3

Step-by-step solution →
Q58·Chemistry·EquilibriumNumerical
Consider the following reaction at 298 K. 32O2(g)⇌O3(g)\dfrac{3}{2}O_{2(g)}\rightleftharpoons O_{3(g)}23​O2(g)​⇌O3(g)​. KP=2.47×10−29K_P=2.47\times10^{-29}KP​=2.47×10−29. ΔrG⊖\Delta_r G^\ominusΔr​G⊖ for the reaction is ______ kJ. (Given R = 8.314 JK−1^{-1}−1 mol−1^{-1}−1)

Correct answer: 163

Step-by-step solution →
Q59·Chemistry·Atomic StructureNumerical
The ionization energy of sodium in kJ mol−1^{-1}−1, if electromagnetic radiation of wavelength 242 nm is just sufficient to ionize sodium atom, is ______.

Correct answer: 494

Step-by-step solution →
Q60·Chemistry·Redox Reactions and ElectrochemistryNumerical
One Faraday of electricity liberates x×10−1x\times10^{-1}x×10−1 gram atom of copper from copper sulphate, x is ______.

Correct answer: 5

Step-by-step solution →

Mathematics — JEE Main 31 January 2024 Shift 1

Q61·Mathematics·Quadratic EquationsSingle correct
For 0<c<b<a0<c<b<a0<c<b<a, let (a+b−2c)x2+(b+c−2a)x+(c+a−2b)=0(a+b-2c)x^2+(b+c-2a)x+(c+a-2b)=0(a+b−2c)x2+(b+c−2a)x+(c+a−2b)=0 and α≠1\alpha\ne 1α=1 be one of its root. Then, among the two statements (I) If α∈(−1,0)\alpha\in(-1,0)α∈(−1,0), then b cannot be the geometric mean of a and c (II) If α∈(0,1)\alpha\in(0,1)α∈(0,1), then b may be the geometric mean of a and c
  1. (A)Both (I) and (II) are true
  2. (B)Neither (I) nor (II) is true
  3. (C)Only (II) is true
  4. (D)Only (I) is true

Correct answer: (A)

Step-by-step solution →
Q62·Mathematics·Quadratic EquationsSingle correct
Let a be the sum of all coefficients in the expansion of (1−2x+2x2)2023(3−4x2+2x3)2024\left(1-2x+2x^2\right)^{2023}\left(3-4x^2+2x^3\right)^{2024}(1−2x+2x2)2023(3−4x2+2x3)2024 and b=lim⁡x→0(∫0xlog⁡(1+t)t2024+1dtx2)b=\displaystyle\lim_{x\to 0}\left(\dfrac{\int_0^x \frac{\log(1+t)}{t^{2024}+1}dt}{x^2}\right)b=x→0lim​(x2∫0x​t2024+1log(1+t)​dt​). If the equations cx2+dx+e=0cx^2+dx+e=0cx2+dx+e=0 and 2bx2+ax+4=02bx^2+ax+4=02bx2+ax+4=0 have a common root, where c,d,e∈Rc,d,e\in Rc,d,e∈R, then d:c:ed:c:ed:c:e equals
  1. (A)2:1:42:1:42:1:4
  2. (B)4:1:44:1:44:1:4
  3. (C)1:2:41:2:41:2:4
  4. (D)1:1:41:1:41:1:4

Correct answer: (D)

Step-by-step solution →
Q63·Mathematics·EllipseSingle correct
If the foci of a hyperbola are same as that of the ellipse x29+y225=1\dfrac{x^2}{9}+\dfrac{y^2}{25}=19x2​+25y2​=1 and the eccentricity of the hyperbola is 158\dfrac{15}{8}815​ times the eccentricity of the ellipse, then the smaller focal distance of the point (2,14325)\left(\sqrt{2},\dfrac{14}{3}\sqrt{\dfrac{2}{5}}\right)(2​,314​52​​) on the hyperbola, is equal to
  1. (A)725−837\sqrt{\dfrac{2}{5}}-\dfrac{8}{3}752​​−38​
  2. (B)1425−4314\sqrt{\dfrac{2}{5}}-\dfrac{4}{3}1452​​−34​
  3. (C)1425−16314\sqrt{\dfrac{2}{5}}-\dfrac{16}{3}1452​​−316​
  4. (D)725+837\sqrt{\dfrac{2}{5}}+\dfrac{8}{3}752​​+38​

