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JEE Main 5 April 2024 Shift 1 Question Paper with Answers

5 April 2024 · April session · 90 questions

The complete JEE Main 5 April 2024 Shift 1 paper — all 90 questions with the correct answer for each, tagged to the chapter it tests. Free to read, no account needed.

Physics
30
Chemistry
30
Mathematics
30

Physics — JEE Main 5 April 2024 Shift 1

Q1·PhysicsSingle correct
Light emerges out of a convex lens when a source of light is kept at its focus. The shape of wavefront of the light is:
  1. (A)Both spherical and cylindrical
  2. (B)Cylindrical
  3. (C)Spherical
  4. (D)Plane

Correct answer: (D)

Step-by-step solution →
Q2·PhysicsSingle correct
A combination of logic gates is connected in a complete suitable circuit (shown in the figure). For which of the following input combinations will the bulb glow (ON)?
  1. (A)A = 0, B = 1, C = 1, D = 1
  2. (B)A = 1, B = 0, C = 0, D = 0
  3. (C)A = 0, B = 0, C = 0, D = 1
  4. (D)A = 1, B = 1, C = 1, D = 0

Correct answer: (B)

Step-by-step solution →
Q3·PhysicsSingle correct
If G is the gravitational constant and uuu is the energy density then which of the following quantity has the same dimensions as uG\sqrt{uG}uG​:
  1. (A)Pressure gradient per unit mass
  2. (B)Force per unit mass
  3. (C)Gravitational potential
  4. (D)Energy per unit mass

Correct answer: (B)

Step-by-step solution →
Q4·PhysicsSingle correct
Given below are two statements: Statement-I: When a capillary tube is dipped into a liquid, the liquid neither rises nor falls in the capillary. The contact angle may be 90∘90^{\circ}90∘. Statement-II: The contact angle between a solid and a liquid is a property of the material of the solid and liquid as well. In the light of the above statements, choose the correct answer from the options given below.
  1. (A)Statement-I is false and Statement-II is true.
  2. (B)Both Statement-I and Statement-II are true.
  3. (C)Both Statement-I and Statement-II are false.
  4. (D)Statement-I is true and Statement-II is false.

Correct answer: (A)

Step-by-step solution →
Q5·PhysicsSingle correct
Given below are two statements: Statement-I: The figure shows the variation of stopping potential with frequency (ν\nuν) for two photosensitive materials M1M_1M1​ and M2M_2M2​. The slope gives the value of he\dfrac{h}{e}eh​, where hhh is Planck’s constant and eee is the charge of the electron. Statement-II: M2M_2M2​ will emit photoelectrons of greater kinetic energy for incident radiation having the same frequency. In the light of the above statements, choose the most appropriate answer from the options given below.
  1. (A)Statement-I is correct and Statement-II is incorrect.
  2. (B)Statement-I is incorrect but Statement-II is correct.
  3. (C)Both Statement-I and Statement-II are incorrect.
  4. (D)Both Statement-I and Statement-II are correct.

Correct answer: (A)

Step-by-step solution →
Q6·PhysicsSingle correct
The angle between vector Q⃗\vec{Q}Q​ and the resultant of (2Q⃗+2P⃗)(2\vec{Q}+2\vec{P})(2Q​+2P) and (2Q⃗−2P⃗)(2\vec{Q}-2\vec{P})(2Q​−2P) is:
  1. (A)0∘0^{\circ}0∘
  2. (B)tan⁡−1(2Q⃗−2P⃗2Q⃗+2P⃗)\tan^{-1}\left(\dfrac{2\vec{Q}-2\vec{P}}{2\vec{Q}+2\vec{P}}\right)tan−1(2Q​+2P2Q​−2P​)
  3. (C)tan⁡−1(PQ)\tan^{-1}\left(\dfrac{P}{Q}\right)tan−1(QP​)
  4. (D)tan⁡−1(2QP)\tan^{-1}\left(\dfrac{2Q}{P}\right)tan−1(P2Q​)

Correct answer: (A)

Step-by-step solution →
Q7·PhysicsSingle correct
In a hydrogen-like system the ratio of the Coulomb force and the gravitational force between an electron and a proton is of the order of:
  1. (A)103910^{39}1039
  2. (B)101910^{19}1019
  3. (C)102910^{29}1029
  4. (D)103610^{36}1036

Correct answer: (A)

Step-by-step solution →
Q8·PhysicsSingle correct
In a coaxial straight cable, the central conductor and the outer conductor carry equal currents in opposite directions. The magnetic field is zero:
  1. (A)inside the outer conductor
  2. (B)in between the two conductors
  3. (C)outside the cable
  4. (D)inside the inner conductor

Correct answer: (C)

Step-by-step solution →
Q9·PhysicsSingle correct
An electron rotates in a circle around a nucleus having positive charge ZeZeZe. The correct relation between the total energy (E) of the electron and its potential energy (U) is:
  1. (A)E=2UE = 2UE=2U
  2. (B)2E=3U2E = 3U2E=3U
  3. (C)E=UE = UE=U
  4. (D)2E=U2E = U2E=U

Correct answer: (D)

Step-by-step solution →
Q10·PhysicsSingle correct
If the collision frequency of hydrogen molecules in a closed chamber at 27∘C27^{\circ}\text{C}27∘C is ZZZ, then the collision frequency of the same system at 127∘C127^{\circ}\text{C}127∘C is:
  1. (A)32Z\dfrac{\sqrt{3}}{2}Z23​​Z
  2. (B)43Z\dfrac{4}{3}Z34​Z
  3. (C)23Z\dfrac{2}{\sqrt{3}}Z3​2​Z
  4. (D)34Z\dfrac{3}{4}Z43​Z

Correct answer: (C)

Step-by-step solution →
Q11·PhysicsSingle correct
The ratio of the radius of gyration of a hollow sphere to that of a solid cylinder of equal mass, for the moment of inertia about their diameter axis AB as shown in the figure, is 8x\sqrt{\dfrac{8}{x}}x8​​. The value of xxx is:
  1. (A)34
  2. (B)17
  3. (C)67
  4. (D)51

Correct answer: (C)

Step-by-step solution →
Q12·PhysicsSingle correct
Two conducting circular loops A and B are placed in the same plane with their centres coinciding as shown in the figure (radius of A is aaa, radius of B is bbb, with b≫ab \gg ab≫a). The mutual inductance between them is:
  1. (A)μ0πa22b\dfrac{\mu_0\pi a^2}{2b}2bμ0​πa2​
  2. (B)μ02πb2a\dfrac{\mu_0}{2\pi}\dfrac{b^2}{a}2πμ0​​ab2​
  3. (C)μ0πb22a\dfrac{\mu_0\pi b^2}{2a}2aμ0​πb2​
  4. (D)μ02πa2b\dfrac{\mu_0}{2\pi}\dfrac{a^2}{b}2πμ0​​ba2​

