Jarvis OS
PYQ papersPricingSign inGet started
  1. Home
  2. /JEE Main PYQs
  3. /2026
  4. /6 Apr Shift 1

JEE Main 6 April 2026 Shift 1 Question Paper with Answers

6 April 2026 · April session · 75 questions

The complete JEE Main 6 April 2026 Shift 1 paper — all 75 questions with the correct answer for each, tagged to the chapter it tests. Free to read, no account needed.

Physics
25
Chemistry
25
Mathematics
25

Physics — JEE Main 6 April 2026 Shift 1

Q1·PhysicsSingle correct
The density ρ of a uniform cylinder is determined by measuring its mass m, length l and diameter d. The measured values of m, l and d are 97.42 ± 0.02 g, 8.35 ± 0.05 mm and 20.20 ± 0.02 mm, respectively. Calculated percentage fractional error in ρ is ________.
  1. (A)0.63%
  2. (B)0.82%
  3. (C)0.72%
  4. (D)0.25%

Correct answer: (B)

Step-by-step solution →
Q2·PhysicsSingle correct
The potential energy of a particle changes with distance x from a fixed origin as V=Axx+BV = \frac{A\sqrt{x}}{x + B}V=x+BAx​​, where A and B are constant with appropriate dimensions. The dimensions of AB are ________.
  1. (A)[M1L5/2T−2][M^{1}L^{5/2}T^{-2}][M1L5/2T−2]
  2. (B)[M3/2L5/2T−2][M^{3/2}L^{5/2}T^{-2}][M3/2L5/2T−2]
  3. (C)[M1L2T−2][M^{1}L^{2}T^{-2}][M1L2T−2]
  4. (D)[M1L7/2T−2][M^{1}L^{7/2}T^{-2}][M1L7/2T−2]

Correct answer: (D)

Step-by-step solution →
Q3·PhysicsSingle correct
The rain drop of mass 1 g, starts with zero velocity from a height of 1 km. It hits the ground with a speed of 5 m/s. The work done by the unknown resistive force is ________ J. (take g = 10 m/s²)
  1. (A)−8.75
  2. (B)−8.35
  3. (C)−9.55
  4. (D)−9.98

Correct answer: (D)

Step-by-step solution →
Q4·PhysicsSingle correct
Two blocks (P and Q) with respectively masses 2 kg and 1.5 kg are joined by a massless thread. These blocks are mounted on a frictionless pulley which is fixed on the edge of a cube (S), as shown in the figure below. Block P is positioned on the top surface which has no friction and block Q is in contact with side-surface, having coefficient friction μ. The cube (S) moves towards the right with acceleration of g2\frac{g}{2}2g​, where g is gravitational acceleration. During this movement the block P and Q remain stationary. The value of μ is ________. (take g = 10 m/s²)
  1. (A)0.33
  2. (B)0.67
  3. (C)1
  4. (D)0.5

Correct answer: (B)

Step-by-step solution →
Q5·PhysicsSingle correct
A lift of mass 1600 kg is supported by thick iron wire. If the maximum stress which the wire can withstand is 4 × 108^{8}8 N/m² and its radius is 4 mm, then maximum acceleration the lift can take is ________ m/s². (take g = 10 m/s² and π = 3.14)
  1. (A)2.56
  2. (B)3.89
  3. (C)4.32
  4. (D)5.16

Correct answer: (A)

Step-by-step solution →
Q6·PhysicsSingle correct
A solid sphere of radius 4 cm and mass 5 kg is rotating (rotation axis is passing through the centre of the sphere) with an angular velocity of 1200 rpm. It is brought to rest in 10 s by applying a constant torque. The torque applied and the number of rotations it made before it comes to rest are ________ and ________ respectively.
  1. (A)0.128π Nm, 100
  2. (B)0.0128π Nm, 50
  3. (C)0.128π Nm, 50
  4. (D)0.0128π Nm, 100

Correct answer: (D)

Step-by-step solution →
Q7·PhysicsSingle correct
A smooth inclined plane ends in a vertical circular loop, as shown in the figure. A small body is released from height h as shown. If the body exerts a force of three times its weight on the plane at the highest point of circle then the height h = αR. The value of α is ________.
  1. (A)2
  2. (B)4
  3. (C)3
  4. (D)6

Correct answer: (B)

Step-by-step solution →
Q8·PhysicsSingle correct
The position of center of mass of three masses 2 kg, 3 kg and 15 kg placed with respect to mid point (p) of normal bisector, as shown in the figure is ________.
  1. (A)(34,1.25)\left(\frac{\sqrt{3}}{4}, 1.25\right)(43​​,1.25)
  2. (B)(34,1.0)\left(\frac{\sqrt{3}}{4}, 1.0\right)(43​​,1.0)
  3. (C)(0, 0)
  4. (D)(1.25, 0)

Correct answer: (A)

Step-by-step solution →
Q9·PhysicsSingle correct
The two wires A and B of equal cross-section but of different materials are joined together. The ratio of Young's modulus of wire A and wire B is 20/11. When the joined wire is kept under certain tension the elongations in the wires A and B are equal. If the length of wire A is 2.2 m, then the length of wire B is ________ m.
  1. (A)1.1
  2. (B)2.22
  3. (C)1.21
  4. (D)4.44

Correct answer: (C)

Step-by-step solution →
Q10·PhysicsSingle correct
Two closed vessels of same volume are joined through a narrow tube and both vessels are filled with air of pressure 90 kPa and temperature 400 K. Keeping the temperature of one vessel constant at 400 K the second vessel temperature is raised to 500 K. The final pressure in the vessels is ________ kPa.
  1. (A)100
  2. (B)120
  3. (C)90
  4. (D)105

Correct answer: (A)

