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JEE Main 1 September 2021 Shift 2 Question Paper with Answers

1 September 2021 · September session · 86 questions

86 of the 90 questions from the JEE Main 1 September 2021 Shift 2 paper, each with its correct answer and tagged to the chapter it tests. Free to read, no account needed.

4 questions are held back from this paper while we re-check the transcription or the answer key. We would rather show you nothing than show you an answer we are not confident is right.

Physics
29
Chemistry
27
Mathematics
30

Physics — JEE Main 1 September 2021 Shift 2

Q1·PhysicsSingle correct
A cube is placed inside an electric field, E⃗=150y2j^\vec{E} = 150y^{2}\hat{j}E=150y2j^​. The side of the cube is 0.5 m and is placed in the field as shown in the given figure. The charge inside the cube is :
  1. (A)3.8 × 10−11^{-11}−11 C
  2. (B)8.3 × 10−11^{-11}−11 C
  3. (C)3.8 × 10−12^{-12}−12 C
  4. (D)8.3 × 10−12^{-12}−12 C

Correct answer: (B)

Step-by-step solution →
Q2·PhysicsSingle correct
A square loop of side 20 cm and resistance 1Ω is moved towards right with a constant speed v0_{0}0​. The right arm of the loop is in a uniform magnetic field of 5T. The field is perpendicular to the plane of the loop and is going into it. The loop is connected to a network of resistors each of value 4Ω. What should be the value of v0_{0}0​ so that a steady current of 2 mA flows in the loop ?
  1. (A)1 m/s
  2. (B)1 cm/s
  3. (C)102^{2}2 m/s
  4. (D)10−2^{-2}−2 cm/s

Correct answer: (B)

Step-by-step solution →
Q3·PhysicsSingle correct
The temperature of an ideal gas in 3-dimensions is 300 K. The corresponding de-Broglie wavelength of the electron approximately at 300 K, is : [me_{e}e​ = mass of electron = 9 × 10−31^{-31}−31 kg h = Planck constant = 6.6 × 10−34^{-34}−34 Js kB_{B}B​ = Boltzmann constant = 1.38 × 10−23^{-23}−23 JK−1^{-1}−1]
  1. (A)6.26 nm
  2. (B)8.46 nm
  3. (C)2.26 nm
  4. (D)3.25 nm

Correct answer: (A)

Step-by-step solution →
Q4·PhysicsSingle correct
A body of mass 'm' dropped from a height 'h' reaches the ground with a speed of 0.8gh0.8\sqrt{gh}0.8gh​. The value of workdone by the air-friction is :
  1. (A)–0.68 mgh
  2. (B)mgh
  3. (C)1.64 mgh
  4. (D)0.64 mgh

Correct answer: (A)

Step-by-step solution →
Q5·PhysicsSingle correct
The ranges and heights for two projectiles projected with the same initial velocity at angles 42° and 48° with the horizontal are R1_{1}1​, R2_{2}2​ and H1_{1}1​, H2_{2}2​ respectively. Choose the correct option :
  1. (A)R1_{1}1​ > R2_{2}2​ and H1_{1}1​ = H2_{2}2​
  2. (B)R1_{1}1​ = R2_{2}2​ and H1_{1}1​ < H2_{2}2​
  3. (C)R1_{1}1​ < R2_{2}2​ and H1_{1}1​ < H2_{2}2​
  4. (D)R1_{1}1​ = R2_{2}2​ and H1_{1}1​ = H2_{2}2​

Correct answer: (B)

Step-by-step solution →
Q6·PhysicsSingle correct
A block of mass m slides on the wooden wedge, which in turn slides backward on the horizontal surface. The acceleration of the block with respect to the wedge is : Given m = 8 kg, M = 16 kg Assume all the surfaces shown in the figure to be frictionless.
  1. (A)43\frac{4}{3}34​g
  2. (B)65\frac{6}{5}56​g
  3. (C)35\frac{3}{5}53​g
  4. (D)23\frac{2}{3}32​g

Correct answer: (D)

Step-by-step solution →
Q7·PhysicsSingle correct
Due to cold weather a 1 m water pipe of cross–sectional area 1 cm2^{2}2 is filled with ice at −10°C. Resistive heating is used to melt the ice. Current of 0.5 A is passed through 4 kΩ resistance. Assuming that all the heat produced is used for melting, what is the minimum time required ? (Given latent heat of fusion for water/ice = 3.33 × 105^{5}5 J kg−1^{-1}−1, specific heat of ice = 2 × 103^{3}3 J kg−1^{-1}−1 and density of ice = 103^{3}3 kg / m3^{3}3
  1. (A)0.353 s
  2. (B)35.3 s
  3. (C)3.53 s
  4. (D)70.6 s

Correct answer: (B)

Step-by-step solution →
Q8·PhysicsSingle correct
A student determined Young's Modulus of elasticity using the formula Y=MgL34bd3δY = \frac{MgL^{3}}{4bd^{3}\delta}Y=4bd3δMgL3​. The value of g is taken to be 9.8 m/s2^{2}2, without any significant error, his observation are as following. Then the fractional error in the measurement of Y is :
Physical QuantityLeast count of the Equipment used for measurementObserved value
Mass (M)1 g2 kg
Length of bar (L)1 mm1 m
Breadth of bar (b)0.1 mm4 cm
Thickness of bar (d)0.01 mm0.4 cm
Depression (δ)0.01 mm5 mm
  1. (A)0.0083
  2. (B)0.0155
  3. (C)0.155
  4. (D)0.083

Correct answer: (B)

Step-by-step solution →
Q9·PhysicsSingle correct
Two resistors R1_{1}1​ = (4 ± 0.8) Ω and R2_{2}2​ = (4 ± 0.4) Ω are connected in parallel. The equivalent resistance of their parallel combination will be :
  1. (A)(4 ± 0.4) Ω
  2. (B)(2 ± 0.4) Ω
  3. (C)(2 ± 0.3) Ω
  4. (D)(4 ± 0.3) Ω

Correct answer: (C)

Step-by-step solution →
Q10·PhysicsSingle correct
The half life period of radioactive element x is same as the mean life time of another radioactive element y. Initially they have the same number of atoms. Then :
  1. (A)x–will decay faster than y.
  2. (B)y– will decay faster than x.
  3. (C)x and y have same decay rate initially and later on different decay rate.
  4. (D)x and y decay at the same rate always.

