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JEE Main 6 April 2026 Shift 2 Question Paper with Answers

6 April 2026 · April session · 75 questions

The complete JEE Main 6 April 2026 Shift 2 paper — all 75 questions with the correct answer for each, tagged to the chapter it tests. Free to read, no account needed.

Physics
25
Chemistry
25
Mathematics
25

Physics — JEE Main 6 April 2026 Shift 2

Q1·PhysicsSingle correct
The percentage error in the calculated volume of a sphere, if there is 2% error in its diameter measurement, is __________.
  1. (A)1
  2. (B)2
  3. (C)6
  4. (D)8

Correct answer: (C)

Step-by-step solution →
Q2·PhysicsSingle correct
Match List - I with List - II. Choose the correct answer from the options given below :
List - IList - II
A.Boltzmann constantI.[M−1L3T−2][M^{-1}L^{3}T^{-2}][M−1L3T−2]
B.Stefan's constantII.[ML2T−1][ML^{2}T^{-1}][ML2T−1]
C.Planck's constantIII.[ML2T−2K−1][ML^{2}T^{-2}K^{-1}][ML2T−2K−1]
D.Gravitational constantIV.[ML0T−3K−4][ML^{0}T^{-3}K^{-4}][ML0T−3K−4]
  1. (A)A-I, B-II, C-III, D-IV
  2. (B)A-IV, B-III, C-II, D-I
  3. (C)A-III, B-IV, C-II, D-I
  4. (D)A-II, B-I, C-IV, D-III

Correct answer: (C)

Step-by-step solution →
Q3·PhysicsSingle correct
A solid sphere (A)(A)(A) of mass 5m5m5m and a spherical shell (B)(B)(B) of mass mmm, both having same radius, are placed on a rough surface. When a force of same magnitude is applied tangentially at the highest points of AAA and BBB, they start rolling without slipping with an acceleration of aAa_{A}aA​ and aBa_{B}aB​, respectively. The ratio of aAa_{A}aA​ and aBa_{B}aB​ is __________.
  1. (A)5 : 21
  2. (B)6 : 10
  3. (C)21 : 25
  4. (D)1 : 5

Correct answer: (A)

Step-by-step solution →
Q4·PhysicsSingle correct
A body of mass 1 kg moves along a straight line with a velocity v=2x2v = 2x^{2}v=2x2. The work done by the body during displacement from x=0x = 0x=0 to 5 m is __________ J.
  1. (A)0
  2. (B)250
  3. (C)1250
  4. (D)1000

Correct answer: (C)

Step-by-step solution →
Q5·PhysicsSingle correct
A cylinder with adiabatic walls is closed at both ends and is divided into two compartments by a frictionless adiabatic piston. Ideal gas is filled in both (left and right) the compartments at same P,V,TP, V, TP,V,T. Heating is started from left side until pressure changes to 27P8\frac{27P}{8}827P​. If initial volume of each compartment was 9 litres then the final volume in right-hand side compartment is __________ litres. (for this ideal gas CP/CV=1.5C_{P}/C_{V} = 1.5CP​/CV​=1.5)
  1. (A)3
  2. (B)4
  3. (C)14
  4. (D)9

Correct answer: (B)

Step-by-step solution →
Q6·PhysicsSingle correct
For an electromagnetic wave propagating through vacuum, k⃗\vec{k}k, E⃗\vec{E}E and ω\omegaω represent propagation vector, electric field and angular frequency, respectively. The magnetic field associated with this wave is represented by :
  1. (A)E⃗×k⃗ω\frac{\vec{E} \times \vec{k}}{\omega}ωE×k​
  2. (B)k⃗×E⃗ω\frac{\vec{k} \times \vec{E}}{\omega}ωk×E​
  3. (C)ω(E⃗×k⃗)\omega(\vec{E} \times \vec{k})ω(E×k)
  4. (D)ω(k⃗×E⃗)\omega(\vec{k} \times \vec{E})ω(k×E)

Correct answer: (B)

Step-by-step solution →
Q7·PhysicsSingle correct
Two identical bodies AAA and BBB of equal masses have initial velocities v⃗1=4i^\vec{v}_{1} = 4\hat{i}v1​=4i^ m/s and v⃗2=4j^\vec{v}_{2} = 4\hat{j}v2​=4j^​ m/s respectively. The body AAA has acceleration a⃗1=6i^+6j^\vec{a}_{1} = 6\hat{i} + 6\hat{j}a1​=6i^+6j^​ m/s2^{2}2 while the acceleration of the other body BBB is zero. The centre of mass of the two bodies moves in __________ path.
  1. (A)circular
  2. (B)parabolic
  3. (C)straight line
  4. (D)elliptical

Correct answer: (C)

Step-by-step solution →
Q8·PhysicsSingle correct
Figure represents the extension (Δl\Delta lΔl) of a wire of length 1 meter, suspended from the ceiling of the room at one end with a load WWW connected to the other end. If the cross-sectional area of the wire is 10−510^{-5}10−5 m2^{2}2 then the Young's modulus of the wire is __________ N/m2^{2}2.
  1. (A)1.0×10111.0 \times 10^{11}1.0×1011
  2. (B)2.0×10102.0 \times 10^{10}2.0×1010
  3. (C)1.0×10101.0 \times 10^{10}1.0×1010
  4. (D)2.0×10112.0 \times 10^{11}2.0×1011

Correct answer: (C)

Step-by-step solution →
Q9·PhysicsSingle correct
A cylindrical vessel of 40 cm radius is completely filled with water and its capacity is 528 dm3^{3}3 (dm : decimeter). The vessel is placed on a solid block of exactly same height as vessel. If a small hole is made at 70 cm below the top of water level, then horizontal range of water falling on the ground in the beginning is __________ cm.
  1. (A)1202120\sqrt{2}1202​
  2. (B)1402140\sqrt{2}1402​
  3. (C)1403140\sqrt{3}1403​
  4. (D)1203120\sqrt{3}1203​

Correct answer: (B)

Step-by-step solution →
Q10·PhysicsSingle correct
If 2 mole of an ideal monoatomic gas at temperature TTT, is mixed with 6 mole of another ideal monoatomic gas at temperature 2T2T2T then the temperature of mixture is :
  1. (A)52T\frac{5}{2}T25​T
  2. (B)54T\frac{5}{4}T45​T
  3. (C)72T\frac{7}{2}T27​T
  4. (D)74T\frac{7}{4}T47​T

