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JEE Main 30 January 2024 Shift 2 Question Paper with Answers

30 January 2024 · January session · 87 questions

87 of the 90 questions from the JEE Main 30 January 2024 Shift 2 paper, each with its correct answer and tagged to the chapter it tests. Free to read, no account needed.

3 questions are held back from this paper while we re-check the transcription or the answer key. We would rather show you nothing than show you an answer we are not confident is right.

Physics
28
Chemistry
30
Mathematics
29

Physics — JEE Main 30 January 2024 Shift 2

Q1·Physics·Experimental SkillsSingle correct
If 50 Vernier divisions are equal to 49 main scale divisions of a travelling microscope and one smallest reading of main scale is 0.5 mm, the Vernier constant of travelling microscope is:
  1. (A)0.1 mm
  2. (B)0.1 cm
  3. (C)0.01 cm
  4. (D)0.01 mm

Correct answer: (D)

Step-by-step solution →
Q2·Physics·Work, Energy and PowerSingle correct
A block of mass 1 kg is pushed up a surface inclined at angle 60∘60^\circ60∘ by a force of 10 N parallel to the inclined surface as shown in figure. When the block is pushed up by 10 m along inclined surface, the work done against frictional force is: [g=10 m/s2g=10\ \text{m/s}^2g=10 m/s2]
  1. (A)535\sqrt{3}53​ J
  2. (B)5 J
  3. (C)5×1035\times 10^35×103 J
  4. (D)10 J

Correct answer: (B)

Step-by-step solution →
Q3·Physics·Dual Nature of Matter and RadiationSingle correct
For the photoelectric effect, the maximum kinetic energy (Ek)(E_k)(Ek​) of the photoelectrons is plotted against the frequency (ν)(\nu)(ν) of the incident photons as shown in figure. The slope of the graph gives:
  1. (A)Ratio of Planck's constant to electric charge
  2. (B)Work function of the metal
  3. (C)Charge of electron
  4. (D)Planck's constant

Correct answer: (D)

Step-by-step solution →
Q4·Physics·Properties of Solids and LiquidsSingle correct
A block of ice at −10∘-10^\circ−10∘C is slowly heated and converted to steam at 100∘100^\circ100∘C. Which of the following curves represent the phenomenon qualitatively?
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (D)

Step-by-step solution →
Q5·Physics·Atoms and NucleiSingle correct
In a nuclear fission reaction of an isotope of mass M, three similar daughter nuclei of same mass are formed. The speed of a daughter nuclei in terms of mass defect ΔM\Delta MΔM will be:
  1. (A)2cΔMM\sqrt{\dfrac{2c\Delta M}{M}}M2cΔM​​
  2. (B)ΔMc23\dfrac{\Delta Mc^2}{3}3ΔMc2​
  3. (C)c2ΔMMc\sqrt{\dfrac{2\Delta M}{M}}cM2ΔM​​
  4. (D)c3ΔMMc\sqrt{\dfrac{3\Delta M}{M}}cM3ΔM​​

Correct answer: (C)

Step-by-step solution →
Q6·Physics·ThermodynamicsMultiple correct
Choose the correct statement for processes A & B shown in figure.
  1. (A)PVγ=kPV^\gamma=kPVγ=k for process B and PV=kPV=kPV=k for process A.
  2. (B)PV=kPV=kPV=k for process B and A.
  3. (C)Pγ−1Tγ=k\dfrac{P^{\gamma-1}}{T^\gamma}=kTγPγ−1​=k for process B and T=kT=kT=k for process A.
  4. (D)TγPγ−1=k\dfrac{T^\gamma}{P^{\gamma-1}}=kPγ−1Tγ​=k for process A and PV=kPV=kPV=k for process B.

Correct answer: (A), (C)

Step-by-step solution →
Q7·Physics·Atoms and NucleiSingle correct
An electron revolving in nthn^{\text{th}}nth Bohr orbit has magnetic moment μn\mu_nμn​. If μn∝nx\mu_n\propto n^xμn​∝nx, then the value of xxx is:
  1. (A)2
  2. (B)1
  3. (C)3
  4. (D)0

Correct answer: (B)

Step-by-step solution →
Q8·Physics·Alternating CurrentsSingle correct
An alternating voltage V(t)=220sin⁡100πtV(t)=220\sin 100\pi tV(t)=220sin100πt volt is applied to a purely resistive load of 50 Ω50\,\Omega50Ω. The time taken for the current to rise from half of the peak value to the peak value is:
  1. (A)5 ms
  2. (B)3.3 ms
  3. (C)7.2 ms
  4. (D)2.2 ms

Correct answer: (B)

Step-by-step solution →
Q9·Physics·Laws of MotionSingle correct
A block of mass mmm is placed on a surface having vertical cross section given by y=x24y=\dfrac{x^2}{4}y=4x2​. If coefficient of friction is 0.5, the maximum height above the ground at which block can be placed without slipping is:
  1. (A)14\dfrac{1}{4}41​ m
  2. (B)12\dfrac{1}{2}21​ m
  3. (C)16\dfrac{1}{6}61​ m
  4. (D)13\dfrac{1}{3}31​ m

Correct answer: (A)

Step-by-step solution →
Q10·Physics·Electromagnetic WavesSingle correct
If the total energy transferred to a surface in time ttt is 6.48×1056.48\times10^56.48×105 J, then the magnitude of the total momentum delivered to this surface for complete absorption will be:
  1. (A)2.46×10−32.46\times10^{-3}2.46×10−3 kg m/s
  2. (B)2.16×10−32.16\times10^{-3}2.16×10−3 kg m/s
  3. (C)1.58×10−31.58\times10^{-3}1.58×10−3 kg m/s
  4. (D)4.32×10−34.32\times10^{-3}4.32×10−3 kg m/s

Correct answer: (B)

Step-by-step solution →
Q11·Physics·Wave OpticsSingle correct
A beam of unpolarised light of intensity I0I_0I0​ is passed through a polaroid A and then through another polaroid B which is oriented so that its principal plane makes an angle of 45∘45^\circ45∘ relative to that of A. The intensity of emergent light is:
  1. (A)I04\dfrac{I_0}{4}4I0​​
  2. (B)I0I_0I0​
  3. (C)I02\dfrac{I_0}{2}2I0​​
  4. (D)I08\dfrac{I_0}{8}8I0​​

Correct answer: (A)

Step-by-step solution →
Q12·Physics·GravitationSingle correct
Escape velocity of a body from earth is 11.2 km/s. If the radius of a planet be one-third the radius of earth and mass be one-sixth that of earth, the escape velocity from the planet is:
  1. (A)11.2 km/s
  2. (B)8.4 km/s
  3. (C)4.2 km/s
  4. (D)7.9 km/s

Correct answer: (D)

