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JEE Main 9 January 2019 Shift 2 Question Paper with Answers

9 January 2019 · January session · 86 questions

86 of the 90 questions from the JEE Main 9 January 2019 Shift 2 paper, each with its correct answer and tagged to the chapter it tests. Free to read, no account needed.

4 questions are held back from this paper while we re-check the transcription or the answer key. We would rather show you nothing than show you an answer we are not confident is right.

Physics
29
Chemistry
30
Mathematics
27

Physics — JEE Main 9 January 2019 Shift 2

Q1·PhysicsSingle correct
At a given instant, say t = 0, two radioactive substances A and B have equal activates. The ratio RBRA\frac{R_B}{R_A}RA​RB​​ of their activities. The ratio RBRA\frac{R_B}{R_A}RA​RB​​ of their activates after time t itself decays with time t as e−3te^{-3t}e−3t. If the half-life of A is ℓn2\ell n2ℓn2, the half-life of B is:
  1. (A)4ℓn24\ell n24ℓn2
  2. (B)ℓn22\frac{\ell n2}{2}2ℓn2​
  3. (C)ℓn24\frac{\ell n2}{4}4ℓn2​
  4. (D)2ℓn22\ell n22ℓn2

Correct answer: (C)

Step-by-step solution →
Q2·PhysicsSingle correct
A power transmission line feeds input power at 2300 V to a step down transformer with its primary windings having 4000 turns. The output power is delivered at 230 V by the transformer. If the current in the primary of the transformer is 5A and its efficiency is 90%, the output current would be:
  1. (A)50 A
  2. (B)45 A
  3. (C)35 A
  4. (D)25 A

Correct answer: (B)

Step-by-step solution →
Q3·PhysicsSingle correct
The energy associated with electric field is (UEU_EUE​) and with magnetic field is (UBU_BUB​) for an electromagnetic wave in free space. Then:
  1. (A)UE=UB2U_E = \frac{U_B}{2}UE​=2UB​​
  2. (B)UE>UBU_E > U_BUE​>UB​
  3. (C)UE<UBU_E < U_BUE​<UB​
  4. (D)UE=UBU_E = U_BUE​=UB​

Correct answer: (D)

Step-by-step solution →
Q4·PhysicsSingle correct
A force acts on a 2 kg object so that its position is given as a function of time as x=3t2+5x = 3t^{2} + 5x=3t2+5. What is the work done by this force in first 5 seconds?
  1. (A)850 J
  2. (B)950 J
  3. (C)875 J
  4. (D)900 J

Correct answer: (D)

Step-by-step solution →
Q5·PhysicsSingle correct
A particle having the same charge as of electron moves in a circular path of radius 0.5 cm under the influence of a magnetic field of 0.5 T. If an electric field of 100 V/m makes it to move in a straight path, then the mass of the particle is (given charge of electron =1.6×10−19= 1.6 \times 10^{-19}=1.6×10−19 C)
  1. (A)9.1×10−319.1 \times 10^{-31}9.1×10−31 kg
  2. (B)1.6×10−271.6 \times 10^{-27}1.6×10−27 kg
  3. (C)1.6×10−191.6 \times 10^{-19}1.6×10−19 kg
  4. (D)2.0×10−242.0 \times 10^{-24}2.0×10−24 kg

Correct answer: (D)

Step-by-step solution →
Q6·PhysicsSingle correct
Two point charges q1(10 μC)q_1(\sqrt{10}\ \mu C)q1​(10​ μC) and q2(−25 μC)q_2(-25\ \mu C)q2​(−25 μC) are placed on the x-axis at x = 1 m and x = 4 m respectively. The electric field (in V/m) at a point y = 3 m on y-axis is, [take 14πε0=9×109 Nm2C−2]\left[\text{take } \frac{1}{4\pi\varepsilon_0} = 9 \times 10^{9}\ Nm^{2}C^{-2}\right][take 4πε0​1​=9×109 Nm2C−2]
  1. (A)(63i^−27i^)×102(63\hat{i} - 27\hat{i}) \times 10^{2}(63i^−27i^)×102
  2. (B)(−63i^+27i^)×102(-63\hat{i} + 27\hat{i}) \times 10^{2}(−63i^+27i^)×102
  3. (C)(81i^−81i^)×102(81\hat{i} - 81\hat{i}) \times 10^{2}(81i^−81i^)×102
  4. (D)(−81i^+81i^)×102(-81\hat{i} + 81\hat{i}) \times 10^{2}(−81i^+81i^)×102

Correct answer: (A)

Step-by-step solution →
Q7·PhysicsSingle correct
Expression for time in terms of G (universal gravitational constant), h (Planck constant) and c (speed of light) is proportional to:
  1. (A)hc5G\sqrt{\dfrac{hc^{5}}{G}}Ghc5​​
  2. (B)c3Gh\sqrt{\dfrac{c^{3}}{Gh}}Ghc3​​
  3. (C)Ghc5\sqrt{\dfrac{Gh}{c^{5}}}c5Gh​​
  4. (D)Ghc3\sqrt{\dfrac{Gh}{c^{3}}}c3Gh​​

Correct answer: (C)

Step-by-step solution →
Q8·PhysicsSingle correct
Ge and Si diodes start conducting at 0.3 V and 0.7 V respectively. In the following figure if Ge diode connection are reversed, the value of VoV_oVo​ changes by: (assume that the Ge diode has large breakdown voltage)
  1. (A)0.8 V
  2. (B)0.6 V
  3. (C)0.2 V
  4. (D)0.4 V

Correct answer: (D)

Step-by-step solution →
Q9·PhysicsSingle correct
The top of a water tank is open to air and its water level is maintained. It is giving out 0.74 m30.74\ m^{3}0.74 m3 water per minute through a circular opening of 2 cm radius in its wall. The depth of the centre of the opening from the level of water in the tank is close to:
  1. (A)6.0 m
  2. (B)4.8 m
  3. (C)9.6 m
  4. (D)2.9 m

Correct answer: (B)