Correct answer: (D)

Step-by-step solution →
Q11·PhysicsSingle correct
A spring stretches by 2 mm when it is loaded with a mass of 200 g. From equilibrium position the mass is further pulled down by 2 mm and released. The frequency associated with the system and maximum energy in the spring are __________ Hz and __________ J, respectively. (Take g =10= 10=10 m/s2^{2}2)
  1. (A)550π\frac{5\sqrt{50}}{\pi}π550​​ and 8×10−38 \times 10^{-3}8×10−3
  2. (B)550π\frac{5\sqrt{50}}{\pi}π550​​ and 8
  3. (C)105010\sqrt{50}1050​ and 2×10−32 \times 10^{-3}2×10−3
  4. (D)550π\frac{5\sqrt{50}}{\pi}π550​​ and 16×10−316 \times 10^{-3}16×10−3

Correct answer: (A)

Step-by-step solution →
Q12·PhysicsSingle correct
The electric potential as a function of x,yx, yx,y is given by V=5(x2−y2)V = 5(x^{2} - y^{2})V=5(x2−y2) V. The electric field at a point (2,3)(2, 3)(2,3) m is __________ V/m.
  1. (A)(−20i^+30j^)(-20\hat{i} + 30\hat{j})(−20i^+30j^​)
  2. (B)(20i^−30j^)(20\hat{i} - 30\hat{j})(20i^−30j^​)
  3. (C)(20i^+45j^)(20\hat{i} + 45\hat{j})(20i^+45j^​)
  4. (D)(−4i^+6j^)(-4\hat{i} + 6\hat{j})(−4i^+6j^​)

Correct answer: (A)

Step-by-step solution →
Q13·Physics·Magnetic Field of CurrentSingle correct
A current of 30 A each flows in opposite directions in two conducting wires, placed parallel to each other at a distance of 8 cm. The magnetic field at the mid point between the two wires is __________ μT. (μ04π=10−7 N/A2)\left(\frac{\mu_{0}}{4\pi} = 10^{-7} \text{ N/A}^{2}\right)(4πμ0​​=10−7 N/A2)
  1. (A)30
  2. (B)300
  3. (C)150
  4. (D)0.0

Correct answer: (B)

Step-by-step solution →
Q14·PhysicsSingle correct
A square loop of side 2 cm is placed in a time varying magnetic field with magnitude as B=0.4sin⁡(300t)B = 0.4\sin(300t)B=0.4sin(300t) Tesla. The normal to the plane of loop makes an angle of 60° with the field. The maximum induced emf produced in the loop is __________ mV.
  1. (A)12
  2. (B)18
  3. (C)21
  4. (D)24

Correct answer: (D)

Step-by-step solution →
Q15·PhysicsSingle correct
A sphere of capacitance 100 pF is charged to a potential of 100 V. Another identical uncharged metal sphere is brought in contact with the charged sphere, then the change in the total energy stored on these spheres, when they touch is α×10−7\alpha \times 10^{-7}α×10−7 J. The value of α\alphaα is __________. (combined capacitance of spheres is 200 pF)
  1. (A)5
  2. (B)52\frac{5}{2}25​
  3. (C)72\frac{7}{2}27​
  4. (D)92\frac{9}{2}29​

Correct answer: (B)

Step-by-step solution →
Q16·PhysicsSingle correct
The energy released if hydrogen atoms are combined to form 24{}^{4}_{2}24​He is __________ MeV. (Take binding energies per nucleon of 12{}^{2}_{1}12​H and 24{}^{4}_{2}24​He as 1.1 MeV and 7.2 MeV, respectively)
  1. (A)6.1
  2. (B)24.4
  3. (C)26.6
  4. (D)5

Correct answer: (B)

Step-by-step solution →
Q17·PhysicsSingle correct
Angle of minimum deviation is equal to the half of the angle of prism in an equilateral prism. The refractive index of the prism is __________.
  1. (A)1.5
  2. (B)3\sqrt{3}3​
  3. (C)2\sqrt{2}2​
  4. (D)1.65

Correct answer: (C)

Step-by-step solution →
Q18·PhysicsSingle correct
Refer to the logic circuit given below. For two inputs (A=1,B=1)(A = 1, B = 1)(A=1,B=1) and (A=0,B=1)(A = 0, B = 1)(A=0,B=1), output (Y)(Y)(Y) will be __________.
  1. (A)1, 0 respectively
  2. (B)0, 1 respectively
  3. (C)0, 0 respectively
  4. (D)1, 1 respectively

Correct answer: (C)

Step-by-step solution →
Q19·PhysicsSingle correct
The velocity at which 6 kg mass (shown in figure) strikes the ground when it is released from a height of 6 m above the ground is __________ m/s. Assume pulley is massless and string is light and inextensible. (Take g =10= 10=10 m/s2^{2}2)
  1. (A)7.74
  2. (B)7.20
  3. (C)6.55
  4. (D)4.50

Correct answer: (A)

Step-by-step solution →
Q20·PhysicsSingle correct
In a Young double slit experiment, the wavelength of incident light is 6000 Å, the separation between slits S1S_{1}S1​ and S2S_{2}S2​ is 5 cm and the distance between slits plane and screen is 50 cm, as shown in the figure below. If the resultant intensity at PPP is equal to the intensity due to individual slits, the path difference between interfering waves is __________ Å.
  1. (A)4000
  2. (B)3000
  3. (C)2000
  4. (D)1000

Correct answer: (C)

Step-by-step solution →
Q21·PhysicsNumerical
A block takes ttt time to slide down a plane inclined at 45° to the horizontal. If the surface is made smooth (frictionless), the block takes time t2\frac{t}{2}2t​ to slide down the plane. The coefficient of friction between the block and the inclined plane is (α100)\left(\frac{\alpha}{100}\right)(100α​). The value of α\alphaα is __________.

Correct answer: 75

Step-by-step solution →
Q22·PhysicsNumerical
The de Broglie wavelength for an electron accelerated through the potential difference of V1V_{1}V1​ volt is λ1\lambda_{1}λ1​. When the potential difference is changed to V2V_{2}V2​ volt, the associated de Broglie wavelength is increased by 50%. If (V1/V2)=(9/α)(V_{1}/V_{2}) = (9/\alpha)(V1​/V2​)=(9/α), then the value of α\alphaα is __________.

