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JEE Main 4 April 2025 Shift 2 Question Paper with Answers

4 April 2025 · April session · 75 questions

The complete JEE Main 4 April 2025 Shift 2 paper — all 75 questions with the correct answer for each, tagged to the chapter it tests. Free to read, no account needed.

Physics
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Chemistry
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Mathematics
25

Physics — JEE Main 4 April 2025 Shift 2

Q1·Physics·Atoms and NucleiSingle correct
A radioactive material P first decays into Q and then Q decays to non-radioactive material R. Which of the following figure represents the time dependent mass of P, Q and R?
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (B)

Step-by-step solution →
Q2·Physics·Current ElectricitySingle correct
There are 'n' number of identical electric bulbs, each is designed to draw a power p independently from the mains supply. They are now joined in series across the main supply. The total power drawn by the combination is:
  1. (A)npnpnp
  2. (B)pn2\dfrac{p}{n^2}n2p​
  3. (C)pn\dfrac{p}{n}np​
  4. (D)ppp

Correct answer: (C)

Step-by-step solution →
Q3·Physics·Properties of Solids and LiquidsSingle correct
Consider a rectangular sheet of solid material of length ℓ=9\ell=9ℓ=9 cm and width d=4d=4d=4 cm. The coefficient of linear expansion is α=3.1×10−5 K−1\alpha=3.1\times10^{-5}\ K^{-1}α=3.1×10−5 K−1 at room temperature and one atmospheric pressure. The mass of sheet m=0.1m=0.1m=0.1 kg and the specific heat capacity Cv=900 J kg−1K−1C_v=900\ J\,kg^{-1}K^{-1}Cv​=900 Jkg−1K−1. If the amount of heat supplied to the material is 8.1×1028.1\times10^28.1×102 J then change in area of the rectangular sheet is:
  1. (A)2.0×10−5 m22.0\times10^{-5}\ m^22.0×10−5 m2
  2. (B)2.0×10−3 m22.0\times10^{-3}\ m^22.0×10−3 m2
  3. (C)6.0×10−5 m26.0\times10^{-5}\ m^26.0×10−5 m2
  4. (D)4.0×10−5 m24.0\times10^{-5}\ m^24.0×10−5 m2

Correct answer: (A)

Step-by-step solution →
Q4·Physics·Atoms and NucleiSingle correct
Given below are two statements: Statement (I): The dimensions of Planck's constant and angular momentum are same. Statement (II): In Bohr's model electron revolve around the nucleus only in those orbits for which angular momentum is integral multiple of Planck's constant. In the light of the above statements, choose the most appropriate answer from the options given below:
  1. (A)Both Statement I and Statement II are correct
  2. (B)Statement I is incorrect but Statement II is correct
  3. (C)Statement I is correct but Statement II is incorrect
  4. (D)Both Statement I and Statement II are incorrect

Correct answer: (C)

Step-by-step solution →
Q5·Physics·Properties of Solids and LiquidsSingle correct
A cylindrical rod of length 1 m and radius 4 cm is mounted vertically. It is subjected to a shear force of 10710^7107 N at the top. Considering infinitesimally small displacement in the upper edge, the angular displacement θ\thetaθ of the rod axis from its original position is: (shear moduli, G=1010 N/m2G=10^{10}\ N/m^2G=1010 N/m2)
  1. (A)1160π\dfrac{1}{160\pi}160π1​
  2. (B)14π\dfrac{1}{4\pi}4π1​
  3. (C)140π\dfrac{1}{40\pi}40π1​
  4. (D)12π\dfrac{1}{2\pi}2π1​

Correct answer: (A)

Step-by-step solution →
Q6·Physics·Current ElectricitySingle correct
From the combination of resistors with resistance values R1=R2=R3=5 ΩR_1=R_2=R_3=5\ \OmegaR1​=R2​=R3​=5 Ω and R4=10 ΩR_4=10\ \OmegaR4​=10 Ω, which of the following combination is the best circuit to get an equivalent resistance of 6 Ω6\ \Omega6 Ω?
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (A)

Step-by-step solution →
Q7·Physics·Electric Field and Coulomb's LawSingle correct
A metallic ring is uniformly charged as shown in the figure. AC and BD are two mutually perpendicular diameters. Electric field due to arc AB to "O" is "E" is magnitude. What would be the magnitude of electric field at "O" due to arc ABC?
  1. (A)2E2E2E
  2. (B)2 E\sqrt2\,E2​E
  3. (C)E2\dfrac{E}{2}2E​
  4. (D)Zero

Correct answer: (B)

Step-by-step solution →
Q8·Physics·Kinetic Theory of GasesSingle correct
There are two vessels filled with an ideal gas where volume of one is double the volume of other. The large vessel contains the gas at 8 kPa at 1000 K while the smaller vessel contains the gas at 7 kPa at 500 K. If the vessels are connected to each other by a thin tube allowing the gas to flow and the temperature of both vessels is maintained at 600 K, at steady state the pressure in the vessels will be (in kPa):
  1. (A)4.4
  2. (B)6
  3. (C)24
  4. (D)18

Correct answer: (B)

Step-by-step solution →
Q9·Physics·GravitationSingle correct
An object is kept at rest at a distance of 3R3R3R above the earth's surface where R is earth's radius. The minimum speed with which it must be projected so that it does not return to earth is: (Assume M = mass of earth, G = Universal gravitational constant)
  1. (A)GM2R\sqrt{\dfrac{GM}{2R}}2RGM​​
  2. (B)GMR\sqrt{\dfrac{GM}{R}}RGM​​
  3. (C)3GMR\sqrt{\dfrac{3GM}{R}}R3GM​​
  4. (D)2GMR\sqrt{\dfrac{2GM}{R}}R2GM​​

Correct answer: (A)

Step-by-step solution →
Q10·Physics·Capacitors and DielectricsSingle correct
Three parallel plate capacitors C1C_1C1​, C2C_2C2​ and C3C_3C3​ each of capacitance 5 μ\muμF are connected as shown in the figure. The effective capacitance between points A and B, when the space between the parallel plates of C1C_1C1​ capacitor is filled with a dielectric medium having dielectric constant of 4, is:
  1. (A)22.5 μF22.5\ \mu F22.5 μF
  2. (B)7.5 μF7.5\ \mu F7.5 μF
  3. (C)9 μF9\ \mu F9 μF
  4. (D)30 μF30\ \mu F30 μF

Correct answer: (C)

