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JEE Main 6 April 2024 Shift 1 Question Paper with Answers

6 April 2024 · April session · 89 questions

89 of the 90 questions from the JEE Main 6 April 2024 Shift 1 paper, each with its correct answer and tagged to the chapter it tests. Free to read, no account needed.

1 question is held back from this paper while we re-check the transcription or the answer key. We would rather show you nothing than show you an answer we are not confident is right.

Physics
29
Chemistry
30
Mathematics
30

Physics — JEE Main 6 April 2024 Shift 1

Q1·PhysicsSingle correct
To find the spring constant (kkk) of a spring experimentally, a student commits 2% positive error in the measurement of time and 1% negative error in the measurement of mass. The percentage error in determining the value of kkk is:
  1. (A)3%3\%3%
  2. (B)1%1\%1%
  3. (C)4%4\%4%
  4. (D)5%5\%5%

Correct answer: (D)

Step-by-step solution →
Q2·PhysicsSingle correct
A bullet of mass 50 g is fired with a speed 100 m/s on a plywood and emerges with 40 m/s. The percentage loss of kinetic energy is:
  1. (A)32%32\%32%
  2. (B)44%44\%44%
  3. (C)16%16\%16%
  4. (D)84%84\%84%

Correct answer: (D)

Step-by-step solution →
Q3·PhysicsSingle correct
The ratio of the shortest wavelength of the Balmer series to the shortest wavelength of the Lyman series for hydrogen atom is:
  1. (A)4:14:14:1
  2. (B)1:21:21:2
  3. (C)1:41:41:4
  4. (D)2:12:12:1

Correct answer: (A)

Step-by-step solution →
Q4·PhysicsSingle correct
To project a body of mass mmm from earth's surface to infinity, the required kinetic energy is (assume the radius of earth is RER_{E}RE​, g=g=g= acceleration due to gravity on the surface of earth):
  1. (A)2mgRE2mgR_{E}2mgRE​
  2. (B)mgREmgR_{E}mgRE​
  3. (C)12mgRE\tfrac{1}{2}mgR_{E}21​mgRE​
  4. (D)4mgRE4mgR_{E}4mgRE​

Correct answer: (B)

Step-by-step solution →
Q5·PhysicsSingle correct
Electromagnetic waves travel in a medium with a speed of 1.5×1081.5\times10^{8}1.5×108 m s−1^{-1}−1. The relative permeability of the medium is 2.0. The relative permittivity of the medium will be:
  1. (A)555
  2. (B)111
  3. (C)444
  4. (D)222

Correct answer: (D)

Step-by-step solution →
Q6·PhysicsSingle correct
Which of the following phenomena is not explained by the wave nature of light? (A) reflection (B) diffraction (C) photoelectric effect (D) interference (E) polarization. Choose the most appropriate answer from the options given below:
  1. (A)(E) only
  2. (B)(C) only
  3. (C)(B), (D) only
  4. (D)(A), (C) only

Correct answer: (B)

Step-by-step solution →
Q7·PhysicsSingle correct
While measuring the diameter of a wire using a screw gauge the following readings were noted. Main scale reading is 1 mm and the 42nd division of the circular scale coincides with the reference line. Pitch of the screw gauge is 1 mm and it has 100 divisions on the circular scale. The diameter of the wire is x50\tfrac{x}{50}50x​ mm. The value of xxx is:
  1. (A)142142142
  2. (B)717171
  3. (C)424242
  4. (D)212121

Correct answer: (B)

Step-by-step solution →
Q8·PhysicsSingle correct
σ\sigmaσ is the uniform surface charge density of a thin spherical shell of radius RRR. The electric field at any point on the surface of the spherical shell is:
  1. (A)σε0R\tfrac{\sigma}{\varepsilon_{0}}Rε0​σ​R
  2. (B)σ2ε0\tfrac{\sigma}{2\varepsilon_{0}}2ε0​σ​
  3. (C)σε0\tfrac{\sigma}{\varepsilon_{0}}ε0​σ​
  4. (D)σ4ε0\tfrac{\sigma}{4\varepsilon_{0}}4ε0​σ​

Correct answer: (C)

Step-by-step solution →
Q9·PhysicsSingle correct
The value of the unknown resistance (xxx) for which the potential difference between BBB and DDD will be zero in the arrangement shown, is:
  1. (A)3 Ω3\,\Omega3Ω
  2. (B)9 Ω9\,\Omega9Ω
  3. (C)6 Ω6\,\Omega6Ω
  4. (D)42 Ω42\,\Omega42Ω

Correct answer: (C)

Step-by-step solution →
Q10·PhysicsSingle correct
The specific heat at constant pressure of a real gas obeying PV2=RTPV^{2}=RTPV2=RT equation is:
  1. (A)Cv+RC_{v}+RCv​+R
  2. (B)R3+Cv\tfrac{R}{3}+C_{v}3R​+Cv​
  3. (C)RRR
  4. (D)Cv+R2VC_{v}+\tfrac{R}{2V}Cv​+2VR​

Correct answer: (D)

Step-by-step solution →
Q11·PhysicsSingle correct
Match List-I (physical quantities) with List-II (their dimensional formulae). Choose the correct answer from the options given below:
List-IList-II
A.TorqueI.[M1L1T−2A−2][M^{1}L^{1}T^{-2}A^{-2}][M1L1T−2A−2]
B.Magnetic fieldII.[L2A1][L^{2}A^{1}][L2A1]
C.Magnetic momentIII.[M1T−2A−1][M^{1}T^{-2}A^{-1}][M1T−2A−1]
D.Permeability of free spaceIV.[M1L2T−2][M^{1}L^{2}T^{-2}][M1L2T−2]
  1. (A)A-I, B-III, C-II, D-IV
  2. (B)A-IV, B-III, C-II, D-I
  3. (C)A-III, B-I, C-II, D-IV
  4. (D)A-IV, B-II, C-III, D-I

Correct answer: (B)

Step-by-step solution →
Q12·PhysicsSingle correct
Given below are two statements: Statement I: In an LCR series circuit, current is maximum at resonance. Statement II: Current in a purely resistive circuit can never be less than that in a series LCR circuit when connected to the same voltage source. In the light of the above statements, choose the correct answer from the options given below:
  1. (A)Statement I is true but Statement II is false
  2. (B)Statement I is false but Statement II is true
  3. (C)Both Statement I and Statement II are true
  4. (D)Both Statement I and Statement II are false