Correct answer: 4

Step-by-step solution →
Q23·PhysicsNumerical
A moving coil of galvanometer when shunted with 2 Ω resistance gives a full scale deflection for a current of 500 mA. When a resistance of 470 Ω is connected in series it gives a full scale deflection for 10 V potential applied on it. The value of resistance of galvanometer coil is __________ Ω.

Correct answer: 50

Step-by-step solution →
Q24·PhysicsNumerical
Two cells of emfs 1 V and 2 V and internal resistance 2 Ω and 1 Ω, respectively connected in parallel, gave a current of 1 A through an external resistance. If the polarity of one cell is reversed, then value of current through the external resistance will be α5\frac{\alpha}{5}5α​ A. The value of α\alphaα is __________.

Correct answer: 3

Step-by-step solution →
Q25·PhysicsNumerical
A concave mirror of focal length 10 cm forms an image which is double the size of object when the object is placed at two different positions. The distance between the two positions of the object is __________ cm.

Correct answer: 10

Step-by-step solution →

Chemistry — JEE Main 6 April 2026 Shift 2

Q26·ChemistrySingle correct
Which of the following contain the same number of atoms ? (Given : Molar mass in g mol−1^{-1}−1 of H, He, O and S are 1, 4, 16 and 32 respectively) A. 2 g of O2\mathrm{O_{2}}O2​ gas B. 4 g of SO2\mathrm{SO_{2}}SO2​ gas C. 1400 mL of O2\mathrm{O_{2}}O2​ at STP D. 0.05 L of He at STP E. 0.0625 mol of H2\mathrm{H_{2}}H2​ gas Choose the correct answer from the options given below :
  1. (A)A and B only
  2. (B)B and C only
  3. (C)C and D only
  4. (D)A, C and E only

Correct answer: (D)

Step-by-step solution →
Q27·ChemistrySingle correct
The Bohr radius of a hydrogen like species is 70.53 pm. The species and the stationary state (n)(n)(n) are respectively (Given : Hydrogen atom Bohr radius is 52.9 pm)
  1. (A)Li2+\mathrm{Li^{2+}}Li2+, 3
  2. (B)He+\mathrm{He^{+}}He+, 3
  3. (C)He+\mathrm{He^{+}}He+, 2
  4. (D)Li2+\mathrm{Li^{2+}}Li2+, 2

Correct answer: (D)

Step-by-step solution →
Q28·ChemistrySingle correct
Given below are two statements : Statement I : The number of compounds among SO2\mathrm{SO_{2}}SO2​, SO3\mathrm{SO_{3}}SO3​, SF4\mathrm{SF_{4}}SF4​, SF6\mathrm{SF_{6}}SF6​ and H2S\mathrm{H_{2}S}H2​S in which sulphur does not obey the Octet rule is 3. Statement II : Among [H2O[\mathrm{H_{2}O}[H2​O, ClF3\mathrm{ClF_{3}}ClF3​, SF4]\mathrm{SF_{4}}]SF4​], [NH3[\mathrm{NH_{3}}[NH3​, BrF5\mathrm{BrF_{5}}BrF5​, SF4]\mathrm{SF_{4}}]SF4​], [BrF5[\mathrm{BrF_{5}}[BrF5​, ClF3\mathrm{ClF_{3}}ClF3​, XeF4]\mathrm{XeF_{4}}]XeF4​] and [XeF4[\mathrm{XeF_{4}}[XeF4​, ClF3\mathrm{ClF_{3}}ClF3​, H2O]\mathrm{H_{2}O}]H2​O], the number of sets in which all the molecules have one lone pair of electrons on the central atom is 1. In the light of the above statements, choose the correct answer from the options given below :
  1. (A)Both Statement I and Statement II are true
  2. (B)Both Statement I and Statement II are false
  3. (C)Statement I is true but Statement II is false
  4. (D)Statement I is false but Statement II is true

Correct answer: (D)

Step-by-step solution →
Q29·ChemistrySingle correct
Match List - I (Isothermal process) with List - II (Expression). Given V1V_{1}V1​ and V2V_{2}V2​ are initial and final volumes respectively. Choose the correct answer from the options given below :
List - I (Isothermal process)List - II (Expression)
A.Reversible expansionI.q=0q = 0q=0
B.Free expansionII.q=nRTln⁡V2V1q = nRT \ln \frac{V_{2}}{V_{1}}q=nRTlnV1​V2​​
C.Irreversible CompressionIII.w=−pext(V1−V2)w = -p_{ext}(V_{1} - V_{2})w=−pext​(V1​−V2​)
D.Cyclic reversibleIV.qrevT=0\frac{q_{rev}}{T} = 0Tqrev​​=0
  1. (A)A-II, B-III, C-I, D-IV
  2. (B)A-II, B-I, C-IV, D-III
  3. (C)A-II, B-I, C-III, D-IV
  4. (D)A-I, B-II, C-III, D-IV

Correct answer: (C)

Step-by-step solution →
Q30·ChemistrySingle correct
Given below are two statements : Statement I : H2O\mathrm{H_{2}O}H2​O molecules move from the chamber 1 to chamber 2. Statement II : The osmotic pressure of a solution prepared by dissolving 50 mg of potassium sulphate (molar mass = 174 g/mol) in 2 L of water (at 27 °C) is 0.0107 bar. (Given : R = 0.083 dm3^{3}3 bar K−1^{-1}−1 mol−1^{-1}−1 and assume complete dissociation of electrolyte) In the light of the above statements, choose the correct answer from the options given below :
  1. (A)Both Statement I and Statement II are true
  2. (B)Both Statement I and Statement II are false
  3. (C)Statement I is true but Statement II is false
  4. (D)Statement I is false but Statement II is true

Correct answer: (D)

Step-by-step solution →
Q31·ChemistrySingle correct
Given is a concentrated solution of a weak electrolyte AxByA_{x}B_{y}Ax​By​ of concentration 'c' and dissociation constant 'K'. The degree of dissociation is given by :
  1. (A)[K×cx+y−1xxyy]x+y\left[K \times c^{x+y-1} x^{x} y^{y}\right]^{x+y}[K×cx+y−1xxyy]x+y
  2. (B)(Kcx+y−1xxyy)1x+y\left(\frac{K}{c^{x+y-1} x^{x} y^{y}}\right)^{\frac{1}{x+y}}(cx+y−1xxyyK​)x+y1​
  3. (C)(cx+y−1xxyyK)x+y\left(\frac{c^{x+y-1} x^{x} y^{y}}{K}\right)^{x+y}(Kcx+y−1xxyy​)x+y
  4. (D)(cx+y−1xxyyK)1x+y\left(\frac{c^{x+y-1} x^{x} y^{y}}{K}\right)^{\frac{1}{x+y}}(Kcx+y−1xxyy​)x+y1​