Step-by-step solution →
Q10·PhysicsSingle correct
The energy required to take a satellite to a height 'h' above Earth surface (radius of Earth =6.4×103= 6.4 \times 10^{3}=6.4×103 km) is E1E_1E1​ and kinetic energy required for the satellite to be in a circular orbit at this height is E2E_2E2​. The value of h for which E1E_1E1​ and E2E_2E2​ are equal is
  1. (A)1.6×1031.6 \times 10^{3}1.6×103 km
  2. (B)3.2×1033.2 \times 10^{3}3.2×103 km
  3. (C)6.4×1036.4 \times 10^{3}6.4×103 km
  4. (D)1.28×1041.28 \times 10^{4}1.28×104 km

Correct answer: (B)

Step-by-step solution →
Q11·PhysicsSingle correct
Two Carnot engines A and B are operated in series. The first one, A, receives heat at T1(=600T_1(= 600T1​(=600 K))) and rejects to a reservoir at temperature T2T_2T2​. The second engine B receives heat rejected by the first engine and, in turns, rejects to a heat reservoir at T3(=400T_3 (=400T3​(=400 K))). Calculate the temperature T2T_2T2​ if the work outputs of the two engines are equal:
  1. (A)600 K
  2. (B)400 K
  3. (C)300 K
  4. (D)500 K

Correct answer: (D)

Step-by-step solution →
Q12·PhysicsSingle correct
A series AC circuit containing an inductor (20 mH), a capacitor (120 μF\mu FμF) and a resistor (60 Ω\OmegaΩ) is driven by an AC source of 24 V/50 Hz. The energy dissipated in the circuit in 60 s is:
  1. (A)5.65×1025.65 \times 10^{2}5.65×102 J
  2. (B)2.26×1032.26 \times 10^{3}2.26×103 J
  3. (C)5.17×1025.17 \times 10^{2}5.17×102 J
  4. (D)3.39×1033.39 \times 10^{3}3.39×103 J

Correct answer: (C)

Step-by-step solution →
Q13·PhysicsSingle correct
A particle is executing simple harmonic motion (SHM) of amplitude A, along the x-axis, about x = 0. When its potential energy (PE) equals kinetic energy (KE), the position of the particle will be
  1. (A)A2\dfrac{A}{2}2A​
  2. (B)A22\dfrac{A}{2\sqrt{2}}22​A​
  3. (C)A2\dfrac{A}{\sqrt{2}}2​A​
  4. (D)A

Correct answer: (C)

Step-by-step solution →
Q14·PhysicsSingle correct
A mass of 10 kg is suspended vertically by a rope from the roof. When a horizontal force is applied on the rope at some point, the rope deviated at an angle of 45° at the roof point. If the suspended mass is at equilibrium, the magnitude of the force applied is (g = 10 ms−2ms^{-2}ms−2)
  1. (A)200 N
  2. (B)140 N
  3. (C)70 N
  4. (D)100 N

Correct answer: (D)

Step-by-step solution →
Q15·PhysicsSingle correct
A 15 g mass of nitrogen gas is enclosed in a vessel at a temperature 27°C. Amount of heat transferred to the gas, so that rms velocity of molecules is doubled, is about: [Take R = 8.3 J/K mole]
  1. (A)0.9 kJ
  2. (B)6 kJ
  3. (C)10 kJ
  4. (D)14 kJ

Correct answer: (C)

Step-by-step solution →
Q16·PhysicsSingle correct
In a Young's double slit experiment, the slits are placed 0.320 mm apart. Light of wavelength λ=500\lambda = 500λ=500 nm is incident on the slits. The total number of bright fringes that are observed in the angular range −30°≤θ≤30°-30° \leq \theta \leq 30°−30°≤θ≤30° is:
  1. (A)640
  2. (B)320
  3. (C)321
  4. (D)641

Correct answer: (D)

Step-by-step solution →
Q17·PhysicsSingle correct
Two plane mirrors are inclined to each other such that a ray of light incident to the first mirror (M1_11​) and parallel to the second mirror (M2_22​) is finally reflected from the second mirror (M2_22​) parallel to the first mirror (M1_11​). The angle between the two mirrors will be:
  1. (A)45°
  2. (B)60°
  3. (C)75°
  4. (D)90°

Correct answer: (B)

Step-by-step solution →
Q18·PhysicsSingle correct
A rod of length 50 cm is pivoted at one end. It is raised such that if makes an angle of 30° fro the horizontal as shown and released from rest. Its angular speed when it passes through the horizontal (in rad s−1^{-1}−1) will be (g = 10 ms−2^{-2}−2).
  1. (A)302\sqrt{\dfrac{30}{2}}230​​
  2. (B)30\sqrt{30}30​
  3. (C)202\sqrt{\dfrac{20}{2}}220​​
  4. (D)302\dfrac{\sqrt{30}}{2}230​​

Correct answer: (B)

Step-by-step solution →
Q19·PhysicsSingle correct
A carbon resistance has a following colour code. What is the value of the resistance?
  1. (A)530 kΩ ± 5%
  2. (B)5.3 MΩ ± 5%
  3. (C)6.4 MΩ ± 5%
  4. (D)64 kΩ ± 10%

Correct answer: (A)

Step-by-step solution →
Q20·PhysicsSingle correct
One of the two identical conducing wires of length L is bent in the form of a circular loop and the other one into a circular coil of N identical turns. If the same current is passed in both, the ratio of the magnetic field at the central of the loop (BL_LL​) to that at the centre of the coil (BC_CC​), i.e. BLBC\dfrac{B_L}{B_C}BC​BL​​ will be
  1. (A)N
  2. (B)1N\dfrac{1}{N}N1​
  3. (C)N2^{2}2
  4. (D)1N2\dfrac{1}{N^{2}}N21​

Correct answer: (D)

Step-by-step solution →
Q21·PhysicsSingle correct
A rod of mass ‘M’ and length ‘2L’ is suspended at its middle by a wire. It exhibits torsional oscillations; If two masses each of ‘m’ are attached at distance ‘L/2’ from its centre on both sides, it reduces the oscillation frequency by 20%. The value of ratio m/M is close to:
  1. (A)0.77
  2. (B)0.57
  3. (C)0.37
  4. (D)0.17

Correct answer: (C)