Correct answer: (C)

Step-by-step solution →
Q13·PhysicsSingle correct
A sample contains a mixture of helium and oxygen gas. The ratio of the root mean square speed of helium to that of oxygen in the sample is:
  1. (A)132\tfrac{1}{\sqrt{32}}32​1​
  2. (B)222\sqrt{2}22​
  3. (C)14\tfrac{1}{4}41​
  4. (D)122\tfrac{1}{2\sqrt{2}}22​1​

Correct answer: (B)

Step-by-step solution →
Q14·PhysicsSingle correct
A light string passing over a smooth light pulley connects two blocks of masses m1m_{1}m1​ and m2m_{2}m2​ (where m2>m1m_{2}>m_{1}m2​>m1​). If the acceleration of the system is g2\tfrac{g}{\sqrt{2}}2​g​, then the ratio of the masses m1m2\tfrac{m_{1}}{m_{2}}m2​m1​​ is:
  1. (A)2−12+1\tfrac{\sqrt{2}-1}{\sqrt{2}+1}2​+12​−1​
  2. (B)1+55−1\tfrac{1+\sqrt{5}}{\sqrt{5}-1}5​−11+5​​
  3. (C)1+52−1\tfrac{1+\sqrt{5}}{\sqrt{2}-1}2​−11+5​​
  4. (D)3+12−1\tfrac{\sqrt{3}+1}{\sqrt{2}-1}2​−13​+1​

Correct answer: (A)

Step-by-step solution →
Q15·PhysicsSingle correct
Four particles AAA, BBB, CCC, DDD of mass m2\tfrac{m}{2}2m​, mmm, 2m2m2m, 4m4m4m have the same momentum, respectively. The particle with maximum kinetic energy is:
  1. (A)DDD
  2. (B)CCC
  3. (C)AAA
  4. (D)BBB

Correct answer: (C)

Step-by-step solution →
Q16·PhysicsSingle correct
A train starting from rest first accelerates uniformly up to a speed of 80 km/h for time ttt, then it moves with a constant speed for time 3t3t3t. The average speed of the train for this duration of the journey will be (in km/h):
  1. (A)808080
  2. (B)707070
  3. (C)303030
  4. (D)404040

Correct answer: (B)

Step-by-step solution →
Q17·PhysicsSingle correct
An element Δl=Δx i^\Delta l=\Delta x\,\hat{i}Δl=Δxi^ is placed at the origin and carries a large current I=10I=10I=10 A. The magnetic field on the yyy-axis at a distance of 0.5 m from the element Δx\Delta xΔx of 1 cm length is:
  1. (A)4×10−84\times10^{-8}4×10−8 T
  2. (B)8×10−88\times10^{-8}8×10−8 T
  3. (C)12×10−812\times10^{-8}12×10−8 T
  4. (D)10×10−810\times10^{-8}10×10−8 T

Correct answer: (A)

Step-by-step solution →
Q18·PhysicsSingle correct
A small ball of mass mmm and density ρ\rhoρ is dropped in a viscous liquid of density ρ0\rho_{0}ρ0​. After some time, the ball falls with constant velocity. The viscous force on the ball is:
  1. (A)mg(ρ0ρ−1)mg\left(\tfrac{\rho_{0}}{\rho}-1\right)mg(ρρ0​​−1)
  2. (B)mg(1+ρρ0)mg\left(1+\tfrac{\rho}{\rho_{0}}\right)mg(1+ρ0​ρ​)
  3. (C)mg(1−ρρ0)mg(1-\rho\rho_{0})mg(1−ρρ0​)
  4. (D)mg(1−ρ0ρ)mg\left(1-\tfrac{\rho_{0}}{\rho}\right)mg(1−ρρ0​​)

Correct answer: (D)

Step-by-step solution →
Q19·PhysicsSingle correct
In a photoelectric experiment, light of energy 2.48 eV irradiates a photosensitive material. The stopping potential was measured to be 0.5 V. The work function of the photosensitive material is:
  1. (A)0.50.50.5 eV
  2. (B)1.681.681.68 eV
  3. (C)2.482.482.48 eV
  4. (D)1.981.981.98 eV

Correct answer: (D)

Step-by-step solution →
Q20·PhysicsNumerical
If the radius of earth is reduced to three-fourth of its present value without change in its mass, then the value of the duration of the day of earth will be _______ hours 30 minutes.

Correct answer: 13

Step-by-step solution →
Q21·PhysicsNumerical
Three infinitely long charged thin sheets are placed as shown in the figure. The magnitude of the electric field at the point PPP is xσε0\tfrac{x\sigma}{\varepsilon_{0}}ε0​xσ​. The value of xxx is _______. (all quantities are measured in SI units)

Correct answer: 2

Step-by-step solution →
Q22·PhysicsNumerical
A big drop is formed by coalescing 1000 small droplets of water. The ratio of the surface energy of 1000 droplets to that of the big drop is 10x\tfrac{10}{x}x10​. The value of xxx is _______.

Correct answer: 1

Step-by-step solution →
Q23·PhysicsNumerical
When a dc voltage of 100 V is applied to an inductor, a current of 5 A flows through it. When an ac voltage of 200 V peak value is connected to the inductor, its inductive reactance is found to be 203 Ω20\sqrt{3}\,\Omega203​Ω. The power dissipated in the circuit is _______ W.

Correct answer: 250

Step-by-step solution →
Q24·PhysicsNumerical
The refractive index of a prism is μ=3\mu=\sqrt{3}μ=3​ and the ratio of the angle of minimum deviation to the angle of the prism is one. The value of the angle of the prism is _______ degrees.

Correct answer: 60

Step-by-step solution →
Q25·PhysicsNumerical
A wire of resistance RRR and radius rrr is stretched till its radius becomes r2\tfrac{r}{2}2r​. If the resistance of the stretched wire becomes xRxRxR, then the value of xxx is _______.

Correct answer: 16

Step-by-step solution →
Q26·PhysicsNumerical
Radius of a certain orbit of hydrogen atom is 8.48 Å. If energy of the electron in this orbit is Ex\tfrac{E}{x}xE​, then x=x=x= _______. (Given a0=0.529a_{0}=0.529a0​=0.529 Å, E=E=E= energy of electron in the ground state)

Correct answer: 16

Step-by-step solution →
Q27·PhysicsNumerical
A circular coil having 200 turns, 2.5×10−42.5\times10^{-4}2.5×10−4 m2^{2}2 area and carrying 100 μ100\,\mu100μA current is placed in a uniform magnetic field of 1 T. Initially the magnetic dipole moment (M⃗)(\vec{M})(M) was directed along B⃗\vec{B}B. The amount of work required to rotate the coil through 90∘90^{\circ}90∘ from its initial orientation such that M⃗\vec{M}M becomes perpendicular to B⃗\vec{B}B is _______ μ\muμJ.