Correct answer: (B)

Step-by-step solution →
Q32·ChemistrySingle correct
For a general redox reaction Anode : Red1→Ox1n1++n1e−\mathrm{Red_{1}} \rightarrow \mathrm{Ox_{1}^{n_{1}^{+}}} + n_{1}e^{-}Red1​→Ox1n1+​​+n1​e− Cathode : Ox2+n2e−→Red2n2−\mathrm{Ox_{2}} + n_{2}e^{-} \rightarrow \mathrm{Red_{2}^{n_{2}^{-}}}Ox2​+n2​e−→Red2n2−​​ Which of the following statement is incorrect ?
  1. (A)The overall reaction can be written as n2Red1+n1Ox2⇌n2Ox1n1++n1Red2n2−n_{2}\mathrm{Red_{1}} + n_{1}\mathrm{Ox_{2}} \rightleftharpoons n_{2}\mathrm{Ox_{1}^{n_{1}^{+}}} + n_{1}\mathrm{Red_{2}^{n_{2}^{-}}}n2​Red1​+n1​Ox2​⇌n2​Ox1n1+​​+n1​Red2n2−​​
  2. (B)The electrons do not appear in the overall reaction because electrons produced at the anode are consumed at the cathode.
  3. (C)Here nnn is the number of electrons transferred in redox reaction.
  4. (D)If the reaction is carried out reversibly, the electrical work done is equal to the ratio of charge and potential difference through which charge is moved.

Correct answer: (D)

Step-by-step solution →
Q33·ChemistrySingle correct
In a period, the first ionisation enthalpy of the element at extreme left and the negative electron gain enthalpy of the extreme right element, except noble gases, are respectively.
  1. (A)lowest and lowest
  2. (B)highest and lowest
  3. (C)lowest and highest
  4. (D)highest and highest

Correct answer: (C)

Step-by-step solution →
Q34·ChemistrySingle correct
Given below are two statements : Statement I : F2O<H2O<Cl2O\mathrm{F_{2}O} < \mathrm{H_{2}O} < \mathrm{Cl_{2}O}F2​O<H2​O<Cl2​O is the correct trend in terms of bond angle. Statement II : SiF4\mathrm{SiF_{4}}SiF4​, SnF4\mathrm{SnF_{4}}SnF4​ and PbF4\mathrm{PbF_{4}}PbF4​ are ionic in nature. In the light of the above statements, choose the correct answer from the options given below :
  1. (A)Both Statement I and Statement II are true
  2. (B)Both Statement I and Statement II are false
  3. (C)Statement I is true but Statement II is false
  4. (D)Statement I is false but Statement II is true

Correct answer: (C)

Step-by-step solution →
Q35·ChemistrySingle correct
The correct order of first (ΔiH1)(\Delta_{i}H_{1})(Δi​H1​) and second (ΔiH2)(\Delta_{i}H_{2})(Δi​H2​) ionisation enthalpy values of Cr and Mn are : A. ΔiH1\Delta_{i}H_{1}Δi​H1​ : Cr > Mn B. ΔiH2\Delta_{i}H_{2}Δi​H2​ : Cr > Mn C. ΔiH1\Delta_{i}H_{1}Δi​H1​ : Mn > Cr D. ΔiH2\Delta_{i}H_{2}Δi​H2​ : Mn > Cr Choose the correct answer from the options given below :
  1. (A)A and B only
  2. (B)B and C only
  3. (C)A and D only
  4. (D)C and D only

Correct answer: (B)

Step-by-step solution →
Q36·ChemistrySingle correct
Which of the following sequences of hybridisation, geometry and magnetic nature are correct for the given coordination compounds ? A. [NiCl4]2−[\mathrm{NiCl_{4}}]^{2-}[NiCl4​]2− − sp3\mathrm{sp^{3}}sp3, tetrahedral, paramagnetic B. [Ni(NH3)6]2+[\mathrm{Ni(NH_{3})_{6}}]^{2+}[Ni(NH3​)6​]2+ − sp3d2\mathrm{sp^{3}d^{2}}sp3d2, octahedral, paramagnetic C. [Ni(CO)4][\mathrm{Ni(CO)_{4}}][Ni(CO)4​] − sp3\mathrm{sp^{3}}sp3, tetrahedral, paramagnetic D. [Ni(CN)4]2−[\mathrm{Ni(CN)_{4}}]^{2-}[Ni(CN)4​]2− − dsp2\mathrm{dsp^{2}}dsp2, square planar, diamagnetic Choose the correct answer from the options given below :
  1. (A)A, B, C and D
  2. (B)B, C and D only
  3. (C)A, C and D only
  4. (D)A, B and D only

Correct answer: (D)

Step-by-step solution →
Q37·ChemistrySingle correct
Given below are two statements : Statement I : A mixture of C12H22O11\mathrm{C_{12}H_{22}O_{11}}C12​H22​O11​ (sugar) and NaCl can be separated by dissolving sugar in alcohol, due to differential solubility. Statement II : Rose essence from rose petals is seperated by steam distillation due to its high volatility and insolubility in H2O\mathrm{H_{2}O}H2​O. In the light of the above statements, choose the correct answer from the options given below :
  1. (A)Both Statement I and Statement II are true
  2. (B)Both Statement I and Statement II are false
  3. (C)Statement I is true but Statement II is false
  4. (D)Statement I is false but Statement II is true

Correct answer: (A)

Step-by-step solution →
Q38·Chemistry·Electronic Effects and StabilitySingle correct
Shown below is the structure of methyl acetate with three different α, β and γ carbon - oxygen bonds. The correct order of bond lengths of these bonds is :
  1. (A)α>β>γ\alpha > \beta > \gammaα>β>γ
  2. (B)α<β<γ\alpha < \beta < \gammaα<β<γ
  3. (C)α=β=γ\alpha = \beta = \gammaα=β=γ
  4. (D)α<β=γ\alpha < \beta = \gammaα<β=γ

Correct answer: (B)