Step-by-step solution →
Q22·PhysicsSingle correct
A parallel palate capacitor with square plates is filled with four dielectrics of dielectric constants K1_11​, K2_22​, K3_33​, K4_44​ arranged as shown in the figure. The effective dielectric constant K will be:
  1. (A)K = (K1+K3)(K2+K4)K1+K2+K3+K4\dfrac{(K_1+K_3)(K_2+K_4)}{K_1+K_2+K_3+K_4}K1​+K2​+K3​+K4​(K1​+K3​)(K2​+K4​)​
  2. (B)K = (K1+K2)(K3+K4)2(K1+K2+K3+K4)\dfrac{(K_1+K_2)(K_3+K_4)}{2(K_1+K_2+K_3+K_4)}2(K1​+K2​+K3​+K4​)(K1​+K2​)(K3​+K4​)​
  3. (C)K = (K1+K2)(K3+K4)K1+K2+K3+K4\dfrac{(K_1+K_2)(K_3+K_4)}{K_1+K_2+K_3+K_4}K1​+K2​+K3​+K4​(K1​+K2​)(K3​+K4​)​
  4. (D)K = (K1+K4)(K2+K3)2(K1+K2+K3+K4)\dfrac{(K_1+K_4)(K_2+K_3)}{2(K_1+K_2+K_3+K_4)}2(K1​+K2​+K3​+K4​)(K1​+K4​)(K2​+K3​)​

Correct answer: (A)

Step-by-step solution →
Q23·PhysicsSingle correct
The pitch and the number of divisions, on the circular scale, for a given screw gauge are 0.5 mm and 100 respectively. When the screw gauge is fully tightened without any object, the zero of its circular scale lies 3 divisions below the mean line. The readings of the main scale and the circular scale for a thin sheet, are 5.5 mm and 48 respectively, the thickness of this sheet is
  1. (A)5.755 mm
  2. (B)5.950 mm
  3. (C)5.725 mm
  4. (D)5.740 mm

Correct answer: (C)

Step-by-step solution →
Q24·PhysicsSingle correct
A musician using an open flute of length 50 cm produces second harmonic sound waves. A person runs towards the musician from another end of a hall at a speed of 10 km/h. If the wave speed is 330 m/s, the frequency heard by the running person shall be close to:
  1. (A)666 Hz
  2. (B)753 Hz
  3. (C)500 Hz
  4. (D)333 Hz

Correct answer: (A)

Step-by-step solution →
Q25·PhysicsSingle correct
In a car race on straight road, car A takes a time ‘t’ less than car B at the finish and passes finishing point with a speed ‘v’ more than that of car B. Both the cars start from rest and travel with constant acceleration a1_11​ and a2_22​ respectively. Then ‘v’ is equal to
  1. (A)2a1a1a1+a2 t\dfrac{2a_1a_1}{a_1+a_2}\,ta1​+a2​2a1​a1​​t
  2. (B)2a1a2 t\sqrt{2a_1a_2}\,t2a1​a2​​t
  3. (C)a1a2 t\sqrt{a_1a_2}\,ta1​a2​​t
  4. (D)a1+a22 t\dfrac{a_1+a_2}{2}\,t2a1​+a2​​t

Correct answer: (C)

Step-by-step solution →
Q26·PhysicsSingle correct
The magnetic field associated with a light wave is given, at the origin, by B=B0[sin⁡(3.14×107)ct+sin⁡(6.28×107)ct]B = B_0[\sin(3.14 \times 10^{7})ct + \sin(6.28 \times 10^{7})ct]B=B0​[sin(3.14×107)ct+sin(6.28×107)ct] If this light falls on a silver plate having a work function of 4.7 eV, what will be the maximum kinetic energy of the photo electrons?
  1. (A)6.82 eV
  2. (B)12.5 eV
  3. (C)8.52 eV
  4. (D)7.72 eV

Correct answer: (D)

Step-by-step solution →
Q27·PhysicsSingle correct
In the given circuit the internal resistance of the 18 V cell is negligible. If R1_11​ = 400 Ω, R3_33​ = 100 Ω and R4_44​ = 500 Ω and the reading of an ideal voltmeter across R4_44​ is 5 V, then the value of R2_22​ will be
  1. (A)300 Ω
  2. (B)450 Ω
  3. (C)550 Ω
  4. (D)230 Ω

Correct answer: (A)

Step-by-step solution →
Q28·PhysicsSingle correct
In a communication system operating at wavelength 800 nm, only one percent of source frequency is available as signal bandwidth. The number of channels accommodated for transmitting TV signals of band width 6 MHz are (Take velocity of light c = 3×1083 \times 10^{8}3×108 m/s, h = 6.6×10−346.6 \times 10^{-34}6.6×10−34 J-s)
  1. (A)3.75 ×\times× 106^{6}6
  2. (B)3.86 ×\times× 106^{6}6
  3. (C)6.25 ×\times× 105^{5}5
  4. (D)4.87 ×\times× 105^{5}5

Correct answer: (C)

Step-by-step solution →
Q29·PhysicsSingle correct
The position co-ordinates of a particle moving in a 3-D coordinates system is given by x=acos⁡ωtx = a\cos\omega tx=acosωt y=asin⁡ωty = a\sin\omega ty=asinωt and z=aωtz = a\omega tz=aωt The speed of the particle is:
  1. (A)2 aω\sqrt{2}\,a\omega2​aω
  2. (B)aωa\omegaaω
  3. (C)3 aω\sqrt{3}\,a\omega3​aω
  4. (D)2aω2a\omega2aω

Correct answer: (A)

Step-by-step solution →

Chemistry — JEE Main 9 January 2019 Shift 2

Q30·ChemistrySingle correct
The entropy change associated with the conversion of 1 kg of ice at 273 K to water vapours at 383 K is: (Specific heat of water liquid and water vapours are 4.2 kJ K−1^{-1}−1 kg−1^{-1}−1 and 2.0 kJ K−1^{-1}−1 kg−1^{-1}−1, heat of liquid fusion and vapourisation of water are 334 kJ kg−1^{-1}−1 and 2491 kJ kg−1^{-1}−1, respectively) (log 273 = 2.436, log 373 = 2.572, log 383 = 2.583)
  1. (A)7.90 kJ K−1^{-1}−1 kg−1^{-1}−1
  2. (B)2.64 kJ K−1^{-1}−1 kg−1^{-1}−1
  3. (C)8.49 kJ K−1^{-1}−1 kg−1^{-1}−1
  4. (D)9.26 kJ K−1^{-1}−1 kg−1^{-1}−1