Correct answer: (A)

Step-by-step solution →
Q13·PhysicsSingle correct
Match List-I (energies of a planet of mass mmm in a circular orbit of radius aaa around the Sun of mass MMM; rrr = radius of the planet) with List-II (their expressions). Choose the correct answer from the options given below.
List-IList-II
A.Kinetic energy of planetI.GMma\dfrac{GMm}{a}aGMm​
B.Gravitational potential energy of Sun–planet systemII.GMm2a\dfrac{GMm}{2a}2aGMm​
C.Total mechanical energy of planetIII.−GMma-\dfrac{GMm}{a}−aGMm​
D.Escape energy at the surface of planet for a unit-mass objectIV.Gmr\dfrac{Gm}{r}rGm​
  1. (A)(A)–II, (B)–I, (C)–IV, (D)–III
  2. (B)(A)–III, (B)–IV, (C)–I, (D)–II
  3. (C)(A)–I, (B)–IV, (C)–II, (D)–III
  4. (D)(A)–I, (B)–II, (C)–III, (D)–IV

Correct answer: (A)

Step-by-step solution →
Q14·PhysicsSingle correct
A wooden block of mass 5 kg rests on a soft horizontal floor. When an iron cylinder of mass 25 kg is placed on top of the block, the floor yields and the block and cylinder together go down with an acceleration of 0.1 ms−20.1\ \text{ms}^{-2}0.1 ms−2. The action force of the system on the floor is equal to:
  1. (A)297 N
  2. (B)294 N
  3. (C)291 N
  4. (D)196 N

Correct answer: (C)

Step-by-step solution →
Q15·PhysicsSingle correct
A simple pendulum doing small oscillations at a place at height R above the earth’s surface has time period T1=4T_1 = 4T1​=4 s. T2T_2T2​ would be its time period if it is brought to a point at height 2R from the earth’s surface. Choose the correct relation [R = radius of Earth]:
  1. (A)T1=T2T_1 = T_2T1​=T2​
  2. (B)2T1=3T22T_1 = 3T_22T1​=3T2​
  3. (C)3T1=2T23T_1 = 2T_23T1​=2T2​
  4. (D)2T1=T22T_1 = T_22T1​=T2​

Correct answer: (C)

Step-by-step solution →
Q16·PhysicsSingle correct
A body of mass 50 kg is lifted to a height of 20 m from the ground in two different ways as shown in the figures. The ratio of the work done against gravity in the two respective cases will be:
  1. (A)1 : 1
  2. (B)2 : 1
  3. (C)3:2\sqrt{3}:23​:2
  4. (D)1 : 2

Correct answer: (A)

Step-by-step solution →
Q17·PhysicsSingle correct
Time periods of oscillation of the same simple pendulum measured using four different measuring clocks were recorded as 4.62 s, 4.632 s, 4.6 s and 4.64 s. The arithmetic mean of these readings to the correct significant figures is:
  1. (A)4.623 s
  2. (B)4.62 s
  3. (C)4.6 s
  4. (D)5 s

Correct answer: (C)

Step-by-step solution →
Q18·PhysicsSingle correct
The heat absorbed by a system in going through the given cyclic process is:
  1. (A)61.6 J
  2. (B)431.2 J
  3. (C)616 J
  4. (D)19.6 J

Correct answer: (A)

Step-by-step solution →
Q19·PhysicsSingle correct
In the given figure R1=10 ΩR_1 = 10\ \OmegaR1​=10 Ω, R2=8 ΩR_2 = 8\ \OmegaR2​=8 Ω, R3=4 ΩR_3 = 4\ \OmegaR3​=4 Ω and R4=8 ΩR_4 = 8\ \OmegaR4​=8 Ω. The battery is ideal with emf 12 V. The equivalent resistance of the circuit and the current supplied by the battery are respectively:
  1. (A)12 Ω12\ \Omega12 Ω and 11.4 A11.4\ \text{A}11.4 A
  2. (B)10.5 Ω10.5\ \Omega10.5 Ω and 1.14 A1.14\ \text{A}1.14 A
  3. (C)10.5 Ω10.5\ \Omega10.5 Ω and 1 A1\ \text{A}1 A
  4. (D)12 Ω12\ \Omega12 Ω and 1 A1\ \text{A}1 A

Correct answer: (D)

Step-by-step solution →
Q20·PhysicsSingle correct
An alternating voltage of amplitude 40 V and frequency 4 kHz is applied directly across a capacitor of 12 μF12\ \mu\text{F}12 μF. The maximum displacement current between the plates of the capacitor is nearly:
  1. (A)13 A
  2. (B)8 A
  3. (C)10 A
  4. (D)12 A

Correct answer: (D)

Step-by-step solution →
Q21·PhysicsNumerical
In Young’s double slit experiment, carried out with light of wavelength 5000 A˚5000\ \text{Å}5000 A˚, the distance between the slits is 0.3 mm and the screen is at 200 cm from the slits. The central maximum is at x=0x = 0x=0 cm. The value of xxx for the third maximum is ___ mm.

Correct answer: 10

Step-by-step solution →
Q22·PhysicsNumerical
A 2 A current-carrying straight metal wire of resistance 1 Ω1\ \Omega1 Ω, resistivity 2×10−6 Ω m2\times10^{-6}\ \Omega\,\text{m}2×10−6 Ωm, area of cross-section 10 mm210\ \text{mm}^210 mm2 and mass 500 g is suspended horizontally in mid air by applying a uniform magnetic field B⃗\vec{B}B. The magnitude of B is ___ ×10−1\times10^{-1}×10−1 T (given g=10 m/s2g = 10\ \text{m/s}^2g=10 m/s2).

Correct answer: 5

Step-by-step solution →
Q23·PhysicsNumerical
The electric field between the two parallel plates of a capacitor of 1.5 μF1.5\ \mu\text{F}1.5 μF capacitance drops to one third of its initial value in 6.6 μs6.6\ \mu\text{s}6.6 μs when the plates are connected by a thin wire. The resistance of this wire is ___ Ω\OmegaΩ. (Given log⁡3=1.1\log 3 = 1.1log3=1.1.)

Correct answer: 4

Step-by-step solution →
Q24·PhysicsNumerical
Three blocks M1M_1M1​, M2M_2M2​, M3M_3M3​ of masses 4 kg, 6 kg and 10 kg respectively hang from a smooth pulley using ropes 1, 2 and 3 in succession (rope 1 at the top carries all three, rope 2 carries M2M_2M2​ and M3M_3M3​, rope 3 carries M3M_3M3​). The tension T1T_1T1​ in rope 1 when they move upward with acceleration 2 ms−22\ \text{ms}^{-2}2 ms−2 is ___ N (with g=10 m/s2g = 10\ \text{m/s}^2g=10 m/s2).