Correct answer: 5

Step-by-step solution →
Q28·PhysicsNumerical
A particle is doing simple harmonic motion of amplitude 0.06 m and time period 3.14 s. The maximum velocity of the particle is _______ cm/s.

Correct answer: 12

Step-by-step solution →
Q29·PhysicsNumerical
For three vectors A⃗=(−xi^−6j^−2k^)\vec{A}=(-x\hat{i}-6\hat{j}-2\hat{k})A=(−xi^−6j^​−2k^), B⃗=(−i^+4j^+3k^)\vec{B}=(-\hat{i}+4\hat{j}+3\hat{k})B=(−i^+4j^​+3k^) and C⃗=(−8i^−j^+3k^)\vec{C}=(-8\hat{i}-\hat{j}+3\hat{k})C=(−8i^−j^​+3k^), if A⃗⋅(B⃗×C⃗)=0\vec{A}\cdot(\vec{B}\times\vec{C})=0A⋅(B×C)=0, then the value of xxx is _______.

Correct answer: 4

Step-by-step solution →

Chemistry — JEE Main 6 April 2024 Shift 1

Q30·Chemistry·IUPAC NomenclatureSingle correct
The functional group present in sulphonic acid is:
  1. (A)−SO4H-SO_4H−SO4​H
  2. (B)−SO3H-SO_3H−SO3​H
  3. (C)−S(=O)−OH-S(=O)-OH−S(=O)−OH
  4. (D)−SO2−-SO_2-−SO2​−

Correct answer: (B)

Step-by-step solution →
Q31·ChemistrySingle correct
Match List-I (Molecule / Species) with List-II (Property / Shape). Choose the correct answer from the options given below:
List-I (Molecule / Species)List-II (Property / Shape)
A.SO2Cl2SO_2Cl_2SO2​Cl2​I.Paramagnetic
B.NONONOII.Diamagnetic
C.NO2−NO_2^{-}NO2−​III.Tetrahedral
D.I3−I_3^{-}I3−​IV.Linear
  1. (A)A-IV, B-I, C-III, D-II
  2. (B)A-III, B-I, C-II, D-IV
  3. (C)A-II, B-III, C-I, D-IV
  4. (D)A-III, B-IV, C-II, D-I

Correct answer: (B)

Step-by-step solution →
Q32·Chemistry·Alcohols and EthersSingle correct
Given below are two statements: Statement I: Picric acid is 2,4,6-trinitrotoluene. Statement II: Phenol-2,4-disulphonic acid is treated with conc. HNO3HNO_3HNO3​ to get picric acid. In the light of the above statements, choose the most appropriate answer from the options given below:
  1. (A)Statement I is incorrect but Statement II is correct.
  2. (B)Both Statement I and Statement II are incorrect.
  3. (C)Statement I is correct but Statement II is incorrect.
  4. (D)Both Statement I and Statement II are correct.

Correct answer: (A)

Step-by-step solution →
Q33·Chemistry·IsomerismSingle correct
Which of the following (shown in the figure) is a metamer of the given compound (X)?
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (D)

Step-by-step solution →
Q34·ChemistrySingle correct
A DNA molecule contains 4 bases whose structures are shown in the figure. One of the structures is not correct. Identify the incorrect base structure.
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (C)

Step-by-step solution →
Q35·ChemistrySingle correct
Match List-I (Hybridization) with List-II (Orientation in Space). Choose the correct answer from the options given below:
List-I (Hybridization)List-II (Orientation in Space)
A.sp3sp^3sp3I.Trigonal bipyramidal
B.dsp2dsp^2dsp2II.Octahedral
C.sp3dsp^3dsp3dIII.Tetrahedral
D.sp3d2sp^3d^2sp3d2IV.Square planar
  1. (A)A-III, B-I, C-IV, D-II
  2. (B)A-II, B-I, C-IV, D-III
  3. (C)A-IV, B-III, C-I, D-II
  4. (D)A-III, B-IV, C-I, D-II

Correct answer: (D)

Step-by-step solution →
Q36·ChemistrySingle correct
Given below are two statements: Statement I: Gallium is used in the manufacturing of thermometers. Statement II: A thermometer containing gallium is useful for measuring the freezing point (256 K) of brine solution. In the light of the above statements, choose the correct answer from the options given below:
  1. (A)Both Statement I and Statement II are false.
  2. (B)Statement I is false but Statement II is true.
  3. (C)Both Statement I and Statement II are true.
  4. (D)Statement I is true but Statement II is false.

Correct answer: (D)

Step-by-step solution →
Q37·ChemistrySingle correct
Which of the following statements are correct? A. Glycerol is purified by vacuum distillation because it decomposes at its normal boiling point. B. Aniline can be purified by steam distillation as aniline is miscible in water. C. Ethanol can be separated from ethanol-water mixture by azeotropic distillation because it forms azeotrope. D. An organic compound is pure, if mixed M.P. is remained same. Choose the most appropriate answer from the options given below:
  1. (A)A, B, C only
  2. (B)A, C, D only
  3. (C)B, C, D only
  4. (D)A, B, D only

Correct answer: (B)

Step-by-step solution →
Q38·ChemistrySingle correct
Match List-I (Compound / Species) with List-II (Shape / Geometry). Choose the correct answer from the options given below:
List-I (Compound / Species)List-II (Shape / Geometry)
A.SF4SF_4SF4​I.Tetrahedral
B.BrF3BrF_3BrF3​II.Pyramidal
C.BrO3−BrO_3^{-}BrO3−​III.See saw
D.NH4+NH_4^{+}NH4+​IV.Bent T-shape
  1. (A)A-II, B-III, C-I, D-IV
  2. (B)A-III, B-IV, C-II, D-I
  3. (C)A-II, B-IV, C-III, D-I
  4. (D)A-III, B-II, C-IV, D-I

Correct answer: (B)

Step-by-step solution →
Q39·Chemistry·Alcohols and EthersSingle correct
In the Reimer-Tiemann reaction, phenol is converted into salicylaldehyde through an intermediate. The structure of the intermediate is (choose the correct option from the structures shown in the figure):
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (D)