Step-by-step solution →
Q13·Physics·Electric Field and Coulomb's LawSingle correct
A particle of charge −q-q−q and mass mmm moves in a circle of radius rrr around an infinitely long line charge of linear density +λ+\lambda+λ. Then time period will be given as: (Consider kkk as Coulomb's constant)
  1. (A)T2=4π2m2kλqr3T^2=\dfrac{4\pi^2 m}{2k\lambda q}r^3T2=2kλq4π2m​r3
  2. (B)T=2πrm2kλqT=2\pi r\sqrt{\dfrac{m}{2k\lambda q}}T=2πr2kλqm​​
  3. (C)T=12πrm2kλqT=\dfrac{1}{2\pi r}\sqrt{\dfrac{m}{2k\lambda q}}T=2πr1​2kλqm​​
  4. (D)T=12π2kλqmT=\dfrac{1}{2\pi}\sqrt{\dfrac{2k\lambda q}{m}}T=2π1​m2kλq​​

Correct answer: (B)

Step-by-step solution →
Q14·Physics·Units and MeasurementsSingle correct
If mass is written as m=k cPG−1/2h1/2m=k\,c^P G^{-1/2} h^{1/2}m=kcPG−1/2h1/2 then the value of PPP will be: (Constants have their usual meaning with kkk a dimensionless constant)
  1. (A)12\dfrac{1}{2}21​
  2. (B)13\dfrac{1}{3}31​
  3. (C)2
  4. (D)−13-\dfrac{1}{3}−31​

Correct answer: (A)

Step-by-step solution →
Q15·Physics·Electronic DevicesSingle correct
In the given circuit, the voltage across resistance (RL)(R_L)(RL​) will be:
  1. (A)8.75 V
  2. (B)9.00 V
  3. (C)8.50 V
  4. (D)14.00 V

Correct answer: (A)

Step-by-step solution →
Q16·Physics·Kinetic Theory of GasesSingle correct
If three moles of monoatomic gas (γ=53)\left(\gamma=\dfrac{5}{3}\right)(γ=35​) is mixed with two moles of a diatomic gas (γ=75)\left(\gamma=\dfrac{7}{5}\right)(γ=57​), the value of adiabatic exponent γ\gammaγ for the mixture is:
  1. (A)1.75
  2. (B)1.40
  3. (C)1.52
  4. (D)1.35

Correct answer: (C)

Step-by-step solution →
Q17·Physics·Laws of MotionSingle correct
Three blocks A, B and C are pulled on a horizontal smooth surface by a force of 80 N as shown in figure. The tensions T1T_1T1​ and T2T_2T2​ in the string are respectively:
  1. (A)40N, 64N
  2. (B)60N, 80N
  3. (C)88N, 96N
  4. (D)80N, 100N

Correct answer: (A)

Step-by-step solution →
Q18·Physics·Current ElectricitySingle correct
When a potential difference V is applied across a wire of resistance R, it dissipates energy at a rate W. If the wire is cut into two halves and these halves are connected mutually parallel across the same supply, the energy dissipation rate will become:
  1. (A)14W\dfrac{1}{4}W41​W
  2. (B)12W\dfrac{1}{2}W21​W
  3. (C)2W2W2W
  4. (D)4W4W4W

Correct answer: (D)

Step-by-step solution →
Q19·Physics·Electromagnetic WavesSingle correct
Match List I with List II. Choose the correct answer from the options given below:
List-IList-II
A.Gauss's law of magnetostaticsI.∮E⃗⋅da⃗=1ε0∫ρ dV\oint \vec{E}\cdot d\vec{a}=\dfrac{1}{\varepsilon_0}\int \rho\,dV∮E⋅da=ε0​1​∫ρdV
B.Faraday's law of electromagnetic inductionII.∮B⃗⋅da⃗=0\oint \vec{B}\cdot d\vec{a}=0∮B⋅da=0
C.Ampere's lawIII.∮E⃗⋅dl⃗=−ddt∫B⃗⋅da⃗\oint \vec{E}\cdot d\vec{l}=-\dfrac{d}{dt}\int \vec{B}\cdot d\vec{a}∮E⋅dl=−dtd​∫B⋅da
D.Gauss's law of electrostaticsIV.∮B⃗⋅dl⃗=μ0I\oint \vec{B}\cdot d\vec{l}=\mu_0 I∮B⋅dl=μ0​I
  1. (A)A-I, B-III, C-IV, D-II
  2. (B)A-III, B-IV, C-I, D-II
  3. (C)A-IV, B-III, C-II, D-I
  4. (D)A-II, B-III, C-IV, D-I

Correct answer: (D)

Step-by-step solution →
Q20·Physics·Alternating CurrentsNumerical
A power transmission line feeds input power at 2.3 kV to a step down transformer with its primary winding 3000 turns. The output power is delivered at 230 V to the primary of the transformer is 5A and its efficiency is 90%. The winding of transformer is made of copper. The output current of transformer is ______ A.

Correct answer: 45

Step-by-step solution →
Q21·Physics·Properties of Solids and LiquidsNumerical
A big drop is formed by coalescing 1000 small identical drops of water. If E1E_1E1​ be the total surface energy of 1000 small drops of water and E2E_2E2​ be the surface energy of single big drop of water, then E1:E2E_1:E_2E1​:E2​ is x:1x:1x:1 where x=x=x= ______.

Correct answer: 10

Step-by-step solution →
Q22·Physics·Rotational MotionNumerical
Two discs of moment of inertia I1=4I_1=4I1​=4 kg m2^22 and I2=2I_2=2I2​=2 kg m2^22 about their central axes & normal to their planes, rotating with angular speeds 10 rad/s & 4 rad/s respectively are brought into contact face to face with their axes of rotation coincident. The loss in kinetic energy of the system in the process is ______ J.

Correct answer: 24

Step-by-step solution →
Q23·Physics·Geometrical OpticsNumerical
In an experiment to measure the focal length (f) of a convex lens, the magnitude of object distance (x) and the image distance (y) are measured with reference to the focal point of the lens. The y-x plot is shown in figure. The focal length of the lens is ______ cm.

Correct answer: 20

Step-by-step solution →
Q24·Physics·KinematicsNumerical
A vector has magnitude same as that of A⃗=3i^+4j^\vec{A}=3\hat{i}+4\hat{j}A=3i^+4j^​ and is parallel to B⃗=4i^+3j^\vec{B}=4\hat{i}+3\hat{j}B=4i^+3j^​. The x and y components of this vector in first quadrant are xxx and 3 respectively where x=x=x= ______.

Correct answer: 4

Step-by-step solution →
Q25·Physics·Magnetic Field of CurrentNumerical
The current of 5A flows in a square loop of sides 1 m is placed in air. The magnetic field at centre of the loop is X2×10−7X\sqrt{2}\times10^{-7}X2​×10−7 T. The value of XXX is ______.

Correct answer: 40

Step-by-step solution →
Q26·Physics·Capacitors and DielectricsNumerical
Two identical charged spheres are suspended by string of equal lengths. The string make an angle of 37∘37^\circ37∘ with each other. When suspended in a liquid of density 0.7 g/cm3^33, the angle remains same. If density of material of the sphere is 1.4 g/cm3^33, the dielectric constant of the liquid is ______. (tan⁡37∘=34)\left(\tan 37^\circ=\dfrac{3}{4}\right)(tan37∘=43​)

Correct answer: 2

Step-by-step solution →
Q27·Physics·GravitationNumerical
A simple pendulum is placed at a place where its distance from the earth's surface is equal to the radius of the earth. If the length of the string is 4m, then the time period of small oscillations will be ______ s. [take g=π2g=\pi^2g=π2 m/s2^22]

Correct answer: 8

Step-by-step solution →
Q28·Physics·Current ElectricityNumerical
Two resistance of 100 Ω\OmegaΩ and 200 Ω\OmegaΩ are connected in series with a battery of 4 V and negligible internal resistance. A voltmeter is used to measure voltage across 100 Ω\OmegaΩ resistance, which gives reading as 1 V. The resistance of voltmeter must be ______ Ω\OmegaΩ.