Correct answer: 240

Step-by-step solution →
Q25·PhysicsNumerical
The density and breaking stress of a wire are 6×104 kg/m36\times10^4\ \text{kg/m}^36×104 kg/m3 and 1.2×108 N/m21.2\times10^8\ \text{N/m}^21.2×108 N/m2 respectively. The wire is suspended from a rigid support on a planet where the acceleration due to gravity is 13\dfrac{1}{3}31​ of the value on the surface of earth. The maximum length of the wire without breaking is ___ m (take g=10 m/s2g = 10\ \text{m/s}^2g=10 m/s2).

Correct answer: 600

Step-by-step solution →
Q26·PhysicsNumerical
A body moves on a frictionless plane starting from rest. If SnS_nSn​ is the distance moved between t=n−1t = n-1t=n−1 and t=nt = nt=n and Sn−1S_{n-1}Sn−1​ is the distance moved between t=n−2t = n-2t=n−2 and t=n−1t = n-1t=n−1, then the ratio Sn−1Sn\dfrac{S_{n-1}}{S_n}Sn​Sn−1​​ is (1−2x)\left(1-\dfrac{2}{x}\right)(1−x2​) for n=10n = 10n=10. The value of xxx is ___.

Correct answer: 19

Step-by-step solution →
Q27·PhysicsNumerical
If three helium nuclei combine to form a carbon nucleus, then the energy released in this reaction is ___ ×10−2\times10^{-2}×10−2 MeV. (Given 1 u=931 MeV/c21\ \text{u} = 931\ \text{MeV}/c^21 u=931 MeV/c2; atomic mass of helium = 4.002603 u; mass of carbon-12 = 12 u.)

Correct answer: 727

Step-by-step solution →
Q28·PhysicsNumerical
An ac source V=502sin⁡(100t)V = 50\sqrt{2}\sin(100t)V=502​sin(100t) V is connected in a series LCR circuit with L=1L = 1L=1 H, R=300 ΩR = 300\ \OmegaR=300 Ω and C=20 μFC = 20\ \mu\text{F}C=20 μF. The rms potential difference across the capacitor is ___ V.

Correct answer: 50

Step-by-step solution →
Q29·PhysicsNumerical
In the experiment to determine the galvanometer resistance by the half-deflection method, the plot of 1θ\dfrac{1}{\theta}θ1​ versus the resistance R of the resistance box is shown in the figure. The figure of merit of the galvanometer is ___ ×10−1\times10^{-1}×10−1 A/division. [The source has emf 2 V.]

Correct answer: 5

Step-by-step solution →
Q30·PhysicsNumerical
Three capacitors of capacitances 25 μF25\ \mu\text{F}25 μF, 30 μF30\ \mu\text{F}30 μF and 45 μF45\ \mu\text{F}45 μF are connected in parallel to a supply of 100 V. The energy stored in this combination is E. When these capacitors are connected in series to the same supply, the stored energy is 9xE\dfrac{9}{x}Ex9​E. The value of xxx is ___.

Correct answer: 86

Step-by-step solution →

Chemistry — JEE Main 5 April 2024 Shift 1

Q31·ChemistrySingle correct
The incorrect postulates of Dalton's atomic theory are: (A) Atoms of different elements differ in mass. (B) Matter consists of divisible atoms. (C) Compounds are formed when atoms of different elements combine in a fixed ratio. (D) All the atoms of a given element have different properties including mass. (E) Chemical reactions involve reorganisation of atoms. Choose the correct answer from the options given below:
  1. (A)(B), (D), (E) only
  2. (B)(A), (B), (D) only
  3. (C)(C), (D), (E) only
  4. (D)(B), (D) only

Correct answer: (D)

Step-by-step solution →
Q32·ChemistrySingle correct
The following reaction occurs in the blast furnace where iron ore is reduced to iron metal: Fe2O3(s)+3CO(g)→2Fe(l)+3CO2(g)\text{Fe}_2\text{O}_3(s) + 3\text{CO}(g) \rightarrow 2\text{Fe}(l) + 3\text{CO}_2(g)Fe2​O3​(s)+3CO(g)→2Fe(l)+3CO2​(g). Using Le Chatelier’s principle, predict which one of the following will not disturb the equilibrium.
  1. (A)Addition of Fe2O3\text{Fe}_2\text{O}_3Fe2​O3​
  2. (B)Addition of CO2\text{CO}_2CO2​
  3. (C)Removal of CO
  4. (D)Removal of CO2\text{CO}_2CO2​

Correct answer: (A)

Step-by-step solution →
Q33·ChemistrySingle correct
Identify compound (Z) in the following reaction sequence (shown in the figure).
  1. (A)(B), (D), (E) only
  2. (B)(A), (B), (D) only
  3. (C)(C), (D), (E) only
  4. (D)All the atoms of given element have different

Correct answer: (C)

Step-by-step solution →
Q34·ChemistrySingle correct
Given below are two statements: Assertion (A): Enthalpy of neutralisation of a strong monobasic acid with a strong monoacidic base is always −57-57−57 kJ mol−1^{-1}−1. Reason (R): Enthalpy of neutralisation is the amount of heat liberated when one mole of H+\text{H}^+H+ ions furnished by the acid combine with one mole of OH−\text{OH}^-OH− ions furnished by the base to form one mole of water. In the light of the above statements, choose the correct answer from the options given below.
  1. (A)(A) is true but (R) is false
  2. (B)Both (A) and (R) are true and (R) is the correct explanation of (A)
  3. (C)(A) is false but (R) is true
  4. (D)Both (A) and (R) are true but (R) is not the correct explanation of (A)

Correct answer: (B)

Step-by-step solution →
Q35·ChemistrySingle correct
The statement(s) that are correct about the species O2−\text{O}^{2-}O2−, F−\text{F}^-F−, Na+\text{Na}^+Na+ and Mg2+\text{Mg}^{2+}Mg2+: (A) All are isoelectronic. (B) All have the same nuclear charge. (C) O2−\text{O}^{2-}O2− has the largest ionic radius. (D) Mg2+\text{Mg}^{2+}Mg2+ has the smallest ionic radius. Choose the most appropriate answer from the options given below:
  1. (A)(B), (C) and (D) only
  2. (B)(A), (B), (C) and (D)
  3. (C)(C) and (D) only
  4. (D)(A), (C) and (D) only

Correct answer: (D)