Correct answer: (A)

Step-by-step solution →
Q64·Mathematics·CirclesSingle correct
If one of the diameters of the circle x2+y2−10x+4y+13=0x^2+y^2-10x+4y+13=0x2+y2−10x+4y+13=0 is a chord of another circle C, whose center is the point of intersection of the lines 2x+3y=122x+3y=122x+3y=12 and 3x−2y=53x-2y=53x−2y=5, then the radius of the circle C is
  1. (A)20\sqrt{20}20​
  2. (B)444
  3. (C)666
  4. (D)323\sqrt{2}32​

Correct answer: (C)

Step-by-step solution →
Q65·Mathematics·Area Under CurvesSingle correct
The area of the region {(x,y):y2≤4x, x<4, xy(x−1)(x−2)(x−3)(x−4)>0, x≠3}\left\{(x,y): y^2\le 4x,\ x<4,\ \dfrac{xy(x-1)(x-2)}{(x-3)(x-4)}>0,\ x\ne 3\right\}{(x,y):y2≤4x, x<4, (x−3)(x−4)xy(x−1)(x−2)​>0, x=3} is
  1. (A)163\dfrac{16}{3}316​
  2. (B)643\dfrac{64}{3}364​
  3. (C)83\dfrac{8}{3}38​
  4. (D)323\dfrac{32}{3}332​

Correct answer: (D)

Step-by-step solution →
Q66·Mathematics·Sets, Relations and FunctionsSingle correct
If f(x)=4x+36x−4f(x)=\dfrac{4x+3}{6x-4}f(x)=6x−44x+3​, x≠23x\ne\dfrac{2}{3}x=32​ and (f∘f)(x)=g(x)(f\circ f)(x)=g(x)(f∘f)(x)=g(x), where g:R−{23}→R−{23}g:R-\left\{\dfrac{2}{3}\right\}\to R-\left\{\dfrac{2}{3}\right\}g:R−{32​}→R−{32​}, then (g∘g∘g)(4)(g\circ g\circ g)(4)(g∘g∘g)(4) is equal to
  1. (A)−1920-\dfrac{19}{20}−2019​
  2. (B)1920\dfrac{19}{20}2019​
  3. (C)−4-4−4
  4. (D)444

Correct answer: (D)

Step-by-step solution →
Q67·Mathematics·Limits and ContinuitySingle correct
lim⁡x→0e2∣sin⁡x∣−2∣sin⁡x∣−1x2\displaystyle\lim_{x\to 0}\dfrac{e^{2|\sin x|}-2|\sin x|-1}{x^2}x→0lim​x2e2∣sinx∣−2∣sinx∣−1​
  1. (A)is equal to −1-1−1
  2. (B)does not exist
  3. (C)is equal to 111
  4. (D)is equal to 222

Correct answer: (D)

Step-by-step solution →
Q68·Mathematics·Matrices and DeterminantsSingle correct
If the system of linear equations x−2y+z=−4x-2y+z=-4x−2y+z=−4; 2x+αy+3z=52x+\alpha y+3z=52x+αy+3z=5; 3x−y+βz=33x-y+\beta z=33x−y+βz=3 has infinitely many solutions, then 12α+13β12\alpha+13\beta12α+13β is equal to
  1. (A)606060
  2. (B)646464
  3. (C)545454
  4. (D)585858

Correct answer: (D)

