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JEE Main 24 June 2022 Shift 1 Question Paper with Answers

24 June 2022 · June session · 87 questions

87 of the 90 questions from the JEE Main 24 June 2022 Shift 1 paper, each with its correct answer and tagged to the chapter it tests. Free to read, no account needed.

3 questions are held back from this paper while we re-check the transcription or the answer key. We would rather show you nothing than show you an answer we are not confident is right.

Physics
30
Chemistry
28
Mathematics
29

Physics — JEE Main 24 June 2022 Shift 1

Q1·PhysicsSingle correct
The bulk modulus of a liquid is 3×10103\times10^{10}3×1010 Nm−2^{-2}−2. The pressure required to reduce the volume of liquid by 2% is :
  1. (A)3×1083\times10^{8}3×108 Nm−2^{-2}−2
  2. (B)9×1089\times10^{8}9×108 Nm−2^{-2}−2
  3. (C)6×1086\times10^{8}6×108 Nm−2^{-2}−2
  4. (D)12×10812\times10^{8}12×108 Nm−2^{-2}−2

Correct answer: (C)

Step-by-step solution →
Q2·Physics·Magnetic Field of CurrentSingle correct
Given below are two statements : One is labelled as Assertion (A) and the other is labelled as Reason (R). Assertion (A) : In an uniform magnetic field, speed and energy remains the same for a moving charged particle. Reason (R) : Moving charged particle experiences magnetic force perpendicular to its direction of motion.
  1. (A)Both (A) and (R) are true and (R) is the correct explanation of (A)
  2. (B)Both (A) and (R) are true but (R) is NOT the correct explanation of (A)
  3. (C)(A) is true but (R) is false
  4. (D)(A) is false but (R) is true.

Correct answer: (A)

Step-by-step solution →
Q3·PhysicsSingle correct
Two identical cells each of emf 1.5 V are connected in parallel across a parallel combination of two resistors each of resistance 20Ω20\Omega20Ω. A voltmeter connected in the circuit measures 1.2 V. The internal resistance of each cell is
  1. (A)2.5Ω2.5\Omega2.5Ω
  2. (B)4Ω4\Omega4Ω
  3. (C)5Ω5\Omega5Ω
  4. (D)10Ω10\Omega10Ω

Correct answer: (C)

Step-by-step solution →
Q4·PhysicsSingle correct
Identify the pair of physical quantities which have different dimensions :
  1. (A)Wave number and Rydberg's constant
  2. (B)Stress and Coefficient of elasticity
  3. (C)Coercivity and Magnetisation
  4. (D)Specific heat capacity and Latent heat

Correct answer: (D)

Step-by-step solution →
Q5·PhysicsSingle correct
A projectile is projected with velocity of 25 m/s at an angle θ\thetaθ with the horizontal. After t seconds its inclination with horizontal becomes zero. If R represents horizontal range of the projectile, the value of θ\thetaθ will be : [use g = 10 m/s2^{2}2]
  1. (A)12sin⁡−1(5t24R)\dfrac{1}{2}\sin^{-1}\left(\dfrac{5t^{2}}{4R}\right)21​sin−1(4R5t2​)
  2. (B)12sin⁡−1(4R5t2)\dfrac{1}{2}\sin^{-1}\left(\dfrac{4R}{5t^{2}}\right)21​sin−1(5t24R​)
  3. (C)tan⁡−1(4t25R)\tan^{-1}\left(\dfrac{4t^{2}}{5R}\right)tan−1(5R4t2​)
  4. (D)cot⁡−1(R20t2)\cot^{-1}\left(\dfrac{R}{20t^{2}}\right)cot−1(20t2R​)

Correct answer: (D)

Step-by-step solution →
Q6·PhysicsSingle correct
A block of mass 10 kg starts sliding on a surface with an initial velocity of 9.8 ms−1^{-1}−1. The coefficient of friction between the surface and bock is 0.5. The distance covered by the block before coming to rest is : [use g = 9.8 ms−2^{-2}−2]
  1. (A)4.9 m
  2. (B)9.8 m
  3. (C)12.5 m
  4. (D)19.6 m

Correct answer: (B)

Step-by-step solution →
Q7·PhysicsSingle correct
A boy ties a stone of mass 100 g to the end of a 2 m long string and whirls it around in a horizontal plane. The string can withstand the maximum tension of 80 N. If the maximum speed with which the stone can revolve is Kπ\dfrac{K}{\pi}πK​ rev./min. The value of K is : (Assume the string is massless and unstretchable)
  1. (A)400
  2. (B)300
  3. (C)600
  4. (D)800

Correct answer: (C)

Step-by-step solution →
Q8·PhysicsSingle correct
A vertical electric field of magnitude 4.9×1054.9\times10^{5}4.9×105 N/C just prevents a water droplet of a mass 0.1 g from falling. The value of charge on the droplet will be : (Given g = 9.8 m/s2^{2}2)
  1. (A)1.6×10−91.6\times10^{-9}1.6×10−9 C
  2. (B)2.0×10−92.0\times10^{-9}2.0×10−9 C
  3. (C)3.2×10−93.2\times10^{-9}3.2×10−9 C
  4. (D)0.5×10−90.5\times10^{-9}0.5×10−9 C

Correct answer: (B)

Step-by-step solution →
Q9·PhysicsSingle correct
A particle experiences a variable force F⃗=(4xi^+3y2j^)\vec{F}=(4x\hat{i}+3y^{2}\hat{j})F=(4xi^+3y2j^​) in a horizontal x-y plane. Assume distance in meters and force is newton. If the particle moves from point (1, 2) to point (2, 3) in the x-y plane, the Kinetic Energy changes by
  1. (A)50.0 J
  2. (B)12.5 J
  3. (C)25.0 J
  4. (D)0 J

Correct answer: (C)

Step-by-step solution →
Q10·PhysicsSingle correct
The approximate height from the surface of earth at which the weight of the body becomes 13\dfrac{1}{3}31​ of its weight on the surface of earth is : [Radius of earth R = 6400 km and 3=1.732\sqrt{3} = 1.7323​=1.732]
  1. (A)3840 km
  2. (B)4685 km
  3. (C)2133 km
  4. (D)4267 km

Correct answer: (B)