Step-by-step solution →
Q36·Chemistry·Alcohols and EthersSingle correct
For the compounds: (A) H3C-CH2-O-CH2-CH2-CH3\text{H}_3\text{C-CH}_2\text{-O-CH}_2\text{-CH}_2\text{-CH}_3H3​C-CH2​-O-CH2​-CH2​-CH3​, (B) H3C-CH2-CH2-CH2-CH2-CH3\text{H}_3\text{C-CH}_2\text{-CH}_2\text{-CH}_2\text{-CH}_2\text{-CH}_3H3​C-CH2​-CH2​-CH2​-CH2​-CH3​, (C) CH3-CH2-CO-CH2-CH3\text{CH}_3\text{-CH}_2\text{-CO-CH}_2\text{-CH}_3CH3​-CH2​-CO-CH2​-CH3​, (D) H3C-CH(OH)-CH2-CH2-CH3\text{H}_3\text{C-CH(OH)-CH}_2\text{-CH}_2\text{-CH}_3H3​C-CH(OH)-CH2​-CH2​-CH3​, the increasing order of boiling point is: Choose the correct answer from the options given below:
  1. (A)(A) < (B) < (C) < (D)
  2. (B)(B) < (A) < (C) < (D)
  3. (C)(D) < (C) < (A) < (B)
  4. (D)(B) < (A) < (D) < (C)

Correct answer: (B)

Step-by-step solution →
Q37·ChemistrySingle correct
Given below are two statements: Statement I: In group 13, the stability of the +1 oxidation state increases down the group. Statement II: The atomic size of gallium is greater than that of aluminium. In the light of the above statements, choose the most appropriate answer from the options given below:
  1. (A)Statement I is incorrect but Statement II is correct
  2. (B)Both Statement I and Statement II are correct
  3. (C)Both Statement I and Statement II are incorrect
  4. (D)Statement I is correct but Statement II is incorrect

Correct answer: (D)

Step-by-step solution →
Q38·ChemistrySingle correct
The number of σ\sigmaσ and π\piπ bonds present in an ethylene molecule is respectively:
  1. (A)3 and 1
  2. (B)5 and 2
  3. (C)4 and 1
  4. (D)5 and 1

Correct answer: (D)

Step-by-step solution →
Q39·ChemistrySingle correct
Identify 'A' in the following reaction (shown in the figure).
  1. (A)(1)
  2. (B)(2)
  3. (C)(3)
  4. (D)(4)

Correct answer: (B)

Step-by-step solution →
Q40·ChemistrySingle correct
The reaction at the cathode in the cells commonly used in clocks involves:
  1. (A)reduction of Mn from +4 to +3
  2. (B)oxidation of Mn from +3 to +4
  3. (C)reduction of Mn from +7 to +2
  4. (D)oxidation of Mn from +7 to +2

Correct answer: (A)

Step-by-step solution →
Q41·ChemistrySingle correct
Which one of the following complexes will exhibit the least paramagnetic behaviour? [Atomic numbers: Cr = 24, Mn = 25, Fe = 26, Co = 27]
  1. (A)[Co(H2O)6]2+[\text{Co(H}_2\text{O})_6]^{2+}[Co(H2​O)6​]2+
  2. (B)[Fe(H2O)6]2+[\text{Fe(H}_2\text{O})_6]^{2+}[Fe(H2​O)6​]2+
  3. (C)[Mn(H2O)6]2+[\text{Mn(H}_2\text{O})_6]^{2+}[Mn(H2​O)6​]2+
  4. (D)[Cr(H2O)6]2+[\text{Cr(H}_2\text{O})_6]^{2+}[Cr(H2​O)6​]2+

Correct answer: (A)

Step-by-step solution →
Q42·ChemistrySingle correct
Given below are two statements: Assertion (A): The cis form of an alkene is found to be more polar than the trans form. Reason (R): The dipole moment of the trans isomer of 2-butene is zero. In the light of the above statements, choose the correct answer from the options given below:
  1. (A)Both (A) and (R) are true but (R) is not the correct explanation of (A)
  2. (B)(A) is true but (R) is false
  3. (C)Both (A) and (R) are true and (R) is the correct explanation of (A)
  4. (D)(A) is false but (R) is true

Correct answer: (C)

Step-by-step solution →
Q43·ChemistrySingle correct
Given below are two statements: Statement I: Nitration of benzene involves the following step: H-O-NO2→H2O+NO2+\text{H-O-NO}_2 \rightarrow \text{H}_2\text{O} + \text{NO}_2^+H-O-NO2​→H2​O+NO2+​. Statement II: Use of a Lewis base promotes the electrophilic substitution of benzene. In the light of the above statements, choose the most appropriate answer from the options given below:
  1. (A)Both Statement I and Statement II are incorrect
  2. (B)Statement I is correct but Statement II is incorrect
  3. (C)Both Statement I and Statement II are correct
  4. (D)Statement I is incorrect but Statement II is correct

Correct answer: (B)

Step-by-step solution →
Q44·ChemistrySingle correct
The correct order of ligands arranged in increasing field strength is:
  1. (A)Cl−<−OH<Br−<CN−\text{Cl}^- < {}^-\text{OH} < \text{Br}^- < \text{CN}^-Cl−<−OH<Br−<CN−
  2. (B)F−<Br−<I−<NH3\text{F}^- < \text{Br}^- < \text{I}^- < \text{NH}_3F−<Br−<I−<NH3​
  3. (C)Br−<F−<H2O<NH3\text{Br}^- < \text{F}^- < \text{H}_2\text{O} < \text{NH}_3Br−<F−<H2​O<NH3​
  4. (D)H2O<−OH<CN−<NH3\text{H}_2\text{O} < {}^-\text{OH} < \text{CN}^- < \text{NH}_3H2​O<−OH<CN−<NH3​

Correct answer: (C)

Step-by-step solution →
Q45·ChemistrySingle correct
Which of the following gives a positive test with ninhydrin?
  1. (A)Cellulose
  2. (B)Starch
  3. (C)Polyvinyl chloride
  4. (D)Egg albumin

Correct answer: (D)

Step-by-step solution →
Q46·ChemistrySingle correct
The metal that shows the highest and maximum number of oxidation states is:
  1. (A)Fe
  2. (B)Mn
  3. (C)Ti
  4. (D)Co

Correct answer: (B)

Step-by-step solution →
Q47·ChemistrySingle correct
An organic compound has 42.1% carbon, 6.4% hydrogen and the remainder oxygen. If its molecular weight is 342, then its molecular formula is:
  1. (A)C11H18O12\text{C}_{11}\text{H}_{18}\text{O}_{12}C11​H18​O12​
  2. (B)C12H20O12\text{C}_{12}\text{H}_{20}\text{O}_{12}C12​H20​O12​
  3. (C)C14H20O10\text{C}_{14}\text{H}_{20}\text{O}_{10}C14​H20​O10​
  4. (D)C12H22O11\text{C}_{12}\text{H}_{22}\text{O}_{11}C12​H22​O11​

Correct answer: (D)

