Jarvis OS
PYQ papersPricingSign inGet started
  1. Home
  2. /JEE Main PYQs
  3. /2023
  4. /24 Jan Shift 2

JEE Main 24 January 2023 Shift 2 Question Paper with Answers

24 January 2023 · January session · 90 questions

The complete JEE Main 24 January 2023 Shift 2 paper — all 90 questions with the correct answer for each, tagged to the chapter it tests. Free to read, no account needed.

Physics
30
Chemistry
30
Mathematics
30

Physics — JEE Main 24 January 2023 Shift 2

Q1·PhysicsSingle correct
Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R. Assertion A: A pendulum clock when taken to Mount Everest becomes fast. Reason R: The value of ggg (acceleration due to gravity) is less at Mount Everest than on the surface of earth. In the light of the above statements, choose the most appropriate answer from the options given below
  1. (A)Both A and R are correct and R is the correct explanation of A
  2. (B)A is correct but R is not correct
  3. (C)Both A and R are correct but R is NOT the correct explanation of A
  4. (D)A is not correct but R is correct

Correct answer: (D)

Step-by-step solution →
Q2·PhysicsSingle correct
The frequency (ν)(\nu)(ν) of an oscillating liquid drop may depend upon radius (r)(r)(r) of the drop, density (ρ)(\rho)(ρ) of liquid and the surface tension (s)(s)(s) of the liquid as: ν=raρbsc\nu=r^a\rho^b s^cν=raρbsc. The values of aaa, bbb and ccc respectively are
  1. (A)(−32,12,12)\left(-\dfrac32,\dfrac12,\dfrac12\right)(−23​,21​,21​)
  2. (B)(32,−12,12)\left(\dfrac32,-\dfrac12,\dfrac12\right)(23​,−21​,21​)
  3. (C)(−32,−12,12)\left(-\dfrac32,-\dfrac12,\dfrac12\right)(−23​,−21​,21​)
  4. (D)(32,12,−12)\left(\dfrac32,\dfrac12,-\dfrac12\right)(23​,21​,−21​)

Correct answer: (C)

Step-by-step solution →
Q3·PhysicsSingle correct
Given below are two statements: Statement I: Acceleration due to earth's gravity decreases as you go 'up' or 'down' from earth's surface. Statement II: Acceleration due to earth's gravity is same at a height hhh and depth ddd from earth's surface, if h=dh=dh=d. In the light of above statements, choose the most appropriate answer from the options given below
  1. (A)Both Statement I and Statement II are incorrect
  2. (B)Statement I is incorrect but statement II is correct
  3. (C)Both Statement I and Statement II are correct
  4. (D)Statement I is correct but statement II is incorrect

Correct answer: (D)

Step-by-step solution →
Q4·Physics·Magnetic Field of CurrentSingle correct
A long solenoid is formed by winding 707070 turns cm−1cm^{-1}cm−1. If 2.02.02.0 A current flows, then the magnetic field produced inside the solenoid is _________ (μ0=4π×10−7 T m A−1)(\mu_0=4\pi\times10^{-7}\,T\,m\,A^{-1})(μ0​=4π×10−7TmA−1)
  1. (A)88×10−488\times10^{-4}88×10−4 T
  2. (B)352×10−4352\times10^{-4}352×10−4 T
  3. (C)176×10−4176\times10^{-4}176×10−4 T
  4. (D)1232×10−41232\times10^{-4}1232×10−4 T

Correct answer: (C)

Step-by-step solution →
Q5·Physics·Electric PotentialSingle correct
The electric potential at the centre of two concentric half rings of radii R1R_1R1​ and R2R_2R2​, having same linear charge density λ\lambdaλ is:
  1. (A)λ2ε0\dfrac{\lambda}{2\varepsilon_0}2ε0​λ​
  2. (B)λ4ε0\dfrac{\lambda}{4\varepsilon_0}4ε0​λ​
  3. (C)2λε0\dfrac{2\lambda}{\varepsilon_0}ε0​2λ​
  4. (D)λε0\dfrac{\lambda}{\varepsilon_0}ε0​λ​

Correct answer: (A)

Step-by-step solution →
Q6·PhysicsSingle correct
If the distance of the earth from Sun is 1.5×1061.5\times10^61.5×106 km, then the distance of an imaginary planet from Sun, if its period of revolution is 2.832.832.83 years is:
  1. (A)6×1066\times10^66×106 km
  2. (B)3×1063\times10^63×106 km
  3. (C)3×1073\times10^73×107 km
  4. (D)6×1076\times10^76×107 km

Correct answer: (B)

Step-by-step solution →
Q7·PhysicsSingle correct
A photon is emitted in transition from n=4n=4n=4 to n=1n=1n=1 level in hydrogen atom. The corresponding wavelength for this transition is (given, h=4×10−15h=4\times10^{-15}h=4×10−15 eVs):
  1. (A)99.399.399.3 nm
  2. (B)941941941 nm
  3. (C)974974974 nm
  4. (D)94.194.194.1 nm

Correct answer: (D)

Step-by-step solution →
Q8·PhysicsSingle correct
A cell of emf 909090 V is connected across series combination of two resistors each of 100 Ω100\,\Omega100Ω resistance. A voltmeter of resistance 400 Ω400\,\Omega400Ω is used to measure the potential difference across each resistor. The reading of the voltmeter will be:
  1. (A)909090 V
  2. (B)454545 V
  3. (C)808080 V
  4. (D)404040 V

Correct answer: (B)

Step-by-step solution →
Q9·PhysicsSingle correct
If two vectors P⃗=i^+2mj^+mk^\vec P=\hat i+2m\hat j+m\hat kP=i^+2mj^​+mk^ and Q⃗=4i^−2j^+mk^\vec Q=4\hat i-2\hat j+m\hat kQ​=4i^−2j^​+mk^ are perpendicular to each other, then the value of mmm will be:
  1. (A)−1-1−1
  2. (B)333
  3. (C)222
  4. (D)111

Correct answer: (C)