Step-by-step solution →
Q11·Physics·KinematicsSingle correct
The displacement x versus time t graph is shown below. (A) The average velocity during 0 to 3 s is 10 m/s. (B) The average velocity during 3 to 5 s is 0 m/s. (C) The instantaneous velocity at t = 2 s is 5 m/s. (D) The average velocity during 5 to 7 s and instantaneous velocity at t = 6.5 s are zero. (E) The average velocity from t = 0 to t = 9 s is zero. Choose the correct answer from the options given below:
  1. (A)(A), (D), (E) only
  2. (B)(B), (C), (D) only
  3. (C)(B), (D), (E) only
  4. (D)(B), (C), (E) only

Correct answer: (D)

Step-by-step solution →
Q12·Physics·Rotational MotionSingle correct
A wheel is rolling on a plane surface. The speed of a particle at the highest point of the rim is 8 m/s. The speed of the particle on the rim of the wheel at the same level as the centre of the wheel, will be:
  1. (A)424\sqrt242​ m/s
  2. (B)8 m/s
  3. (C)4 m/s
  4. (D)828\sqrt282​ m/s

Correct answer: (A)

Step-by-step solution →
Q13·Physics·Units and MeasurementsSingle correct
For the determination of refractive index of glass slab, a travelling microscope is used whose main scale contains 300 equal divisions equals to 15 cm. The vernier scale attached to the microscope has 25 divisions equals to 24 divisions of main scale. The least count (LC) of the travelling microscope is (in cm):
  1. (A)0.001
  2. (B)0.002
  3. (C)0.0005
  4. (D)0.0025

Correct answer: (B)

Step-by-step solution →
Q14·Physics·Laws of MotionSingle correct
A block of mass 25 kg is pulled along a horizontal surface by a force at an angle 45∘45^\circ45∘ with the horizontal. The friction coefficient between the block and the surface is 0.25. The displacement of 5 m of the block is: (work done by the applied force)
  1. (A)970 J
  2. (B)735 J
  3. (C)245 J
  4. (D)490 J

Correct answer: (C)

Step-by-step solution →
Q15·Physics·Wave OpticsSingle correct
Two polarisers P1P_1P1​ and P2P_2P2​ are placed in such a way that the intensity of the transmitted light will be zero. A third polariser P3P_3P3​ is inserted in between P1P_1P1​ and P2P_2P2​ at the particular angle between them. The transmitted intensity of the light passing through all three polarisers is maximum. The angle between the polarisers P1P_1P1​ and P3P_3P3​ is:
  1. (A)π4\dfrac{\pi}{4}4π​
  2. (B)π6\dfrac{\pi}{6}6π​
  3. (C)π8\dfrac{\pi}{8}8π​
  4. (D)π3\dfrac{\pi}{3}3π​

Correct answer: (A)

Step-by-step solution →
Q16·Physics·Electronic DevicesSingle correct
Consider a n-type semiconductor in which nen_ene​ and nhn_hnh​ are number of electrons and holes, respectively. (A) Holes are minority carriers. (B) The dopant is a pentavalent atom. (C) nenh≠ni2n_e n_h \ne n_i^2ne​nh​=ni2​ (where nin_ini​ is number of electrons or holes in semiconductor when it is in intrinsic form). (D) nenh≥ni2n_e n_h \ge n_i^2ne​nh​≥ni2​. (E) The holes are not generated due to the donors. Choose the correct answer from the options given below:
  1. (A)(A), (C), (D) only
  2. (B)(A), (C), (E) only
  3. (C)(A), (B), (E) only
  4. (D)(A), (B), (C) only

Correct answer: (C)

Step-by-step solution →
Q17·Physics·ThermodynamicsSingle correct
Match List-I (Process) with List-II (First-law relation). Choose the correct answer from the options given below:
List-I (Process)List-II (First-law relation)
A.IsobaricI.ΔQ=ΔW\Delta Q=\Delta WΔQ=ΔW
B.IsochoricII.ΔQ=ΔU\Delta Q=\Delta UΔQ=ΔU
C.AdiabaticIII.ΔQ=\Delta Q=ΔQ= zero
D.IsothermalIV.ΔQ=ΔU+PΔV\Delta Q=\Delta U+P\Delta VΔQ=ΔU+PΔV
  1. (A)(A)-(IV), (B)-(III), (C)-(I), (D)-(II)
  2. (B)(A)-(IV), (B)-(I), (C)-(II), (D)-(III)
  3. (C)(A)-(IV), (B)-(II), (C)-(III), (D)-(I)
  4. (D)(A)-(II), (B)-(III), (C)-(I), (D)-(IV)

Correct answer: (C)

Step-by-step solution →
Q18·Physics·WavesSingle correct
Displacement of a wave is expressed as x(t)=5cos⁡(628t+π2)x(t)=5\cos\left(628t+\dfrac{\pi}{2}\right)x(t)=5cos(628t+2π​) m. The wavelength of the wave when its velocity is 300 m/s is:
  1. (A)1.5 m
  2. (B)3 m
  3. (C)0.5 m
  4. (D)0.33 m

Correct answer: (B)

Step-by-step solution →
Q19·Physics·Geometrical OpticsSingle correct
A finite size object is placed normal to the principal axis at a distance of 30 cm from a convex mirror of focal length 30 cm. A plane mirror is now placed in such a way that the image produced by both the mirrors coincide with each other. The distance between the two mirrors is:
  1. (A)45 cm
  2. (B)7.5 cm
  3. (C)22.5 cm
  4. (D)15 cm

Correct answer: (B)

Step-by-step solution →
Q20·Physics·Units and MeasurementsSingle correct
In an electromagnetic system, a quantity defined as the ratio of electric dipole moment and magnetic dipole moment has dimension of [MP LQ TA][M^P\,L^Q\,T^A][MPLQTA]. The value of P and Q are:
  1. (A)1, 0
  2. (B)−1,1-1, 1−1,1
  3. (C)1,−11, -11,−1
  4. (D)0,−10, -10,−1

Correct answer: (D)

Step-by-step solution →
Q21·Physics·Magnetic Field of CurrentInteger
A particle of charge 1.6 μ\muμC and mass 16 μ\muμg is present in a strong magnetic field of 6.28 T. The particle is then fired perpendicular to the magnetic field. The time required for the particle to return to original location for the first time is ______ s. (π=3.14\pi=3.14π=3.14)

Correct answer: 10

Step-by-step solution →
Q22·Physics·Rotational MotionInteger
A solid sphere with uniform density and radius R is rotating with constant angular velocity ω1\omega_1ω1​ about its diameter. After some time during the rotation its mass starts losing at a uniform rate, with no change in its shape. The angular velocity of the sphere when its radius becomes R/2R/2R/2 is xω1x\omega_1xω1​. The value of x is ______.