Correct answer: (D)

Step-by-step solution →
Q31·ChemistrySingle correct
For the following reaction the mass of water produced from 445 g of C57_{57}57​H110_{110}110​O6_66​ is 2C57H110O6(s)+163O2(g)⟶114CO2(g)+110H2O(l)2C_{57}H_{110}O_6(s) + 163O_2(g) \longrightarrow 114CO_2(g) + 110H_2O(l)2C57​H110​O6​(s)+163O2​(g)⟶114CO2​(g)+110H2​O(l)
  1. (A)490 g
  2. (B)445 g
  3. (C)495 g
  4. (D)890 g

Correct answer: (C)

Step-by-step solution →
Q32·ChemistrySingle correct
The major product formed in the following reaction is:
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (C)

Step-by-step solution →
Q33·ChemistrySingle correct
Which of the following conditions in drinking water causes methemoglobinemia?
  1. (A)> 50 ppm of lead
  2. (B)> 50 ppm of chloride
  3. (C)> 50 ppm of nitrate
  4. (D)> 100 ppm of sulphate

Correct answer: (C)

Step-by-step solution →
Q34·ChemistrySingle correct
The major product of the following reaction is:
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (C)

Step-by-step solution →
Q35·ChemistrySingle correct
The major product obtained in the following reaction is:
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (D)

Step-by-step solution →
Q36·ChemistrySingle correct
The major product of the following reaction is:
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (C)

Step-by-step solution →
Q37·ChemistrySingle correct
The correct match between item I and item II is
Item IItem II
a.Benzaldehydep.Mobile phase
b.Aluminaq.Adsorbent
c.Acetonitriler.Adsorbate
  1. (A)a →\rightarrow→ q, b →\rightarrow→ p, c →\rightarrow→ r
  2. (B)a →\rightarrow→ r, b →\rightarrow→ q, c →\rightarrow→ p
  3. (C)a →\rightarrow→ q, b →\rightarrow→ r, c →\rightarrow→ p
  4. (D)a →\rightarrow→ p, b →\rightarrow→ r, c →\rightarrow→ q

Correct answer: (B)

Step-by-step solution →
Q38·ChemistrySingle correct
The metal that forms nitride by reacting directly with N2_22​ of air is
  1. (A)K
  2. (B)Li
  3. (C)Rb
  4. (D)Cs

Correct answer: (B)

Step-by-step solution →
Q39·ChemistrySingle correct
For coagulation of arsenious sulphide sol, which one of the following salt solution will be most effective?
  1. (A)BaCl2_22​
  2. (B)AlCl3_33​
  3. (C)NaCl
  4. (D)Na3_33​PO4_44​

Correct answer: (B)

Step-by-step solution →
Q40·ChemistrySingle correct
The complex that has highest crystal field splitting energy(Δ\DeltaΔ) is
  1. (A)[Co(NH3_33​)5_55​(H2_22​O)]Cl3_33​
  2. (B)K2_22​[CoCl4_44​]
  3. (C)[Co(NH3_33​)5_55​Cl]Cl2_22​
  4. (D)K3_33​[Co(CN)6_66​]

Correct answer: (D)

Step-by-step solution →
Q41·ChemistrySingle correct
The pH of rain water is approximately
  1. (A)5.6
  2. (B)7.5
  3. (C)7.0
  4. (D)6.5

Correct answer: (A)

Step-by-step solution →
Q42·ChemistrySingle correct
Consider the following reversible chemical reactions: A2(g)+B2(g)⇌K12AB(g)A_2(g) + B_2(g) \underset{}{\overset{K_1}{\rightleftharpoons}} 2AB(g)A2​(g)+B2​(g)⇌K1​​​2AB(g) .......(1) 6AB(g)⇌K23A2(g)+3B2(g)6AB(g) \underset{}{\overset{K_2}{\rightleftharpoons}} 3A_2(g) + 3B_2(g)6AB(g)⇌K2​​​3A2​(g)+3B2​(g) .......(2) The relation between K1_11​ and K2_22​ is
  1. (A)K1K2=13K_1K_2 = \frac{1}{3}K1​K2​=31​
  2. (B)K2=K13K_2 = K_1^{3}K2​=K13​
  3. (C)K2=K1−3K_2 = K_1^{-3}K2​=K1−3​
  4. (D)K1K2=3K_1K_2 = 3K1​K2​=3

Correct answer: (C)

Step-by-step solution →
Q43·ChemistrySingle correct
The correct sequence of amino acids present in the tripeptide given below is
  1. (A)Val – Ser – Thr
  2. (B)Thr – Ser – Val
  3. (C)Leu – Ser – Thr
  4. (D)Thr – Ser – Leu

Correct answer: (A)

Step-by-step solution →
Q44·ChemistrySingle correct
For the reaction, 2A+B⟶2A + B \longrightarrow2A+B⟶ products, when the concentrations of A and B both were doubled, the rate of the reaction increased from 0.3 mol L−1^{-1}−1 s−1^{-1}−1 to 2.4 mol L−1^{-1}−1 s−1^{-1}−1. When the concentration of A alone is doubled, the rate increased from 0.3 mol L−1^{-1}−1 s−1^{-1}−1 to 0.6 mol L−1^{-1}−1 s−1^{-1}−1. Which one of the following statements is correct?
  1. (A)Total order of the reaction is 4
  2. (B)Order of the reaction with respect to B is 2
  3. (C)Order of the reaction with respect to B is 1
  4. (D)Order of the reaction with respect to A is 2

Correct answer: (B)

Step-by-step solution →
Q45·ChemistrySingle correct
The products formed in the reaction of cumene with O2_22​ followed by treatment with dil. HCl are:
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (C)

Step-by-step solution →
Q46·ChemistrySingle correct
The tests performed on compound X and their inferences are: Compound 'X' is
TestInterference
(a) 2, 4-DNP testColorued precipitate
(b) Iodoform testYellow precipitate
(c) Azo-dye testNo dye formation
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (B)