Step-by-step solution →
Q10·PhysicsSingle correct
The electric field and magnetic field components of an electromagnetic wave going through vacuum is described by Ex=E0sin⁡(kz−ωt)E_x=E_0\sin(kz-\omega t)Ex​=E0​sin(kz−ωt) and By=B0sin⁡(kz−ωt)B_y=B_0\sin(kz-\omega t)By​=B0​sin(kz−ωt). Then the correct relation between E0E_0E0​ and B0B_0B0​ is given by
  1. (A)E0B0=ωkE_0 B_0=\omega kE0​B0​=ωk
  2. (B)E0B0=ωkE_0 B_0=\dfrac{\omega}{k}E0​B0​=kω​
  3. (C)kE0=ωB0kE_0=\omega B_0kE0​=ωB0​
  4. (D)ωE0=kB0\omega E_0=kB_0ωE0​=kB0​

Correct answer: (C)

Step-by-step solution →
Q11·PhysicsSingle correct
The logic gate equivalent to the given circuit diagram is:
  1. (A)NAND
  2. (B)OR
  3. (C)AND
  4. (D)NOR

Correct answer: (A)

Step-by-step solution →
Q12·PhysicsSingle correct
Let γ1\gamma_1γ1​ be the ratio of molar specific heat at constant pressure and molar specific heat at constant volume of a monoatomic gas and γ2\gamma_2γ2​ be the similar ratio of diatomic gas. Considering the diatomic gas molecule as a rigid rotator, the ratio γ1γ2\dfrac{\gamma_1}{\gamma_2}γ2​γ1​​ is:
  1. (A)2521\dfrac{25}{21}2125​
  2. (B)2527\dfrac{25}{27}2725​
  3. (C)2125\dfrac{21}{25}2521​
  4. (D)2735\dfrac{27}{35}3527​

Correct answer: (A)

Step-by-step solution →
Q13·Physics·Geometrical OpticsSingle correct
When a beam of white light is allowed to pass through convex lens parallel to principal axis, the different colours of light converge at different point on the principle axis after refraction. This is called:
  1. (A)Spherical aberration
  2. (B)Polarisation
  3. (C)Chromatic aberration
  4. (D)Scattering

Correct answer: (C)

Step-by-step solution →
Q14·Physics·Electromagnetic InductionSingle correct
A metallic rod of length 'LLL' is rotated with an angular speed of 'ω\omegaω' normal to a uniform magnetic field 'BBB' about an axis passing through one end of rod as shown in figure. The induced emf will be:
  1. (A)14BL2ω\dfrac14 BL^2\omega41​BL2ω
  2. (B)12B2L2ω\dfrac12 B^2 L^2\omega21​B2L2ω
  3. (C)14B2Lω\dfrac14 B^2 L\omega41​B2Lω
  4. (D)12BL2ω\dfrac12 BL^2\omega21​BL2ω

Correct answer: (D)

Step-by-step solution →
Q15·PhysicsSingle correct
An α\alphaα-particle, a proton and an electron have the same kinetic energy. Which one of the following is correct in case of their de-Broglie wavelength:
  1. (A)λα<λp<λe\lambda_\alpha<\lambda_p<\lambda_eλα​<λp​<λe​
  2. (B)λα=λp=λe\lambda_\alpha=\lambda_p=\lambda_eλα​=λp​=λe​
  3. (C)λα>λp>λe\lambda_\alpha>\lambda_p>\lambda_eλα​>λp​>λe​
  4. (D)λα>λp<λe\lambda_\alpha>\lambda_p<\lambda_eλα​>λp​<λe​

Correct answer: (A)

Step-by-step solution →
Q16·PhysicsSingle correct
Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R. Assertion A: Steel is used in the construction of buildings and bridges. Reason R: Steel is most elastic and its elastic limit is high. In the light of above statements, choose the most appropriate answer from the options given below
  1. (A)Both A and R are correct and R is the correct explanation of A
  2. (B)Both A and R are correct but R is NOT the correct explanation of A
  3. (C)A is correct but R is not correct
  4. (D)A is not correct but R is correct

Correct answer: (A)

Step-by-step solution →
Q17·PhysicsSingle correct
In an Isothermal change, the change in pressure and volume of a gas can be represented for three different temperature; T3>T2>T1T_3>T_2>T_1T3​>T2​>T1​ as:
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (C)

Step-by-step solution →
Q18·PhysicsSingle correct
Match List I (broadcast / communication service) with List II (frequency band). Choose the correct answer from the options given below:
List IList II
A.AM BroadcastI.88–108 MHz
B.FM BroadcastII.540–1600 kHz
C.TelevisionIII.3.7–4.2 GHz
D.Satellite CommunicationIV.54 MHz–890 MHz
  1. (A)A-II, B-I, C-IV, D-III
  2. (B)A-I, B-III, C-II, D-IV
  3. (C)A-IV, B-III, C-I, D-II
  4. (D)A-III, B-III, C-I, D-IV

Correct answer: (A)

Step-by-step solution →
Q19·PhysicsSingle correct
A body of mass 200200200 g is tied to a spring of spring constant 12.512.512.5 N/m, while the other end of spring is fixed at point OOO. If the body moves about OOO in a circular path on a smooth horizontal surface with constant angular speed 555 rad/s, then the ratio of extension in the spring to its natural length will be:
  1. (A)2:52:52:5
  2. (B)1:11:11:1
  3. (C)2:32:32:3
  4. (D)1:21:21:2

Correct answer: (C)

Step-by-step solution →
Q20·PhysicsSingle correct
The velocity time graph of a body moving in a straight line is shown in figure. The ratio of displacement to distance travelled by the body in time 000 to 101010 s is:
  1. (A)1:11:11:1
  2. (B)1:21:21:2
  3. (C)1:31:31:3
  4. (D)1:41:41:4

Correct answer: (C)

Step-by-step solution →
Q21·PhysicsNumerical
A body of mass 111 kg begins to move under the action of a time dependent force F⃗=(ti^+3t2j^)\vec F=(t\hat i+3t^2\hat j)F=(ti^+3t2j^​) N, where i^\hat ii^ and j^\hat jj^​ are the unit vectors along xxx and yyy axis. The power developed by above force, at the time t=2t=2t=2 s, will be _________ W.