Step-by-step solution →
Q11·PhysicsSingle correct
In interference experiment the path difference between two interfering waves at a point A on the screen is λ/3, where λ is the wavelength of these waves, and at another point B the path difference is λ/6. The ratio of intensities at points A and B is ________.
  1. (A)3
  2. (B)4
  3. (C)1/3
  4. (D)1/4

Correct answer: (C)

Step-by-step solution →
Q12·PhysicsSingle correct
A particle is executing simple harmonic motion. Its amplitude is A and time period is 5 sec. The time required by it to move from x = A to x=A2x = \frac{A}{\sqrt{2}}x=2​A​ is ________ sec.
  1. (A)1/4
  2. (B)5/4
  3. (C)5/8
  4. (D)3/8

Correct answer: (C)

Step-by-step solution →
Q13·PhysicsSingle correct
A thin half ring of radius 35 cm is uniformly charged with a total charge of Q coulomb. If the magnitude of the electric field at centre of the half ring is 100 V/m, then the value of Q is ________ nC. (ε₀ = 8.85 × 10−12^{-12}−12 C²/Nm² and π = 3.14)
  1. (A)2.14
  2. (B)2.44
  3. (C)3.25
  4. (D)0.7

Correct answer: (A)

Step-by-step solution →
Q14·PhysicsSingle correct
The maximum rated power of the LED is 2 mW and it is used in the circuit with input voltage of 5 V as shown in the figure below. The current through resistance RSR_SRS​ is 0.5 mA. The minimum value of the resistance of RSR_SRS​, to ensure that the LED is not damaged is _______ kΩ.
  1. (A)6
  2. (B)2
  3. (C)4
  4. (D)5

Correct answer: (B)

Step-by-step solution →
Q15·PhysicsSingle correct
A point light source emits E.M. waves in free space. A detector, placed at a distance of LLL m, measures the intensity as IoI_oIo​. The detector is now shifted to another location on the same spherical surface ensuring the angle between original location and new location as 45°. The measured intensity at new location will be _______.
  1. (A)Io4\frac{I_o}{4}4Io​​
  2. (B)IoI_oIo​
  3. (C)Io2\frac{I_o}{\sqrt{2}}2​Io​​
  4. (D)Io2\frac{I_o}{2}2Io​​

Correct answer: (B)

Step-by-step solution →
Q16·PhysicsSingle correct
A spherical interface lens of radius RRR separates two media of refractive indices 1 and 1.4 respectively as shown in the figure below. A point source is placed at a distance of 4R4R4R in front of spherical interface. The magnitude of the magnification of point source image is _______.
  1. (A)1.66
  2. (B)2.33
  3. (C)2.66
  4. (D)1.33

Correct answer: (A)

Step-by-step solution →
Q17·PhysicsSingle correct
A small cube of side 1 mm is placed at the centre of a circular loop of radius 10 cm carrying a current of 2 A. The magnetic energy stored inside the cube is α×10−14\alpha \times 10^{-14}α×10−14 J. The value of α\alphaα is _______. (μo=4π×10−7\mu_o = 4\pi \times 10^{-7}μo​=4π×10−7 Tm/A, π=3.14\pi = 3.14π=3.14)
  1. (A)6.28
  2. (B)6.28×10−66.28 \times 10^{-6}6.28×10−6
  3. (C)628
  4. (D)6.28×10−46.28 \times 10^{-4}6.28×10−4

Correct answer: (A)

Step-by-step solution →
Q18·PhysicsSingle correct
An inductor of inductance 10 mH having resistance of 100 Ω is connected to battery of E.M.F. 1.0 V through a switch as shown in the figure below. After switch is closed, the ratio of instantaneous voltages across the inductor when the current passing through it is 2 mA and 4 mA is _______.
  1. (A)4/3
  2. (B)3/4
  3. (C)5/3
  4. (D)3/5

Correct answer: (A)

Step-by-step solution →
Q19·PhysicsSingle correct
The ratio of momentum of the photons of the 1st^{st}st and 2nd^{nd}nd line of Balmer series of Hydrogen atoms is α/β\alpha/\betaα/β. The possible values of α\alphaα and β\betaβ are:-
  1. (A)27 and 20
  2. (B)3 and 16
  3. (C)5 and 36
  4. (D)20 and 27

Correct answer: (D)

Step-by-step solution →
Q20·PhysicsSingle correct
A LCR series circuit driven with Erms=90E_{rms} = 90Erms​=90 V at frequency fd=30f_d = 30fd​=30 Hz has resistance R=80R = 80R=80 Ω, an inductance with inductive reactance XL=20.0X_L = 20.0XL​=20.0 Ω and capacitance with capacitive reactance XC=80.0X_C = 80.0XC​=80.0 Ω. The power factor of the circuit is _______.
  1. (A)0.8
  2. (B)0.64
  3. (C)0.9
  4. (D)0.5

Correct answer: (A)

Step-by-step solution →
Q21·PhysicsNumerical
Refer to the circuit diagram given below. The heat generated across the 6 Ω resistance in 100 second is α100\frac{\alpha}{100}100α​ J. The value of α\alphaα is _______. (Nearest integer)

Correct answer: 3477

Step-by-step solution →
Q22·PhysicsNumerical
An unpolarized light of intensity IoI_oIo​ passes through polarizer and then through a certain optically active solution and finally it goes to analyser. If the angle between analyser and polariser is 0° and intensity of light emerged from analyser is 38Io\frac{3}{8}I_o83​Io​, the angle of rotation of the light by the solution with respect to analyser is _______ degrees.