Step-by-step solution →
Q39·ChemistrySingle correct
'xxx' is the product which is obtained by the hydrolysis of prop-1-yne in the presence of mercuric sulphate under dilute acidic medium at 333 K. 'yyy' is the product which is obtained by the reaction of ethane nitrile with methyl magnesium bromide in dry ether followed by hydrolysis. IUPAC name of product obtained from 'xxx' and 'yyy' in the presence of barium hydroxide followed by heating is :
  1. (A)2-Methylpent-4-en-3-one
  2. (B)4-Methylpent-3-en-2-one
  3. (C)4-Methylpent-1-ene
  4. (D)2-Methylpent-3-one

Correct answer: (B)

Step-by-step solution →
Q40·ChemistrySingle correct
An optically active alkyl bromide C4H9Br\mathrm{C_{4}H_{9}Br}C4​H9​Br, reacts with ethanolic KOH to form major compound [A] which reacts with bromine to give compound [B]. Compound [B] reacts with ethanolic KOH and sodamide to give compound [C]. One molecule of water adds to compound [C] on warming with mercuric sulphate and dilute sulphuric acid at 333 K to form compound [D]. The functional group in compound D will be confirmed by :
  1. (A)Haloform test
  2. (B)Lucas test
  3. (C)Silver mirror test
  4. (D)Benedict test

Correct answer: (A)

Step-by-step solution →
Q41·ChemistrySingle correct
Consider the following reaction. Statement I : In the above reaction, product formed will be a mixture of benzyl alcohol and iodobenzene. Statement II : In the above reaction, the −O−CH2−-\mathrm{O}-\mathrm{CH_{2}}-−O−CH2​− bond is cleaved to give the product. In the light of the above statements, choose the correct answer from the options given below :
  1. (A)Both Statement I and Statement II are true
  2. (B)Both Statement I and Statement II are false
  3. (C)Statement I is true but Statement II is false
  4. (D)Statement I is false but Statement II is true

Correct answer: (D)

Step-by-step solution →
Q42·ChemistrySingle correct
Consider the following organic reaction sequence. Choose the final product (X)(X)(X) from the following (consider the major product in all intermediate reactions)
  1. (A)Benzene
  2. (B)Phenol
  3. (C)Propanol
  4. (D)Chlorobenzene

Correct answer: (A)

Step-by-step solution →
Q43·ChemistrySingle correct
The number of compounds from the following which can undergo reaction with Br2\mathrm{Br_{2}}Br2​/KOH (alcoholic) to give respective products and these respective products can also be obtained separately by Gabriel phthalimide reaction is :
  1. (A)5
  2. (B)4
  3. (C)3
  4. (D)6

Correct answer: (C)

Step-by-step solution →
Q44·ChemistrySingle correct
Consider the following reactions. Total number of electrons in the π bonds and lone pair of electrons in the product (X)(X)(X) is :
  1. (A)12
  2. (B)16
  3. (C)14
  4. (D)18

Correct answer: (D)

Step-by-step solution →
Q45·ChemistrySingle correct
Treatment of a gas 'XXX' with a freshly prepared ferrous sulphate solution gives a compound 'YYY' as a brown ring. The compounds XXX and YYY are.
  1. (A)NO and [Fe(NO)]SO4[\mathrm{Fe(NO)}]\mathrm{SO_{4}}[Fe(NO)]SO4​
  2. (B)NO2\mathrm{NO_{2}}NO2​ and [Fe(NO2)]SO4[\mathrm{Fe(NO_{2})}]\mathrm{SO_{4}}[Fe(NO2​)]SO4​
  3. (C)N2O\mathrm{N_{2}O}N2​O and [Fe(N2O)]SO4[\mathrm{Fe(N_{2}O)}]\mathrm{SO_{4}}[Fe(N2​O)]SO4​
  4. (D)N2O4\mathrm{N_{2}O_{4}}N2​O4​ and [Fe(N2O4)]SO4[\mathrm{Fe(N_{2}O_{4})}]\mathrm{SO_{4}}[Fe(N2​O4​)]SO4​

Correct answer: (A)

Step-by-step solution →
Q46·ChemistryNumerical
An excess of AgNO3\mathrm{AgNO_{3}}AgNO3​ is added to 100 mL of a 0.05 M solution of tetraaquadichloridochromium (III) chloride. The number of moles of AgCl precipitated will be __________ ×10−3\times 10^{-3}×10−3. (Nearest integer)

Correct answer: 5

Step-by-step solution →
Q47·ChemistryNumerical
An alkane (Y)(Y)(Y) requires 8 moles of oxygen for complete combustion and on chlorination with Cl2\mathrm{Cl_{2}}Cl2​/hνh\nuhν, (Y)(Y)(Y) gives only one monochlorinated product (Z)(Z)(Z). The total number of primary carbon atoms in (Y)(Y)(Y) is __________.

Correct answer: 4

Step-by-step solution →
Q48·ChemistryNumerical
500 mL of 0.2 M MnO4−\mathrm{MnO_{4}^{-}}MnO4−​ solution in basic medium when mixed with 500 mL of 1.5 M KI solution, oxidises iodide ions to liberate molecular iodine. This liberated iodine is then titrated with a standard xxx M thiosulphate solution in presence of starch till the end point. If 300 mL of thiosulphate was consumed, then the value of xxx is __________.

Correct answer: 1

Step-by-step solution →
Q49·ChemistryNumerical
In a closed flask at 600 K, one mole of X2Y4(g)\mathrm{X_{2}Y_{4}(g)}X2​Y4​(g) attains equilibrium as given below : X2Y4(g)⇌2XY2(g)\mathrm{X_{2}Y_{4}}(g) \rightleftharpoons 2\mathrm{XY_{2}}(g)X2​Y4​(g)⇌2XY2​(g) At equilibrium, 75% X2Y4(g)\mathrm{X_{2}Y_{4}(g)}X2​Y4​(g) was dissociated and the total pressure is 1 atm. The magnitude of ΔrG⊖\Delta_{r}G^{\ominus}Δr​G⊖ (in kJ mol−1^{-1}−1) at this temperature is __________. (Nearest Integer) (Given : R = 8.3 J mol−1^{-1}−1 K−1^{-1}−1; ln 10 = 2.3, log 2 = 0.3, log 3 = 0.48, log 5 = 0.69, log 7 = 0.84)

Correct answer: 8

Step-by-step solution →
Q50·ChemistryNumerical
Decomposition of a hydrocarbon follows the equation k=(5.5×1011 s−1) e−28000 KTk = (5.5 \times 10^{11}\ \mathrm{s^{-1}})\, e^{\frac{-28000\ \mathrm{K}}{T}}k=(5.5×1011 s−1)eT−28000 K​. The activation energy of reaction is __________ kJ mol−1^{-1}−1. (Nearest Integer) Given : R = 8.3 J K−1^{-1}−1 mol−1^{-1}−1

