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JEE Main 5 April 2024 Shift 2 Question Paper with Answers

5 April 2024 · April session · 89 questions

89 of the 90 questions from the JEE Main 5 April 2024 Shift 2 paper, each with its correct answer and tagged to the chapter it tests. Free to read, no account needed.

1 question is held back from this paper while we re-check the transcription or the answer key. We would rather show you nothing than show you an answer we are not confident is right.

Physics
30
Chemistry
29
Mathematics
30

Physics — JEE Main 5 April 2024 Shift 2

Q1·PhysicsSingle correct
Given below are two statements: Statement I: When white light is passed through a prism, the red light bends lesser than yellow and violet. Statement II: The refractive indices are different for different wavelengths in a dispersive medium. In the light of the above statements, choose the correct answer from the options given below:
  1. (A)Both Statement I and Statement II are true.
  2. (B)Statement I is true but Statement II is false.
  3. (C)Both Statement I and Statement II are false.
  4. (D)Statement I is false but Statement II is true.

Correct answer: (A)

Step-by-step solution →
Q2·PhysicsSingle correct
Which of the following statements is not true about stopping potential (V0)(V_0)(V0​)?
  1. (A)It depends on the nature of emitter material.
  2. (B)It depends upon the frequency of the incident light.
  3. (C)It increases with increase in intensity of the incident light.
  4. (D)It is 1e\tfrac{1}{e}e1​ times the maximum kinetic energy of electrons emitted.

Correct answer: (C)

Step-by-step solution →
Q3·PhysicsSingle correct
The angular momentum of an electron in a hydrogen atom is proportional to: (where rrr is the radius of the orbit of the electron)
  1. (A)r\sqrt{r}r​
  2. (B)1r\dfrac{1}{r}r1​
  3. (C)rrr
  4. (D)1r\dfrac{1}{\sqrt{r}}r​1​

Correct answer: (A)

Step-by-step solution →
Q4·PhysicsSingle correct
A galvanometer of resistance 100 Ω100\,\Omega100Ω, when connected in series with 400 Ω400\,\Omega400Ω, measures a voltage of upto 10 V. The value of resistance required to convert the galvanometer into an ammeter to read upto 10 A is x×10−2 Ωx\times10^{-2}\,\Omegax×10−2Ω. The value of xxx is:
  1. (A)2
  2. (B)800
  3. (C)20
  4. (D)200

Correct answer: (C)

Step-by-step solution →
Q5·PhysicsSingle correct
The vehicles carrying inflammable fluids usually have metallic chains touching the ground:
  1. (A)To conduct excess charge due to air friction to the ground and prevent sparking.
  2. (B)To alert other vehicles.
  3. (C)To protect tyres from catching dirt from the ground.
  4. (D)It is a custom.

Correct answer: (A)

Step-by-step solution →
Q6·PhysicsSingle correct
If nnn is the number density and ddd is the diameter of the molecule, then the average distance covered by a molecule between two successive collisions (i.e. mean free path) is represented by:
  1. (A)12nπd2\dfrac{1}{\sqrt{2n\pi d^2}}2nπd2​1​
  2. (B)2 nπd2\sqrt{2}\,n\pi d^22​nπd2
  3. (C)12 nπd2\dfrac{1}{\sqrt{2}\,n\pi d^2}2​nπd21​
  4. (D)12 n2π2d2\dfrac{1}{\sqrt{2}\,n^2\pi^2 d^2}2​n2π2d21​

Correct answer: (C)

Step-by-step solution →
Q7·PhysicsSingle correct
A particle moves in the x-y plane under the influence of a force F⃗\vec{F}F such that its linear momentum is P⃗(t)=i^cos⁡(kt)−j^sin⁡(kt)\vec{P}(t)=\hat{i}\cos(kt)-\hat{j}\sin(kt)P(t)=i^cos(kt)−j^​sin(kt). If kkk is constant, the angle between F⃗\vec{F}F and P⃗\vec{P}P will be:
  1. (A)π2\dfrac{\pi}{2}2π​
  2. (B)π6\dfrac{\pi}{6}6π​
  3. (C)π4\dfrac{\pi}{4}4π​
  4. (D)π3\dfrac{\pi}{3}3π​

Correct answer: (A)

Step-by-step solution →
Q8·PhysicsSingle correct
The electrostatic force (F1⃗)(\vec{F_1})(F1​​) and magnetic force (F2⃗)(\vec{F_2})(F2​​) acting on a charge qqq moving with velocity v⃗\vec{v}v can be written as:
  1. (A)F1⃗=q(V⃗⋅E⃗)\vec{F_1}=q(\vec{V}\cdot\vec{E})F1​​=q(V⋅E), F2⃗=q(B⃗⋅V⃗)\vec{F_2}=q(\vec{B}\cdot\vec{V})F2​​=q(B⋅V)
  2. (B)F1⃗=qB⃗\vec{F_1}=q\vec{B}F1​​=qB, F2⃗=q(B⃗×V⃗)\vec{F_2}=q(\vec{B}\times\vec{V})F2​​=q(B×V)
  3. (C)F1⃗=qE⃗\vec{F_1}=q\vec{E}F1​​=qE, F2⃗=q(V⃗×B⃗)\vec{F_2}=q(\vec{V}\times\vec{B})F2​​=q(V×B)
  4. (D)F1⃗=qE⃗\vec{F_1}=q\vec{E}F1​​=qE, F2⃗=q(B⃗×V⃗)\vec{F_2}=q(\vec{B}\times\vec{V})F2​​=q(B×V)

Correct answer: (C)

Step-by-step solution →
Q9·PhysicsSingle correct
A man carrying a monkey on his shoulder does cycling smoothly on a circular track of radius 9 m and completes 120 revolutions in 3 minutes. The magnitude of the centripetal acceleration of the monkey is (in m/s2^22):
  1. (A)zero
  2. (B)16π216\pi^216π2 ms−2^{-2}−2
  3. (C)4π24\pi^24π2 ms−2^{-2}−2
  4. (D)57600π257600\pi^257600π2 ms−2^{-2}−2

Correct answer: (B)

Step-by-step solution →
Q10·PhysicsSingle correct
A series LCR circuit is subjected to an AC signal of 200 V, 50 Hz. If the voltage across the inductor (L=10L=10L=10 mH) is 31.4 V, then the current in this circuit is __________:
  1. (A)68 A
  2. (B)63 A
  3. (C)10 A
  4. (D)10 mA

Correct answer: (C)