Step-by-step solution →
Q48·Chemistry·Alcohols and EthersSingle correct
Given below are two statements: Statement I: Bromination of phenol in a solvent with low polarity such as CHCl3\text{CHCl}_3CHCl3​ or CS2\text{CS}_2CS2​ requires a Lewis acid catalyst. Statement II: The Lewis acid catalyst polarises the bromine to generate Br+\text{Br}^+Br+. In the light of the above statements, choose the correct answer from the options given below:
  1. (A)Statement I is true but Statement II is false
  2. (B)Both Statement I and Statement II are true
  3. (C)Both Statement I and Statement II are false
  4. (D)Statement I is false but Statement II is true

Correct answer: (D)

Step-by-step solution →
Q49·ChemistrySingle correct
Molar ionic conductivities of a divalent cation and anion are 57 S cm2mol−157\ \text{S cm}^2\text{mol}^{-1}57 S cm2mol−1 and 73 S cm2mol−173\ \text{S cm}^2\text{mol}^{-1}73 S cm2mol−1 respectively. The molar conductivity of a solution of an electrolyte with the above cation and anion will be:
  1. (A)65 S cm2mol−165\ \text{S cm}^2\text{mol}^{-1}65 S cm2mol−1
  2. (B)130 S cm2mol−1130\ \text{S cm}^2\text{mol}^{-1}130 S cm2mol−1
  3. (C)187 S cm2mol−1187\ \text{S cm}^2\text{mol}^{-1}187 S cm2mol−1
  4. (D)260 S cm2mol−1260\ \text{S cm}^2\text{mol}^{-1}260 S cm2mol−1

Correct answer: (B)

Step-by-step solution →
Q50·ChemistrySingle correct
The number of neutrons present in the more abundant isotope of boron is 'x'. Amorphous boron upon heating with air forms a product in which the oxidation state of boron is 'y'. The value of x+yx + yx+y is:
  1. (A)4
  2. (B)6
  3. (C)3
  4. (D)9

Correct answer: (D)

Step-by-step solution →
Q51·ChemistryNumerical
The value of the Rydberg constant RHR_HRH​ is 2.18×10−182.18\times10^{-18}2.18×10−18 J. The velocity of an electron of mass 9.1×10−319.1\times10^{-31}9.1×10−31 kg in Bohr's first orbit of the hydrogen atom is ___ ×106 ms−1\times10^{6}\ \text{ms}^{-1}×106 ms−1 (nearest integer).

Correct answer: 22

Step-by-step solution →
Q52·ChemistryNumerical
In a borax bead test under hot condition, a metal salt (one from the given) is heated at point B of the flame (shown in the figure), resulting in a green-coloured bead. The spin-only magnetic moment value of the salt is ___ (nearest integer). [Given atomic numbers: Cu = 29, Ni = 28, Mn = 25, Fe = 26]

Correct answer: 6

Step-by-step solution →
Q53·ChemistryNumerical
The heat of combustion of solid benzoic acid at constant volume is −321.30-321.30−321.30 kJ at 27∘C27^{\circ}\text{C}27∘C. The heat of combustion at constant pressure is (−321.30−xR)(-321.30 - xR)(−321.30−xR) kJ. The value of x is ___.

Correct answer: 150

Step-by-step solution →
Q54·Chemistry·Alcohols and EthersNumerical
Consider the reaction sequence: phenol reacts with concentrated H2SO4\text{H}_2\text{SO}_4H2​SO4​ to give Product A, which then reacts with concentrated HNO3\text{HNO}_3HNO3​ to give Product B. The total sum of oxygen atoms in Product A and Product B is ___.

Correct answer: 14

Step-by-step solution →
Q55·ChemistryNumerical
The spin-only magnetic moment value of the ion among Ti2+\text{Ti}^{2+}Ti2+, V2+\text{V}^{2+}V2+, Co3+\text{Co}^{3+}Co3+ and Cr2+\text{Cr}^{2+}Cr2+ that acts as a strong oxidising agent in aqueous solution is ___ BM (nearest integer). (Given atomic numbers: Ti = 22, V = 23, Cr = 24, Co = 27)

Correct answer: 5

Step-by-step solution →
Q56·ChemistryNumerical
During the kinetic study of the reaction 2A+B→C+D2A + B \rightarrow C + D2A+B→C+D, the following results were obtained: (I) [A]=0.1[A]=0.1[A]=0.1, [B]=0.1[B]=0.1[B]=0.1, rate =6.0×10−3=6.0\times10^{-3}=6.0×10−3; (II) [A]=0.3[A]=0.3[A]=0.3, [B]=0.2[B]=0.2[B]=0.2, rate =7.2×10−2=7.2\times10^{-2}=7.2×10−2; (III) [A]=0.3[A]=0.3[A]=0.3, [B]=0.4[B]=0.4[B]=0.4, rate =2.88×10−1=2.88\times10^{-1}=2.88×10−1; (IV) [A]=0.4[A]=0.4[A]=0.4, [B]=0.1[B]=0.1[B]=0.1, rate =2.40×10−2=2.40\times10^{-2}=2.40×10−2 (all rates of formation of D, in M s−1^{-1}−1). Based on the above data, the overall order of the reaction is ___.

Correct answer: 3

Step-by-step solution →
Q57·ChemistryNumerical
An artificial cell is made by encapsulating a 0.2 M glucose solution within a semipermeable membrane. The osmotic pressure developed when the artificial cell is placed within a 0.05 M solution of NaCl at 300 K is ___ ×10−1\times10^{-1}×10−1 bar (nearest integer). [Given R=0.083 L bar mol−1K−1R = 0.083\ \text{L bar mol}^{-1}\text{K}^{-1}R=0.083 L bar mol−1K−1; assume complete dissociation of NaCl.]

Correct answer: 25

Step-by-step solution →
Q58·ChemistryNumerical
From the following monohalobenzenes — fluorobenzene, chlorobenzene, bromobenzene, iodobenzene and astatobenzene — the number that can be prepared by Sandmeyer's reaction is ___.

Correct answer: 2

Step-by-step solution →
Q59·ChemistryNumerical
In the Lewis dot structure for NO2−\text{NO}_2^-NO2−​, the total number of valence electrons around nitrogen is ___.

Correct answer: 8

Step-by-step solution →
Q60·ChemistryNumerical
9.3 g of pure aniline is treated with bromine water at room temperature to give a white precipitate of the product 'P'. The mass of product 'P' obtained is 26.4 g. The percentage yield is ___ %.