Correct answer: 200

Step-by-step solution →

Chemistry — JEE Main 30 January 2024 Shift 2

Q29·Chemistry·Purification and Characterisation of Organic CompoundsSingle correct
Which among the following purification methods is based on the principle of "Solubility" in two different solvents?
  1. (A)Column Chromatography
  2. (B)Sublimation
  3. (C)Distillation
  4. (D)Differential Extraction

Correct answer: (D)

Step-by-step solution →
Q30·Chemistry·Alcohols and EthersSingle correct
Salicylaldehyde is synthesized from phenol, when reacted with:
  1. (A)HCOClHCOClHCOCl, NaOH
  2. (B)CO2CO_2CO2​, NaOH
  3. (C)CCl4CCl_4CCl4​, NaOH
  4. (D)HCCl3HCCl_3HCCl3​, NaOH

Correct answer: (D)

Step-by-step solution →
Q31·Chemistry·Organic Compounds Containing HalogensSingle correct
Given below are two statements: Statement-I: High concentration of strong nucleophilic reagent with secondary alkyl halides which do not have bulky substituents will follow SN2S_N2SN​2 mechanism. Statement-II: A secondary alkyl halide when treated with a large excess of ethanol follows SN1S_N1SN​1 mechanism. In the light of the above statements, choose the most appropriate answer from the options given below:
  1. (A)Statement I is true but Statement II is false.
  2. (B)Statement I is false but Statement II is true.
  3. (C)Both Statement I and Statement II are false.
  4. (D)Both Statement I and Statement II are true.

Correct answer: (D)

Step-by-step solution →
Q32·Chemistry·Aldehydes and KetonesSingle correct
m-Chlorobenzaldehyde on treatment with 50% KOH solution yields:
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (B)

Step-by-step solution →
Q33·Chemistry·p-Block ElementsSingle correct
Given below are two statements. One is labelled as Assertion A and the other is labelled as Reason R. Assertion A: H2TeH_2TeH2​Te is more acidic than H2SH_2SH2​S. Reason R: Bond dissociation enthalpy of H2TeH_2TeH2​Te is lower than H2SH_2SH2​S. In the light of the above statements, choose the most appropriate answer from the options given below:
  1. (A)Both A and R are true but R is NOT the correct explanation of A.
  2. (B)Both A and R are true and R is the correct explanation of A.
  3. (C)A is false but R is true.
  4. (D)A is true but R is false.

Correct answer: (B)

Step-by-step solution →
Q34·Chemistry·Aldehydes and KetonesSingle correct
Product A and B formed in the following set of reactions are:
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (B)

Step-by-step solution →
Q35·Chemistry·IUPAC NomenclatureSingle correct
IUPAC name of following compound is: CH3−CH(NH2)−CH2−CNCH_3-CH(NH_2)-CH_2-CNCH3​−CH(NH2​)−CH2​−CN
  1. (A)2-Aminopentanenitrile
  2. (B)2-Aminobutanenitrile
  3. (C)3-Aminobutanenitrile
  4. (D)3-Aminopropanenitrile

Correct answer: (C)

Step-by-step solution →
Q36·Chemistry·AminesSingle correct
The products A and B formed in the following reaction scheme are respectively:
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (C)

Step-by-step solution →
Q37·Chemistry·Chemical Bonding and Molecular StructureSingle correct
The molecule/ion with square pyramidal shape is:
  1. (A)[Ni(CN)4]2−[Ni(CN)_4]^{2-}[Ni(CN)4​]2−
  2. (B)PCl5PCl_5PCl5​
  3. (C)BrF5BrF_5BrF5​
  4. (D)PF5PF_5PF5​

Correct answer: (C)

Step-by-step solution →
Q38·Chemistry·d- and f-Block ElementsSingle correct
The orange colour of K2Cr2O7K_2Cr_2O_7K2​Cr2​O7​ and purple colour of KMnO4KMnO_4KMnO4​ is due to:
  1. (A)Charge transfer transition in both.
  2. (B)ddd-ddd transition in KMnO4KMnO_4KMnO4​ and charge transfer transitions in K2Cr2O7K_2Cr_2O_7K2​Cr2​O7​.
  3. (C)ddd-ddd transition in K2Cr2O7K_2Cr_2O_7K2​Cr2​O7​ and charge transfer transition in KMnO4KMnO_4KMnO4​.
  4. (D)ddd-ddd transition in both.

Correct answer: (A)

Step-by-step solution →
Q39·Chemistry·d- and f-Block ElementsSingle correct
Alkaline oxidative fusion of MnO2MnO_2MnO2​ gives "A" which on electrolytic oxidation in alkaline solution produces B. A and B respectively are:
  1. (A)Mn2O3Mn_2O_3Mn2​O3​ and MnO4−MnO_4^-MnO4−​
  2. (B)MnO42−MnO_4^{2-}MnO42−​ and MnO4−MnO_4^-MnO4−​
  3. (C)Mn2O3Mn_2O_3Mn2​O3​ and MnO42−MnO_4^{2-}MnO42−​
  4. (D)MnO42−MnO_4^{2-}MnO42−​ and Mn2O3Mn_2O_3Mn2​O3​

Correct answer: (B)

Step-by-step solution →
Q40·Chemistry·Some Basic Concepts in ChemistrySingle correct
If a substance 'A' dissolves in solution of a mixture of 'B' and 'C' with their respective number of moles as nAn_AnA​, nBn_BnB​ and nCn_CnC​, mole fraction of C in the solution is:
  1. (A)nCnA×nB×nC\dfrac{n_C}{n_A\times n_B\times n_C}nA​×nB​×nC​nC​​
  2. (B)nCnA+nB+nC\dfrac{n_C}{n_A+n_B+n_C}nA​+nB​+nC​nC​​
  3. (C)nCnA−nB−nC\dfrac{n_C}{n_A-n_B-n_C}nA​−nB​−nC​nC​​
  4. (D)nBnA+nB\dfrac{n_B}{n_A+n_B}nA​+nB​nB​​

Correct answer: (B)

Step-by-step solution →
Q41·Chemistry·Classification of Elements and Periodicity in PropertiesSingle correct
Given below are two statements: Statement-I: Along the period, the chemical reactivity of the element gradually increases from group 1 to group 18. Statement-II: The nature of oxides formed by group 1 element is basic while that of group 17 elements is acidic. In the light of the above statements, choose the most appropriate answer from the options given below:
  1. (A)Both Statement I and Statement II are true.
  2. (B)Statement I is true but Statement II is false.
  3. (C)Statement I is false but Statement II is true.
  4. (D)Both Statement I and Statement II are false.