Step-by-step solution →
Q47·ChemistrySingle correct
If the standard electrode potential for a cell is 2 V at 300 K, the equilibrium constant (K) for the reaction Zn(s)+Cu2+(aq)⇌Zn2+(aq)+Cu(s)Zn(s) + Cu^{2+}(aq) \rightleftharpoons Zn^{2+}(aq) + Cu(s)Zn(s)+Cu2+(aq)⇌Zn2+(aq)+Cu(s) At 300 K is approximately (R = 8 JK−1^{-1}−1 mol−1^{-1}−1, F = 96000 C mol−1^{-1}−1)
  1. (A)e−80e^{-80}e−80
  2. (B)e−160e^{-160}e−160
  3. (C)e320e^{320}e320
  4. (D)e160e^{160}e160

Correct answer: (D)

Step-by-step solution →
Q48·ChemistrySingle correct
The temporary hardness of water is due to
  1. (A)Na2_22​SO4_44​
  2. (B)NaCl
  3. (C)Ca(HCO3_33​)2_22​
  4. (D)CaCl2_22​

Correct answer: (C)

Step-by-step solution →
Q49·ChemistrySingle correct
In which of the following processes, the bond order has increased and paramagnetic character has changed to diamagnetic?
  1. (A)NO →\rightarrow→ NO+^{+}+
  2. (B)N2_22​ →\rightarrow→ N2+_2^{+}2+​
  3. (C)O2_22​ →\rightarrow→ O2+_2^{+}2+​
  4. (D)O2_22​ →\rightarrow→ O22−_2^{2-}22−​

Correct answer: (A)

Step-by-step solution →
Q50·ChemistrySingle correct
Which of the following combination of statements is true regarding the interpretation of the atomic orbitals? (1) An electron in an orbital of high angular momentum stays away from the nucleus than an electron in the orbital of lower angular momentum. (2) For a given value of the principal quantum number, the size of the orbit is inversely proportional to the azimuthal quantum number (3) According to wave mechanics, the ground state angular momentum is equal to h2π\frac{h}{2\pi}2πh​ (4) The plot of ψ Vs r for various azimuthal quantum numbers, shows peak shifting towards higher r value
  1. (A)(1), (4)
  2. (B)(1), (2)
  3. (C)(1), (3)
  4. (D)(2), (3)

Correct answer: (A)

Step-by-step solution →
Q51·ChemistrySingle correct
Which of the following compounds is not aromatic?
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (A)

Step-by-step solution →
Q52·ChemistrySingle correct
Good reducing nature of H3_33​PO2_22​ is attributed to the presence of
  1. (A)Two P – OH bonds
  2. (B)One P – H bond
  3. (C)Two P – H bonds
  4. (D)One P – OH bond

Correct answer: (C)

Step-by-step solution →
Q53·ChemistrySingle correct
The correct statement regarding the given Ellingham diagram is
  1. (A)At 1400°C, Al can be used for the extraction of Zn from ZnO
  2. (B)At 500°C, coke can be used for the extraction of Zn from ZnO
  3. (C)Coke cannot be used for the extraction of Cu from Cu2_22​O
  4. (D)At 800°C Cu can be used for the extraction of Zn from ZnO

Correct answer: (A)

Step-by-step solution →
Q54·ChemistrySingle correct
The transition element that has lowest enthalpy of atomisation is
  1. (A)Fe
  2. (B)Cu
  3. (C)V
  4. (D)Zn

Correct answer: (D)

Step-by-step solution →
Q55·ChemistrySingle correct
The increasing basicity order of the following compounds is (1) CH3_33​CH2_22​NH2_22​ (2) CH3_33​CH2_22​NH-CH2_22​CH3_33​ (3) (CH3_33​)3_33​N (4) Ph-N(CH3_33​)-H
  1. (A)(4) < (3) < (2) < (1)
  2. (B)(4) < (3) < (1) < (2)
  3. (C)(1) < (2) < (3) < (4)
  4. (D)(1) < (2) < (4) < (3)

Correct answer: (B)

Step-by-step solution →
Q56·ChemistrySingle correct
When the first electron gain enthalpy (Δeg\Delta_{eg}Δeg​H) of oxygen is -141 kJ/mol, its second electron gain enthalpy is
  1. (A)a more negative value than the first
  2. (B)almost the same as that of the first
  3. (C)negative, but less negative than the first
  4. (D)a positive value

Correct answer: (D)

Step-by-step solution →
Q57·ChemistrySingle correct
At 100°C, copper(Cu) has FCC unit cell structure with cell edge length x Å. What is the approximate density of Cu(in g cm−3^{-3}−3) at this temperature? [Atomic mass of Cu = 63.55 u]
  1. (A)205x3\dfrac{205}{x^{3}}x3205​
  2. (B)105x3\dfrac{105}{x^{3}}x3105​
  3. (C)211x3\dfrac{211}{x^{3}}x3211​
  4. (D)422x3\dfrac{422}{x^{3}}x3422​

Correct answer: (D)

Step-by-step solution →
Q58·ChemistrySingle correct
A solution containing 62 g ethylene glycol in 250 g water is cooled to -10°C. If Kf_ff​ for water is 1.86 K kg mol−1^{-1}−1, the amount of water(in g) separated as ice is
  1. (A)48
  2. (B)32
  3. (C)64
  4. (D)16

Correct answer: (C)

Step-by-step solution →
Q59·ChemistrySingle correct
Homoleptic octahedral complexes of a metal ion 'M3+^{3+}3+' with three monodentate ligands L1_11​, L2_22​ and L3_33​ absorb wavelengths in the region of green, blue and red respectively. The increasing order of the ligand strength is
  1. (A)L3_33​ < L1_11​ < L2_22​
  2. (B)L3_33​ < L2_22​ < L1_11​
  3. (C)L1_11​ < L2_22​ < L3_33​
  4. (D)L2_22​ < L1_11​ < L3_33​

Correct answer: (A)