Correct answer: 30

Step-by-step solution →
Q23·PhysicsNumerical
The energy released when 717.13\frac{7}{17.13}17.137​ kg of 37^{7}_{3}37​Li is converted into 24^{4}_{2}24​He by proton bombardment is α×1032\alpha \times 10^{32}α×1032 eV. The value of α\alphaα is _______. (Nearest integer) (Mass of 37^{7}_{3}37​Li = 7.0183 u, mass of 24^{4}_{2}24​He = 4.004 u, mass of proton = 1.008 u and 1 u = 931 MeV/c2^{2}2 and Avogadro number = 6.0×10236.0 \times 10^{23}6.0×1023)

Correct answer: 6

Step-by-step solution →
Q24·PhysicsNumerical
A three coulomb charge moves from the point (0,−2,−5)(0, -2, -5)(0,−2,−5) to the point (5,1,2)(5, 1, 2)(5,1,2) in an electric field expressed as E⃗=2xi^+3y2j^+4k^\vec{E} = 2x\hat{i} + 3y^{2}\hat{j} + 4\hat{k}E=2xi^+3y2j^​+4k^ N/C. The work done in moving the charge is _______ J.

Correct answer: 186

Step-by-step solution →
Q25·PhysicsNumerical
A certain gas is isothermally compressed to (13)rd\left(\frac{1}{3}\right)^{rd}(31​)rd of its initial volume (Vo=3V_o = 3Vo​=3 litre) by applying required pressure. If the bulk modulus of the gas is 3×1053 \times 10^{5}3×105 N/m2^{2}2, the magnitude of work done on the gas is _______ J.

Correct answer: 989

Step-by-step solution →

Chemistry — JEE Main 6 April 2026 Shift 1

Q26·ChemistrySingle correct
An oxide of iron contains 69.9% iron, its empirical formula, is: (Given: Molar mass of Fe and O are 56 and 16 g mol⁻¹ respectively.)
  1. (A)FeO
  2. (B)Fe₂O₃
  3. (C)Fe₃O₄
  4. (D)FeO₃

Correct answer: (B)

Step-by-step solution →
Q27·ChemistrySingle correct
If shortest wavelength of hydrogen atom in Lyman series is xxx, then longest wavelength in Balmer series of He⁺ is:
  1. (A)9x5\frac{9x}{5}59x​
  2. (B)36x5\frac{36x}{5}536x​
  3. (C)x4\frac{x}{4}4x​
  4. (D)5x9\frac{5x}{9}95x​

Correct answer: (A)

Step-by-step solution →
Q28·ChemistrySingle correct
Match the LIST-I (Orbital) with LIST-II (Radial nodes and nodal plane) Choose the correct answer from the options given below:
List-I (Orbital)List-II (Radial nodes and nodal plane)
A.2sI.1 Radial node + two nodal planes
B.3sII.1 Radial node + one nodal plane
C.3pIII.2 Radial nodes + No nodal plane
D.4dIV.1 Radial node + No nodal plane
  1. (A)A-IV, B-I, C-III, D-II
  2. (B)A-IV, B-II, C-III, D-I
  3. (C)A-III, B-I, C-IV, D-II
  4. (D)A-IV, B-III, C-II, D-I

Correct answer: (D)

Step-by-step solution →
Q29·ChemistrySingle correct
The pairs among A = [SO₃²⁻, CO₃²⁻], B = [O₂²⁻, F₂], C = [CN⁻, CO], D = [NH₃, H₃O⁺] and E = [MnO₄²⁻, CrO₄²⁻] that do not have similar Lewis dot structure are
  1. (A)A, B and E
  2. (B)A and E
  3. (C)B, C and D
  4. (D)C and D

Correct answer: (B)

Step-by-step solution →
Q30·ChemistrySingle correct
Arrange the following isothermal processes in order of the magnitude of the work (p−V)(p - V)(p−V) involved between states 1 and 2. A. Expansion in single stage wAw_AwA​ B. Expansion in multi stages wBw_BwB​ C. Compression in single stage wCw_CwC​ D. Compression in multi stages wDw_DwD​ Choose the correct option.
  1. (A)∣wB∣>∣wA∣>∣wC∣>∣wD∣|w_B| > |w_A| > |w_C| > |w_D|∣wB​∣>∣wA​∣>∣wC​∣>∣wD​∣
  2. (B)∣wC∣>∣wD∣>∣wA∣>∣wB∣|w_C| > |w_D| > |w_A| > |w_B|∣wC​∣>∣wD​∣>∣wA​∣>∣wB​∣
  3. (C)∣wC∣>∣wD∣>∣wB∣>∣wA∣|w_C| > |w_D| > |w_B| > |w_A|∣wC​∣>∣wD​∣>∣wB​∣>∣wA​∣
  4. (D)∣wB∣>∣wA∣>∣wD∣>∣wC∣|w_B| > |w_A| > |w_D| > |w_C|∣wB​∣>∣wA​∣>∣wD​∣>∣wC​∣

Correct answer: (C)

Step-by-step solution →
Q31·ChemistrySingle correct
When 0.25 moles of a non-volatile, non-ionizable solute was dissolved in 1 mole of a solvent the vapor pressure of solution was x%x\%x% of vapor pressure of pure solvent. What is x%x\%x%?
  1. (A)50%
  2. (B)60%
  3. (C)70%
  4. (D)80%

Correct answer: (D)

Step-by-step solution →
Q32·ChemistrySingle correct
One mole each of He and A(g) are taken in a 10 L closed flask and heated to 400 K to establish the following equilibrium. A(g) ⇌ B(g). KcK_cKc​ for this reaction at 400 K is 4.0. The partial pressures (in atm) of He and B(g) are respectively (at equilibrium) (Assume He, A(g) and B(g) behave as ideal gases) (Given: R = 0.082 L atm K⁻¹ mol⁻¹)
  1. (A)3.28, 2.624
  2. (B)2.624, 3.28
  3. (C)3.28, 0.656
  4. (D)0.656, 6.56