Step-by-step solution →
Q40·ChemistrySingle correct
Which of the following material is not a semiconductor?
  1. (A)Germanium
  2. (B)Graphite
  3. (C)Silicon
  4. (D)Copper oxide

Correct answer: (B)

Step-by-step solution →
Q41·ChemistrySingle correct
Consider the following complexes: (A) [CoCl(NH3)5]2+[CoCl(NH_3)_5]^{2+}[CoCl(NH3​)5​]2+, (B) [Co(CN)6]3−[Co(CN)_6]^{3-}[Co(CN)6​]3−, (C) [Co(NH3)5(H2O)]3+[Co(NH_3)_5(H_2O)]^{3+}[Co(NH3​)5​(H2​O)]3+, (D) [Cu(H2O)4]2+[Cu(H_2O)_4]^{2+}[Cu(H2​O)4​]2+. The correct order of A, B, C and D in terms of wavenumber of light absorbed is:
  1. (A)C < D < A < B
  2. (B)D < A < C < B
  3. (C)A < C < B < D
  4. (D)B < C < A < D

Correct answer: (B)

Step-by-step solution →
Q42·ChemistrySingle correct
Match List-I (Precipitating reagent and conditions) with List-II (Cation). Choose the correct answer from the options given below:
List-I (Precipitating reagent and conditions)List-II (Cation)
A.NH4Cl+NH4OHNH_4Cl + NH_4OHNH4​Cl+NH4​OHI.Mn2+Mn^{2+}Mn2+
B.NH4OH+Na2CO3NH_4OH + Na_2CO_3NH4​OH+Na2​CO3​II.Pb2+Pb^{2+}Pb2+
C.NH4OH+NH4Cl+H2SNH_4OH + NH_4Cl + H_2SNH4​OH+NH4​Cl+H2​S gasIII.Al3+Al^{3+}Al3+
D.dilute HClIV.Sr2+Sr^{2+}Sr2+
  1. (A)A-IV, B-III, C-II, D-I
  2. (B)A-IV, B-III, C-I, D-II
  3. (C)A-III, B-IV, C-I, D-II
  4. (D)A-III, B-IV, C-II, D-I

Correct answer: (C)

Step-by-step solution →
Q43·ChemistrySingle correct
The electron affinity values are negative for: A. Be→Be−Be \rightarrow Be^{-}Be→Be−, B. N→N−N \rightarrow N^{-}N→N−, C. O→O2−O \rightarrow O^{2-}O→O2−, D. Na→Na−Na \rightarrow Na^{-}Na→Na−, E. Al→Al−Al \rightarrow Al^{-}Al→Al−. Choose the most appropriate answer from the options given below:
  1. (A)D and E only
  2. (B)A, B, D and E only
  3. (C)A and D only
  4. (D)A, B and C only

Correct answer: (D)

Step-by-step solution →
Q44·ChemistrySingle correct
The number of elements from the following that do not belong to lanthanoids is: EuEuEu, CmCmCm, ErErEr, TbTbTb, YbYbYb and LuLuLu.
  1. (A)3
  2. (B)4
  3. (C)1
  4. (D)5

Correct answer: (C)

Step-by-step solution →
Q45·ChemistrySingle correct
The density of 'x' M (x molar) solution of NaOH is 1.12 g mL−1^{-1}−1, while in molality, the concentration of the solution is 3 m (3 molal). Then x is: (Given: Molar mass of NaOH is 40 g/mol)
  1. (A)3.5
  2. (B)3.0
  3. (C)3.8
  4. (D)2.8

Correct answer: (B)

Step-by-step solution →
Q46·ChemistrySingle correct
Which among the following aldehydes is most reactive towards nucleophilic addition reactions?
  1. (A)H−CHOH-CHOH−CHO
  2. (B)C2H5−CHOC_2H_5-CHOC2​H5​−CHO
  3. (C)CH3−CHOCH_3-CHOCH3​−CHO
  4. (D)C3H7−CHOC_3H_7-CHOC3​H7​−CHO

Correct answer: (A)

Step-by-step solution →
Q47·ChemistrySingle correct
At −20 ∘-20\,^{\circ}−20∘C and 1 atm pressure, a cylinder is filled with equal number of H2H_2H2​, I2I_2I2​ and HIHIHI molecules for the reaction H2(g)+I2(g)⇌2HI(g)H_2(g) + I_2(g) \rightleftharpoons 2HI(g)H2​(g)+I2​(g)⇌2HI(g). The KPK_PKP​ for the process is x×10−1x\times10^{-1}x×10−1. The value of xxx is: (Given: R=0.082R=0.082R=0.082 L atm K−1^{-1}−1 mol−1^{-1}−1)
  1. (A)2
  2. (B)1
  3. (C)10
  4. (D)0.01

Correct answer: (C)

Step-by-step solution →
Q48·ChemistrySingle correct
Match List-I (Compound) with List-II (Uses). Choose the correct answer from the options given below:
List-I (Compound)List-II (Uses)
A.IodoformI.Fire extinguisher
B.Carbon tetrachlorideII.Insecticide
C.CFCIII.Antiseptic
D.DDTIV.Refrigerants
  1. (A)A-I, B-II, C-III, D-IV
  2. (B)A-III, B-II, C-IV, D-I
  3. (C)A-III, B-I, C-IV, D-II
  4. (D)A-II, B-IV, C-I, D-III

Correct answer: (C)

Step-by-step solution →
Q49·ChemistrySingle correct
A conductivity cell with two electrodes (dark side) is half filled with infinitely dilute aqueous solution of a weak electrolyte (cell shown in the figure). If volume is doubled by adding more water at constant temperature, the molar conductivity of the cell will:
  1. (A)increase sharply
  2. (B)remain same or can not be measured accurately
  3. (C)decrease sharply
  4. (D)depend upon type of electrolyte

Correct answer: (B)

Step-by-step solution →
Q50·ChemistryNumerical
Consider the dissociation of the weak acid HX as given below: HX(aq)⇌H+(aq)+X−(aq)HX(aq) \rightleftharpoons H^{+}(aq) + X^{-}(aq)HX(aq)⇌H+(aq)+X−(aq), Ka=1.2×10−5K_a = 1.2\times10^{-5}Ka​=1.2×10−5. The osmotic pressure of 0.03 M aqueous solution of HX at 300 K is _______ ×10−2\times10^{-2}×10−2 bar (nearest integer). (Given: R=0.083R=0.083R=0.083 L bar mol−1^{-1}−1 K−1^{-1}−1)

Correct answer: 76

Step-by-step solution →
Q51·ChemistryNumerical
The difference in the 'spin-only' magnetic moment values of KMnO4KMnO_4KMnO4​ and the manganese product formed during titration of KMnO4KMnO_4KMnO4​ against oxalic acid in acidic medium is _______ BM (nearest integer).

