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JEE Main 8 April 2026 Shift 2 Question Paper with Answers

8 April 2026 · April session · 73 questions

73 of the 75 questions from the JEE Main 8 April 2026 Shift 2 paper, each with its correct answer and tagged to the chapter it tests. Free to read, no account needed.

2 questions are held back from this paper while we re-check the transcription or the answer key. We would rather show you nothing than show you an answer we are not confident is right.

Physics
24
Chemistry
24
Mathematics
25

Physics — JEE Main 8 April 2026 Shift 2

Q1·PhysicsSingle correct
A new unit (α)(\alpha)(α) of length is chosen such that it is equal to the speed of light in vacuum. What is the distance between Venus and Earth in terms of α\alphaα units if light takes 6 min. 40 s to cover this distance?
  1. (A)200 α200\,\alpha200α
  2. (B)400 α400\,\alpha400α
  3. (C)300 α300\,\alpha300α
  4. (D)500 α500\,\alpha500α

Correct answer: (B)

Step-by-step solution →
Q2·PhysicsSingle correct
Consider the equation H=xpϵqErtsH = \dfrac{x^p \epsilon^q E^r}{t^s}H=tsxpϵqEr​, where HHH = magnetic field; EEE = electric field, ϵ\epsilonϵ = permittivity, xxx = distance, ttt = time. The values of p,q,rp, q, rp,q,r and sss respectively are:
  1. (A)1,1,1,11, 1, 1, 11,1,1,1
  2. (B)−1,1,2,1-1, 1, 2, 1−1,1,2,1
  3. (C)1,−1,−2,11, -1, -2, 11,−1,−2,1
  4. (D)−1,−2,−2,1-1, -2, -2, 1−1,−2,−2,1

Correct answer: (A)

Step-by-step solution →
Q3·PhysicsSingle correct
A car moving with a speed of 54 km/h takes a turn of radius 20 m. A simple pendulum is suspended from the ceiling of the car. Determine the angle made by the string of the pendulum with the vertical during the turning. (Take g=10g = 10g=10 m/s2^22)
  1. (A)tan⁡−1(0.5)\tan^{-1}(0.5)tan−1(0.5)
  2. (B)tan⁡−1(0.75)\tan^{-1}(0.75)tan−1(0.75)
  3. (C)tan⁡−1(1.125)\tan^{-1}(1.125)tan−1(1.125)
  4. (D)tan⁡−1(0.25)\tan^{-1}(0.25)tan−1(0.25)

Correct answer: (C)

Step-by-step solution →
Q4·PhysicsSingle correct
A gas balloon is going up with a constant velocity of 10 m/s. When this balloon reached a height of 75 m, a stone is dropped from it and balloon keeps moving up with the same velocity. The height of the balloon when the stone hits the ground is ________ m. (Take g=10g = 10g=10 m/s2^22)
  1. (A)85
  2. (B)150
  3. (C)129
  4. (D)125

Correct answer: (D)

Step-by-step solution →
Q5·PhysicsSingle correct
A thin biconvex lens is prepared from the glass (μ=1.5)(\mu = 1.5)(μ=1.5) both curved surfaces of which have equal radii of 20 cm each. Left side surface of the lens is silvered from outside to make it reflecting. To have the position of image and object at the same place, the object should be placed, from the lens at a distance of ________ cm.
  1. (A)10
  2. (B)12.5
  3. (C)13
  4. (D)13.5

Correct answer: (A)

Step-by-step solution →
Q6·PhysicsSingle correct
Two identical bodies, projected with the same speed at two different angles cover the same horizontal range RRR. If the time of flight of these bodies are 5 s and 10 s, respectively, then the value of RRR is ________ m. (Take g=10g = 10g=10 m/s2^22)
  1. (A)250
  2. (B)25
  3. (C)500
  4. (D)125

Correct answer: (A)

Step-by-step solution →
Q7·PhysicsSingle correct
A solid cylinder having radius RRR and length LLL is slipping on a rough horizontal plane. At time t=0t = 0t=0 the cylinder has a translational velocity v0=49v_0 = 49v0​=49 m/s, perpendicular to its axis and a rotational velocity v0/4Rv_0/4Rv0​/4R about the centre. The time taken by the cylinder to start rolling is ________ seconds. (coefficient of kinetic friction μK=0.25\mu_K = 0.25μK​=0.25 and g=9.8g = 9.8g=9.8 m/s2^22)
  1. (A)15
  2. (B)5
  3. (C)10
  4. (D)7.5

Correct answer: (B)

Step-by-step solution →
Q8·PhysicsSingle correct
A liquid of density 600 kg/m3^33 flowing steadily in a tube of varying cross-section. The cross-section at a point AAA is 1.0 cm2^22 and that at BBB is 20 mm2^22. Both the points AAA and BBB are in same horizontal plane, the speed of the liquid at AAA is 10 cm/s. The difference in pressures at AAA and BBB points is ________ Pa.
  1. (A)18
  2. (B)144
  3. (C)36
  4. (D)72

Correct answer: (D)

Step-by-step solution →
Q9·PhysicsSingle correct
A spherical liquid drop of radius RRR acquires the terminal velocity v1v_1v1​ when falls through a gas of viscosity η\etaη. Now the drop is broken into 64 identical droplets and each droplet acquires terminal velocity v2v_2v2​ falling through the same gas. The ratio of terminal velocities v1/v2v_1/v_2v1​/v2​ is ________.
  1. (A)4
  2. (B)0.25
  3. (C)32
  4. (D)16

Correct answer: (D)

Step-by-step solution →
Q10·PhysicsSingle correct
Initial pressure and volume of a monoatomic ideal gas are PPP and VVV. The change in internal energy of this gas in adiabatic expansion to volume Vfinal=27VV_{final} = 27VVfinal​=27V is ________ J.
  1. (A)−2PV(33−1)-2PV(3\sqrt{3}-1)−2PV(33​−1)
  2. (B)43PV\dfrac{4}{3}PV34​PV
  3. (C)−43PV-\dfrac{4}{3}PV−34​PV
  4. (D)34PV\dfrac{3}{4}PV43​PV

Correct answer: (C)

Step-by-step solution →
Q11·PhysicsSingle correct
The frequency of oscillation of a mass mmm suspended by a spring is v1v_1v1​. If the length of the spring is cut to half, the same mass oscillates with frequency v2v_2v2​. The value of v2/v1v_2/v_1v2​/v1​ is ________.
  1. (A)1
  2. (B)2
  3. (C)2\sqrt{2}2​
  4. (D)3\sqrt{3}3​

Correct answer: (C)