Correct answer: (C)

Step-by-step solution →
Q42·Chemistry·Coordination CompoundsSingle correct
The coordination geometry around the manganese in decacarbonyldimanganese(0) is:
  1. (A)Octahedral
  2. (B)Trigonal bipyramidal
  3. (C)Square pyramidal
  4. (D)Square planar

Correct answer: (A)

Step-by-step solution →
Q43·Chemistry·Chemical Bonding and Molecular StructureSingle correct
Given below are two statements: Statement-I: Since fluorine is more electronegative than nitrogen, the net dipole moment of NF3NF_3NF3​ is greater than NH3NH_3NH3​. Statement-II: In NH3NH_3NH3​ the orbital dipole due to lone pair and the dipole moment of NH bonds are in opposite direction, but in NF3NF_3NF3​ the orbital dipole due to lone pair and dipole moments of N-F bonds are in same direction. In the light of the above statements, choose the most appropriate answer from the options given below:
  1. (A)Statement I is true but Statement II is false.
  2. (B)Both Statement I and Statement II are false.
  3. (C)Both Statement I and Statement II are true.
  4. (D)Statement I is false but Statement II is true.

Correct answer: (B)

Step-by-step solution →
Q44·Chemistry·Electronic Effects and StabilitySingle correct
The correct stability order of carbocations is:
  1. (A)(CH3)3C+>CH3−C+H2>(CH3)2C+H>C+H3(CH_3)_3C^+ > CH_3-\overset{+}{C}H_2 > (CH_3)_2\overset{+}{C}H > \overset{+}{C}H_3(CH3​)3​C+>CH3​−C+H2​>(CH3​)2​C+H>C+H3​
  2. (B)C+H3>(CH3)2C+H>CH3−C+H2>(CH3)3C+\overset{+}{C}H_3 > (CH_3)_2\overset{+}{C}H > CH_3-\overset{+}{C}H_2 > (CH_3)_3\overset{+}{C}C+H3​>(CH3​)2​C+H>CH3​−C+H2​>(CH3​)3​C+
  3. (C)(CH3)3C+>(CH3)2C+H>CH3−C+H2>C+H3(CH_3)_3\overset{+}{C} > (CH_3)_2\overset{+}{C}H > CH_3-\overset{+}{C}H_2 > \overset{+}{C}H_3(CH3​)3​C+>(CH3​)2​C+H>CH3​−C+H2​>C+H3​
  4. (D)C+H3>CH3−C+H2>(CH3)2C+H>(CH3)3C+\overset{+}{C}H_3 > CH_3-\overset{+}{C}H_2 > (CH_3)_2\overset{+}{C}H > (CH_3)_3\overset{+}{C}C+H3​>CH3​−C+H2​>(CH3​)2​C+H>(CH3​)3​C+

Correct answer: (C)

Step-by-step solution →
Q45·Chemistry·SolutionsSingle correct
The solution from the following with highest depression in freezing point/lowest freezing point is:
  1. (A)180 g of acetic acid dissolved in water
  2. (B)180 g of acetic acid dissolved in benzene
  3. (C)180 g of benzoic acid dissolved in benzene
  4. (D)180 g of glucose dissolved in water

Correct answer: (A)

Step-by-step solution →
Q46·Chemistry·d- and f-Block ElementsSingle correct
A and B formed in the following reactions are: CrO2Cl2+4NaOH→A+2NaCl+2H2OCrO_2Cl_2 + 4NaOH \rightarrow A + 2NaCl + 2H_2OCrO2​Cl2​+4NaOH→A+2NaCl+2H2​O A+2HCl+2H2O2→B+3H2OA + 2HCl + 2H_2O_2 \rightarrow B + 3H_2OA+2HCl+2H2​O2​→B+3H2​O
  1. (A)A=Na2CrO4, B=CrO5A = Na_2CrO_4,\ B = CrO_5A=Na2​CrO4​, B=CrO5​
  2. (B)A=Na2Cr2O7, B=CrO4A = Na_2Cr_2O_7,\ B = CrO_4A=Na2​Cr2​O7​, B=CrO4​
  3. (C)A=Na2Cr2O7, B=CrO3A = Na_2Cr_2O_7,\ B = CrO_3A=Na2​Cr2​O7​, B=CrO3​
  4. (D)A=Na2Cr2O7, B=CrO5A = Na_2Cr_2O_7,\ B = CrO_5A=Na2​Cr2​O7​, B=CrO5​

Correct answer: (A)

Step-by-step solution →
Q47·Chemistry·p-Block ElementsSingle correct
Choose the correct statements about the hydrides of group 15 elements. A. The stability of the hydrides decreases in the order NH3>PH3>AsH3>SbH3>BiH3NH_3 > PH_3 > AsH_3 > SbH_3 > BiH_3NH3​>PH3​>AsH3​>SbH3​>BiH3​. B. The reducing ability of the hydrides increases in the order NH3<PH3<AsH3<SbH3<BiH3NH_3 < PH_3 < AsH_3 < SbH_3 < BiH_3NH3​<PH3​<AsH3​<SbH3​<BiH3​. C. Among the hydrides, NH3NH_3NH3​ is strong reducing agent while BiH3BiH_3BiH3​ is mild reducing agent. D. The basicity of the hydrides increases in the order NH3<PH3<AsH3<SbH3<BiH3NH_3 < PH_3 < AsH_3 < SbH_3 < BiH_3NH3​<PH3​<AsH3​<SbH3​<BiH3​. Choose the most appropriate answer from the option given below:
  1. (A)B and C only
  2. (B)C and D only
  3. (C)A and B only
  4. (D)A and D only

Correct answer: (C)

Step-by-step solution →
Q48·Chemistry·Redox Reactions and ElectrochemistrySingle correct
Reduction potential of ions are given below: EClO4−∘=1.19E^\circ_{ClO_4^-}=1.19EClO4−​∘​=1.19 V, EIO4−∘=1.65E^\circ_{IO_4^-}=1.65EIO4−​∘​=1.65 V, EBrO4−∘=1.74E^\circ_{BrO_4^-}=1.74EBrO4−​∘​=1.74 V. The correct order of their oxidising power is:
  1. (A)ClO4−>IO4−>BrO4−ClO_4^- > IO_4^- > BrO_4^-ClO4−​>IO4−​>BrO4−​
  2. (B)ClO4−>BrO4−>IO4−ClO_4^- > BrO_4^- > IO_4^-ClO4−​>BrO4−​>IO4−​
  3. (C)BrO4−>ClO4−>IO4−BrO_4^- > ClO_4^- > IO_4^-BrO4−​>ClO4−​>IO4−​
  4. (D)BrO4−>IO4−>ClO4−BrO_4^- > IO_4^- > ClO_4^-BrO4−​>IO4−​>ClO4−​

Correct answer: (D)