Correct answer: 32

Step-by-step solution →
Q23·Physics·Electromagnetic WavesInteger
If an optical medium possesses a relative permeability of 10π\dfrac{10}{\pi}π10​ and relative permittivity of 10.0885\dfrac{1}{0.0885}0.08851​, then the velocity of light is greater in vacuum than in this medium by ______ times. (μ0=4π×10−7\mu_0=4\pi\times10^{-7}μ0​=4π×10−7 H/m, ε0=8.85×10−12\varepsilon_0=8.85\times10^{-12}ε0​=8.85×10−12 F/m, c=3×108c=3\times10^8c=3×108 m/s)

Correct answer: 6

Step-by-step solution →
Q24·Physics·Wave OpticsInteger
In a Young's double slit experiment, two slits are located 1.5 mm apart. The distance of screen from slits is 2 m and the wavelength of the source is 400 nm. If the double slit pattern is replaced with a single slit of width equal to that of each slit, then the width of 20 maxima of double slit is ______ times the width of central maxima of single slit. (take x-value is ______)

Correct answer: 15

Step-by-step solution →
Q25·Physics·Electromagnetic InductionInteger
An inductor of self inductance 1 H connected in series with a resistor of 100π Ω100\pi\ \Omega100π Ω and an AC supply of 100π100\pi100π volt, 50 Hz. Maximum current flowing in the circuit is ______ A.

Correct answer: 1

Step-by-step solution →

Chemistry — JEE Main 4 April 2025 Shift 2

Q26·Chemistry·AminesSingle correct
The correct order of basicity for the following molecules is:
  1. (A)P>Q>RP > Q > RP>Q>R
  2. (B)R>P>QR > P > QR>P>Q
  3. (C)Q>P>RQ > P > RQ>P>R
  4. (D)R>Q>PR > Q > PR>Q>P

Correct answer: (D)

Step-by-step solution →
Q27·Chemistry·d- and f-Block ElementsSingle correct
The incorrect relationship in the following pairs in relation to ionisation enthalpies is:
  1. (A)Mn+<Cr+Mn^+ < Cr^+Mn+<Cr+
  2. (B)Mn2+<Mn+Mn^{2+} < Mn^+Mn2+<Mn+
  3. (C)Fe2+<Fe3+Fe^{2+} < Fe^{3+}Fe2+<Fe3+
  4. (D)Mn2+<Fe2+Mn^{2+} < Fe^{2+}Mn2+<Fe2+

Correct answer: (D)

Step-by-step solution →
Q28·Chemistry·Aldehydes and KetonesSingle correct
Which among the following compounds give yellow solid when reacted with NaOI/NaOH?
  1. (A)(B), (C) and (E) Only
  2. (B)(A) and (C) Only
  3. (C)(C) and (D) Only
  4. (D)(A), (C) and (D) Only

Correct answer: (B)

Step-by-step solution →
Q29·Chemistry·BiomoleculesSingle correct
A dipeptide, "x" on complete hydrolysis gives "y" and "z". "y" on treatment with aq. HNO2HNO_2HNO2​ produces lactic acid. On the other hand "z" on heating gives the following cyclic molecule. Based on the information given, the dipeptide X is:
  1. (A)valine-glycine
  2. (B)alanine-glycine
  3. (C)valine-leucine
  4. (D)alanine-alanine

Correct answer: (B)

Step-by-step solution →
Q30·Chemistry·Electronic Effects and StabilitySingle correct
In which pairs, the first ion is more stable than the second?
  1. (A)(B) & (D) only
  2. (B)(A) & (B) only
  3. (C)(B) & (C) only
  4. (D)(A) & (C) only

Correct answer: (B)

Step-by-step solution →
Q31·Chemistry·Organic Compounds Containing HalogensSingle correct
Given below are two statements: Statement (I): Alcohols are formed when alkyl chlorides are treated with aqueous potassium hydroxide by elimination reaction. Statement (II): In alcoholic potassium hydroxide, alkyl chlorides form alkenes by abstracting the hydrogen from the β\betaβ-carbon. In the light of the above statements, choose the most appropriate answer from the options given below:
  1. (A)Both Statement I and Statement II are incorrect
  2. (B)Statement I is incorrect but Statement II is correct
  3. (C)Statement I is correct but Statement II is incorrect
  4. (D)Both Statement I and Statement II are correct

Correct answer: (B)

Step-by-step solution →
Q32·Chemistry·SolutionsSingle correct
Given below are two statements: Statement (I): Molal depression constant KfK_fKf​ is given by M1RTfΔSfus\dfrac{M_1 R T_f}{\Delta S_{fus}}ΔSfus​M1​RTf​​, where symbols have their usual meaning. Statement (II): KfK_fKf​ for benzene is less than the KfK_fKf​ for water. In the light of the above statements, choose the most appropriate answer from the options given below:
  1. (A)Statement I is incorrect but Statement II is correct
  2. (B)Both Statement I and Statement II are incorrect
  3. (C)Both Statement I and Statement II are correct
  4. (D)Statement I is correct but Statement II is incorrect

Correct answer: (D)

Step-by-step solution →
Q33·Chemistry·IUPAC NomenclatureSingle correct
The IUPAC name of the following compound is:
  1. (A)4-Hydroxyhept-1-en-6-yne
  2. (B)4-Hydroxyhept-6-en-1-yne
  3. (C)Hept-6-en-1-yn-4-ol
  4. (D)Hept-1-en-6-yn-4-ol

Correct answer: (D)

Step-by-step solution →
Q34·Chemistry·Purification and Characterisation of Organic CompoundsSingle correct
Match List-I (Separation of) with List-II (Separation Technique). Choose the correct answer from the options given below:
List-I (Separation of)List-II (Separation Technique)
A.Aniline from aniline-water mixtureI.Simple distillation
B.Glycerol from spent-lye in soap industryII.Fractional distillation
C.Different fractions of crude oil in petroleum industryIII.Distillation at reduced pressure
D.Chloroform-Aniline mixtureIV.Steam distillation
  1. (A)(A)-(IV), (B)-(III), (C)-(II), (D)-(I)
  2. (B)(A)-(I), (B)-(III), (C)-(II), (D)-(IV)
  3. (C)(A)-(III), (B)-(IV), (C)-(I), (D)-(II)
  4. (D)(A)-(I), (B)-(III), (C)-(IV), (D)-(II)