Correct answer: 6

Step-by-step solution →
Q52·ChemistryNumerical
Time required for 99.9% completion of a first order reaction is _______ times the time required for completion of 90% reaction (nearest integer).

Correct answer: 3

Step-by-step solution →
Q53·ChemistryNumerical
The number of molecules from the following which can exhibit hydrogen bonding is _______ (nearest integer): CH3OHCH_3OHCH3​OH, H2OH_2OH2​O, C2H6C_2H_6C2​H6​, C6H6C_6H_6C6​H6​, (the compound shown in the figure), HFHFHF, NH3NH_3NH3​.

Correct answer: 5

Step-by-step solution →
Q54·ChemistryNumerical
9.3 g of pure aniline upon diazotisation followed by coupling with phenol gives an orange dye. The mass of orange dye produced (assume 100% yield/conversion) is _______ g (nearest integer).

Correct answer: 20

Step-by-step solution →
Q55·ChemistryNumerical
The major product of the following reaction is P: CH3−C≡C−CH3CH_3-C{\equiv}C-CH_3CH3​−C≡C−CH3​ on treatment with (i) Na/liq. NH3NH_3NH3​ then (ii) dil. KMnO4KMnO_4KMnO4​ at 273 K gives 'P'. The number of oxygen atoms present in product 'P' is _______ (nearest integer).

Correct answer: 2

Step-by-step solution →
Q56·ChemistryNumerical
Frequency of the de-Broglie wave of an electron in Bohr's first orbit of hydrogen atom is _______ ×1013\times10^{13}×1013 Hz (nearest integer). (Given: RHR_HRH​ (Rydberg constant) =2.18×10−18=2.18\times10^{-18}=2.18×10−18 J; hhh (Planck's constant) =6.6×10−34=6.6\times10^{-34}=6.6×10−34 J s)

Correct answer: 661

Step-by-step solution →
Q57·ChemistryNumerical
The reaction sequence shown in the figure is carried out (starting from the compound in the figure). The total sum of π\piπ electrons in product A and product B is _______ (nearest integer).

Correct answer: 8

Step-by-step solution →
Q58·ChemistryNumerical
Among CrO, Cr2O3Cr_2O_3Cr2​O3​ and CrO3CrO_3CrO3​, the sum of spin-only magnetic moment values of the basic and amphoteric oxides is _______ ×10−2\times10^{-2}×10−2 BM (nearest integer). (Given atomic number of Cr is 24)

Correct answer: 877

Step-by-step solution →
Q59·ChemistryNumerical
An ideal gas, CV=52RC_V = \tfrac{5}{2}RCV​=25​R, is expanded adiabatically against a constant pressure of 1 atm until it doubles in volume. If the initial temperature and pressure are 298 K and 5 atm respectively, then the final temperature is _______ K (nearest integer). (CVC_VCV​ is the molar heat capacity at constant volume)

Correct answer: 274

Step-by-step solution →

Mathematics — JEE Main 6 April 2024 Shift 1

Q60·MathematicsSingle correct
If f(x)=x3sin⁡(1x)f(x)=x^{3}\sin\left(\tfrac{1}{x}\right)f(x)=x3sin(x1​) for x≠0x\neq 0x=0 and f(0)=0f(0)=0f(0)=0, then
  1. (A)f′′(0)=1f''(0)=1f′′(0)=1
  2. (B)f′′(2π)=24−π22πf''\left(\tfrac{2}{\pi}\right)=\tfrac{24-\pi^{2}}{2\pi}f′′(π2​)=2π24−π2​
  3. (C)f′′(2π)=12−π22πf''\left(\tfrac{2}{\pi}\right)=\tfrac{12-\pi^{2}}{2\pi}f′′(π2​)=2π12−π2​
  4. (D)f′′(0)=0f''(0)=0f′′(0)=0

Correct answer: (B)

Step-by-step solution →
Q61·MathematicsSingle correct
If A(3,1,−1)A(3,1,-1)A(3,1,−1), B(53,73,13)B\left(\tfrac{5}{3},\tfrac{7}{3},\tfrac{1}{3}\right)B(35​,37​,31​), C(2,2,1)C(2,2,1)C(2,2,1) and D(103,23,−13)D\left(\tfrac{10}{3},\tfrac{2}{3},-\tfrac{1}{3}\right)D(310​,32​,−31​) are the vertices of a quadrilateral ABCDABCDABCD, then its area is
  1. (A)423\tfrac{4\sqrt{2}}{3}342​​
  2. (B)523\tfrac{5\sqrt{2}}{3}352​​
  3. (C)222\sqrt{2}22​
  4. (D)223\tfrac{2\sqrt{2}}{3}322​​

Correct answer: (A)

Step-by-step solution →
Q62·MathematicsSingle correct
∫0π/4cos⁡2x sin⁡2x(cos⁡3x+sin⁡3x)2 dx\displaystyle\int_{0}^{\pi/4}\frac{\cos^{2}x\,\sin^{2}x}{(\cos^{3}x+\sin^{3}x)^{2}}\,dx∫0π/4​(cos3x+sin3x)2cos2xsin2x​dx is equal to
  1. (A)112\tfrac{1}{12}121​
  2. (B)13\tfrac{1}{3}31​
  3. (C)16\tfrac{1}{6}61​
  4. (D)19\tfrac{1}{9}91​

Correct answer: (C)

Step-by-step solution →
Q63·MathematicsSingle correct
The mean and standard deviation of 20 observations are found to be 10 and 2, respectively. On rechecking, it was found that an observation 8 was incorrect. If 8 is replaced by 12, then the correct standard deviation is
  1. (A)3.86\sqrt{3.86}3.86​
  2. (B)1.81.81.8
  3. (C)3.96\sqrt{3.96}3.96​
  4. (D)1.941.941.94

Correct answer: (C)