Step-by-step solution →
Q11·PhysicsSingle correct
A resistance of 40 Ω\OmegaΩ is connected to a source of alternating current rated 220 V, 50 Hz. Find the time taken by the current to change from its maximum value to rms value :
  1. (A)2.5 ms
  2. (B)1.25 ms
  3. (C)2.5 s
  4. (D)0.25 s

Correct answer: (A)

Step-by-step solution →
Q12·PhysicsSingle correct
The equations of two waves are given by : y1=5sin⁡2π(x−vt)y_{1}=5\sin 2\pi(x-vt)y1​=5sin2π(x−vt) cm y2=3sin⁡2π(x−vt+1.5)y_{2}=3\sin 2\pi(x-vt+1.5)y2​=3sin2π(x−vt+1.5) cm These waves are simultaneously passing through a string. The amplitude of the resulting wave is
  1. (A)2 cm
  2. (B)4 cm
  3. (C)5.8 cm
  4. (D)8 cm

Correct answer: (A)

Step-by-step solution →
Q13·PhysicsSingle correct
A plane electromagnetic wave travels in a medium of relative permeability 1.61 and relative permittivity 6.44. If magnitude of magnetic intensity is 4.5×10−24.5\times10^{-2}4.5×10−2 Am−1^{-1}−1 at a point, what will be the approximate magnitude of electric field intensity at that point ? (Given : permeability of free space μ0=4π×10−7\mu_{0}=4\pi\times10^{-7}μ0​=4π×10−7 NA−2^{-2}−2, speed of light in vacuum c=3×108c=3\times10^{8}c=3×108 ms−1^{-1}−1)
  1. (A)16.96 Vm−1^{-1}−1
  2. (B)2.25×10−22.25\times10^{-2}2.25×10−2 Vm−1^{-1}−1
  3. (C)8.48 Vm−1^{-1}−1
  4. (D)6.75×1066.75\times10^{6}6.75×106 Vm−1^{-1}−1

Correct answer: (C)

Step-by-step solution →
Q14·PhysicsSingle correct
Choose the correct option from the following options given below :
  1. (A)In the ground state of Rutherford's model electrons are in stable equilibrium. While in Thomson's model electrons always experience a net-force.
  2. (B)An atom has a nearly continuous mass distribution in a Rutherford's model but has a highly non-uniform mass distribution in Thomson's model
  3. (C)A classical atom based on Rutherford's model is doomed to collapse.
  4. (D)The positively charged part of the atom possesses most of the mass in Rutherford's model but not in Thomson's model.

Correct answer: (C)

Step-by-step solution →
Q15·PhysicsSingle correct
Nucleus A is having mass number 220 and its binding energy per nucleon is 5.6 MeV. It splits in two fragments 'B' and 'C' of mass numbers 105 and 115. The binding energy of nucleons in 'B' and 'C' is 6.4 MeV per nucleon. The energy Q released per fission will be :
  1. (A)0.8 MeV
  2. (B)275 MeV
  3. (C)220 MeV
  4. (D)176 MeV

Correct answer: (D)

Step-by-step solution →
Q16·PhysicsSingle correct
A baseband signal of 3.5 MHz frequency is modulated with a carrier signal of 3.5 GHz frequency using amplitude modulation method. What should be the minimum size of antenna required to transmit the modulated signal ?
  1. (A)42.8 m
  2. (B)42.8 mm
  3. (C)21.4 mm
  4. (D)21.4 m

Correct answer: (C)

Step-by-step solution →
Q17·PhysicsSingle correct
A Carnot engine whose heat sinks at 27∘27^{\circ}27∘C, has an efficiency of 25%. By how many degrees should the temperature of the source be changed to increase the efficiency by 100% of the original efficiency ?
  1. (A)Increases by 18∘18^{\circ}18∘C
  2. (B)Increase by 200∘200^{\circ}200∘C
  3. (C)Increase by 120∘120^{\circ}120∘C
  4. (D)Increase by 73∘73^{\circ}73∘

Correct answer: (B)

Step-by-step solution →
Q18·PhysicsSingle correct
A parallel plate capacitor is formed by two plates each of area 30π30\pi30π cm2^{2}2 separated by 1 mm. A material of dielectric strength 3.6×1073.6\times10^{7}3.6×107 Vm−1^{-1}−1 is filled between the plates. If the maximum charge that can be stored on the capacitor without causing any dielectric breakdown is 7×10−67\times10^{-6}7×10−6 C, the value of dielectric constant of the material is : {Use:14πε0=9×109 Nm2C−2}\left\{\text{Use}:\dfrac{1}{4\pi\varepsilon_{0}}=9\times10^{9}\ \text{Nm}^{2}\text{C}^{-2}\right\}{Use:4πε0​1​=9×109 Nm2C−2}
  1. (A)1.66
  2. (B)1.75
  3. (C)2.25
  4. (D)2.33

Correct answer: (D)

Step-by-step solution →
Q19·PhysicsSingle correct
The magnetic field at the centre of a circular coil of radius r, due to current I flowing through it, is B. The magnetic field at a point along the axis at a distance r2\dfrac{r}{2}2r​ from the centre is :
  1. (A)B/2
  2. (B)2B
  3. (C)(25)3B\left(\dfrac{2}{\sqrt{5}}\right)^{3}B(5​2​)3B
  4. (D)(23)3B\left(\dfrac{2}{\sqrt{3}}\right)^{3}B(3​2​)3B

Correct answer: (C)

Step-by-step solution →
Q20·PhysicsSingle correct
Two metallic blocks M1M_{1}M1​ and M2M_{2}M2​ of same area of cross-section are connected to each other (as shown in figure). If the thermal conductivity of M2M_{2}M2​ is K then the thermal conductivity of M1M_{1}M1​ will be : [Assume steady state heat conduction]
  1. (A)10 K
  2. (B)8 K
  3. (C)12.5 K
  4. (D)2 K

Correct answer: (B)

Step-by-step solution →
Q21·PhysicsNumerical
0.056 kg of Nitrogen is enclosed in a vessel at a temperature of 127∘127^{\circ}127∘C. The amount of heat required to double the speed of its molecules is ______ k cal. (Take R = 2 cal mole−1^{-1}−1K−1^{-1}−1)

Correct answer: 12

Step-by-step solution →
Q22·PhysicsNumerical
Two identical thin biconvex lenses of focal length 15 cm and refractive index 1.5 are in contact with each other. The space between the lenses is filled with a liquid of refractive index 1.25. The focal length of the combination is _______ cm.

