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JEE Main 2 April 2026 Shift 2 Question Paper with Answers

2 April 2026 · April session · 75 questions

The complete JEE Main 2 April 2026 Shift 2 paper — all 75 questions with the correct answer for each, tagged to the chapter it tests. Free to read, no account needed.

Physics
25
Chemistry
25
Mathematics
25

Physics — JEE Main 2 April 2026 Shift 2

Q1·PhysicsSingle correct
Dimensions of universal gravitational constant (G)(G)(G) in terms of Planck's constant (h)(h)(h), distance (L)(L)(L), mass (M)(M)(M) and time (T)(T)(T) are ______.
  1. (A)[hTLM−2][hTLM^{-2}][hTLM−2]
  2. (B)[hT−1LM−2][hT^{-1}LM^{-2}][hT−1LM−2]
  3. (C)[hTL2M−2][hTL^{2}M^{-2}][hTL2M−2]
  4. (D)[h−1T−1LM−2][h^{-1}T^{-1}LM^{-2}][h−1T−1LM−2]

Correct answer: (B)

Step-by-step solution →
Q2·PhysicsSingle correct
A 0.5 kg mass is in contact against the inner wall of a cylindrical drum of radius 4 m rotating about its vertical axis. The minimum rotational speed of the drum to enable the mass to remain stuck to the wall (without falling) is 5 rad/s. The coefficient of friction between the drum's inner wall surface and mass is ______. (Take g=10g = 10g=10 m/s2^{2}2)
  1. (A)0.1
  2. (B)0.5
  3. (C)0.7
  4. (D)0.3

Correct answer: (A)

Step-by-step solution →
Q3·PhysicsSingle correct
Two blocks of masses 2 kg and 1 kg respectively, are tied to the ends of a string which passes over a light frictionless pulley as shown in the figure below. The masses are held at rest at the same horizontal level and then released. The distance traversed by the centre of mass in 2 s is ______ m. (Take g=10g = 10g=10 m/s2^{2}2)
  1. (A)3.33
  2. (B)3.12
  3. (C)2.22
  4. (D)1.42

Correct answer: (C)

Step-by-step solution →
Q4·PhysicsSingle correct
A particle having charge 10−910^{-9}10−9 C moving in xxx-yyy plane in fields of 0.4j^0.4\hat{j}0.4j^​ N/C and 4×10−3k^4 \times 10^{-3}\hat{k}4×10−3k^ T experiences a force of (4i^+2j^)×10−10(4\hat{i} + 2\hat{j}) \times 10^{-10}(4i^+2j^​)×10−10 N. The velocity of the particle at that instant is ______ m/s.
  1. (A)50i^+100j^50\hat{i} + 100\hat{j}50i^+100j^​
  2. (B)100i^+50j^100\hat{i} + 50\hat{j}100i^+50j^​
  3. (C)−50i^+100j^-50\hat{i} + 100\hat{j}−50i^+100j^​
  4. (D)50i^−100j^50\hat{i} - 100\hat{j}50i^−100j^​

Correct answer: (A)

Step-by-step solution →
Q5·PhysicsSingle correct
If XXX and YYY are the inputs, the given circuit works as ______.
  1. (A)OR gate
  2. (B)AND gate
  3. (C)NAND gate
  4. (D)NOR gate

Correct answer: (D)

Step-by-step solution →
Q6·PhysicsSingle correct
If a body of mass 1 kg falls on the earth from infinity, it attains velocity (v)(v)(v) and kinetic energy (k)(k)(k) on reaching the surface of earth. The values of vvv and kkk respectively are ______. (Take radius of earth to be 6400 km and g=9.8g = 9.8g=9.8 m/s2^{2}2)
  1. (A)11.2 km/s; 6.27×1076.27 \times 10^{7}6.27×107 J
  2. (B)11.2 km/s; 12.54×10712.54 \times 10^{7}12.54×107 J
  3. (C)8.8 km/s; 6.27×1076.27 \times 10^{7}6.27×107 J
  4. (D)8.8 km/s; 12.54×10712.54 \times 10^{7}12.54×107 J

Correct answer: (A)

Step-by-step solution →
Q7·PhysicsSingle correct
In a screw gauge the zero of main scale reference line coincides with the fifth division of the circular scale when two studs are in contact. There are 100 divisions in circular scale and pitch of screw gauge is 0.1 mm. When diameter of a sphere is measured, the reading of main scale is 5 mm and 50th50^{\text{th}}50th division of circular scale coincides with the reference line of main scale. The diameter of sphere is ______ mm.
  1. (A)5.045
  2. (B)5.055
  3. (C)5.450
  4. (D)5.550

Correct answer: (A)

Step-by-step solution →
Q8·PhysicsSingle correct
The surface tension of a soap bubble is 0.03 N/m. The work done in increasing the diameter of bubble from 2 cm to 6 cm is απ×10−4\alpha\pi \times 10^{-4}απ×10−4 J. The value of α\alphaα is ______. (Take π=3.14\pi = 3.14π=3.14)
  1. (A)0.86
  2. (B)0.64
  3. (C)1.92
  4. (D)7.68

Correct answer: (C)

Step-by-step solution →
Q9·PhysicsSingle correct
A mixture of carbon dioxide and oxygen has volume 8310 cm3^{3}3, temperature 300 K, pressure 100 kPa and mass 13.2 g. The number of moles of carbon dioxide and oxygen gases in the mixture respectively are ______. (Assume both carbon dioxide and oxygen gases behave like ideal gases) [R=8.31[R = 8.31[R=8.31 J/mol.K]]]
  1. (A)0.15 and 0.18
  2. (B)0.25 and 0.08
  3. (C)0.21 and 0.12
  4. (D)0.13 and 0.20

Correct answer: (C)

Step-by-step solution →
Q10·PhysicsSingle correct
If an air bubble of diameter 2 mm rises steadily through a liquid of density 2000 kg/m3^{3}3 at a rate of 0.5 cm/s, then the coefficient of viscosity of liquid is ______ Poise. (Take g=10g = 10g=10 m/s2^{2}2)
  1. (A)0.88
  2. (B)8.8
  3. (C)88.8
  4. (D)0.088

Correct answer: (B)

Step-by-step solution →
Q11·PhysicsSingle correct
A spherical ball of mass 2 kg falls from a height of 10 m and is brought to rest after penetrating 10 cm into sand. The average force exerted by sand on the ball is ______ N. (Take g=10g = 10g=10 m/s2^{2}2)
  1. (A)1980
  2. (B)2020
  3. (C)2000
  4. (D)1000