Correct answer: (B)

Step-by-step solution →
Q11·PhysicsSingle correct
Following plots show Magnetization (M) vs Magnetising field (H) and Magnetic susceptibility ( χ ) vs temperature (T) graph : Which of the following combination will be represented by a diamagnetic material?
  1. (A)(a), (c)
  2. (B)(a), (d)
  3. (C)(b), (d)
  4. (D)(b), (c)

Correct answer: (A)

Step-by-step solution →
Q12·PhysicsSingle correct
A glass tumbler having inner depth of 17.5 cm is kept on a table. A student starts pouring water (μ = 4/3) into it while looking at the surface of water from the above. When he feels that the tumbler is half filled, he stops pouring water. Up to what height, the tumbler is actually filled ?
  1. (A)11.7 cm
  2. (B)10 cm
  3. (C)7.5 cm
  4. (D)8.75 cm

Correct answer: (B)

Step-by-step solution →
Q13·PhysicsSingle correct
In the given figure, each diode has a forward bias resistance of 30Ω and infinite resistance in reverse bias. The current I1_{1}1​ will be :
  1. (A)3.75 A
  2. (B)2.35 A
  3. (C)2 A
  4. (D)2.73 A

Correct answer: (C)

Step-by-step solution →
Q14·PhysicsSingle correct
For the given circuit the current iii through the battery when the key in closed and the steady state has been reached is__________.
  1. (A)6 A
  2. (B)25 A
  3. (C)10 A
  4. (D)0 A

Correct answer: (C)

Step-by-step solution →
Q15·PhysicsSingle correct
An object of mass 'm' is being moved with a constant velocity under the action of an applied force of 2N along a frictionless surface with following surface profile. The correct applied force vs distance graph will be:
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (B)

Step-by-step solution →
Q16·PhysicsSingle correct
A mass of 5 kg is connected to a spring. The potential energy curve of the simple harmonic motion executed by the system is shown in the figure. A simple pendulum of length 4 m has the same period of oscillation as the spring system. What is the value of acceleration due to gravity on the planet where these experiments are performed?
  1. (A)10 m/s2^{2}2
  2. (B)5 m/s2^{2}2
  3. (C)4 m/s2^{2}2
  4. (D)9.8 m/s2^{2}2

Correct answer: (C)

Step-by-step solution →
Q17·PhysicsSingle correct
A capacitor is connected to a 20 V battery through a resistance of 10Ω. It is found that the potential difference across the capacitor rises to 2 V in 1 μs. The capacitance of the capacitor is ....................μF. Given : ln⁡(109)=0.105\ln\left(\frac{10}{9}\right) = 0.105ln(910​)=0.105
  1. (A)9.52
  2. (B)0.95
  3. (C)0.105
  4. (D)1.85

Correct answer: (B)

Step-by-step solution →
Q18·PhysicsSingle correct
Four particles each of mass M, move along a circle of radius R under the action of their mutual gravitational attraction as shown in figure. The speed of each particle is :
  1. (A)12GMR(22+1)\frac{1}{2}\sqrt{\frac{GM}{R(2\sqrt{2}+1)}}21​R(22​+1)GM​​
  2. (B)12GMR(22+1)\frac{1}{2}\sqrt{\frac{GM}{R}(2\sqrt{2}+1)}21​RGM​(22​+1)​
  3. (C)12GMR(22−1)\frac{1}{2}\sqrt{\frac{GM}{R}(2\sqrt{2}-1)}21​RGM​(22​−1)​
  4. (D)GMR\sqrt{\frac{GM}{R}}RGM​​

Correct answer: (B)

Step-by-step solution →
Q19·PhysicsSingle correct
Electric field of plane electromagnetic wave propagating through a non–magnetic medium is given by E = 20cos(2 × 1010^{10}10 t–200x) V/m. The dielectric constant of the medium is equal to : (Take μr_{r}r​ = 1)
  1. (A)9
  2. (B)2
  3. (C)13\frac{1}{3}31​
  4. (D)3

Correct answer: (A)

Step-by-step solution →
Q20·PhysicsSingle correct
There are two infinitely long straight current carrying conductors and they are held at right angles to each other so that their common ends meet at the origin as shown in the figure given below. The ratio of current in both conductor is 1 : 1. The magnetic field at point P is ____.
  1. (A)μ0I4πxy[x2+y2+(x+y)]\frac{\mu_{0}I}{4\pi xy}\left[\sqrt{x^{2}+y^{2}}+(x+y)\right]4πxyμ0​I​[x2+y2​+(x+y)]
  2. (B)μ0I4πxy[x2+y2−(x+y)]\frac{\mu_{0}I}{4\pi xy}\left[\sqrt{x^{2}+y^{2}}-(x+y)\right]4πxyμ0​I​[x2+y2​−(x+y)]
  3. (C)μ0Ixy4π[x2+y2−(x+y)]\frac{\mu_{0}Ixy}{4\pi}\left[\sqrt{x^{2}+y^{2}}-(x+y)\right]4πμ0​Ixy​[x2+y2​−(x+y)]
  4. (D)μ0Ixy4π[x2+y2+(x+y)]\frac{\mu_{0}Ixy}{4\pi}\left[\sqrt{x^{2}+y^{2}}+(x+y)\right]4πμ0​Ixy​[x2+y2​+(x+y)]

Correct answer: (A)

Step-by-step solution →
Q21·PhysicsNumerical
The temperature of 3.00 mol of an ideal diatomic gas is increased by 40.0 °C without changing the pressure of the gas. The molecules in the gas rotate but do not oscillate. If the ratio of change in internal energy of the gas to the amount of workdone by the gas is x10\frac{x}{10}10x​. Then the value of x (round off to the nearest integer) is ________ . (Given R = 8.31 J mol−1^{-1}−1 K−1^{-1}−1)

Correct answer: 25

Step-by-step solution →
Q22·PhysicsNumerical
The width of one of the two slits in a Young's double slit experiment is three times the other slit. If the amplitude of the light coming from a slit is proportional to the slit-width, the ratio of minimum to maximum intensity in the interference pattern is x : 4 where x is ________ .

