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JEE Main 25 July 2022 Shift 1 Question Paper with Answers

25 July 2022 · July session · 88 questions

88 of the 90 questions from the JEE Main 25 July 2022 Shift 1 paper, each with its correct answer and tagged to the chapter it tests. Free to read, no account needed.

2 questions are held back from this paper while we re-check the transcription or the answer key. We would rather show you nothing than show you an answer we are not confident is right.

Physics
30
Chemistry
29
Mathematics
29

Physics — JEE Main 25 July 2022 Shift 1

Q1·PhysicsSingle correct
If momentum [P], area [A] and time [T] are taken as fundamental quantities, then the dimensional formula for coefficient of viscosity is :
  1. (A)[P A−1 T0][P\ A^{-1}\ T^{0}][P A−1 T0]
  2. (B)[P A T−1][P\ A\ T^{-1}][P A T−1]
  3. (C)[P A−1 T][P\ A^{-1}\ T][P A−1 T]
  4. (D)[P A−1 T−1][P\ A^{-1}\ T^{-1}][P A−1 T−1]

Correct answer: (A)

Step-by-step solution →
Q2·PhysicsSingle correct
Which of the following physical quantities have the same dimensions ?
  1. (A)Electric displacement (D⃗)(\vec{D})(D) and surface charge density
  2. (B)Displacement current and electric field
  3. (C)Current density and surface charge density
  4. (D)Electric potential and energy

Correct answer: (A)

Step-by-step solution →
Q3·PhysicsSingle correct
A person moved from A to B on a circular path as shown in figure. If the distance travelled by him is 60 m, then the magnitude of displacement would be : (Given cos⁡135∘=− 0.7\cos 135^\circ = -\,0.7cos135∘=−0.7)
  1. (A)42 m
  2. (B)47 m
  3. (C)19 m
  4. (D)40 m

Correct answer: (B)

Step-by-step solution →
Q4·PhysicsSingle correct
A body of mass 0.5 kg travels on straight line path with velocity v=(3x2+4)v = (3x^{2} + 4)v=(3x2+4) m/s. The net workdone by the force during its displacement from x=0x = 0x=0 to x=2x = 2x=2 m is :
  1. (A)64 J
  2. (B)60 J
  3. (C)120 J
  4. (D)128 J

Correct answer: (B)

Step-by-step solution →
Q5·PhysicsSingle correct
A solid cylinder and a solid sphere, having same mass M and radius R, roll down the same inclined plane from top without slipping. They start from rest. The ratio of velocity of the solid cylinder to that of the solid sphere, with which they reach the ground, will be :
  1. (A)53\sqrt{\frac{5}{3}}35​​
  2. (B)45\sqrt{\frac{4}{5}}54​​
  3. (C)35\sqrt{\frac{3}{5}}53​​
  4. (D)1415\sqrt{\frac{14}{15}}1514​​

Correct answer: (D)

Step-by-step solution →
Q6·PhysicsSingle correct
Three identical particle A, B and C of mass 100 kg each are placed in a straight line with AB = BC = 13 m. The gravitational force on a fourth particle P of the same mass is F, when placed at a distance 13 m from the particle B on the perpendicular bisector of the line AC. The value of F will be approximately :
  1. (A)21 G
  2. (B)100 G
  3. (C)59 G
  4. (D)42 G

Correct answer: (B)

Step-by-step solution →
Q7·PhysicsSingle correct
A certain amount of gas of volume V at 27∘27^\circ27∘C temperature and pressure 2×1072 \times 10^{7}2×107 Nm−2^{-2}−2 expands isothermally until its volume gets doubled. Later it expands adiabatically until its volume gets redoubled. The final pressure of the gas will be (Use γ=1.5\gamma = 1.5γ=1.5)
  1. (A)3.536×1053.536 \times 10^{5}3.536×105 Pa
  2. (B)3.536×1063.536 \times 10^{6}3.536×106 Pa
  3. (C)1.25×1061.25 \times 10^{6}1.25×106 Pa
  4. (D)1.25×1051.25 \times 10^{5}1.25×105 Pa

Correct answer: (B)

Step-by-step solution →
Q8·PhysicsSingle correct
Following statements are given : (1) The average kinetic energy of a gas molecule decreases when the temperature is reduced. (2) The average kinetic energy of a gas molecule increases with increase in pressure at constant temperature. (3) The average kinetic energy of a gas molecule decreases with increases in volume. (4) Pressure of a gas increases with increase in temperature at constant pressure. (5) The volume of gas decreases with increase in temperature. Choose the correct answer from the options given below :
  1. (A)(1) and (4) only
  2. (B)(1), (2) and (4) only
  3. (C)(2) and (4) only
  4. (D)(1), (2) and (5) only

Correct answer: (A)

Step-by-step solution →
Q9·PhysicsSingle correct
In figure (A), mass '2 m' is fixed on mass 'm' which is attached to two springs of spring constant k. In figure (B), mass 'm' is attached to two spring of spring constant 'k' and '2k'. If mass 'm' in (A) and (B) are displaced by distance 'x' horizontally and then released, then time period T1T_1T1​ and T2T_2T2​ corresponding to (A) and (B) respectively follow the relation.
  1. (A)T1T2=32\frac{T_1}{T_2} = \frac{3}{\sqrt{2}}T2​T1​​=2​3​
  2. (B)T1T2=32\frac{T_1}{T_2} = \sqrt{\frac{3}{2}}T2​T1​​=23​​
  3. (C)T1T2=23\frac{T_1}{T_2} = \sqrt{\frac{2}{3}}T2​T1​​=32​​
  4. (D)T1T2=23\frac{T_1}{T_2} = \frac{\sqrt{2}}{3}T2​T1​​=32​​

Correct answer: (A)

Step-by-step solution →
Q10·PhysicsSingle correct
A condenser of 2 μ\muμF capacitance is charged steadily from 0 to 5C. Which of the following graph represents correctly the variation of potential difference (V) across it's plates with respect to the charge (Q) on the condenser ?
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (A)

Step-by-step solution →
Q11·Physics·Magnetic Field of CurrentSingle correct
Two charged particles, having same kinetic energy, are allowed to pass through a uniform magnetic field perpendicular to the direction of motion. If the ratio of radii of their circular paths is 6 : 5 and their respective masses ratio is 9 : 4. Then, the ratio of their charges will be :
  1. (A)8 : 5
  2. (B)5 : 4
  3. (C)5 : 3
  4. (D)8 : 7

Correct answer: (B)