Step-by-step solution →
Q64·MathematicsSingle correct
The function f(x)=x2+2x−15x2−4x+9f(x)=\dfrac{x^{2}+2x-15}{x^{2}-4x+9}f(x)=x2−4x+9x2+2x−15​, x∈Rx\in\mathbb{R}x∈R is
  1. (A)both one-one and onto
  2. (B)onto but not one-one
  3. (C)neither one-one nor onto
  4. (D)one-one but not onto

Correct answer: (C)

Step-by-step solution →
Q65·MathematicsSingle correct
Let A={n∈[100,700]∩N:n is neither a multiple of 3 nor a multiple of 4}A=\{n\in[100,700]\cap\mathbb{N}:n\text{ is neither a multiple of 3 nor a multiple of 4}\}A={n∈[100,700]∩N:n is neither a multiple of 3 nor a multiple of 4}. Then the number of elements in AAA is
  1. (A)300300300
  2. (B)280280280
  3. (C)310310310
  4. (D)290290290

Correct answer: (A)

Step-by-step solution →
Q66·MathematicsSingle correct
Let CCC be the circle of minimum area touching the parabola y=6−x2y=6-x^{2}y=6−x2 and the lines y=3 ∣x∣y=\sqrt{3}\,|x|y=3​∣x∣. Then, which one of the following points lies on the circle CCC?
  1. (A)(2,4)(2,4)(2,4)
  2. (B)(1,2)(1,2)(1,2)
  3. (C)(2,2)(2,2)(2,2)
  4. (D)(1,1)(1,1)(1,1)

Correct answer: (A)

Step-by-step solution →
Q67·MathematicsSingle correct
For α,β∈R\alpha,\beta\in\mathbb{R}α,β∈R and a natural number nnn, let Ar=∣r1n22+α2r2n2−β3r−23n(3n−1)2∣A_{r}=\begin{vmatrix} r & 1 & \tfrac{n^{2}}{2}+\alpha \\ 2r & 2 & n^{2}-\beta \\ 3r-2 & 3 & \tfrac{n(3n-1)}{2}\end{vmatrix}Ar​=​r2r3r−2​123​2n2​+αn2−β2n(3n−1)​​​. Then 2A10−A82A_{10}-A_{8}2A10​−A8​ is
  1. (A)4α+2β4\alpha+2\beta4α+2β
  2. (B)2α+4β2\alpha+4\beta2α+4β
  3. (C)2β2\beta2β
  4. (D)000

Correct answer: (A)

Step-by-step solution →
Q68·MathematicsSingle correct
The shortest distance between the lines x−32=y+15−7=z−95\dfrac{x-3}{2}=\dfrac{y+15}{-7}=\dfrac{z-9}{5}2x−3​=−7y+15​=5z−9​ and x+12=y−11=z−9−3\dfrac{x+1}{2}=\dfrac{y-1}{1}=\dfrac{z-9}{-3}2x+1​=1y−1​=−3z−9​ is
  1. (A)656\sqrt{5}65​
  2. (B)434\sqrt{3}43​
  3. (C)535\sqrt{3}53​
  4. (D)838\sqrt{3}83​

Correct answer: (B)

Step-by-step solution →
Q69·MathematicsSingle correct
A company has two plants AAA and BBB to manufacture motorcycles. 60% motorcycles are manufactured at plant AAA and the remaining at plant BBB. 80% of the motorcycles manufactured at plant AAA are of standard quality, while 90% of those manufactured at plant BBB are of standard quality. If ppp is the probability that a motorcycle, found to be of standard quality, is manufactured at plant BBB, then 126p126p126p is
  1. (A)545454
  2. (B)646464
  3. (C)666666
  4. (D)565656

Correct answer: (A)

Step-by-step solution →
Q70·MathematicsSingle correct
Let α,β\alpha,\betaα,β be the distinct roots of the equation x2−(t2−5t+6)x+1=0x^{2}-(t^{2}-5t+6)x+1=0x2−(t2−5t+6)x+1=0, t∈Rt\in\mathbb{R}t∈R and an=αn+βna_{n}=\alpha^{n}+\beta^{n}an​=αn+βn. Then the minimum value of a2023+a2025a2024\dfrac{a_{2023}+a_{2025}}{a_{2024}}a2024​a2023​+a2025​​ is
  1. (A)14\tfrac{1}{4}41​
  2. (B)−12-\tfrac{1}{2}−21​
  3. (C)−14-\tfrac{1}{4}−41​
  4. (D)12\tfrac{1}{2}21​

Correct answer: (C)

Step-by-step solution →
Q71·MathematicsSingle correct
Let the relations R1R_{1}R1​ and R2R_{2}R2​ on the set X={1,2,3,…,20}X=\{1,2,3,\ldots,20\}X={1,2,3,…,20} be given by R1={(x,y):2x−3y=2}R_{1}=\{(x,y):2x-3y=2\}R1​={(x,y):2x−3y=2} and R2={(x,y):−5x+4y=0}R_{2}=\{(x,y):-5x+4y=0\}R2​={(x,y):−5x+4y=0}. If MMM and NNN are the minimum number of elements required to be added in R1R_{1}R1​ and R2R_{2}R2​, respectively, in order to make the relations symmetric, then M+NM+NM+N equals
  1. (A)888
  2. (B)161616
  3. (C)121212
  4. (D)101010

Correct answer: (D)

Step-by-step solution →
Q72·MathematicsSingle correct
Let a variable line of slope m>0m>0m>0 passing through the point (4,−9)(4,-9)(4,−9) intersect the coordinate axes at the points AAA and BBB. The minimum value of the sum of the distances of AAA and BBB from the origin is
  1. (A)252525
  2. (B)303030
  3. (C)151515
  4. (D)101010

Correct answer: (A)

Step-by-step solution →
Q73·MathematicsSingle correct
The interval in which the function f(x)=xxf(x)=x^{x}f(x)=xx, x>0x>0x>0, is strictly increasing is
  1. (A)(0,1e]\left(0,\tfrac{1}{e}\right](0,e1​]
  2. (B)[1e2,1)\left[\tfrac{1}{e^{2}},1\right)[e21​,1)
  3. (C)(0,∞)(0,\infty)(0,∞)
  4. (D)[1e,∞)\left[\tfrac{1}{e},\infty\right)[e1​,∞)

Correct answer: (D)

Step-by-step solution →
Q74·MathematicsSingle correct
A circle is inscribed in an equilateral triangle of side length 12. If the area and perimeter of any square inscribed in this circle are mmm and nnn, respectively, then m+n2m+n^{2}m+n2 is equal to
  1. (A)396396396
  2. (B)408408408
  3. (C)312312312
  4. (D)414414414