Correct answer: 1

Step-by-step solution →
Q23·PhysicsNumerical
Two satellites revolve around a planet in coplanar circular orbits in anticlockwise direction. Their period of revolutions are 1 hour and 8 hours respectively. The radius of the orbit of nearer satellite is 2 × 103^{3}3 km. The angular speed of the farther satellite as observed from the nearer satellite at the instant when both the satellites are closest is πx\frac{\pi}{x}xπ​ rad h−1^{-1}−1 where x is ..........

Correct answer: 3

Step-by-step solution →
Q24·PhysicsNumerical
When a body slides down from rest along a smooth inclined plane making an angle of 30° with the horizontal, it takes time T. When the same body slides down from the rest along a rough inclined plane making the same angle and through the same distance, it takes time αT, where α is a constant greater than 1. The co-efficient of friction between the body and the rough plane is 1x(α2−1α2)\frac{1}{\sqrt{x}}\left(\frac{\alpha^{2}-1}{\alpha^{2}}\right)x​1​(α2α2−1​) where x = ..........

Correct answer: 3

Step-by-step solution →
Q25·PhysicsNumerical
The average translational kinetic energy of N2_{2}2​ gas molecules at ..........°C becomes equal to the K.E. of an electron accelerated from rest through a potential difference of 0.1 volt. (Given kB_{B}B​ = 1.38 × 10−23^{-23}−23 J/K) (Fill the nearest integer).

Correct answer: 500

Step-by-step solution →
Q26·PhysicsNumerical
A uniform heating wire of resistance 36 Ω is connected across a potential difference of 240 V. The wire is then cut into half and potential difference of 240 V is applied across each half separately. The ratio of power dissipation in first case to the total power dissipation in the second case would be 1 : x, where x is ..........

Correct answer: 4

Step-by-step solution →
Q27·PhysicsNumerical
A steel rod with y = 2.0 × 1011^{11}11 Nm−2^{-2}−2 and α = 10−5^{-5}−5 °C−1^{-1}−1 of length 4 m and area of cross-section 10 cm2^{2}2 is heated from 0° C to 400°C without being allowed to extend. The tension produced in the rod is x × 105^{5}5 N where the value of x is ..........

Correct answer: 8

Step-by-step solution →
Q28·PhysicsNumerical
A carrier wave with amplitude of 250 V is amplitude modulated by a sinusoidal base band signal of amplitude 150 V. The ratio of minimum amplitude to maximum amplitude for the amplitude modulated wave is 50 : x, then value of x is ..........

Correct answer: 200

Step-by-step solution →
Q29·PhysicsNumerical
An engine is attached to a wagon through a shock absorber of length 1.5 m. The system with a total mass of 40,000 kg is moving with a speed of 72 kmh−1^{-1}−1 when the brakes are applied to bring it to rest. In the process of the system being brought to rest, the spring of the shock absorber gets compressed by 1.0 m. If 90% of energy of the wagon is lost due to friction, the spring constant is .......... × 105^{5}5 N/m.

Correct answer: 16

Step-by-step solution →

Chemistry — JEE Main 1 September 2021 Shift 2

Q30·ChemistrySingle correct
Water sample is called cleanest on the basis of which one of the BOD values given below
  1. (A)11 ppm
  2. (B)15 ppm
  3. (C)3 ppm
  4. (D)21 ppm

Correct answer: (C)

Step-by-step solution →
Q31·ChemistrySingle correct
Calamine and Malachite, respectively, are the ores of :
  1. (A)Nickel and Aluminium
  2. (B)Zinc and Copper
  3. (C)Copper and Iron
  4. (D)Aluminium and Zinc

Correct answer: (B)

Step-by-step solution →
Q32·Chemistry·Reaction MechanismSingle correct
Experimentally reducing a functional group cannot be done by which one of the following reagents ?
  1. (A)Pt-C/H2_{2}2​
  2. (B)Na/H2_{2}2​
  3. (C)Pd-C/H2_{2}2​
  4. (D)Zn/H2_{2}2​O

Correct answer: (B)

Step-by-step solution →
Q33·ChemistrySingle correct
Which one of the following given graphs represents the variation of rate constant (k) with temperature (T) for an endothermic reaction ?
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (C)

Step-by-step solution →
Q34·ChemistrySingle correct
Identify A in the following reaction.
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (A)

Step-by-step solution →
Q35·ChemistrySingle correct
In the following sequence of reactions a compound A, (molecular formula C6_{6}6​H12_{12}12​O2_{2}2​) with a straight chain structure gives a C4_{4}4​ carboxylic acid. A is : A —[LiAlH4_{4}4​ / H3_{3}3​O+^{+}+]→ B —[Oxidation]→ C4_{4}4​ − carboxylic acid
  1. (A)CH3_{3}3​ – CH2_{2}2​ – COO – CH2_{2}2​ – CH2_{2}2​ – CH3_{3}3​
  2. (B)CH3_{3}3​–CH2_{2}2​–CH(OH)–CH2_{2}2​–O–CH=CH2_{2}2​
  3. (C)CH3_{3}3​ – CH2_{2}2​ – CH2_{2}2​ – COO – CH2_{2}2​ – CH3_{3}3​
  4. (D)CH3_{3}3​ – CH2_{2}2​ – CH2_{2}2​ – O – CH = CH – CH2_{2}2​ – OH

Correct answer: (C)