Step-by-step solution →
Q12·PhysicsSingle correct
A monochromatic source of light operating at 15 kW emits 2.5×10222.5 \times 10^{22}2.5×1022 photons/s. The region of an electromagnetic spectrum to which the emitted electromagnetic radiation belongs to ________. (Take h=6.6×10−34h = 6.6 \times 10^{-34}h=6.6×10−34 J·s and c=3×108c = 3 \times 10^{8}c=3×108 m/s).
  1. (A)Microwave
  2. (B)Infrared
  3. (C)Visible
  4. (D)Ultraviolet

Correct answer: (D)

Step-by-step solution →
Q13·Physics·Magnetic Field of CurrentSingle correct
A current carrying circular loop of radius 2 cm with unit normal n^=k^+i^2\hat{n} = \dfrac{\hat{k}+\hat{i}}{\sqrt{2}}n^=2​k^+i^​ is placed in a magnetic field, B⃗=B0(3i^+2k^)\vec{B} = B_0(3\hat{i}+2\hat{k})B=B0​(3i^+2k^). If B0=4×10−3B_0 = 4\times 10^{-3}B0​=4×10−3 T and current I=1002I = 100\sqrt{2}I=1002​ A, the torque experienced by the loop is ________ Wb·A. (π=3.14\pi = 3.14π=3.14)
  1. (A)16×10−5 k^16\times 10^{-5}\,\hat{k}16×10−5k^
  2. (B)5024×10−7 k^5024\times 10^{-7}\,\hat{k}5024×10−7k^
  3. (C)5024×10−7 i^5024\times 10^{-7}\,\hat{i}5024×10−7i^
  4. (D)5024×10−7 j^5024\times 10^{-7}\,\hat{j}5024×10−7j^​

Correct answer: (D)

Step-by-step solution →
Q14·PhysicsSingle correct
A 30 cm long solenoid has 10 turns per cm and area of 5 cm2^22. The current through the solenoid coil varies from 2 A to 4 A in 3.14 s. The e.m.f. induced in the coil is α×10−5\alpha \times 10^{-5}α×10−5 V. The value of α\alphaα is ________.
  1. (A)60
  2. (B)12
  3. (C)120
  4. (D)34

Correct answer: (B)

Step-by-step solution →
Q15·PhysicsSingle correct
Two point charges q1=3 μCq_1 = 3\,\mu Cq1​=3μC and q2=−4 μCq_2 = -4\,\mu Cq2​=−4μC are placed at points (2i^+3j^+3k^)(2\hat{i}+3\hat{j}+3\hat{k})(2i^+3j^​+3k^) and (i^+j^+k^)(\hat{i}+\hat{j}+\hat{k})(i^+j^​+k^) respectively. Force on charge q2q_2q2​ is ________ N. (Take 14πϵ0=9×109 SI Units)\left(\text{Take } \dfrac{1}{4\pi\epsilon_0} = 9\times 10^{9}\text{ SI Units}\right)(Take 4πϵ0​1​=9×109 SI Units)
  1. (A)(12i^+24j^+24k^)×10−3(12\hat{i}+24\hat{j}+24\hat{k})\times 10^{-3}(12i^+24j^​+24k^)×10−3
  2. (B)(4i^+8j^+8k^)×10−3(4\hat{i}+8\hat{j}+8\hat{k})\times 10^{-3}(4i^+8j^​+8k^)×10−3
  3. (C)(3i^+6j^+6k^)×10−3(3\hat{i}+6\hat{j}+6\hat{k})\times 10^{-3}(3i^+6j^​+6k^)×10−3
  4. (D)(−4i^−8j^−8k^)×10−3(-4\hat{i}-8\hat{j}-8\hat{k})\times 10^{-3}(−4i^−8j^​−8k^)×10−3

Correct answer: (B)

Step-by-step solution →
Q16·PhysicsSingle correct
Light ray incident along a vector AO⃗\vec{AO}AO (AO⃗=2i^−3j^\vec{AO} = 2\hat{i} - 3\hat{j}AO=2i^−3j^​) emerges out along vector OB⃗\vec{OB}OB (OB⃗=Ci^−4j^\vec{OB} = C\hat{i} - 4\hat{j}OB=Ci^−4j^​) as shown in the figure below. The value of CCC is ________.
  1. (A)1.6
  2. (B)0.16
  3. (C)11.6
  4. (D)16

Correct answer: (A)

Step-by-step solution →
Q17·PhysicsSingle correct
K1K_1K1​ and K2K_2K2​ be the maximum kinetic energies of photoelectrons emitted from a surface of a given material for the light of wavelength λ1\lambda_1λ1​ and λ2\lambda_2λ2​, respectively. If λ1=2λ2\lambda_1 = 2\lambda_2λ1​=2λ2​ then the work function of material is given by:
  1. (A)K2+2K1K_2 + 2K_1K2​+2K1​
  2. (B)2K2−K12K_2 - K_12K2​−K1​
  3. (C)K1−2K2K_1 - 2K_2K1​−2K2​
  4. (D)K2−2K1K_2 - 2K_1K2​−2K1​

Correct answer: (D)

Step-by-step solution →
Q18·PhysicsSingle correct
Two radioactive substances A and B of mass numbers 200 and 212 respectively, shows spontaneous α\alphaα-decay with same QQQ value of 1 MeV. The ratio of energies of α\alphaα-rays produced by A and B is ________.
  1. (A)25482650\dfrac{2548}{2650}26502548​
  2. (B)27062646\dfrac{2706}{2646}26462706​
  3. (C)25972600\dfrac{2597}{2600}26002597​
  4. (D)28622499\dfrac{2862}{2499}24992862​

Correct answer: (C)

Step-by-step solution →
Q19·PhysicsSingle correct
The output YYY for the given inputs AAA and BBB to the circuit is:
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (B)

Step-by-step solution →
Q20·PhysicsNumerical
A parallel plate capacitor is having separation between plates 0.885 mm. It has a capacitance of 1 μ1\,\mu1μF when the space between the plates is filled with an insulating material of resistivity 1×10131\times 10^{13}1×1013 Ω\OmegaΩm and resistance 17.7×101417.7\times 10^{14}17.7×1014 Ω\OmegaΩ. Relative permittivity of the insulating material is α×107\alpha \times 10^{7}α×107. The value of α\alphaα is ________. (Take permittivity of free space =8.85×10−12= 8.85\times 10^{-12}=8.85×10−12 F/m)

Correct answer: 2

Step-by-step solution →
Q21·PhysicsNumerical
Some distant star is to be observed by some telescope of diameter of objective lens aaa, at an angular resolution of 3.0×10−73.0\times 10^{-7}3.0×10−7 radian. If the wavelength of light from the star reaching the telescope is 500 nm, the minimum diameter of the objective lens of the telescope is ________ cm. (nearest integer)

Correct answer: 203

Step-by-step solution →
Q22·Physics·Magnetic Field of CurrentNumerical
A 5 mg particle carrying a charge of 5π×10−65\pi \times 10^{-6}5π×10−6 C is moving with velocity of (3i^+2k^)×10−2(3\hat{i}+2\hat{k})\times 10^{-2}(3i^+2k^)×10−2 m/s in a region having magnetic field B⃗=0.1k^\vec{B} = 0.1\hat{k}B=0.1k^ Wb/m2^22. It moves a distance of α\alphaα meter along k^\hat{k}k^ when it completes 5 revolutions. The value of α\alphaα is ________.