Correct answer: (B)

Step-by-step solution →
Q75·MathematicsSingle correct
The number of triangles whose vertices are at the vertices of a regular octagon but none of whose sides is a side of the octagon is
  1. (A)242424
  2. (B)565656
  3. (C)161616
  4. (D)484848

Correct answer: (C)

Step-by-step solution →
Q76·MathematicsSingle correct
Let y=y(x)y=y(x)y=y(x) be the solution of the differential equation (1+x2)dydx+y=etan⁡−1x(1+x^{2})\dfrac{dy}{dx}+y=e^{\tan^{-1}x}(1+x2)dxdy​+y=etan−1x, y(1)=0y(1)=0y(1)=0. Then y(0)y(0)y(0) is
  1. (A)14(eπ/2−1)\tfrac{1}{4}\left(e^{\pi/2}-1\right)41​(eπ/2−1)
  2. (B)12(1−eπ/2)\tfrac{1}{2}\left(1-e^{\pi/2}\right)21​(1−eπ/2)
  3. (C)14(1−eπ/2)\tfrac{1}{4}\left(1-e^{\pi/2}\right)41​(1−eπ/2)
  4. (D)12(eπ/2−1)\tfrac{1}{2}\left(e^{\pi/2}-1\right)21​(eπ/2−1)

Correct answer: (B)

Step-by-step solution →
Q77·MathematicsSingle correct
Let y=y(x)y=y(x)y=y(x) be the solution of the differential equation (2xlog⁡ex)dydx+2y=3xlog⁡ex(2x\log_{e}x)\dfrac{dy}{dx}+2y=\dfrac{3}{x}\log_{e}x(2xloge​x)dxdy​+2y=x3​loge​x, x>0x>0x>0 and y(e−1)=0y(e^{-1})=0y(e−1)=0. Then y(e)y(e)y(e) is equal to
  1. (A)32e\tfrac{3}{2e}2e3​
  2. (B)23e\tfrac{2}{3e}3e2​
  3. (C)−3e-\tfrac{3}{e}−e3​
  4. (D)2e\tfrac{2}{e}e2​

Correct answer: (C)

Step-by-step solution →
Q78·MathematicsSingle correct
Let the area of the region enclosed by the curves y=3xy=3xy=3x, 2y=27−3x2y=27-3x2y=27−3x and y=3x−xxy=3x-x\sqrt{x}y=3x−xx​ be AAA. Then 10A10A10A is equal to
  1. (A)184184184
  2. (B)154154154
  3. (C)172172172
  4. (D)162162162

Correct answer: (D)

Step-by-step solution →
Q79·Mathematics·DifferentiabilitySingle correct
Let f:(−∞,∞)−{0}→Rf:(-\infty,\infty)-\{0\}\to\mathbb{R}f:(−∞,∞)−{0}→R be a differentiable function such that f′(1)=lim⁡a→∞a2f(1a)f'(1)=\displaystyle\lim_{a\to\infty}a^{2}f\left(\tfrac{1}{a}\right)f′(1)=a→∞lim​a2f(a1​). Then lim⁡a→∞a(a+1)2tan⁡−1(1a)+a2−2log⁡ea\displaystyle\lim_{a\to\infty}\frac{a(a+1)}{2}\tan^{-1}\left(\tfrac{1}{a}\right)+a^{2}-2\log_{e}aa→∞lim​2a(a+1)​tan−1(a1​)+a2−2loge​a is equal to
  1. (A)32+π4\tfrac{3}{2}+\tfrac{\pi}{4}23​+4π​
  2. (B)38+π4\tfrac{3}{8}+\tfrac{\pi}{4}83​+4π​
  3. (C)52+π8\tfrac{5}{2}+\tfrac{\pi}{8}25​+8π​
  4. (D)34+π8\tfrac{3}{4}+\tfrac{\pi}{8}43​+8π​

Correct answer: (C)

Step-by-step solution →
Q80·MathematicsNumerical
Let αβγ=45\alpha\beta\gamma=45αβγ=45; α,β,γ∈R\alpha,\beta,\gamma\in\mathbb{R}α,β,γ∈R. If x(α,1,2)+y(1,β,2)+z(2,3,γ)=(0,0,0)x(\alpha,1,2)+y(1,\beta,2)+z(2,3,\gamma)=(0,0,0)x(α,1,2)+y(1,β,2)+z(2,3,γ)=(0,0,0) for some x,y,z∈Rx,y,z\in\mathbb{R}x,y,z∈R, xyz≠0xyz\neq 0xyz=0, then 6α+4β+γ6\alpha+4\beta+\gamma6α+4β+γ is equal to _______.

Correct answer: 55

Step-by-step solution →
Q81·MathematicsNumerical
Let a conic CCC pass through the point (4,−2)(4,-2)(4,−2) and P(x,y)P(x,y)P(x,y), x≥3x\geq 3x≥3, be any point on CCC. Let the slope of the line touching the conic CCC only at a single point PPP be half the slope of the line joining the points PPP and (3,−5)(3,-5)(3,−5). If the focal distance of the point (7,1)(7,1)(7,1) on CCC is ddd, then 12d12d12d equals _______.

Correct answer: 75

Step-by-step solution →
Q82·MathematicsNumerical
Let rk=∫01(1−x7)k dx∫01(1−x7)k+1 dxr_{k}=\dfrac{\int_{0}^{1}(1-x^{7})^{k}\,dx}{\int_{0}^{1}(1-x^{7})^{k+1}\,dx}rk​=∫01​(1−x7)k+1dx∫01​(1−x7)kdx​, k∈Nk\in\mathbb{N}k∈N. Then the value of ∑k=11017(rk−1)\displaystyle\sum_{k=1}^{10}\frac{1}{7(r_{k}-1)}k=1∑10​7(rk​−1)1​ is equal to _______.

Correct answer: 65

Step-by-step solution →
Q83·MathematicsNumerical
Let x1,x2,x3,x4x_{1},x_{2},x_{3},x_{4}x1​,x2​,x3​,x4​ be the solution of the equation 4x4+8x3−17x2−12x+9=04x^{4}+8x^{3}-17x^{2}-12x+9=04x4+8x3−17x2−12x+9=0 and (4+x12)(4+x22)(4+x32)(4+x42)=12516m(4+x_{1}^{2})(4+x_{2}^{2})(4+x_{3}^{2})(4+x_{4}^{2})=\dfrac{125}{16}m(4+x12​)(4+x22​)(4+x32​)(4+x42​)=16125​m. Then the value of mmm is _______.