Correct answer: 80

Step-by-step solution →

Mathematics — JEE Main 5 April 2024 Shift 1

Q61·MathematicsSingle correct
Let ddd be the distance of the point of intersection of the lines x+63=y2=z+11\dfrac{x+6}{3}=\dfrac{y}{2}=\dfrac{z+1}{1}3x+6​=2y​=1z+1​ and x−74=y−93=z−42\dfrac{x-7}{4}=\dfrac{y-9}{3}=\dfrac{z-4}{2}4x−7​=3y−9​=2z−4​ from the point (7,8,9)(7, 8, 9)(7,8,9). Then d2+6d^2 + 6d2+6 is equal to:
  1. (A)727272
  2. (B)696969
  3. (C)757575
  4. (D)787878

Correct answer: (C)

Step-by-step solution →
Q62·MathematicsSingle correct
Let a rectangle ABCD of sides 2 and 4 be inscribed in another rectangle PQRS such that the vertices of the rectangle ABCD lie on the sides of the rectangle PQRS. Let aaa and bbb be the sides of the rectangle PQRS when its area is maximum. Then (a+b)2(a + b)^2(a+b)2 is equal to:
  1. (A)727272
  2. (B)606060
  3. (C)808080
  4. (D)646464

Correct answer: (A)

Step-by-step solution →
Q63·MathematicsSingle correct
Let two straight lines drawn from the origin O intersect the line 3x+4y=123x + 4y = 123x+4y=12 at the points P and Q such that ΔOPQ\Delta OPQΔOPQ is an isosceles triangle and ∠POQ=90∘\angle POQ = 90^\circ∠POQ=90∘. If l=OP2+PQ2+QO2l = OP^2 + PQ^2 + QO^2l=OP2+PQ2+QO2, then the greatest integer less than or equal to lll is:
  1. (A)444444
  2. (B)484848
  3. (C)464646
  4. (D)424242

Correct answer: (C)

Step-by-step solution →
Q64·MathematicsSingle correct
If y=y(x)y = y(x)y=y(x) is the solution of the differential equation dydx+2y=sin⁡(2x)\dfrac{dy}{dx} + 2y = \sin(2x)dxdy​+2y=sin(2x), y(0)=34y(0) = \dfrac{3}{4}y(0)=43​, then y(π8)y\left(\dfrac{\pi}{8}\right)y(8π​) is equal to:
  1. (A)e−π/8e^{-\pi/8}e−π/8
  2. (B)e−π/4e^{-\pi/4}e−π/4
  3. (C)eπ/4e^{\pi/4}eπ/4
  4. (D)eπ/8e^{\pi/8}eπ/8

Correct answer: (B)

Step-by-step solution →
Q65·MathematicsSingle correct
For the function f(x)=sin⁡x+3x−2π(x2+x)f(x) = \sin x + 3x - \dfrac{2}{\pi}(x^2 + x)f(x)=sinx+3x−π2​(x2+x), where x∈[0,π2]x \in \left[0, \dfrac{\pi}{2}\right]x∈[0,2π​], consider the following two statements: (I) fff is increasing in (0,π2)\left(0, \dfrac{\pi}{2}\right)(0,2π​). (II) f′f'f′ is decreasing in (0,π2)\left(0, \dfrac{\pi}{2}\right)(0,2π​). Between the above two statements,
  1. (A)only (I) is true.
  2. (B)only (II) is true.
  3. (C)neither (I) nor (II) is true.
  4. (D)both (I) and (II) are true.

Correct answer: (D)

Step-by-step solution →
Q66·MathematicsSingle correct
If the system of equations 11x+y+λz=−511x + y + \lambda z = -511x+y+λz=−5, 2x+3y+5z=32x + 3y + 5z = 32x+3y+5z=3, 8x−19y−39z=μ8x - 19y - 39z = \mu8x−19y−39z=μ has infinitely many solutions, then λ4−μ\lambda^4 - \muλ4−μ is equal to:
  1. (A)494949
  2. (B)454545
  3. (C)474747
  4. (D)515151

Correct answer: (C)

Step-by-step solution →
Q67·MathematicsSingle correct
Let A={1,3,7,9,11}A = \{1, 3, 7, 9, 11\}A={1,3,7,9,11} and B={2,4,5,7,8,10,12}B = \{2, 4, 5, 7, 8, 10, 12\}B={2,4,5,7,8,10,12}. Then the total number of one-one maps f:A→Bf : A \to Bf:A→B, such that f(1)+f(3)=14f(1) + f(3) = 14f(1)+f(3)=14, is:
  1. (A)180180180
  2. (B)120120120
  3. (C)480480480
  4. (D)240240240

Correct answer: (D)

Step-by-step solution →
Q68·Mathematics·Limits and ContinuitySingle correct
If the function f(x)=sin⁡3x+αsin⁡x−βcos⁡3xx3f(x) = \dfrac{\sin 3x + \alpha \sin x - \beta \cos 3x}{x^3}f(x)=x3sin3x+αsinx−βcos3x​, x∈Rx \in \mathbb{R}x∈R, is continuous at x=0x = 0x=0, then f(0)f(0)f(0) is equal to:
  1. (A)222
  2. (B)−2-2−2
  3. (C)444
  4. (D)−4-4−4

Correct answer: (D)

Step-by-step solution →
Q69·MathematicsSingle correct
The integral ∫0π/4136sin⁡x3sin⁡x+5cos⁡x dx\displaystyle\int_{0}^{\pi/4} \dfrac{136\sin x}{3\sin x + 5\cos x}\,dx∫0π/4​3sinx+5cosx136sinx​dx is equal to:
  1. (A)3π−50log⁡e2+20log⁡e53\pi - 50\log_e 2 + 20\log_e 53π−50loge​2+20loge​5
  2. (B)3π−25log⁡e2+10log⁡e53\pi - 25\log_e 2 + 10\log_e 53π−25loge​2+10loge​5
  3. (C)3π−10log⁡e(22)+10log⁡e53\pi - 10\log_e\left(2\sqrt{2}\right) + 10\log_e 53π−10loge​(22​)+10loge​5
  4. (D)3π−30log⁡e2+20log⁡e53\pi - 30\log_e 2 + 20\log_e 53π−30loge​2+20loge​5

Correct answer: (A)

Step-by-step solution →
Q70·MathematicsSingle correct
The coefficients a,b,ca, b, ca,b,c in the quadratic equation ax2+bx+c=0ax^2 + bx + c = 0ax2+bx+c=0 are chosen from the set {1,2,3,4,5,6,7,8}\{1, 2, 3, 4, 5, 6, 7, 8\}{1,2,3,4,5,6,7,8}. The probability of this equation having repeated roots is:
  1. (A)3256\dfrac{3}{256}2563​
  2. (B)1128\dfrac{1}{128}1281​
  3. (C)164\dfrac{1}{64}641​
  4. (D)3128\dfrac{3}{128}1283​

Correct answer: (C)

Step-by-step solution →
Q71·MathematicsSingle correct
Let A and B be two square matrices of order 3 such that ∣A∣=3|A| = 3∣A∣=3 and ∣B∣=2|B| = 2∣B∣=2. Then ∣ATA(adj(2A))−1(adj(4B))(adj(AB))−1AAT∣\left|A^T A(\text{adj}(2A))^{-1} (\text{adj}(4B))(\text{adj}(AB))^{-1} A A^T\right|​ATA(adj(2A))−1(adj(4B))(adj(AB))−1AAT​ is equal to:
  1. (A)646464
  2. (B)818181
  3. (C)323232
  4. (D)108108108