Correct answer: 2

Step-by-step solution →
Q23·PhysicsNumerical
The stored charge in the capacitor in steady state of the following circuit is ________ μ\muμC.

Correct answer: 200

Step-by-step solution →
Q24·PhysicsNumerical
Two masses of 3.4 kg and 2.5 kg are accelerated from an initial speed of 5 m/s and 12 m/s, respectively. The distances traversed by the masses in the 5th^{\text{th}}th second are 104 m and 129 m, respectively. The ratio of their momenta after 10 s is x8\dfrac{x}{8}8x​. The value of xxx is ________.

Correct answer: 9

Step-by-step solution →

Chemistry — JEE Main 8 April 2026 Shift 2

Q25·ChemistrySingle correct
Match List-I (Mass of substance) with List-II (Number of atoms). Choose the correct answer from the options given below:
List-I (Mass of substance)List-II (Number of atoms)
A.1.8 mg waterI.2×10−4×NA2 \times 10^{-4} \times N_A2×10−4×NA​
B.9.8 mg sulphuric acidII.1.5×10−4×NA1.5 \times 10^{-4} \times N_A1.5×10−4×NA​
C.1.8 mg carbonIII.3×10−4×NA3 \times 10^{-4} \times N_A3×10−4×NA​
D.5.85 mg salt (NaCl)IV.7×10−4×NA7 \times 10^{-4} \times N_A7×10−4×NA​
  1. (A)A-IV, B-III, C-I, D-II
  2. (B)A-III, B-II, C-IV, D-I
  3. (C)A-III, B-IV, C-II, D-I
  4. (D)A-III, B-IV, C-I, D-II

Correct answer: (C)

Step-by-step solution →
Q26·ChemistrySingle correct
Given below are two statements: Given: Molar mass of C, H, O, Cl are 12, 1, 16 and 35.5 g mol−1^{-1}−1, respectively. Statement I: In 30% (w/w) solution of methanol in CCl4_44​ (at T K), the mole fraction of CCl4_44​ is equal to 0.33. Statement II: Mixture of methanol and CCl4_44​ shows positive deviation from Raoult's law. In the light of the above statements, choose the correct answer from the options given below:
  1. (A)Both Statement I and Statement II are true
  2. (B)Both Statement I and Statement II are false
  3. (C)Statement I is true but Statement II is false
  4. (D)Statement I is false but Statement II is true

Correct answer: (A)

Step-by-step solution →
Q27·ChemistrySingle correct
Bromine trifluoride autoionizes to form BrF2⊕BrF_2^{\oplus}BrF2⊕​ and BrF4⊖BrF_4^{\ominus}BrF4⊖​. The shapes of the cation and anion are respectively ________, and ________.
  1. (A)bent, square planar
  2. (B)linear, square planar
  3. (C)bent, see-saw
  4. (D)linear, tetrahedral

Correct answer: (A)

Step-by-step solution →
Q28·ChemistrySingle correct
Consider the following reactions in which all the reactants and products are present in gaseous state 2xy⇌x2+y22xy \rightleftharpoons x_2 + y_22xy⇌x2​+y2​ K1=2.5×105K_1 = 2.5 \times 10^5K1​=2.5×105 xy+12z2⇌xyzxy + \frac{1}{2}z_2 \rightleftharpoons xyzxy+21​z2​⇌xyz K2=5×10−3K_2 = 5 \times 10^{-3}K2​=5×10−3 The value of K3K_3K3​ for the equilibrium 12x2+12y2+12z2⇌xyz\frac{1}{2}x_2 + \frac{1}{2}y_2 + \frac{1}{2}z_2 \rightleftharpoons xyz21​x2​+21​y2​+21​z2​⇌xyz is:
  1. (A)2.5×10−32.5 \times 10^{-3}2.5×10−3
  2. (B)2.5×1032.5 \times 10^{3}2.5×103
  3. (C)1.0×10−51.0 \times 10^{-5}1.0×10−5
  4. (D)5×10−35 \times 10^{-3}5×10−3

Correct answer: (C)

Step-by-step solution →
Q29·ChemistrySingle correct
Given at 298 K: EFe2+/Fe⊖=XE^{\ominus}_{Fe^{2+}/Fe} = XEFe2+/Fe⊖​=X Volt; EFe3+/Fe⊖=YE^{\ominus}_{Fe^{3+}/Fe} = YEFe3+/Fe⊖​=Y Volt. The EFe3+/Fe2+⊖E^{\ominus}_{Fe^{3+}/Fe^{2+}}EFe3+/Fe2+⊖​ in Volt at 298 K is given by:
  1. (A)2X−3Y2X - 3Y2X−3Y
  2. (B)3Y−2X3Y - 2X3Y−2X
  3. (C)3Y+2X3Y + 2X3Y+2X
  4. (D)Y+XY + XY+X

Correct answer: (B)

Step-by-step solution →
Q30·ChemistrySingle correct
Given below are two statements: R=8.314R = 8.314R=8.314 J K−1^{-1}−1 mol−1^{-1}−1 and 1 cal =4.2= 4.2=4.2 J Statement I: When Ea=12.6E_a = 12.6Ea​=12.6 kcal/mol, the room temperature rate constant is doubled by a 10 ∘10\,^{\circ}10∘C increase in temperature (298 K to 308 K) Statement II: For a first order reactions A →\rightarrow→ B, Here [A]o[A]_o[A]o​ is the initial concentration of A and t1/2t_{1/2}t1/2​ is half life of reaction. In the light of the above statements, choose the correct answer from the options given below:
  1. (A)Both Statement I and Statement II are true
  2. (B)Both Statement I and Statement II are false
  3. (C)Statement I is true but Statement II is false
  4. (D)Statement I is false but Statement II is true

Correct answer: (C)