Correct answer: 100

Step-by-step solution →
Q22·Physics·Geometrical OpticsNumerical
A convex lens of refractive index 1.51.51.5 and focal length 181818 cm in air is immersed in water. The change in focal length of the lens will be _________ cm. (Given refractive index of water =43=\dfrac43=34​)

Correct answer: 54

Step-by-step solution →
Q23·PhysicsNumerical
The energy released per fission of nucleus of 240X^{240}X240X is 200200200 MeV. The energy released if all the atoms in 120120120 g of pure 240X^{240}X240X undergo fission is _________ ×1025\times10^{25}×1025 MeV (Given NA=6×1023N_A=6\times10^{23}NA​=6×1023)

Correct answer: 6

Step-by-step solution →
Q24·PhysicsNumerical
A uniform solid cylinder with radius RRR and length LLL has moment of inertia I1I_1I1​ about the axis of the cylinder. A concentric solid cylinder of radius R′=R2R'=\dfrac{R}{2}R′=2R​ and length L′=L2L'=\dfrac{L}{2}L′=2L​ is carved out of the original cylinder. If I2I_2I2​ is the moment of inertia of the carved out portion of the cylinder then I1I2=\dfrac{I_1}{I_2}=I2​I1​​= _________ (Both I1I_1I1​ and I2I_2I2​ are about the axis of the cylinder)

Correct answer: 32

Step-by-step solution →
Q25·Physics·Capacitors and DielectricsNumerical
A parallel plate capacitor with air between the plate has a capacitance of 151515 pF. The separation between the plate becomes twice and the space between them is filled with a medium of dielectric constant 3.53.53.5. Then the capacitance becomes x4\dfrac{x}{4}4x​ pF. The value of xxx is _________

Correct answer: 105

Step-by-step solution →
Q26·Physics·Magnetic Field of CurrentNumerical
A single turn current loop in the shape of a right angle triangle with sides 555 cm, 121212 cm, 131313 cm is carrying a current of 222 A. The loop is in a uniform magnetic field of magnitude 0.750.750.75 T whose direction is parallel to the current in the 131313 cm side of the loop. The magnitude of the magnetic force on the 555 cm side will be x130\dfrac{x}{130}130x​ N. The value of xxx is _________

Correct answer: 9

Step-by-step solution →
Q27·Physics·OscillationsNumerical
A mass mmm attached to free end of a spring executes SHM with a period of 111 s. If the mass is increased by 333 kg the period of oscillation increases by one second, the value of mass mmm is _________ kg.

Correct answer: 1

Step-by-step solution →
Q28·PhysicsNumerical
If a copper wire is stretched to increase its length by 20%20\%20%, the percentage increase in resistance of the wire is _________ %

Correct answer: 44

Step-by-step solution →
Q29·Physics·Electromagnetic InductionNumerical
Three identical resistors with resistance R=12 ΩR=12\,\OmegaR=12Ω and two identical inductors with self inductance L=5L=5L=5 mH are connected to an ideal battery with emf of 121212 V as shown in figure. The current through the battery long after the switch has been closed will be _________ A.

Correct answer: 3

Step-by-step solution →
Q30·PhysicsNumerical
A spherical ball of radius 111 mm and density 10.510.510.5 g/cc is dropped in glycerine of coefficient of viscosity 9.89.89.8 poise and density 1.51.51.5 g/cc. Viscous force on the ball when it attains constant velocity is 3696×10−x3696\times10^{-x}3696×10−x N. The value of xxx is _________ (Given, g=9.8g=9.8g=9.8 m/s2^22 and π=227\pi=\dfrac{22}{7}π=722​)

Correct answer: 7

Step-by-step solution →

Chemistry — JEE Main 24 January 2023 Shift 2

Q31·ChemistrySingle correct
Identify the correct statements about alkali metals. A. The order of standard reduction potential (M+∣M)(M^+|M)(M+∣M) for alkali metal ions is Na>Rb>LiNa>Rb>LiNa>Rb>Li. B. CsI is highly soluble in water. C. Lithium carbonate is highly stable to heat. D. Potassium dissolved in concentrated liquid ammonia is blue in colour and paramagnetic. E. All the alkali metal hydrides are ionic solids. Choose the correct answer from the options given below:
  1. (A)C and E only
  2. (B)A, B and E only
  3. (C)A, B, D only
  4. (D)A and E only

Correct answer: (D)

Step-by-step solution →
Q32·ChemistrySingle correct
Given below are two statements, one is labelled as Assertion A and the other is labelled as Reason R. Assertion A: Beryllium has less negative value of reduction potential compared to the other alkaline earth metals. Reason R: Beryllium has large hydration energy due to small size of Be2+Be^{2+}Be2+ but relatively large value of atomization enthalpy. In the light of the above statements, choose the most appropriate answer from the options given below
  1. (A)A is not correct but R is correct
  2. (B)A is correct but R is not correct
  3. (C)Both A and R are correct and R is the correct explanation of A
  4. (D)Both A and R are correct but R is NOT the correct explanation of A

Correct answer: (C)

Step-by-step solution →
Q33·ChemistrySingle correct
A student has studied the decomposition of a gas AB3AB_3AB3​ at 25 ∘C25\,^\circ C25∘C. He obtained the following data. ppp (mmHg): 505050, 100100100, 200200200, 400400400; relative t1/2t_{1/2}t1/2​ (s): 444, 222, 111, 0.50.50.5. The order of the reaction is
  1. (A)000 (zero)
  2. (B)0.50.50.5
  3. (C)111
  4. (D)222

Correct answer: (D)

Step-by-step solution →
Q34·ChemistrySingle correct
K2Cr2O7K_2Cr_2O_7K2​Cr2​O7​ paper acidified with dilute H2SO4H_2SO_4H2​SO4​ turns green when exposed to
  1. (A)Carbon dioxide
  2. (B)Sulphur trioxide
  3. (C)Sulphur dioxide
  4. (D)Hydrogen sulphide

Correct answer: (C)

Step-by-step solution →
Q35·Chemistry·Electronic Effects and StabilitySingle correct
Which will undergo deprotonation most readily in basic medium?
  1. (A)c only
  2. (B)a only
  3. (C)Both a and c
  4. (D)b only

Correct answer: (B)

Step-by-step solution →
Q36·ChemistrySingle correct
The hybridization and magnetic behaviour of cobalt ion in [Co(NH3)6]3+[Co(NH_3)_6]^{3+}[Co(NH3​)6​]3+ complex, respectively is
  1. (A)d2sp3d^2sp^3d2sp3 and paramagnetic
  2. (B)sp3d2sp^3d^2sp3d2 and diamagnetic
  3. (C)d2sp3d^2sp^3d2sp3 and diamagnetic
  4. (D)sp3d2sp^3d^2sp3d2 and paramagnetic

Correct answer: (C)