Step-by-step solution →
Q11·PhysicsSingle correct
What is the dimensional formula of ab−1ab^{-1}ab−1 in the equation (P+aV2)(V−b)=RT\left(P+\dfrac{a}{V^2}\right)(V-b)=RT(P+V2a​)(V−b)=RT, where the letters have their usual meaning?
  1. (A)[M0L3T−2][M^0L^3T^{-2}][M0L3T−2]
  2. (B)[ML2T−2][ML^2T^{-2}][ML2T−2]
  3. (C)[M−1L5T3][M^{-1}L^5T^3][M−1L5T3]
  4. (D)[M6L7T4][M^6L^7T^4][M6L7T4]

Correct answer: (B)

Step-by-step solution →
Q12·PhysicsSingle correct
The output (Y) of the logic circuit given below is 0 only when:
  1. (A)A = 1, B = 0
  2. (B)A = 0, B = 0
  3. (C)A = 1, B = 1
  4. (D)A = 0, B = 1

Correct answer: (B)

Step-by-step solution →
Q13·PhysicsSingle correct
A body is moving unidirectionally under the influence of a constant power source. Its displacement in time ttt is proportional to:
  1. (A)t2t^2t2
  2. (B)t2/3t^{2/3}t2/3
  3. (C)t3/2t^{3/2}t3/2
  4. (D)ttt

Correct answer: (C)

Step-by-step solution →
Q14·PhysicsSingle correct
Match List-I (electromagnetic wave) with List-II (wavelength range). Choose the correct answer from the options given below:
List-I (EM-Wave)List-II (Wavelength Range)
A.Infra-redI.<10−3<10^{-3}<10−3 nm
B.UltravioletII.400 nm to 1 nm
C.X-raysIII.1 mm to 700 nm
D.Gamma raysIV.1 nm to 10−310^{-3}10−3 nm
  1. (A)(A)-(II), (B)-(I), (C)-(IV), (D)-(III)
  2. (B)(A)-(III), (B)-(II), (C)-(IV), (D)-(I)
  3. (C)(A)-(IV), (B)-(III), (C)-(II), (D)-(I)
  4. (D)(A)-(I), (B)-(III), (C)-(II), (D)-(IV)

Correct answer: (B)

Step-by-step solution →
Q15·PhysicsSingle correct
During an adiabatic process, if the pressure of a gas is found to be proportional to the cube of its absolute temperature, then the ratio CPCV\dfrac{C_P}{C_V}CV​CP​​ for the gas is:
  1. (A)53\dfrac{5}{3}35​
  2. (B)97\dfrac{9}{7}79​
  3. (C)32\dfrac{3}{2}23​
  4. (D)75\dfrac{7}{5}57​

Correct answer: (C)

Step-by-step solution →
Q16·PhysicsSingle correct
Match List-I (description of an elastic deformation) with List-II (corresponding modulus or quantity). Choose the correct answer from the options given below:
List-IList-II
A.A force that restores an elastic body of unit area to its original stateI.Bulk modulus
B.Two equal and opposite forces parallel to opposite facesII.Young's modulus
C.Forces perpendicular everywhere to the surface, per unit area, same everywhereIII.Stress
D.Two equal and opposite forces perpendicular to opposite facesIV.Shear modulus
  1. (A)(A)-(II), (B)-(IV), (C)-(I), (D)-(III)
  2. (B)(A)-(IV), (B)-(II), (C)-(III), (D)-(I)
  3. (C)(A)-(III), (B)-(IV), (C)-(I), (D)-(II)
  4. (D)(A)-(III), (B)-(I), (C)-(II), (D)-(IV)

Correct answer: (C)

Step-by-step solution →
Q17·PhysicsSingle correct
A vernier callipers has 20 divisions on the vernier scale, which coincide with the 19th division on the main scale. The least count of the instrument is 0.1 mm. One main scale division is equal to __________ mm.
  1. (A)1
  2. (B)0.5
  3. (C)2
  4. (D)5

Correct answer: (C)

Step-by-step solution →
Q18·PhysicsSingle correct
A heavy box of mass 50 kg is moving on a horizontal surface. If the coefficient of kinetic friction between the box and the horizontal surface is 0.3, then the force of kinetic friction is: (Take g=9.8g=9.8g=9.8 m/s2^22)
  1. (A)14.7 N
  2. (B)147 N
  3. (C)1.47 N
  4. (D)1470 N

Correct answer: (B)

Step-by-step solution →
Q19·PhysicsSingle correct
A satellite revolving around a planet in a stationary orbit has a time period of 6 hours. The mass of the planet is one-fourth the mass of the earth. The radius of the orbit of the planet is: (Given: radius of the geo-stationary orbit for earth is 4.2×1044.2\times10^44.2×104 km)
  1. (A)1.4×1041.4\times10^41.4×104 km
  2. (B)8.4×1048.4\times10^48.4×104 km
  3. (C)1.68×1051.68\times10^51.68×105 km
  4. (D)1.05×1041.05\times10^41.05×104 km

Correct answer: (D)

Step-by-step solution →
Q20·PhysicsSingle correct
The ratio of heat dissipated per second through the resistances 5 Ω5\,\Omega5Ω and 10 Ω10\,\Omega10Ω in the circuit given below is:
  1. (A)1 : 2
  2. (B)2 : 1
  3. (C)4 : 1
  4. (D)1 : 1

Correct answer: (B)

Step-by-step solution →
Q21·PhysicsNumerical
A solenoid of length 0.5 m has a radius of 1 cm and is made up of mmm number of turns. It carries a current of 5 A. If the magnitude of the magnetic field inside the solenoid is 6.28×10−36.28\times10^{-3}6.28×10−3 T, then the value of mmm is __________.

Correct answer: 500

Step-by-step solution →
Q22·PhysicsNumerical
The shortest wavelength of the spectral lines in the Lyman series of the hydrogen spectrum is 915 Å. The longest wavelength of the spectral lines in the Balmer series will be __________ Å.

Correct answer: 6588

Step-by-step solution →
Q23·PhysicsNumerical
In a single slit experiment, a parallel beam of green light of wavelength 550 nm passes through a slit of width 0.20 mm. The transmitted light is collected on a screen 100 cm away. The distance of the first order minima from the central maximum will be x×10−5x\times10^{-5}x×10−5 m. The value of xxx is __________.

Correct answer: 275

Step-by-step solution →
Q24·PhysicsNumerical
A sonometer wire of resonating length 90 cm has a fundamental frequency of 400 Hz when kept under some tension. The resonating length of the wire with a fundamental frequency of 600 Hz under the same tension is __________ cm.

Correct answer: 60

Step-by-step solution →
Q25·PhysicsNumerical
A hollow sphere is rolling on a plane surface about its axis of symmetry. The ratio of its rotational kinetic energy to its total kinetic energy is x5\dfrac{x}{5}5x​. The value of xxx is __________.

Correct answer: 2

Step-by-step solution →
Q26·PhysicsNumerical
A hydraulic press containing water has two arms with diameters 14 cm and 1.4 cm. A force of 10 N is applied on the surface of water in the thinner arm (diameter 1.4 cm). The force required to be applied on the surface of water in the thicker arm (diameter 14 cm) to maintain equilibrium of water is __________ N.