Step-by-step solution →
Q36·ChemistrySingle correct
Match List – I (Colloid Preparation Method) with List – II (Chemical Reaction). Choose the most appropriate answer from the options given below.
List-I (Colloid Preparation Method)List-II (Chemical Reaction)
a.Hydrolysisi.2AuCl3_{3}3​ + 3HCHO + 3H2_{2}2​O → 2Au(sol) + 3HCOOH + 6HCl
b.Reductionii.As2_{2}2​O3_{3}3​ + 3H2_{2}2​S → As2_{2}2​S3_{3}3​(sol) + 3H2_{2}2​O
c.Oxidationiii.SO2_{2}2​ + 2H2_{2}2​S → 3S(sol) + 2H2_{2}2​O
d.Double Decompositioniv.FeCl3_{3}3​ + 3H2_{2}2​O → Fe(OH)3_{3}3​(sol) + 3HCl
  1. (A)(a)-(i), (b)-(iii), (c)-(ii), (d)-(iv)
  2. (B)(a)-(iv), (b)-(i), (c)-(iii), (d)-(ii)
  3. (C)(a)-(iv), (b)-(ii), (c)-(iii), (d)-(i)
  4. (D)(a)-(i), (b)-(ii), (c)-(iv), (d)-(iii)

Correct answer: (B)

Step-by-step solution →
Q37·ChemistrySingle correct
The Crystal Field Stabilization Energy (CFSE) and magnetic moment (spin-only) of an octahedral aqua complex of a metal ion (Mz+^{z+}z+) are −0.8 Δ0_{0}0​ and 3.87 BM, respectively. Identify (MZ+^{Z+}Z+) :
  1. (A)V3+^{3+}3+
  2. (B)Cr3+^{3+}3+
  3. (C)Mn4+^{4+}4+
  4. (D)Co2+^{2+}2+

Correct answer: (D)

Step-by-step solution →
Q38·ChemistrySingle correct
Monomer units of Dacron polymer are :
  1. (A)ethylene glycol and phthalic acid
  2. (B)ethylene glycol and terephthalic acid
  3. (C)glycerol and terephthalic acid
  4. (D)glycerol and phthalic acid

Correct answer: (B)

Step-by-step solution →
Q39·ChemistrySingle correct
In the given chemical reaction, colors of the Fe2+^{2+}2+ and Fe3+^{3+}3+ ions, are respectively : 5Fe2+^{2+}2+ + MnO4−_{4}^{-}4−​ + 8H+^{+}+ → Mn2+^{2+}2+ + 4H2_{2}2​O + 5Fe3+^{3+}3+
  1. (A)Yellow, Orange
  2. (B)Yellow, Green
  3. (C)Green, Orange
  4. (D)Green, Yellow

Correct answer: (D)

Step-by-step solution →
Q40·Chemistry·IsomerismSingle correct
The stereoisomers that are formed by electrophilic addition of bromine to trans-but-2-ene is/are :
  1. (A)2 enantiomers and 2 mesomers
  2. (B)2 identical mesomers
  3. (C)2 enantiomers
  4. (D)1 racemic and 2 enantiomers

Correct answer: (B)

Step-by-step solution →
Q41·ChemistrySingle correct
Hydrogen peroxide reacts with iodine in basic medium to give :
  1. (A)IO4−_{4}^{-}4−​
  2. (B)IO−^{-}−
  3. (C)I−^{-}−
  4. (D)IO3−_{3}^{-}3−​

Correct answer: (C)

Step-by-step solution →
Q42·ChemistrySingle correct
Given below are two statements : Statement I : The nucleophilic addition of sodium hydrogen sulphite to an aldehyde or a ketone involves proton transfer to form a stable ion. Statement II : The nucleophilic addition of hydrogen cyanide to an aldehyde or a ketone yields amine as final product. In the light of the above statements, choose the most appropriate answer from the options given below :
  1. (A)Both Statement I and Statement II are true.
  2. (B)Statement I is true but Statement II is false.
  3. (C)Statement I is false but Statement II is true.
  4. (D)Both Statement I and Statement II are false.

Correct answer: (B)

Step-by-step solution →
Q43·ChemistrySingle correct
Which one of the following gives the most stable Diazonium salt ?
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (B)

Step-by-step solution →
Q44·ChemistrySingle correct
The potassium ferrocyanide solution gives a Prussian blue colour, when added to :
  1. (A)CoCl3_{3}3​
  2. (B)FeCl2_{2}2​
  3. (C)CoCl2_{2}2​
  4. (D)FeCl3_{3}3​

Correct answer: (D)

Step-by-step solution →
Q45·ChemistrySingle correct
The oxide without nitrogen-nitrogen bond is :
  1. (A)N2_{2}2​O
  2. (B)N2_{2}2​O4_{4}4​
  3. (C)N2_{2}2​O3_{3}3​
  4. (D)N2_{2}2​O5_{5}5​

Correct answer: (D)

Step-by-step solution →
Q46·ChemistrySingle correct
Identify the element for which electronic configuration in +3 oxidation state is [Ar]3d5^{5}5:
  1. (A)Ru
  2. (B)Mn
  3. (C)Co
  4. (D)Fe

Correct answer: (D)

Step-by-step solution →
Q47·ChemistryNumerical
An empty LPG cylinder weighs 14.8 kg. When full, it weighs 29.0 kg and shows a pressure of 3.47 atm. In the course of use at ambient temperature, the mass of the cylinder is reduced to 23.0 kg. The final pressure inside of the cylinder is ______ atm. (Nearest integer) (Assume LPG of be an ideal gas)

Correct answer: 2

Step-by-step solution →
Q48·ChemistryNumerical
The molar solubility of Zn(OH)2_{2}2​ in 0.1 M NaOH solution is x × 10−18^{-18}−18 M. The value of x is ______ (Nearest integer) (Given : The solubility product of Zn(OH)2_{2}2​ is 2 × 10−20^{-20}−20)

Correct answer: 2

Step-by-step solution →
Q49·ChemistryNumerical
For the reaction 2NO2_{2}2​(g) ⇌ N2_{2}2​O4_{4}4​(g), when ∆S = −176.0 JK−1^{-1}−1 and ∆H = −57.8 kJ mol−1^{-1}−1, the magnitude of ∆G at 298 K for the reaction is ______ kJ mol−1^{-1}−1. (Nearest integer)

Correct answer: 5

Step-by-step solution →
Q50·ChemistryNumerical
The sum of oxidation states of two silver ions in [Ag(NH3_{3}3​)2_{2}2​] [Ag(CN)2_{2}2​] complex is ______ .