Step-by-step solution →
Q12·PhysicsSingle correct
To increase the resonant frequency in series LCR circuit,
  1. (A)Source frequency should be increased
  2. (B)Another resistance should be added in series with the first resistance.
  3. (C)Another capacitor should be added in series with the first capacitor
  4. (D)The source frequency should be decreased

Correct answer: (C)

Step-by-step solution →
Q13·PhysicsSingle correct
A small square loop of wire of side lll is placed inside a large square loop of wire L (L >> lll). Both loops are coplanar and their centres coincide at point O as shown in figure. The mutual inductance of the system is :
  1. (A)22μ0L2πℓ\frac{2\sqrt{2}\mu_0 L^{2}}{\pi \ell}πℓ22​μ0​L2​
  2. (B)μ0ℓ222πL\frac{\mu_0 \ell^{2}}{2\sqrt{2}\pi L}22​πLμ0​ℓ2​
  3. (C)22μ0ℓ2πL\frac{2\sqrt{2}\mu_0 \ell^{2}}{\pi L}πL22​μ0​ℓ2​
  4. (D)μ0L222πℓ\frac{\mu_0 L^{2}}{2\sqrt{2}\pi \ell}22​πℓμ0​L2​

Correct answer: (C)

Step-by-step solution →
Q14·PhysicsSingle correct
The rms value of conduction current in a parallel plate capacitor is 6.9 μ\muμA. The capacity of this capacitor, if it is connected to 230 V ac supply with an angular frequency of 600 rad/s, will be :
  1. (A)5 pF
  2. (B)50 pF
  3. (C)100 pF
  4. (D)200 pF

Correct answer: (B)

Step-by-step solution →
Q15·PhysicsSingle correct
Which of the following statement is correct ?
  1. (A)In primary rainbow, observer sees red colour on the top and violet on the bottom
  2. (B)In primary rainbow, observer sees violet colour on the top and red on the bottom
  3. (C)In primary rainbow, light wave suffers total internal reflection twice before coming out of water drops
  4. (D)Primary rainbow is less bright than secondary rainbow.

Correct answer: (A)

Step-by-step solution →
Q16·PhysicsSingle correct
Time taken by light to travel in two different materials A and B of refractive indices μA\mu_AμA​ and μB\mu_BμB​ of same thickness is t1t_1t1​ and t2t_2t2​ respectively. If t2−t1=5×10−10t_2 - t_1 = 5 \times 10^{-10}t2​−t1​=5×10−10 s and the ratio of μA\mu_AμA​ to μB\mu_BμB​ is 1 : 2. Then the thickness of material, in meter is : (Given vAv_AvA​ and vBv_BvB​ are velocities of light in A and B materials respectively).
  1. (A)5×10−10va5 \times 10^{-10} v_a5×10−10va​ m
  2. (B)5×10−105 \times 10^{-10}5×10−10 m
  3. (C)1.5×10−101.5 \times 10^{-10}1.5×10−10 m
  4. (D)5×10−10vB5 \times 10^{-10} v_B5×10−10vB​ m

Correct answer: (A)

Step-by-step solution →
Q17·PhysicsSingle correct
A metal exposed to light of wavelength 800 nm and emits photoelectrons with a certain kinetic energy. The maximum kinetic energy of photo-electron doubles when light of wavelength 500 nm is used. The work function of the metal is (Take hc = 1230 eV-nm).
  1. (A)1.537 eV
  2. (B)2.46 eV
  3. (C)0.615 eV
  4. (D)1.23 eV

Correct answer: (C)

Step-by-step solution →
Q18·PhysicsSingle correct
The momentum of an electron revolving in nthn^{th}nth orbit is given by : (Symbols have their usual meanings)
  1. (A)nh2πr\frac{nh}{2\pi r}2πrnh​
  2. (B)nh2r\frac{nh}{2r}2rnh​
  3. (C)nh2π\frac{nh}{2\pi}2πnh​
  4. (D)2πrnh\frac{2\pi r}{nh}nh2πr​

Correct answer: (A)

Step-by-step solution →
Q19·Physics·Magnetism and MatterSingle correct
The magnetic moment of an electron (e) revolving in an orbit around nucleus with an orbital angular momentum is given by :
  1. (A)μ⃗L=eL⃗2m\vec{\mu}_L = \frac{e\vec{L}}{2m}μ​L​=2meL​
  2. (B)μ⃗L=−eL⃗2m\vec{\mu}_L = -\frac{e\vec{L}}{2m}μ​L​=−2meL​
  3. (C)μ⃗l=−eL⃗m\vec{\mu}_l = -\frac{e\vec{L}}{m}μ​l​=−meL​
  4. (D)μ⃗l=2eL⃗m\vec{\mu}_l = \frac{2e\vec{L}}{m}μ​l​=m2eL​

Correct answer: (B)

Step-by-step solution →
Q20·PhysicsSingle correct
In the circuit, the logical value of A = 1 or B = 1 when potential at A or B is 5V and the logical value of A = 0 or B = 0 when potential at A or B is 0 V. The truth table of the given circuit will be :
  1. (A)A B Y 0 0 0 1 0 0 0 1 0 1 1 1
  2. (B)A B Y 0 0 0 1 0 1 0 1 1 1 1 1
  3. (C)A B Y 0 0 0 1 0 0 0 1 0 1 1 0
  4. (D)A B Y 0 0 1 1 0 1 0 1 1 1 1 0

Correct answer: (A)

Step-by-step solution →
Q21·PhysicsNumerical
A car is moving with speed of 150 km/h and after applying the brake it will move 27 m before it stops. If the same car is moving with a speed of one third the reported speed then it will stop after travelling _______ m distance.

Correct answer: 3

Step-by-step solution →
Q22·PhysicsNumerical
Four forces are acting at a point P in equilibrium as shown in figure. The ratio of force F1F_1F1​ to F2F_2F2​ is 1 : x where x = _______ .

Correct answer: 3

Step-by-step solution →
Q23·PhysicsNumerical
A wire of length L and radius r is clamped rigidly at one end. When the other end of the wire is pulled by a force F, its length increases by 5 cm. Another wire of the same material of length 4L and radius 4r is pulled by a force 4F under same conditions. The increase in length of this wire is _______ cm.

Correct answer: 5

Step-by-step solution →
Q24·PhysicsNumerical
A unit scale is to be prepared whose length does not change with temperature and remains 20 cm, using a bimetallic strip made of brass and iron each of different length. The length of both components would change in such a way that difference between their lengths remains constant. If length of brass is 40 cm and length of iron will be _______ cm. (αiron=1.2×10−5\alpha_{iron} = 1.2 \times 10^{-5}αiron​=1.2×10−5 K−1K^{-1}K−1 and αbrass=1.8×10−5\alpha_{brass} = 1.8 \times 10^{-5}αbrass​=1.8×10−5 K−1K^{-1}K−1).