Step-by-step solution →
Q69·Mathematics·Differential EquationsSingle correct
The solution curve of the differential equation ydxdy=x(log⁡ex−log⁡ey+1)y\dfrac{dx}{dy}=x\left(\log_e x-\log_e y+1\right)ydydx​=x(loge​x−loge​y+1), x>0, y>0x>0,\ y>0x>0, y>0 passing through the point (e,1)(e,1)(e,1) is
  1. (A)∣log⁡eyx∣=x\left|\log_e\dfrac{y}{x}\right|=x​loge​xy​​=x
  2. (B)∣log⁡eyx∣=y2\left|\log_e\dfrac{y}{x}\right|=y^2​loge​xy​​=y2
  3. (C)∣log⁡exy∣=y\left|\log_e\dfrac{x}{y}\right|=y​loge​yx​​=y
  4. (D)2∣log⁡exy∣=y+12\left|\log_e\dfrac{x}{y}\right|=y+12​loge​yx​​=y+1

Correct answer: (C)

Step-by-step solution →
Q70·Mathematics·Straight LinesSingle correct
Let α,β,γ,δ∈Z\alpha,\beta,\gamma,\delta\in Zα,β,γ,δ∈Z and let A(α,β)A(\alpha,\beta)A(α,β), B(1,0)B(1,0)B(1,0), C(γ,δ)C(\gamma,\delta)C(γ,δ) and D(1,2)D(1,2)D(1,2) be the vertices of a parallelogram ABCD. If AB=10AB=\sqrt{10}AB=10​ and the points A and C lie on the line 3y=2x+13y=2x+13y=2x+1, then 2(α+β+γ+δ)2(\alpha+\beta+\gamma+\delta)2(α+β+γ+δ) is equal to
  1. (A)101010
  2. (B)555
  3. (C)121212
  4. (D)888

Correct answer: (D)

Step-by-step solution →
Q71·Mathematics·Differential EquationsSingle correct
Let y=y(x)y=y(x)y=y(x) be the solution of the differential equation dydx=tan⁡x+ysin⁡x(sec⁡x−sin⁡xtan⁡x)\dfrac{dy}{dx}=\dfrac{\tan x+y}{\sin x(\sec x-\sin x\tan x)}dxdy​=sinx(secx−sinxtanx)tanx+y​, x∈(0,π2)x\in\left(0,\dfrac{\pi}{2}\right)x∈(0,2π​) satisfying the condition y(π4)=2y\left(\dfrac{\pi}{4}\right)=2y(4π​)=2. Then, y(π3)y\left(\dfrac{\pi}{3}\right)y(3π​) is
  1. (A)3(2+log⁡e3)\sqrt{3}\left(2+\log_e\sqrt{3}\right)3​(2+loge​3​)
  2. (B)32(2+log⁡e3)\dfrac{\sqrt{3}}{2}\left(2+\log_e 3\right)23​​(2+loge​3)
  3. (C)3(1+2log⁡e3)\sqrt{3}\left(1+2\log_e 3\right)3​(1+2loge​3)
  4. (D)3(2+log⁡e3)\sqrt{3}\left(2+\log_e 3\right)3​(2+loge​3)

Correct answer: (A)

Step-by-step solution →
Q72·Mathematics·Vector AlgebraSingle correct
Let a⃗=3i^+j^−2k^\vec{a}=3\hat{i}+\hat{j}-2\hat{k}a=3i^+j^​−2k^, b⃗=4i^+j^+7k^\vec{b}=4\hat{i}+\hat{j}+7\hat{k}b=4i^+j^​+7k^ and c⃗=i^−3j^+4k^\vec{c}=\hat{i}-3\hat{j}+4\hat{k}c=i^−3j^​+4k^ be three vectors. If a vector p⃗\vec{p}p​ satisfies p⃗×b⃗=c⃗×b⃗\vec{p}\times\vec{b}=\vec{c}\times\vec{b}p​×b=c×b and p⃗⋅a⃗=0\vec{p}\cdot\vec{a}=0p​⋅a=0, then p⃗⋅(i^−j^−k^)\vec{p}\cdot\left(\hat{i}-\hat{j}-\hat{k}\right)p​⋅(i^−j^​−k^) is equal to
  1. (A)242424
  2. (B)363636
  3. (C)282828
  4. (D)323232