Correct answer: 1000

Step-by-step solution →
Q27·PhysicsNumerical
The electric field at a point P, at a distance rrr on the axial line of a short electric dipole, is E. The electric field at a point R, at a distance 2r2r2r on the equatorial line of the same dipole, will be Ex\dfrac{E}{x}xE​. The value of xxx is __________.

Correct answer: 16

Step-by-step solution →
Q28·PhysicsNumerical
The maximum height reached by a projectile is 64 m. If the initial velocity is halved, the new maximum height of the projectile is __________ m.

Correct answer: 16

Step-by-step solution →
Q29·PhysicsNumerical
A wire of resistance 20 Ω20\,\Omega20Ω is divided into 10 equal parts. A combination of two parts is connected in parallel, and so on. Now the resulting pairs of parallel combinations are connected in series. The equivalent resistance of the final combination is __________ Ω\OmegaΩ.

Correct answer: 5

Step-by-step solution →
Q30·PhysicsNumerical
The current in an inductor is given by I=(3t+8)I=(3t+8)I=(3t+8), where ttt is in seconds. The magnitude of the induced emf produced in the inductor is 12 mV. The self-inductance of the inductor is __________ mH.

Correct answer: 4

Step-by-step solution →

Chemistry — JEE Main 5 April 2024 Shift 2

Q31·ChemistrySingle correct
Match List-I (interhalogen / halogen species) with List-II (molecular shape). Choose the correct answer from the options given below:
List-IList-II
A.ICl\text{ICl}IClI.T-Shape
B.ICl3\text{ICl}_3ICl3​II.Square pyramidal
C.ClF5\text{ClF}_5ClF5​III.Pentagonal bipyramidal
D.IF7\text{IF}_7IF7​IV.Linear
  1. (A)(A)-(I), (B)-(IV), (C)-(III), (D)-(II)
  2. (B)(A)-(I), (B)-(III), (C)-(II), (D)-(IV)
  3. (C)(A)-(IV), (B)-(I), (C)-(II), (D)-(III)
  4. (D)(A)-(IV), (B)-(III), (C)-(II), (D)-(I)

Correct answer: (C)

Step-by-step solution →
Q32·ChemistrySingle correct
While preparing crystals of Mohr's salt, dil. H2SO4\text{H}_2\text{SO}_4H2​SO4​ is added to a mixture of ferrous sulphate and ammonium sulphate before dissolving this mixture in water. Dil. H2SO4\text{H}_2\text{SO}_4H2​SO4​ is added here to:
  1. (A)prevent the hydrolysis of ferrous sulphate
  2. (B)prevent the hydrolysis of ammonium sulphate
  3. (C)make the medium strongly acidic
  4. (D)increase the rate of formation of crystals

Correct answer: (A)

Step-by-step solution →
Q33·ChemistrySingle correct
1-Bromo-1-methylcyclopentane is heated with sodium ethoxide (NaOEt) in ethanol (C2H5OH\text{C}_2\text{H}_5\text{OH}C2​H5​OH). Identify the major product formed from the structures shown:
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (C)

Step-by-step solution →
Q34·Chemistry·IUPAC NomenclatureSingle correct
The correct IUPAC nomenclature for the compound shown below is:
  1. (A)2-carboxy-4-hydroxyhept-6-enal
  2. (B)2-carboxy-4-hydroxyhept-7-enal
  3. (C)2-formyl-4-hydroxyhept-6-enoic acid
  4. (D)2-formyl-4-hydroxyhept-7-enoic acid

Correct answer: (C)

Step-by-step solution →
Q35·ChemistrySingle correct
Given below are two statements: one is labelled as Assertion (A) and the other is labelled as Reason (R). Assertion (A): NH3\text{NH}_3NH3​ and NF3\text{NF}_3NF3​ molecules have a pyramidal shape with a lone pair of electrons on the nitrogen atom. The resultant dipole moment of NH3\text{NH}_3NH3​ is greater than that of NF3\text{NF}_3NF3​. Reason (R): In NH3\text{NH}_3NH3​, the orbital dipole due to the lone pair is in the same direction as the resultant dipole moment of the N–H bonds; F is the most electronegative element. In the light of the above statements, choose the correct answer from the options given below:
  1. (A)Both (A) and (R) are true and (R) is the correct explanation of (A)
  2. (B)(A) is false but (R) is true
  3. (C)(A) is true but (R) is false
  4. (D)Both (A) and (R) are true but (R) is NOT the correct explanation of (A)

Correct answer: (A)

Step-by-step solution →
Q36·ChemistrySingle correct
The metal atom present in the complex MABXL (where A, B, X and L are unidentate ligands and M is the metal) involves sp3sp^3sp3 hybridization. The number of geometrical isomers exhibited by the complex is:
  1. (A)4
  2. (B)0
  3. (C)2
  4. (D)3

Correct answer: (B)

Step-by-step solution →
Q37·Chemistry·IsomerismSingle correct
Match List-I (pair of compounds) with List-II (type of isomerism). Choose the correct answer from the options given below:
List-I (Pair of Compounds)List-II (Isomerism)
A.n-Propanol and isopropanolI.Metamerism
B.Methoxypropane and ethoxyethaneII.Chain isomerism
C.Propanone and propanalIII.Position isomerism
D.Neopentane and isopentaneIV.Functional isomerism
  1. (A)(A)-(II), (B)-(I), (C)-(IV), (D)-(III)
  2. (B)(A)-(III), (B)-(I), (C)-(II), (D)-(IV)
  3. (C)(A)-(I), (B)-(III), (C)-(IV), (D)-(II)
  4. (D)(A)-(III), (B)-(I), (C)-(IV), (D)-(II)

Correct answer: (D)

Step-by-step solution →
Q38·ChemistrySingle correct
The quantity of silver deposited when one coulomb of charge is passed through AgNO3\text{AgNO}_3AgNO3​ solution is:
  1. (A)0.1 g atom of silver
  2. (B)1 chemical equivalent of silver
  3. (C)1 g of silver
  4. (D)1 electrochemical equivalent of silver

Correct answer: (D)

Step-by-step solution →
Q39·ChemistrySingle correct
Which one of the following reactions is NOT possible?
  1. (A)Anisole + HBr → Phenol
  2. (B)Phenol + HCl → Chlorobenzene
  3. (C)Chlorobenzene + NaOH (high temperature), then H+ → Phenol
  4. (D)Anisole + Cl2/AlCl3 → 4-Chloroanisole

Correct answer: (B)