Step-by-step solution →
Q31·ChemistrySingle correct
Match List-I (Electronic configuration of neutral atom, where n=2n = 2n=2) with List-II (1st Ionization Energy / kJ mol−1^{-1}−1). Choose the correct answer from the options given below:
List-I (Electronic configuration of neutral atom, where $n = 2$)List-II (1st Ionization Energy / kJ mol$^{-1}$)
A.ns2ns^2ns2I.2080
B.ns2np1ns^2np^1ns2np1II.899
C.ns2np3ns^2np^3ns2np3III.800
D.ns2np6ns^2np^6ns2np6IV.1402
  1. (A)A-II, B-III, C-IV, D-I
  2. (B)A-IV, B-III, C-II, D-I
  3. (C)A-III, B-II, C-IV, D-I
  4. (D)A-III, B-II, C-I, D-IV

Correct answer: (A)

Step-by-step solution →
Q32·ChemistrySingle correct
Find the correct statements related to group 15 hydrides. A. Reducing nature increases from NH3_33​ to BiH3_33​ B. Tendency to donate lone pair of electrons decreases from NH3_33​ to BiH3_33​ C. The stability of hydrides decreases from NH3_33​ to BiH3_33​ D. HEH bond angle decreases from NH3_33​ to SbH3_33​ (E = Elements of group 15) Choose the correct answer from the options given below:
  1. (A)A and B only
  2. (B)B and C only
  3. (C)A, B, C and D
  4. (D)A, C and D Only

Correct answer: (C)

Step-by-step solution →
Q33·ChemistrySingle correct
Given below are two statements: Statement I: The number of pairs among [Ti4+,V2+][Ti^{4+}, V^{2+}][Ti4+,V2+], [V2+,Mn2+][V^{2+}, Mn^{2+}][V2+,Mn2+], [Mn2+,Fe3+][Mn^{2+}, Fe^{3+}][Mn2+,Fe3+] and [V2+,Cr2+][V^{2+}, Cr^{2+}][V2+,Cr2+] in which both ions are coloured is 3. Statement II: The number of pairs among [La3+,Yb2+][La^{3+}, Yb^{2+}][La3+,Yb2+], [Lu3+,Ce4+][Lu^{3+}, Ce^{4+}][Lu3+,Ce4+] and [Ac3+,Lr3+][Ac^{3+}, Lr^{3+}][Ac3+,Lr3+] ions in which both are diamagnetic is 3. In the light of the above statements, choose the correct from the options given below:
  1. (A)Both Statement I and Statement II are correct
  2. (B)Both Statement I and Statement II are incorrect
  3. (C)Statement I is correct but Statement II is incorrect
  4. (D)Statement I is incorrect but Statement II is correct

Correct answer: (A)

Step-by-step solution →
Q34·ChemistrySingle correct
Given below are two statements for catalytic properties of transition metals. Statement I: First row transition metals which act as catalyst utilise their 3d electrons only for formation of bonds between reactant molecules and atoms on the surface of catalyst. Statement II: There is increase in the concentration of reactants on the surface of catalyst which strengthens the bonds in reacting molecules. In the light of the above statements, choose the correct answer from the options given below:
  1. (A)Both Statement I and Statement II are correct
  2. (B)Both Statement I and Statement II are incorrect
  3. (C)Statement I is correct but Statement II is incorrect
  4. (D)Statement I is incorrect but Statement II is correct

Correct answer: (B)

Step-by-step solution →
Q35·ChemistrySingle correct
Given below are two statements: Statement I: Vapours of the liquid with higher boiling point condense before vapours of the liquid with lower boiling points in fractional distillation. Statement II: The vapours rising up in the fractionating column become richer in high boiling component of the mixture. In the light of the above statements, choose the correct answer from the options given below:
  1. (A)Both Statement I and Statement II are true
  2. (B)Both Statement I and Statement II are false
  3. (C)Statement I is true but Statement II is false
  4. (D)Statement I is false but Statement II is true

Correct answer: (C)

Step-by-step solution →
Q36·Chemistry·Reaction MechanismSingle correct
The major product of which of the following reaction is not obtained by rearrangement reaction?
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (B)

Step-by-step solution →
Q37·Chemistry·AromaticitySingle correct
The total number of aromatic compounds/species from the following is
  1. (A)6
  2. (B)4
  3. (C)3
  4. (D)5

Correct answer: (B)

Step-by-step solution →
Q38·ChemistrySingle correct
n-Butane on monochlorination under photochemical condition gives an optically active compound "P". "P" on further chlorination gives dichloro compounds. The number of dichloro compounds obtained (ignore stereoisomers) is:
  1. (A)3
  2. (B)4
  3. (C)5
  4. (D)6

Correct answer: (B)

Step-by-step solution →
Q39·ChemistrySingle correct
Given below are two statements: Statement I: Due to increase in van der Waals forces, the order of boiling points is CH3CH2CH2I>CH3CH2I>CH3ICH_3CH_2CH_2I > CH_3CH_2I > CH_3ICH3​CH2​CH2​I>CH3​CH2​I>CH3​I. Statement II: As para-dichlorobenzene is more symmetric, its melting point is higher than ortho-dichlorobenzene, however its boiling point is lower than ortho-dichlorobenzene. In the light of the above statements, choose the correct answer from the options given below:
  1. (A)Both Statement I and Statement II are true
  2. (B)Both Statement I and Statement II are false
  3. (C)Statement I is true but Statement II is false
  4. (D)Statement I is false but Statement II is true

Correct answer: (A)

Step-by-step solution →
Q40·ChemistrySingle correct
Consider the following reaction. The major product (P) formed is:
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (C)

Step-by-step solution →
Q41·ChemistrySingle correct
Which statements are True? A. In Hoffmann bromamide degradation, 4 moles of NaOH and 2 moles of Br2Br_2Br2​ are consumed per mole of an amide B. Hoffmann bromamide reaction is not given by alkyl amides. C. Primary amines can be synthesized by Hoffmann bromamide degradation. D. Secondary amide on reaction with Br2Br_2Br2​ and NaOH will give secondary amine. E. The by-products of Hoffmann degradation are Na2CO3Na_2CO_3Na2​CO3​, NaBr and H2OH_2OH2​O. Choose the correct answer from the options given below:
  1. (A)A, C and E only
  2. (B)B, C and D only
  3. (C)C and E only
  4. (D)C, D and E only

Correct answer: (C)

Step-by-step solution →
Q42·ChemistrySingle correct
The incorrect statement from the following with respect to carbohydrates is:
  1. (A)All monosaccharides are reducing sugars.
  2. (B)The monosaccharide units obtained from hydrolysis of oligosaccharides are always the same.
  3. (C)Starch and cellulose are typical examples of polysaccharides, which are very high molecular weight compounds of more than ten monosaccharide units.
  4. (D)Open chain and cyclic structures co-exist at equilibrium that are responsible for certain properties as in the case of D−(+)D-(+)D−(+)-glucose.