Correct answer: (A)

Step-by-step solution →
Q72·MathematicsSingle correct
Let a circle C of radius 1 and closer to the origin be such that the lines passing through the point (3,2)(3, 2)(3,2) and parallel to the coordinate axes touch it. Then the shortest distance of the circle C from the point (5,5)(5, 5)(5,5) is:
  1. (A)222\sqrt{2}22​
  2. (B)555
  3. (C)424\sqrt{2}42​
  4. (D)444

Correct answer: (D)

Step-by-step solution →
Q73·MathematicsSingle correct
Let the line 2x+3y−k=02x + 3y - k = 02x+3y−k=0, k>0k > 0k>0, intersect the x-axis and y-axis at the points A and B, respectively. If the equation of the circle having the line segment AB as a diameter is x2+y2−3x−2y=0x^2 + y^2 - 3x - 2y = 0x2+y2−3x−2y=0 and the length of the latus rectum of the ellipse x2+9y2=k2x^2 + 9y^2 = k^2x2+9y2=k2 is mn\dfrac{m}{n}nm​, where m and n are coprime, then 2m+n2m + n2m+n is equal to:
  1. (A)101010
  2. (B)111111
  3. (C)131313
  4. (D)121212

Correct answer: (B)

Step-by-step solution →
Q74·MathematicsSingle correct
Consider the following two statements: Statement I: For any two non-zero complex numbers z1,z2z_1, z_2z1​,z2​, (∣z1∣+∣z2∣)∣z1∣z1∣+z2∣z2∣∣≤2(∣z1∣+∣z2∣)(|z_1| + |z_2|)\left|\dfrac{z_1}{|z_1|} + \dfrac{z_2}{|z_2|}\right| \le 2(|z_1| + |z_2|)(∣z1​∣+∣z2​∣)​∣z1​∣z1​​+∣z2​∣z2​​​≤2(∣z1​∣+∣z2​∣) and Statement II: If x,y,zx, y, zx,y,z are three distinct complex numbers and a,b,ca, b, ca,b,c are three positive real numbers such that a∣y−z∣=b∣z−x∣=c∣x−y∣\dfrac{a}{|y-z|} = \dfrac{b}{|z-x|} = \dfrac{c}{|x-y|}∣y−z∣a​=∣z−x∣b​=∣x−y∣c​, then a2y−z+b2z−x+c2x−y=1\dfrac{a^2}{y-z} + \dfrac{b^2}{z-x} + \dfrac{c^2}{x-y} = 1y−za2​+z−xb2​+x−yc2​=1. Between the above two statements,
  1. (A)both Statement I and Statement II are incorrect.
  2. (B)Statement I is incorrect but Statement II is correct.
  3. (C)Statement I is correct but Statement II is incorrect.
  4. (D)both Statement I and Statement II are correct.

Correct answer: (C)

Step-by-step solution →
Q75·MathematicsSingle correct
Suppose θ∈[0,π4]\theta \in \left[0, \dfrac{\pi}{4}\right]θ∈[0,4π​] is a solution of 4cos⁡θ−3sin⁡θ=14\cos\theta - 3\sin\theta = 14cosθ−3sinθ=1. Then cos⁡θ\cos\thetacosθ is equal to:
  1. (A)4(36−2)\dfrac{4}{\left(3\sqrt{6} - 2\right)}(36​−2)4​
  2. (B)6−6(36−2)\dfrac{6 - \sqrt{6}}{\left(3\sqrt{6} - 2\right)}(36​−2)6−6​​
  3. (C)6+6(36+2)\dfrac{6 + \sqrt{6}}{\left(3\sqrt{6} + 2\right)}(36​+2)6+6​​
  4. (D)4(36+2)\dfrac{4}{\left(3\sqrt{6} + 2\right)}(36​+2)4​

Correct answer: (A)

Step-by-step solution →
Q76·MathematicsSingle correct
If 11+2+12+3+…+199+100=m\dfrac{1}{\sqrt{1}+\sqrt{2}} + \dfrac{1}{\sqrt{2}+\sqrt{3}} + \ldots + \dfrac{1}{\sqrt{99}+\sqrt{100}} = m1​+2​1​+2​+3​1​+…+99​+100​1​=m and 11⋅2+12⋅3+…+199⋅100=n\dfrac{1}{1\cdot 2} + \dfrac{1}{2\cdot 3} + \ldots + \dfrac{1}{99\cdot 100} = n1⋅21​+2⋅31​+…+99⋅1001​=n, then the point (m,n)(m, n)(m,n) lies on the line:
  1. (A)11(x−1)−100(y−2)=011(x - 1) - 100(y - 2) = 011(x−1)−100(y−2)=0
  2. (B)11(x−2)−100(y−1)=011(x - 2) - 100(y - 1) = 011(x−2)−100(y−1)=0
  3. (C)11(x−1)−100y=011(x - 1) - 100y = 011(x−1)−100y=0
  4. (D)11x−100y=011x - 100y = 011x−100y=0

Correct answer: (D)

Step-by-step solution →
Q77·Mathematics·DifferentiabilitySingle correct
Let f(x)=x5+2x3+3x+1f(x) = x^5 + 2x^3 + 3x + 1f(x)=x5+2x3+3x+1, x∈Rx \in \mathbb{R}x∈R, and g(x)g(x)g(x) be a function such that g(f(x))=xg(f(x)) = xg(f(x))=x for all x∈Rx \in \mathbb{R}x∈R. Then g(7)g′(7)\dfrac{g(7)}{g'(7)}g′(7)g(7)​ is equal to:
  1. (A)777
  2. (B)424242
  3. (C)111
  4. (D)141414

Correct answer: (D)

Step-by-step solution →
Q78·MathematicsSingle correct
If A(1,−1,2)A(1, -1, 2)A(1,−1,2), B(5,7,−6)B(5, 7, -6)B(5,7,−6), C(3,4,−10)C(3, 4, -10)C(3,4,−10) and D(−1,−4,−2)D(-1, -4, -2)D(−1,−4,−2) are the vertices of a quadrilateral ABCD, then its area is:
  1. (A)122912\sqrt{29}1229​
  2. (B)242924\sqrt{29}2429​
  3. (C)24724\sqrt{7}247​
  4. (D)48748\sqrt{7}487​

Correct answer: (A)

Step-by-step solution →
Q79·MathematicsSingle correct
The value of ∫−ππ2y(1+sin⁡y)1+cos⁡2y dy\displaystyle\int_{-\pi}^{\pi} \dfrac{2y(1+\sin y)}{1+\cos^2 y}\,dy∫−ππ​1+cos2y2y(1+siny)​dy is:
  1. (A)π2\pi^2π2
  2. (B)π22\dfrac{\pi^2}{2}2π2​
  3. (C)π2\dfrac{\pi}{2}2π​
  4. (D)2π22\pi^22π2