Correct answer: (A)

Step-by-step solution →
Q33·ChemistrySingle correct
Consider the following data. BaSO₄ is sparingly soluble in water. If the conductivity of the saturated BaSO₄ solution is x S cm⁻¹ then the solubility product of BaSO₄ can be given as (Here Λm = Λ°m)
ElectrolyteΛ°m (S cm² mol⁻¹)
BaCl₂x₁
H₂SO₄x₂
HClx₃
  1. (A)106x2α2(x1+x2−2x3)2\frac{10^{6}x^{2}}{\alpha^{2}(x_1 + x_2 - 2x_3)^{2}}α2(x1​+x2​−2x3​)2106x2​
  2. (B)x2(x1+x2−2x3)2\frac{x^{2}}{(x_1 + x_2 - 2x_3)^{2}}(x1​+x2​−2x3​)2x2​
  3. (C)α2(x1+x2−2x3)2106x2\frac{\alpha^{2}(x_1 + x_2 - 2x_3)^{2}}{10^{6}x^{2}}106x2α2(x1​+x2​−2x3​)2​
  4. (D)x2(x1+x2+2x3)2\frac{x^{2}}{(x_1 + x_2 + 2x_3)^{2}}(x1​+x2​+2x3​)2x2​

Correct answer: (A)

Step-by-step solution →
Q34·ChemistrySingle correct
Given below are two statements: Statement I: Aluminium is more electropositive than thallium as the standard electrode potential value of EAl3+/Al∘E^\circ_{Al^{3+}/Al}EAl3+/Al∘​ is negative and ETl3+/Tl∘E^\circ_{Tl^{3+}/Tl}ETl3+/Tl∘​ is positive. Statement II: The sum of first three ionization enthalpies of boron is very high when compared to that of aluminium. Due to this reason boron forms covalent compounds only and aluminium forms Al³⁺ ion. In the light of the above statements, choose the correct answer from the options given below
  1. (A)Both Statement I and Statement II are true
  2. (B)Both Statement I and Statement II are false
  3. (C)Statement I is true but Statement II is false
  4. (D)Statement I is false but Statement II is true

Correct answer: (A)

Step-by-step solution →
Q35·ChemistrySingle correct
The correct statements among the following are. A. Basic vanadium oxide is used in the manufacture of H₂SO₄. B. The spin-only magnetic moment value of the transition metal halide employed in Ziegler-Natta polymerization is 2.84 BM. C. The p-block metal compound employed in Ziegler-Natta polymerization has the metal in +3 oxidation state. D. The number of electrons present in the outer most 'd' orbital of metal halide employed in Wacker process is 8. Choose the correct answer from the options given below:
  1. (A)A and B Only
  2. (B)A, C and D Only
  3. (C)C and D Only
  4. (D)B, C and D Only

Correct answer: (C)

Step-by-step solution →
Q36·ChemistrySingle correct
Match the LIST-I (Electronic configuration of tetrahedral metal ion) with LIST-II (Crystal Field Stabilization Energy (Δₜ)) Choose the correct answer from the options given below:
List-I (Electronic configuration of tetrahedral metal ion)List-II (Crystal Field Stabilization Energy (Δₜ))
A.d²I.−0.6
B.d⁴II.−0.8
C.d⁶III.−1.2
D.d⁸IV.−0.4
  1. (A)A-III, B-IV, C-II, D-I
  2. (B)A-III, B-I, C-IV, D-II
  3. (C)A-III, B-IV, C-I, D-II
  4. (D)A-II, B-I, C-IV, D-III

Correct answer: (C)

Step-by-step solution →
Q37·ChemistrySingle correct
Which of the following are true about the energy of the given d-orbitals of a tetrahedral complex? A. dxy=dxz>dx2−y2d_{xy} = d_{xz} > d_{x^2-y^2}dxy​=dxz​>dx2−y2​ B. dxy=dyz>dz2d_{xy} = d_{yz} > d_{z^2}dxy​=dyz​>dz2​ C. dx2−y2>dz2>dxzd_{x^2-y^2} > d_{z^2} > d_{xz}dx2−y2​>dz2​>dxz​ D. dx2−y2=dz2<dxzd_{x^2-y^2} = d_{z^2} < d_{xz}dx2−y2​=dz2​<dxz​ Choose the correct answer from the given below:
  1. (A)A, B and D only
  2. (B)A and B only
  3. (C)B and D only
  4. (D)B, C and D only

Correct answer: (A)

Step-by-step solution →
Q38·ChemistrySingle correct
RfR_fRf​ value for 2-methylpropene in a solvent system (Ethyl acetate + ether) is 0.42. 2-methylpropene is treated with dilute H₂SO₄ to give major organic product (X). RfR_fRf​ value for (X) in the same solvent system under identical condition will be:
  1. (A)0.42
  2. (B)0.82
  3. (C)0.62
  4. (D)0.12

Correct answer: (D)

Step-by-step solution →
Q39·Chemistry·IsomerismSingle correct
Given below are two statements: Statement I: 2,6-diethylcyclohexanone and 6-methyl-2-n-propylcyclohexanone are metamers. Statement II: 2,2,6,6-tetramethylcyclohexanone exhibits keto-enol tautomerism. In the light of the above statements, choose the correct answer from the options given below
  1. (A)Both Statement I and Statement II are true
  2. (B)Both Statement I and Statement II are false
  3. (C)Statement I is true but Statement II is false
  4. (D)Statement I is false but Statement II is true

Correct answer: (C)