Correct answer: 232

Step-by-step solution →

Mathematics — JEE Main 6 April 2026 Shift 2

Q51·MathematicsSingle correct
Let f:R→Rf : \mathbb{R} \to \mathbb{R}f:R→R be defined as f(x)=2x2−3x+23x2+x+3f(x) = \frac{2x^{2} - 3x + 2}{3x^{2} + x + 3}f(x)=3x2+x+32x2−3x+2​. Then fff is :
  1. (A)both one-one and onto
  2. (B)one-one but not onto
  3. (C)onto but not one-one
  4. (D)neither one-one nor onto

Correct answer: (D)

Step-by-step solution →
Q52·MathematicsSingle correct
Consider the quadratic equation (n2−2n+2)x2−3x+(n2−2n+2)2=0(n^{2} - 2n + 2)x^{2} - 3x + (n^{2} - 2n + 2)^{2} = 0(n2−2n+2)x2−3x+(n2−2n+2)2=0, n∈Rn \in \mathbb{R}n∈R. Let α be the minimum value of the product of its roots and β be the maximum value of the sum of its roots. Then the sum of the first six terms of the G.P., whose first term is α and the common ratio is αβ\frac{\alpha}{\beta}βα​, is :
  1. (A)6137\frac{61}{37}3761​
  2. (B)12181\frac{121}{81}81121​
  3. (C)364243\frac{364}{243}243364​
  4. (D)1093729\frac{1093}{729}7291093​

Correct answer: (C)

Step-by-step solution →
Q53·MathematicsSingle correct
Let S={z∈C:z2+6 iz−3=0}S = \{z \in \mathbb{C} : z^{2} + \sqrt{6}\,iz - 3 = 0\}S={z∈C:z2+6​iz−3=0}. Then ∑z∈Sz8\sum_{z \in S} z^{8}∑z∈S​z8 is equal to :
  1. (A)162
  2. (B)184
  3. (C)262
  4. (D)324

Correct answer: (A)

Step-by-step solution →
Q54·MathematicsSingle correct
The sum of all possible values of θ ∈ [0, 2π], for which the system of equations : xcos⁡3θ−8y−12z=0x\cos 3\theta - 8y - 12z = 0xcos3θ−8y−12z=0 xcos⁡2θ+3y+3z=0x\cos 2\theta + 3y + 3z = 0xcos2θ+3y+3z=0 x+y+3z=0x + y + 3z = 0x+y+3z=0 has a non-trivial solution, is equal to :
  1. (A)π
  2. (B)2π
  3. (C)3π
  4. (D)4π

Correct answer: (D)

Step-by-step solution →
Q55·MathematicsSingle correct
Let A=[100310931]A = \begin{bmatrix} 1 & 0 & 0 \\ 3 & 1 & 0 \\ 9 & 3 & 1 \end{bmatrix}A=​139​013​001​​ and B=[bij]B = [b_{ij}]B=[bij​], 1≤i,j≤31 \leq i, j \leq 31≤i,j≤3. If B=A99−IB = A^{99} - IB=A99−I, then the value of b31−b21b32\frac{b_{31} - b_{21}}{b_{32}}b32​b31​−b21​​ is :
  1. (A)99
  2. (B)199
  3. (C)149
  4. (D)159

Correct answer: (C)

Step-by-step solution →
Q56·MathematicsSingle correct
The sum 1+12(12+22)+13(12+22+32)+…1 + \frac{1}{2}(1^{2} + 2^{2}) + \frac{1}{3}(1^{2} + 2^{2} + 3^{2}) + \ldots1+21​(12+22)+31​(12+22+32)+… upto 10 terms is equal to :
  1. (A)130
  2. (B)155
  3. (C)3152\frac{315}{2}2315​
  4. (D)3252\frac{325}{2}2325​

Correct answer: (C)

Step-by-step solution →
Q57·MathematicsSingle correct
A building has ground floor and 10 more floors. Nine persons enter in a lift at the ground floor. The lift goes up to the 10th10^{\text{th}}10th floor. The number of ways, in which any 4 persons exit at a floor and the remaining 5 persons exit at a different floor, if the lift does not stop at the first and the second floors, is equal to :
  1. (A)2184
  2. (B)3064
  3. (C)7056
  4. (D)11340

Correct answer: (C)

Step-by-step solution →
Q58·MathematicsSingle correct
Let the mean and the variance of seven observations 2, 4, α, 8, β, 12, 14, α < β, be 8 and 16 respectively. Then the quadratic equation whose roots are 3α + 2 and 2β + 1 is :
  1. (A)x2−35x+306=0x^{2} - 35x + 306 = 0x2−35x+306=0
  2. (B)x2−41x+420=0x^{2} - 41x + 420 = 0x2−41x+420=0
  3. (C)x2−45x+506=0x^{2} - 45x + 506 = 0x2−45x+506=0
  4. (D)x2−37x+342=0x^{2} - 37x + 342 = 0x2−37x+342=0

Correct answer: (B)

Step-by-step solution →
Q59·MathematicsSingle correct
A bag contains 6 blue and 6 green balls. Pairs of balls are drawn without replacement until the bag is empty. The probability that each drawn pair consists of one blue and one green ball is :
  1. (A)63925\frac{63}{925}92563​
  2. (B)17231\frac{17}{231}23117​
  3. (C)16231\frac{16}{231}23116​
  4. (D)64925\frac{64}{925}92564​

Correct answer: (C)

Step-by-step solution →
Q60·MathematicsSingle correct
Let CCC be a circle having centre in the first quadrant and touching the xxx-axis at a distance of 3 units from the origin. If the circle CCC has an intercept of length 636\sqrt{3}63​ on yyy-axis, then the length of the chord of the circle CCC on the line x−y=3x - y = 3x−y=3 is :
  1. (A)8
  2. (B)6
  3. (C)626\sqrt{2}62​
  4. (D)828\sqrt{2}82​

Correct answer: (C)