Correct answer: 221

Step-by-step solution →
Q84·MathematicsNumerical
Let L1,L2L_{1},L_{2}L1​,L2​ be the lines passing through the point P(0,1)P(0,1)P(0,1) and touching the parabola 9x2+12x+18y−14=09x^{2}+12x+18y-14=09x2+12x+18y−14=0. Let QQQ and RRR be the points on the lines L1L_{1}L1​ and L2L_{2}L2​ such that △PQR\triangle PQR△PQR is an isosceles triangle with base QRQRQR. If the slopes of the lines QRQRQR are m1m_{1}m1​ and m2m_{2}m2​, then 16(m12+m22)16(m_{1}^{2}+m_{2}^{2})16(m12​+m22​) is equal to _______.

Correct answer: 68

Step-by-step solution →
Q85·MathematicsNumerical
If the second, third and fourth terms in the expansion of (x+y)n(x+y)^{n}(x+y)n are 135, 30 and 103\dfrac{10}{3}310​, respectively, then 6(n3+x2+y)6(n^{3}+x^{2}+y)6(n3+x2+y) is equal to _______.

Correct answer: 806

Step-by-step solution →
Q86·MathematicsNumerical
Let the first term of a series be T1=6T_{1}=6T1​=6 and its rthr^{\text{th}}rth term Tr=3Tr−1+6rT_{r}=3T_{r-1}+6^{r}Tr​=3Tr−1​+6r, r=2,3,…,nr=2,3,\ldots,nr=2,3,…,n. If the sum of the first nnn terms of this series is 15(n2−12n+39)(4⋅6n−5⋅3n+1)\dfrac{1}{5}(n^{2}-12n+39)(4\cdot 6^{n}-5\cdot 3^{n}+1)51​(n2−12n+39)(4⋅6n−5⋅3n+1), then nnn is equal to _______.

Correct answer: 6

Step-by-step solution →
Q87·MathematicsNumerical
For n∈Nn\in\mathbb{N}n∈N, if cot⁡−13+cot⁡−14+cot⁡−15+cot⁡−1n=π4\cot^{-1}3+\cot^{-1}4+\cot^{-1}5+\cot^{-1}n=\dfrac{\pi}{4}cot−13+cot−14+cot−15+cot−1n=4π​, then nnn is equal to _______.

Correct answer: 47

Step-by-step solution →
Q88·MathematicsNumerical
Let PPP be the point (10,−2,−1)(10,-2,-1)(10,−2,−1) and QQQ be the foot of the perpendicular drawn from the point R(1,7,6)R(1,7,6)R(1,7,6) on the line passing through the points (2,−5,11)(2,-5,11)(2,−5,11) and (−6,7,−5)(-6,7,-5)(−6,7,−5). Then the length of the line segment PQPQPQ is equal to _______.

Correct answer: 13

Step-by-step solution →
Q89·MathematicsNumerical
Let a⃗=2i^−3j^+4k^\vec{a}=2\hat{i}-3\hat{j}+4\hat{k}a=2i^−3j^​+4k^, b⃗=3i^+4j^−5k^\vec{b}=3\hat{i}+4\hat{j}-5\hat{k}b=3i^+4j^​−5k^, and a vector c⃗\vec{c}c be such that a⃗×(b⃗+c⃗)+b⃗×c⃗=i^+8j^+13k^\vec{a}\times(\vec{b}+\vec{c})+\vec{b}\times\vec{c}=\hat{i}+8\hat{j}+13\hat{k}a×(b+c)+b×c=i^+8j^​+13k^. If a⃗⋅c⃗=13\vec{a}\cdot\vec{c}=13a⋅c=13, then 24−b⃗⋅c⃗24-\vec{b}\cdot\vec{c}24−b⋅c is equal to _______.

Correct answer: 46

Step-by-step solution →

Chapters tested in this paper

Open any chapter to practise every past-year question on that topic across all papers, and see how often it has actually appeared.

  • Properties of Solids and Liquids 172/186
  • Three Dimensional Geometry 176/186
  • Matrices and Determinants 180/186
  • Coordination Compounds 176/186
  • Sets, Relations and Functions 165/186
  • Current Electricity 160/186
  • Sequence and Series 164/186
  • p-Block Elements 164/186
  • Definite Integration 168/186
  • Rotational Motion 172/186
  • Redox Reactions and Electrochemistry 177/186
  • Geometrical Optics 172/186
  • Kinematics 156/186
  • Vector Algebra 173/186
  • Differential Equations 167/186
  • Probability 176/186
  • Permutations and Combinations 162/186
  • Magnetic Field of Current 147/186
  • Binomial Theorem and Its Simple Applications 158/186
  • Electromagnetic Waves 144/186
  • Chemical Bonding and Molecular Structure 151/186
  • Application of Derivatives 139/186
  • d- and f-Block Elements 126/186
  • Thermodynamics 154/186
  • Aldehydes and Ketones 135/186
  • Equilibrium 163/186
  • Solutions 158/186
  • Laws of Motion 130/186
  • Chemical Thermodynamics 165/186
  • Units and Measurements 149/186
  • Hydrocarbons 126/186
  • Trigonometric Functions 144/186
  • Biomolecules 162/186
  • Chemical Kinetics 169/186
  • Gravitation 152/186
  • Electric Field and Coulomb's Law 133/186
  • Atomic Structure 161/186
  • Circles 142/186
  • Dual Nature of Matter and Radiation 155/186
  • Quadratic Equations 148/186
  • Work, Energy and Power 132/186
  • Area Under Curves 139/186
  • Kinetic Theory of Gases 135/186
  • Alcohols and Ethers 106/186
  • Purification and Characterisation of Organic Compounds 116/186
  • Oscillations 117/186
  • Alternating Currents 108/186
  • Organic Compounds Containing Halogens 109/186
  • Straight Lines 114/186
  • Atoms 112/186
  • Classification of Elements and Periodicity in Properties 113/186
  • Parabola 101/186
  • Statistics 118/186
  • Differentiability 91/186
  • Inverse Trigonometric Functions 93/186
  • Experimental Skills 68/186
  • Solid State 63/186
  • Principles of Qualitative Analysis 58/186
  • Diazonium Salts and Reactions 53/186
  • Isomerism 51/186
  • IUPAC Nomenclature 37/186
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