Correct answer: 10

Step-by-step solution →
Q23·PhysicsNumerical
A transistor is used in common-emitter mode in an amplifier circuit. When a signal of 10 mV is added to the base-emitter voltage, the base current changes by 10 μ\muμA and the collector current changes by 1.5 mA. The load resistance is 5 kΩ\OmegaΩ. The voltage gain of the transistor will be ______ .

Correct answer: 750

Step-by-step solution →
Q24·PhysicsNumerical
As shown in the figure an inductor of inductance 200 mH is connected to an AC source of emf 220 V and frequency 50 Hz. The instantaneous voltage of the source is 0 V when the peak value of current is aπ\dfrac{\sqrt{a}}{\pi}πa​​ A. The value of a is ________.

Correct answer: 242

Step-by-step solution →
Q25·PhysicsNumerical
Sodium light of wavelengths 650 nm and 655 nm is used to study diffraction at a single slit of aperture 0.5 mm. The distance between the slit and the screen is 2.0 m. The separation between the positions of the first maxima of diffraction pattern obtained in the two cases is ______ ×10−5\times10^{-5}×10−5 m.

Correct answer: 3

Step-by-step solution →
Q26·PhysicsNumerical
When light of frequency twice the threshold frequency is incident on the metal plate, the maximum velocity of emitted election is v1v_{1}v1​. When the frequency of incident radiation is increased to five times the threshold value, the maximum velocity of emitted electron becomes v2v_{2}v2​. If v2v_{2}v2​ = x v1v_{1}v1​, the value of x will be ______.

Correct answer: 2

Step-by-step solution →
Q27·PhysicsNumerical
From the top of a tower, a ball is thrown vertically upward which reaches the ground in 6 s. A second ball thrown vertically downward from the same position with the same speed reaches the ground in 1.5 s. A third ball released, from the rest from the same location, will reach the ground in ________ s.

Correct answer: 3

Step-by-step solution →
Q28·PhysicsNumerical
A ball of mass 100 g is dropped from a height h = 10 cm on a platform fixed at the top of vertical spring (as shown in figure). The ball stays on the platform and the platform is depressed by a distance h2\dfrac{h}{2}2h​. The spring constant is ________ Nm−1^{-1}−1. (Use g = 10 ms−2^{-2}−2)

Correct answer: 120

Step-by-step solution →
Q29·PhysicsNumerical
In a potentiometer arrangement, a cell gives a balancing point at 75 cm length of wire. This cell is now replaced by another cell of unknown emf. If the ratio of the emf's of two cells respectively is 3 : 2, the difference in the balancing length of the potentiometer wire in above two cases will be ______ cm.

Correct answer: 25

Step-by-step solution →
Q30·PhysicsNumerical
A metre scale is balanced on a knife edge at its centre. When two coins, each of mass 10 g are put one on the top of the other at the 10.0 cm mark the scale is found to be balanced at 40.0 cm mark. The mass of the metre scale is found to be x×10−2x \times 10^{-2}x×10−2 kg. The value of x is

Correct answer: 6

Step-by-step solution →

Chemistry — JEE Main 24 June 2022 Shift 1

Q31·ChemistrySingle correct
If a rocket runs on a fuel (C15_{15}15​ H30_{30}30​) and liquid oxygen, the weight of oxygen required and CO2_22​ released for every litre of fuel respectively are: (Given: density of the fuel is 0.756 g/mL)
  1. (A)1188 g and 1296 g
  2. (B)2376 g and 2592 g
  3. (C)2592g and 2376 g
  4. (D)3429 g and 3142 g

Correct answer: (C)

Step-by-step solution →
Q32·ChemistrySingle correct
Consider the following pairs of electrons (A) (a) n=3n = 3n=3, ℓ=1\ell = 1ℓ=1, mℓ=1m_\ell = 1mℓ​=1, ms=+12m_s = +\dfrac{1}{2}ms​=+21​ (b) n=3n = 3n=3, ℓ=2\ell = 2ℓ=2, mℓ=1m_\ell = 1mℓ​=1, ms=+12m_s = +\dfrac{1}{2}ms​=+21​ (B) (a) n=3n = 3n=3, ℓ=2\ell = 2ℓ=2, mℓ=−2m_\ell = -2mℓ​=−2, ms=−12m_s = -\dfrac{1}{2}ms​=−21​ (b) n=3n = 3n=3, ℓ=2\ell = 2ℓ=2, mℓ=−1m_\ell = -1mℓ​=−1, ms=−12m_s = -\dfrac{1}{2}ms​=−21​ (C) (a) n=4n = 4n=4, ℓ=2\ell = 2ℓ=2, mℓ=2m_\ell = 2mℓ​=2, ms=+12m_s = +\dfrac{1}{2}ms​=+21​ (b) n=3n = 3n=3, ℓ=2\ell = 2ℓ=2, mℓ=2m_\ell = 2mℓ​=2, ms=+12m_s = +\dfrac{1}{2}ms​=+21​ The pairs of electron present in degenerate orbitals is/are:
  1. (A)Only A
  2. (B)Only B
  3. (C)Only C
  4. (D)(B) and (C)

Correct answer: (B)

Step-by-step solution →
Q33·ChemistrySingle correct
Match List – I with List - II
List-IList-II
A.[PtCl4_44​]2−^{2-}2−I.sp3^33d
B.BrF5_55​II.d2^22sp3^33
C.PCl5_55​III.dsp2^22
D.[Co(NH3_33​)6_66​]3+^{3+}3+IV.sp3^33d2^22
  1. (A)(A)→(II), (B)→(IV), (C)→(I), (D)→(III)
  2. (B)(A)→(III), (B)→(IV), (C)→(I), (D)→(II)
  3. (C)(A)→(III), (B)→(I), (C)→(IV), (D)→(II)
  4. (D)(A)→(II), (B)→(I), (C)→(IV), (D)→(III)

Correct answer: (B)