Correct answer: 2

Step-by-step solution →
Q51·ChemistryNumerical
The number of atoms in 8 g of sodium is x × 1023^{23}23. The value of x is ______ .(Nearest integer) [Given : NA_{A}A​ = 6.02 × 1023^{23}23 mol−1^{-1}−1 Atomic mass of Na = 23.0 u]

Correct answer: 2

Step-by-step solution →
Q52·ChemistryNumerical
If 80 g of copper sulphate CuSO4_{4}4​·5H2_{2}2​O is dissolved in deionised water to make 5 L of solution. The concentration of the copper sulphate solution is x × 10−3^{-3}−3 mol L−1^{-1}−1. The value of x is ______ . [Atomic masses Cu : 63.54 u, S : 32 u, O : 16 u, H : 1 u]

Correct answer: 64

Step-by-step solution →
Q53·ChemistryNumerical
A 50 watt bulb emits monochromatic red light of wavelength of 795 nm. The number of photons emitted per second by the bulb is x × 1020^{20}20. The value of x is ______ . [Given : h = 6.63 × 10−34^{-34}−34 Js and c = 3.0 × 108^{8}8 ms−1^{-1}−1]

Correct answer: 2

Step-by-step solution →
Q54·ChemistryNumerical
The spin-only magnetic moment value of B2+_{2}^{+}2+​ species is ______ ×10−2^{-2}−2 BM. (Nearest integer) [Given : 3\sqrt{3}3​ = 1.73 ]

Correct answer: 173

Step-by-step solution →
Q55·ChemistryNumerical
If the conductivity of mercury at 0°C is 1.07 × 106^{6}6 S m−1^{-1}−1 and the resistance of a cell containing mercury is 0.243 Ω, then the cell constant of the cell is x × 104^{4}4 m−1^{-1}−1. The value of x is ______ .(Nearest integer)

Correct answer: 26

Step-by-step solution →
Q56·ChemistryNumerical
A peptide synthesized by the reactions of one molecule each of Glycine, Leucine, Aspartic acid and Histidine will have ______ peptide linkages.

Correct answer: 3

Step-by-step solution →

Mathematics — JEE Main 1 September 2021 Shift 2

Q57·MathematicsSingle correct
Let f:R→Rf : \mathbb{R} \to \mathbb{R}f:R→R be a continuous function. Then lim⁡x→π4π4∫2sec⁡2xf(x) dxx2−π216\lim_{x \to \frac{\pi}{4}} \frac{\frac{\pi}{4}\int_{2}^{\sec^{2} x} f(x)\,dx}{x^{2} - \frac{\pi^{2}}{16}}limx→4π​​x2−16π2​4π​∫2sec2x​f(x)dx​ is equal to :
  1. (A)f(2)f(2)f(2)
  2. (B)2f(2)2f(2)2f(2)
  3. (C)2f(2)2f\left(\sqrt{2}\right)2f(2​)
  4. (D)4f(2)4f(2)4f(2)

Correct answer: (B)

Step-by-step solution →
Q58·MathematicsSingle correct
cos⁡−1(cos⁡(−5))+sin⁡−1(sin⁡(6))−tan⁡−1(tan⁡(12))\cos^{-1}(\cos(-5)) + \sin^{-1}(\sin(6)) - \tan^{-1}(\tan(12))cos−1(cos(−5))+sin−1(sin(6))−tan−1(tan(12)) is equal to : (The inverse trigonometric functions take the principal values)
  1. (A)3π − 11
  2. (B)4 π − 9
  3. (C)4 π − 11
  4. (D)3π + 1

Correct answer: (C)

Step-by-step solution →
Q59·MathematicsSingle correct
Consider the system of linear equations − x + y + 2z = 0 3x − ay + 5z =1 2x − 2y − az = 7 Let S1S_{1}S1​ be the set of all a ∈ ℝ for which the system is inconsistent and S2S_{2}S2​ be the set of all a ∈ ℝ for which the system has infinitely many solutions. If n(S1)n(S_{1})n(S1​) and n(S2)n(S_{2})n(S2​) denote the number of elements in S1S_{1}S1​ and S2S_{2}S2​ respectively, then
  1. (A)n(S1)=2n(S_{1}) = 2n(S1​)=2, n(S2)=2n(S_{2}) = 2n(S2​)=2
  2. (B)n(S1)=1n(S_{1}) = 1n(S1​)=1, n(S2)=0n(S_{2}) = 0n(S2​)=0
  3. (C)n(S1)=2n(S_{1}) = 2n(S1​)=2, n(S2)=0n(S_{2}) = 0n(S2​)=0
  4. (D)n(S1)=0n(S_{1}) = 0n(S1​)=0, n(S2)=2n(S_{2}) = 2n(S2​)=2

Correct answer: (C)

Step-by-step solution →
Q60·MathematicsSingle correct
Let the acute angle bisector of the two planes x − 2y − 2z + 1 = 0 and 2x − 3y − 6z + 1 = 0 be the plane P. Then which of the following points lies on P?
  1. (A)(3,1,−12)\left(3, 1, -\frac{1}{2}\right)(3,1,−21​)
  2. (B)(−2,0,−12)\left(-2, 0, -\frac{1}{2}\right)(−2,0,−21​)
  3. (C)(0, 2, –4)
  4. (D)(4, 0, – 2)

Correct answer: (B)

Step-by-step solution →
Q61·MathematicsSingle correct
Which of the following is equivalent to the Boolean expression p ∧ ~q ?
  1. (A)~ (q → p)
  2. (B)~ p → ~q
  3. (C)~ (p → ~q)
  4. (D)~ (p → q)