Correct answer: (A)

Step-by-step solution →
Q35·Chemistry·Carboxylic Acids and DerivativesSingle correct
A toxic compound "A" when reacted with NaCN in aqueous acidic medium yields an edible cooking component and food preservative "B". "B" is converted to "C" by diborane and can be used as an additive to petrol to reduce emission. "C" upon reaction with oleum at 140∘C140^\circ C140∘C yields an inhalable anaesthetic "D". Identify "A", "B", "C" and "D", respectively.
  1. (A)Methanol; formaldehyde; methyl chloride; chloroform
  2. (B)Ethanol; acetonitrile; ethylamine; ethylene
  3. (C)Methanol; acetic acid; ethanol; diethyl ether
  4. (D)Acetaldehyde; 2-hydroxypropanoic acid; propanoic acid; dipropyl ether

Correct answer: (C)

Step-by-step solution →
Q36·Chemistry·Coordination CompoundsSingle correct
The correct order of [FeF6]3−[FeF_6]^{3-}[FeF6​]3−, [CoF6]3−[CoF_6]^{3-}[CoF6​]3−, [Ni(CO)4][Ni(CO)_4][Ni(CO)4​] and [Ni(CN)4]2−[Ni(CN)_4]^{2-}[Ni(CN)4​]2− complex species based on the number of unpaired electrons present is:
  1. (A)[FeF6]3−>[CoF6]3−>[Ni(CN)4]2−>[Ni(CO)4][FeF_6]^{3-} > [CoF_6]^{3-} > [Ni(CN)_4]^{2-} > [Ni(CO)_4][FeF6​]3−>[CoF6​]3−>[Ni(CN)4​]2−>[Ni(CO)4​]
  2. (B)[Ni(CN)4]2−>[FeF6]3−>[CoF6]3−>[Ni(CO)4][Ni(CN)_4]^{2-} > [FeF_6]^{3-} > [CoF_6]^{3-} > [Ni(CO)_4][Ni(CN)4​]2−>[FeF6​]3−>[CoF6​]3−>[Ni(CO)4​]
  3. (C)[CoF6]3−>[FeF6]3−>[Ni(CO)4]>[Ni(CN)4]2−[CoF_6]^{3-} > [FeF_6]^{3-} > [Ni(CO)_4] > [Ni(CN)_4]^{2-}[CoF6​]3−>[FeF6​]3−>[Ni(CO)4​]>[Ni(CN)4​]2−
  4. (D)[FeF6]3−>[CoF6]3−>[Ni(CN)4]2−=[Ni(CO)4][FeF_6]^{3-} > [CoF_6]^{3-} > [Ni(CN)_4]^{2-} = [Ni(CO)_4][FeF6​]3−>[CoF6​]3−>[Ni(CN)4​]2−=[Ni(CO)4​]

Correct answer: (D)

Step-by-step solution →
Q37·Chemistry·Chemical ThermodynamicsSingle correct
Consider the given data: (a) HCl(g)+10H2O(l)→HCl.10H2OHCl(g) + 10H_2O(l) \rightarrow HCl.10H_2OHCl(g)+10H2​O(l)→HCl.10H2​O, ΔH=−69.01 kJ mol−1\Delta H = -69.01\ kJ\,mol^{-1}ΔH=−69.01 kJmol−1; (b) HCl(g)+40H2O(l)→HCl.40H2OHCl(g) + 40H_2O(l) \rightarrow HCl.40H_2OHCl(g)+40H2​O(l)→HCl.40H2​O, ΔH=−72.79 kJ mol−1\Delta H = -72.79\ kJ\,mol^{-1}ΔH=−72.79 kJmol−1. Choose the correct statement:
  1. (A)Dissolution of gas in water is an endothermic process
  2. (B)The heat of solution depends on the amount of solvent.
  3. (C)The heat of dilution for the HCl.10H2OHCl.10H_2OHCl.10H2​O to HCl.40H2OHCl.40H_2OHCl.40H2​O is 3.78 kJ mol−13.78\ kJ\,mol^{-1}3.78 kJmol−1.
  4. (D)The heat of formation of HCl solution is represented by both (a) and (b)

Correct answer: (B)

Step-by-step solution →
Q38·Chemistry·Atomic StructureSingle correct
Consider the ground state of chromium atom (Z=24)(Z = 24)(Z=24). How many electrons are with Azimuthal quantum number l=1l = 1l=1 and l=2l = 2l=2 respectively?
  1. (A)12 and 4
  2. (B)16 and 4
  3. (C)12 and 5
  4. (D)16 and 5

Correct answer: (C)

Step-by-step solution →
Q39·Chemistry·p-Block ElementsSingle correct
Given below are two statements: Statement (I): The first ionisation enthalpy of group 14 elements is higher than the corresponding elements of group 13. Statement (II): Melting points and boiling points of group 13 elements are in general much higher than the corresponding elements of group 14. In the light of the above statements, choose the most appropriate answer from the options given below:
  1. (A)Statement I is correct but Statement II is incorrect
  2. (B)Statement I is incorrect but Statement II is correct
  3. (C)Both Statement I and Statement II are incorrect
  4. (D)Both Statement I and Statement II are correct

Correct answer: (A)

Step-by-step solution →
Q40·Chemistry·Chemical KineticsSingle correct
Consider the following plots of log of rate constant (log⁡k\log klogk) vs 1/T1/T1/T for three different reactions. The correct order of activation energies of these reactions is:
  1. (A)Ea2>Ea1>Ea3Ea_2 > Ea_1 > Ea_3Ea2​>Ea1​>Ea3​
  2. (B)Ea1>Ea3>Ea2Ea_1 > Ea_3 > Ea_2Ea1​>Ea3​>Ea2​
  3. (C)Ea1>Ea2>Ea3Ea_1 > Ea_2 > Ea_3Ea1​>Ea2​>Ea3​
  4. (D)Ea3>Ea2>Ea1Ea_3 > Ea_2 > Ea_1Ea3​>Ea2​>Ea1​

Correct answer: (A)