Correct answer: (B)

Step-by-step solution →
Q12·PhysicsSingle correct
An electromagnetic wave travels in free space along the xxx-direction. At a particular point in space and time, B⃗=2×10−7j^\vec{B} = 2 \times 10^{-7}\hat{j}B=2×10−7j^​ T is associated with this wave. The value of corresponding electric field E⃗\vec{E}E at this point is ______ V/m.
  1. (A)60k^60\hat{k}60k^
  2. (B)−60k^-60\hat{k}−60k^
  3. (C)30k^30\hat{k}30k^
  4. (D)−600k^-600\hat{k}−600k^

Correct answer: (B)

Step-by-step solution →
Q13·PhysicsSingle correct
Two resistors of 200 Ω200\ \Omega200 Ω and 400 Ω400\ \Omega400 Ω are connected in series with a battery of 100 V. A bulb rated at 200 V, 100 W is connected across the 400 Ω400\ \Omega400 Ω resistance. The potential drop across the bulb is ______ V.
  1. (A)25
  2. (B)50
  3. (C)66.6
  4. (D)100

Correct answer: (B)

Step-by-step solution →
Q14·PhysicsSingle correct
Two metal plates (A,B)(A, B)(A,B) are kept horizontally with separation of (12π)\left(\frac{12}{\pi}\right)(π12​) cm, with plate A on the top. An atomizer jet sprays oil (density 1.5 g/cm3^{3}3) droplets of radius 1 mm horizontally. All oil droplets carry a charge 5 nC. The potentials VAV_AVA​ and VBV_BVB​ are required on plates A and B respectively in order to ensure the droplets do not descend. The values of VAV_AVA​ and VBV_BVB​ are ________. (Neglect the air resistance to the droplets and take g=10g = 10g=10 m/s2^{2}2)
  1. (A)100 V100\,V100V and 580 V580\,V580V
  2. (B)580 V580\,V580V and 100 V100\,V100V
  3. (C)60 V60\,V60V and 400 V400\,V400V
  4. (D)0 V0\,V0V and −200 V-200\,V−200V

Correct answer: (A)

Step-by-step solution →
Q15·PhysicsSingle correct
Two point charges 8 μC8\,\mu C8μC and −2 μC-2\,\mu C−2μC are located at x=2x = 2x=2 cm and x=4x = 4x=4 cm, respectively on the xxx-axis. The ratio of electric flux due to these charges through two spheres of radii 3 cm and 5 cm with their centers at the origin is ________.
  1. (A)4:14 : 14:1
  2. (B)3:43 : 43:4
  3. (C)4:34 : 34:3
  4. (D)4:54 : 54:5

Correct answer: (C)

Step-by-step solution →
Q16·PhysicsSingle correct
One side of an equilateral prism is painted by a transparent material of refractive index n2n_2n2​. The refractive index of prism is 1.6. The minimum value of n2n_2n2​ required for total internal reflection from painted face is ________.
  1. (A)33/1.63\sqrt{3}/1.633​/1.6
  2. (B)3\sqrt{3}3​
  3. (C)3.2/33.2/\sqrt{3}3.2/3​
  4. (D)43/54\sqrt{3}/543​/5

Correct answer: (D)

Step-by-step solution →
Q17·PhysicsSingle correct
The figure given below shows an LCRLCRLCR series circuit with two switches S1S_1S1​ and S2S_2S2​. When switch S1S_1S1​ is closed keeping S2S_2S2​ open, the phase difference (ϕ)(\phi)(ϕ) between the current and source voltage is 30∘30^\circ30∘ and phase difference is 60∘60^\circ60∘ when S2S_2S2​ is closed keeping S1S_1S1​ open. The value of (3L1−L2)(3L_1 - L_2)(3L1​−L2​) is ________ H.
  1. (A)92\frac{9}{2}29​
  2. (B)29\frac{2}{9}92​
  3. (C)13\frac{1}{3}31​
  4. (D)333

Correct answer: (B)

Step-by-step solution →
Q18·PhysicsSingle correct
A circular current loop of radius RRR is placed inside square loop of side length LLL (L>>R)(L >> R)(L>>R) such that they are co-planar and their centers coincide. The permeability of free space is μ0\mu_0μ0​. The mutual inductance between circular loop and square loop is ________.
  1. (A)22 μ0L2R2\sqrt{2}\,\frac{\mu_0 L^2}{R}22​Rμ0​L2​
  2. (B)2 μ0L2R\sqrt{2}\,\frac{\mu_0 L^2}{R}2​Rμ0​L2​
  3. (C)2 μ0R2L\sqrt{2}\,\frac{\mu_0 R^2}{L}2​Lμ0​R2​
  4. (D)22 μ0R2L2\sqrt{2}\,\frac{\mu_0 R^2}{L}22​Lμ0​R2​

Correct answer: (D)

Step-by-step solution →
Q19·PhysicsSingle correct
The binding energy per nucleon of 83209Bi^{209}_{83}Bi83209​Bi is ________ MeV. [[[Take m(83209Bi)=208.980388 um(^{209}_{83}Bi) = 208.980388\,um(83209​Bi)=208.980388u, mp=1.007825 um_p = 1.007825\,ump​=1.007825u, mn=1.008665 um_n = 1.008665\,umn​=1.008665u, 1 u=931 MeV/c2]1\,u = 931\,\mathrm{MeV}/c^2]1u=931MeV/c2]
  1. (A)7.48
  2. (B)7.84
  3. (C)8.79
  4. (D)6.94

Correct answer: (B)

Step-by-step solution →
Q20·PhysicsSingle correct
The equation of motion of a particle is given by x=asin⁡(50t+π3)x = a \sin\left(50t + \frac{\pi}{3}\right)x=asin(50t+3π​) cm. The particle will come to rest at time t1t_1t1​ and it will have zero acceleration at time t2t_2t2​. The t1t_1t1​ and t2t_2t2​ respectively are ________.
  1. (A)π300 s\frac{\pi}{300}\,s300π​s, π75 s\frac{\pi}{75}\,s75π​s
  2. (B)π75 s\frac{\pi}{75}\,s75π​s, π300 s\frac{\pi}{300}\,s300π​s
  3. (C)π300 s\frac{\pi}{300}\,s300π​s, π25 s\frac{\pi}{25}\,s25π​s
  4. (D)π50 s\frac{\pi}{50}\,s50π​s, π100 s\frac{\pi}{100}\,s100π​s

Correct answer: (A)

Step-by-step solution →
Q21·PhysicsNumerical
In a Young's double slit experiment, the intensity at some point on the screen is found to be 34\frac{3}{4}43​ times of the maximum of the interference pattern. The path difference between the interfering waves at this point is λx\frac{\lambda}{x}xλ​ where λ\lambdaλ is wavelength of the incident light. The value of xxx is ________.