Correct answer: (D)

Step-by-step solution →
Q73·Mathematics·Sequence and SeriesSingle correct
The sum of the series 11−3⋅12+14+21−3⋅22+24+31−3⋅32+34+⋯\dfrac{1}{1-3\cdot 1^2+1^4}+\dfrac{2}{1-3\cdot 2^2+2^4}+\dfrac{3}{1-3\cdot 3^2+3^4}+\cdots1−3⋅12+141​+1−3⋅22+242​+1−3⋅32+343​+⋯ up to 10 terms is
  1. (A)45109\dfrac{45}{109}10945​
  2. (B)−45109-\dfrac{45}{109}−10945​
  3. (C)55109\dfrac{55}{109}10955​
  4. (D)−55109-\dfrac{55}{109}−10955​

Correct answer: (D)

Step-by-step solution →
Q74·Mathematics·Three Dimensional GeometrySingle correct
The distance of the point Q(0,2,−2)Q(0,2,-2)Q(0,2,−2) from the line passing through the point P(5,−4,3)P(5,-4,3)P(5,−4,3) and perpendicular to the lines r⃗=(−3i^+2k^)+λ(2i^+3j^+5k^)\vec{r}=\left(-3\hat{i}+2\hat{k}\right)+\lambda\left(2\hat{i}+3\hat{j}+5\hat{k}\right)r=(−3i^+2k^)+λ(2i^+3j^​+5k^), λ∈R\lambda\in Rλ∈R and r⃗=(i^−2j^+k^)+μ(−i^+3j^+2k^)\vec{r}=\left(\hat{i}-2\hat{j}+\hat{k}\right)+\mu\left(-\hat{i}+3\hat{j}+2\hat{k}\right)r=(i^−2j^​+k^)+μ(−i^+3j^​+2k^), μ∈R\mu\in Rμ∈R is
  1. (A)86\sqrt{86}86​
  2. (B)20\sqrt{20}20​
  3. (C)54\sqrt{54}54​
  4. (D)74\sqrt{74}74​

Correct answer: (D)

Step-by-step solution →
Q75·Mathematics·Inverse Trigonometric FunctionsSingle correct
For α,β,γ≠0\alpha,\beta,\gamma\ne 0α,β,γ=0. If sin⁡−1α+sin⁡−1β+sin⁡−1γ=π\sin^{-1}\alpha+\sin^{-1}\beta+\sin^{-1}\gamma=\pisin−1α+sin−1β+sin−1γ=π and (α+β+γ)(α−γ+β)=3αβ(\alpha+\beta+\gamma)(\alpha-\gamma+\beta)=3\alpha\beta(α+β+γ)(α−γ+β)=3αβ, then γ\gammaγ equal to
  1. (A)32\dfrac{\sqrt{3}}{2}23​​
  2. (B)12\dfrac{1}{\sqrt{2}}2​1​
  3. (C)3−122\dfrac{\sqrt{3}-1}{2\sqrt{2}}22​3​−1​
  4. (D)3\sqrt{3}3​

Correct answer: (A)

Step-by-step solution →
Q76·Mathematics·Statistics and ProbabilitySingle correct
Two marbles are drawn in succession from a box containing 10 red, 30 white, 20 blue and 15 orange marbles, with replacement being made after each drawing. Then the probability, that first drawn marble is red and second drawn marble is white, is
  1. (A)225\dfrac{2}{25}252​
  2. (B)425\dfrac{4}{25}254​
  3. (C)23\dfrac{2}{3}32​
  4. (D)475\dfrac{4}{75}754​

Correct answer: (D)