Step-by-step solution →
Q41·Chemistry·d- and f-Block ElementsSingle correct
'X' is the number of electrons in t2gt_{2g}t2g​ orbitals of the most stable complex ion among [Fe(NH3)6]3+[Fe(NH_3)_6]^{3+}[Fe(NH3​)6​]3+, [Fe(Cl)6]3−[Fe(Cl)_6]^{3-}[Fe(Cl)6​]3−, [Fe(C2O4)3]3−[Fe(C_2O_4)_3]^{3-}[Fe(C2​O4​)3​]3− and [Fe(H2O)6]3+[Fe(H_2O)_6]^{3+}[Fe(H2​O)6​]3+. The nature of oxide of vanadium of the type V2OxV_2O_xV2​Ox​ is:
  1. (A)Acidic
  2. (B)Neutral
  3. (C)Basic
  4. (D)Amphoteric

Correct answer: (D)

Step-by-step solution →
Q42·Chemistry·p-Block ElementsSingle correct
The elements of Group 13 with highest and lowest first ionisation enthalpies are respectively:
  1. (A)B & Ga
  2. (B)B & Tl
  3. (C)Tl & B
  4. (D)B & In

Correct answer: (D)

Step-by-step solution →
Q43·Chemistry·IUPAC NomenclatureSingle correct
Consider the following molecule (X). The structure of X is:
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (B)

Step-by-step solution →
Q44·Chemistry·Chemical Bonding and Molecular StructureSingle correct
Given below are two statements: Statement (I): for ClF3ClF_3ClF3​, all three possible structures may be drawn as follows. Statement (II): Structure III is most stable, as the orbitals having the lone pairs are axial, where the lp–bp repulsion is minimum. In the light of the above statements, choose the most appropriate answer from the options given below:
  1. (A)Statement I is incorrect but statement II is correct
  2. (B)Statement I is correct but statement II is incorrect
  3. (C)Both Statement I and statement II are correct
  4. (D)Both Statement I and statement II are incorrect

Correct answer: (B)

Step-by-step solution →
Q45·Chemistry·Chemical KineticsSingle correct
Half life of zero order reaction A→A \rightarrowA→ product is 1 hour, when initial concentration of reactant is 2.0 mol L−12.0\ mol\,L^{-1}2.0 molL−1. The time required to decrease concentration of A from 0.50 to 0.25 mol L−10.25\ mol\,L^{-1}0.25 molL−1 is:
  1. (A)0.5 hour
  2. (B)4 hour
  3. (C)15 min
  4. (D)60 min

Correct answer: (C)

Step-by-step solution →
Q46·Chemistry·SolutionsInteger
Sea water, which can be considered as a 6 molar (6 M) solution of NaCl, has a density of 2 g mL−12\ g\,mL^{-1}2 gmL−1. The concentration of dissolved oxygen (O2)(O_2)(O2​) in sea water is 5.8 ppm. Then the concentration of dissolved oxygen (O2)(O_2)(O2​) in sea water, is x×10−4 mx \times 10^{-4}\ mx×10−4 m. x=x = x= ______ (Nearest integer). (Given: Molar mass of NaCl is 58.5 g mol−158.5\ g\,mol^{-1}58.5 gmol−1; Molar mass of O2O_2O2​ is 32 g mol−132\ g\,mol^{-1}32 gmol−1)

Correct answer: 2

Step-by-step solution →
Q47·Chemistry·Some Basic Concepts in ChemistryInteger
The amount of calcium oxide produced on heating 150 kg limestone (75% pure) is ______ kg. (Nearest integer). (Given molar mass in g mol−1^{-1}−1 of Ca:40, O:16, C:12)

Correct answer: 63

Step-by-step solution →
Q48·Chemistry·Coordination CompoundsInteger
A metal complex with a formula MCl3.3NH3MCl_3.3NH_3MCl3​.3NH3​ is involved in sp3d2sp^3d^2sp3d2 hybridisation. It upon reaction with excess of AgNO3AgNO_3AgNO3​ solution gives "x" moles of AgCl. Consider "x" is equal to the number of lone pairs of electron present in central atom of BrF3BrF_3BrF3​. Then the number of geometrical isomers exhibited by the complex is ______.

Correct answer: 2

Step-by-step solution →
Q49·Chemistry·Redox Reactions and ElectrochemistryInteger
The molar conductance of an infinitely dilute solution of ammonium chloride was found to be 185 S cm2 mol−1185\ S\,cm^2\,mol^{-1}185 Scm2mol−1 and the ionic conductance of hydroxyl and chloride ions are 170 and 70 S cm2 mol−170\ S\,cm^2\,mol^{-1}70 Scm2mol−1, respectively. If molar conductance of 0.02 M solution of ammonium hydroxide is 85.5 S cm2 mol−185.5\ S\,cm^2\,mol^{-1}85.5 Scm2mol−1, its degree of dissociation is given by x×10−1x \times 10^{-1}x×10−1. The value of x is ______ (Nearest integer).

Correct answer: 3

Step-by-step solution →
Q50·Chemistry·EquilibriumInteger
x mg of Mg(OH)2Mg(OH)_2Mg(OH)2​ (molar mass = 58) is required to be dissolved in 1.0 L of water to produce a pH of 10.0 at 298 K. The value of x is ______ mg. (Nearest integer). (Given: Mg(OH)2Mg(OH)_2Mg(OH)2​ is assumed to dissociate completely in H2OH_2OH2​O)

Correct answer: 3

Step-by-step solution →

Mathematics — JEE Main 4 April 2025 Shift 2

Q51·Mathematics·Application of DerivativesSingle correct
Let a>0a>0a>0. If the function f(x)=6x3−45ax2+108a2x+1f(x)=6x^3-45ax^2+108a^2x+1f(x)=6x3−45ax2+108a2x+1 attains its local maximum and minimum values at the points x1x_1x1​ and x2x_2x2​ respectively such that x1x2=54x_1x_2=54x1​x2​=54, then a+x1+x2a+x_1+x_2a+x1​+x2​ is equal to:
  1. (A)15
  2. (B)18
  3. (C)24
  4. (D)13

Correct answer: (B)

Step-by-step solution →
Q52·Mathematics·Limits and ContinuitySingle correct
Let fff be a differentiable function on R\mathbb{R}R such that f(2)=1f(2)=1f(2)=1, f′(2)=4f'(2)=4f′(2)=4. Let lim⁡x→0(f(2+x)f(2))3/x=eα\lim_{x\to0}\left(\dfrac{f(2+x)}{f(2)}\right)^{3/x}=e^{\alpha}limx→0​(f(2)f(2+x)​)3/x=eα. Then the number of times the curve y=4x3−4x2−4(α−7)x−αy=4x^3-4x^2-4(\alpha-7)x-\alphay=4x3−4x2−4(α−7)x−α meets x-axis is:
  1. (A)2
  2. (B)1
  3. (C)0
  4. (D)3