Step-by-step solution →
Q34·ChemistrySingle correct
For a reaction at equilibrium A(g)⇌B(g)+12C(g)A(g)\rightleftharpoons B(g)+\dfrac{1}{2}C(g)A(g)⇌B(g)+21​C(g) the relation between dissociation constant (K), degree of dissociation (α\alphaα) and equilibrium pressure (p) is given by :
  1. (A)K=α12p32(1+32α)12(1−α)K=\dfrac{\alpha^{\frac{1}{2}}p^{\frac{3}{2}}}{\left(1+\dfrac{3}{2}\alpha\right)^{\frac{1}{2}}(1-\alpha)}K=(1+23​α)21​(1−α)α21​p23​​
  2. (B)K=α32p12(2+α)12(1−α)K=\dfrac{\alpha^{\frac{3}{2}}p^{\frac{1}{2}}}{(2+\alpha)^{\frac{1}{2}}(1-\alpha)}K=(2+α)21​(1−α)α23​p21​​
  3. (C)K=(αp)32(1+32α)12(1−α)K=\dfrac{(\alpha p)^{\frac{3}{2}}}{\left(1+\dfrac{3}{2}\alpha\right)^{\frac{1}{2}}(1-\alpha)}K=(1+23​α)21​(1−α)(αp)23​​
  4. (D)K=(αp)32(1+α)(1−α)12K=\dfrac{(\alpha p)^{\frac{3}{2}}}{(1+\alpha)(1-\alpha)^{\frac{1}{2}}}K=(1+α)(1−α)21​(αp)23​​

Correct answer: (B)

Step-by-step solution →
Q35·ChemistrySingle correct
Given below are two statements : Statement I : Emulsions of oil in water are unstable and sometimes they separate into two layers on standing. Statement II :For stabilisation of an emulsion, excess of electrolyte is added. In the light of the above statements, choose the most appropriate answer from the options given below :
  1. (A)Both Statement I and Statement II are correct.
  2. (B)Both Statement I and Statement II are incorrect.
  3. (C)Statement I is correct but Statement II is incorrect.
  4. (D)Statement I is incorrect but Statement II is correct.

Correct answer: (C)

Step-by-step solution →
Q36·ChemistrySingle correct
Given below are the oxides: Na2_22​O, As2_22​O3_33​, N2_22​O, NO and Cl2_22​O7_77​ Number of amphoteric oxides is:
  1. (A)0
  2. (B)1
  3. (C)2
  4. (D)3

Correct answer: (B)

Step-by-step solution →
Q37·ChemistrySingle correct
Match List – I with List – II Choose the most appropriate answer from the options given below:
List-IList-II
A.SphaleriteI.FeCO3_33​
B.CalamineII.PbS
C.GalenaIII.ZnCO3_33​
D.SideriteIV.ZnS
  1. (A)(A) - (IV), (B) - (III), (C) - (II), (D) - (I)
  2. (B)(A) - (IV), (B) - (I), (C) - (II), (D) - (III)
  3. (C)(A) - (II), (B) - (III), (C) - (I), (D) - (IV)
  4. (D)(A) - (III), (B) - (IV), (C) - (II), (D) - (I)

Correct answer: (A)

Step-by-step solution →
Q38·ChemistrySingle correct
The highest industrial consumption of molecular hydrogen is to produce compounds of element:
  1. (A)Carbon
  2. (B)Nitrogen
  3. (C)Oxygen
  4. (D)Chlorine

Correct answer: (B)

Step-by-step solution →
Q39·ChemistrySingle correct
Identify the correct statement for B2_22​H6_66​ from those given below. (A) In B2_22​H6_66​, all B-H bonds are equivalent. (B) In B2_22​H6_66​ there are four 3-centre-2-electron bonds. (C) B2_22​H6_66​ is a Lewis acid. (D) B2_22​H6_66​ can be synthesized form both BF3_33​ and NaBH4_44​. (E) B2_22​H6_66​ is a planar molecule. Choose the most appropriate answer from the options given below :
  1. (A)(A) and (E) only
  2. (B)(B), (C) and (E) only
  3. (C)(C) and (D) only
  4. (D)(C) and (E) only

Correct answer: (C)

Step-by-step solution →
Q40·ChemistrySingle correct
The most stable trihalide of nitrogen is:
  1. (A)NF3_33​
  2. (B)NCl3_33​
  3. (C)NBr3_33​
  4. (D)NI3_33​

Correct answer: (A)

Step-by-step solution →
Q41·ChemistrySingle correct
Which one of the following elemental forms is not present in the enamel of the teeth?
  1. (A)Ca2+^{2+}2+
  2. (B)P3+^{3+}3+
  3. (C)F−^-−
  4. (D)P5+^{5+}5+

Correct answer: (B)

Step-by-step solution →
Q42·ChemistrySingle correct
In the given reactions sequence, the major product 'C' is :
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (B)

Step-by-step solution →
Q43·Chemistry·Carboxylic Acids and DerivativesSingle correct
Two statements are given below : Statement I: The melting point of monocarboxylic acid with even number of carbon atoms is higher than that of with odd number of carbon atoms acid immediately below and above it in the series. Statement II : The solubility of monocarboxylic acids in water decreases with increase in molar mass. Choose the most appropriate option:
  1. (A)Both Statement I and Statement II are correct.
  2. (B)Both Statement I and Statement II are incorrect.
  3. (C)Statement I is correct but Statement II is incorrect.
  4. (D)Statement I is incorrect but Statement II is correct.

Correct answer: (A)

Step-by-step solution →
Q44·ChemistrySingle correct
Which of the following is an example of conjugated diketone?
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (C)

Step-by-step solution →
Q45·ChemistrySingle correct
The major product of the above reaction is
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (D)

Step-by-step solution →
Q46·ChemistrySingle correct
Which of the following is an example of polyester?
  1. (A)Butadiene-styrene copolymer
  2. (B)Melamine polymer
  3. (C)Neoprene
  4. (D)Poly-β\betaβ-hydroxybutyrate-co-β\betaβ-hydroxy valerate

Correct answer: (D)

Step-by-step solution →
Q47·ChemistrySingle correct
A polysaccharide 'X' on boiling with dil H2_22​SO4_44​ at 393 K under 2-3 atm pressure yields 'Y'. 'Y' on treatment with bromine water gives gluconic acid. 'X' contains β\betaβ-glycosidic linkages only. Compound 'X' is :
  1. (A)starch
  2. (B)cellulose
  3. (C)amylose
  4. (D)amylopectin

Correct answer: (B)

Step-by-step solution →
Q48·ChemistrySingle correct
Which of the following is not a broad spectrum antibiotic?
  1. (A)Vancomycin
  2. (B)Ampicillin
  3. (C)Ofloxacin
  4. (D)Penicillin G

Correct answer: (D)