Step-by-step solution →
Q40·ChemistrySingle correct
Given below are two statements: Statement I: Methane can be prepared by decarboxylation of sodium ethanoate, Kolbe's electrolysis of sodium acetate and reaction of CH₃MgBr with water. Statement II: Methane cannot be prepared from unsaturated hydrocarbons and by Wurtz reaction. In the light of the above statements, choose the correct answer from the options given below
  1. (A)Both Statement I and Statement II are true
  2. (B)Both Statement I and Statement II are false
  3. (C)Statement I is true but Statement II is false
  4. (D)Statement I is false but Statement II is true

Correct answer: (D)

Step-by-step solution →
Q41·ChemistrySingle correct
Given below are two statements: Statement I: 3-phenylpropene reacts with HBr and gives secondary alkyl bromide having a chiral carbon atom as the major product. Statement II: Aryl chlorides and aryl cyanides can be prepared by Sandmeyer reaction as well as Gattermann reaction. In the light of the above statements, choose the correct answer from the options given below
  1. (A)Both Statement I and Statement II are true
  2. (B)Both Statement I and Statement II are false
  3. (C)Statement I is true but Statement II is false
  4. (D)Statement I is false but Statement II is true

Correct answer: (C)

Step-by-step solution →
Q42·ChemistrySingle correct
Consider the following sequence of reactions The major product P is:
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (C)

Step-by-step solution →
Q43·ChemistrySingle correct
Arrange the following compounds according to increasing order of boiling points. n-C₄H₉OH (A), n-C₄H₉NH₂ (B), n-C₄H₁₀ (C) and C₂H₅NHC₂H₅ (D).
  1. (A)C<B<A<DC < B < A < DC<B<A<D
  2. (B)D<C<B<AD < C < B < AD<C<B<A
  3. (C)C<D<B<AC < D < B < AC<D<B<A
  4. (D)D<B<A<CD < B < A < CD<B<A<C

Correct answer: (C)

Step-by-step solution →
Q44·ChemistrySingle correct
Match the LIST-I (Deficiency Disease) with LIST-II (Vitamin) Choose the correct answer from the options given below:
List-I (Deficiency Disease)List-II (Vitamin)
A.ScurvyI.Pyridoxine
B.ConvulsionsII.Vitamin A
C.CheilosisIII.Ascorbic Acid
D.XerophthalmiaIV.Riboflavin
  1. (A)A-I, B-III, C-II, D-IV
  2. (B)A-I, B-III, C-IV, D-II
  3. (C)A-III, B-I, C-IV, D-II
  4. (D)A-III, B-I, C-II, D-IV

Correct answer: (C)

Step-by-step solution →
Q45·ChemistrySingle correct
Match the LIST-I (Amino acid) with LIST-II (Positive reaction/Test for functional group present in side chain of amino acid) Choose the correct answer from the options given below:
List-I (Amino acid)List-II (Positive reaction/Test for functional group present in side chain of amino acid)
A.GlutamineI.Hinsberg's test
B.LysineII.Neutral FeCl₃ test
C.TyrosineIII.Ceric ammonium nitrate test
D.SerineIV.Hoffman bromamide degradation
  1. (A)A-IV, B-II, C-I, D-III
  2. (B)A-IV, B-I, C-II, D-III
  3. (C)A-III, B-II, C-I, D-IV
  4. (D)A-IV, B-I, C-III, D-II

Correct answer: (B)

Step-by-step solution →
Q46·ChemistryNumerical
First and second ionization enthalpies of lithium are 520 kJ mol⁻¹ and 7297 kJ mol⁻¹ respectively. Energy required to convert 3.5 mg lithium (g) into Li²⁺(g) [Li(g) → Li²⁺(g)] is _______ kJ mol⁻¹. (nearest integer) [Molar mass of Li = 7 g mol⁻¹]

Correct answer: 3909

Step-by-step solution →
Q47·ChemistryNumerical
Consider the following sequence of reactions. The percentage of nitrogen in the yellow product (X) formed is _______%. (Nearest Integer) (Given Molar mass in g mol⁻¹ H:1, C:12, N:14)

Correct answer: 21

Step-by-step solution →
Q48·ChemistryNumerical
4.7 g of phenol is heated with Zn to give product X. If this reaction goes to 60% completion then the number of moles of compound X formed will be _______ ×10⁻². (Nearest Integer) (Given molar mass in g mol⁻¹: H:1, C:12, O:16)

Correct answer: 3

Step-by-step solution →
Q49·ChemistryNumerical
Sucrose hydrolyses in acidic medium into glucose and fructose by first order rate law with t1/2=3t_{1/2} = 3t1/2​=3 hour. The percentage of sucrose remaining after 6 hours is _______. (Nearest integer) (Given: log 2 = 0.3010 and log 3 = 0.4771)

Correct answer: 25

Step-by-step solution →
Q50·ChemistryNumerical
Consider the reaction XXX ⇌ YYY at 300 K. If ΔH° and KKK are 28.40 kJ mol⁻¹ and 1.8 × 10⁻⁷ at the same temperature, then the magnitude of ΔS° for the reaction in J K⁻¹ mol⁻¹ is _______. (Nearest integer) (Given: R = 8.3 J K⁻¹ mol⁻¹, ln 10 = 2.3, log 3 = 0.48, log 2 = 0.30)

Correct answer: 34

Step-by-step solution →

Mathematics — JEE Main 6 April 2026 Shift 1

Q51·MathematicsSingle correct
Let [·] denote the greatest integer function. If the domain of the function f(x)=sin⁡−1(x+[x]3)f(x) = \sin^{-1}\left(\frac{x + [x]}{3}\right)f(x)=sin−1(3x+[x]​) is [α, β), then α2^22 + β2^22 is equal to:
  1. (A)2
  2. (B)5
  3. (C)10
  4. (D)13