Correct answer: (B)

Step-by-step solution →
Q43·ChemistrySingle correct
Which of the following amino acid will give violet coloured complex with neutral ferric chloride solution?
  1. (A)Threonine
  2. (B)Serine
  3. (C)Tyrosine
  4. (D)Cysteine

Correct answer: (C)

Step-by-step solution →
Q44·ChemistryNumerical
Number of paramagnetic complexes among the following is __________. [MnBr4]2−[MnBr_4]^{2-}[MnBr4​]2−, [NiCl4]2−[NiCl_4]^{2-}[NiCl4​]2−, [Ni(CN)4]2−[Ni(CN)_4]^{2-}[Ni(CN)4​]2−, [Ni(CO)4][Ni(CO)_4][Ni(CO)4​], [CoF6]3−[CoF_6]^{3-}[CoF6​]3−, [Fe(CN)6]4−[Fe(CN)_6]^{4-}[Fe(CN)6​]4−, [Mn(CN)6]3−[Mn(CN)_6]^{3-}[Mn(CN)6​]3−, [Ti(CN)6]3−[Ti(CN)_6]^{3-}[Ti(CN)6​]3−, [Cu(H2O)6]2+[Cu(H_2O)_6]^{2+}[Cu(H2​O)6​]2+, [Co(C2O4)3]3−[Co(C_2O_4)_3]^{3-}[Co(C2​O4​)3​]3−

Correct answer: 6

Step-by-step solution →
Q45·ChemistryNumerical
'xxx' is the product which is obtained from benzene by reacting it with carbon monoxide and hydrogen chloride in the presence of cuprous chloride. 'yyy' is the major product obtained from the benzene by reacting it with ethanoyl chloride in the presence of anhydrous AlCl3AlCl_3AlCl3​. Product (major) obtained by heating xxx and yyy in the presence of alkali is zzz. Total number of π\piπ (pi) electrons in zzz is __________.

Correct answer: 16

Step-by-step solution →
Q46·ChemistryNumerical
Consider two radiations of wavelengths 1. λ1=2000\lambda_1 = 2000λ1​=2000 Å 2. λ2=6000\lambda_2 = 6000λ2​=6000 Å The ratio of the energies of these two radiations (E1E2)\left(\frac{E_1}{E_2}\right)(E2​E1​​) is __________ (Nearest integer).

Correct answer: 3

Step-by-step solution →
Q47·ChemistryNumerical
Consider the reaction 2H2S(g)+3O2(g)→2H2O(l)+2SO2(g)2H_2S(g) + 3O_2(g) \rightarrow 2H_2O(l) + 2SO_2(g)2H2​S(g)+3O2​(g)→2H2​O(l)+2SO2​(g) The magnitude of enthalpy change for the reaction in kJ mol−1^{-1}−1 is __________. (Nearest integer) Given: ΔfH⊖(H2S)=−20.1\Delta_f H^{\ominus}(H_2S) = -20.1Δf​H⊖(H2​S)=−20.1 kJ mol−1^{-1}−1 ΔfH⊖(H2O)=−286.0\Delta_f H^{\ominus}(H_2O) = -286.0Δf​H⊖(H2​O)=−286.0 kJ mol−1^{-1}−1 ΔfH⊖(SO2)=−297.0\Delta_f H^{\ominus}(SO_2) = -297.0Δf​H⊖(SO2​)=−297.0 kJ mol−1^{-1}−1

Correct answer: 1126

Step-by-step solution →
Q48·ChemistryNumerical
Solid carbon, CaO and CaCO3CaCO_3CaCO3​ are mixed and allowed to attain equilibrium at T K. CaCO3(s)⇌CaO(s)+CO2(g)CaCO_3(s) \rightleftharpoons CaO(s) + CO_2(g)CaCO3​(s)⇌CaO(s)+CO2​(g) Kp1=0.08K_{p_1} = 0.08Kp1​​=0.08 atm C(s)+CO2(g)⇌2CO(g)C(s) + CO_2(g) \rightleftharpoons 2CO(g)C(s)+CO2​(g)⇌2CO(g) Kp2=2K_{p_2} = 2Kp2​​=2 atm The partial pressure of CO is __________ ×10−1\times 10^{-1}×10−1 atm

Correct answer: 4

Step-by-step solution →

Mathematics — JEE Main 8 April 2026 Shift 2

Q49·MathematicsSingle correct
Consider the relation R on the set {−2,−1,0,1,2}\{-2, -1, 0, 1, 2\}{−2,−1,0,1,2} defined by (a,b)∈R(a, b) \in R(a,b)∈R if and only if 1+ab>01 + ab > 01+ab>0. Then, among the statements: I. The number of elements in R is 17 II. R is an equivalence relation
  1. (A)Only I is true
  2. (B)Only II is true
  3. (C)Both I and II are true
  4. (D)Neither I nor II is true

Correct answer: (A)

Step-by-step solution →
Q50·MathematicsSingle correct
The number of values of z∈Cz \in \mathbb{C}z∈C, satisfying the equations ∣z−(4+8i)∣=10|z - (4 + 8i)| = \sqrt{10}∣z−(4+8i)∣=10​ and ∣z−(3+5i)∣+∣z−(5+11i)∣=45|z - (3 + 5i)| + |z - (5 + 11i)| = 4\sqrt{5}∣z−(3+5i)∣+∣z−(5+11i)∣=45​, is:
  1. (A)0
  2. (B)2
  3. (C)1
  4. (D)4

Correct answer: (B)

Step-by-step solution →
Q51·MathematicsSingle correct
If the system of linear equations: x+y+z=6x + y + z = 6x+y+z=6, x+2y+5z=10x + 2y + 5z = 10x+2y+5z=10, 2x+3y+λz=μ2x + 3y + \lambda z = \mu2x+3y+λz=μ has infinitely many solutions, then the value of λ+μ\lambda + \muλ+μ equals:
  1. (A)12
  2. (B)16
  3. (C)22
  4. (D)28

Correct answer: (C)