Step-by-step solution →
Q49·Chemistry·Coordination CompoundsNumerical
Number of complexes which show optical isomerism among the following is ______. cis-[Cr(ox)2Cl2]3−[Cr(ox)_2Cl_2]^{3-}[Cr(ox)2​Cl2​]3−, [Co(en)3]3+[Co(en)_3]^{3+}[Co(en)3​]3+, cis-[Pt(en)2Cl2]2+[Pt(en)_2Cl_2]^{2+}[Pt(en)2​Cl2​]2+, cis-[Co(en)2Cl2]+[Co(en)_2Cl_2]^{+}[Co(en)2​Cl2​]+, trans-[Pt(en)2Cl2]2+[Pt(en)_2Cl_2]^{2+}[Pt(en)2​Cl2​]2+, trans-[Cr(ox)2Cl2]3−[Cr(ox)_2Cl_2]^{3-}[Cr(ox)2​Cl2​]3−

Correct answer: 4

Step-by-step solution →
Q50·Chemistry·Chemical KineticsNumerical
NO2NO_2NO2​ required for a reaction is produced by decomposition of N2O5N_2O_5N2​O5​ in CCl4CCl_4CCl4​ as by equation 2N2O5(g)→4NO2(g)+O2(g)2N_2O_5(g)\rightarrow 4NO_2(g)+O_2(g)2N2​O5​(g)→4NO2​(g)+O2​(g). The initial concentration of N2O5N_2O_5N2​O5​ is 3 mol L−1^{-1}−1 and it is 2.75 mol L−1^{-1}−1 after 30 minutes. The rate of formation of NO2NO_2NO2​ is x×10−3x\times10^{-3}x×10−3 mol L−1^{-1}−1 min−1^{-1}−1, value of xxx is ______.

Correct answer: 17

Step-by-step solution →
Q51·Chemistry·Chemical ThermodynamicsNumerical
Two reactions are given below: 2Fe(s)+32O2(g)→Fe2O3(s)2Fe(s)+\dfrac{3}{2}O_2(g)\rightarrow Fe_2O_3(s)2Fe(s)+23​O2​(g)→Fe2​O3​(s), ΔH∘=−822\Delta H^\circ=-822ΔH∘=−822 kJ/mol C(s)+12O2(g)→CO(g)C(s)+\dfrac{1}{2}O_2(g)\rightarrow CO(g)C(s)+21​O2​(g)→CO(g), ΔH∘=−110\Delta H^\circ=-110ΔH∘=−110 kJ/mol Then enthalpy change for following reaction 3C(s)+Fe2O3(s)→2Fe(s)+3CO(g)3C(s)+Fe_2O_3(s)\rightarrow 2Fe(s)+3CO(g)3C(s)+Fe2​O3​(s)→2Fe(s)+3CO(g) is ΔH=\Delta H=ΔH= ______ kJ/mol.

Correct answer: 492

Step-by-step solution →
Q52·Chemistry·BiomoleculesNumerical
The total number of correct statements, regarding the nucleic acids is ______. A. RNA is regarded as the reserve of genetic information. B. DNA molecule self-duplicates during cell division. C. DNA synthesizes proteins in the cell. D. The message for the synthesis of particular proteins is present in DNA. E. Identical DNA strands are transferred to daughter cells.

Correct answer: 3

Step-by-step solution →
Q53·Chemistry·EquilibriumNumerical
The pH of an aqueous solution containing 1M benzoic acid (pKa=4.20pK_a=4.20pKa​=4.20) and 1M sodium benzoate is 4.5. The volume of benzoic acid solution in 300 mL of this buffer solution is ______ mL.

Correct answer: 100

Step-by-step solution →
Q54·Chemistry·IsomerismNumerical
Number of geometrical isomers possible for the given structure is/are ______.

Correct answer: 4

Step-by-step solution →
Q55·Chemistry·Redox Reactions and ElectrochemistryNumerical
Total number of species from the following which can undergo disproportionation reaction is ______. H2O2H_2O_2H2​O2​, ClO3−ClO_3^-ClO3−​, P4P_4P4​, Cl2Cl_2Cl2​, AgAgAg, Cu+1Cu^{+1}Cu+1, F2F_2F2​, NO2NO_2NO2​, K+K^+K+

Correct answer: 6

Step-by-step solution →
Q56·Chemistry·s-Block ElementsNumerical
Number of metal ions characterized by flame test among the following is ______. Sr2+Sr^{2+}Sr2+, Ba2+Ba^{2+}Ba2+, Ca2+Ca^{2+}Ca2+, Cu2+Cu^{2+}Cu2+, Zn2+Zn^{2+}Zn2+, Co2+Co^{2+}Co2+, Fe2+Fe^{2+}Fe2+

Correct answer: 4

Step-by-step solution →
Q57·Chemistry·Organic Compounds Containing HalogensNumerical
2-chlorobutane + Cl2→C4H8Cl2+\ Cl_2 \rightarrow C_4H_8Cl_2+ Cl2​→C4​H8​Cl2​ (isomers). Total number of optically active isomers shown by C4H8Cl2C_4H_8Cl_2C4​H8​Cl2​, obtained in the above reaction is ______.

Correct answer: 6

Step-by-step solution →
Q58·Chemistry·Atomic StructureNumerical
Number of spectral lines obtained in He+He^+He+ spectra, when an electron makes transition from fifth excited state to first excited state will be ______.

Correct answer: 10

Step-by-step solution →

Mathematics — JEE Main 30 January 2024 Shift 2

Q59·Mathematics·Matrices and DeterminantsSingle correct
Consider the system of linear equations x+y+z=5x+y+z=5x+y+z=5, x+2y+λ2z=9x+2y+\lambda^2 z=9x+2y+λ2z=9, x+3y+λz=μx+3y+\lambda z=\mux+3y+λz=μ, where λ,μ∈R\lambda,\mu\in Rλ,μ∈R. Then, which of the following statement is NOT correct?
  1. (A)System has infinite number of solutions if λ=1\lambda=1λ=1 and μ=13\mu=13μ=13
  2. (B)System is inconsistent if λ=1\lambda=1λ=1 and μ≠13\mu\ne 13μ=13
  3. (C)System is consistent if λ≠1\lambda\ne 1λ=1 and μ=13\mu=13μ=13
  4. (D)System has unique solution if λ≠1\lambda\ne 1λ=1 and μ≠13\mu\ne 13μ=13

Correct answer: (D)

Step-by-step solution →
Q60·Mathematics·Trigonometric FunctionsSingle correct
For α,β∈(0,π2)\alpha,\beta\in\left(0,\dfrac{\pi}{2}\right)α,β∈(0,2π​), let 3sin⁡(α+β)=2sin⁡(α−β)3\sin(\alpha+\beta)=2\sin(\alpha-\beta)3sin(α+β)=2sin(α−β) and a real number kkk be such that tan⁡α=ktan⁡β\tan\alpha=k\tan\betatanα=ktanβ. Then the value of kkk is equal to:
  1. (A)−23-\dfrac{2}{3}−32​
  2. (B)−5-5−5
  3. (C)23\dfrac{2}{3}32​
  4. (D)555

Correct answer: (B)