Step-by-step solution →
Q40·ChemistrySingle correct
Given below are two statements: Statement I: The metallic radius of Na is 1.86 Å and the ionic radius of Na+\text{Na}^+Na+ is lesser than 1.86 Å. Statement II: Ions are always smaller in size than the corresponding elements. In the light of the above statements, choose the correct answer from the options given below:
  1. (A)Statement I is correct but Statement II is false
  2. (B)Both Statement I and Statement II are true
  3. (C)Both Statement I and Statement II are false
  4. (D)Statement I is incorrect but Statement II is true

Correct answer: (A)

Step-by-step solution →
Q41·Chemistry·Carboxylic Acids and DerivativesSingle correct
CH3CH2OH\text{CH}_3\text{CH}_2\text{OH}CH3​CH2​OH is treated successively with (i) Jones' reagent, (ii) KMnO4\text{KMnO}_4KMnO4​, (iii) NaOH, CaO, Δ\DeltaΔ. Consider the above reaction sequence and identify the major product P.
  1. (A)Methane
  2. (B)Methanal
  3. (C)Methoxymethane
  4. (D)Methanoic acid

Correct answer: (A)

Step-by-step solution →
Q42·ChemistrySingle correct
When cyclohexene is treated with KMnO4\text{KMnO}_4KMnO4​–H2SO4\text{H}_2\text{SO}_4H2​SO4​ and heated, the product "A" is:
  1. (A)picric acid
  2. (B)oxalic acid
  3. (C)acetic acid
  4. (D)adipic acid

Correct answer: (D)

Step-by-step solution →
Q43·ChemistrySingle correct
For the electrochemical cell M ∣ M2+ ∣∣ X ∣ X2−M\,|\,M^{2+}\,||\,X\,|\,X^{2-}M∣M2+∣∣X∣X2−, if E(M2+/M)∘=0.46E^\circ_{(M^{2+}/M)} = 0.46E(M2+/M)∘​=0.46 V and E(X/X2−)∘=0.34E^\circ_{(X/X^{2-})} = 0.34E(X/X2−)∘​=0.34 V, which of the following is correct?
  1. (A)Ecell=−0.80E_{cell} = -0.80Ecell​=−0.80 V
  2. (B)M+X→M2++X2−M + X \rightarrow M^{2+} + X^{2-}M+X→M2++X2− is a spontaneous reaction
  3. (C)M2++X2−→M+XM^{2+} + X^{2-} \rightarrow M + XM2++X2−→M+X is a spontaneous reaction
  4. (D)Ecell=0.80E_{cell} = 0.80Ecell​=0.80 V

Correct answer: (C)

Step-by-step solution →
Q44·ChemistrySingle correct
The number of moles of methane required to produce 11 g of CO2\text{CO}_2CO2​(g) after complete combustion is: (Given molar mass of methane = 16 g mol−1^{-1}−1)
  1. (A)0.75
  2. (B)0.25
  3. (C)0.35
  4. (D)0.5

Correct answer: (B)

Step-by-step solution →
Q45·ChemistrySingle correct
The number of complexes from the following with no electrons in the t2t_2t2​ orbital is: TiCl4\text{TiCl}_4TiCl4​, [MnO4]−[\text{MnO}_4]^-[MnO4​]−, [FeO4]2−[\text{FeO}_4]^{2-}[FeO4​]2−, [FeCl4]−[\text{FeCl}_4]^-[FeCl4​]−, [CoCl4]2−[\text{CoCl}_4]^{2-}[CoCl4​]2−.
  1. (A)3
  2. (B)1
  3. (C)4
  4. (D)2

Correct answer: (A)

Step-by-step solution →
Q46·ChemistrySingle correct
The number of ions from the following that have the ability to liberate hydrogen from a dilute acid is: Ti2+\text{Ti}^{2+}Ti2+, Cr2+\text{Cr}^{2+}Cr2+ and V2+\text{V}^{2+}V2+.
  1. (A)0
  2. (B)2
  3. (C)3
  4. (D)1

Correct answer: (C)

Step-by-step solution →
Q47·Chemistry·Carboxylic Acids and DerivativesSingle correct
Benzene reacts with succinic anhydride in the presence of anhydrous AlCl3\text{AlCl}_3AlCl3​ (Friedel-Crafts acylation) to give (A). Compound (A), on Clemmensen reduction (Zn-Hg/HCl) followed by acidic work-up (H+\text{H}^+H+), gives (B). Identify (A) and (B) from the structures shown:
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (B)

Step-by-step solution →
Q48·ChemistrySingle correct
The correct statements from the following are: (A) The decreasing order of atomic radii of group 13 elements is Tl > In > Ga > Al > B. (B) Down group 13, electronegativity decreases from top to bottom. (C) Al dissolves in dil. HCl and liberates H2\text{H}_2H2​, but conc. HNO3\text{HNO}_3HNO3​ renders Al passive by forming a protective oxide layer on the surface. (D) All elements of group 13 exhibit a highly stable +1 oxidation state. (E) The hybridisation of Al in [Al(H2O)6]3+[\text{Al}(\text{H}_2\text{O})_6]^{3+}[Al(H2​O)6​]3+ ion is sp3d2sp^3d^2sp3d2. Choose the correct answer from the options given below:
  1. (A)(C) and (E) only
  2. (B)(A), (C) and (E) only
  3. (C)(A), (B), (C) and (E) only
  4. (D)(A) and (C) only

Correct answer: (A)

Step-by-step solution →
Q49·ChemistrySingle correct
Coagulation of egg, on heating, is because of:
  1. (A)Denaturation of protein occurs
  2. (B)The secondary structure of protein remains unchanged
  3. (C)Breaking of the peptide linkage in the primary structure of protein occurs
  4. (D)Biological property of protein remains unchanged

Correct answer: (A)

Step-by-step solution →
Q50·ChemistryNumerical
Combustion of 1 mole of benzene is expressed as C6H6(l)+152O2(g)→6CO2(g)+3H2O(l)\text{C}_6\text{H}_6(l) + \tfrac{15}{2}\text{O}_2(g) \rightarrow 6\text{CO}_2(g) + 3\text{H}_2\text{O}(l)C6​H6​(l)+215​O2​(g)→6CO2​(g)+3H2​O(l). The standard enthalpy of combustion of 2 mol of benzene is −x-x−x kJ. Given: standard enthalpy of formation of C6H6(l)\text{C}_6\text{H}_6(l)C6​H6​(l) is +48.5+48.5+48.5 kJ mol−1^{-1}−1, of CO2(g)\text{CO}_2(g)CO2​(g) is −393.5-393.5−393.5 kJ mol−1^{-1}−1, and of H2O(l)\text{H}_2\text{O}(l)H2​O(l) is −286-286−286 kJ mol−1^{-1}−1. The value of xxx is __________.