Correct answer: 60

Step-by-step solution →
Q25·PhysicsNumerical
An observer is riding on a bicycle and moving towards a hill at 18 kmh−1kmh^{-1}kmh−1. He hears a sound from a source at some distance behind him directly as well as after its reflection from the hill. If the original frequency of the sound as emitted by source is 640 Hz and velocity of the sound in air is 320 m/s, the beat frequency between the two sounds heard by observer will be _______ Hz.

Correct answer: 20

Step-by-step solution →
Q26·PhysicsNumerical
The volume charge density of a sphere of radius 6 m is 2 μC\mu CμC cm−3cm^{-3}cm−3. The number of lines of force per unit surface area coming out from the surface of the sphere is _______ ×1010\times 10^{10}×1010 NC−1NC^{-1}NC−1. [Given : Permittivity of vacuum ∈0=8.85×10−12\in_0 = 8.85 \times 10^{-12}∈0​=8.85×10−12 C2C^2C2 N−1−m−2N^{-1} - m^{-2}N−1−m−2 ]

Correct answer: 45

Step-by-step solution →
Q27·PhysicsNumerical
In the given figure, the value of V0V_0V0​ will be _______ V.

Correct answer: 4

Step-by-step solution →
Q28·PhysicsNumerical
Eight copper wire of length lll and diameter d are joined in parallel to form a single composite conductor of resistance R. If a single copper wire of length 2l2l2l have the same resistance (R) then its diameter will be _______ d.

Correct answer: 4

Step-by-step solution →
Q29·PhysicsNumerical
The energy band gap of semiconducting material to produce violet (wavelength = 4000 Å) LED is _______ eV. (Round off to the nearest integer).

Correct answer: 3

Step-by-step solution →
Q30·PhysicsNumerical
The required height of a TV tower which can cover the population of 6.03 lakh is h. If the average population density is 100 per square km and the radius of earth is 6400 km, then the value of h will be _______ m.

Correct answer: 150

Step-by-step solution →

Chemistry — JEE Main 25 July 2022 Shift 1

Q31·ChemistrySingle correct
SO2Cl2SO_{2}Cl_{2}SO2​Cl2​ on reaction with excess of water results into acidic mixture SO2Cl2+2H2O→H2SO4+2HClSO_{2}Cl_{2} + 2H_{2}O \rightarrow H_{2}SO_{4} + 2HClSO2​Cl2​+2H2​O→H2​SO4​+2HCl 16 moles of NaOH is required for the complete neutralisation of the resultant acidic mixture. The number of moles of SO2Cl2SO_{2}Cl_{2}SO2​Cl2​ used is :
  1. (A)16
  2. (B)8
  3. (C)4
  4. (D)2

Correct answer: (C)

Step-by-step solution →
Q32·ChemistrySingle correct
Which of the following sets of quantum numbers is not allowed ?
  1. (A)n=3,l=2,ml=0,s=+12n = 3, l = 2, m_{l} = 0, s = +\frac{1}{2}n=3,l=2,ml​=0,s=+21​
  2. (B)n=3,l=2,ml=−2,s=+12n = 3, l = 2, m_{l} = -2, s = +\frac{1}{2}n=3,l=2,ml​=−2,s=+21​
  3. (C)n=3,l=3,ml=−3,s=−12n = 3, l = 3, m_{l} = -3, s = -\frac{1}{2}n=3,l=3,ml​=−3,s=−21​
  4. (D)n=3,l=0,ml=0,s=−12n = 3, l = 0, m_{l} = 0, s = -\frac{1}{2}n=3,l=0,ml​=0,s=−21​

Correct answer: (C)

Step-by-step solution →
Q33·ChemistrySingle correct
The depression in freezing point observed for a formic acid solution of concentration 0.5 mL L−1L^{-1}L−1 is 0.0405°C. Density of formic acid is 1.05 g mL−1mL^{-1}mL−1. The Van't Hoff factor of the formic acid solution is nearly : (Given for water kfk_{f}kf​= 1.86 K kg mol−1mol^{-1}mol−1)
  1. (A)0.8
  2. (B)1.1
  3. (C)1.9
  4. (D)2.4

Correct answer: (C)

Step-by-step solution →
Q34·ChemistrySingle correct
20 mL of 0.1 M NH4OHNH_{4}OHNH4​OH is mixed with 40 mL of 0.05 M HCl. The pH of the mixture is nearest to: (Given: Kb(NH4OH)=1×10−5K_{b}(NH_{4}OH) = 1 \times 10^{-5}Kb​(NH4​OH)=1×10−5, log 2 = 0.30, log 3 = 0.48, log 5 = 0.69, log 7 = 0.84, log 11 =1.04)
  1. (A)3.2
  2. (B)4.2
  3. (C)5.2
  4. (D)6.2

Correct answer: (C)

Step-by-step solution →
Q35·ChemistrySingle correct
Match List - I with List - II Choose the correct answer from the options given below :
List - IList - II
A.N2(g)+3H2(g)→2NH3(g)N_{2}(g) + 3H_{2}(g) \rightarrow 2NH_{3}(g)N2​(g)+3H2​(g)→2NH3​(g)I.Cu
B.CO(g)+3H2(g)→CH4(g)+H2O(g)CO(g) + 3H_{2}(g) \rightarrow CH_{4}(g) + H_{2}O(g)CO(g)+3H2​(g)→CH4​(g)+H2​O(g)II.Cu/ZnO−Cr2O3Cu/ZnO - Cr_{2}O_{3}Cu/ZnO−Cr2​O3​
C.CO(g)+H2(g)→HCHO(g)CO(g) + H_{2}(g) \rightarrow HCHO(g)CO(g)+H2​(g)→HCHO(g)III.FexOy+K2O+Al2O3Fe_{x}O_{y} + K_{2}O + Al_{2}O_{3}Fex​Oy​+K2​O+Al2​O3​
D.CO(g)+2H2(g)→CH3OH(g)CO(g) + 2H_{2}(g) \rightarrow CH_{3}OH(g)CO(g)+2H2​(g)→CH3​OH(g)IV.Ni
  1. (A)(A) - (II), (B) - (IV), (C) - (I), (D) - (III)
  2. (B)(A) - (II), (B) - (I), (C) - (IV), (D) - (III)
  3. (C)(A) - (III), (B) - (IV), (C) - (I), (D) - (II)
  4. (D)(A) - (III), (B) - (I), (C) - (IV), (D) - (II)