Correct answer: 6

Step-by-step solution →
Q22·PhysicsNumerical
Using Bohr's model, calculate the ratio of the magnetic fields generated due to the motion of the electrons in the 2nd2^{nd}2nd and 4th4^{th}4th orbits of hydrogen atom ________.

Correct answer: 32

Step-by-step solution →
Q23·PhysicsNumerical
5 moles of unknown gas is heated at constant volume from 10 ∘C10\,^\circ C10∘C to 20 ∘C20\,^\circ C20∘C. The molar specific heat of this gas at constant pressure cp=8c_p = 8cp​=8 cal/mol.∘^\circ∘C and R=8.36R = 8.36R=8.36 J/mol.∘^\circ∘C. The change in the internal energy of the gas is ________ calorie.

Correct answer: 300

Step-by-step solution →
Q24·PhysicsNumerical
If sunlight is focused on a paper using convex lens, it starts burning the paper in shortest time when the lens is kept at 30 cm above the paper. If the radius of curvature of the lens is 60 cm then the refractive index of the lens material is α10\frac{\alpha}{10}10α​. The value of α\alphaα is ________.

Correct answer: 20

Step-by-step solution →
Q25·PhysicsNumerical
Moment of inertia about an axis ABABAB for a rod of mass 40 kg and length 3 m is same as that of a solid sphere of mass of 10 kg and radius RRR about an axis parallel to ABABAB axis with separation of 3 m as shown in figure below. The value of RRR is given as α2\sqrt{\frac{\alpha}{2}}2α​​. The value of α\alphaα is ________.

Correct answer: 15

Step-by-step solution →

Chemistry — JEE Main 2 April 2026 Shift 2

Q26·ChemistrySingle correct
The ratio of mass percentage (w/w) of C : H in a hydrocarbon is 12 : 1. It has two carbon atoms. The weight (in g) of CO2(g)CO_2(g)CO2​(g) formed when 3.38 g of this hydrocarbon is completely burnt in oxygen is : (Given : Molar mass in g mol−1^{-1}−1 C : 12, H : 1, O : 16)
  1. (A)5.68
  2. (B)11.44
  3. (C)22.74
  4. (D)17.05

Correct answer: (B)

Step-by-step solution →
Q27·ChemistrySingle correct
The first and second ionization constants of a weak dibasic acid H2AH_2AH2​A are 8.1×10−88.1 \times 10^{-8}8.1×10−8 and 1.0×10−131.0 \times 10^{-13}1.0×10−13 respectively. 0.1 mol of H2AH_2AH2​A was dissolved in 1 L of 0.1 M HCl solution. The concentration of HA−HA^-HA− in the resultant solution is:
  1. (A)0.1 M
  2. (B)9.53×10−69.53 \times 10^{-6}9.53×10−6 M
  3. (C)8.1×10−88.1 \times 10^{-8}8.1×10−8 M
  4. (D)1.0×10−131.0 \times 10^{-13}1.0×10−13 M

Correct answer: (C)

Step-by-step solution →
Q28·ChemistrySingle correct
SF4SF_4SF4​ is isostructural with: A. BrF4⊖BrF_4^{\ominus}BrF4⊖​ B. CH4CH_4CH4​ C. IF4⊕IF_4^{\oplus}IF4⊕​ D. XeF4XeF_4XeF4​ E. XeO2F2XeO_2F_2XeO2​F2​ Choose the correct answer from the options given below:
  1. (A)C Only
  2. (B)C and E Only
  3. (C)A and D Only
  4. (D)B and E Only

Correct answer: (B)

Step-by-step solution →
Q29·ChemistrySingle correct
Gas 'A' undergoes change from state 'X' to state 'Y'. In this process, the heat absorbed and work done by the gas is 10 J and 18 J respectively. Now gas is brought back to state 'X' by another process during which 6 J of heat is evolved. In the reverse process of 'Y' to 'X',
  1. (A)18 J of the work is done by the gas 'A'.
  2. (B)2 J of the work is done by the gas 'A'.
  3. (C)12 J of the work is done on the gas 'A' by the surrounding.
  4. (D)14 J of the work is done on the gas 'A' by the surrounding.

Correct answer: (D)

Step-by-step solution →
Q30·ChemistrySingle correct
Solution A is prepared by dissolving 1 g of a protein (molar mass = 50000 g mol−1^{-1}−1) in 0.5 L of water at 300 K. Its osmotic pressure is xxx bar. Solution B is made by dissolving 2 g of same protein in 1 L of water at 300 K. Osmotic pressure of solution B is yyy bar. Entire solution of A is mixed with entire solution of B at same temperature. The osmotic pressure of resultant solution is zzz bar. x,yx, yx,y and zzz respectively are: (R=0.083(R = 0.083(R=0.083 L bar mol−1^{-1}−1 K−1)^{-1})−1)
  1. (A)9.96×10−49.96 \times 10^{-4}9.96×10−4; 9.96×10−49.96 \times 10^{-4}9.96×10−4; 9.96×10−49.96 \times 10^{-4}9.96×10−4
  2. (B)9.96×10−49.96 \times 10^{-4}9.96×10−4; 9.96×10−49.96 \times 10^{-4}9.96×10−4; 19.92×10−419.92 \times 10^{-4}19.92×10−4
  3. (C)4.98×10−44.98 \times 10^{-4}4.98×10−4; 4.98×10−44.98 \times 10^{-4}4.98×10−4; 9.96×10−49.96 \times 10^{-4}9.96×10−4
  4. (D)4.98×10−44.98 \times 10^{-4}4.98×10−4; 4.98×10−44.98 \times 10^{-4}4.98×10−4; 4.98×10−44.98 \times 10^{-4}4.98×10−4

Correct answer: (A)

Step-by-step solution →
Q31·ChemistrySingle correct
At 25∘C25^{\circ}C25∘C, 20.0 mL of 0.2 M weak monoprotic acid HX is titrated against 0.2 M NaOH. The pH of the solution (a) at the start of the titration (when NaOH has not been added) and (b) when 10 mL of NaOH is added respectively, are: Given: Ka=5×10−4K_a = 5 \times 10^{-4}Ka​=5×10−4, pKa=3.3pK_a = 3.3pKa​=3.3, α<<1\alpha << 1α<<1
  1. (A)(a) 0.7 (b) 2.0
  2. (B)(a) 2.0 (b) 3.3
  3. (C)(a) 1.1 (b) 2.2
  4. (D)(a) 3.0 (b) 2.2