Step-by-step solution →
Q77·Mathematics·Limits and ContinuitySingle correct
Let g(x)g(x)g(x) be a linear function and f(x)={g(x),x≤0(1+x2+x)1x,x>0f(x)=\begin{cases}g(x), & x\le 0\\ \left(\dfrac{1+x}{2+x}\right)^{\frac{1}{x}}, & x>0\end{cases}f(x)=⎩⎨⎧​g(x),(2+x1+x​)x1​,​x≤0x>0​, is continuous at x=0x=0x=0. If f′(1)=f(−1)f'(1)=f(-1)f′(1)=f(−1), then the value of g(3)g(3)g(3) is
  1. (A)13log⁡e(49e1/3)\dfrac{1}{3}\log_e\left(\dfrac{4}{9e^{1/3}}\right)31​loge​(9e1/34​)
  2. (B)13log⁡e(49)+1\dfrac{1}{3}\log_e\left(\dfrac{4}{9}\right)+131​loge​(94​)+1
  3. (C)log⁡e(49)−1\log_e\left(\dfrac{4}{9}\right)-1loge​(94​)−1
  4. (D)log⁡e(49e1/3)\log_e\left(\dfrac{4}{9e^{1/3}}\right)loge​(9e1/34​)

Correct answer: (D)

Step-by-step solution →
Q78·Mathematics·Matrices and DeterminantsSingle correct
If f(x)=∣x32x2+11+3x3x2+22xx3+6x3−x4x2−2∣f(x)=\begin{vmatrix}x^3 & 2x^2+1 & 1+3x\\ 3x^2+2 & 2x & x^3+6\\ x^3-x & 4 & x^2-2\end{vmatrix}f(x)=​x33x2+2x3−x​2x2+12x4​1+3xx3+6x2−2​​ for all x∈Rx\in Rx∈R, then 2f(0)+f′(0)2f(0)+f'(0)2f(0)+f′(0) is equal to
  1. (A)484848
  2. (B)242424
  3. (C)424242
  4. (D)181818

Correct answer: (C)

Step-by-step solution →
Q79·Mathematics·Statistics and ProbabilitySingle correct
Three rotten apples are accidently mixed with fifteen good apples. Assuming the random variable x to be the number of rotten apples in a draw of two apples, the variance of x is
  1. (A)37153\dfrac{37}{153}15337​
  2. (B)57153\dfrac{57}{153}15357​
  3. (C)47153\dfrac{47}{153}15347​
  4. (D)40153\dfrac{40}{153}15340​

Correct answer: (D)

Step-by-step solution →
Q80·Mathematics·Quadratic EquationsSingle correct
Let S be the set of positive integral values of a for which ax2+2(a+1)x+9a+4x2−8x+32<0\dfrac{ax^2+2(a+1)x+9a+4}{x^2-8x+32}<0x2−8x+32ax2+2(a+1)x+9a+4​<0, ∀x∈R\forall x\in R∀x∈R. Then, the number of elements in S is
  1. (A)111
  2. (B)000
  3. (C)∞\infty∞
  4. (D)333

Correct answer: (B)

Step-by-step solution →
Q81·Mathematics·Definite IntegrationNumerical
If the integral 525∫0π/2sin⁡2xcos⁡11/2x(1+cos⁡5/2x)1/2dx525\displaystyle\int_0^{\pi/2}\sin 2x\cos^{11/2}x\left(1+\cos^{5/2}x\right)^{1/2}dx525∫0π/2​sin2xcos11/2x(1+cos5/2x)1/2dx is equal to (n2−64)\left(n\sqrt{2}-64\right)(n2​−64), then n is equal to ______.

Correct answer: 176

Step-by-step solution →
Q82·Mathematics·Application of DerivativesNumerical
Let S=(−1,∞)S=(-1,\infty)S=(−1,∞) and f:S→Rf:S\to Rf:S→R be defined as f(x)=∫−1x(et−1)11(2t−1)5(t−2)7(t−3)12(2t−10)61dtf(x)=\displaystyle\int_{-1}^x \left(e^t-1\right)^{11}(2t-1)^5(t-2)^7(t-3)^{12}(2t-10)^{61}dtf(x)=∫−1x​(et−1)11(2t−1)5(t−2)7(t−3)12(2t−10)61dt. Let p = Sum of square of the values of x, where f(x)f(x)f(x) attains local maxima on S, and q = Sum of the values of x, where f(x)f(x)f(x) attains local minima on S. Then, the value of p2+2qp^2+2qp2+2q is ______.