Step-by-step solution →
Q61·Mathematics·EllipseSingle correct
Let A(α,0)A(\alpha,0)A(α,0) and B(0,β)B(0,\beta)B(0,β) be the points on the line 5x+7y=505x+7y=505x+7y=50. Let the point PPP divide the line segment ABABAB internally in the ratio 7:37:37:3. Let 3x−25=03x-25=03x−25=0 be a directrix of the ellipse E:x2a2+y2b2=1E:\dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}=1E:a2x2​+b2y2​=1 and the corresponding focus be SSS. If from SSS, the perpendicular on the x-axis passes through PPP, then the length of the latus rectum of EEE is equal to:
  1. (A)253\dfrac{25}{3}325​
  2. (B)329\dfrac{32}{9}932​
  3. (C)259\dfrac{25}{9}925​
  4. (D)325\dfrac{32}{5}532​

Correct answer: (D)

Step-by-step solution →
Q62·Mathematics·Vector AlgebraSingle correct
Let a⃗=i^+αj^+βk^\vec{a}=\hat{i}+\alpha\hat{j}+\beta\hat{k}a=i^+αj^​+βk^, α,β∈R\alpha,\beta\in Rα,β∈R. Let a vector b⃗\vec{b}b be such that the angle between a⃗\vec{a}a and b⃗\vec{b}b is π4\dfrac{\pi}{4}4π​ and ∣b⃗∣2=6|\vec{b}|^2=6∣b∣2=6. If a⃗⋅b⃗=32\vec{a}\cdot\vec{b}=3\sqrt{2}a⋅b=32​, then the value of (α2+β2) ∣a⃗×b⃗∣2(\alpha^2+\beta^2)\,|\vec{a}\times\vec{b}|^2(α2+β2)∣a×b∣2 is equal to:
  1. (A)909090
  2. (B)757575
  3. (C)959595
  4. (D)858585

Correct answer: (A)

Step-by-step solution →
Q63·Mathematics·Application of DerivativesSingle correct
Let f(x)=(x+3)2(x−2)3f(x)=(x+3)^2(x-2)^3f(x)=(x+3)2(x−2)3, x∈[−4,4]x\in[-4,4]x∈[−4,4]. If MMM and mmm are the maximum and minimum values of fff, respectively in [−4,4][-4,4][−4,4], then the value of M−mM-mM−m is:
  1. (A)600600600
  2. (B)392392392
  3. (C)608608608
  4. (D)108108108

Correct answer: (C)

Step-by-step solution →
Q64·Mathematics·Sequence and SeriesSingle correct
Let aaa and bbb be two distinct positive real numbers. Let 11th11^{\text{th}}11th term of a GP, whose first term is aaa and third term is bbb, is equal to pthp^{\text{th}}pth term of another GP, whose first term is aaa and fifth term is bbb. Then ppp is equal to:
  1. (A)202020
  2. (B)252525
  3. (C)212121
  4. (D)242424

Correct answer: (C)

Step-by-step solution →
Q65·Mathematics·Straight LinesSingle correct
If x2−y2+2hxy+2gx+2fy+c=0x^2-y^2+2hxy+2gx+2fy+c=0x2−y2+2hxy+2gx+2fy+c=0 is the locus of a point, which moves such that it is always equidistant from the lines x+2y+7=0x+2y+7=0x+2y+7=0 and 2x−y+8=02x-y+8=02x−y+8=0, then the value of g+c+h−fg+c+h-fg+c+h−f equals:
  1. (A)141414
  2. (B)666
  3. (C)888
  4. (D)292929

Correct answer: (A)

Step-by-step solution →
Q66·Mathematics·Vector AlgebraSingle correct
Let a⃗\vec{a}a and b⃗\vec{b}b be two vectors such that ∣b⃗∣=1|\vec{b}|=1∣b∣=1 and ∣b⃗×a⃗∣=2|\vec{b}\times\vec{a}|=2∣b×a∣=2. Then ∣(b⃗×a⃗)−b⃗∣2\left|(\vec{b}\times\vec{a})-\vec{b}\right|^2​(b×a)−b​2 is equal to:
  1. (A)333
  2. (B)555
  3. (C)111
  4. (D)444

Correct answer: (B)

Step-by-step solution →
Q67·Mathematics·Definite IntegrationSingle correct
Let y=f(x)y=f(x)y=f(x) be a thrice differentiable function in (−5,5)(-5,5)(−5,5). Let the tangents to the curve y=f(x)y=f(x)y=f(x) at (1,f(1))(1,f(1))(1,f(1)) and (3,f(3))(3,f(3))(3,f(3)) make angles π6\dfrac{\pi}{6}6π​ and π4\dfrac{\pi}{4}4π​ respectively with positive x-axis. If 27∫13((f′(t))2+1)f′′(t) dt=α+β327\displaystyle\int_1^3\left((f'(t))^2+1\right)f''(t)\,dt=\alpha+\beta\sqrt{3}27∫13​((f′(t))2+1)f′′(t)dt=α+β3​ where α,β\alpha,\betaα,β are integers, then the value of α+β\alpha+\betaα+β equals:
  1. (A)−14-14−14
  2. (B)262626
  3. (C)−16-16−16
  4. (D)363636

Correct answer: (B)

Step-by-step solution →
Q68·Mathematics·HyperbolaSingle correct
Let PPP be a point on the hyperbola H:x29−y24=1H:\dfrac{x^2}{9}-\dfrac{y^2}{4}=1H:9x2​−4y2​=1, in the first quadrant such that the area of triangle formed by PPP and the two foci of HHH is 2132\sqrt{13}213​. Then, the square of the distance of PPP from the origin is:
  1. (A)181818
  2. (B)262626
  3. (C)222222
  4. (D)202020

Correct answer: (C)

Step-by-step solution →
Q69·Mathematics·Statistics and ProbabilitySingle correct
Bag A contains 3 white, 7 red balls and bag B contains 3 white, 2 red balls. One bag is selected at random and a ball is drawn from it. The probability of drawing the ball from bag A, if the ball drawn is white, is:
  1. (A)14\dfrac{1}{4}41​
  2. (B)19\dfrac{1}{9}91​
  3. (C)13\dfrac{1}{3}31​
  4. (D)310\dfrac{3}{10}103​

Correct answer: (C)

Step-by-step solution →
Q70·Mathematics·Definite IntegrationSingle correct
Let f:R→Rf:R\to Rf:R→R be defined f(x)=ae2x+bex+cxf(x)=ae^{2x}+be^{x}+cxf(x)=ae2x+bex+cx. If f(0)=−1f(0)=-1f(0)=−1, f′(log⁡e2)=21f'(\log_e 2)=21f′(loge​2)=21 and ∫0log⁡e4(f(x)−cx) dx=392\displaystyle\int_0^{\log_e 4}(f(x)-cx)\,dx=\dfrac{39}{2}∫0loge​4​(f(x)−cx)dx=239​, then the value of ∣a+b+c∣|a+b+c|∣a+b+c∣ equals:
  1. (A)161616
  2. (B)101010
  3. (C)121212
  4. (D)888

Correct answer: (D)