Correct answer: (B)

Step-by-step solution →
Q32·ChemistrySingle correct
Consider the reaction aX→bYaX \rightarrow bYaX→bY, for which the rate constant at 30∘C30^{\circ}C30∘C is 1×10−31 \times 10^{-3}1×10−3 mol−1^{-1}−1 L s−1^{-1}−1. Which of the following statements are true? A. When concentration of 'X' is increased to four times, the rate of reaction becomes 16 times. B. The reaction is a second order reaction. C. The half-life period is independent of the concentration of X. D. Decomposition of N2O5N_2O_5N2​O5​ is an example of the above reaction. E. ln⁡[Ro][R]\ln \frac{[R_o]}{[R]}ln[R][Ro​]​ vs time is valid for the above reaction. Choose the correct answer from the options given below:
  1. (A)A and B Only
  2. (B)A, B and C Only
  3. (C)A, B, D and E Only
  4. (D)C and D Only

Correct answer: (A)

Step-by-step solution →
Q33·ChemistrySingle correct
The correct set that contains all kinds (basic, acidic, amphoteric and neutral) of oxides is:
  1. (A)Na2ONa_2ONa2​O, K2OK_2OK2​O, Al2O3Al_2O_3Al2​O3​ and As2O3As_2O_3As2​O3​
  2. (B)Al2O3Al_2O_3Al2​O3​, As2O3As_2O_3As2​O3​, COCOCO and NONONO
  3. (C)K2OK_2OK2​O, Cl2O7Cl_2O_7Cl2​O7​, As2O3As_2O_3As2​O3​ and NONONO
  4. (D)Na2ONa_2ONa2​O, N2ON_2ON2​O, Al2O3Al_2O_3Al2​O3​ and COCOCO

Correct answer: (C)

Step-by-step solution →
Q34·ChemistrySingle correct
Given below are two statements: Statement I: The second ionization enthalpy of B, Al and Ga is in the order of B>Al>GaB > Al > GaB>Al>Ga. Statement II: The correct order in terms of first ionization enthalpy is Si<Ge<Pb<SnSi < Ge < Pb < SnSi<Ge<Pb<Sn. In the light of the above statements, choose the correct answer from the options given below:
  1. (A)Both Statement I and Statement II are true
  2. (B)Both Statement I and Statement II are false
  3. (C)Statement I is true but Statement II is false
  4. (D)Statement I is false but Statement II is true

Correct answer: (B)

Step-by-step solution →
Q35·ChemistrySingle correct
Given below are two statements: Statement I: Among ZnZnZn, MnMnMn, ScScSc and CuCuCu, the energy required to remove the third valence electron is highest for ZnZnZn and lowest for ScScSc. Statement II: The correct order of the following complexes in terms of CFSE is [Co(H2O)6]2+<[Co(H2O)6]3+<[Co(en)3]3+[Co(H_2O)_6]^{2+} < [Co(H_2O)_6]^{3+} < [Co(en)_3]^{3+}[Co(H2​O)6​]2+<[Co(H2​O)6​]3+<[Co(en)3​]3+. In the light of the above statements, choose the correct answer from the options given below:
  1. (A)Both Statement I and Statement II are true
  2. (B)Both Statement I and Statement II are false
  3. (C)Statement I is true but Statement II is false
  4. (D)Statement I is false but Statement II is true

Correct answer: (A)

Step-by-step solution →
Q36·ChemistrySingle correct
Which of the following complexes will show coordination isomerism? A. [Ag(NH3)2][Ag(CN)2][Ag(NH_3)_2][Ag(CN)_2][Ag(NH3​)2​][Ag(CN)2​] B. [Co(NH3)6][Cr(CN)6][Co(NH_3)_6][Cr(CN)_6][Co(NH3​)6​][Cr(CN)6​] C. [Co(NH3)6][Co(CN)6][Co(NH_3)_6][Co(CN)_6][Co(NH3​)6​][Co(CN)6​] D. [Fe(NH3)6][Co(CN)6][Fe(NH_3)_6][Co(CN)_6][Fe(NH3​)6​][Co(CN)6​] E. [Co(NH3)6][Fe(CN)6][Co(NH_3)_6][Fe(CN)_6][Co(NH3​)6​][Fe(CN)6​] Choose the correct answer from the options given below:
  1. (A)B, C and D Only
  2. (B)B, D and E Only
  3. (C)A, C and D Only
  4. (D)C, D and E Only

Correct answer: (B)

Step-by-step solution →
Q37·ChemistrySingle correct
Complete combustion of XXX g of an organic compound gave 0.25 g of CO2CO_2CO2​ and 0.12 g of H2OH_2OH2​O. If the % of carbon is 25% and of hydrogen is 4.89%, then X=X = X= _____ ×10−3\times 10^{-3}×10−3 g. (Nearest integer) (Molar mass of C, H and O are 12,112, 112,1 and 16 g mol−1^{-1}−1 respectively.)
  1. (A)273
  2. (B)27
  3. (C)2730
  4. (D)227

Correct answer: (A)

Step-by-step solution →
Q38·Chemistry·Electronic Effects and StabilitySingle correct
Given below are two statements: Statement I: In O2N-C6H4-CH⊕-C6H4-OCH3O_2N\text{-}C_6H_4\text{-}CH^{\oplus}\text{-}C_6H_4\text{-}OCH_3O2​N-C6​H4​-CH⊕-C6​H4​-OCH3​, the carbocation is stabilised by +R+R+R effect of −OCH3-OCH_3−OCH3​ group. Statement II: In O2N-C6H4-CH⊖-C6H4-OCH3O_2N\text{-}C_6H_4\text{-}CH^{\ominus}\text{-}C_6H_4\text{-}OCH_3O2​N-C6​H4​-CH⊖-C6​H4​-OCH3​, the carbanion is stabilised by −R-R−R effect of −NO2-NO_2−NO2​ group. In the light of the above statements, choose the correct answer from the options given below:
  1. (A)Both Statement I and Statement II are true
  2. (B)Both Statement I and Statement II are false
  3. (C)Statement I is true but Statement II is false
  4. (D)Statement I is false but Statement II is true

Correct answer: (A)