Correct answer: (A)

Step-by-step solution →
Q53·Mathematics·Inverse Trigonometric FunctionsSingle correct
The sum of the infinite series cot⁡−1(74)+cot⁡−1(194)+cot⁡−1(394)+cot⁡−1(674)+…\cot^{-1}\left(\dfrac{7}{4}\right)+\cot^{-1}\left(\dfrac{19}{4}\right)+\cot^{-1}\left(\dfrac{39}{4}\right)+\cot^{-1}\left(\dfrac{67}{4}\right)+\dotscot−1(47​)+cot−1(419​)+cot−1(439​)+cot−1(467​)+… is:
  1. (A)π2+tan⁡−1(12)\dfrac{\pi}{2}+\tan^{-1}\left(\dfrac{1}{2}\right)2π​+tan−1(21​)
  2. (B)π2−cot⁡−1(12)\dfrac{\pi}{2}-\cot^{-1}\left(\dfrac{1}{2}\right)2π​−cot−1(21​)
  3. (C)π2+cot⁡−1(12)\dfrac{\pi}{2}+\cot^{-1}\left(\dfrac{1}{2}\right)2π​+cot−1(21​)
  4. (D)π2−tan⁡−1(12)\dfrac{\pi}{2}-\tan^{-1}\left(\dfrac{1}{2}\right)2π​−tan−1(21​)

Correct answer: (D)

Step-by-step solution →
Q54·Mathematics·Sets, Relations and FunctionsSingle correct
Let A={−3,−2,−1,0,1,2,3}A=\{-3,-2,-1,0,1,2,3\}A={−3,−2,−1,0,1,2,3} and RRR be a relation on AAA defined by xRyxRyxRy if and only if 2x−y∈{0,1}2x-y\in\{0,1\}2x−y∈{0,1}. Let lll be the number of elements in RRR. Let mmm and nnn be the minimum number of elements required to be added in RRR to make it reflexive and symmetric relations, respectively. Then l+m+nl+m+nl+m+n is equal to:
  1. (A)18
  2. (B)17
  3. (C)15
  4. (D)16

Correct answer: (B)

Step-by-step solution →
Q55·Mathematics·Quadratic EquationsSingle correct
Let the product of ω1=(8+i)sin⁡θ+(7+4i)cos⁡θ\omega_1=(8+i)\sin\theta+(7+4i)\cos\thetaω1​=(8+i)sinθ+(7+4i)cosθ and ω2=(1+8i)sin⁡θ+(4+7i)cos⁡θ\omega_2=(1+8i)\sin\theta+(4+7i)\cos\thetaω2​=(1+8i)sinθ+(4+7i)cosθ be α+iβ\alpha+i\betaα+iβ, i=−1i=\sqrt{-1}i=−1​. Let ppp and qqq be the maximum and minimum values of α+β\alpha+\betaα+β respectively. Then p+qp+qp+q is equal to:
  1. (A)140
  2. (B)130
  3. (C)160
  4. (D)150

Correct answer: (B)

Step-by-step solution →
Q56·Mathematics·Three Dimensional GeometrySingle correct
Let the values of ppp, for which the shortest distance between the lines x+13=y4=z5\dfrac{x+1}{3}=\dfrac{y}{4}=\dfrac{z}{5}3x+1​=4y​=5z​ and r⃗=(pi^+2j^+k^)+λ(2i^+3j^+4k^)\vec{r}=(p\hat{i}+2\hat{j}+\hat{k})+\lambda(2\hat{i}+3\hat{j}+4\hat{k})r=(pi^+2j^​+k^)+λ(2i^+3j^​+4k^) is 16\dfrac{1}{\sqrt6}6​1​, be a,ba, ba,b, (a<b)(a<b)(a<b). Then the length of the latus rectum of the ellipse x2a2+y2b2=1\dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}=1a2x2​+b2y2​=1 is:
  1. (A)9
  2. (B)32\dfrac{3}{2}23​
  3. (C)23\dfrac{2}{3}32​
  4. (D)18

Correct answer: (C)

Step-by-step solution →
Q57·Mathematics·ParabolaSingle correct
The axis of a parabola is the line y=xy=xy=x and its vertex and focus are in the first quadrant at distances 2\sqrt22​ and 222\sqrt222​ units from the origin, respectively. If the point (1,k)(1,k)(1,k) lies on the parabola, then a possible value of kkk is:
  1. (A)4
  2. (B)9
  3. (C)3
  4. (D)8

Correct answer: (B)

Step-by-step solution →
Q58·Mathematics·Sets, Relations and FunctionsSingle correct
Let the domains of the functions f(x)=log⁡4log⁡3log⁡7(8−log⁡2(x2+4x+5))f(x)=\log_4\log_3\log_7\left(8-\log_2(x^2+4x+5)\right)f(x)=log4​log3​log7​(8−log2​(x2+4x+5)) and g(x)=sin⁡−1(7x+10x−2)g(x)=\sin^{-1}\left(\dfrac{7x+10}{x-2}\right)g(x)=sin−1(x−27x+10​) be (α,β)(\alpha,\beta)(α,β) and [γ,δ][\gamma,\delta][γ,δ], respectively. Then α2+β2+γ2+δ2\alpha^2+\beta^2+\gamma^2+\delta^2α2+β2+γ2+δ2 is equal to:
  1. (A)15
  2. (B)13
  3. (C)16
  4. (D)14

Correct answer: (A)

Step-by-step solution →
Q59·Mathematics·ParabolaSingle correct
A line passing through the point A(−2,0)A(-2,0)A(−2,0), touches the parabola P:y2=x−2P:y^2=x-2P:y2=x−2 at the point BBB in the first quadrant. The area of the region bounded by the line ABABAB, parabola PPP and the x-axis, is:
  1. (A)73\dfrac{7}{3}37​
  2. (B)2
  3. (C)83\dfrac{8}{3}38​
  4. (D)3

Correct answer: (C)