Step-by-step solution →
Q61·MathematicsSingle correct
The eccentricity of an ellipse EEE with centre at the origin OOO is 32\frac{\sqrt{3}}{2}23​​ and its directrices are x=±463x = \pm\frac{4\sqrt{6}}{3}x=±346​​. Let H:x2a2−y2b2=1H : \frac{x^{2}}{a^{2}} - \frac{y^{2}}{b^{2}} = 1H:a2x2​−b2y2​=1 be a hyperbola whose eccentricity is equal to the length of semi-major axis of EEE, and whose length of latus rectum is equal to the length of minor axis of EEE. Then the distance between the foci of HHH is :
  1. (A)427\frac{4\sqrt{2}}{\sqrt{7}}7​42​​
  2. (B)427\frac{4\sqrt{2}}{7}742​​
  3. (C)47\frac{4}{\sqrt{7}}7​4​
  4. (D)87\frac{8}{7}78​

Correct answer: (D)

Step-by-step solution →
Q62·MathematicsSingle correct
Let x=9x = 9x=9 be a directrix of an ellipse EEE, whose centre is at the origin and eccentricity is 13\frac{1}{3}31​. Let P(α,0)P(\alpha, 0)P(α,0), α>0\alpha > 0α>0, be a focus of EEE and ABABAB be a chord passing through PPP. Then the locus of the mid point of ABABAB is :
  1. (A)9y2=8x(1−x)9y^{2} = 8x(1 - x)9y2=8x(1−x)
  2. (B)3y2=4x(1−x)3y^{2} = 4x(1 - x)3y2=4x(1−x)
  3. (C)9y2=8x(x−1)9y^{2} = 8x(x - 1)9y2=8x(x−1)
  4. (D)3y2=4x(x−1)3y^{2} = 4x(x - 1)3y2=4x(x−1)

Correct answer: (A)

Step-by-step solution →
Q63·MathematicsSingle correct
If sin⁡(tan⁡−1(x2))=cot⁡(sin⁡−11−x2)\sin(\tan^{-1}(x\sqrt{2})) = \cot(\sin^{-1}\sqrt{1 - x^{2}})sin(tan−1(x2​))=cot(sin−11−x2​), x∈(0,1)x \in (0, 1)x∈(0,1), then the value of xxx is :
  1. (A)12\frac{1}{2}21​
  2. (B)13\frac{1}{3}31​
  3. (C)23\frac{2}{3}32​
  4. (D)58\frac{5}{8}85​

Correct answer: (A)

Step-by-step solution →
Q64·MathematicsSingle correct
The shortest distance between the lines x−41=y−32=z−2−3\frac{x-4}{1} = \frac{y-3}{2} = \frac{z-2}{-3}1x−4​=2y−3​=−3z−2​ and x+22=y−64=z−5−5\frac{x+2}{2} = \frac{y-6}{4} = \frac{z-5}{-5}2x+2​=4y−6​=−5z−5​ is :
  1. (A)566\frac{5\sqrt{6}}{6}656​​
  2. (B)252\sqrt{5}25​
  3. (C)353\sqrt{5}35​
  4. (D)454\sqrt{5}45​

Correct answer: (C)

Step-by-step solution →
Q65·MathematicsSingle correct
Let a⃗=2i^+3j^+3k^\vec{a} = 2\hat{i} + 3\hat{j} + 3\hat{k}a=2i^+3j^​+3k^ and b⃗=6i^+3j^+3k^\vec{b} = 6\hat{i} + 3\hat{j} + 3\hat{k}b=6i^+3j^​+3k^. Then the square of the area of the triangle with adjacent sides determined by the vectors (2a⃗+3b⃗)(2\vec{a} + 3\vec{b})(2a+3b) and (a⃗−b⃗)(\vec{a} - \vec{b})(a−b) is :
  1. (A)450
  2. (B)900
  3. (C)1800
  4. (D)2400

Correct answer: (C)

Step-by-step solution →
Q66·MathematicsSingle correct
Let lim⁡x→2(tan⁡(x−2))(rx2+(p−2)x−2p)(x−2)2=5\lim_{x \to 2} \frac{(\tan(x-2))(rx^{2} + (p-2)x - 2p)}{(x-2)^{2}} = 5limx→2​(x−2)2(tan(x−2))(rx2+(p−2)x−2p)​=5 for some r,p∈Rr, p \in \mathbb{R}r,p∈R. If the set of all possible values of qqq, such that the roots of the equation rx2−px+q=0rx^{2} - px + q = 0rx2−px+q=0 lie in (0,2)(0, 2)(0,2), be the interval (α,β](\alpha, \beta](α,β], then 4(α+β)4(\alpha + \beta)4(α+β) equals :
  1. (A)11
  2. (B)13
  3. (C)17
  4. (D)21

Correct answer: (C)

Step-by-step solution →
Q67·MathematicsSingle correct
Let A=[13−121α01−1]A = \begin{bmatrix} 1 & 3 & -1 \\ 2 & 1 & \alpha \\ 0 & 1 & -1 \end{bmatrix}A=​120​311​−1α−1​​ be a singular matrix. Let f(x)=∫0x(t2+2t+3) dtf(x) = \int_{0}^{x} (t^{2} + 2t + 3)\, dtf(x)=∫0x​(t2+2t+3)dt, x∈[1,α]x \in [1, \alpha]x∈[1,α]. If MMM and mmm are respectively the maximum and the minimum values of fff in [1,α][1, \alpha][1,α], then 3(M−m)3(M - m)3(M−m) is equal to :
  1. (A)64
  2. (B)68
  3. (C)72
  4. (D)76

Correct answer: (B)

Step-by-step solution →
Q68·MathematicsSingle correct
Let f:R→Rf : \mathbb{R} \to \mathbb{R}f:R→R be such that f(xy)=f(x)f(y)f(xy) = f(x)f(y)f(xy)=f(x)f(y), for all x,y∈Rx, y \in \mathbb{R}x,y∈R and f(0)≠0f(0) \neq 0f(0)=0. Let g:[1,∞)→Rg : [1, \infty) \to \mathbb{R}g:[1,∞)→R be a differentiable function such that x2g(x)=∫1x(t2f(t)−tg(t)) dt.x^{2}g(x) = \int_{1}^{x} (t^{2}f(t) - tg(t))\, dt.x2g(x)=∫1x​(t2f(t)−tg(t))dt. Then g(2)g(2)g(2) is equal to :
  1. (A)138\frac{13}{8}813​
  2. (B)1116\frac{11}{16}1611​
  3. (C)1532\frac{15}{32}3215​
  4. (D)1764\frac{17}{64}6417​

Correct answer: (C)