Correct answer: 27

Step-by-step solution →
Q83·Mathematics·Permutations and CombinationsNumerical
The total number of words (with or without meaning) that can be formed out of the letters of the word "DISTRIBUTION" taken four at a time, is equal to ______.

Correct answer: 3734

Step-by-step solution →
Q84·Mathematics·Three Dimensional GeometryNumerical
Let Q and R be the feet of perpendiculars from the point P(a,a,a)P(a,a,a)P(a,a,a) on the lines x=yx=yx=y, z=1z=1z=1 and x=−yx=-yx=−y, z=−1z=-1z=−1 respectively. If ∠QPR\angle QPR∠QPR is a right angle, then 12a212a^212a2 is equal to ______.

Correct answer: 12

Step-by-step solution →
Q85·Mathematics·Binomial Theorem and Its Simple ApplicationsNumerical
In the expansion of (1+x)(1−x2)(1+3x+3x2+1x3)5(1+x)\left(1-x^2\right)\left(1+\dfrac{3}{x}+\dfrac{3}{x^2}+\dfrac{1}{x^3}\right)^5(1+x)(1−x2)(1+x3​+x23​+x31​)5, x≠0x\ne 0x=0, the sum of the coefficient of x3x^3x3 and x−13x^{-13}x−13 is equal to ______.

Correct answer: 118

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Q86·Mathematics·Complex NumbersNumerical
If α\alphaα denotes the number of solutions of ∣1−i∣x=2x|1-i|^x=2^x∣1−i∣x=2x and β=∣z∣arg⁡(z)\beta=\dfrac{|z|}{\arg(z)}β=arg(z)∣z∣​, where z=π4(1+i)4[1−πiπ+i+π−i1+πi]z=\dfrac{\pi}{4}(1+i)^4\left[\dfrac{1-\sqrt{\pi}i}{\sqrt{\pi}+i}+\dfrac{\sqrt{\pi}-i}{1+\sqrt{\pi}i}\right]z=4π​(1+i)4[π​+i1−π​i​+1+π​iπ​−i​], i=−1i=\sqrt{-1}i=−1​, then the distance of the point (α,β)(\alpha,\beta)(α,β) from the line 4x−3y=74x-3y=74x−3y=7 is ______.

Correct answer: 3

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Q87·Mathematics·EllipseNumerical
Let the foci and length of the latus rectum of an ellipse x2a2+y2b2=1\dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}=1a2x2​+b2y2​=1, a>ba>ba>b be (±5,0)(\pm 5,0)(±5,0) and 50\sqrt{50}50​ respectively. Then, the square of the eccentricity of the hyperbola x2b2−y2a2b2=1\dfrac{x^2}{b^2}-\dfrac{y^2}{a^2 b^2}=1b2x2​−a2b2y2​=1 equals ______.

Correct answer: 51

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Q88·Mathematics·Vector AlgebraNumerical
Let a⃗\vec{a}a and b⃗\vec{b}b be two vectors such that ∣a⃗∣=1|\vec{a}|=1∣a∣=1, ∣b⃗∣=4|\vec{b}|=4∣b∣=4 and a⃗⋅b⃗=2\vec{a}\cdot\vec{b}=2a⋅b=2. If c⃗=(2a⃗×b⃗)−3b⃗\vec{c}=(2\vec{a}\times\vec{b})-3\vec{b}c=(2a×b)−3b and the angle between b⃗\vec{b}b and c⃗\vec{c}c is α\alphaα, then 192sin⁡2α192\sin^2\alpha192sin2α is equal to ______.