Step-by-step solution →
Q39·ChemistrySingle correct
The compound (X) on (i) on heating in the presence of anhydrous AlCl3AlCl_3AlCl3​ and HCl gas gives 2,4-dimethyl pentane (ii) aromatization gives toluene and (iii) cyclisation gives methyl cyclohexane The correct name of compound (X) is:
  1. (A)Hept-2-ene
  2. (B)Hept-1,3,5-triene
  3. (C)Heptane
  4. (D)Hept-2,4,6-triene

Correct answer: (C)

Step-by-step solution →
Q40·ChemistrySingle correct
Correct statements regarding alkyl halides (R−X)(R - X)(R−X) among the following are: A. Alcohol being less polar solvent as compared to water, alcoholic KOH favours elimination reaction with R−XR - XR−X. B. Order of reactivity towards SN1S_N^1SN1​ mechanism is C6H5−CH2−Cl>C6H5−CHCl−C6H5C_6H_5 - CH_2 - Cl > C_6H_5 - CHCl - C_6H_5C6​H5​−CH2​−Cl>C6​H5​−CHCl−C6​H5​. C. Non substituted aryl halides exhibit properties similar to alkyl halides. D. Vinyl chloride is an example of haloalkene and allyl chloride is an example of haloalkyne. E. R−ClR - ClR−Cl can be prepared by reacting R−OHR - OHR−OH with SOCl2SOCl_2SOCl2​ but Ar−ClAr - ClAr−Cl cannot be prepared by reacting Ar−OHAr - OHAr−OH with SOCl2SOCl_2SOCl2​. Choose the correct answer from the options given below:
  1. (A)A, B and C Only
  2. (B)B and D Only
  3. (C)A and E Only
  4. (D)D and E Only

Correct answer: (C)

Step-by-step solution →
Q41·ChemistrySingle correct
An organic compound "xxx" where molar ratio of C, O and H are equal, on treatment with 50% KOH under reflux followed by acidification produced "yyy". The most likely structure of "yyy" is: [Molar mass of 'xxx' is 58 g mol−1^{-1}−1]
  1. (A)CH2=CH−C∣∣O−OHCH_2 = CH - \overset{O}{\overset{||}{C}} - OHCH2​=CH−C∣∣O−OH
  2. (B)CH3−CH=CH−CH=OCH_3 - CH = CH - CH = OCH3​−CH=CH−CH=O
  3. (C)O=C−OH,CH2−OHO = C - OH, CH_2 - OHO=C−OH,CH2​−OH (with C-C bond)
  4. (D)CH3−C∣∣O−OHCH_3 - \overset{O}{\overset{||}{C}} - OHCH3​−C∣∣O−OH

Correct answer: (C)

Step-by-step solution →
Q42·ChemistrySingle correct
A molecule (X) with following structure under mild acidic condition is hydrolysed to produce (Y) and (Z). Identify the correct statements about (Y) and (Z). A. Both (Y) and (Z) have same molar mass. B. (Y) and (Z) can be distinguished from each other by NaHCO3NaHCO_3NaHCO3​. C. (Y) and (Z) react with HCN with same rates. D. (Y) and (Z) undergo addition reaction with 2,4-DNP. Choose the correct answer from the options given below:
  1. (A)A, B and C Only
  2. (B)B and C Only
  3. (C)C and D Only
  4. (D)A and D Only

Correct answer: (D)

Step-by-step solution →
Q43·ChemistrySingle correct
Identify compounds A and E in the following reaction sequence.
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (B)

Step-by-step solution →
Q44·ChemistrySingle correct
Identify the correct pair having amino acid (A) and the hormone (B) that is iodinated derivative of the amino acid (A). (T and Y represent one letter code for amino acids)
  1. (A)T Insulin
  2. (B)T Thyroxine
  3. (C)Y Thyroxine
  4. (D)Y Insulin

Correct answer: (C)

Step-by-step solution →
Q45·ChemistrySingle correct
Among Fe2+,Fe3+,Cr2+Fe^{2+}, Fe^{3+}, Cr^{2+}Fe2+,Fe3+,Cr2+ and Zn2+Zn^{2+}Zn2+, the ion that shows positive borax bead test and with highest ionisation enthalpy is:
  1. (A)Fe2+Fe^{2+}Fe2+
  2. (B)Zn2+Zn^{2+}Zn2+
  3. (C)Cr2+Cr^{2+}Cr2+
  4. (D)Fe3+Fe^{3+}Fe3+

Correct answer: (D)

Step-by-step solution →
Q46·ChemistryNumerical
The surface of sodium metal is irradiated with radiation of wavelength xxx nm. The kinetic energy of ejected electrons is 2.8×10−202.8 \times 10^{-20}2.8×10−20 J. The work function of sodium is 2.3 eV. The value of xxx is _______ ×102\times 10^2×102 nm. (Nearest integer) (Given: h=6.6×10−34h = 6.6 \times 10^{-34}h=6.6×10−34 J s; 1 eV =1.6×10−19= 1.6 \times 10^{-19}=1.6×10−19 J; c=3.0×108c = 3.0 \times 10^8c=3.0×108 m s−1^{-1}−1)

Correct answer: 5

Step-by-step solution →
Q47·ChemistryNumerical
Consider the following gas phase reaction being carried out in a closed vessel at 25∘C25^\circ C25∘C. 2A(g)→4B(g)+C(g)2A(g) \rightarrow 4B(g) + C(g)2A(g)→4B(g)+C(g) The pressure of C(g)C(g)C(g) at 30 minutes time interval would be ________ mm Hg. (nearest integer)
time (min)total pressure of the system (mm Hg)
30300
∞\infty∞600

Correct answer: 20

Step-by-step solution →
Q48·ChemistryNumerical
Consider the following two half-cell reactions along with the standard reduction potential given: CO2+6H++6e−→CH3OH+H2OCO_2 + 6H^+ + 6e^- \rightarrow CH_3OH + H_2OCO2​+6H++6e−→CH3​OH+H2​O Ered∘=0.02E^\circ_{red} = 0.02Ered∘​=0.02 V 12O2+2H++2e−→H2O\frac{1}{2}O_2 + 2H^+ + 2e^- \rightarrow H_2O21​O2​+2H++2e−→H2​O Ered∘=1.23E^\circ_{red} = 1.23Ered∘​=1.23 V A fuel cell was set up using the above two reactions such that the cell operates under the standard condition of 1 bar pressure and 298 K temperature. The fuel cell works with 80% efficiency. If the work derived from the cell using 1 mol of CH3OHCH_3OHCH3​OH is used to compress an ideal gas isothermally against a constant pressure of 1 kPa, then the change in the volume of the gas, ΔV=\Delta V =ΔV= ______ m3^33. (nearest integer) Given: F=96500F = 96500F=96500 C mol−1^{-1}−1