Correct answer: (D)

Step-by-step solution →
Q62·MathematicsSingle correct
Two squares are chosen at random on a chessboard (see figure). The probability that they have a side in common is :
  1. (A)27\frac{2}{7}72​
  2. (B)118\frac{1}{18}181​
  3. (C)17\frac{1}{7}71​
  4. (D)19\frac{1}{9}91​

Correct answer: (B)

Step-by-step solution →
Q63·MathematicsSingle correct
If y = y (x) is the solution curve of the differential equation x2dy+(y−1x)dx=0x^{2}dy + \left(y - \frac{1}{x}\right)dx = 0x2dy+(y−x1​)dx=0 ; x > 0 and y(1) = 1, then y(12)y\left(\frac{1}{2}\right)y(21​) is equal to :
  1. (A)32−1e\frac{3}{2} - \frac{1}{\sqrt{e}}23​−e​1​
  2. (B)3+1e3 + \frac{1}{\sqrt{e}}3+e​1​
  3. (C)3 + e
  4. (D)3 − e

Correct answer: (D)

Step-by-step solution →
Q64·MathematicsSingle correct
If n is the number of solutions of the equation 2cos⁡x(4sin⁡(π4+x)sin⁡(π4−x)−1)=12\cos x\left(4\sin\left(\frac{\pi}{4} + x\right)\sin\left(\frac{\pi}{4} - x\right) - 1\right) = 12cosx(4sin(4π​+x)sin(4π​−x)−1)=1, x ∈ [0, π] and S is the sum of all these solutions, then the ordered pair (n, S) is :
  1. (A)(3, 13π / 9)
  2. (B)(2, 2π / 3)
  3. (C)(2, 8π / 9)
  4. (D)(3, 5π / 3)

Correct answer: (A)

Step-by-step solution →
Q65·MathematicsSingle correct
The function f(x)=x3−6x2+ax+bf(x) = x^{3} - 6x^{2} + ax + bf(x)=x3−6x2+ax+b is such that f(2) = f(4) = 0. Consider two statements. (S1) there exists x1,x2∈(2,4)x_{1}, x_{2} \in (2, 4)x1​,x2​∈(2,4), x1<x2x_{1} < x_{2}x1​<x2​, such that f′(x1)=−1f'(x_{1}) = -1f′(x1​)=−1 and f′(x2)=0f'(x_{2}) = 0f′(x2​)=0. (S2) there exists x3,x4∈(2,4)x_{3}, x_{4} \in (2, 4)x3​,x4​∈(2,4), x3<x4x_{3} < x_{4}x3​<x4​, such that f is decreasing in (2,x4)(2, x_{4})(2,x4​), increasing in (x4,4)(x_{4}, 4)(x4​,4) and 2f′(x3)=3f(x4)2f'(x_{3}) = \sqrt{3}f\left(x_{4}\right)2f′(x3​)=3​f(x4​). Then
  1. (A)both (S1) and (S2) are true
  2. (B)(S1) is false and (S2) is true
  3. (C)both (S1) and (S2) are false
  4. (D)(S1) is true and (S2) is false

Correct answer: (A)

Step-by-step solution →
Q66·MathematicsSingle correct
Let Jn,m=∫012xnxm−1dxJ_{n,m} = \int_{0}^{\frac{1}{2}} \frac{x^{n}}{x^{m} - 1}dxJn,m​=∫021​​xm−1xn​dx, ∀ n > m and n, m ∈ N . Consider a matrix A=[aij]3×3A = [a_{ij}]_{3 \times 3}A=[aij​]3×3​ where aij={J6+i,3−Ji+3,3,i≤j0,i>ja_{ij} = \begin{cases} J_{6+i,3} - J_{i+3,3}, & i \le j \\ 0, & i > j \end{cases}aij​={J6+i,3​−Ji+3,3​,0,​i≤ji>j​. Then ∣adjA−1∣\left|\mathrm{adj}A^{-1}\right|​adjA−1​ is :
  1. (A)(15)2×242(15)^{2} \times 2^{42}(15)2×242
  2. (B)(15)2×234(15)^{2} \times 2^{34}(15)2×234
  3. (C)(105)2×238(105)^{2} \times 2^{38}(105)2×238
  4. (D)(105)2×236(105)^{2} \times 2^{36}(105)2×236

Correct answer: (C)

Step-by-step solution →
Q67·MathematicsSingle correct
The area, enclosed by the curves y = sin x + cos x and y=∣cos⁡x−sin⁡x∣y = \left|\cos x - \sin x\right|y=∣cosx−sinx∣ and the lines x = 0, x=π2x = \frac{\pi}{2}x=2π​, is :
  1. (A)22(2−1)2\sqrt{2}\left(\sqrt{2} - 1\right)22​(2​−1)
  2. (B)2(2+1)2\left(\sqrt{2} + 1\right)2(2​+1)
  3. (C)4(2−1)4\left(\sqrt{2} - 1\right)4(2​−1)
  4. (D)22(2+1)2\sqrt{2}\left(\sqrt{2} + 1\right)22​(2​+1)

Correct answer: (A)

Step-by-step solution →
Q68·MathematicsSingle correct
The distance of line 3y − 2z − 1 = 0 = 3x − z + 4 from the point (2, − 1, 6) is :
  1. (A)26\sqrt{26}26​
  2. (B)252\sqrt{5}25​
  3. (C)262\sqrt{6}26​
  4. (D)424\sqrt{2}42​

Correct answer: (C)

Step-by-step solution →
Q69·MathematicsSingle correct
Consider the parabola with vertex (12,34)\left(\frac{1}{2}, \frac{3}{4}\right)(21​,43​) and the directrix y=12y = \frac{1}{2}y=21​ . Let P be the point where the parabola meets the line x=−12x = -\frac{1}{2}x=−21​. If the normal to the parabola at P intersects the parabola again at the point Q, then (PQ)2(PQ)^{2}(PQ)2 is equal to :
  1. (A)758\frac{75}{8}875​
  2. (B)12516\frac{125}{16}16125​
  3. (C)252\frac{25}{2}225​
  4. (D)152\frac{15}{2}215​