Step-by-step solution →
Q69·MathematicsSingle correct
The area of the region {(x,y):x2−8x≤y≤−x}\{(x, y) : x^{2} - 8x \le y \le -x\}{(x,y):x2−8x≤y≤−x} is :
  1. (A)3436\frac{343}{6}6343​
  2. (B)6376\frac{637}{6}6637​
  3. (C)4376\frac{437}{6}6437​
  4. (D)5236\frac{523}{6}6523​

Correct answer: (A)

Step-by-step solution →
Q70·MathematicsSingle correct
The value of the integral ∫−11(x3+∣x∣+1x2+2∣x∣+1)dx\int_{-1}^{1} \left( \frac{x^{3} + |x| + 1}{x^{2} + 2|x| + 1} \right) dx∫−11​(x2+2∣x∣+1x3+∣x∣+1​)dx is equal to :
  1. (A)3log⁡e23\log_{e} 23loge​2
  2. (B)2log⁡e22\log_{e} 22loge​2
  3. (C)5log⁡e35\log_{e} 35loge​3
  4. (D)3log⁡e33\log_{e} 33loge​3

Correct answer: (B)

Step-by-step solution →
Q71·MathematicsNumerical
Let R={(x,y)∈N×N:log⁡e(x+y)≤2}R = \{(x, y) \in \mathbb{N} \times \mathbb{N} : \log_{e}(x + y) \le 2\}R={(x,y)∈N×N:loge​(x+y)≤2}. Then the minimum number of elements, required to be added in RRR to make it a transitive relation, is __________.

Correct answer: 15

Step-by-step solution →
Q72·MathematicsNumerical
If (1−x3)10=∑r=010arxr(1−x)30−2r(1 - x^{3})^{10} = \sum_{r=0}^{10} a_{r} x^{r} (1 - x)^{30-2r}(1−x3)10=∑r=010​ar​xr(1−x)30−2r, then 9a9a10\frac{9a_{9}}{a_{10}}a10​9a9​​ is equal to __________.

Correct answer: 30

Step-by-step solution →
Q73·MathematicsNumerical
Let the line x−y=4x - y = 4x−y=4 intersect the circle C:(x−4)2+(y+3)2=9C : (x - 4)^{2} + (y + 3)^{2} = 9C:(x−4)2+(y+3)2=9 at the points QQQ and RRR. If P(α,β)P(\alpha, \beta)P(α,β) is a point on CCC such that PQ=PRPQ = PRPQ=PR, then (6α+8β)2(6\alpha + 8\beta)^{2}(6α+8β)2 is equal to __________.

Correct answer: 18

Step-by-step solution →
Q74·MathematicsNumerical
Let the image of the point P(0,−5,0)P(0, -5, 0)P(0,−5,0) in the line x−12=y1=z+1−2\frac{x-1}{2} = \frac{y}{1} = \frac{z+1}{-2}2x−1​=1y​=−2z+1​ be the point RRR and the image of the point Q(0,−12,0)Q\left(0, \frac{-1}{2}, 0\right)Q(0,2−1​,0) in the line x−1−1=y+94=z+11\frac{x-1}{-1} = \frac{y+9}{4} = \frac{z+1}{1}−1x−1​=4y+9​=1z+1​ be the point SSS. Then the square of the area of the parallelogram PQRSPQRSPQRS is __________.

Correct answer: 162

Step-by-step solution →
Q75·Mathematics·Limits and ContinuityNumerical
Let f(x)={x3+8;x<0x2−4;x≥0f(x) = \begin{cases} x^{3} + 8; & x < 0 \\ x^{2} - 4; & x \ge 0 \end{cases}f(x)={x3+8;x2−4;​x<0x≥0​ and g(x)={(x−8)1/3;x<0(x+4)1/2;x≥0g(x) = \begin{cases} (x - 8)^{1/3}; & x < 0 \\ (x + 4)^{1/2}; & x \ge 0 \end{cases}g(x)={(x−8)1/3;(x+4)1/2;​x<0x≥0​. Then the number of points, where the function g∘fg \circ fg∘f is discontinuous, is __________.

Correct answer: 3

Step-by-step solution →

Chapters tested in this paper

Open any chapter to practise every past-year question on that topic across all papers, and see how often it has actually appeared.

  • Properties of Solids and Liquids 172/186
  • Three Dimensional Geometry 176/186
  • Matrices and Determinants 180/186
  • Coordination Compounds 176/186
  • Sets, Relations and Functions 165/186
  • Current Electricity 160/186
  • Sequence and Series 164/186
  • p-Block Elements 164/186
  • Definite Integration 168/186
  • Rotational Motion 172/186
  • Redox Reactions and Electrochemistry 177/186
  • Geometrical Optics 172/186
  • Vector Algebra 173/186
  • Differential Equations 167/186
  • Probability 176/186
  • Permutations and Combinations 162/186
  • Magnetic Field of Current 147/186
  • Binomial Theorem and Its Simple Applications 158/186
  • Electromagnetic Waves 144/186
  • Chemical Bonding and Molecular Structure 151/186
  • Limits and Continuity 149/186
  • d- and f-Block Elements 126/186
  • Thermodynamics 154/186
  • Aldehydes and Ketones 135/186
  • Equilibrium 163/186
  • Solutions 158/186
  • Laws of Motion 130/186
  • Chemical Thermodynamics 165/186
  • Units and Measurements 149/186
  • Hydrocarbons 126/186
  • Complex Numbers 165/186
  • Biomolecules 162/186
  • Chemical Kinetics 169/186
  • Atomic Structure 161/186
  • Electronic Devices 145/186
  • Circles 142/186
  • Dual Nature of Matter and Radiation 155/186
  • Amines 133/186
  • Quadratic Equations 148/186
  • Work, Energy and Power 132/186
  • Some Basic Concepts in Chemistry 129/186
  • Electromagnetic Induction 120/186
  • Wave Optics 130/186
  • Area Under Curves 139/186
  • Kinetic Theory of Gases 135/186
  • Alcohols and Ethers 106/186
  • Purification and Characterisation of Organic Compounds 116/186
  • Oscillations 117/186
  • Nuclei 116/186
  • Capacitors and Dielectrics 115/186
  • Classification of Elements and Periodicity in Properties 113/186
  • Statistics 118/186
  • Ellipse 103/186
  • Inverse Trigonometric Functions 93/186
  • Electronic Effects and Stability 74/186
  • Hyperbola 77/186
  • Electric Potential 63/186
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