Step-by-step solution →
Q37·Chemistry·Aldehydes and KetonesSingle correct
Given below are two statements: Statement I: The given compound under Clemmensen reduction conditions will give the indicated product. Statement II: The given compound under Wolff-Kishner reduction condition will give the indicated product. In the light of the above statements, choose the correct answer from the options given below:
  1. (A)Statement I is false but Statement II is true
  2. (B)Statement I is true but Statement II is false
  3. (C)Both Statement I and Statement II are true
  4. (D)Both Statement I and Statement II are false

Correct answer: (B)

Step-by-step solution →
Q38·ChemistrySingle correct
Which of the following cannot be explained by crystal field theory?
  1. (A)The order of spectrochemical series
  2. (B)Stability of metal complexes
  3. (C)Magnetic properties of transition metal complexes
  4. (D)Colour of metal complexes

Correct answer: (A)

Step-by-step solution →
Q39·ChemistrySingle correct
The number of s-electrons present in an ion with 555555 protons in its unipositive state is
  1. (A)888
  2. (B)101010
  3. (C)999
  4. (D)121212

Correct answer: (B)

Step-by-step solution →
Q40·ChemistrySingle correct
Which one amongst the following are good oxidizing agents? (A) Sm2+Sm^{2+}Sm2+ (B) Ce2+Ce^{2+}Ce2+ (C) Ce4+Ce^{4+}Ce4+ (D) Tb4+Tb^{4+}Tb4+. Choose the most appropriate answer from the options given below:
  1. (A)D only
  2. (B)C only
  3. (C)C and D only
  4. (D)A and B only

Correct answer: (C)

Step-by-step solution →
Q41·ChemistrySingle correct
Choose the correct representation of conductometric titration of benzoic acid vs sodium hydroxide.
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (A)

Step-by-step solution →
Q42·ChemistrySingle correct
Match List I (type of drug) with List II (example medicine). Choose the correct answer from the options given below:
List IList II
A.Antifertility drugI.Norethindrone
B.TranquilizerII.Meprobomate
C.AntihistamineIII.Seldane
D.AntibioticIV.Ampicillin
  1. (A)A-I, B-III, C-II, D-IV
  2. (B)A-IV, B-III, C-II, D-I
  3. (C)A-I, B-II, C-III, D-IV
  4. (D)A-II, B-I, C-III, D-IV

Correct answer: (C)

Step-by-step solution →
Q43·ChemistrySingle correct
Find out the major products from the following reaction
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (B)

Step-by-step solution →
Q44·ChemistrySingle correct
Given below are two statements, one is labelled as Assertion A and the other is labelled as Reason R. Assertion A: Benzene is more stable than hypothetical cyclohexatriene. Reason R: The delocalized π\piπ electron cloud is attracted more strongly by nuclei of carbon atoms. In the light of the above statements, choose the correct answer from the options given below:
  1. (A)Both A and R are correct and R is the correct explanation of A
  2. (B)Both A and R are correct but R is NOT the correct explanation of A
  3. (C)A is false but R is true
  4. (D)A is true but R is false

Correct answer: (A)

Step-by-step solution →
Q45·ChemistrySingle correct
In which of the following reactions the hydrogen peroxide acts as a reducing agent?
  1. (A)PbS+4H2O2→PbSO4+4H2OPbS+4H_2O_2\rightarrow PbSO_4+4H_2OPbS+4H2​O2​→PbSO4​+4H2​O
  2. (B)Mn2++H2O2→Mn4++2OH−Mn^{2+}+H_2O_2\rightarrow Mn^{4+}+2OH^-Mn2++H2​O2​→Mn4++2OH−
  3. (C)HOCl+H2O2→H3O++Cl−+O2HOCl+H_2O_2\rightarrow H_3O^++Cl^-+O_2HOCl+H2​O2​→H3​O++Cl−+O2​
  4. (D)2Fe2++H2O2→2Fe3++2OH−2Fe^{2+}+H_2O_2\rightarrow 2Fe^{3+}+2OH^-2Fe2++H2​O2​→2Fe3++2OH−

Correct answer: (C)

Step-by-step solution →
Q46·Chemistry·AminesSingle correct
Given below are two statements: Statement I: Pure Aniline and other arylamines are usually colourless. Statement II: Arylamines get coloured on storage due to atmospheric reduction. In the light of the above statements, choose the most appropriate answer from the options given below:
  1. (A)Both Statement I and Statement II are incorrect
  2. (B)Statement I is incorrect but Statement II is correct
  3. (C)Statement I is correct but Statement II is incorrect
  4. (D)Both Statement I and Statement II are correct

Correct answer: (C)

Step-by-step solution →
Q47·ChemistrySingle correct
Correct statement is:
  1. (A)An average human being consumes nearly 15 times more air than food
  2. (B)An average human being consumes 100 times more air than food
  3. (C)An average human being consumes equal amount of food and air
  4. (D)An average human being consumes more food than air

Correct answer: (A)

Step-by-step solution →
Q48·ChemistrySingle correct
What is the number of unpaired electron(s) in the highest occupied molecular orbital of the following species: N2N_2N2​; N2+N_2^+N2+​; O2O_2O2​; O2+O_2^+O2+​?
  1. (A)2,1,0,1
  2. (B)0,1,2,1
  3. (C)0,1,0,1
  4. (D)2,1,2,1

Correct answer: (B)

Step-by-step solution →
Q49·ChemistrySingle correct
The metal which is extracted by oxidation and subsequent reduction from its ore is:
  1. (A)Ag
  2. (B)Fe
  3. (C)Cu
  4. (D)Al

Correct answer: (A)

Step-by-step solution →
Q50·ChemistrySingle correct
Choose the correct colour of the product for the following reaction.
  1. (A)White
  2. (B)Red
  3. (C)Blue
  4. (D)Yellow

Correct answer: (B)

Step-by-step solution →
Q51·ChemistryNumerical
Following figure shows spectrum of an ideal black body at four different temperatures. The number of correct statement/s from the following is _________. A. T4>T3>T2>T1T_4>T_3>T_2>T_1T4​>T3​>T2​>T1​. B. The black body consists of particles performing simple harmonic motion. C. The peak of the spectrum shifts to shorter wavelength as temperature increases. D. T1ν1=T2ν2=T3ν3≠\dfrac{T_1}{\nu_1}=\dfrac{T_2}{\nu_2}=\dfrac{T_3}{\nu_3}\neqν1​T1​​=ν2​T2​​=ν3​T3​​= constant. E. The spectrum could be explained using quantisation of energy.