Correct answer: (B)

Step-by-step solution →
Q70·MathematicsSingle correct
The numbers of pairs (a, b) of real numbers, such that whenever α is a root of the equation x2+ax+b=0x^{2} + ax + b = 0x2+ax+b=0 , α2−2\alpha^{2} - 2α2−2 is also a root of this equation, is :
  1. (A)6
  2. (B)2
  3. (C)4
  4. (D)8

Correct answer: (A)

Step-by-step solution →
Q71·MathematicsSingle correct
Let Sn=1⋅(n−1)+2⋅(n−2)+3⋅(n−3)+⋯+(n−1)⋅1S_{n} = 1 \cdot (n - 1) + 2 \cdot (n - 2) + 3 \cdot (n - 3) + \dots + (n - 1) \cdot 1Sn​=1⋅(n−1)+2⋅(n−2)+3⋅(n−3)+⋯+(n−1)⋅1 , n ≥ 4. The sum ∑n=4∞(2Snn!−1(n−2)!)\sum_{n=4}^{\infty}\left(\frac{2S_{n}}{n!} - \frac{1}{(n-2)!}\right)∑n=4∞​(n!2Sn​​−(n−2)!1​) is equal to :
  1. (A)e−13\frac{e-1}{3}3e−1​
  2. (B)e−26\frac{e-2}{6}6e−2​
  3. (C)e3\frac{e}{3}3e​
  4. (D)e6\frac{e}{6}6e​

Correct answer: (A)

Step-by-step solution →
Q72·MathematicsSingle correct
Let P1P_{1}P1​, P2P_{2}P2​, ....., P15P_{15}P15​ be 15 points on a circle. The number of distinct triangles formed by points Pi,Pj,PkP_{i}, P_{j}, P_{k}Pi​,Pj​,Pk​ such that i + j + k ≠ 15, is :
  1. (A)12
  2. (B)419
  3. (C)443
  4. (D)455

Correct answer: (C)

Step-by-step solution →
Q73·MathematicsSingle correct
The range of the function, f(x)=log⁡5(3+cos⁡(3π4+x)+cos⁡(π4+x)+cos⁡(π4−x)−cos⁡(3π4−x))f(x) = \log_{\sqrt{5}}\left(3 + \cos\left(\frac{3\pi}{4} + x\right) + \cos\left(\frac{\pi}{4} + x\right) + \cos\left(\frac{\pi}{4} - x\right) - \cos\left(\frac{3\pi}{4} - x\right)\right)f(x)=log5​​(3+cos(43π​+x)+cos(4π​+x)+cos(4π​−x)−cos(43π​−x)) is :
  1. (A)(0,5)\left(0, \sqrt{5}\right)(0,5​)
  2. (B)[–2, 2]
  3. (C)[15,5]\left[\frac{1}{\sqrt{5}}, \sqrt{5}\right][5​1​,5​]
  4. (D)[0, 2]

Correct answer: (D)

Step-by-step solution →
Q74·MathematicsSingle correct
Let a1,a2,.......,a21a_{1}, a_{2}, ......., a_{21}a1​,a2​,.......,a21​ be an AP such that ∑n=1201anan+1=49\sum_{n=1}^{20}\frac{1}{a_{n}a_{n+1}} = \frac{4}{9}∑n=120​an​an+1​1​=94​. If the sum of this AP is 189, then a6a16a_{6}a_{16}a6​a16​ is equal to :
  1. (A)57
  2. (B)72
  3. (C)48
  4. (D)36

Correct answer: (B)

Step-by-step solution →
Q75·MathematicsSingle correct
The function f(x), that satisfies the condition f(x)=x+∫0π/2sin⁡x⋅cos⁡y f(y)dyf(x) = x + \int_{0}^{\pi/2} \sin x \cdot \cos y\, f(y)dyf(x)=x+∫0π/2​sinx⋅cosyf(y)dy, is :
  1. (A)x+23(π−2)sin⁡xx + \frac{2}{3}(\pi - 2)\sin xx+32​(π−2)sinx
  2. (B)x + (π + 2) sinx
  3. (C)x+π2sin⁡xx + \frac{\pi}{2}\sin xx+2π​sinx
  4. (D)x + (π − 2) sinx

Correct answer: (D)

Step-by-step solution →
Q76·MathematicsSingle correct
Let θ be the acute angle between the tangents to the ellipse x29+y21=1\frac{x^{2}}{9} + \frac{y^{2}}{1} = 19x2​+1y2​=1 and the circle x2+y2=3x^{2} + y^{2} = 3x2+y2=3 at their point of intersection in the first quadrant. Then tanθ is equal to :
  1. (A)523\frac{5}{2\sqrt{3}}23​5​
  2. (B)23\frac{2}{\sqrt{3}}3​2​
  3. (C)43\frac{4}{\sqrt{3}}3​4​
  4. (D)2

Correct answer: (B)

Step-by-step solution →
Q77·MathematicsNumerical
Let X be a random variable with distribution. If the mean of X is 2.3 and variance of X is σ2\sigma^{2}σ2, then 100 σ2100\,\sigma^{2}100σ2 is equal to ________ .
x−2−1346
P(X = x)15\frac{1}{5}51​a13\frac{1}{3}31​15\frac{1}{5}51​b

Correct answer: 781

Step-by-step solution →
Q78·MathematicsNumerical
Let f(x)=x6+2x4+x3+2x+3f(x) = x^{6} + 2x^{4} + x^{3} + 2x + 3f(x)=x6+2x4+x3+2x+3, x ∈ ℝ. Then the natural number n for which lim⁡x→1xnf(1)−f(x)x−1=44\lim_{x \to 1} \frac{x^{n} f(1) - f(x)}{x - 1} = 44limx→1​x−1xnf(1)−f(x)​=44 is ________ .