Step-by-step solution →
Q71·Mathematics·Three Dimensional GeometrySingle correct
Let L1:r⃗=(i^−j^+2k^)+λ(i^−j^+2k^)L_1:\vec{r}=(\hat{i}-\hat{j}+2\hat{k})+\lambda(\hat{i}-\hat{j}+2\hat{k})L1​:r=(i^−j^​+2k^)+λ(i^−j^​+2k^), λ∈R\lambda\in Rλ∈R; L2:r⃗=(j^−k^)+μ(3i^+j^+pk^)L_2:\vec{r}=(\hat{j}-\hat{k})+\mu(3\hat{i}+\hat{j}+p\hat{k})L2​:r=(j^​−k^)+μ(3i^+j^​+pk^), μ∈R\mu\in Rμ∈R and L3:r⃗=δ(ℓi^+mj^+nk^)L_3:\vec{r}=\delta(\ell\hat{i}+m\hat{j}+n\hat{k})L3​:r=δ(ℓi^+mj^​+nk^), δ∈R\delta\in Rδ∈R be three lines such that L1L_1L1​ is perpendicular to L2L_2L2​ and L3L_3L3​ is perpendicular to both L1L_1L1​ and L2L_2L2​. Then the point which lies on L3L_3L3​ is:
  1. (A)(−1,7,4)(-1,7,4)(−1,7,4)
  2. (B)(−1,−7,4)(-1,-7,4)(−1,−7,4)
  3. (C)(1,7,−4)(1,7,-4)(1,7,−4)
  4. (D)(1,−7,4)(1,-7,4)(1,−7,4)

Correct answer: (A)

Step-by-step solution →
Q72·Mathematics·DifferentiabilitySingle correct
Let aaa and bbb be real constants such that the function fff defined by f(x)={x2+3x+a,x≤1bx+2,x>1f(x)=\begin{cases}x^2+3x+a, & x\le 1\\ bx+2, & x>1\end{cases}f(x)={x2+3x+a,bx+2,​x≤1x>1​ be differentiable on RRR. Then the value of ∫−22f(x) dx\displaystyle\int_{-2}^{2}f(x)\,dx∫−22​f(x)dx equals:
  1. (A)156\dfrac{15}{6}615​
  2. (B)196\dfrac{19}{6}619​
  3. (C)212121
  4. (D)171717

Correct answer: (D)

Step-by-step solution →
Q73·Mathematics·Limits and ContinuitySingle correct
Let f:R−{0}→Rf:R-\{0\}\to Rf:R−{0}→R be a function satisfying f(xy)=f(x)f(y)f\left(\dfrac{x}{y}\right)=\dfrac{f(x)}{f(y)}f(yx​)=f(y)f(x)​ for all x,yx,yx,y, f(y)≠0f(y)\ne 0f(y)=0. If f′(1)=2024f'(1)=2024f′(1)=2024, then:
  1. (A)xf′(x)−2024f(x)=0xf'(x)-2024f(x)=0xf′(x)−2024f(x)=0
  2. (B)xf′(x)+2024f(x)=0xf'(x)+2024f(x)=0xf′(x)+2024f(x)=0
  3. (C)xf′(x)+f(x)=2024xf'(x)+f(x)=2024xf′(x)+f(x)=2024
  4. (D)xf′(x)−2023f(x)=0xf'(x)-2023f(x)=0xf′(x)−2023f(x)=0

Correct answer: (A)

Step-by-step solution →
Q74·Mathematics·Complex NumbersSingle correct
If zzz is a complex number, then the number of common roots of the equation z1985+z100+1=0z^{1985}+z^{100}+1=0z1985+z100+1=0 and z3+2z2+2z+1=0z^3+2z^2+2z+1=0z3+2z2+2z+1=0, is equal to:
  1. (A)111
  2. (B)222
  3. (C)000
  4. (D)333

Correct answer: (B)

Step-by-step solution →
Q75·Mathematics·Sets, Relations and FunctionsSingle correct
If the domain of the function f(x)=log⁡e(2x+34x2+x−3)+cos⁡−1(2x−1x+2)f(x)=\log_e\left(\dfrac{2x+3}{4x^2+x-3}\right)+\cos^{-1}\left(\dfrac{2x-1}{x+2}\right)f(x)=loge​(4x2+x−32x+3​)+cos−1(x+22x−1​) is (α,β](\alpha,\beta](α,β], then the value of 5β−4α5\beta-4\alpha5β−4α is equal to:
  1. (A)101010
  2. (B)121212
  3. (C)111111
  4. (D)999

Correct answer: (B)

Step-by-step solution →
Q76·Mathematics·Definite IntegrationSingle correct
Let f:R→Rf:R\to Rf:R→R be a function defined f(x)=x(1+x4)1/4f(x)=\dfrac{x}{(1+x^4)^{1/4}}f(x)=(1+x4)1/4x​ and g(x)=f(f(f(f(x))))g(x)=f(f(f(f(x))))g(x)=f(f(f(f(x)))) then 18∫025x2 g(x) dx18\displaystyle\int_0^{\sqrt{2\sqrt{5}}}x^2\,g(x)\,dx18∫025​​​x2g(x)dx
  1. (A)333333
  2. (B)363636
  3. (C)424242
  4. (D)393939

Correct answer: (D)

Step-by-step solution →
Q77·Mathematics·Matrices and DeterminantsSingle correct
Let R=[x000y000z]R=\begin{bmatrix}x&0&0\\0&y&0\\0&0&z\end{bmatrix}R=​x00​0y0​00z​​ be a non-zero 3×33\times 33×3 matrix, where xsin⁡θ=ysin⁡(θ+2π3)=zsin⁡(θ+4π3)≠0x\sin\theta=y\sin\left(\theta+\dfrac{2\pi}{3}\right)=z\sin\left(\theta+\dfrac{4\pi}{3}\right)\ne 0xsinθ=ysin(θ+32π​)=zsin(θ+34π​)=0, θ∈(0,2π)\theta\in(0,2\pi)θ∈(0,2π). For a square matrix MMM, let trace(M)(M)(M) denote the sum of all the diagonal entries of MMM. Then, among the statements: (I) Trace(R)=0(R)=0(R)=0 (II) If trace(adj(adj(R)))=0(\text{adj}(\text{adj}(R)))=0(adj(adj(R)))=0, then RRR has exactly one non-zero entry.
  1. (A)Both (I) and (II) are true
  2. (B)Neither (I) nor (II) is true
  3. (C)Only (II) is true
  4. (D)Only (I) is true

Correct answer: (B)

Step-by-step solution →
Q78·Mathematics·Differential EquationsNumerical
Let Y=Y(X)Y=Y(X)Y=Y(X) be a curve lying in the first quadrant such that the area enclosed by the line Y−y=Y′(x)(X−x)Y-y=Y'(x)(X-x)Y−y=Y′(x)(X−x) and the co-ordinate axes, where (x,y)(x,y)(x,y) is any point on the curve, is always −y22Y′(x)+1\dfrac{-y^2}{2Y'(x)}+12Y′(x)−y2​+1, Y′(x)≠0Y'(x)\ne 0Y′(x)=0. If Y(1)=1Y(1)=1Y(1)=1, then 12 Y(2)12\,Y(2)12Y(2) equals ______.