Correct answer: (C)

Step-by-step solution →
Q36·ChemistrySingle correct
The IUPAC nomenclature of an element with electronic configuration [Rn]5f146d17s2[Rn]5f^{14}6d^{1}7s^{2}[Rn]5f146d17s2 is :
  1. (A)Unnilbium
  2. (B)Unnilunium
  3. (C)Unnilquadium
  4. (D)Unniltrium

Correct answer: (D)

Step-by-step solution →
Q37·ChemistrySingle correct
The compound(s) that is(are) removed as slag during the extraction of copper is : (1) CaO (2) FeO (3) Al2O3Al_{2}O_{3}Al2​O3​ (4) ZnO (5) NiO Choose the correct answer from the options given below :
  1. (A)(3) (4) Only
  2. (B)(1), (2), (5) Only
  3. (C)(1), (2) Only
  4. (D)(2) Only

Correct answer: (D)

Step-by-step solution →
Q38·ChemistrySingle correct
The reaction of H2O2H_{2}O_{2}H2​O2​ with potassium permanganate in acidic medium leads to the formation of mainly:
  1. (A)Mn2+Mn^{2+}Mn2+
  2. (B)Mn4+Mn^{4+}Mn4+
  3. (C)Mn3+Mn^{3+}Mn3+
  4. (D)Mn6+Mn^{6+}Mn6+

Correct answer: (A)

Step-by-step solution →
Q39·ChemistrySingle correct
Choose the correct order of density of the alkali metals :
  1. (A)Li < K < Na < Rb < Cs
  2. (B)Li < Na < K < Rb < Cs
  3. (C)Cs < Rb < K < Na < Li
  4. (D)Li < Na < K < Cs < Rb

Correct answer: (A)

Step-by-step solution →
Q40·ChemistrySingle correct
The geometry around boron in the product 'B' formed from the following reaction is BF3+NaH→450KA+NaFBF_{3} + NaH \xrightarrow{450K} A + NaFBF3​+NaH450K​A+NaF A+NMe3→BA + NMe_{3} \rightarrow BA+NMe3​→B
  1. (A)trigonal planar
  2. (B)tetrahedral
  3. (C)pyramidal
  4. (D)square planar

Correct answer: (B)

Step-by-step solution →
Q41·ChemistrySingle correct
The interhalogen compound formed from the reaction of bromine with excess of fluorine is a :
  1. (A)hypohalite
  2. (B)halate
  3. (C)perhalate
  4. (D)halite

Correct answer: (B)

Step-by-step solution →
Q42·ChemistrySingle correct
The photochemical smog does not generally contain :
  1. (A)NO
  2. (B)NO2NO_{2}NO2​
  3. (C)SO2SO_{2}SO2​
  4. (D)HCHO

Correct answer: (C)

Step-by-step solution →
Q43·ChemistrySingle correct
A compound 'A' on reaction with 'X' and 'Y' produces the same major product but different by product 'a' and 'b'. Oxidation of 'a’ gives a substance produced by ants. ‘X’ and ‘Y’ respectively are :
  1. (A)KMnO4/H+KMnO_{4}/H^{+}KMnO4​/H+ and dil. KMnO4KMnO_{4}KMnO4​, 273 K
  2. (B)KMnO4KMnO_{4}KMnO4​,(dilute), 273 K and KMnO4/H+KMnO_{4}/H^{+}KMnO4​/H+
  3. (C)KMnO4/H+KMnO_{4}/H^{+}KMnO4​/H+ and O3O_{3}O3​, H2O/ZnH_{2}O/ZnH2​O/Zn
  4. (D)O3O_{3}O3​, H2O/ZnH_{2}O/ZnH2​O/Zn and KMnO4/H+KMnO_{4}/H^{+}KMnO4​/H+

Correct answer: (D)

Step-by-step solution →
Q44·ChemistrySingle correct
Most stable product of the following reaction is:
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (B)

Step-by-step solution →
Q45·ChemistrySingle correct
Which one of the following reactions does not represent correct combination of substrate and product under the given conditions ?
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (D)

Step-by-step solution →
Q46·ChemistrySingle correct
An organic compound 'A' on reaction with NH3NH_{3}NH3​ followed by heating gives compound B. Which on further strong heating gives compound C (C8H5NO2C_{8}H_{5}NO_{2}C8​H5​NO2​). Compound C on sequential reaction with ethanolic KOH, alkyl chloride and hydrolysis with alkali gives a primary amine. The compound A is :
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (C)

Step-by-step solution →
Q47·ChemistrySingle correct
Melamine polymer is formed by the condensation of :
  1. (A)(A)
  2. (B)(B)
  3. (C)(C)
  4. (D)(D)

Correct answer: (A)

Step-by-step solution →
Q48·ChemistrySingle correct
During the denaturation of proteins, which of these structures will remain intact ?
  1. (A)Primary
  2. (B)Secondary
  3. (C)Tertiary
  4. (D)Quaternary

Correct answer: (A)

Step-by-step solution →
Q49·ChemistrySingle correct
Drugs used to bind to receptors, inhibiting its natural function and blocking a message are called :
  1. (A)Agonists
  2. (B)Antagonists
  3. (C)Allosterists
  4. (D)Anti histaminists

Correct answer: (B)

Step-by-step solution →
Q50·ChemistrySingle correct
Given below are two statements : Statement I : On heating with KHSO4KHSO_{4}KHSO4​, glycerol is dehydrated and acrolein is formed. Statement II : Acrolein has fruity odour and can be used to test glycerol's presence. Choose the correct option.
  1. (A)Both Statement I and Statement II are correct.
  2. (B)Both Statement I and Statement II are incorrect
  3. (C)Statement I is correct but Statement II is incorrect.
  4. (D)Statement I is incorrect but Statement II is correct.