Correct answer: 2

Step-by-step solution →
Q52·ChemistryNumerical
Number of units, which are used to express concentration of solutions from the following is _________. Mass percentage, Mole, Mole fraction, Molarity, ppm, Molality

Correct answer: 5

Step-by-step solution →
Q53·ChemistryNumerical
The number of statement/s which are the characteristics of physisorption is _________. A. It is highly specific in nature. B. Enthalpy of adsorption is high. C. It decreases with increase in temperature. D. It results into unimolecular layer. E. No activation energy is needed

Correct answer: 2

Step-by-step solution →
Q54·ChemistryNumerical
Sum of π\piπ-bonds present in peroxodisulphuric acid and pyrosulphuric acid is:

Correct answer: 8

Step-by-step solution →
Q55·ChemistryNumerical
If the pKapK_apKa​ of lactic acid is 555, then the pH of 0.0050.0050.005 M calcium lactate solution at 25 ∘C25\,^\circ C25∘C is _________ ×10−1\times10^{-1}×10−1 (Nearest integer)

Correct answer: 85

Step-by-step solution →
Q56·ChemistryNumerical
The total pressure observed by mixing two liquids A and B is 350350350 mmHg when their mole fractions are 0.70.70.7 and 0.30.30.3 respectively. The total pressure become 410410410 mmHg if the mole fractions are changed to 0.20.20.2 and 0.80.80.8 respectively for A and B. The vapour pressure of pure A is _________ mmHg. (Nearest integer) Consider the liquids and solutions behave ideally.

Correct answer: 314

Step-by-step solution →
Q57·ChemistryNumerical
The number of statement/s, which are correct with respect to the compression of carbon dioxide from point (a) in the Andrews isotherm from the following is _________. A. Carbon dioxide remains as a gas upto point (b). B. Liquid carbon dioxide appears at point (c). C. Liquid and gaseous carbon dioxide coexist between points (b) and (c). D. As the volume decreases from (b) to (c), the amount of liquid decreases

Correct answer: 4

Step-by-step solution →
Q58·ChemistryNumerical
Maximum number of isomeric monochloro derivatives which can be obtained from 2,2,5,52,2,5,52,2,5,5-tetramethylhexane by chlorination is _________

Correct answer: 3

Step-by-step solution →
Q59·ChemistryNumerical
Total number of tripeptides possible by mixing of valine and proline is _________

Correct answer: 8

Step-by-step solution →
Q60·ChemistryNumerical
One mole of an ideal monoatomic gas is subjected to changes as shown in the graph. The magnitude of the work done (by the system or on the system) is _________ J (nearest integer)

Correct answer: 6

Step-by-step solution →

Mathematics — JEE Main 24 January 2023 Shift 2

Q61·Mathematics·DifferentiabilitySingle correct
If f(x)=x3−x2f′(1)+xf′′(2)−f′′′(3), x∈Rf(x)=x^3-x^2f'(1)+xf''(2)-f'''(3),\ x\in\mathbb{R}f(x)=x3−x2f′(1)+xf′′(2)−f′′′(3), x∈R then
  1. (A)f(1)+f(2)+f(3)=f(0)f(1)+f(2)+f(3)=f(0)f(1)+f(2)+f(3)=f(0)
  2. (B)2f(0)−f(1)+f(3)=f(2)2f(0)-f(1)+f(3)=f(2)2f(0)−f(1)+f(3)=f(2)
  3. (C)3f(1)+f(2)=f(3)3f(1)+f(2)=f(3)3f(1)+f(2)=f(3)
  4. (D)f(3)−f(2)=f(1)f(3)-f(2)=f(1)f(3)−f(2)=f(1)

Correct answer: (B)

Step-by-step solution →
Q62·MathematicsSingle correct
If the system of equations x+2y+3z=3x+2y+3z=3x+2y+3z=3, 4x+3y−4z=44x+3y-4z=44x+3y−4z=4, 8x+4y+λz=9+μ8x+4y+\lambda z=9+\mu8x+4y+λz=9+μ has infinitely many solutions, then the ordered pair (λ,μ)(\lambda,\mu)(λ,μ) is equal to:
  1. (A)(−725,215)\left(-\dfrac{72}{5},\dfrac{21}{5}\right)(−572​,521​)
  2. (B)(−725,−215)\left(-\dfrac{72}{5},-\dfrac{21}{5}\right)(−572​,−521​)
  3. (C)(725,−215)\left(\dfrac{72}{5},-\dfrac{21}{5}\right)(572​,−521​)
  4. (D)(725,215)\left(\dfrac{72}{5},\dfrac{21}{5}\right)(572​,521​)

Correct answer: (C)

Step-by-step solution →
Q63·MathematicsSingle correct
If f(x)=22x22x+2, x∈Rf(x)=\dfrac{2^{2x}}{2^{2x}+2},\ x\in\mathbb{R}f(x)=22x+222x​, x∈R, then f(12023)+f(22023)+⋯+f(20222023)f\left(\dfrac{1}{2023}\right)+f\left(\dfrac{2}{2023}\right)+\cdots+f\left(\dfrac{2022}{2023}\right)f(20231​)+f(20232​)+⋯+f(20232022​) is equal to
  1. (A)101110111011
  2. (B)201020102010
  3. (C)101010101010
  4. (D)201120112011

Correct answer: (A)

Step-by-step solution →
Q64·MathematicsSingle correct
Let α⃗=4i^+3j^+5k^\vec\alpha=4\hat i+3\hat j+5\hat kα=4i^+3j^​+5k^ and β⃗=i^+2j^−4k^\vec\beta=\hat i+2\hat j-4\hat kβ​=i^+2j^​−4k^. Let β1⃗\vec{\beta_1}β1​​ be parallel to α⃗\vec\alphaα and β2⃗\vec{\beta_2}β2​​ be perpendicular to α⃗\vec\alphaα. If β⃗=β1⃗+β2⃗\vec\beta=\vec{\beta_1}+\vec{\beta_2}β​=β1​​+β2​​, then the value of 5β2⃗⋅(i^+j^+k^)5\vec{\beta_2}\cdot(\hat i+\hat j+\hat k)5β2​​⋅(i^+j^​+k^) is
  1. (A)777
  2. (B)999
  3. (C)666
  4. (D)111111

Correct answer: (A)