Correct answer: 7

Step-by-step solution →
Q79·MathematicsNumerical
If for the complex numbers z satisfying |z − 2 − 2i| ≤ 1, the maximum value of |3iz + 6| is attained at a + ib, then a + b is equal to ________ .

Correct answer: 5

Step-by-step solution →
Q80·MathematicsNumerical
Let the points of intersections of the lines x − y + 1 = 0, x − 2y + 3 = 0 and 2x − 5y + 11 = 0 are the mid points of the sides of a triangle ABC. Then the area of the triangle ABC is ________ .

Correct answer: 6

Step-by-step solution →
Q81·MathematicsNumerical
Let f(x) be a polynomial of degree 3 such that f(k)=−2kf(k) = -\frac{2}{k}f(k)=−k2​ for k = 2, 3, 4, 5. Then the value of 52 − 10 f(10) is equal to :

Correct answer: 26

Step-by-step solution →
Q82·MathematicsNumerical
All the arrangements, with or without meaning, of the word FARMER are written excluding any word that has two R appearing together. The arrangements are listed serially in the alphabetic order as in the English dictionary. Then the serial number of the word FARMER in this list is ______ .

Correct answer: 77

Step-by-step solution →
Q83·MathematicsNumerical
If the sum of the coefficients in the expansion of (x+y)n(x + y)^{n}(x+y)n is 4096, then the greatest coefficient in the expansion is ________ .

Correct answer: 924

Step-by-step solution →
Q84·MathematicsNumerical
Let a⃗=2i^−j^+2k^\vec{a} = 2\hat{i} - \hat{j} + 2\hat{k}a=2i^−j^​+2k^ and b⃗=i^+2j^−k^\vec{b} = \hat{i} + 2\hat{j} - \hat{k}b=i^+2j^​−k^. Let a vector v⃗\vec{v}v be in the plane containing a⃗\vec{a}a and b⃗\vec{b}b. If v⃗\vec{v}v is perpendicular to the vector 3i^+2j^−k^3\hat{i} + 2\hat{j} - \hat{k}3i^+2j^​−k^ and its projection on a⃗\vec{a}a is 19 units, then ∣2v⃗∣2\left|2\vec{v}\right|^{2}∣2v∣2 is equal to ______ .

Correct answer: 1494

Step-by-step solution →
Q85·MathematicsNumerical
Let [t] denote the greatest integer ≤ t. The number of points where the function f(x)=[x]∣x2−1∣+sin⁡(π[x]+3)−[x+1],x∈(−2,2)f(x) = [x]\left|x^{2} - 1\right| + \sin\left(\frac{\pi}{[x] + 3}\right) - [x + 1], x \in (-2, 2)f(x)=[x]​x2−1​+sin([x]+3π​)−[x+1],x∈(−2,2) is not continuous is ______ .

Correct answer: 2

Step-by-step solution →
Q86·MathematicsNumerical
A man starts walking from the point P(−3,4), touches the x-axis at R, and then turns to reach at the point Q(0, 2). The man is walking at a constant speed. If the man reaches the point Q in the minimum time, then 50((PR)2+(RQ)2)50\left((PR)^{2} + (RQ)^{2}\right)50((PR)2+(RQ)2) is equal to ______ .

Correct answer: 1250

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Chapters tested in this paper

Open any chapter to practise every past-year question on that topic across all papers, and see how often it has actually appeared.

  • Properties of Solids and Liquids 172/186
  • Three Dimensional Geometry 176/186
  • Matrices and Determinants 180/186
  • Coordination Compounds 176/186
  • Sets, Relations and Functions 165/186
  • Current Electricity 160/186
  • Sequence and Series 164/186
  • p-Block Elements 164/186
  • Definite Integration 168/186
  • Redox Reactions and Electrochemistry 177/186
  • Geometrical Optics 172/186
  • Kinematics 156/186
  • Vector Algebra 173/186
  • Differential Equations 167/186
  • Probability 176/186
  • Permutations and Combinations 162/186
  • Magnetic Field of Current 147/186
  • Binomial Theorem and Its Simple Applications 158/186
  • Electromagnetic Waves 144/186
  • Chemical Bonding and Molecular Structure 151/186
  • Application of Derivatives 139/186
  • Limits and Continuity 149/186
  • d- and f-Block Elements 126/186
  • Thermodynamics 154/186
  • Aldehydes and Ketones 135/186
  • Equilibrium 163/186
  • Laws of Motion 130/186
  • Chemical Thermodynamics 165/186
  • Units and Measurements 149/186
  • Complex Numbers 165/186
  • Trigonometric Functions 144/186
  • Biomolecules 162/186
  • Chemical Kinetics 169/186
  • Gravitation 152/186
  • Electric Field and Coulomb's Law 133/186
  • Atomic Structure 161/186
  • Electronic Devices 145/186
  • Dual Nature of Matter and Radiation 155/186
  • Amines 133/186
  • Quadratic Equations 148/186
  • Work, Energy and Power 132/186
  • Some Basic Concepts in Chemistry 129/186
  • Electromagnetic Induction 120/186
  • Wave Optics 130/186
  • Area Under Curves 139/186
  • Kinetic Theory of Gases 135/186
  • Oscillations 117/186
  • Nuclei 116/186
  • Straight Lines 114/186
  • Capacitors and Dielectrics 115/186
  • Parabola 101/186
  • Ellipse 103/186
  • Isolation of Metals 106/186
  • Surface Chemistry 98/186
  • Inverse Trigonometric Functions 93/186
  • Environmental Chemistry 83/186
  • Hydrogen 81/186
  • Polymers 64/186
  • Carboxylic Acids and Derivatives 54/186
  • Principles of Qualitative Analysis 58/186
  • Diazonium Salts and Reactions 53/186
  • States of Matter: Gases and Liquids 52/186
  • Isomerism 51/186
  • Magnetism and Matter 50/186
  • Reaction Mechanism 29/186
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