Correct answer: (C)

Step-by-step solution →
Q51·ChemistryNumerical
Among the following species N2N_{2}N2​, N2+N_{2}^{+}N2+​, N2−N_{2}^{-}N2−​, N22−N_{2}^{2-}N22−​, O2O_{2}O2​, O2+O_{2}^{+}O2+​, O2−O_{2}^{-}O2−​, O22−O_{2}^{2-}O22−​ the number of species showing diamagnetism is

Correct answer: 2

Step-by-step solution →
Q52·ChemistryNumerical
The enthalpy of combustion of propane, graphite and dihydrogen at 298 K are: –2220.0 kJ mol−1mol^{-1}mol−1, –393.5 kJ mol−1mol^{-1}mol−1 and –285.8 kJ mol−1mol^{-1}mol−1 respectively. The magnitude enthalpy of formation of propane (C3H8C_{3}H_{8}C3​H8​) is………kJ mol−1mol^{-1}mol−1. (Nearest integer)

Correct answer: 104

Step-by-step solution →
Q53·ChemistryNumerical
The pressure of a moist gas at 27°C is 4 atm. The volume of the container is doubled at the same temperature. The new pressure of the moist gas is …. ×10−1\times 10^{-1}×10−1 atm. (Nearest integer) (Given : The vapour pressure of water at 27°C is 0.4 atm)

Correct answer: 22

Step-by-step solution →
Q54·ChemistryNumerical
The half life for the decomposition of gaseous compound A is 240 s when the gaseous pressure was 500 Torr initially. When the pressure was 250 Torr, the half life was found to be 4.0 min. The order of the reaction is……. (Nearest integer)

Correct answer: 1

Step-by-step solution →
Q55·ChemistryNumerical
Consider the following metal complexes : [Co(NH3)]3+[Co(NH_{3})]^{3+}[Co(NH3​)]3+ [CoCl(NH3)5]2+[CoCl(NH_{3})_{5}]^{2+}[CoCl(NH3​)5​]2+ [Co(CN)6]3−[Co(CN)_{6}]^{3-}[Co(CN)6​]3− [Co(NH3)5(H2O)]3+[Co(NH_{3})_{5}(H_{2}O)]^{3+}[Co(NH3​)5​(H2​O)]3+ The spin-only magnetic moment value of the complex that absorbs light with shortest wavelength is B.M. (Nearest integer)

Correct answer: 0

Step-by-step solution →
Q56·ChemistryNumerical
Among Co3+Co^{3+}Co3+, Ti2+Ti^{2+}Ti2+, V2+V^{2+}V2+ and Cr2+Cr^{2+}Cr2+ions, one if used as a reagent cannot liberate H2H_{2}H2​ from dilute mineral acid solution, its spin-only magnetic moment in gaseous state is ……B.M. (Nearest integer)

Correct answer: 5

Step-by-step solution →
Q57·ChemistryNumerical
While estimating the nitrogen present in an organic compound by Kjeldahl's method, the ammonia evolved from 0.25 g of the compound neutralized 2.5 mL of 2 M H2SO4H_{2}SO_{4}H2​SO4​. The percentage of nitrogen present in organic compound is …… .

Correct answer: 56

Step-by-step solution →
Q58·ChemistryNumerical
The number of sp3sp^{3}sp3 hybridised carbons in an acyclic neutral compound with molecular formula C4H5NC_{4}H_{5}NC4​H5​N is :

Correct answer: 1

Step-by-step solution →
Q59·ChemistryNumerical
In the given reaction (Where Et is -C2H5C_{2}H_{5}C2​H5​) The number of chiral carbon/s in product A is

Correct answer: 2

Step-by-step solution →

Mathematics — JEE Main 25 July 2022 Shift 1

Q60·MathematicsSingle correct
The total number of functions, f : {1,2,3,4}→{1,2,3,4,5,6}\{1, 2, 3, 4\} \to \{1, 2, 3, 4, 5, 6\}{1,2,3,4}→{1,2,3,4,5,6} such that f(1) + f(2) = f(3), is equal to :
  1. (A)60
  2. (B)90
  3. (C)108
  4. (D)126

Correct answer: (B)

Step-by-step solution →
Q61·MathematicsSingle correct
If α,β,γ,δ\alpha, \beta, \gamma, \deltaα,β,γ,δ are the roots of the equation x4+x3+x2+x+1=0x^{4} + x^{3} + x^{2} + x + 1 = 0x4+x3+x2+x+1=0, then α2021+β2021+γ2021+δ2021\alpha^{2021} + \beta^{2021} + \gamma^{2021} + \delta^{2021}α2021+β2021+γ2021+δ2021 is equal to .
  1. (A)−4-4−4
  2. (B)−1-1−1
  3. (C)111
  4. (D)444

Correct answer: (B)

Step-by-step solution →
Q62·MathematicsSingle correct
The number of θ∈(0,4π)\theta \in (0, 4\pi)θ∈(0,4π) for which the system of linear equations 3(sin⁡3θ)x−y+z=23 (\sin 3\theta) x - y + z = 23(sin3θ)x−y+z=2 3(cos⁡2θ)x+4y+3z=33 (\cos 2\theta) x + 4y + 3z = 33(cos2θ)x+4y+3z=3 6x+7y+7z=96x + 7y + 7z = 96x+7y+7z=9 has no solution is :
  1. (A)6
  2. (B)7
  3. (C)8
  4. (D)9

Correct answer: (B)

Step-by-step solution →
Q63·Mathematics·Limits and ContinuitySingle correct
If lim⁡n→∞(n2−n−1+nα+β)=0\lim_{n \to \infty} \left( \sqrt{n^{2} - n - 1} + n\alpha + \beta \right) = 0limn→∞​(n2−n−1​+nα+β)=0 then 8(α+β)8(\alpha + \beta)8(α+β) is equal to :
  1. (A)444
  2. (B)−8-8−8
  3. (C)−4-4−4
  4. (D)888

Correct answer: (C)

Step-by-step solution →
Q64·MathematicsSingle correct
If the absolute maximum value of the function f(x)=(x2−2x+7) e(4x3−12x2−180x+31)f(x) = (x^{2} - 2x + 7)\, e^{(4x^{3} - 12x^{2} - 180x + 31)}f(x)=(x2−2x+7)e(4x3−12x2−180x+31) in the interval [−3,0][-3, 0][−3,0] is f(α)f(\alpha)f(α), then :
  1. (A)α=0\alpha = 0α=0
  2. (B)α=−3\alpha = -3α=−3
  3. (C)α∈(−1,0)\alpha \in (-1, 0)α∈(−1,0)
  4. (D)α∈(−3,−1)\alpha \in (-3, -1)α∈(−3,−1)

Correct answer: (B)

Step-by-step solution →
Q65·MathematicsSingle correct
The curve y(x)=ax3+bx2+cx+5y(x) = ax^{3} + bx^{2} + cx + 5y(x)=ax3+bx2+cx+5 touches the x-axis at the point P(−2,0)(-2, 0)(−2,0) and cuts the y-axis at the point Q, where y' is equal to 3. Then the local maximum value of y(x) is :
  1. (A)274\frac{27}{4}427​
  2. (B)294\frac{29}{4}429​
  3. (C)374\frac{37}{4}437​
  4. (D)92\frac{9}{2}29​