Step-by-step solution →
Q52·MathematicsSingle correct
Let A=[α12230045]A = \begin{bmatrix} \alpha & 1 & 2 \\ 2 & 3 & 0 \\ 0 & 4 & 5 \end{bmatrix}A=​α20​134​205​​ and B=[1000−5α004α−2α]+adj(A)B = \begin{bmatrix} 1 & 0 & 0 \\ 0 & -5\alpha & 0 \\ 0 & 4\alpha & -2\alpha \end{bmatrix} + \mathrm{adj}(A)B=​100​0−5α4α​00−2α​​+adj(A). If det⁡(B)=66\det(B) = 66det(B)=66, then det⁡(adj(A))\det(\mathrm{adj}(A))det(adj(A)) equals:
  1. (A)289
  2. (B)361
  3. (C)441
  4. (D)529

Correct answer: (C)

Step-by-step solution →
Q53·MathematicsSingle correct
Let α=3+4+8+9+13+14+…\alpha = 3 + 4 + 8 + 9 + 13 + 14 + \ldotsα=3+4+8+9+13+14+… upto 40 terms. If (tan⁡β)α1020(\tan \beta)^{\frac{\alpha}{1020}}(tanβ)1020α​ is a root of the equation x2+x−2=0x^2 + x - 2 = 0x2+x−2=0, β∈(0,π2)\beta \in \left(0, \frac{\pi}{2}\right)β∈(0,2π​), then sin⁡2β+3cos⁡2β\sin^2 \beta + 3\cos^2 \betasin2β+3cos2β is equal to:
  1. (A)2
  2. (B)74\frac{7}{4}47​
  3. (C)52\frac{5}{2}25​
  4. (D)32\frac{3}{2}23​

Correct answer: (A)

Step-by-step solution →
Q54·MathematicsSingle correct
A candidate has to go to the examination centre to appear in an examination. The candidate uses only one means of transportation for the entire distance out of bus, scooter and car. The probabilities of the candidate going by bus, scooter and car, respectively, are 25\frac{2}{5}52​, 15\frac{1}{5}51​ and 25\frac{2}{5}52​. The probabilities that the candidate reaches late at the examination centre are 15\frac{1}{5}51​, 13\frac{1}{3}31​ and 14\frac{1}{4}41​ if the candidate uses bus, scooter and car, respectively. Given that the candidate reached late at the examination centre, the probability that the candidate travelled by bus is:
  1. (A)1137\frac{11}{37}3711​
  2. (B)1237\frac{12}{37}3712​
  3. (C)1337\frac{13}{37}3713​
  4. (D)1437\frac{14}{37}3714​

Correct answer: (B)

Step-by-step solution →
Q55·MathematicsSingle correct
A set of four observations has mean 1 and variance 13. Another set of six observations has mean 2 and variance 1. Then, the variance of all these 10 observations is equal to:
  1. (A)5.96
  2. (B)6.14
  3. (C)6.04
  4. (D)6.24

Correct answer: (C)

Step-by-step solution →
Q56·MathematicsSingle correct
If 26(233(122)+255(124)+277(126)+…+21313(1212))=313−α26\left(\frac{2^3}{3}\binom{12}{2} + \frac{2^5}{5}\binom{12}{4} + \frac{2^7}{7}\binom{12}{6} + \ldots + \frac{2^{13}}{13}\binom{12}{12}\right) = 3^{13} - \alpha26(323​(212​)+525​(412​)+727​(612​)+…+13213​(1212​))=313−α, then α\alphaα is equal to:
  1. (A)45
  2. (B)48
  3. (C)51
  4. (D)54

Correct answer: (C)

Step-by-step solution →
Q57·MathematicsSingle correct
A person has three different bags and four different books. The number of ways, in which he can put these books in the bags so that no bag is empty, is:
  1. (A)18
  2. (B)36
  3. (C)39
  4. (D)72

Correct answer: (B)

Step-by-step solution →
Q58·MathematicsSingle correct
If a straight line drawn through the point of intersection of the lines 4x+3y−1=04x + 3y - 1 = 04x+3y−1=0 and 3x+4y−1=03x + 4y - 1 = 03x+4y−1=0, meets the co-ordinate axes at the points P and Q, then the locus of the mid point of PQ is:
  1. (A)x+y−7=0x + y - 7 = 0x+y−7=0
  2. (B)x+y−14xy=0x + y - 14xy = 0x+y−14xy=0
  3. (C)2x+y+14xy=02x + y + 14xy = 02x+y+14xy=0
  4. (D)x+2y−14xy=0x + 2y - 14xy = 0x+2y−14xy=0

Correct answer: (B)

Step-by-step solution →
Q59·MathematicsSingle correct
Let O be the vertex of the parabola y2=4xy^2 = 4xy2=4x and its chords OP and OQ are perpendicular to each other. If the locus of the mid-point of the line segment PQ is a conic C, then the length of its latus rectum is:
  1. (A)1
  2. (B)2
  3. (C)4
  4. (D)8

Correct answer: (B)

Step-by-step solution →
Q60·MathematicsSingle correct
Let α=3sin⁡−1(611)\alpha = 3\sin^{-1}\left(\frac{6}{11}\right)α=3sin−1(116​) and β=3cos⁡−1(49)\beta = 3\cos^{-1}\left(\frac{4}{9}\right)β=3cos−1(94​), where inverse trigonometric functions take only the principal values. Given below are two statements: Statement I: cos⁡(α+β)>0\cos(\alpha + \beta) > 0cos(α+β)>0. Statement II: cos⁡(α)<0\cos(\alpha) < 0cos(α)<0. In the light of the above statements, choose the correct answer from the options given below:
  1. (A)Both Statement I and Statement II are true
  2. (B)Both Statement I and Statement II are false
  3. (C)Statement I is true but Statement II is false
  4. (D)Statement I is false but Statement II is true

Correct answer: (A)

Step-by-step solution →
Q61·Mathematics·DifferentiabilitySingle correct
For the function f(x)=esin⁡∣x∣−∣x∣f(x) = e^{\sin|x|} - |x|f(x)=esin∣x∣−∣x∣, x∈Rx \in \mathbb{R}x∈R, consider the following statements: Statement I: fff is differentiable for all x∈Rx \in \mathbb{R}x∈R. Statement II: fff is increasing in (−π,−π2)\left(-\pi, -\frac{\pi}{2}\right)(−π,−2π​). In the light of the above statements, choose the correct answer from the options given below:
  1. (A)Both Statement I and Statement II are true
  2. (B)Both Statement I and Statement II are false
  3. (C)Statement I is true but Statement II is false
  4. (D)Statement I is false but Statement II is true

Correct answer: (A)