Step-by-step solution →
Q65·MathematicsSingle correct
Let y=y(x)y=y(x)y=y(x) be the solution of the differential equation (x2−3y2)dx+3xy dy=0, y(1)=1(x^2-3y^2)dx+3xy\,dy=0,\ y(1)=1(x2−3y2)dx+3xydy=0, y(1)=1. Then 6y2(e)6y^2(e)6y2(e) is equal to
  1. (A)2e22e^22e2
  2. (B)3e23e^23e2
  3. (C)e2e^2e2
  4. (D)32e2\dfrac32 e^223​e2

Correct answer: (A)

Step-by-step solution →
Q66·MathematicsSingle correct
The locus of the mid points of the chords of the circle C1:(x−4)2+(y−5)2=4C_1:(x-4)^2+(y-5)^2=4C1​:(x−4)2+(y−5)2=4 which subtend an angle θi\theta_iθi​ at the centre of the circle C1C_1C1​, is a circle of radius rir_iri​. If θ1=π3, θ3=2π3\theta_1=\dfrac{\pi}{3},\ \theta_3=\dfrac{2\pi}{3}θ1​=3π​, θ3​=32π​ and r12=r22+r32r_1^2=r_2^2+r_3^2r12​=r22​+r32​, then θ2\theta_2θ2​ is equal to
  1. (A)π4\dfrac{\pi}{4}4π​
  2. (B)π2\dfrac{\pi}{2}2π​
  3. (C)π6\dfrac{\pi}{6}6π​
  4. (D)3π4\dfrac{3\pi}{4}43π​

Correct answer: (B)

Step-by-step solution →
Q67·MathematicsSingle correct
The number of real solutions of the equation 3(x2+1x2)−2(x+1x)+5=03\left(x^2+\dfrac{1}{x^2}\right)-2\left(x+\dfrac{1}{x}\right)+5=03(x2+x21​)−2(x+x1​)+5=0, is
  1. (A)000
  2. (B)333
  3. (C)444
  4. (D)222

Correct answer: (A)

Step-by-step solution →
Q68·MathematicsSingle correct
Let A be a 3×33\times33×3 matrix such that ∣adj(adj(adj A))∣=124|\mathrm{adj}(\mathrm{adj}(\mathrm{adj}\,A))|=12^4∣adj(adj(adjA))∣=124. Then ∣A−1 adj A∣|A^{-1}\,\mathrm{adj}\,A|∣A−1adjA∣ is equal to
  1. (A)6\sqrt66​
  2. (B)232\sqrt323​
  3. (C)121212
  4. (D)111

Correct answer: (B)

Step-by-step solution →
Q69·MathematicsSingle correct
∫324334489−4x2 dx\displaystyle\int_{\frac{3\sqrt2}{4}}^{\frac{3\sqrt3}{4}}\dfrac{48}{\sqrt{9-4x^2}}\,dx∫432​​433​​​9−4x2​48​dx is equal to
  1. (A)2π2\pi2π
  2. (B)π6\dfrac{\pi}{6}6π​
  3. (C)π3\dfrac{\pi}{3}3π​
  4. (D)π2\dfrac{\pi}{2}2π​

Correct answer: (A)

Step-by-step solution →
Q70·MathematicsSingle correct
The number of square matrices of order 555 with entries from the set {0,1}\{0,1\}{0,1}, such that the sum of all the elements in each row is 111 and the sum of all the elements in each column is also 111, is
  1. (A)125125125
  2. (B)225225225
  3. (C)150150150
  4. (D)120120120

Correct answer: (D)

Step-by-step solution →
Q71·MathematicsSingle correct
If (30C1)2+2(30C2)2+3(30C3)2+⋯+30(30C30)2=α 60!(30!)2\left(^{30}C_1\right)^2+2\left(^{30}C_2\right)^2+3\left(^{30}C_3\right)^2+\cdots+30\left(^{30}C_{30}\right)^2=\dfrac{\alpha\,60!}{(30!)^2}(30C1​)2+2(30C2​)2+3(30C3​)2+⋯+30(30C30​)2=(30!)2α60!​ then α\alphaα is equal to:
  1. (A)303030
  2. (B)101010
  3. (C)606060
  4. (D)151515

Correct answer: (D)

Step-by-step solution →
Q72·MathematicsSingle correct
Let the plane containing the line of intersection of the planes P1:x+(λ+4)y+z=1P_1:x+(\lambda+4)y+z=1P1​:x+(λ+4)y+z=1 and P2:2x+y+z=2P_2:2x+y+z=2P2​:2x+y+z=2 pass through the points (0,1,0)(0,1,0)(0,1,0) and (1,0,1)(1,0,1)(1,0,1). Then the distance of the point (2λ,λ,−λ)(2\lambda,\lambda,-\lambda)(2λ,λ,−λ) from the plane P2P_2P2​ is
  1. (A)464\sqrt646​
  2. (B)363\sqrt636​
  3. (C)565\sqrt656​
  4. (D)262\sqrt626​

Correct answer: (B)

Step-by-step solution →
Q73·MathematicsSingle correct
Let f(x)f(x)f(x) be a function such that f(x+y)=f(x)⋅f(y)f(x+y)=f(x)\cdot f(y)f(x+y)=f(x)⋅f(y) for all x,y∈Nx,y\in\mathbb{N}x,y∈N. If f(1)=3f(1)=3f(1)=3 and ∑k=1nf(k)=3279\sum_{k=1}^{n}f(k)=3279∑k=1n​f(k)=3279, then the value of nnn is
  1. (A)999
  2. (B)666
  3. (C)888
  4. (D)777

Correct answer: (D)

Step-by-step solution →
Q74·MathematicsSingle correct
Let the six numbers a1,a2,a3,a4,a5,a6a_1,a_2,a_3,a_4,a_5,a_6a1​,a2​,a3​,a4​,a5​,a6​ be in A.P. and a1+a3=10a_1+a_3=10a1​+a3​=10. If the mean of these six numbers is 192\dfrac{19}{2}219​ and their variance is σ2\sigma^2σ2, then 8σ28\sigma^28σ2 is equal to:
  1. (A)210210210
  2. (B)220220220
  3. (C)200200200
  4. (D)105105105

Correct answer: (A)