Correct answer: (A)

Step-by-step solution →
Q66·MathematicsSingle correct
The area of the region given by A={(x,y):x2≤y≤min⁡{x+2,4−3x}}A = \{(x, y) : x^{2} \le y \le \min \{x + 2, 4 - 3x\}\}A={(x,y):x2≤y≤min{x+2,4−3x}} is :
  1. (A)318\frac{31}{8}831​
  2. (B)176\frac{17}{6}617​
  3. (C)196\frac{19}{6}619​
  4. (D)278\frac{27}{8}827​

Correct answer: (B)

Step-by-step solution →
Q67·MathematicsSingle correct
For any real number x, let [x] denote the largest integer less than equal to x. Let f be a real valued function defined on the interval [−10,10][-10, 10][−10,10] by f(x)={x−[x],if(x) is odd1+[x]−xif(x) is evenf(x) = \begin{cases} x - [x], & \text{if}(x) \text{ is odd} \\ 1 + [x] - x & \text{if}(x) \text{ is even} \end{cases}f(x)={x−[x],1+[x]−x​if(x) is oddif(x) is even​ Then the value of π210∫−1010f(x)cos⁡πx dx\frac{\pi^{2}}{10} \int_{-10}^{10} f(x) \cos \pi x\, dx10π2​∫−1010​f(x)cosπxdx is :
  1. (A)4
  2. (B)2
  3. (C)1
  4. (D)0

Correct answer: (A)

Step-by-step solution →
Q68·MathematicsSingle correct
The slope of the tangent to a curve C : y = y(x) at any point [x,y)[x, y)[x,y) on it is 2e2x−6e−x+92+9e−2x\frac{2e^{2x} - 6e^{-x} + 9}{2 + 9e^{-2x}}2+9e−2x2e2x−6e−x+9​. If C passes through the points (0,12+π22)\left( 0, \frac{1}{2} + \frac{\pi}{2\sqrt{2}} \right)(0,21​+22​π​) and (α,12e2α)\left( \alpha, \frac{1}{2} e^{2\alpha} \right)(α,21​e2α) then eαe^{\alpha}eα is equal to :
  1. (A)3+23−2\frac{3 + \sqrt{2}}{3 - \sqrt{2}}3−2​3+2​​
  2. (B)32(3+23−2)\frac{3}{\sqrt{2}} \left( \frac{3 + \sqrt{2}}{3 - \sqrt{2}} \right)2​3​(3−2​3+2​​)
  3. (C)12(2+12−1)\frac{1}{\sqrt{2}} \left( \frac{\sqrt{2} + 1}{\sqrt{2} - 1} \right)2​1​(2​−12​+1​)
  4. (D)2+12−1\frac{\sqrt{2} + 1}{\sqrt{2} - 1}2​−12​+1​

Correct answer: (B)

Step-by-step solution →
Q69·MathematicsSingle correct
The general solution of the differential equation (x−y2)dx+y(5x+y2)dy=0(x - y^{2})dx + y(5x + y^{2})dy = 0(x−y2)dx+y(5x+y2)dy=0 is :
  1. (A)(y2+x)4=C∣(y2+2x)3∣(y^{2} + x)^{4} = C|(y^{2} + 2x)^{3}|(y2+x)4=C∣(y2+2x)3∣
  2. (B)(y2+2x)4=C∣(y2+x)3∣(y^{2} + 2x)^{4} = C|(y^{2} + x)^{3}|(y2+2x)4=C∣(y2+x)3∣
  3. (C)∣(y2+x)3∣=C(2y2+x)4|(y^{2} + x)^{3}| = C(2y^{2} + x)^{4}∣(y2+x)3∣=C(2y2+x)4
  4. (D)∣(y2+2x)3∣=C(2y2+x)4|(y^{2} + 2x)^{3}| = C(2y^{2} + x)^{4}∣(y2+2x)3∣=C(2y2+x)4

Correct answer: (A)

Step-by-step solution →
Q70·MathematicsSingle correct
A line, with the slope greater than one, passes through the point A(4, 3) and intersects the line x−y−2=0x - y - 2 = 0x−y−2=0 at the point B. If the length of the line segment AB is 293\frac{\sqrt{29}}{3}329​​, then B also lies on the line :
  1. (A)2x+y=92x + y = 92x+y=9
  2. (B)3x−2y=73x - 2y = 73x−2y=7
  3. (C)x+2y=6x + 2y = 6x+2y=6
  4. (D)2x−3y=32x - 3y = 32x−3y=3

Correct answer: (C)

Step-by-step solution →
Q71·MathematicsSingle correct
Let the locus of the centre (α,β)(\alpha, \beta)(α,β), β>0\beta > 0β>0, of the circle which touches the circle x2+(y−1)2=1x^{2} + (y - 1)^{2} = 1x2+(y−1)2=1 externally and also touches the x-axis be L. Then the area bounded by L and the line y=4y = 4y=4 is :
  1. (A)3223\frac{32\sqrt{2}}{3}3322​​
  2. (B)4023\frac{40\sqrt{2}}{3}3402​​
  3. (C)643\frac{64}{3}364​
  4. (D)323\frac{32}{3}332​

Correct answer: (C)

Step-by-step solution →
Q72·MathematicsSingle correct
Let P be the plane containing the straight line x−39=y+4−1=z−7−5\frac{x - 3}{9} = \frac{y + 4}{-1} = \frac{z - 7}{-5}9x−3​=−1y+4​=−5z−7​ and perpendicular to the plane containing the straight lines x2=y3=z5\frac{x}{2} = \frac{y}{3} = \frac{z}{5}2x​=3y​=5z​ and x3=y7=z8\frac{x}{3} = \frac{y}{7} = \frac{z}{8}3x​=7y​=8z​. If d is the distance of P from the point (2,−5,11)(2, -5, 11)(2,−5,11), then d2d^{2}d2 is equal to :
  1. (A)1472\frac{147}{2}2147​
  2. (B)969696
  3. (C)323\frac{32}{3}332​
  4. (D)545454

Correct answer: (C)