Step-by-step solution →
Q62·MathematicsSingle correct
Let a⃗=4i^−j^+3k^\vec{a} = 4\hat{i} - \hat{j} + 3\hat{k}a=4i^−j^​+3k^, b⃗=10i^+2j^−k^\vec{b} = 10\hat{i} + 2\hat{j} - \hat{k}b=10i^+2j^​−k^ and a vector c⃗\vec{c}c be such that 2(a⃗×b⃗)+3(b⃗×c⃗)=0⃗2(\vec{a} \times \vec{b}) + 3(\vec{b} \times \vec{c}) = \vec{0}2(a×b)+3(b×c)=0. If a⃗⋅c⃗=15\vec{a} \cdot \vec{c} = 15a⋅c=15, then c⃗⋅(i^+j^−3k^)\vec{c} \cdot (\hat{i} + \hat{j} - 3\hat{k})c⋅(i^+j^​−3k^) is equal to:
  1. (A)−6-6−6
  2. (B)−5-5−5
  3. (C)−4-4−4
  4. (D)−3-3−3

Correct answer: (B)

Step-by-step solution →
Q63·MathematicsSingle correct
Let the foot of perpendicular from the point (λ,2,3)(\lambda, 2, 3)(λ,2,3) on the line x−41=y−92=z−51\dfrac{x-4}{1} = \dfrac{y-9}{2} = \dfrac{z-5}{1}1x−4​=2y−9​=1z−5​ be the point (1,μ,2)(1, \mu, 2)(1,μ,2). Then the distance between the lines x−12=y−23=z+46\dfrac{x-1}{2} = \dfrac{y-2}{3} = \dfrac{z+4}{6}2x−1​=3y−2​=6z+4​ and x−λ2=y−μ3=z+56\dfrac{x-\lambda}{2} = \dfrac{y-\mu}{3} = \dfrac{z+5}{6}2x−λ​=3y−μ​=6z+5​ is equal to:
  1. (A)127\dfrac{12}{7}712​
  2. (B)1457\dfrac{\sqrt{145}}{7}7145​​
  3. (C)1467\dfrac{\sqrt{146}}{7}7146​​
  4. (D)1437\dfrac{\sqrt{143}}{7}7143​​

Correct answer: (C)

Step-by-step solution →
Q64·MathematicsSingle correct
The value of the integral ∫02x(x2+x+1)(x+1)(x4+x2+1) dx\displaystyle\int_{0}^{2} \dfrac{\sqrt{x(x^2+x+1)}}{(\sqrt{x+1})(\sqrt{x^4+x^2+1})}\,dx∫02​(x+1​)(x4+x2+1​)x(x2+x+1)​​dx is equal to:
  1. (A)13log⁡e(3−22)\dfrac{1}{3}\log_e(3 - 2\sqrt{2})31​loge​(3−22​)
  2. (B)23log⁡e(4+2)\dfrac{2}{3}\log_e(4 + \sqrt{2})32​loge​(4+2​)
  3. (C)23log⁡e(3+22)\dfrac{2}{3}\log_e(3 + 2\sqrt{2})32​loge​(3+22​)
  4. (D)13log⁡e(1+62)\dfrac{1}{3}\log_e(1 + 6\sqrt{2})31​loge​(1+62​)

Correct answer: (C)

Step-by-step solution →
Q65·MathematicsSingle correct
Let y=y(x)y = y(x)y=y(x) be the solution of the differential equation x1−x2 dy+(y1−x2−xcos⁡−1x)dx=0x\sqrt{1-x^2}\,dy + \left(y\sqrt{1-x^2} - x\cos^{-1}x\right)dx = 0x1−x2​dy+(y1−x2​−xcos−1x)dx=0, x∈(0,1)x \in (0,1)x∈(0,1), lim⁡x→1−y(x)=1\displaystyle\lim_{x \to 1^-} y(x) = 1x→1−lim​y(x)=1. Then y(12)y\left(\dfrac{1}{2}\right)y(21​) equals:
  1. (A)3−π33 - \dfrac{\pi}{\sqrt{3}}3−3​π​
  2. (B)4−3π4 - \sqrt{3}\pi4−3​π
  3. (C)4−2π34 - \dfrac{2\pi}{\sqrt{3}}4−3​2π​
  4. (D)3−π233 - \dfrac{\pi}{2\sqrt{3}}3−23​π​

Correct answer: (A)

Step-by-step solution →
Q66·MathematicsSingle correct
Let f:(1,∞)→Rf : (1, \infty) \to \mathbb{R}f:(1,∞)→R be a function defined as f(x)=x−1x+1f(x) = \dfrac{x-1}{x+1}f(x)=x+1x−1​. Let fi+1(x)=f(fi(x))f^{i+1}(x) = f(f^{i}(x))fi+1(x)=f(fi(x)), i=1,2,…,25i = 1, 2, \ldots, 25i=1,2,…,25, where f1(x)=f(x)f^{1}(x) = f(x)f1(x)=f(x). If g(x)+f26(x)=0g(x) + f^{26}(x) = 0g(x)+f26(x)=0, x∈(1,∞)x \in (1, \infty)x∈(1,∞), then the area of the region bounded by the curves y=g(x)y = g(x)y=g(x), 2y=2x−32y = 2x - 32y=2x−3, y=0y = 0y=0 and x=4x = 4x=4 is:
  1. (A)18+log⁡e2\dfrac{1}{8} + \log_e 281​+loge​2
  2. (B)14+log⁡e2\dfrac{1}{4} + \log_e 241​+loge​2
  3. (C)56+3log⁡e2\dfrac{5}{6} + 3\log_e 265​+3loge​2
  4. (D)56+log⁡e2\dfrac{5}{6} + \log_e 265​+loge​2

Correct answer: (A)

Step-by-step solution →
Q67·Mathematics·Limits and ContinuitySingle correct
Let f(x)={13,x≤π/2b(1−sin⁡x)(π−2x)2,x>π/2f(x) = \begin{cases} \dfrac{1}{3}, & x \le \pi/2 \\ \dfrac{b(1 - \sin x)}{(\pi - 2x)^2}, & x > \pi/2 \end{cases}f(x)=⎩⎨⎧​31​,(π−2x)2b(1−sinx)​,​x≤π/2x>π/2​. If fff is continuous at x=π/2x = \pi/2x=π/2, then the value of ∫03b−6∣x2+2x−3∣ dx\displaystyle\int_{0}^{3b-6} |x^2 + 2x - 3|\,dx∫03b−6​∣x2+2x−3∣dx is:
  1. (A)555
  2. (B)222
  3. (C)333
  4. (D)444

Correct answer: (D)

Step-by-step solution →
Q68·MathematicsSingle correct
Let x2f(a2+7a+3)+y2f(3a+15)=1\dfrac{x^2}{f(a^2 + 7a + 3)} + \dfrac{y^2}{f(3a + 15)} = 1f(a2+7a+3)x2​+f(3a+15)y2​=1 represent an ellipse with major axis along yyy-axis, where fff is a strictly decreasing positive function on R\mathbb{R}R. If the set of all possible values of aaa is R−[α,β]\mathbb{R} - [\alpha, \beta]R−[α,β], then α2+β2\alpha^2 + \beta^2α2+β2 is equal to:
  1. (A)282828
  2. (B)404040
  3. (C)616161
  4. (D)242424

Correct answer: (B)

Step-by-step solution →
Q69·MathematicsNumerical
The sum of squares of all the real solutions of the equation log⁡(x+1)(2x2+5x+3)=4−log⁡(2x+3)(x2+2x+1)\log_{(x+1)}(2x^2 + 5x + 3) = 4 - \log_{(2x+3)}(x^2 + 2x + 1)log(x+1)​(2x2+5x+3)=4−log(2x+3)​(x2+2x+1) is equal to ________.