Correct answer: 6535

Step-by-step solution →
Q51·ChemistryNumerical
The fusion of chromite ore with sodium carbonate in the presence of air leads to the formation of products A and B along with the evolution of CO2\text{CO}_2CO2​. The sum of the spin-only magnetic moment values of A and B is __________ B.M. (Nearest integer). (Given atomic numbers: C: 6, Na: 11, O: 8, Fe: 26, Cr: 24)

Correct answer: 6

Step-by-step solution →
Q52·ChemistryNumerical
X g of ethanamine was subjected to reaction with NaNO2\text{NaNO}_2NaNO2​/HCl, followed by hydrolysis to liberate N2\text{N}_2N2​ and HCl. The HCl generated was completely neutralised by 0.2 moles of NaOH. X is __________ g.

Correct answer: 9

Step-by-step solution →
Q53·ChemistryNumerical
In an atom, the total number of electrons having quantum numbers n=4n = 4n=4, ∣ml∣=1|m_l| = 1∣ml​∣=1 and ms=−12m_s = -\tfrac{1}{2}ms​=−21​ is __________.

Correct answer: 6

Step-by-step solution →
Q54·Chemistry·Purification and Characterisation of Organic CompoundsNumerical
In a paper chromatography experiment, the solvent front rises to 12.5 cm. From the base line, sample A rises to 5.0 cm and sample C rises to 10.0 cm. The ratio of the RfR_fRf​ values of sample A and sample C is x×10−2x \times 10^{-2}x×10−2. The value of xxx is __________.

Correct answer: 50

Step-by-step solution →
Q55·Chemistry·Aldehydes and KetonesNumerical
In the Claisen-Schmidt reaction to prepare 351 g of dibenzalacetone using 87 g of acetone, the amount of benzaldehyde required is __________ g. (Nearest integer)

Correct answer: 318

Step-by-step solution →
Q56·ChemistryNumerical
Consider the following single step reaction in the gas phase at constant temperature: 2A(g)+B(g)→C(g)2A(g) + B(g) \rightarrow C(g)2A(g)+B(g)→C(g). The initial rate of the reaction is recorded as r1r_1r1​ when the reaction starts with 1.5 atm pressure of A and 0.7 atm pressure of B. After some time, the rate r2r_2r2​ is recorded when the pressure of C becomes 0.5 atm. The ratio r1:r2r_1 : r_2r1​:r2​ is __________ ×10−1\times 10^{-1}×10−1. (Nearest integer)

Correct answer: 315

Step-by-step solution →
Q57·Chemistry·Carboxylic Acids and DerivativesNumerical
The product C in the following sequence of reactions has __________ π\piπ bonds. Toluene →KMnO4−KOH, Δ\xrightarrow{\text{KMnO}_4-\text{KOH},\,\Delta}KMnO4​−KOH,Δ​ A →H3O+\xrightarrow{\text{H}_3\text{O}^+}H3​O+​ B →Br2/FeBr3\xrightarrow{\text{Br}_2/\text{FeBr}_3}Br2​/FeBr3​​ C.

Correct answer: 4

Step-by-step solution →
Q58·ChemistryNumerical
Acetic acid dissociates in water with a dissociation constant of 6.25×10−56.25 \times 10^{-5}6.25×10−5. If 5 mL of acetic acid is dissolved in 1 litre of water, the solution will freeze at −x×10−2-x \times 10^{-2}−x×10−2 °C, provided pure water freezes at 0 °C. The value of xxx is __________. (Nearest integer) Given: (Kf)water=1.86(K_f)_{water} = 1.86(Kf​)water​=1.86 K kg mol−1^{-1}−1; density of acetic acid = 1.2 g mL−1^{-1}−1; molar mass of water = 18 g mol−1^{-1}−1; molar mass of acetic acid = 60 g mol−1^{-1}−1; density of water = 1 g cm−3^{-3}−3.

Correct answer: 19

Step-by-step solution →
Q59·ChemistryNumerical
The number of compounds from the following with zero dipole moment is __________. HF\text{HF}HF, H2\text{H}_2H2​, H2S\text{H}_2\text{S}H2​S, CO2\text{CO}_2CO2​, NH3\text{NH}_3NH3​, BF3\text{BF}_3BF3​, CH4\text{CH}_4CH4​, CHCl3\text{CHCl}_3CHCl3​, SiF4\text{SiF}_4SiF4​, H2O\text{H}_2\text{O}H2​O, BeF2\text{BeF}_2BeF2​.

Correct answer: 6

Step-by-step solution →

Mathematics — JEE Main 5 April 2024 Shift 2

Q60·Mathematics·Limits and ContinuitySingle correct
Let f:[−1,2]→Rf:[-1,2]\to\mathbb{R}f:[−1,2]→R be given by f(x)=2x2+x+[x2]−[x]f(x)=2x^2+x+[x^2]-[x]f(x)=2x2+x+[x2]−[x], where [t][t][t] denotes the greatest integer less than or equal to ttt. The number of points where fff is not continuous is:
  1. (A)6
  2. (B)3
  3. (C)4
  4. (D)5

Correct answer: (C)

Step-by-step solution →
Q61·MathematicsSingle correct
The differential equation of the family of circles passing through the origin and having their centre on the line y=xy=xy=x is:
  1. (A)(x2−y2+2xy) dx=(x2−y2+2xy) dy(x^2-y^2+2xy)\,dx=(x^2-y^2+2xy)\,dy(x2−y2+2xy)dx=(x2−y2+2xy)dy
  2. (B)(x2+y2+2xy) dx=(x2+y2−2xy) dy(x^2+y^2+2xy)\,dx=(x^2+y^2-2xy)\,dy(x2+y2+2xy)dx=(x2+y2−2xy)dy
  3. (C)(x2−y2+2xy) dx=(x2−y2−2xy) dy(x^2-y^2+2xy)\,dx=(x^2-y^2-2xy)\,dy(x2−y2+2xy)dx=(x2−y2−2xy)dy
  4. (D)(x2+y2−2xy) dx=(x2+y2+2xy) dy(x^2+y^2-2xy)\,dx=(x^2+y^2+2xy)\,dy(x2+y2−2xy)dx=(x2+y2+2xy)dy

Correct answer: (C)

Step-by-step solution →
Q62·MathematicsSingle correct
Let S1={z∈C:∣z∣≤5}S_1=\{z\in\mathbb{C}:|z|\le 5\}S1​={z∈C:∣z∣≤5}, S2={z∈C:Im⁡(z+1−3 i1−3 i)≥0}S_2=\left\{z\in\mathbb{C}:\operatorname{Im}\left(\dfrac{z+1-\sqrt{3}\,i}{1-\sqrt{3}\,i}\right)\ge 0\right\}S2​={z∈C:Im(1−3​iz+1−3​i​)≥0} and S3={z∈C:Re⁡(z)≥0}S_3=\{z\in\mathbb{C}:\operatorname{Re}(z)\ge 0\}S3​={z∈C:Re(z)≥0}. Then the area of S1∩S2∩S3S_1\cap S_2\cap S_3S1​∩S2​∩S3​ is:
  1. (A)125π6\dfrac{125\pi}{6}6125π​
  2. (B)125π24\dfrac{125\pi}{24}24125π​
  3. (C)125π4\dfrac{125\pi}{4}4125π​
  4. (D)125π12\dfrac{125\pi}{12}12125π​