Step-by-step solution →
Q49·ChemistrySingle correct
During the qualitative analysis of salt with cation y2+^{2+}2+ , addition of a reagent (X) to alkaline solution of the salt gives a bright red precipitate. The reagent (X) and the cation (y2+^{2+}2+) present respectively are:
  1. (A)Dimethylglyoxime and Ni2+^{2+}2+
  2. (B)Dimethylglyoxime and Co2+^{2+}2+
  3. (C)Nessler's reagent and Hg2+^{2+}2+
  4. (D)Nessler's reagent and Ni2+^{2+}2+

Correct answer: (A)

Step-by-step solution →
Q50·ChemistryNumerical
Atoms of element X form hcp lattice and those of element Y occupy 23\frac{2}{3}32​ of its tetrahedral voids. The percentage of element X in the lattice is__________ (Nearest integer)

Correct answer: 43

Step-by-step solution →
Q51·ChemistryNumerical
2O3_33​(g) ⇌\rightleftharpoons⇌ 3O2_22​(g) At 300 K, ozone is fifty percent dissociated. The standard free energy change at this temperature and 1 atm pressure is (–) __J mol−1^{-1}−1 (Nearest integer) [Given: ln 1.35 = 0.3 and R = 8.3 J K−1^{-1}−1 mol−1^{-1}−1]

Correct answer: 747

Step-by-step solution →
Q52·ChemistryNumerical
The osmotic pressure of blood is 7.47 bar at 300 K. To inject glucose to a patient intravenously, it has to be isotonic with blood. The concentration of glucose solution in gL−1^{-1}−1 is _____(Molar mass of glucose = 180 g mol−1^{-1}−1 R = 0.083 L bar K−1^{-1}−1 mol−1^{-1}−1) (Nearest integer)

Correct answer: 54

Step-by-step solution →
Q53·ChemistryNumerical
The cell potential for the following cell Pt ∣ H2(g) ∣ H+(aq) ∣∣ Cu2+(0.01 M) ∣ Cu(s)\mathrm{Pt}\,|\,\mathrm{H}_2(g)\,|\,\mathrm{H}^{+}(aq)\,||\,\mathrm{Cu}^{2+}(0.01\,\mathrm{M})\,|\,\mathrm{Cu}(s)Pt∣H2​(g)∣H+(aq)∣∣Cu2+(0.01M)∣Cu(s) is 0.576 V at 298 K. The pH of the solution is ___. (Nearest integer)

Correct answer: 5

Step-by-step solution →
Q54·ChemistryNumerical
The rate constants for decomposition of acetaldehyde have been measured over the temperature range 700–1000 K. The data has been analysed by plotting In k vs 103T\dfrac{10^{3}}{T}T103​ graph. The value of activation energy for the reaction is ____ kJ mol−1^{-1}−1. (Nearest integer) (Given : R = 8.31 J K−1^{-1}−1 mol−1^{-1}−1)

Correct answer: 154

Step-by-step solution →
Q55·ChemistryNumerical
The difference in oxidation state of chromium in chromate and dichromate salts is ________

Correct answer: 0

Step-by-step solution →
Q56·ChemistryNumerical
In the cobalt-carbonyl complex: [Co2_22​(CO)8_88​], number of Co-Co bonds is "X" and terminal CO ligands is "Y". X + Y =_____

Correct answer: 7

Step-by-step solution →
Q57·Chemistry·Reaction MechanismNumerical
Number of electrophilic centre in the given compound is ____

Correct answer: 3

Step-by-step solution →
Q58·ChemistryNumerical
The major product 'A' of the following given reaction has _____ sp2^22 hybridized carbon atoms. 2,7 - Dimethyl1 - 2, 6 - octadiene →H+\xrightarrow{\text{H}^+}H+​ A (Mojor Product)

Correct answer: 2

Step-by-step solution →

Mathematics — JEE Main 24 June 2022 Shift 1

Q59·MathematicsSingle correct
Let A={z∈C:1≤∣z−(1+i)∣≤2}A=\{z\in\mathbb{C}:1\le |z-(1+i)|\le 2\}A={z∈C:1≤∣z−(1+i)∣≤2} and B={z∈A:∣z−(1−i)∣=1}B=\{z\in A:|z-(1-i)|=1\}B={z∈A:∣z−(1−i)∣=1}. Then, B :
  1. (A)is an empty set
  2. (B)contains exactly two elements
  3. (C)contains exactly three elements
  4. (D)is an infinite set

Correct answer: (D)

Step-by-step solution →
Q60·MathematicsSingle correct
The remainder when 320223^{2022}32022 is divided by 5 is
  1. (A)1
  2. (B)2
  3. (C)3
  4. (D)4

Correct answer: (D)

Step-by-step solution →
Q61·MathematicsSingle correct
The surface area of a balloon of spherical shape being inflated, increases at a constant rate. If initially, the radius of balloon is 3 units and after 5 seconds,, it becomes 7 units, then its radius after 9 seconds is :
  1. (A)9
  2. (B)10
  3. (C)11
  4. (D)12

Correct answer: (A)

Step-by-step solution →
Q62·MathematicsSingle correct
Bag A contains 2 white, 1 black and 3 red balls and bag B contains 3 black, 2 red and n white balls. One bag is chosen at random and 2 balls drawn from it at random, are found to be 1 red and 1 black. If the probability that both balls come from Bag A is 611\dfrac{6}{11}116​, then n is equal to ______ .
  1. (A)13
  2. (B)6
  3. (C)4
  4. (D)3

Correct answer: (C)

Step-by-step solution →
Q63·MathematicsSingle correct
Let x2+y2+Ax+By+C=0x^2 + y^2 + Ax + By + C = 0x2+y2+Ax+By+C=0 be a circle passing through (0,6)(0, 6)(0,6) and touching the parabola y=x2y = x^2y=x2 at (2,4)(2, 4)(2,4). Then A+CA + CA+C is equal to_______ .
  1. (A)16
  2. (B)88/5
  3. (C)72
  4. (D)−8-8−8

Correct answer: (A)

Step-by-step solution →
Q64·MathematicsSingle correct
The number of values of α\alphaα for which the system of equations : x+y+z=αx + y + z = \alphax+y+z=α αx+2αy+3z=−1\alpha x + 2\alpha y + 3z = -1αx+2αy+3z=−1 x+3αy+5z=4x + 3\alpha y + 5z = 4x+3αy+5z=4 is inconsistent, is
  1. (A)0
  2. (B)1
  3. (C)2
  4. (D)3