Step-by-step solution →
Q75·MathematicsSingle correct
The equations of the sides AB and AC of a triangle ABC are (λ+1)x+λy=4(\lambda+1)x+\lambda y=4(λ+1)x+λy=4 and λx+(1−λ)y+λ=0\lambda x+(1-\lambda)y+\lambda=0λx+(1−λ)y+λ=0 respectively. Its vertex A is on the y-axis and its orthocentre is (1,2)(1,2)(1,2). The length of the tangent from the point C to the part of the parabola y2=6xy^2=6xy2=6x in the first quadrant is:
  1. (A)444
  2. (B)222
  3. (C)6\sqrt66​
  4. (D)222\sqrt222​

Correct answer: (D)

Step-by-step solution →
Q76·MathematicsSingle correct
Let ppp and qqq be two statements. Then ∼(p∧(p⇒∼q))\sim(p\wedge(p\Rightarrow\sim q))∼(p∧(p⇒∼q)) is equivalent to
  1. (A)p∨(p∧q)p\vee(p\wedge q)p∨(p∧q)
  2. (B)p∨(p∧(∼q))p\vee(p\wedge(\sim q))p∨(p∧(∼q))
  3. (C)(∼p)∨q(\sim p)\vee q(∼p)∨q
  4. (D)p∨((∼p)∧q)p\vee((\sim p)\wedge q)p∨((∼p)∧q)

Correct answer: (C)

Step-by-step solution →
Q77·Mathematics·Limits and ContinuitySingle correct
The set of all values of aaa for which lim⁡x→a([x−5]−[2x+2])=0\lim_{x\to a}([x-5]-[2x+2])=0limx→a​([x−5]−[2x+2])=0, where [α][\alpha][α] denotes the greatest integer less than or equal to α\alphaα, is equal to
  1. (A)[−7.5,−6.5)[-7.5,-6.5)[−7.5,−6.5)
  2. (B)[−7.5,−6.5][-7.5,-6.5][−7.5,−6.5]
  3. (C)(−7.5,−6.5](-7.5,-6.5](−7.5,−6.5]
  4. (D)(−7.5,−6.5)(-7.5,-6.5)(−7.5,−6.5)

Correct answer: (D)

Step-by-step solution →
Q78·MathematicsSingle correct
If the foot of the perpendicular drawn from (1,9,7)(1,9,7)(1,9,7) to the line passing through the point (3,2,1)(3,2,1)(3,2,1) and parallel to the planes x+2y+z=0x+2y+z=0x+2y+z=0 and 3y−z=33y-z=33y−z=3 is (α,β,γ)(\alpha,\beta,\gamma)(α,β,γ), then α+β+γ\alpha+\beta+\gammaα+β+γ is equal to
  1. (A)333
  2. (B)111
  3. (C)−1-1−1
  4. (D)555

Correct answer: (D)

Step-by-step solution →
Q79·MathematicsSingle correct
The number of integers, greater than 700070007000 that can be formed, using the digits 3,5,6,7,83,5,6,7,83,5,6,7,8 without repetition, is
  1. (A)168168168
  2. (B)220220220
  3. (C)120120120
  4. (D)484848

Correct answer: (A)

Step-by-step solution →
Q80·MathematicsSingle correct
The value of (1+sin⁡2π9+icos⁡2π91+sin⁡2π9−icos⁡2π9)3\left(\dfrac{1+\sin\frac{2\pi}{9}+i\cos\frac{2\pi}{9}}{1+\sin\frac{2\pi}{9}-i\cos\frac{2\pi}{9}}\right)^3(1+sin92π​−icos92π​1+sin92π​+icos92π​​)3 is
  1. (A)−12(3−i)-\dfrac12(\sqrt3-i)−21​(3​−i)
  2. (B)−12(1−i3)-\dfrac12(1-i\sqrt3)−21​(1−i3​)
  3. (C)12(1−i3)\dfrac12(1-i\sqrt3)21​(1−i3​)
  4. (D)12(3+i)\dfrac12(\sqrt3+i)21​(3​+i)

Correct answer: (A)

Step-by-step solution →
Q81·MathematicsNumerical
If the shortest distance between the lines x+62=y−63=z−64\dfrac{x+\sqrt6}{2}=\dfrac{y-\sqrt6}{3}=\dfrac{z-\sqrt6}{4}2x+6​​=3y−6​​=4z−6​​ and x−λ3=y−264=z+265\dfrac{x-\lambda}{3}=\dfrac{y-2\sqrt6}{4}=\dfrac{z+2\sqrt6}{5}3x−λ​=4y−26​​=5z+26​​ is 666, then the square of sum of all possible values of λ\lambdaλ is

Correct answer: 384

Step-by-step solution →
Q82·MathematicsNumerical
Three urns A, B and C contain 444 red, 666 black; 555 red, 555 black; and λ\lambdaλ red, 444 black balls respectively. One of the urns is selected at random and a ball is drawn. If the ball drawn is red and the probability that it is drawn from urn C is 0.40.40.4, then the square of the length of the side of the largest equilateral triangle, inscribed in the parabola y2=λxy^2=\lambda xy2=λx with one vertex at the vertex of the parabola, is

Correct answer: 432

Step-by-step solution →
Q83·MathematicsNumerical
Let S={θ∈[0,2π):tan⁡(πcos⁡θ)+tan⁡(πsin⁡θ)=0}S=\{\theta\in[0,2\pi):\tan(\pi\cos\theta)+\tan(\pi\sin\theta)=0\}S={θ∈[0,2π):tan(πcosθ)+tan(πsinθ)=0}. Then ∑θ∈Ssin⁡2(θ+π4)\sum_{\theta\in S}\sin^2\left(\theta+\dfrac{\pi}{4}\right)∑θ∈S​sin2(θ+4π​) is equal to

Correct answer: 2

Step-by-step solution →
Q84·MathematicsNumerical
If 13+23+33+⋯ up to n terms1⋅3+2⋅5+3⋅7+⋯ up to n terms=95\dfrac{1^3+2^3+3^3+\cdots\text{ up to }n\text{ terms}}{1\cdot3+2\cdot5+3\cdot7+\cdots\text{ up to }n\text{ terms}}=\dfrac{9}{5}1⋅3+2⋅5+3⋅7+⋯ up to n terms13+23+33+⋯ up to n terms​=59​, then the value of nnn is

Correct answer: 5

Step-by-step solution →
Q85·MathematicsNumerical
Let the sum of the coefficients of the first three terms in the expansion of (x−3x2)n, x≠0, n∈N\left(x-\dfrac{3}{x^2}\right)^n,\ x\neq0,\ n\in\mathbb{N}(x−x23​)n, x=0, n∈N, be 376376376. Then the coefficient of x4x^4x4 is