Correct answer: 48

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Q89·Mathematics·Sets, Relations and FunctionsNumerical
Let A={1,2,3,4}A=\{1,2,3,4\}A={1,2,3,4} and R={(1,2),(2,3),(1,4)}R=\{(1,2),(2,3),(1,4)\}R={(1,2),(2,3),(1,4)} be a relation on A. Let S be the equivalence relation on A such that R⊂SR\subset SR⊂S and the number of elements in S is n. Then, the minimum value of n is ______.

Correct answer: 16

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Q90·Mathematics·Definite IntegrationNumerical
Let f:R→Rf:R\to Rf:R→R be a function defined by f(x)=4x4x+2f(x)=\dfrac{4^x}{4^x+2}f(x)=4x+24x​ and M=∫f(a)f(1−a)xsin⁡4(x(1−x))dxM=\displaystyle\int_{f(a)}^{f(1-a)} x\sin^4\left(x(1-x)\right)dxM=∫f(a)f(1−a)​xsin4(x(1−x))dx, N=∫f(a)f(1−a)sin⁡4(x(1−x))dxN=\displaystyle\int_{f(a)}^{f(1-a)}\sin^4\left(x(1-x)\right)dxN=∫f(a)f(1−a)​sin4(x(1−x))dx; a≠12a\ne\dfrac{1}{2}a=21​. If αM=βN\alpha M=\beta NαM=βN, α,β∈N\alpha,\beta\in Nα,β∈N, then the least value of α2+β2\alpha^2+\beta^2α2+β2 is equal to ______.

Correct answer: 5

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Chapters tested in this paper

Open any chapter to practise every past-year question on that topic across all papers, and see how often it has actually appeared.

  • Properties of Solids and Liquids 172/186
  • Three Dimensional Geometry 176/186
  • Matrices and Determinants 180/186
  • Coordination Compounds 176/186
  • Sets, Relations and Functions 165/186
  • Current Electricity 160/186
  • Sequence and Series 164/186
  • p-Block Elements 164/186
  • Definite Integration 168/186
  • Rotational Motion 172/186
  • Redox Reactions and Electrochemistry 177/186
  • Geometrical Optics 172/186
  • Kinematics 156/186
  • Vector Algebra 173/186
  • Differential Equations 167/186
  • Probability 176/186
  • Permutations and Combinations 162/186
  • Magnetic Field of Current 147/186
  • Binomial Theorem and Its Simple Applications 158/186
  • Electromagnetic Waves 144/186
  • Chemical Bonding and Molecular Structure 151/186
  • Application of Derivatives 139/186
  • Limits and Continuity 149/186
  • d- and f-Block Elements 126/186
  • Thermodynamics 154/186
  • Aldehydes and Ketones 135/186
  • Equilibrium 163/186
  • Solutions 158/186
  • Laws of Motion 130/186
  • Units and Measurements 149/186
  • Hydrocarbons 126/186
  • Complex Numbers 165/186
  • Biomolecules 162/186
  • Chemical Kinetics 169/186
  • Gravitation 152/186
  • Electric Field and Coulomb's Law 133/186
  • Atomic Structure 161/186
  • Electronic Devices 145/186
  • Circles 142/186
  • Dual Nature of Matter and Radiation 155/186
  • Quadratic Equations 148/186
  • Work, Energy and Power 132/186
  • Some Basic Concepts in Chemistry 129/186
  • Electromagnetic Induction 120/186
  • Wave Optics 130/186
  • Area Under Curves 139/186
  • Kinetic Theory of Gases 135/186
  • Alcohols and Ethers 106/186
  • Purification and Characterisation of Organic Compounds 116/186
  • Oscillations 117/186
  • Nuclei 116/186
  • Organic Compounds Containing Halogens 109/186
  • Straight Lines 114/186
  • Waves 109/186
  • Capacitors and Dielectrics 115/186
  • Atoms 112/186
  • Classification of Elements and Periodicity in Properties 113/186
  • Ellipse 103/186
  • Inverse Trigonometric Functions 93/186
  • Principles of Qualitative Analysis 58/186
  • IUPAC Nomenclature 37/186
  • Reaction Mechanism 29/186
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