Correct answer: (D)

Step-by-step solution →
Q63·MathematicsSingle correct
The area enclosed between the curves y=x∣x∣y=x|x|y=x∣x∣ and y=x−∣x∣y=x-|x|y=x−∣x∣ is:
  1. (A)83\dfrac{8}{3}38​
  2. (B)23\dfrac{2}{3}32​
  3. (C)1
  4. (D)43\dfrac{4}{3}34​

Correct answer: (D)

Step-by-step solution →
Q64·MathematicsSingle correct
60 words can be made using all the letters of the word BHBJO, with or without meaning. If these words are written as in a dictionary, then the 50th word is:
  1. (A)OBBHJ
  2. (B)HBBJO
  3. (C)OBBJH
  4. (D)JBBOH

Correct answer: (C)

Step-by-step solution →
Q65·MathematicsSingle correct
Let a⃗=2i^+5j^−k^\vec{a}=2\hat{i}+5\hat{j}-\hat{k}a=2i^+5j^​−k^, b⃗=2i^−2j^+2k^\vec{b}=2\hat{i}-2\hat{j}+2\hat{k}b=2i^−2j^​+2k^ and c⃗\vec{c}c be three vectors such that (c⃗+i^)×(a⃗+b⃗+i^)=a⃗×(c⃗+i^)(\vec{c}+\hat{i})\times(\vec{a}+\vec{b}+\hat{i})=\vec{a}\times(\vec{c}+\hat{i})(c+i^)×(a+b+i^)=a×(c+i^) and a⃗⋅c⃗=−29\vec{a}\cdot\vec{c}=-29a⋅c=−29. Then c⃗⋅(−2i^+j^+k^)\vec{c}\cdot(-2\hat{i}+\hat{j}+\hat{k})c⋅(−2i^+j^​+k^) is equal to:
  1. (A)10
  2. (B)5
  3. (C)15
  4. (D)12

Correct answer: (B)

Step-by-step solution →
Q66·MathematicsSingle correct
Consider three vectors a⃗,b⃗,c⃗\vec{a},\vec{b},\vec{c}a,b,c. Let ∣a⃗∣=2|\vec{a}|=2∣a∣=2, ∣b⃗∣=3|\vec{b}|=3∣b∣=3 and a⃗=b⃗×c⃗\vec{a}=\vec{b}\times\vec{c}a=b×c. If α∈[0,π3]\alpha\in\left[0,\dfrac{\pi}{3}\right]α∈[0,3π​] is the angle between the vectors b⃗\vec{b}b and c⃗\vec{c}c, then the minimum value of 27∣c⃗−a⃗∣227|\vec{c}-\vec{a}|^227∣c−a∣2 is equal to:
  1. (A)110
  2. (B)105
  3. (C)124
  4. (D)121

Correct answer: (C)

Step-by-step solution →
Q67·MathematicsSingle correct
Let A(−1,1)A(-1,1)A(−1,1) and B(2,3)B(2,3)B(2,3) be two points and PPP be a variable point above the line ABABAB such that the area of △PAB\triangle PAB△PAB is 10. If the locus of PPP is ax+by=15ax+by=15ax+by=15, then 5a+2b5a+2b5a+2b is:
  1. (A)−125-\dfrac{12}{5}−512​
  2. (B)−65-\dfrac{6}{5}−56​
  3. (C)4
  4. (D)6

Correct answer: (A)

Step-by-step solution →
Q68·MathematicsSingle correct
Let (α,β,γ)(\alpha,\beta,\gamma)(α,β,γ) be the image of the point (8,5,7)(8,5,7)(8,5,7) in the line x−12=y+13=z−25\dfrac{x-1}{2}=\dfrac{y+1}{3}=\dfrac{z-2}{5}2x−1​=3y+1​=5z−2​. Then α+β+γ\alpha+\beta+\gammaα+β+γ is equal to:
  1. (A)16
  2. (B)18
  3. (C)14
  4. (D)20

Correct answer: (C)

Step-by-step solution →
Q69·MathematicsSingle correct
If the constant term in the expansion of (35x+2x53)12\left(\dfrac{\sqrt[5]{3}}{x}+\dfrac{2x}{\sqrt[3]{5}}\right)^{12}(x53​​+35​2x​)12, x≠0x\ne 0x=0, is α×28×35\alpha\times 2^8\times\sqrt[5]{3}α×28×53​, then 25α25\alpha25α is equal to:
  1. (A)639
  2. (B)724
  3. (C)693
  4. (D)742

Correct answer: (C)

Step-by-step solution →
Q70·MathematicsSingle correct
Let f,g:R→Rf,g:\mathbb{R}\to\mathbb{R}f,g:R→R be defined as f(x)=∣x−1∣f(x)=|x-1|f(x)=∣x−1∣ and g(x)=exg(x)=e^xg(x)=ex for x≥0x\ge 0x≥0, g(x)=x+1g(x)=x+1g(x)=x+1 for x<0x<0x<0. Then the function f(g(x))f(g(x))f(g(x)) is:
  1. (A)neither one-one nor onto
  2. (B)one-one but not onto
  3. (C)both one-one and onto
  4. (D)onto but not one-one

Correct answer: (A)

Step-by-step solution →
Q71·MathematicsSingle correct
Let the circle C1:x2+y2−2(x+y)+1=0C_1:x^2+y^2-2(x+y)+1=0C1​:x2+y2−2(x+y)+1=0 and C2C_2C2​ be a circle having centre at (−1,0)(-1,0)(−1,0) and radius 2. If the line of the common chord of C1C_1C1​ and C2C_2C2​ intersects the y-axis at the point PPP, then the square of the distance of PPP from the centre of C1C_1C1​ is:
  1. (A)2
  2. (B)1
  3. (C)6
  4. (D)4

Correct answer: (A)

Step-by-step solution →
Q72·MathematicsSingle correct
Let the set S={2,4,8,16,…,512}S=\{2,4,8,16,\ldots,512\}S={2,4,8,16,…,512} be partitioned into 3 sets A,B,CA,B,CA,B,C with an equal number of elements such that A∪B∪C=SA\cup B\cup C=SA∪B∪C=S and A∩B=B∩C=A∩C=∅A\cap B=B\cap C=A\cap C=\varnothingA∩B=B∩C=A∩C=∅. The maximum number of such possible partitions of SSS is equal to:
  1. (A)1680
  2. (B)1520
  3. (C)1710
  4. (D)1640