Step-by-step solution →

Mathematics — JEE Main 9 January 2019 Shift 2

Q60·MathematicsSingle correct
The sum of the following series 1+6+9(12+22+32)7+12(12+22+32+42)9+15(12+22+....+52)11+...1+6+\frac{9(1^{2}+2^{2}+3^{2})}{7}+\frac{12(1^{2}+2^{2}+3^{2}+4^{2})}{9}+\frac{15(1^{2}+2^{2}+....+5^{2})}{11}+...1+6+79(12+22+32)​+912(12+22+32+42)​+1115(12+22+....+52)​+... up to 15 terms, is:
  1. (A)7820
  2. (B)7830
  3. (C)7520
  4. (D)7510

Correct answer: (A)

Step-by-step solution →
Q61·MathematicsSingle correct
Let f:[0,1]→Rf:[0,1]\rightarrow Rf:[0,1]→R be such that f(xy)=f(x)f(y)f(xy)=f(x)f(y)f(xy)=f(x)f(y) for all x,y∈[0,1]x,y\in[0,1]x,y∈[0,1], and f(0)≠0f(0)\neq 0f(0)=0. If y=y(x)y=y(x)y=y(x) satisfies the differential equation, dydx=f(x)\frac{dy}{dx}=f(x)dxdy​=f(x) with y(0)=1y(0)=1y(0)=1, then y(14)+y(34)y\left(\frac{1}{4}\right)+y\left(\frac{3}{4}\right)y(41​)+y(43​) is equal to
  1. (A)4
  2. (B)3
  3. (C)5
  4. (D)2

Correct answer: (B)

Step-by-step solution →
Q62·MathematicsSingle correct
If x=sin⁡−1(sin⁡10)x=\sin^{-1}(\sin 10)x=sin−1(sin10) and y=cos⁡−1(cos⁡10)y=\cos^{-1}(\cos 10)y=cos−1(cos10), then y−xy-xy−x is equal to:
  1. (A)π\piπ
  2. (B)7π7\pi7π
  3. (C)0
  4. (D)10

Correct answer: (A)

Step-by-step solution →
Q63·MathematicsSingle correct
If 0≤x<π20 \le x < \frac{\pi}{2}0≤x<2π​, then the number of values of x for which sin⁡x−sin⁡2x+sin⁡3x=0\sin x - \sin 2x + \sin 3x = 0sinx−sin2x+sin3x=0, is
  1. (A)222
  2. (B)111
  3. (C)333
  4. (D)444

Correct answer: (A)

Step-by-step solution →
Q64·MathematicsSingle correct
Let z0z_{0}z0​ be a root of the quadratic equation, x2+x+1=0x^{2}+x+1=0x2+x+1=0. If z=3+6iz081−3iz093z=3+6iz_{0}^{81}-3iz_{0}^{93}z=3+6iz081​−3iz093​, then arg⁡z\arg zargz is equal to
  1. (A)π4\frac{\pi}{4}4π​
  2. (B)π3\frac{\pi}{3}3π​
  3. (C)0
  4. (D)π6\frac{\pi}{6}6π​

Correct answer: (A)

Step-by-step solution →
Q65·MathematicsSingle correct
The area of the region A{(x,y):0≤y≤x∣x∣+1A\{(x,y):0\leq y\leq x|x|+1A{(x,y):0≤y≤x∣x∣+1 and −1≤x≤1}-1\leq x\leq 1\}−1≤x≤1} in sq. units, is:
  1. (A)23\frac{2}{3}32​
  2. (B)13\frac{1}{3}31​
  3. (C)2
  4. (D)43\frac{4}{3}34​

Correct answer: (C)

Step-by-step solution →
Q66·MathematicsSingle correct
If the system of linear equation x−4y+7z=g,3y−5z=h,−2x+5y−9z=kx-4y+7z=g, 3y-5z=h, -2x+5y-9z=kx−4y+7z=g,3y−5z=h,−2x+5y−9z=k is consistent, then:
  1. (A)g+h+k=0g+h+k=0g+h+k=0
  2. (B)2g+h+k=02g+h+k=02g+h+k=0
  3. (C)g+h+2k=0g+h+2k=0g+h+2k=0
  4. (D)g+2h+k=0g+2h+k=0g+2h+k=0

Correct answer: (B)

Step-by-step solution →
Q67·MathematicsSingle correct
The coefficient of t4t^{4}t4 in the expansion of (1−t61−t)3\left(\frac{1-t^{6}}{1-t}\right)^{3}(1−t1−t6​)3 is
  1. (A)12
  2. (B)15
  3. (C)10
  4. (D)14

Correct answer: (B)

Step-by-step solution →
Q68·MathematicsSingle correct
Let S be the set of all triangle in the xy −-− plane, each having one vertex at the origin and the other two vertices lie on coordinate axes with integral coordinates. If each triangle in S has area 50 sq. units, then the number of elements in the set S is:
  1. (A)9
  2. (B)18
  3. (C)32
  4. (D)36

Correct answer: (D)

Step-by-step solution →
Q69·MathematicsSingle correct
Let a, b and c be the 7th7^{th}7th, 11th11^{th}11th and 13th13^{th}13th terms respectively of a non −-− constant A.P. If these are also the three consecutive terms of a G.P. then ac\frac{a}{c}ca​ is equal to:
  1. (A)12\frac{1}{2}21​
  2. (B)4
  3. (C)2
  4. (D)713\frac{7}{13}137​

Correct answer: (B)

Step-by-step solution →
Q70·MathematicsSingle correct
The equation of the plane containing the straight line x2=y3=z4\frac{x}{2} = \frac{y}{3} = \frac{z}{4}2x​=3y​=4z​ and perpendicular to the plane containing the straight lines x3=y4=z2\frac{x}{3} = \frac{y}{4} = \frac{z}{2}3x​=4y​=2z​ and x4=y2=z3\frac{x}{4} = \frac{y}{2} = \frac{z}{3}4x​=2y​=3z​ is:
  1. (A)x+2y−2z=0x + 2y - 2z = 0x+2y−2z=0
  2. (B)x−2y+z=0x - 2y + z = 0x−2y+z=0
  3. (C)5x+2y−4z=05x + 2y - 4z = 05x+2y−4z=0
  4. (D)3x+2y−3z=03x + 2y - 3z = 03x+2y−3z=0