Step-by-step solution →
Q73·MathematicsSingle correct
Let ABC be a triangle such that BC→=a⃗\overrightarrow{BC} = \vec{a}BC=a, CA→=b⃗\overrightarrow{CA} = \vec{b}CA=b, AB→=c⃗\overrightarrow{AB} = \vec{c}AB=c, ∣a⃗∣=62|\vec{a}| = 6\sqrt{2}∣a∣=62​, ∣b⃗∣=23|\vec{b}| = 2\sqrt{3}∣b∣=23​ and b⃗⋅c⃗=12\vec{b} \cdot \vec{c} = 12b⋅c=12. Consider the statements : (S1) : ∣(a⃗×b⃗)+(c⃗×b⃗)∣−∣c⃗∣=6(22−1)|(\vec{a} \times \vec{b}) + (\vec{c} \times \vec{b})| - |\vec{c}| = 6(2\sqrt{2} - 1)∣(a×b)+(c×b)∣−∣c∣=6(22​−1) (S2) : ∠ABC=cos⁡−1(23)\angle ABC = \cos^{-1}\left( \sqrt{\frac{2}{3}} \right)∠ABC=cos−1(32​​). Then
  1. (A)both (S1) and (S2) are true
  2. (B)only (S1) is true
  3. (C)only (S2) is true
  4. (D)both (S1) and (S2) are false

Correct answer: (D)

Step-by-step solution →
Q74·MathematicsSingle correct
If the sum and the product of mean and variance of a binomial distribution are 24 and 128 respectively, then the probability of one or two successes is :
  1. (A)33232\frac{33}{2^{32}}23233​
  2. (B)33229\frac{33}{2^{29}}22933​
  3. (C)33228\frac{33}{2^{28}}22833​
  4. (D)33227\frac{33}{2^{27}}22733​

Correct answer: (C)

Step-by-step solution →
Q75·MathematicsSingle correct
If the numbers appeared on the two throws of a fair six faced die are α\alphaα and β\betaβ, then the probability that x2+αx+β>0x^{2} + \alpha x + \beta > 0x2+αx+β>0, for all x∈Rx \in Rx∈R, is :
  1. (A)1736\frac{17}{36}3617​
  2. (B)49\frac{4}{9}94​
  3. (C)12\frac{1}{2}21​
  4. (D)1936\frac{19}{36}3619​

Correct answer: (A)

Step-by-step solution →
Q76·MathematicsSingle correct
The number of solutions of ∣cos⁡x∣=sin⁡x|\cos x| = \sin x∣cosx∣=sinx, such that −4π≤x≤4π-4\pi \le x \le 4\pi−4π≤x≤4π is :
  1. (A)4
  2. (B)6
  3. (C)8
  4. (D)12

Correct answer: (C)

Step-by-step solution →
Q77·MathematicsSingle correct
A tower PQ stands on a horizontal ground with base Q on the ground. The point R divides the tower in two parts such that QR = 15 m. If from a point A on the ground the angle of elevation of R is 60∘60^\circ60∘ and the part PR of the tower subtends an angle of 15∘15^\circ15∘ at A, then the height of the tower is :
  1. (A)5(23+3)5(2\sqrt{3}+3)5(23​+3) m
  2. (B)5(3+3)5(\sqrt{3}+3)5(3​+3) m
  3. (C)10(3+1)10(\sqrt{3}+1)10(3​+1) m
  4. (D)10(23+1)10(2\sqrt{3}+1)10(23​+1) m

Correct answer: (A)

Step-by-step solution →
Q78·MathematicsSingle correct
Which of the following statements is a tautology ?
  1. (A)((∼p)∨q)⇒p((\sim p) \vee q) \Rightarrow p((∼p)∨q)⇒p
  2. (B)p⇒((∼p)∨q)p \Rightarrow ((\sim p) \vee q)p⇒((∼p)∨q)
  3. (C)((∼p)∨q)⇒q((\sim p) \vee q) \Rightarrow q((∼p)∨q)⇒q
  4. (D)q⇒((∼p)∨q)q \Rightarrow ((\sim p) \vee q)q⇒((∼p)∨q)

Correct answer: (D)

Step-by-step solution →
Q79·MathematicsNumerical
Let A=[2−1−110−11−10]A = \begin{bmatrix} 2 & -1 & -1 \\ 1 & 0 & -1 \\ 1 & -1 & 0 \end{bmatrix}A=​211​−10−1​−1−10​​ and B=A−IB = A - IB=A−I. If ω=3i−12\omega = \frac{\sqrt{3}i - 1}{2}ω=23​i−1​, then the number of elements in the set {n∈{1,2,…,100}:An+(ωB)n=A+B}\{n \in \{1, 2, \ldots, 100\} : A^{n} + (\omega B)^{n} = A + B\}{n∈{1,2,…,100}:An+(ωB)n=A+B} is equal to ________.

Correct answer: 17

Step-by-step solution →
Q80·MathematicsNumerical
The letters of the word 'MANKIND' are written in all possible orders and arranged in serial order as in an English dictionary. Then the serial number of the word 'MANKIND' is ________.

Correct answer: 1492

Step-by-step solution →
Q81·MathematicsNumerical
If the maximum value of the term independent of t in the expansion of (t2x15+(1−x)110t)15\left( t^{2}x^{\frac{1}{5}} + \frac{(1-x)^{\frac{1}{10}}}{t} \right)^{15}(t2x51​+t(1−x)101​​)15, x≥0x \ge 0x≥0, is K, then 8K is equal to ________.

Correct answer: 6006

Step-by-step solution →
Q82·MathematicsNumerical
Let a, b be two non-zero real numbers. If p and r are the roots of the equation x2−8ax+2a=0x^{2} - 8ax + 2a = 0x2−8ax+2a=0 and q and s are the roots of the equation x2+12bx+6b=0x^{2} + 12bx + 6b = 0x2+12bx+6b=0, such that 1p,1q,1r,1s\frac{1}{p}, \frac{1}{q}, \frac{1}{r}, \frac{1}{s}p1​,q1​,r1​,s1​ are in A.P., then a−1−b−1a^{-1} - b^{-1}a−1−b−1 is equal to ________.

Correct answer: 38

Step-by-step solution →
Q83·MathematicsNumerical
Let a1=b1=1a_{1} = b_{1} = 1a1​=b1​=1, an=an−1+2a_{n} = a_{n-1} + 2an​=an−1​+2 and bn=an+bn−1b_{n} = a_{n} + b_{n-1}bn​=an​+bn−1​ for every natural number n≥2n \ge 2n≥2. Then ∑n=115an⋅bn\sum_{n=1}^{15} a_{n} \cdot b_{n}∑n=115​an​⋅bn​ is equal to ________.