Correct answer: (B)

Step-by-step solution →
Q65·MathematicsSingle correct
If the sum of the squares of the reciprocals of the roots α\alphaα and β\betaβ of the equation 3x2+λx−1=03x^{2}+\lambda x-1=03x2+λx−1=0 is 15, then 6(α3+β3)26(\alpha^{3}+\beta^{3})^{2}6(α3+β3)2 is equal to :
  1. (A)18
  2. (B)24
  3. (C)36
  4. (D)96

Correct answer: (B)

Step-by-step solution →
Q66·MathematicsSingle correct
The set of all values of k for which (tan⁡−1x)3+(cot⁡−1x)3=kπ3(\tan^{-1}x)^{3}+(\cot^{-1}x)^{3}=k\pi^{3}(tan−1x)3+(cot−1x)3=kπ3, x∈Rx\in Rx∈R, is the interval :
  1. (A)[132,78)\left[\dfrac{1}{32},\dfrac{7}{8}\right)[321​,87​)
  2. (B)(124,1316)\left(\dfrac{1}{24},\dfrac{13}{16}\right)(241​,1613​)
  3. (C)[148,1316]\left[\dfrac{1}{48},\dfrac{13}{16}\right][481​,1613​]
  4. (D)[132,98)\left[\dfrac{1}{32},\dfrac{9}{8}\right)[321​,89​)

Correct answer: (A)

Step-by-step solution →
Q67·MathematicsSingle correct
Let S={n:1≤n≤50 and n is odd}S=\{\sqrt{n}:1\le n\le 50\ \text{and n is odd}\}S={n​:1≤n≤50 and n is odd}. Let a∈Sa\in Sa∈S and A=[10a−110−a01]A=\begin{bmatrix}1&0&a\\-1&1&0\\-a&0&1\end{bmatrix}A=​1−1−a​010​a01​​. If ∑a∈Sdet⁡(adjA)=100λ\sum_{a\in S}\det(\mathrm{adj}A)=100\lambda∑a∈S​det(adjA)=100λ, then λ\lambdaλ is equal to
  1. (A)218
  2. (B)221
  3. (C)663
  4. (D)1717

Correct answer: (B)

Step-by-step solution →
Q68·MathematicsSingle correct
f(x)=4log⁡e(x−1)−2x2+4x+5f(x)=4\log_e(x-1)-2x^{2}+4x+5f(x)=4loge​(x−1)−2x2+4x+5, x>1x>1x>1, which one of the following is NOT correct ?
  1. (A)f is increasing in (1,2)(1,2)(1,2) and decreasing in (2,∞)(2,\infty)(2,∞)
  2. (B)f(x)=−1f(x)=-1f(x)=−1 has exactly two solutions
  3. (C)f′(e)−f′′(2)<0f'(e)-f''(2)<0f′(e)−f′′(2)<0
  4. (D)f(x)=0f(x)=0f(x)=0 has a root in the interval (e,e+1)(e,e+1)(e,e+1)

Correct answer: (C)

Step-by-step solution →
Q69·MathematicsSingle correct
the tangent at the point (x1, y1)(x_{1},\ y_{1})(x1​, y1​) on the curve y=x3+3x2+5y=x^{3}+3x^{2}+5y=x3+3x2+5 passes through the origin, then (x1,y1)(x_{1},y_{1})(x1​,y1​) does NOT lie on the curve :
  1. (A)x2+y281=2x^{2}+\dfrac{y^{2}}{81}=2x2+81y2​=2
  2. (B)y29−x2=8\dfrac{y^{2}}{9}-x^{2}=89y2​−x2=8
  3. (C)y=4x2+5y=4x^{2}+5y=4x2+5
  4. (D)x3−y2=2\dfrac{x}{3}-y^{2}=23x​−y2=2

Correct answer: (D)

Step-by-step solution →
Q70·MathematicsSingle correct
The sum of absolute maximum and absolute minimum values of the function f(x)=∣2x2+3x−2∣+sin⁡xcos⁡xf(x)=|2x^{2}+3x-2|+\sin x\cos xf(x)=∣2x2+3x−2∣+sinxcosx in the interval [0,1][0,1][0,1] is :
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (B)

Step-by-step solution →
Q71·MathematicsSingle correct
If {ai}i=1n\{a_i\}_{i=1}^{n}{ai​}i=1n​ where n is an even integer , is an arithmetic progression with common difference 1, and ∑i=1nai=192\sum_{i=1}^{n} a_i = 192∑i=1n​ai​=192, ∑i=1n/2a2i=120\sum_{i=1}^{n/2} a_{2i} = 120∑i=1n/2​a2i​=120, then n is equal to:
  1. (A)48
  2. (B)96
  3. (C)92
  4. (D)104

Correct answer: (B)

Step-by-step solution →
Q72·MathematicsSingle correct
If x=x(y)x=x(y)x=x(y) is the solution of the differential equation ydxdy=2x+y3(y+1)eyy\dfrac{dx}{dy}=2x+y^{3}(y+1)e^{y}ydydx​=2x+y3(y+1)ey, x(1)=0x(1)=0x(1)=0 ; then x(e)x(e)x(e) is equal to :
  1. (A)e3(ee−1)e^{3}(e^{e}-1)e3(ee−1)
  2. (B)ee(e3−1)e^{e}(e^{3}-1)ee(e3−1)
  3. (C)e2(ee+1)e^{2}(e^{e}+1)e2(ee+1)
  4. (D)ee(e2−1)e^{e}(e^{2}-1)ee(e2−1)

Correct answer: (A)

Step-by-step solution →
Q73·MathematicsSingle correct
Let λx−2y=μ\lambda x-2y=\muλx−2y=μ be a tangent to the hyperbola a2x2−y2=b2a^{2}x^{2}-y^{2}=b^{2}a2x2−y2=b2. Then (λa)2−(μb)2\left(\dfrac{\lambda}{a}\right)^{2}-\left(\dfrac{\mu}{b}\right)^{2}(aλ​)2−(bμ​)2 is equal to:
  1. (A)−2-2−2
  2. (B)−4-4−4
  3. (C)2
  4. (D)4

Correct answer: (D)