Correct answer: 20

Step-by-step solution →
Q79·Mathematics·Three Dimensional GeometryNumerical
Let a line passing through the point (−1,2,3)(-1,2,3)(−1,2,3) intersect the lines L1:x−13=y−22=z+1−2L_1:\dfrac{x-1}{3}=\dfrac{y-2}{2}=\dfrac{z+1}{-2}L1​:3x−1​=2y−2​=−2z+1​ at M(α,β,γ)M(\alpha,\beta,\gamma)M(α,β,γ) and L2:x+2−3=y−2−2=z−14L_2:\dfrac{x+2}{-3}=\dfrac{y-2}{-2}=\dfrac{z-1}{4}L2​:−3x+2​=−2y−2​=4z−1​ at N(a,b,c)N(a,b,c)N(a,b,c). Then the value of (α+β+γ)2(a+b+c)2\dfrac{(\alpha+\beta+\gamma)^2}{(a+b+c)^2}(a+b+c)2(α+β+γ)2​ equals ______.

Correct answer: 196

Step-by-step solution →
Q80·Mathematics·CirclesNumerical
Consider two circles C1:x2+y2=25C_1:x^2+y^2=25C1​:x2+y2=25 and C2:(x−α)2+y2=16C_2:(x-\alpha)^2+y^2=16C2​:(x−α)2+y2=16. Let the angle between the two radii (one to each circle) drawn from one of the intersection points of C1C_1C1​ and C2C_2C2​ be sin⁡−1(638)\sin^{-1}\left(\dfrac{\sqrt{63}}{8}\right)sin−1(863​​). If the length of common chord of C1C_1C1​ and C2C_2C2​ is β\betaβ, then the value of (αβ)2(\alpha\beta)^2(αβ)2 equals ______.

Correct answer: 1575

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Q81·Mathematics·Binomial Theorem and Its Simple ApplicationsNumerical
Let α=∑k=0n(nCk)2k+1\alpha=\displaystyle\sum_{k=0}^{n}\dfrac{\left({}^nC_k\right)^2}{k+1}α=k=0∑n​k+1(nCk​)2​ and β=∑k=0n−1nCk nCk+1k+2\beta=\displaystyle\sum_{k=0}^{n-1}\dfrac{{}^nC_k\,{}^nC_{k+1}}{k+2}β=k=0∑n−1​k+2nCk​nCk+1​​. If 5α=6β5\alpha=6\beta5α=6β, then nnn equals ______.

Correct answer: 10

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Q82·Mathematics·Sequence and SeriesNumerical
Let SnS_nSn​ be the sum to nnn-terms of an arithmetic progression 3,7,11,…3,7,11,\ldots3,7,11,…. If 40<6n(n+1)∑k=1nSk<4240<\dfrac{6}{n(n+1)}\displaystyle\sum_{k=1}^{n}S_k<4240<n(n+1)6​k=1∑n​Sk​<42, then nnn equals ______.

Correct answer: 9

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Q83·Mathematics·Permutations and CombinationsNumerical
In an examination of Mathematics paper, there are 20 questions of equal marks and the question paper is divided into three sections : A, B and C. A student is required to attempt total 15 questions taking at least 4 questions from each section. If section A has 8 questions, section B has 6 questions and section C has 6 questions, then the total number of ways a student can select 15 questions is ______.

Correct answer: 11376

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Q84·Mathematics·Sets, Relations and FunctionsNumerical
The number of symmetric relations defined on the set {1,2,3,4}\{1,2,3,4\}{1,2,3,4} which are not reflexive is ______.

Correct answer: 960

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Q85·Mathematics·Quadratic EquationsNumerical
The number of real solutions of the equation x(x2+3∣x∣+5∣x−1∣+6∣x−2∣)=0x\left(x^2+3|x|+5|x-1|+6|x-2|\right)=0x(x2+3∣x∣+5∣x−1∣+6∣x−2∣)=0 is ______.

Correct answer: 1

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Q86·Mathematics·Area Under CurvesNumerical
The area of the region enclosed by the parabola (y−2)2=x−1(y-2)^2=x-1(y−2)2=x−1, the line x−2y+4=0x-2y+4=0x−2y+4=0 and the positive coordinate axes is ______.

Correct answer: 5

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Q87·Mathematics·Statistics and ProbabilityNumerical
The variance σ2\sigma^2σ2 of the data | xix_ixi​ | 0 | 1 | 5 | 6 | 10 | 12 | 17 | |---|---|---|---|---|---|---|---| | fif_ifi​ | 3 | 2 | 3 | 2 | 6 | 3 | 3 | is ______.

Correct answer: 29

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Chapters tested in this paper

Open any chapter to practise every past-year question on that topic across all papers, and see how often it has actually appeared.

  • Properties of Solids and Liquids 172/186
  • Three Dimensional Geometry 176/186
  • Matrices and Determinants 180/186
  • Coordination Compounds 176/186
  • Sets, Relations and Functions 165/186
  • Current Electricity 160/186
  • Sequence and Series 164/186
  • p-Block Elements 164/186
  • Definite Integration 168/186
  • Rotational Motion 172/186
  • Redox Reactions and Electrochemistry 177/186
  • Geometrical Optics 172/186
  • Kinematics 156/186
  • Vector Algebra 173/186
  • Differential Equations 167/186
  • Probability 176/186
  • Permutations and Combinations 162/186
  • Magnetic Field of Current 147/186
  • Binomial Theorem and Its Simple Applications 158/186
  • Electromagnetic Waves 144/186
  • Chemical Bonding and Molecular Structure 151/186
  • Application of Derivatives 139/186
  • Limits and Continuity 149/186
  • d- and f-Block Elements 126/186
  • Thermodynamics 154/186
  • Aldehydes and Ketones 135/186
  • Equilibrium 163/186
  • Solutions 158/186
  • Laws of Motion 130/186
  • Chemical Thermodynamics 165/186
  • Units and Measurements 149/186
  • Complex Numbers 165/186
  • Trigonometric Functions 144/186
  • Biomolecules 162/186
  • Chemical Kinetics 169/186
  • Gravitation 152/186
  • Electric Field and Coulomb's Law 133/186
  • Atomic Structure 161/186
  • Electronic Devices 145/186
  • Circles 142/186
  • Dual Nature of Matter and Radiation 155/186
  • Amines 133/186
  • Quadratic Equations 148/186
  • Work, Energy and Power 132/186
  • Some Basic Concepts in Chemistry 129/186
  • Wave Optics 130/186
  • Area Under Curves 139/186
  • Kinetic Theory of Gases 135/186
  • Alcohols and Ethers 106/186
  • Purification and Characterisation of Organic Compounds 116/186
  • Alternating Currents 108/186
  • Nuclei 116/186
  • Organic Compounds Containing Halogens 109/186
  • Straight Lines 114/186
  • Capacitors and Dielectrics 115/186
  • Atoms 112/186
  • Classification of Elements and Periodicity in Properties 113/186
  • Statistics 118/186
  • Ellipse 103/186
  • Differentiability 91/186
  • s-Block Elements 88/186
  • Electronic Effects and Stability 74/186
  • Hyperbola 77/186
  • Experimental Skills 68/186
  • Isomerism 51/186
  • IUPAC Nomenclature 37/186
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