Correct answer: (B)

Step-by-step solution →
Q71·MathematicsSingle correct
A data consists of n observations: x1,x2,......,xnx_{1},x_{2},......,x_{n}x1​,x2​,......,xn​. If ∑i=1n(xi+1)2=9n\displaystyle\sum_{i=1}^{n}(x_{i}+1)^{2}=9ni=1∑n​(xi​+1)2=9n and ∑i=1n(xi−1)2=5n\displaystyle\sum_{i=1}^{n}(x_{i}-1)^{2}=5ni=1∑n​(xi​−1)2=5n, then the standard deviation of this data is:
  1. (A)5
  2. (B)5\sqrt{5}5​
  3. (C)7\sqrt{7}7​
  4. (D)2

Correct answer: (B)

Step-by-step solution →
Q72·MathematicsSingle correct
If A=[ete−tcos⁡te−tsin⁡tet−e−tcos⁡t−e−tsin⁡t−e−tsin⁡t+e−tcos⁡tet2e−tsin⁡t−2e−tcos⁡t]A = \begin{bmatrix} e^{t} & e^{-t}\cos t & e^{-t}\sin t \\ e^{t} & -e^{-t}\cos t - e^{-t}\sin t & -e^{-t}\sin t + e^{-t}\cos t \\ e^{t} & 2e^{-t}\sin t & -2e^{-t}\cos t \end{bmatrix}A=​etetet​e−tcost−e−tcost−e−tsint2e−tsint​e−tsint−e−tsint+e−tcost−2e−tcost​​ Then A is
  1. (A)Invertible only if t=π2t = \frac{\pi}{2}t=2π​
  2. (B)not invertible for any t∈Rt \in Rt∈R
  3. (C)invertible for all t∈Rt \in Rt∈R
  4. (D)invertible only if t=πt = \pit=π

Correct answer: (C)

Step-by-step solution →
Q73·MathematicsSingle correct
If f(x)=∫5x8+7x6(x2+1+2x7)2dx,(x≥0)f(x) = \int \frac{5x^{8} + 7x^{6}}{\left(x^{2} + 1 + 2x^{7}\right)^{2}} dx, (x \ge 0)f(x)=∫(x2+1+2x7)25x8+7x6​dx,(x≥0) and f(0)=0f(0) = 0f(0)=0, then the value of f(1)f(1)f(1) is:
  1. (A)−12-\frac{1}{2}−21​
  2. (B)12\frac{1}{2}21​
  3. (C)−14-\frac{1}{4}−41​
  4. (D)14\frac{1}{4}41​

Correct answer: (D)

Step-by-step solution →
Q74·MathematicsSingle correct
Let f be a differentiable function R to R such that ∣f(x)−f(y)∣≤2∣x−y∣32\left| f(x) - f(y) \right| \le 2\left| x - y \right|^{\frac{3}{2}}∣f(x)−f(y)∣≤2∣x−y∣23​, for all x,y∈Rx, y \in Rx,y∈R. If f(0)=1f(0) = 1f(0)=1 then ∫01f2(x)dx\int_{0}^{1} f^{2}(x) dx∫01​f2(x)dx is equal to
  1. (A)000
  2. (B)12\frac{1}{2}21​
  3. (C)222
  4. (D)111

Correct answer: (D)

Step-by-step solution →
Q75·MathematicsSingle correct
If x=3tan⁡tx = 3\tan tx=3tant and y=3sec⁡ty = 3\sec ty=3sect, then the value of d2ydx2\frac{d^{2}y}{dx^{2}}dx2d2y​ at t=π4t = \frac{\pi}{4}t=4π​, is:
  1. (A)322\frac{3}{2\sqrt{2}}22​3​
  2. (B)132\frac{1}{3\sqrt{2}}32​1​
  3. (C)16\frac{1}{6}61​
  4. (D)162\frac{1}{6\sqrt{2}}62​1​

Correct answer: (D)

Step-by-step solution →
Q76·MathematicsSingle correct
The number of natural numbers less than 7,000 which can be formed by using the digits 0, 1, 3, 7, 9 (repetition of digits allowed) is equal to:
  1. (A)250
  2. (B)374
  3. (C)372
  4. (D)375

Correct answer: (B)

Step-by-step solution →
Q77·MathematicsSingle correct
If the circles x2+y2−16x−20y+164=r2x^{2} + y^{2} - 16x - 20y + 164 = r^{2}x2+y2−16x−20y+164=r2 and (x−4)2+(y−7)2=36(x-4)^{2} + (y-7)^{2} = 36(x−4)2+(y−7)2=36 intersect at two distinct points, then:
  1. (A)0<r<10 < r < 10<r<1
  2. (B)1<r<111 < r < 111<r<11
  3. (C)r>11r > 11r>11
  4. (D)r=11r = 11r=11

Correct answer: (B)

Step-by-step solution →
Q78·MathematicsSingle correct
A hyperbola has its centre at the origin, passes through the point (4, 2) and has transverse axis of length 4 along the x - axis. Then the eccentricity of the hyperbola is:
  1. (A)23\dfrac{2}{\sqrt{3}}3​2​
  2. (B)32\dfrac{3}{2}23​
  3. (C)3\sqrt{3}3​
  4. (D)2

Correct answer: (A)

Step-by-step solution →
Q79·MathematicsSingle correct
Let A(4,−4)A(4, -4)A(4,−4) and B(9,6)B(9, 6)B(9,6) be points on the parabola y2=4xy^{2} = 4xy2=4x. Let C be chosen on the arc AOB of the parabola, where O is the origin, such that the area of △ACB\triangle ACB△ACB is maximum. Then, the area (in sq. units) of △ACB\triangle ACB△ACB, is:
  1. (A)313431\dfrac{3}{4}3143​
  2. (B)32
  3. (C)301230\dfrac{1}{2}3021​
  4. (D)311431\dfrac{1}{4}3141​

Correct answer: (D)