Correct answer: 560

Step-by-step solution →
Q49·ChemistryNumerical
Number of paramagnetic ions among the following d- and f-block metal ions is ________. Mn2+,Cu2+,Zn2+,Yb2+,Sc3+,La3+,Gd3+,Lu3+,Ti4+,Ce4+Mn^{2+}, Cu^{2+}, Zn^{2+}, Yb^{2+}, Sc^{3+}, La^{3+}, Gd^{3+}, Lu^{3+}, Ti^{4+}, Ce^{4+}Mn2+,Cu2+,Zn2+,Yb2+,Sc3+,La3+,Gd3+,Lu3+,Ti4+,Ce4+ (Atomic number of Mn=25,Cu=29,Zn=30,Yb=70,Sc=21,La=57,Gd=64,Lu=71,Ti=22,Ce=58Mn = 25, Cu = 29, Zn = 30, Yb = 70, Sc = 21, La = 57, Gd = 64, Lu = 71, Ti = 22, Ce = 58Mn=25,Cu=29,Zn=30,Yb=70,Sc=21,La=57,Gd=64,Lu=71,Ti=22,Ce=58)

Correct answer: 3

Step-by-step solution →
Q50·ChemistryNumerical
Consider the following reactions sequence When the product (P) is subjected to Carius analysis using AgNO3AgNO_3AgNO3​, 1.0 g of the product (P) will produce ________ g of the precipitate of AgBr. (Nearest Integer) (Given: molar mass in g mol−1^{-1}−1 C : 12, H : 1, O : 16, N : 14, Br : 80, Ag : 108)

Correct answer: 1

Step-by-step solution →

Mathematics — JEE Main 2 April 2026 Shift 2

Q51·MathematicsSingle correct
Let α,β\alpha, \betaα,β be the roots of the equation x2−3x+r=0x^2 - 3x + r = 0x2−3x+r=0, and α2,2β\frac{\alpha}{2}, 2\beta2α​,2β be the roots of the equation x2+3x+r=0x^2 + 3x + r = 0x2+3x+r=0. If the roots of the equation x2+6x=mx^2 + 6x = mx2+6x=m are 2α+β+2r2\alpha + \beta + 2r2α+β+2r and α−2β−r2\alpha - 2\beta - \frac{r}{2}α−2β−2r​, then mmm is equal to:
  1. (A)−135-135−135
  2. (B)−567-567−567
  3. (C)135135135
  4. (D)567567567

Correct answer: (D)

Step-by-step solution →
Q52·MathematicsSingle correct
Let the circles C1:∣z∣=rC_1 : |z| = rC1​:∣z∣=r and C2:∣z−3−4i∣=5C_2 : |z - 3 - 4i| = 5C2​:∣z−3−4i∣=5, z∈Cz \in \mathbb{C}z∈C, be such that C2C_2C2​ lies within C1C_1C1​. If z1z_1z1​ moves on C1C_1C1​, z2z_2z2​ moves on C2C_2C2​ and min⁡∣z1−z2∣=2\min |z_1 - z_2| = 2min∣z1​−z2​∣=2, then max⁡∣z1−z2∣\max |z_1 - z_2|max∣z1​−z2​∣ is equal to:
  1. (A)121212
  2. (B)171717
  3. (C)222222
  4. (D)242424

Correct answer: (C)

Step-by-step solution →
Q53·MathematicsSingle correct
If the system of equations x+5y+6z=4x + 5y + 6z = 4x+5y+6z=4, 2x+3y+4z=72x + 3y + 4z = 72x+3y+4z=7, x+6y+az=bx + 6y + az = bx+6y+az=b has infinitely many solutions, then the point (a,b)(a, b)(a,b) lies on the line
  1. (A)y−x=3y - x = 3y−x=3
  2. (B)x−y=3x - y = 3x−y=3
  3. (C)x+y=11x + y = 11x+y=11
  4. (D)x+y=12x + y = 12x+y=12

Correct answer: (B)

Step-by-step solution →
Q54·MathematicsSingle correct
Let a1,a2,a3,…a_1, a_2, a_3, \ldotsa1​,a2​,a3​,… be an A.P. and g1=a1,g2,g3,…g_1 = a_1, g_2, g_3, \ldotsg1​=a1​,g2​,g3​,… be an increasing G.P. If a1=a2+g2=1a_1 = a_2 + g_2 = 1a1​=a2​+g2​=1 and a3+g3=4a_3 + g_3 = 4a3​+g3​=4, then a10+g5a_{10} + g_5a10​+g5​ is equal to:
  1. (A)818181
  2. (B)767676
  3. (C)626262
  4. (D)555555

Correct answer: (D)

Step-by-step solution →
Q55·MathematicsSingle correct
The sum 131+13+231+3+13+23+331+3+5+⋯\frac{1^3}{1} + \frac{1^3 + 2^3}{1 + 3} + \frac{1^3 + 2^3 + 3^3}{1 + 3 + 5} + \cdots113​+1+313+23​+1+3+513+23+33​+⋯ up to 8 terms, is:
  1. (A)707070
  2. (B)717171
  3. (C)727272
  4. (D)737373

Correct answer: (B)

Step-by-step solution →
Q56·MathematicsSingle correct
If for 3≤r≤303 \leq r \leq 303≤r≤30, (3030−r)+3(3031−r)+3(3032−r)+(3033−r)=(mr)\binom{30}{30-r} + 3\binom{30}{31-r} + 3\binom{30}{32-r} + \binom{30}{33-r} = \binom{m}{r}(30−r30​)+3(31−r30​)+3(32−r30​)+(33−r30​)=(rm​), then mmm equals:
  1. (A)313131
  2. (B)323232
  3. (C)333333
  4. (D)343434

Correct answer: (C)

Step-by-step solution →
Q57·MathematicsSingle correct
Let pnp_npn​ denote the total number of triangles formed by joining the vertices of an nnn-side regular polygon. If pn+1−pn=66p_{n+1} - p_n = 66pn+1​−pn​=66, then the sum of all distinct prime divisors of nnn is:
  1. (A)777
  2. (B)888
  3. (C)555
  4. (D)666

Correct answer: (C)

Step-by-step solution →
Q58·MathematicsSingle correct
A man throws a fair coin repeatedly. He gets 10 points for each head he throws and 5 points for each tail he throws. If the probability that he gets exactly 30 points is mn\frac{m}{n}nm​, gcd⁡(m,n)=1\gcd(m, n) = 1gcd(m,n)=1, then m+nm + nm+n is equal to:
  1. (A)535353
  2. (B)555555
  3. (C)107107107
  4. (D)105105105