Correct answer: 2

Step-by-step solution →
Q70·MathematicsNumerical
If ∫π/6π/4(cot⁡(x−π3)cot⁡(x+π3)+1)dx=αlog⁡e(3−1)\displaystyle\int_{\pi/6}^{\pi/4} \left(\cot\left(x - \dfrac{\pi}{3}\right)\cot\left(x + \dfrac{\pi}{3}\right) + 1\right)dx = \alpha \log_e(\sqrt{3} - 1)∫π/6π/4​(cot(x−3π​)cot(x+3π​)+1)dx=αloge​(3​−1), then 9α29\alpha^29α2 is equal to ________.

Correct answer: 12

Step-by-step solution →
Q71·MathematicsNumerical
Let a line L1L_1L1​ pass through the origin and be perpendicular to the lines L2:r⃗=(3+t)i^+(2t−1)j^+(2t+4)k^L_2 : \vec{r} = (3 + t)\hat{i} + (2t - 1)\hat{j} + (2t + 4)\hat{k}L2​:r=(3+t)i^+(2t−1)j^​+(2t+4)k^ and L3:r⃗=(3+2s)i^+(3+2s)j^+(2+s)k^L_3 : \vec{r} = (3 + 2s)\hat{i} + (3 + 2s)\hat{j} + (2 + s)\hat{k}L3​:r=(3+2s)i^+(3+2s)j^​+(2+s)k^, t,s∈Rt, s \in \mathbb{R}t,s∈R. If (a,b,c)(a, b, c)(a,b,c), a∈Za \in \mathbb{Z}a∈Z, is the point on L3L_3L3​ at a distance of 17\sqrt{17}17​ from the point of intersection of L1L_1L1​ and L2L_2L2​, then (a+b+c)2(a + b + c)^2(a+b+c)2 is equal to ________.

Correct answer: 4

Step-by-step solution →
Q72·MathematicsNumerical
Consider the circle C:x2+y2−6x−8y−11=0C : x^2 + y^2 - 6x - 8y - 11 = 0C:x2+y2−6x−8y−11=0. Let a variable chord AB of the circle C subtend a right angle at the origin. If the locus of the foot of the perpendicular drawn from the origin on the chord AB is the circle x2+y2−αx−βy−γ=0x^2 + y^2 - \alpha x - \beta y - \gamma = 0x2+y2−αx−βy−γ=0, then α+β+2γ\alpha + \beta + 2\gammaα+β+2γ is equal to ________.

Correct answer: 18

Step-by-step solution →
Q73·MathematicsNumerical
Let fff be a polynomial function such that log⁡2(f(x))=(log⁡2(2+23+29+…∞))⋅log⁡3(1+f(x)f(1/x))\log_2(f(x)) = \left(\log_2\left(2 + \dfrac{2}{3} + \dfrac{2}{9} + \ldots \infty\right)\right) \cdot \log_3\left(1 + \dfrac{f(x)}{f(1/x)}\right)log2​(f(x))=(log2​(2+32​+92​+…∞))⋅log3​(1+f(1/x)f(x)​), x>0x > 0x>0 and f(6)=37f(6) = 37f(6)=37. Then ∑n=110f(n)\displaystyle\sum_{n=1}^{10} f(n)n=1∑10​f(n) is equal to ________.

Correct answer: 395

Step-by-step solution →

Chapters tested in this paper

Open any chapter to practise every past-year question on that topic across all papers, and see how often it has actually appeared.

  • Properties of Solids and Liquids 172/186
  • Three Dimensional Geometry 176/186
  • Matrices and Determinants 180/186
  • Coordination Compounds 176/186
  • Sets, Relations and Functions 165/186
  • Current Electricity 160/186
  • Sequence and Series 164/186
  • p-Block Elements 164/186
  • Definite Integration 168/186
  • Rotational Motion 172/186
  • Redox Reactions and Electrochemistry 177/186
  • Geometrical Optics 172/186
  • Kinematics 156/186
  • Vector Algebra 173/186
  • Differential Equations 167/186
  • Probability 176/186
  • Permutations and Combinations 162/186
  • Magnetic Field of Current 147/186
  • Binomial Theorem and Its Simple Applications 158/186
  • Chemical Bonding and Molecular Structure 151/186
  • Limits and Continuity 149/186
  • d- and f-Block Elements 126/186
  • Thermodynamics 154/186
  • Aldehydes and Ketones 135/186
  • Equilibrium 163/186
  • Solutions 158/186
  • Laws of Motion 130/186
  • Chemical Thermodynamics 165/186
  • Units and Measurements 149/186
  • Complex Numbers 165/186
  • Biomolecules 162/186
  • Chemical Kinetics 169/186
  • Electric Field and Coulomb's Law 133/186
  • Atomic Structure 161/186
  • Electronic Devices 145/186
  • Circles 142/186
  • Dual Nature of Matter and Radiation 155/186
  • Amines 133/186
  • Quadratic Equations 148/186
  • Some Basic Concepts in Chemistry 129/186
  • Electromagnetic Induction 120/186
  • Wave Optics 130/186
  • Area Under Curves 139/186
  • Purification and Characterisation of Organic Compounds 116/186
  • Oscillations 117/186
  • Nuclei 116/186
  • Organic Compounds Containing Halogens 109/186
  • Straight Lines 114/186
  • Capacitors and Dielectrics 115/186
  • Classification of Elements and Periodicity in Properties 113/186
  • Parabola 101/186
  • Statistics 118/186
  • Ellipse 103/186
  • Differentiability 91/186
  • Inverse Trigonometric Functions 93/186
  • Carboxylic Acids and Derivatives 54/186
  • Reaction Mechanism 29/186
  • Aromaticity 22/186
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