Correct answer: (B)

Step-by-step solution →
Q52·MathematicsSingle correct
Let one root of the quadratic equation in x: (k2^22 − 15k + 27)x2^22 + 9(k − 1)x + 18 = 0 be twice the other. Then the length of the latus rectum of the parabola y2^22 = 6kx is equal to:
  1. (A)4
  2. (B)6
  3. (C)8
  4. (D)12

Correct answer: (D)

Step-by-step solution →
Q53·MathematicsSingle correct
Let e1_11​ and e2_22​ be two distinct roots of the equation x2^22 − ax + 2 = 0. Let the sets {a ∈ ℝ : e1_11​ and e2_22​ are the eccentricities of hyperbolas} = (α, β), and {a ∈ ℝ : e1_11​ and e2_22​ are the eccentricities of an ellipse and a hyperbola, respectively} = (γ, ∞). Then α2^22 + β2^22 + γ2^22 is equal to:
  1. (A)18
  2. (B)22
  3. (C)26
  4. (D)34

Correct answer: (C)

Step-by-step solution →
Q54·MathematicsSingle correct
Let the set of all values of k ∈ ℝ such that the equation z(zˉ+2+i)+k(2+3i)=0z(\bar{z} + 2 + i) + k(2 + 3i) = 0z(zˉ+2+i)+k(2+3i)=0, z ∈ ℂ, has at least one solution, be the interval [α, β]. Then 9(α + β) is equal to:
  1. (A)−10
  2. (B)−8
  3. (C)10√13
  4. (D)8√13

Correct answer: (A)

Step-by-step solution →
Q55·MathematicsSingle correct
The value of 13^33 − 23^33 + 33^33 − ... + 153^33 is:
  1. (A)1706
  2. (B)1856
  3. (C)1982
  4. (D)2403

Correct answer: (B)

Step-by-step solution →
Q56·MathematicsSingle correct
The sum of the first ten terms of an A.P. is 160 and the sum of the first two terms of a G.P. is 8. If the first term of the A.P. is equal to the common ratio of the G.P. and the first term of the G.P. is equal to common difference of the A.P., then the sum of all possible values of the first term of the G.P. is:
  1. (A)349\frac{34}{9}934​
  2. (B)3413\frac{34}{13}1334​
  3. (C)329\frac{32}{9}932​
  4. (D)3213\frac{32}{13}1332​

Correct answer: (A)

Step-by-step solution →
Q57·MathematicsSingle correct
The number of 4-letter words, with or without meaning, each consisting of two vowels and two consonants that can be formed from the letters of the word INCONSEQUENTIAL, without repeating any letter, is:
  1. (A)2670
  2. (B)2840
  3. (C)2920
  4. (D)3600

Correct answer: (D)

Step-by-step solution →
Q58·MathematicsSingle correct
If the coefficients of the middle terms in the binomial expansions of (1 + αx)26^{26}26 and (1 − αx)28^{28}28, α ≠ 0, are equal, then the value of α is:
  1. (A)1
  2. (B)1413\frac{14}{13}1314​
  3. (C)277\frac{27}{7}727​
  4. (D)727\frac{7}{27}277​

Correct answer: (D)

Step-by-step solution →
Q59·MathematicsSingle correct
A data consists of 20 observations x1_11​, x2_22​, ..., x20_{20}20​. If ∑i=120(xi+5)2=2500\sum_{i=1}^{20}(x_i + 5)^2 = 2500∑i=120​(xi​+5)2=2500 and ∑i=120(xi−5)2=100\sum_{i=1}^{20}(x_i - 5)^2 = 100∑i=120​(xi​−5)2=100, then the ratio of mean to standard deviation of this data is:
  1. (A)2 : 1
  2. (B)3 : 1
  3. (C)3 : 2
  4. (D)4 : 1

Correct answer: (B)

Step-by-step solution →
Q60·MathematicsSingle correct
A bag contains (N + 1) coins − N fair coins, and one coin with 'Head' on both sides. A coin is selected at random and tossed. If the probability of getting 'Head' is 916\frac{9}{16}169​, then N is equal to:
  1. (A)5
  2. (B)7
  3. (C)8
  4. (D)9

Correct answer: (B)

Step-by-step solution →
Q61·MathematicsSingle correct
If the eccentricity e of the hyperbola x2a2−y2b2=1\frac{x^2}{a^2} - \frac{y^2}{b^2} = 1a2x2​−b2y2​=1, passing through (6, 4√3), satisfies 15(e2^22 + 1) = 34e, then the length of the latus rectum of the hyperbola x2b2−y22(a2+1)=1\frac{x^2}{b^2} - \frac{y^2}{2(a^2 + 1)} = 1b2x2​−2(a2+1)y2​=1 is:
  1. (A)10
  2. (B)20
  3. (C)25
  4. (D)30

Correct answer: (A)

Step-by-step solution →
Q62·MathematicsSingle correct
Let chord PQ of length 3√13 of the parabola y2^22 = 12x be such that the ordinates of points P and Q are in the ratio 1 : 2. If the chord PQ subtends an angle α at the focus of the parabola, then sin α is equal to:
  1. (A)35\frac{3}{5}53​
  2. (B)45\frac{4}{5}54​
  3. (C)513\frac{5}{13}135​
  4. (D)1213\frac{12}{13}1312​

Correct answer: (A)

Step-by-step solution →
Q63·MathematicsSingle correct
Let 0 < α < 1, β=13α\beta = \frac{1}{3\alpha}β=3α1​ and tan−1^{-1}−1(1 − α) + tan−1^{-1}−1(1 − β) = π4\frac{\pi}{4}4π​. Then 6(α + β) is equal to:
  1. (A)6
  2. (B)7
  3. (C)8
  4. (D)9