Step-by-step solution →
Q80·MathematicsSingle correct
Let the equation of two sides of a triangle be 3x−2y+6=03x - 2y + 6 = 03x−2y+6=0 and 4x+5y−20=04x + 5y - 20 = 04x+5y−20=0. If the orthocentre of this triangle is at (1, 1), then the equation of its third side is:
  1. (A)122y−26x−1675=0122y - 26x - 1675 = 0122y−26x−1675=0
  2. (B)26x+61y+1675=026x + 61y + 1675 = 026x+61y+1675=0
  3. (C)122y+26x+1675=0122y + 26x + 1675 = 0122y+26x+1675=0
  4. (D)26x−122y−1675=026x - 122y - 1675 = 026x−122y−1675=0

Correct answer: (D)

Step-by-step solution →
Q81·MathematicsSingle correct
An urn contains 5 red and 2 green balls. A ball is drawn at random from the urn. If the drawn ball is green, then a red ball is added to the urn and if the drawn ball is red, then a green ball is added to the urn; the original ball is not returned to the urn. Now, a second ball is drawn at random from it. The probability that the second ball is red, is:
  1. (A)2649\dfrac{26}{49}4926​
  2. (B)3249\dfrac{32}{49}4932​
  3. (C)2749\dfrac{27}{49}4927​
  4. (D)2149\dfrac{21}{49}4921​

Correct answer: (B)

Step-by-step solution →
Q82·MathematicsSingle correct
If the lines x=ay+b,z=cy+dx = ay + b, z = cy + dx=ay+b,z=cy+d and x=a′z+b′,y=c′z+d′x = a'z + b', y = c'z + d'x=a′z+b′,y=c′z+d′ are perpendicular, then:
  1. (A)cc′+a+a′=0cc' + a + a' = 0cc′+a+a′=0
  2. (B)aa′+c+c′=0aa' + c + c' = 0aa′+c+c′=0
  3. (C)ab′+bc′+1=0ab' + bc' + 1 = 0ab′+bc′+1=0
  4. (D)bb′+cc′+1=0bb' + cc' + 1 = 0bb′+cc′+1=0

Correct answer: (B)

Step-by-step solution →
Q83·MathematicsSingle correct
Let a⃗=i^+j^+2k^,b⃗=b1i^+b2j^+2k^\vec{a} = \hat{i} + \hat{j} + \sqrt{2}\hat{k}, \vec{b} = b_{1}\hat{i} + b_{2}\hat{j} + \sqrt{2}\hat{k}a=i^+j^​+2​k^,b=b1​i^+b2​j^​+2​k^ and c⃗=5i^+j^+2k^\vec{c} = 5\hat{i} + \hat{j} + \sqrt{2}\hat{k}c=5i^+j^​+2​k^ be three vectors such that the projection vector of b⃗\vec{b}b on a⃗\vec{a}a is a⃗\vec{a}a. If a⃗+b⃗\vec{a} + \vec{b}a+b is perpendicular to c⃗\vec{c}c, then ∣b⃗∣\left| \vec{b} \right|​b​ is equal to:
  1. (A)22\sqrt{22}22​
  2. (B)444
  3. (C)32\sqrt{32}32​
  4. (D)666

Correct answer: (D)

Step-by-step solution →
Q84·MathematicsSingle correct
The number of all possible positive integral values of α\alphaα for which the roots of the quadratic equation, 6x2−11x+α=06x^{2} - 11x + \alpha = 06x2−11x+α=0 are rational numbers is:
  1. (A)2
  2. (B)5
  3. (C)3
  4. (D)4

Correct answer: (C)

Step-by-step solution →
Q85·MathematicsSingle correct
Let A={x∈R:x is not a positive integer}A = \{x \in R : x \text{ is not a positive integer}\}A={x∈R:x is not a positive integer}. Define a function f:A→Rf : A \rightarrow Rf:A→R as f(x)=2xx−1f(x) = \frac{2x}{x - 1}f(x)=x−12x​ then f is
  1. (A)injective but nor surjective
  2. (B)not injective
  3. (C)surjective but not injective
  4. (D)neither injective nor surjective

Correct answer: (A)

Step-by-step solution →
Q86·MathematicsSingle correct
If ∫0π3tan⁡θ2ksec⁡θdθ=1−12,(k>0)\int_{0}^{\frac{\pi}{3}} \frac{\tan\theta}{\sqrt{2k\sec\theta}} d\theta = 1 - \frac{1}{\sqrt{2}}, (k > 0)∫03π​​2ksecθ​tanθ​dθ=1−2​1​,(k>0), then the value of k is:
  1. (A)222
  2. (B)12\frac{1}{2}21​
  3. (C)444
  4. (D)111

Correct answer: (A)

Step-by-step solution →

Chapters tested in this paper

Open any chapter to practise every past-year question on that topic across all papers, and see how often it has actually appeared.

  • Properties of Solids and Liquids 172/186
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  • Sets, Relations and Functions 165/186
  • Current Electricity 160/186
  • Sequence and Series 164/186
  • p-Block Elements 164/186
  • Definite Integration 168/186
  • Rotational Motion 172/186
  • Redox Reactions and Electrochemistry 177/186
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  • Binomial Theorem and Its Simple Applications 158/186
  • Electromagnetic Waves 144/186
  • Chemical Bonding and Molecular Structure 151/186
  • d- and f-Block Elements 126/186
  • Thermodynamics 154/186
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  • Equilibrium 163/186
  • Solutions 158/186
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  • Kinetic Theory of Gases 135/186
  • Alcohols and Ethers 106/186
  • Oscillations 117/186
  • Alternating Currents 108/186
  • Nuclei 116/186
  • Straight Lines 114/186
  • Waves 109/186
  • Capacitors and Dielectrics 115/186
  • Classification of Elements and Periodicity in Properties 113/186
  • Parabola 101/186
  • Statistics 118/186
  • Isolation of Metals 106/186
  • Differentiability 91/186
  • s-Block Elements 88/186
  • Surface Chemistry 98/186
  • Inverse Trigonometric Functions 93/186
  • Environmental Chemistry 83/186
  • Hydrogen 81/186
  • Hyperbola 77/186
  • Experimental Skills 68/186
  • Indefinite Integration 66/186
  • Carboxylic Acids and Derivatives 54/186
  • Solid State 63/186
  • Aromaticity 22/186
  • Communication Systems 11/186
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