Step-by-step solution →
Q74·MathematicsSingle correct
Let a^,b^\hat{a},\hat{b}a^,b^ be unit vectors. If c⃗\vec{c}c be a vector such that the angle between a^\hat{a}a^ and c⃗\vec{c}c is π12\dfrac{\pi}{12}12π​, and b^=c⃗+2(c⃗×a^)\hat{b}=\vec{c}+2(\vec{c}\times\hat{a})b^=c+2(c×a^), then ∣6c⃗∣2\left|6\vec{c}\right|^{2}∣6c∣2 is equal to
  1. (A)6(3−3)6(3-\sqrt{3})6(3−3​)
  2. (B)3+33+\sqrt{3}3+3​
  3. (C)6(3+3)6(3+\sqrt{3})6(3+3​)
  4. (D)6(3+1)6(\sqrt{3}+1)6(3​+1)

Correct answer: (C)

Step-by-step solution →
Q75·MathematicsSingle correct
If a random variable X follows the Binomial distribution B (33, p) such that 3P(X=0)=P(X=1)3P(X=0)=P(X=1)3P(X=0)=P(X=1), then the value of P(X=15)P(X=18)−P(X=16)P(X=17)\dfrac{P(X=15)}{P(X=18)}-\dfrac{P(X=16)}{P(X=17)}P(X=18)P(X=15)​−P(X=17)P(X=16)​ is equal to
  1. (A)1320
  2. (B)1088
  3. (C)1201331\dfrac{120}{1331}1331120​
  4. (D)10881089\dfrac{1088}{1089}10891088​

Correct answer: (A)

Step-by-step solution →
Q76·MathematicsSingle correct
The domain of the function f(x)=cos⁡−1(x2−5x+6x2−9)log⁡e(x2−3x+2)f(x)=\dfrac{\cos^{-1}\left(\dfrac{x^{2}-5x+6}{x^{2}-9}\right)}{\log_{e}(x^{2}-3x+2)}f(x)=loge​(x2−3x+2)cos−1(x2−9x2−5x+6​)​ is
  1. (A)(−∞,1)∪(2,∞)(-\infty,1)\cup(2,\infty)(−∞,1)∪(2,∞)
  2. (B)(2,∞)(2,\infty)(2,∞)
  3. (C)[−12,1)∪(2,∞)\left[-\dfrac{1}{2},1\right)\cup(2,\infty)[−21​,1)∪(2,∞)
  4. (D)[−12,1)∪(2,∞)−{3+52,3−52}\left[-\dfrac{1}{2},1\right)\cup(2,\infty)-\left\{\dfrac{3+\sqrt{5}}{2},\dfrac{3-\sqrt{5}}{2}\right\}[−21​,1)∪(2,∞)−{23+5​​,23−5​​}

Correct answer: (D)

Step-by-step solution →
Q77·MathematicsSingle correct
Let S={θ∈[−π,π]−{±π2}:sin⁡θtan⁡θ+tan⁡θ=sin⁡2θ}S=\left\{\theta\in[-\pi,\pi]-\left\{\pm\dfrac{\pi}{2}\right\}:\sin\theta\tan\theta+\tan\theta=\sin 2\theta\right\}S={θ∈[−π,π]−{±2π​}:sinθtanθ+tanθ=sin2θ}. If T=∑θ∈Scos⁡2θT=\displaystyle\sum_{\theta\in S}\cos 2\thetaT=θ∈S∑​cos2θ, then T+n(S)T+n(S)T+n(S) is equal
  1. (A)7+37+\sqrt{3}7+3​
  2. (B)999
  3. (C)8+38+\sqrt{3}8+3​
  4. (D)101010

Correct answer: (B)

Step-by-step solution →
Q78·MathematicsSingle correct
The number of choices of Δ∈{∧,∨,⇒,⇔}\Delta\in\{\wedge,\vee,\Rightarrow,\Leftrightarrow\}Δ∈{∧,∨,⇒,⇔}, such that (pΔq)⇒((pΔ∼q)∨((∼p)Δq))(p\Delta q)\Rightarrow((p\Delta\sim q)\vee((\sim p)\Delta q))(pΔq)⇒((pΔ∼q)∨((∼p)Δq)) is a tautology, is
  1. (A)1
  2. (B)2
  3. (C)3
  4. (D)4

Correct answer: (B)

Step-by-step solution →
Q79·MathematicsNumerical
The number of one-one function f:{a,b,c,d}→{0,1,2,…,10}f:\{a,b,c,d\}\to\{0,1,2,\ldots,10\}f:{a,b,c,d}→{0,1,2,…,10} such that 2f(a)−f(b)+3f(c)+f(d)=02f(a)-f(b)+3f(c)+f(d)=02f(a)−f(b)+3f(c)+f(d)=0 is ______ .

Correct answer: 31

Step-by-step solution →
Q80·MathematicsNumerical
Let A(3a,a)A\left(\dfrac{3}{\sqrt{a}},\sqrt{a}\right)A(a​3​,a​) a>0a > 0a>0, be a fixed point in the xy-plane. The image of A in y-axis be B and the image of B in x-axis be C. If D(3 cos θ\thetaθ, a sin θ\thetaθ) is a point in the fourth quadrant such that the maximum area of △ACD\triangle ACD△ACD is 12 square units, then a is equal to ________ .

Correct answer: 8

Step-by-step solution →
Q81·MathematicsNumerical
Let a line having direction ratios 1, -4, 2 intersect the lines x−73=y−1−1=z+21\dfrac{x-7}{3}=\dfrac{y-1}{-1}=\dfrac{z+2}{1}3x−7​=−1y−1​=1z+2​ and x2=y−73=z1\dfrac{x}{2}=\dfrac{y-7}{3}=\dfrac{z}{1}2x​=3y−7​=1z​ at the point A and B. Then (AB)2(AB)^{2}(AB)2 is equal to ____ .

Correct answer: 84

Step-by-step solution →
Q82·Mathematics·Limits and ContinuityNumerical
The number of points where the function f(x)={∣2x2−3x−7∣if x≤−1[4x2−1]if −1<x<1∣x+1∣+∣x−2∣if x≥1f(x)=\begin{cases}|2x^{2}-3x-7| & \text{if } x\le -1\\ [4x^{2}-1] & \text{if } -1<x<1\\ |x+1|+|x-2| & \text{if } x\ge 1\end{cases}f(x)=⎩⎨⎧​∣2x2−3x−7∣[4x2−1]∣x+1∣+∣x−2∣​if x≤−1if −1<x<1if x≥1​ [t][t][t] denotes the greatest integer ≤t\le t≤t, is discontinuous is ______ .