Correct answer: (B)

Step-by-step solution →
Q64·MathematicsSingle correct
Let S = {θ ∈ (−2π, 2π) : cos θ + 1 = 3\sqrt{3}3​ sin θ}. Then ∑θ∈Sθ\sum_{\theta \in S} \theta∑θ∈S​θ is equal to:
  1. (A)−2π3-\frac{2\pi}{3}−32π​
  2. (B)−4π3-\frac{4\pi}{3}−34π​
  3. (C)2π3\frac{2\pi}{3}32π​
  4. (D)4π3\frac{4\pi}{3}34π​

Correct answer: (B)

Step-by-step solution →
Q65·MathematicsSingle correct
Let the image of the point P(1, 6, a) in the line L : x1=y−12=z−a+1b\frac{x}{1} = \frac{y-1}{2} = \frac{z-a+1}{b}1x​=2y−1​=bz−a+1​, b > 0, be (a3,0,a+c)\left(\frac{a}{3}, 0, a+c\right)(3a​,0,a+c). If S(α, β, γ), α > 0, is the point on L such that the distance of S from the foot of perpendicular from the point P on L is 2142\sqrt{14}214​, then α + β + γ is equal to:
  1. (A)19
  2. (B)20
  3. (C)21
  4. (D)22

Correct answer: (C)

Step-by-step solution →
Q66·MathematicsSingle correct
Let a line L be perpendicular to both the lines L1_11​ : x+13=y+35=z+57\frac{x+1}{3} = \frac{y+3}{5} = \frac{z+5}{7}3x+1​=5y+3​=7z+5​ and L2_22​ : x−21=y−44=z−67\frac{x-2}{1} = \frac{y-4}{4} = \frac{z-6}{7}1x−2​=4y−4​=7z−6​. If θ is the acute angle between the lines L and L3_33​ : x−872=y−471=z2\frac{x-\frac{8}{7}}{2} = \frac{y-\frac{4}{7}}{1} = \frac{z}{2}2x−78​​=1y−74​​=2z​, then tan θ is equal to:
  1. (A)322\frac{3}{2}\sqrt{2}23​2​
  2. (B)522\frac{5}{2}\sqrt{2}25​2​
  3. (C)532\frac{5}{3}\sqrt{2}35​2​
  4. (D)432\frac{4}{3}\sqrt{2}34​2​

Correct answer: (B)

Step-by-step solution →
Q67·MathematicsSingle correct
The value of lim⁡x→0(x2sin⁡2xx2−sin⁡2x)\lim_{x \to 0}\left(\frac{x^2 \sin^2 x}{x^2 - \sin^2 x}\right)limx→0​(x2−sin2xx2sin2x​) is:
  1. (A)2
  2. (B)3
  3. (C)4
  4. (D)6

Correct answer: (B)

Step-by-step solution →
Q68·MathematicsSingle correct
The value of the integral ∫−π/4π/4(32cos⁡4x1+esin⁡x)dx\int_{-\pi/4}^{\pi/4}\left(\frac{32\cos^4 x}{1+e^{\sin x}}\right)dx∫−π/4π/4​(1+esinx32cos4x​)dx is:
  1. (A)4π + 2
  2. (B)3π + 8
  3. (C)3π + 4
  4. (D)4π + 3

Correct answer: (B)

Step-by-step solution →
Q69·MathematicsSingle correct
The area of the region {(x, y) : 0 ≤ y ≤ 6 − x, y2^22 ≥ 4x − 3, x ≥ 0} is:
  1. (A)8
  2. (B)9
  3. (C)12
  4. (D)15

Correct answer: (B)

Step-by-step solution →
Q70·MathematicsSingle correct
Let e be the base of natural logarithm and let f : {1, 2, 3, 4} → {1, e, e2^22, e3^33} and g : {1, e, e2^22, e3^33} → {1,12,13,14}\left\{1, \frac{1}{2}, \frac{1}{3}, \frac{1}{4}\right\}{1,21​,31​,41​} be two bijective functions such that f is strictly decreasing and g is strictly increasing. If ϕ(x)=[f−1{g−1(12)}]x\phi(x) = \left[f^{-1}\left\{g^{-1}\left(\frac{1}{2}\right)\right\}\right]^{x}ϕ(x)=[f−1{g−1(21​)}]x, then the area of the region R = {(x, y) : x2^22 ≤ y ≤ φ(x), 0 ≤ x ≤ 1} is:
  1. (A)3−log⁡e(2)3log⁡e(2)\frac{3 - \log_e(2)}{3\log_e(2)}3loge​(2)3−loge​(2)​
  2. (B)13log⁡e(2)\frac{1}{3\log_e(2)}3loge​(2)1​
  3. (C)3 + loge_ee​(2)
  4. (D)3+log⁡e(2)2+log⁡e(3)\frac{3 + \log_e(2)}{2 + \log_e(3)}2+loge​(3)3+loge​(2)​

Correct answer: (A)

Step-by-step solution →
Q71·MathematicsNumerical
Let A = [−11−1101001]\begin{bmatrix} -1 & 1 & -1 \\ 1 & 0 & 1 \\ 0 & 0 & 1 \end{bmatrix}​−110​100​−111​​ satisfy A2^22 + α(adj(adj(A))) + β(adj(A)(adj(adj(A)))) = [2−22−20−100−1]\begin{bmatrix} 2 & -2 & 2 \\ -2 & 0 & -1 \\ 0 & 0 & -1 \end{bmatrix}​2−20​−200​2−1−1​​ for some α, β ∈ ℝ. Then (α − β)2^22 is equal to ______

Correct answer: 4

Step-by-step solution →
Q72·MathematicsNumerical
Let the centre of the circle x2^22 + y2^22 + 2gx + 2fy + 25 = 0 be in the first quadrant and lie on the line 2x − y = 4. Let the area of an equilateral triangle inscribed in the circle be 27327\sqrt{3}273​. Then the square of the length of the chord of the circle on the line x = 1 is ______.