Step-by-step solution →
Q60·Mathematics·HyperbolaSingle correct
Let the sum of the focal distances of the point P(4,3)P(4,3)P(4,3) on the hyperbola H:x2a2−y2b2=1H:\dfrac{x^2}{a^2}-\dfrac{y^2}{b^2}=1H:a2x2​−b2y2​=1 be 8538\sqrt{\dfrac{5}{3}}835​​. If for HHH, the length of the latus rectum is lll and the product of the focal distances of the point PPP is mmm, then 9l2+6m9l^2+6m9l2+6m is equal to:
  1. (A)184
  2. (B)186
  3. (C)185
  4. (D)187

Correct answer: (C)

Step-by-step solution →
Q61·Mathematics·Matrices and DeterminantsSingle correct
Let the matrix A=[100101010]A=\begin{bmatrix}1&0&0\\1&0&1\\0&1&0\end{bmatrix}A=​110​001​010​​ satisfy An=An−2+A2−IA^n=A^{n-2}+A^2-IAn=An−2+A2−I for n≥3n\ge3n≥3. Then the sum of all the elements of A50A^{50}A50 is:
  1. (A)53
  2. (B)52
  3. (C)39
  4. (D)44

Correct answer: (A)

Step-by-step solution →
Q62·Mathematics·Sequence and SeriesSingle correct
If the sum of the first 20 terms of the series 4⋅14+3⋅12+14+4⋅24+3⋅22+24+4⋅34+3⋅32+34+…\dfrac{4\cdot1}{4+3\cdot1^2+1^4}+\dfrac{4\cdot2}{4+3\cdot2^2+2^4}+\dfrac{4\cdot3}{4+3\cdot3^2+3^4}+\dots4+3⋅12+144⋅1​+4+3⋅22+244⋅2​+4+3⋅32+344⋅3​+… is mn\dfrac{m}{n}nm​, where mmm and nnn are coprime, then m+nm+nm+n is equal to:
  1. (A)423
  2. (B)420
  3. (C)421
  4. (D)422

Correct answer: (C)

Step-by-step solution →
Q63·Mathematics·Binomial Theorem and Its Simple ApplicationsSingle correct
If 12(151)+22(152)+32(153)+⋯+152(1515)=2m⋅3n⋅5k1^2\binom{15}{1}+2^2\binom{15}{2}+3^2\binom{15}{3}+\dots+15^2\binom{15}{15}=2^m\cdot3^n\cdot5^k12(115​)+22(215​)+32(315​)+⋯+152(1515​)=2m⋅3n⋅5k, where m,n,k∈Nm,n,k\in\mathbb{N}m,n,k∈N, then m+n+km+n+km+n+k is equal to:
  1. (A)19
  2. (B)21
  3. (C)18
  4. (D)15

Correct answer: (A)

Step-by-step solution →
Q64·Mathematics·EllipseSingle correct
Let for two distinct values of ppp the lines y=x+py=x+py=x+p touch the ellipse E:x242+y232=1E:\dfrac{x^2}{4^2}+\dfrac{y^2}{3^2}=1E:42x2​+32y2​=1 at the points AAA and BBB. Let the line y=xy=xy=x intersect EEE at the points CCC and DDD. Then the area of the quadrilateral ABCDABCDABCD is equal to:
  1. (A)36
  2. (B)24
  3. (C)48
  4. (D)20

Correct answer: (B)

Step-by-step solution →
Q65·Mathematics·Sequence and SeriesSingle correct
Consider two sets AAA and BBB, each containing three numbers in A.P. Let the sum and the product of the elements of AAA be 36 and ppp respectively and the sum and the product of the elements of BBB be 36 and qqq respectively. Let ddd and DDD be the common differences of the APs in AAA and BBB respectively such that D=d+3D=d+3D=d+3, d>0d>0d>0. If p+qp−q=195\dfrac{p+q}{p-q}=\dfrac{19}{5}p−qp+q​=519​, then p−qp-qp−q is equal to:
  1. (A)600
  2. (B)450
  3. (C)630
  4. (D)540

Correct answer: (D)

Step-by-step solution →
Q66·Mathematics·Differential EquationsSingle correct
If a curve y=y(x)y=y(x)y=y(x) passes through the point (1,π2)\left(1,\dfrac{\pi}{2}\right)(1,2π​) and satisfies the differential equation (7x4cot⁡y−excosec⁡y)dxdy=x5(7x^4\cot y-e^x\operatorname{cosec}y)\dfrac{dx}{dy}=x^5(7x4coty−excosecy)dydx​=x5, x≥1x\ge1x≥1, then at x=2x=2x=2, the value of cos⁡y\cos ycosy is:
  1. (A)2e2−e64\dfrac{2e^2-e}{64}642e2−e​
  2. (B)2e2+e64\dfrac{2e^2+e}{64}642e2+e​
  3. (C)2e2−e128\dfrac{2e^2-e}{128}1282e2−e​
  4. (D)2e2+e128\dfrac{2e^2+e}{128}1282e2+e​

Correct answer: (C)

Step-by-step solution →
Q67·Mathematics·EllipseSingle correct
The centre of a circle CCC is at the centre of the ellipse E:x2a2+y2b2=1E:\dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}=1E:a2x2​+b2y2​=1, a>ba>ba>b. Let CCC pass through the foci F1F_1F1​ and F2F_2F2​ of EEE such that the circle CCC and the ellipse EEE intersect at four points. Let PPP be one of these four points. If the area of the triangle PF1F2PF_1F_2PF1​F2​ is 30 and the length of the major axis of EEE is 17, then the distance between the foci of EEE is:
  1. (A)26
  2. (B)13
  3. (C)12
  4. (D)132\dfrac{13}{2}213​

Correct answer: (B)

Step-by-step solution →
Q68·Mathematics·Definite IntegrationSingle correct
Let f(x)+2f(1x)=x2+5f(x)+2f\left(\dfrac{1}{x}\right)=x^2+5f(x)+2f(x1​)=x2+5 and 2g(x)−3g(12)=x2g(x)-3g\left(\dfrac{1}{2}\right)=x2g(x)−3g(21​)=x, x>0x>0x>0. If α=∫12f(x) dx\alpha=\displaystyle\int_1^2 f(x)\,dxα=∫12​f(x)dx, and β=∫12g(x) dx\beta=\displaystyle\int_1^2 g(x)\,dxβ=∫12​g(x)dx, then the value of 9α+β9\alpha+\beta9α+β is:
  1. (A)1
  2. (B)0
  3. (C)10
  4. (D)11

Correct answer: (D)