Correct answer: (A)

Step-by-step solution →
Q73·MathematicsSingle correct
The values of m,nm,nm,n, for which the system of equations x+y+z=4x+y+z=4x+y+z=4, 2x+5y+5z=172x+5y+5z=172x+5y+5z=17, x+2y+mz=nx+2y+mz=nx+2y+mz=n has infinitely many solutions, satisfy the equation:
  1. (A)m2+n2−m−n=46m^2+n^2-m-n=46m2+n2−m−n=46
  2. (B)m2+n2+m+n=64m^2+n^2+m+n=64m2+n2+m+n=64
  3. (C)m2+n2+mn=68m^2+n^2+mn=68m2+n2+mn=68
  4. (D)m2+n2−mn=39m^2+n^2-mn=39m2+n2−mn=39

Correct answer: (D)

Step-by-step solution →
Q74·MathematicsSingle correct
The coefficients a,b,ca,b,ca,b,c in the quadratic equation ax2+bx+c=0ax^2+bx+c=0ax2+bx+c=0 are from the set {1,2,3,4,5,6}\{1,2,3,4,5,6\}{1,2,3,4,5,6}. If the probability of this equation having one real root bigger than the other is ppp, then 216p216p216p equals:
  1. (A)57
  2. (B)38
  3. (C)19
  4. (D)76

Correct answer: (B)

Step-by-step solution →
Q75·MathematicsSingle correct
Let ABCD and AEFG be squares of side 4 and 2 units, respectively. The point E is on the line segment AB and the point F is on the diagonal AC. Then the radius rrr of the circle passing through the point F and touching the line segments BC and CD satisfies:
  1. (A)r=1r=1r=1
  2. (B)r2−8r+8=0r^2-8r+8=0r2−8r+8=0
  3. (C)2r2−4r+1=02r^2-4r+1=02r2−4r+1=0
  4. (D)2r2−8r+7=02r^2-8r+7=02r2−8r+7=0

Correct answer: (B)

Step-by-step solution →
Q76·MathematicsSingle correct
Let β(m,n)=∫01xm−1(1−x)n−1 dx\beta(m,n)=\displaystyle\int_0^1 x^{m-1}(1-x)^{n-1}\,dxβ(m,n)=∫01​xm−1(1−x)n−1dx, m,n>0m,n>0m,n>0. If ∫01(1−x10)20 dx=a β(b,c)\displaystyle\int_0^1 (1-x^{10})^{20}\,dx=a\,\beta(b,c)∫01​(1−x10)20dx=aβ(b,c), then 100(a+b+c)100(a+b+c)100(a+b+c) equals:
  1. (A)1021
  2. (B)1120
  3. (C)2012
  4. (D)2120

Correct answer: (D)

Step-by-step solution →
Q77·MathematicsSingle correct
Let αβ≠0\alpha\beta\ne 0αβ=0 and A=[βα3ααβ−βα2α]A=\begin{bmatrix} \beta & \alpha & 3 \\ \alpha & \alpha & \beta \\ -\beta & \alpha & 2\alpha \end{bmatrix}A=​βα−β​ααα​3β2α​​. If B=[3α−93α−α7−2α−2α5−2β]B=\begin{bmatrix} 3\alpha & -9 & 3\alpha \\ -\alpha & 7 & -2\alpha \\ -2\alpha & 5 & -2\beta \end{bmatrix}B=​3α−α−2α​−975​3α−2α−2β​​ is the matrix of cofactors of the elements of AAA, then det⁡(AB)\det(AB)det(AB) is equal to:
  1. (A)343
  2. (B)125
  3. (C)64
  4. (D)216

Correct answer: (D)

Step-by-step solution →
Q78·Mathematics·DifferentiabilitySingle correct
If y(θ)=2cos⁡θ+cos⁡2θcos⁡3θ+4cos⁡2θ+5cos⁡θ+2y(\theta)=\dfrac{2\cos\theta+\cos 2\theta}{\cos 3\theta+4\cos 2\theta+5\cos\theta+2}y(θ)=cos3θ+4cos2θ+5cosθ+22cosθ+cos2θ​, then at θ=π2\theta=\dfrac{\pi}{2}θ=2π​, y′′+y′+yy''+y'+yy′′+y′+y is equal to:
  1. (A)π2\dfrac{\pi}{2}2π​
  2. (B)1
  3. (C)12\dfrac{1}{2}21​
  4. (D)2

Correct answer: (D)

Step-by-step solution →
Q79·MathematicsSingle correct
For x≥0x\ge 0x≥0, the least value of KKK for which 41+x+41−x4^{1+x}+4^{1-x}41+x+41−x, K2\dfrac{K}{2}2K​, 16x+16−x16^x+16^{-x}16x+16−x are three consecutive terms of an A.P. is equal to:
  1. (A)10
  2. (B)4
  3. (C)8
  4. (D)16

Correct answer: (A)

Step-by-step solution →
Q80·MathematicsNumerical
Let the mean and the standard deviation of the probability distribution with X={α,1,0,−3}X=\{\alpha,1,0,-3\}X={α,1,0,−3} and corresponding P(X)={13,K,16,14}P(X)=\left\{\dfrac{1}{3},K,\dfrac{1}{6},\dfrac{1}{4}\right\}P(X)={31​,K,61​,41​} (in the same order) be μ\muμ and σ\sigmaσ respectively. If σ−μ=2\sigma-\mu=2σ−μ=2, then σ+μ\sigma+\muσ+μ is equal to __________.

Correct answer: 5

Step-by-step solution →
Q81·MathematicsNumerical
Let y=y(x)y=y(x)y=y(x) be the solution of the differential equation dydx+2x(1+x2)2 y=x e11+x2\dfrac{dy}{dx}+\dfrac{2x}{(1+x^2)^2}\,y=x\,e^{\frac{1}{1+x^2}}dxdy​+(1+x2)22x​y=xe1+x21​; y(0)=0y(0)=0y(0)=0. Then the area enclosed by the curve f(x)=y(x) e−11+x2f(x)=y(x)\,e^{-\frac{1}{1+x^2}}f(x)=y(x)e−1+x21​ and the line y−x=4y-x=4y−x=4 is __________.

Correct answer: 18

Step-by-step solution →
Q82·MathematicsNumerical
The number of solutions of sin⁡2x+(2+2x−x2)sin⁡x−3(x−1)2=0\sin^2 x+(2+2x-x^2)\sin x-3(x-1)^2=0sin2x+(2+2x−x2)sinx−3(x−1)2=0, where −π≤x≤π-\pi\le x\le\pi−π≤x≤π, is __________.