Correct answer: 405

Step-by-step solution →
Q86·MathematicsNumerical
The equations of the sides AB, BC and CA of a triangle ABC are: 2x+y=02x+y=02x+y=0, x+py=21ax+py=21ax+py=21a (a≠0)(a\neq0)(a=0) and x−y=3x-y=3x−y=3 respectively. Let P(2,a)P(2,a)P(2,a) be the centroid of △ABC\triangle ABC△ABC. Then (BC)2(BC)^2(BC)2 is equal to

Correct answer: 122

Step-by-step solution →
Q87·MathematicsNumerical
Let a⃗=i^+2j^+λk^, b⃗=3i^−5j^−λk^, a⃗⋅c⃗=7, 2b⃗⋅c⃗+43=0, a⃗×c⃗=b⃗×c⃗\vec a=\hat i+2\hat j+\lambda\hat k,\ \vec b=3\hat i-5\hat j-\lambda\hat k,\ \vec a\cdot\vec c=7,\ 2\vec b\cdot\vec c+43=0,\ \vec a\times\vec c=\vec b\times\vec ca=i^+2j^​+λk^, b=3i^−5j^​−λk^, a⋅c=7, 2b⋅c+43=0, a×c=b×c. Then ∣a⃗⋅b⃗∣|\vec a\cdot\vec b|∣a⋅b∣ is equal to

Correct answer: 8

Step-by-step solution →
Q88·MathematicsNumerical
The minimum number of elements that must be added to the relation R={(a,b),(b,c),(b,d)}R=\{(a,b),(b,c),(b,d)\}R={(a,b),(b,c),(b,d)} on the set {a,b,c,d}\{a,b,c,d\}{a,b,c,d} so that it is an equivalence relation, is

Correct answer: 13

Step-by-step solution →
Q89·MathematicsNumerical
If the area of the region bounded by the curves y2−2y=−x, x+y=0y^2-2y=-x,\ x+y=0y2−2y=−x, x+y=0 is A, then 8A8A8A is equal to

Correct answer: 36

Step-by-step solution →
Q90·MathematicsNumerical
Let fff be a differentiable function defined on [0,π2]\left[0,\dfrac{\pi}{2}\right][0,2π​] such that f(x)>0f(x)>0f(x)>0 and f(x)+∫0xf(t)1−(log⁡ef(t))2 dt=e, ∀x∈[0,π2]f(x)+\int_0^x f(t)\sqrt{1-(\log_e f(t))^2}\,dt=e,\ \forall x\in\left[0,\dfrac{\pi}{2}\right]f(x)+∫0x​f(t)1−(loge​f(t))2​dt=e, ∀x∈[0,2π​]. Then (6log⁡ef(π6))2\left(6\log_e f\left(\dfrac{\pi}{6}\right)\right)^2(6loge​f(6π​))2 is equal to

Correct answer: 27

Step-by-step solution →

Chapters tested in this paper

Open any chapter to practise every past-year question on that topic across all papers, and see how often it has actually appeared.

  • Properties of Solids and Liquids 172/186
  • Three Dimensional Geometry 176/186
  • Matrices and Determinants 180/186
  • Coordination Compounds 176/186
  • Sets, Relations and Functions 165/186
  • Current Electricity 160/186
  • Sequence and Series 164/186
  • p-Block Elements 164/186
  • Definite Integration 168/186
  • Rotational Motion 172/186
  • Redox Reactions and Electrochemistry 177/186
  • Geometrical Optics 172/186
  • Kinematics 156/186
  • Vector Algebra 173/186
  • Differential Equations 167/186
  • Probability 176/186
  • Permutations and Combinations 162/186
  • Magnetic Field of Current 147/186
  • Binomial Theorem and Its Simple Applications 158/186
  • Electromagnetic Waves 144/186
  • Chemical Bonding and Molecular Structure 151/186
  • Limits and Continuity 149/186
  • d- and f-Block Elements 126/186
  • Thermodynamics 154/186
  • Aldehydes and Ketones 135/186
  • Equilibrium 163/186
  • Solutions 158/186
  • Laws of Motion 130/186
  • Chemical Thermodynamics 165/186
  • Units and Measurements 149/186
  • Hydrocarbons 126/186
  • Complex Numbers 165/186
  • Trigonometric Functions 144/186
  • Biomolecules 162/186
  • Chemical Kinetics 169/186
  • Gravitation 152/186
  • Atomic Structure 161/186
  • Electronic Devices 145/186
  • Circles 142/186
  • Dual Nature of Matter and Radiation 155/186
  • Amines 133/186
  • Quadratic Equations 148/186
  • Work, Energy and Power 132/186
  • Electromagnetic Induction 120/186
  • Area Under Curves 139/186
  • Kinetic Theory of Gases 135/186
  • Oscillations 117/186
  • Nuclei 116/186
  • Straight Lines 114/186
  • Capacitors and Dielectrics 115/186
  • Atoms 112/186
  • Statistics 118/186
  • Isolation of Metals 106/186
  • Differentiability 91/186
  • s-Block Elements 88/186
  • Surface Chemistry 98/186
  • Environmental Chemistry 83/186
  • Hydrogen 81/186
  • Electronic Effects and Stability 74/186
  • Electric Potential 63/186
  • Chemistry in Everyday Life 60/186
  • Diazonium Salts and Reactions 53/186
  • States of Matter: Gases and Liquids 52/186
← 24 Jan Shift 1 2023All papers25 Jan Shift 1 2023 →

Attempt this paper under exam timing.

Take the 24 January 2023 Shift 2 paper as a timed mock and Jarvis marks it, then tells you which errors were conceptual gaps, which were silly mistakes, and which pattern you have now repeated. Step-by-step solutions for every question included.

Attempt this paper freeSee pricing

Free plan, no time limit · No credit card needed

Jarvis OS

AI-powered JEE preparation.

Question papers

JEE Main PYQsJEE Advanced PYQsPhysics PYQsChemistry PYQsMaths PYQs

Product

TourPricingSign inCreate account

Legal

Privacy PolicyTerms of ServiceRefund & CancellationShipping & DeliveryContact Us

Operated by

Venyou Craft Private Limited

info@jarvisos.net

© 2026 Jarvis OS