Step-by-step solution →
Q69·Mathematics·Three Dimensional GeometrySingle correct
Let AAA be the point of intersection of the lines L1:x−71=y−50=z−3−1L_1:\dfrac{x-7}{1}=\dfrac{y-5}{0}=\dfrac{z-3}{-1}L1​:1x−7​=0y−5​=−1z−3​ and L2:x−13=y+34=z+75L_2:\dfrac{x-1}{3}=\dfrac{y+3}{4}=\dfrac{z+7}{5}L2​:3x−1​=4y+3​=5z+7​. Let BBB and CCC be the points on the lines L1L_1L1​ and L2L_2L2​ respectively such that AB=AC=15AB=AC=\sqrt{15}AB=AC=15​. Then the square of the area of the triangle ABCABCABC is:
  1. (A)54
  2. (B)63
  3. (C)57
  4. (D)60

Correct answer: (A)

Step-by-step solution →
Q70·Mathematics·Statistics and ProbabilitySingle correct
Let the mean and the standard deviation of the observation 2,3,3,4,5,7,a,b2, 3, 3, 4, 5, 7, a, b2,3,3,4,5,7,a,b be 4 and 2\sqrt22​ respectively. The mean deviation about the mode of these observations is:
  1. (A)1
  2. (B)34\dfrac{3}{4}43​
  3. (C)2
  4. (D)12\dfrac{1}{2}21​

Correct answer: (A)

Step-by-step solution →
Q71·Mathematics·Complex NumbersInteger
If α\alphaα is a root of the equation x2+x+1=0x^2+x+1=0x2+x+1=0 and ∑k=1n(αk+1αk)2=20\displaystyle\sum_{k=1}^{n}\left(\alpha^k+\dfrac{1}{\alpha^k}\right)^2=20k=1∑n​(αk+αk1​)2=20, then nnn is equal to ______.

Correct answer: 11

Step-by-step solution →
Q72·Mathematics·Indefinite IntegrationInteger
If ∫(1+x2+x)10(1+x2−x)9 dx=1m((1+x2+x)n(n1+x2−x))+C\displaystyle\int\dfrac{\left(\sqrt{1+x^2}+x\right)^{10}}{\left(\sqrt{1+x^2}-x\right)^{9}}\,dx=\dfrac{1}{m}\left(\left(\sqrt{1+x^2}+x\right)^{n}\left(n\sqrt{1+x^2}-x\right)\right)+C∫(1+x2​−x)9(1+x2​+x)10​dx=m1​((1+x2​+x)n(n1+x2​−x))+C, where CCC is the constant of integration and m,n∈Nm,n\in\mathbb{N}m,n∈N, then m+nm+nm+n is equal to ______.

Correct answer: 379

Step-by-step solution →
Q73·Mathematics·Statistics and ProbabilityInteger
A card from a pack of 52 cards is lost. From the remaining 51 cards, nnn cards are drawn and are found to be spades. If the probability of the lost card to be a spade is 1150\dfrac{11}{50}5011​, then nnn is equal to ______.

Correct answer: 2

Step-by-step solution →
Q74·Mathematics·Permutations and CombinationsInteger
Let mmm and nnn, (m<n)(m<n)(m<n) be two 2-digit numbers. Then the total number of pairs (m,n)(m,n)(m,n), such that gcd⁡(m,n)=6\gcd(m,n)=6gcd(m,n)=6, is ______.

Correct answer: 64

Step-by-step solution →
Q75·Mathematics·Vector AlgebraInteger
Let the three sides of a triangle ABC be given by the vectors 2i^−j^+k^2\hat{i}-\hat{j}+\hat{k}2i^−j^​+k^, i^−3j^−5k^\hat{i}-3\hat{j}-5\hat{k}i^−3j^​−5k^ and 3i^−4j^−4k^3\hat{i}-4\hat{j}-4\hat{k}3i^−4j^​−4k^. Let G be the centroid of the triangle ABC. Then 6(∣AG∣2+∣BG∣2+∣CG∣2)6\left(|AG|^2+|BG|^2+|CG|^2\right)6(∣AG∣2+∣BG∣2+∣CG∣2) is equal to ______.

Correct answer: 164

Step-by-step solution →

Chapters tested in this paper

Open any chapter to practise every past-year question on that topic across all papers, and see how often it has actually appeared.

  • Properties of Solids and Liquids 172/186
  • Three Dimensional Geometry 176/186
  • Matrices and Determinants 180/186
  • Coordination Compounds 176/186
  • Sets, Relations and Functions 165/186
  • Current Electricity 160/186
  • Sequence and Series 164/186
  • p-Block Elements 164/186
  • Definite Integration 168/186
  • Rotational Motion 172/186
  • Redox Reactions and Electrochemistry 177/186
  • Geometrical Optics 172/186
  • Kinematics 156/186
  • Vector Algebra 173/186
  • Differential Equations 167/186
  • Probability 176/186
  • Permutations and Combinations 162/186
  • Magnetic Field of Current 147/186
  • Binomial Theorem and Its Simple Applications 158/186
  • Electromagnetic Waves 144/186
  • Chemical Bonding and Molecular Structure 151/186
  • Application of Derivatives 139/186
  • Limits and Continuity 149/186
  • d- and f-Block Elements 126/186
  • Thermodynamics 154/186
  • Aldehydes and Ketones 135/186
  • Equilibrium 163/186
  • Solutions 158/186
  • Laws of Motion 130/186
  • Chemical Thermodynamics 165/186
  • Units and Measurements 149/186
  • Complex Numbers 165/186
  • Biomolecules 162/186
  • Chemical Kinetics 169/186
  • Gravitation 152/186
  • Electric Field and Coulomb's Law 133/186
  • Atomic Structure 161/186
  • Electronic Devices 145/186
  • Amines 133/186
  • Quadratic Equations 148/186
  • Some Basic Concepts in Chemistry 129/186
  • Electromagnetic Induction 120/186
  • Wave Optics 130/186
  • Kinetic Theory of Gases 135/186
  • Purification and Characterisation of Organic Compounds 116/186
  • Nuclei 116/186
  • Organic Compounds Containing Halogens 109/186
  • Waves 109/186
  • Capacitors and Dielectrics 115/186
  • Atoms 112/186
  • Parabola 101/186
  • Statistics 118/186
  • Ellipse 103/186
  • Inverse Trigonometric Functions 93/186
  • Electronic Effects and Stability 74/186
  • Hyperbola 77/186
  • Indefinite Integration 66/186
  • Carboxylic Acids and Derivatives 54/186
  • IUPAC Nomenclature 37/186
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