Correct answer: (C)

Step-by-step solution →
Q59·MathematicsSingle correct
The mean and variance of nnn observations are 8 and 16, respectively. If the sum of the first (n−1)(n - 1)(n−1) observations is 48 and the sum of squares of the first (n−1)(n - 1)(n−1) observations is 496, then the value of nnn is:
  1. (A)212121
  2. (B)161616
  3. (C)131313
  4. (D)777

Correct answer: (D)

Step-by-step solution →
Q60·MathematicsSingle correct
Let a circle pass through the origin and its centre be the point of intersection of two mutually perpendicular lines x+(k−1)y+3=0x + (k - 1)y + 3 = 0x+(k−1)y+3=0 and 2x+k2y−4=02x + k^2y - 4 = 02x+k2y−4=0. If the line x−y+2=0x - y + 2 = 0x−y+2=0 intersects the circle at the points A and B, then (AB)2(AB)^2(AB)2 is equal to:
  1. (A)101010
  2. (B)272727
  3. (C)181818
  4. (D)343434

Correct answer: (C)

Step-by-step solution →
Q61·MathematicsSingle correct
Let O be the origin, and P and Q be two points on the rectangular hyperbola xy=12xy = 12xy=12 such that the mid point of the line segment PQ is (12,−12)\left(\frac{1}{2}, -\frac{1}{2}\right)(21​,−21​). Then the area of the triangle OPQ equals:
  1. (A)32\frac{3}{2}23​
  2. (B)52\frac{5}{2}25​
  3. (C)72\frac{7}{2}27​
  4. (D)92\frac{9}{2}29​

Correct answer: (C)

Step-by-step solution →
Q62·MathematicsSingle correct
Let the parabola y=x2+px+qy = x^2 + px + qy=x2+px+q passing through the point (1,−1)(1, -1)(1,−1) be such that the distance between its vertex and the xxx-axis is minimum. Then the value of p2+q2p^2 + q^2p2+q2 is:
  1. (A)222
  2. (B)444
  3. (C)555
  4. (D)888

Correct answer: (B)

Step-by-step solution →
Q63·MathematicsSingle correct
Let P={θ∈[0,4π]:tan⁡2θ≠1}P = \{\theta \in [0, 4\pi] : \tan^2\theta \neq 1\}P={θ∈[0,4π]:tan2θ=1} and S={a∈Z:2(cos⁡8θ−sin⁡8θ)sec⁡2θ=a2,θ∈P}S = \{a \in \mathbb{Z} : 2(\cos^8\theta - \sin^8\theta)\sec 2\theta = a^2, \theta \in P\}S={a∈Z:2(cos8θ−sin8θ)sec2θ=a2,θ∈P}. Then n(S)n(S)n(S) is:
  1. (A)000
  2. (B)111
  3. (C)222
  4. (D)333

Correct answer: (A)

Step-by-step solution →
Q64·MathematicsSingle correct
Let the vectors a⃗=−i^+j^+3k^\vec{a} = -\hat{i} + \hat{j} + 3\hat{k}a=−i^+j^​+3k^ and b⃗=i^+3j^+k^\vec{b} = \hat{i} + 3\hat{j} + \hat{k}b=i^+3j^​+k^. For some λ,μ∈R\lambda, \mu \in \mathbb{R}λ,μ∈R, let c⃗=λa⃗+μb⃗\vec{c} = \lambda\vec{a} + \mu\vec{b}c=λa+μb. If c⃗⋅(3i^−6j^+2k^)=10\vec{c} \cdot (3\hat{i} - 6\hat{j} + 2\hat{k}) = 10c⋅(3i^−6j^​+2k^)=10 and c⃗⋅(i^+j^+k^)=−2\vec{c} \cdot (\hat{i} + \hat{j} + \hat{k}) = -2c⋅(i^+j^​+k^)=−2, then ∣c⃗∣2|\vec{c}|^2∣c∣2 is equal to:
  1. (A)888
  2. (B)121212
  3. (C)141414
  4. (D)151515

Correct answer: (B)

Step-by-step solution →
Q65·MathematicsSingle correct
Let the point A be the foot of perpendicular drawn from the point P(a,b,0)P(a, b, 0)P(a,b,0) on the line x−12=y−21=z−α3\frac{x-1}{2} = \frac{y-2}{1} = \frac{z-\alpha}{3}2x−1​=1y−2​=3z−α​. If the midpoint of the line segment PA is (0,34,−14)\left(0, \frac{3}{4}, \frac{-1}{4}\right)(0,43​,4−1​), then the value of a2+b2+α2a^2 + b^2 + \alpha^2a2+b2+α2 is equal to:
  1. (A)111
  2. (B)222
  3. (C)666
  4. (D)999

Correct answer: (A)

Step-by-step solution →
Q66·MathematicsSingle correct
Two adjacent sides of a parallelogram PQRS are given by PQ⃗=j^+k^\vec{PQ} = \hat{j} + \hat{k}PQ​=j^​+k^ and PS⃗=i^−j^\vec{PS} = \hat{i} - \hat{j}PS=i^−j^​. If the side PS is rotated about the point P by an acute angle α\alphaα in the plane of the parallelogram so that it becomes perpendicular to the side PQ, then sin⁡2(5α2)−sin⁡2(α2)\sin^2\left(\frac{5\alpha}{2}\right) - \sin^2\left(\frac{\alpha}{2}\right)sin2(25α​)−sin2(2α​) is equal to:
  1. (A)12\frac{1}{2}21​
  2. (B)32\frac{\sqrt{3}}{2}23​​
  3. (C)34\frac{\sqrt{3}}{4}43​​
  4. (D)235\frac{2\sqrt{3}}{5}523​​

Correct answer: (B)

Step-by-step solution →
Q67·MathematicsSingle correct
The value of ∫020π(sin⁡4x+cos⁡4x) dx\int_0^{20\pi} (\sin^4 x + \cos^4 x)\, dx∫020π​(sin4x+cos4x)dx is equal to:
  1. (A)15π2\frac{15\pi}{2}215π​
  2. (B)25π25\pi25π
  3. (C)15π15\pi15π
  4. (D)25π2\frac{25\pi}{2}225π​

Correct answer: (C)