Correct answer: 7

Step-by-step solution →
Q83·MathematicsNumerical
Let f(θ)=sin⁡θ+∫−π/2π/2(sin⁡θ+tcos⁡θ)f(t)dtf(\theta)=\sin\theta+\int_{-\pi/2}^{\pi/2}(\sin\theta+t\cos\theta)f(t)dtf(θ)=sinθ+∫−π/2π/2​(sinθ+tcosθ)f(t)dt. Then the value of ∣∫0π/2f(θ)dθ∣\left|\int_{0}^{\pi/2} f(\theta)d\theta\right|​∫0π/2​f(θ)dθ​ is ______ .

Correct answer: 1

Step-by-step solution →
Q84·MathematicsNumerical
Let Max0≤x≤2{9−x25−x}=α\underset{0\le x\le 2}{\mathrm{Max}}\left\{\dfrac{9-x^{2}}{5-x}\right\}=\alpha0≤x≤2Max​{5−x9−x2​}=α and Min0≤x≤2{9−x25−x}=β\underset{0\le x\le 2}{\mathrm{Min}}\left\{\dfrac{9-x^{2}}{5-x}\right\}=\beta0≤x≤2Min​{5−x9−x2​}=β If ∫β−832α−1Max{9−x25−x,x}dx=α1+α2log⁡e(815)\displaystyle\int_{\beta-\frac{8}{3}}^{2\alpha-1}\mathrm{Max}\left\{\dfrac{9-x^{2}}{5-x},x\right\}dx=\alpha_{1}+\alpha_{2}\log_{e}\left(\dfrac{8}{15}\right)∫β−38​2α−1​Max{5−x9−x2​,x}dx=α1​+α2​loge​(158​) then α1+α2\alpha_{1}+\alpha_{2}α1​+α2​ is equal to _______

Correct answer: 34

Step-by-step solution →
Q85·MathematicsNumerical
If two tangents drawn from a point (α,β)(\alpha,\beta)(α,β) lying on the ellipse 25x2+4y2=125x^{2}+4y^{2}=125x2+4y2=1 to the parabola y2=4xy^{2}=4xy2=4x are such that the slope of one tangent is four times the other, then the value of (10α+5)2+(16β2+50)2\left(10\alpha+5\right)^{2}+\left(16\beta^{2}+50\right)^{2}(10α+5)2+(16β2+50)2 equals ______

Correct answer: 2929

Step-by-step solution →
Q86·MathematicsNumerical
Let S be the region bounded by the curves y=x3y=x^{3}y=x3 and y2=xy^{2}=xy2=x. The curve y=2∣x∣y=2|x|y=2∣x∣ divides S into two regions of areas R1R_{1}R1​ and R2R_{2}R2​. If max {R1,R2}=R2\{R_{1},R_{2}\}=R_{2}{R1​,R2​}=R2​, then R2R1\dfrac{R_{2}}{R_{1}}R1​R2​​ is equal to ____ .

Correct answer: 19

Step-by-step solution →
Q87·MathematicsNumerical
If the shortest distance between the line r⃗=(−i^+3k)+λ(i^−aj^)\vec{r} = \left(-\hat{i} + 3k\right) + \lambda\left(\hat{i} - a\hat{j}\right)r=(−i^+3k)+λ(i^−aj^​) and r⃗=(−j^+2k)+μ(i^−j^+k)\vec{r} = \left(-\hat{j} + 2k\right) + \mu\left(\hat{i} - \hat{j} + k\right)r=(−j^​+2k)+μ(i^−j^​+k) is 23\sqrt{\dfrac{2}{3}}32​​, then the integral value of a is equal to

Correct answer: 2

Step-by-step solution →

Chapters tested in this paper

Open any chapter to practise every past-year question on that topic across all papers, and see how often it has actually appeared.

  • Properties of Solids and Liquids 172/186
  • Three Dimensional Geometry 176/186
  • Matrices and Determinants 180/186
  • Coordination Compounds 176/186
  • Sets, Relations and Functions 165/186
  • Current Electricity 160/186
  • Sequence and Series 164/186
  • p-Block Elements 164/186
  • Definite Integration 168/186
  • Rotational Motion 172/186
  • Redox Reactions and Electrochemistry 177/186
  • Geometrical Optics 172/186
  • Kinematics 156/186
  • Vector Algebra 173/186
  • Differential Equations 167/186
  • Probability 176/186
  • Permutations and Combinations 162/186
  • Magnetic Field of Current 147/186
  • Binomial Theorem and Its Simple Applications 158/186
  • Electromagnetic Waves 144/186
  • Chemical Bonding and Molecular Structure 151/186
  • Application of Derivatives 139/186
  • Limits and Continuity 149/186
  • d- and f-Block Elements 126/186
  • Thermodynamics 154/186
  • Aldehydes and Ketones 135/186
  • Equilibrium 163/186
  • Solutions 158/186
  • Laws of Motion 130/186
  • Chemical Thermodynamics 165/186
  • Units and Measurements 149/186
  • Hydrocarbons 126/186
  • Complex Numbers 165/186
  • Trigonometric Functions 144/186
  • Biomolecules 162/186
  • Chemical Kinetics 169/186
  • Gravitation 152/186
  • Electric Field and Coulomb's Law 133/186
  • Atomic Structure 161/186
  • Electronic Devices 145/186
  • Circles 142/186
  • Dual Nature of Matter and Radiation 155/186
  • Amines 133/186
  • Quadratic Equations 148/186
  • Work, Energy and Power 132/186
  • Some Basic Concepts in Chemistry 129/186
  • Wave Optics 130/186
  • Area Under Curves 139/186
  • Kinetic Theory of Gases 135/186
  • Alternating Currents 108/186
  • Nuclei 116/186
  • Straight Lines 114/186
  • Waves 109/186
  • Capacitors and Dielectrics 115/186
  • Atoms 112/186
  • Classification of Elements and Periodicity in Properties 113/186
  • Parabola 101/186
  • Isolation of Metals 106/186
  • Surface Chemistry 98/186
  • Inverse Trigonometric Functions 93/186
  • Hydrogen 81/186
  • Hyperbola 77/186
  • Polymers 64/186
  • Carboxylic Acids and Derivatives 54/186
  • Solid State 63/186
  • Principles of Qualitative Analysis 58/186
  • Chemistry in Everyday Life 60/186
  • Reaction Mechanism 29/186
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