Correct answer: 27560

Step-by-step solution →
Q84·Mathematics·Limits and ContinuityNumerical
Let f(x)={∣4x2−8x+5∣,if 8x2−6x+1≥0[4x2−8x+5],if 8x2−6x+1<0f(x) = \begin{cases} |4x^{2} - 8x + 5|, & \text{if } 8x^{2} - 6x + 1 \ge 0 \\ [4x^{2} - 8x + 5], & \text{if } 8x^{2} - 6x + 1 < 0 \end{cases}f(x)={∣4x2−8x+5∣,[4x2−8x+5],​if 8x2−6x+1≥0if 8x2−6x+1<0​, where [α][\alpha][α] denotes the greatest integer less than or equal to α\alphaα. Then the number of points in R where f is not differentiable is ________.

Correct answer: 3

Step-by-step solution →
Q85·MathematicsNumerical
If lim⁡n→∞(n+1)k−1nk+1[(nk+1)+(nk+2)+…+(nk+n)]=33.lim⁡n→∞1nk+1⋅[1k+2k+3k+…+nk]\lim_{n\to\infty} \frac{(n+1)^{k-1}}{n^{k+1}} [(nk + 1) + (nk + 2) + \ldots + (nk + n)] = 33. \lim_{n\to\infty} \frac{1}{n^{k+1}} \cdot [1^{k} + 2^{k} + 3^{k} + \ldots + n^{k}]limn→∞​nk+1(n+1)k−1​[(nk+1)+(nk+2)+…+(nk+n)]=33.limn→∞​nk+11​⋅[1k+2k+3k+…+nk], then the integral value of k is equal to ________.

Correct answer: 5

Step-by-step solution →
Q86·MathematicsNumerical
Let the equation of two diameters of a circle x2+y2−2x+2fy+1=0x^{2} + y^{2} - 2x + 2fy + 1 = 0x2+y2−2x+2fy+1=0 be 2px−y=12px - y = 12px−y=1 and 2x+py=4p2x + py = 4p2x+py=4p. Then the slope m∈(0,∞)m \in (0, \infty)m∈(0,∞) of the tangent to the hyperbola 3x2−y2=33x^{2} - y^{2} = 33x2−y2=3 passing through the centre of the circle is equal to ________.

Correct answer: 2

Step-by-step solution →
Q87·MathematicsNumerical
The sum of diameters of the circles that touch (i) the parabola 75x2=64(5y−3)75x^{2} = 64(5y - 3)75x2=64(5y−3) at the point (85,65)\left( \frac{8}{5}, \frac{6}{5} \right)(58​,56​) and (ii) the y-axis, is equal to ________.

Correct answer: 10

Step-by-step solution →
Q88·MathematicsNumerical
The line of shortest distance between the lines x−20=y−11=z1\frac{x-2}{0} = \frac{y-1}{1} = \frac{z}{1}0x−2​=1y−1​=1z​ and x−32=y−52=z−11\frac{x-3}{2} = \frac{y-5}{2} = \frac{z-1}{1}2x−3​=2y−5​=1z−1​ makes an angle of cos⁡−1(227)\cos^{-1}\left( \sqrt{\frac{2}{27}} \right)cos−1(272​​) with the plane P:ax−y−z=0P : ax - y - z = 0P:ax−y−z=0, (a>0)(a > 0)(a>0). If the image of the point (1,1,−5)(1, 1, -5)(1,1,−5) in the plane P is (α,β,γ)(\alpha, \beta, \gamma)(α,β,γ), then α+β−γ\alpha + \beta - \gammaα+β−γ is equal to ________.

Correct answer: 3

Step-by-step solution →

Chapters tested in this paper

Open any chapter to practise every past-year question on that topic across all papers, and see how often it has actually appeared.

  • Properties of Solids and Liquids 172/186
  • Three Dimensional Geometry 176/186
  • Matrices and Determinants 180/186
  • Coordination Compounds 176/186
  • Sets, Relations and Functions 165/186
  • Current Electricity 160/186
  • Sequence and Series 164/186
  • p-Block Elements 164/186
  • Definite Integration 168/186
  • Rotational Motion 172/186
  • Redox Reactions and Electrochemistry 177/186
  • Geometrical Optics 172/186
  • Kinematics 156/186
  • Vector Algebra 173/186
  • Differential Equations 167/186
  • Probability 176/186
  • Permutations and Combinations 162/186
  • Magnetic Field of Current 147/186
  • Binomial Theorem and Its Simple Applications 158/186
  • Electromagnetic Waves 144/186
  • Chemical Bonding and Molecular Structure 151/186
  • Application of Derivatives 139/186
  • Limits and Continuity 149/186
  • d- and f-Block Elements 126/186
  • Thermodynamics 154/186
  • Aldehydes and Ketones 135/186
  • Equilibrium 163/186
  • Solutions 158/186
  • Laws of Motion 130/186
  • Chemical Thermodynamics 165/186
  • Units and Measurements 149/186
  • Hydrocarbons 126/186
  • Complex Numbers 165/186
  • Trigonometric Functions 144/186
  • Biomolecules 162/186
  • Chemical Kinetics 169/186
  • Gravitation 152/186
  • Electric Field and Coulomb's Law 133/186
  • Atomic Structure 161/186
  • Electronic Devices 145/186
  • Circles 142/186
  • Dual Nature of Matter and Radiation 155/186
  • Amines 133/186
  • Quadratic Equations 148/186
  • Work, Energy and Power 132/186
  • Some Basic Concepts in Chemistry 129/186
  • Electromagnetic Induction 120/186
  • Area Under Curves 139/186
  • Kinetic Theory of Gases 135/186
  • Alcohols and Ethers 106/186
  • Purification and Characterisation of Organic Compounds 116/186
  • Oscillations 117/186
  • Alternating Currents 108/186
  • Organic Compounds Containing Halogens 109/186
  • Straight Lines 114/186
  • Waves 109/186
  • Capacitors and Dielectrics 115/186
  • Atoms 112/186
  • Classification of Elements and Periodicity in Properties 113/186
  • Isolation of Metals 106/186
  • s-Block Elements 88/186
  • Surface Chemistry 98/186
  • Environmental Chemistry 83/186
  • Hyperbola 77/186
  • Polymers 64/186
  • Carboxylic Acids and Derivatives 54/186
  • Chemistry in Everyday Life 60/186
  • States of Matter: Gases and Liquids 52/186
  • Magnetism and Matter 50/186
  • IUPAC Nomenclature 37/186
← 29 Jun Shift 2 2022All papers26 Jul Shift 1 2022 →

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