Correct answer: 80

Step-by-step solution →
Q73·MathematicsNumerical
If a⃗=i^+j^+k^\vec{a} = \hat{i} + \hat{j} + \hat{k}a=i^+j^​+k^, b⃗=j^−k^\vec{b} = \hat{j} - \hat{k}b=j^​−k^ and c⃗\vec{c}c be three vectors such that a⃗×c⃗=b⃗\vec{a} \times \vec{c} = \vec{b}a×c=b and a⃗⋅c⃗=3\vec{a} \cdot \vec{c} = 3a⋅c=3, then c⃗⋅(a⃗−2b⃗)\vec{c} \cdot (\vec{a} - 2\vec{b})c⋅(a−2b) is equal to ______.

Correct answer: 3

Step-by-step solution →
Q74·MathematicsNumerical
For the functions f(θ) = α tan2^22 θ + β cot2^22 θ, and g(θ) = α sin2^22 θ + β cos2^22 θ, α > β > 0, let min⁡0<θ<π/2f(θ)=max⁡0<θ<πg(θ)\min_{0<\theta<\pi/2} f(\theta) = \max_{0<\theta<\pi} g(\theta)min0<θ<π/2​f(θ)=max0<θ<π​g(θ). If the first term of a G.P. is (α2β)\left(\frac{\alpha}{2\beta}\right)(2βα​), its common ratio is (2βα)\left(\frac{2\beta}{\alpha}\right)(α2β​) and the sum of its first 10 terms is mn\frac{m}{n}nm​, gcd(m, n) = 1, then m + n is equal to ______.

Correct answer: 1279

Step-by-step solution →
Q75·MathematicsNumerical
Let y = y(x) be the solution of the differential equation (x2−xx2−1)dy+(y(x−x2−1)−x)dx=0(x^2 - x\sqrt{x^2-1})dy + (y(x - \sqrt{x^2-1}) - x)dx = 0(x2−xx2−1​)dy+(y(x−x2−1​)−x)dx=0, x ≥ 1. If y(1) = 1, then the greatest integer less than y(5)y(\sqrt{5})y(5​) is ______.

Correct answer: 3

Step-by-step solution →

Chapters tested in this paper

Open any chapter to practise every past-year question on that topic across all papers, and see how often it has actually appeared.

  • Properties of Solids and Liquids 172/186
  • Three Dimensional Geometry 176/186
  • Matrices and Determinants 180/186
  • Coordination Compounds 176/186
  • Sets, Relations and Functions 165/186
  • Current Electricity 160/186
  • Sequence and Series 164/186
  • p-Block Elements 164/186
  • Definite Integration 168/186
  • Rotational Motion 172/186
  • Redox Reactions and Electrochemistry 177/186
  • Geometrical Optics 172/186
  • Vector Algebra 173/186
  • Differential Equations 167/186
  • Probability 176/186
  • Permutations and Combinations 162/186
  • Magnetic Field of Current 147/186
  • Binomial Theorem and Its Simple Applications 158/186
  • Electromagnetic Waves 144/186
  • Chemical Bonding and Molecular Structure 151/186
  • Limits and Continuity 149/186
  • d- and f-Block Elements 126/186
  • Thermodynamics 154/186
  • Equilibrium 163/186
  • Solutions 158/186
  • Laws of Motion 130/186
  • Chemical Thermodynamics 165/186
  • Units and Measurements 149/186
  • Hydrocarbons 126/186
  • Complex Numbers 165/186
  • Trigonometric Functions 144/186
  • Biomolecules 162/186
  • Chemical Kinetics 169/186
  • Electric Field and Coulomb's Law 133/186
  • Atomic Structure 161/186
  • Electronic Devices 145/186
  • Circles 142/186
  • Amines 133/186
  • Quadratic Equations 148/186
  • Work, Energy and Power 132/186
  • Some Basic Concepts in Chemistry 129/186
  • Electromagnetic Induction 120/186
  • Wave Optics 130/186
  • Area Under Curves 139/186
  • Kinetic Theory of Gases 135/186
  • Alcohols and Ethers 106/186
  • Purification and Characterisation of Organic Compounds 116/186
  • Oscillations 117/186
  • Alternating Currents 108/186
  • Nuclei 116/186
  • Organic Compounds Containing Halogens 109/186
  • Atoms 112/186
  • Classification of Elements and Periodicity in Properties 113/186
  • Parabola 101/186
  • Statistics 118/186
  • Inverse Trigonometric Functions 93/186
  • Hyperbola 77/186
  • Electric Potential 63/186
  • Diazonium Salts and Reactions 53/186
  • Isomerism 51/186
← 5 Apr Shift 2 2026All papers6 Apr Shift 2 2026 →

Attempt this paper under exam timing.

Take the 6 April 2026 Shift 1 paper as a timed mock and Jarvis marks it, then tells you which errors were conceptual gaps, which were silly mistakes, and which pattern you have now repeated. Step-by-step solutions for every question included.

Attempt this paper freeSee pricing

Free plan, no time limit · No credit card needed

Jarvis OS

AI-powered JEE preparation.

Question papers

JEE Main PYQsJEE Advanced PYQsPhysics PYQsChemistry PYQsMaths PYQs

Product

TourPricingSign inCreate account

Legal

Privacy PolicyTerms of ServiceRefund & CancellationShipping & DeliveryContact Us

Operated by

Venyou Craft Private Limited

info@jarvisos.net

© 2026 Jarvis OS