Step-by-step solution →
Q68·MathematicsSingle correct
Let f(x)f(x)f(x) be a polynomial of degree 5, and have extrema at x=1x = 1x=1 and x=−1x = -1x=−1. If lim⁡x→0(f(x)x3)=−5\lim_{x \to 0} \left(\frac{f(x)}{x^3}\right) = -5limx→0​(x3f(x)​)=−5, then f(2)−f(−2)f(2) - f(-2)f(2)−f(−2) is equal to:
  1. (A)000
  2. (B)505050
  3. (C)929292
  4. (D)112112112

Correct answer: (D)

Step-by-step solution →
Q69·MathematicsSingle correct
Let f(x)=∫(16x+24x2+2x−15)dxf(x) = \int \left(\frac{16x + 24}{x^2 + 2x - 15}\right) dxf(x)=∫(x2+2x−1516x+24​)dx. If f(4)=14log⁡e(3)f(4) = 14 \log_e(3)f(4)=14loge​(3) and f(7)=log⁡e(2α⋅3β)f(7) = \log_e(2^{\alpha} \cdot 3^{\beta})f(7)=loge​(2α⋅3β), α,β∈N\alpha, \beta \in \mathbb{N}α,β∈N, then α+β\alpha + \betaα+β is equal to:
  1. (A)313131
  2. (B)373737
  3. (C)393939
  4. (D)414141

Correct answer: (C)

Step-by-step solution →
Q70·MathematicsSingle correct
Let x=x(y)x = x(y)x=x(y) be the solution of the differential equation 2y2dxdy−2xy+x2=02y^2 \frac{dx}{dy} - 2xy + x^2 = 02y2dydx​−2xy+x2=0, y>1y > 1y>1, x(e)=ex(e) = ex(e)=e. Then x(e2)x(e^2)x(e2) is equal to:
  1. (A)32e2\frac{3}{2}e^223​e2
  2. (B)23e2\frac{2}{3}e^232​e2
  3. (C)e2e^2e2
  4. (D)2e22e^22e2

Correct answer: (B)

Step-by-step solution →
Q71·MathematicsNumerical
Let A={2,3,4,5,6}A = \{2, 3, 4, 5, 6\}A={2,3,4,5,6}. Let R be a relation on the set A×AA \times AA×A given by (x,y)R(z,w)(x, y)R(z, w)(x,y)R(z,w) if and only if xxx divides zzz and y≤wy \le wy≤w. Then the number of elements in R is ________.

Correct answer: 120

Step-by-step solution →
Q72·MathematicsNumerical
Consider the matrices A=[2−24−2]A = \begin{bmatrix} 2 & -2 \\ 4 & -2 \end{bmatrix}A=[24​−2−2​] and B=[3913]B = \begin{bmatrix} 3 & 9 \\ 1 & 3 \end{bmatrix}B=[31​93​]. If matrices P and Q are such that PA=BPA = BPA=B and AQ=BAQ = BAQ=B, then the absolute value of the sum of the diagonal elements of 2(P+Q)2(P + Q)2(P+Q) is ________.

Correct answer: 34

Step-by-step solution →
Q73·MathematicsNumerical
Let A be the point (3,0)(3, 0)(3,0) and circles with variable diameter AB touch the circle x2+y2=36x^2 + y^2 = 36x2+y2=36 internally. Let the curve C be the locus of the point B. If the eccentricity of C is eee, then 72e272e^272e2 is equal to ________.

Correct answer: 18

Step-by-step solution →
Q74·MathematicsNumerical
If the area of the region bounded by 16x2−9y2=14416x^2 - 9y^2 = 14416x2−9y2=144 and 8x−3y=248x - 3y = 248x−3y=24 is A, then 3(A+6log⁡e(3))3(A + 6\log_e(3))3(A+6loge​(3)) is equal to ________.

Correct answer: 24

Step-by-step solution →
Q75·MathematicsNumerical
The number of points in the interval [2,4][2, 4][2,4], at which the function f(x)=[x2−x−12]f(x) = \left[x^2 - x - \frac{1}{2}\right]f(x)=[x2−x−21​], where [⋅][\cdot][⋅] denotes the greatest integer function, is discontinuous, is ________.

Correct answer: 10

Step-by-step solution →

Chapters tested in this paper

Open any chapter to practise every past-year question on that topic across all papers, and see how often it has actually appeared.

  • Properties of Solids and Liquids 172/186
  • Three Dimensional Geometry 176/186
  • Matrices and Determinants 180/186
  • Coordination Compounds 176/186
  • Sets, Relations and Functions 165/186
  • Current Electricity 160/186
  • Sequence and Series 164/186
  • p-Block Elements 164/186
  • Definite Integration 168/186
  • Rotational Motion 172/186
  • Redox Reactions and Electrochemistry 177/186
  • Geometrical Optics 172/186
  • Vector Algebra 173/186
  • Differential Equations 167/186
  • Probability 176/186
  • Permutations and Combinations 162/186
  • Magnetic Field of Current 147/186
  • Binomial Theorem and Its Simple Applications 158/186
  • Electromagnetic Waves 144/186
  • Chemical Bonding and Molecular Structure 151/186
  • Application of Derivatives 139/186
  • Limits and Continuity 149/186
  • d- and f-Block Elements 126/186
  • Thermodynamics 154/186
  • Aldehydes and Ketones 135/186
  • Equilibrium 163/186
  • Solutions 158/186
  • Laws of Motion 130/186
  • Chemical Thermodynamics 165/186
  • Units and Measurements 149/186
  • Hydrocarbons 126/186
  • Complex Numbers 165/186
  • Trigonometric Functions 144/186
  • Biomolecules 162/186
  • Chemical Kinetics 169/186
  • Gravitation 152/186
  • Electric Field and Coulomb's Law 133/186
  • Atomic Structure 161/186
  • Electronic Devices 145/186
  • Circles 142/186
  • Quadratic Equations 148/186
  • Work, Energy and Power 132/186
  • Some Basic Concepts in Chemistry 129/186
  • Electromagnetic Induction 120/186
  • Wave Optics 130/186
  • Area Under Curves 139/186
  • Kinetic Theory of Gases 135/186
  • Purification and Characterisation of Organic Compounds 116/186
  • Oscillations 117/186
  • Alternating Currents 108/186
  • Nuclei 116/186
  • Organic Compounds Containing Halogens 109/186
  • Atoms 112/186
  • Classification of Elements and Periodicity in Properties 113/186
  • Parabola 101/186
  • Statistics 118/186
  • Ellipse 103/186
  • Electronic Effects and Stability 74/186
  • Hyperbola 77/186
  • Experimental Skills 68/186
  • Electric Potential 63/186
  • Indefinite Integration 66/186
  • Diazonium Salts and Reactions 53/186
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