Correct answer: 2

Step-by-step solution →
Q83·MathematicsNumerical
Let the point (−1,α,β)(-1,\alpha,\beta)(−1,α,β) lie on the line of the shortest distance between the lines x+2−3=y−24=z−52\dfrac{x+2}{-3}=\dfrac{y-2}{4}=\dfrac{z-5}{2}−3x+2​=4y−2​=2z−5​ and x+2−1=y+62=z−10\dfrac{x+2}{-1}=\dfrac{y+6}{2}=\dfrac{z-1}{0}−1x+2​=2y+6​=0z−1​. Then (α−β)2(\alpha-\beta)^2(α−β)2 is equal to __________.

Correct answer: 25

Step-by-step solution →
Q84·MathematicsNumerical
If 1+3−223+5−2618+93−112363+49−206180+⋯1+\dfrac{\sqrt{3}-\sqrt{2}}{2\sqrt{3}}+\dfrac{5-2\sqrt{6}}{18}+\dfrac{9\sqrt{3}-11\sqrt{2}}{36\sqrt{3}}+\dfrac{49-20\sqrt{6}}{180}+\cdots1+23​3​−2​​+185−26​​+363​93​−112​​+18049−206​​+⋯ upto ∞=2(ba+1)log⁡e(ab)\infty=2\left(\sqrt{\dfrac{b}{a}}+1\right)\log_e\left(\dfrac{a}{b}\right)∞=2(ab​​+1)loge​(ba​), where aaa and bbb are integers with gcd⁡(a,b)=1\gcd(a,b)=1gcd(a,b)=1, then 11a+18b11a+18b11a+18b is equal to __________.

Correct answer: 76

Step-by-step solution →
Q85·Mathematics·Limits and ContinuityNumerical
Let a>0a>0a>0 be a root of the equation 2x2+x−2=02x^2+x-2=02x2+x−2=0. If lim⁡x→1a16(1−cos⁡(2+x−2x2))(1−ax)2=α+β17\displaystyle\lim_{x\to\frac{1}{a}}\dfrac{16\left(1-\cos(2+x-2x^2)\right)}{(1-ax)^2}=\alpha+\beta\sqrt{17}x→a1​lim​(1−ax)216(1−cos(2+x−2x2))​=α+β17​, where α,β∈Z\alpha,\beta\in\mathbb{Z}α,β∈Z, then α+β\alpha+\betaα+β is equal to __________.

Correct answer: 170

Step-by-step solution →
Q86·MathematicsNumerical
If f(t)=∫0π2x dx1−cos⁡2t sin⁡2xf(t)=\displaystyle\int_0^{\pi}\dfrac{2x\,dx}{1-\cos^2 t\,\sin^2 x}f(t)=∫0π​1−cos2tsin2x2xdx​, 0<t<π0<t<\pi0<t<π, then the value of ∫0π/2π2 dtf(t)\displaystyle\int_0^{\pi/2}\dfrac{\pi^2\,dt}{f(t)}∫0π/2​f(t)π2dt​ equals __________.

Correct answer: 1

Step-by-step solution →
Q87·MathematicsNumerical
Let the maximum and minimum values of (8x−x2−12−4)2+(x−7)2\left(\sqrt{8x-x^2-12}-4\right)^2+(x-7)^2(8x−x2−12​−4)2+(x−7)2, x∈Rx\in\mathbb{R}x∈R, be MMM and mmm respectively. Then M2−m2M^2-m^2M2−m2 is equal to __________.

Correct answer: 1600

Step-by-step solution →
Q88·MathematicsNumerical
Let a line perpendicular to the line 2x−y=102x-y=102x−y=10 touch the parabola y2=4(x−9)y^2=4(x-9)y2=4(x−9) at the point PPP. The distance of the point PPP from the centre of the circle x2+y2−14x−8y+56=0x^2+y^2-14x-8y+56=0x2+y2−14x−8y+56=0 is __________.

Correct answer: 10

Step-by-step solution →
Q89·MathematicsNumerical
The number of real solutions of the equation x ∣x+5∣+2∣x+7∣−2=0x\,|x+5|+2|x+7|-2=0x∣x+5∣+2∣x+7∣−2=0 is __________.

Correct answer: 3

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Chapters tested in this paper

Open any chapter to practise every past-year question on that topic across all papers, and see how often it has actually appeared.

  • Properties of Solids and Liquids 172/186
  • Three Dimensional Geometry 176/186
  • Matrices and Determinants 180/186
  • Coordination Compounds 176/186
  • Sets, Relations and Functions 165/186
  • Current Electricity 160/186
  • Sequence and Series 164/186
  • p-Block Elements 164/186
  • Definite Integration 168/186
  • Rotational Motion 172/186
  • Redox Reactions and Electrochemistry 177/186
  • Geometrical Optics 172/186
  • Kinematics 156/186
  • Vector Algebra 173/186
  • Differential Equations 167/186
  • Probability 176/186
  • Permutations and Combinations 162/186
  • Magnetic Field of Current 147/186
  • Binomial Theorem and Its Simple Applications 158/186
  • Electromagnetic Waves 144/186
  • Chemical Bonding and Molecular Structure 151/186
  • Limits and Continuity 149/186
  • d- and f-Block Elements 126/186
  • Thermodynamics 154/186
  • Aldehydes and Ketones 135/186
  • Solutions 158/186
  • Laws of Motion 130/186
  • Chemical Thermodynamics 165/186
  • Units and Measurements 149/186
  • Hydrocarbons 126/186
  • Complex Numbers 165/186
  • Trigonometric Functions 144/186
  • Biomolecules 162/186
  • Chemical Kinetics 169/186
  • Gravitation 152/186
  • Electric Field and Coulomb's Law 133/186
  • Atomic Structure 161/186
  • Electronic Devices 145/186
  • Circles 142/186
  • Dual Nature of Matter and Radiation 155/186
  • Amines 133/186
  • Quadratic Equations 148/186
  • Work, Energy and Power 132/186
  • Some Basic Concepts in Chemistry 129/186
  • Electromagnetic Induction 120/186
  • Wave Optics 130/186
  • Area Under Curves 139/186
  • Kinetic Theory of Gases 135/186
  • Alcohols and Ethers 106/186
  • Purification and Characterisation of Organic Compounds 116/186
  • Alternating Currents 108/186
  • Organic Compounds Containing Halogens 109/186
  • Straight Lines 114/186
  • Waves 109/186
  • Atoms 112/186
  • Classification of Elements and Periodicity in Properties 113/186
  • Parabola 101/186
  • Differentiability 91/186
  • Experimental Skills 68/186
  • Carboxylic Acids and Derivatives 54/186
  • Isomerism 51/186
  • IUPAC Nomenclature 37/186
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