Correct answer: (A)

Step-by-step solution →
Q80·MathematicsSingle correct
If the line 2−x3=3y−24λ+1=4−z\dfrac{2-x}{3} = \dfrac{3y-2}{4\lambda+1} = 4 - z32−x​=4λ+13y−2​=4−z makes a right angle with the line x+33μ=1−2y6=5−z7\dfrac{x+3}{3\mu} = \dfrac{1-2y}{6} = \dfrac{5-z}{7}3μx+3​=61−2y​=75−z​, then 4λ+9μ4\lambda + 9\mu4λ+9μ is equal to:
  1. (A)131313
  2. (B)444
  3. (C)555
  4. (D)666

Correct answer: (D)

Step-by-step solution →
Q81·MathematicsNumerical
From a lot of 10 items, which include 3 defective items, a sample of 5 items is drawn at random. Let the random variable X denote the number of defective items in the sample. If the variance of X is σ2\sigma^2σ2, then 96σ296\sigma^296σ2 is equal to ___.

Correct answer: 56

Step-by-step solution →
Q82·MathematicsNumerical
If the constant term in the expansion of (1+2x−3x3)(32x2−13x)9\left(1 + 2x - 3x^3\right)\left(\dfrac{3}{2}x^2 - \dfrac{1}{3x}\right)^9(1+2x−3x3)(23​x2−3x1​)9 is ppp, then 108p108p108p is equal to ___.

Correct answer: 54

Step-by-step solution →
Q83·MathematicsNumerical
The area of the region enclosed by the parabolas y=x2−5xy = x^2 - 5xy=x2−5x and y=7x−x2y = 7x - x^2y=7x−x2 is ___.

Correct answer: 72

Step-by-step solution →
Q84·MathematicsNumerical
The number of ways of getting a sum 16 on throwing a dice four times is ___.

Correct answer: 125

Step-by-step solution →
Q85·MathematicsNumerical
If S={a∈R:∣2a−1∣=3[a]+2{a}}S = \{a \in \mathbb{R} : |2a - 1| = 3[a] + 2\{a\}\}S={a∈R:∣2a−1∣=3[a]+2{a}}, where [t][t][t] denotes the greatest integer less than or equal to ttt and {t}\{t\}{t} represents the fractional part of ttt, then 72∑a∈Sa72\displaystyle\sum_{a \in S} a72a∈S∑​a is equal to ___.

Correct answer: 18

Step-by-step solution →
Q86·MathematicsNumerical
Let fff be a differentiable function in the interval (0,∞)(0, \infty)(0,∞) such that f(1)=1f(1) = 1f(1)=1 and lim⁡t→xt2f(x)−x2f(t)t−x=1\displaystyle\lim_{t \to x} \dfrac{t^2 f(x) - x^2 f(t)}{t - x} = 1t→xlim​t−xt2f(x)−x2f(t)​=1 for each x>0x > 0x>0. Then 2f(2)+3f(3)2f(2) + 3f(3)2f(2)+3f(3) is equal to ___.

Correct answer: 24

Step-by-step solution →
Q87·MathematicsNumerical
Let a1,a2,a3,…a_1, a_2, a_3, \ldotsa1​,a2​,a3​,… be in an arithmetic progression of positive terms. Let Ak=a12−a22+a32−a42+…+a2k−12−a2k2A_k = a_1^2 - a_2^2 + a_3^2 - a_4^2 + \ldots + a_{2k-1}^2 - a_{2k}^2Ak​=a12​−a22​+a32​−a42​+…+a2k−12​−a2k2​. If A3=−153A_3 = -153A3​=−153, A5=−435A_5 = -435A5​=−435 and a12+a22+a32=66a_1^2 + a_2^2 + a_3^2 = 66a12​+a22​+a32​=66, then a17−A7a_{17} - A_7a17​−A7​ is equal to ___.

Correct answer: 910

Step-by-step solution →
Q88·MathematicsNumerical
Let a⃗=i^−3j^+7k^\vec{a} = \hat{i} - 3\hat{j} + 7\hat{k}a=i^−3j^​+7k^, b⃗=2i^−j^+k^\vec{b} = 2\hat{i} - \hat{j} + \hat{k}b=2i^−j^​+k^ and c⃗\vec{c}c be a vector such that (a⃗+2b⃗)×c⃗=3(c⃗×a⃗)(\vec{a} + 2\vec{b}) \times \vec{c} = 3(\vec{c} \times \vec{a})(a+2b)×c=3(c×a). If a⃗⋅c⃗=130\vec{a} \cdot \vec{c} = 130a⋅c=130, then b⃗⋅c⃗\vec{b} \cdot \vec{c}b⋅c is equal to ___.

Correct answer: 30

Step-by-step solution →
Q89·MathematicsNumerical
The number of distinct real roots of the equation ∣x∣ ∣x+2∣−5∣x+1∣−1=0|x|\,|x + 2| - 5|x + 1| - 1 = 0∣x∣∣x+2∣−5∣x+1∣−1=0 is ___.

Correct answer: 3

Step-by-step solution →
Q90·MathematicsNumerical
Suppose ABABAB is a focal chord of the parabola y2=12xy^2 = 12xy2=12x of length lll and slope m<3m < \sqrt{3}m<3​. If the distance of the chord ABABAB from the origin is ddd, then ld2ld^2ld2 is equal to ___.

Correct answer: 108

Step-by-step solution →

Chapters tested in this paper

Open any chapter to practise every past-year question on that topic across all papers, and see how often it has actually appeared.

  • Properties of Solids and Liquids 172/186
  • Three Dimensional Geometry 176/186
  • Matrices and Determinants 180/186
  • Coordination Compounds 176/186
  • Sets, Relations and Functions 165/186
  • Current Electricity 160/186
  • Sequence and Series 164/186
  • p-Block Elements 164/186
  • Definite Integration 168/186
  • Rotational Motion 172/186
  • Redox Reactions and Electrochemistry 177/186
  • Kinematics 156/186
  • Vector Algebra 173/186
  • Differential Equations 167/186
  • Probability 176/186
  • Permutations and Combinations 162/186
  • Magnetic Field of Current 147/186
  • Binomial Theorem and Its Simple Applications 158/186
  • Electromagnetic Waves 144/186
  • Chemical Bonding and Molecular Structure 151/186
  • Application of Derivatives 139/186
  • Limits and Continuity 149/186
  • d- and f-Block Elements 126/186
  • Thermodynamics 154/186
  • Aldehydes and Ketones 135/186
  • Equilibrium 163/186
  • Solutions 158/186
  • Laws of Motion 130/186
  • Chemical Thermodynamics 165/186
  • Units and Measurements 149/186
  • Hydrocarbons 126/186
  • Complex Numbers 165/186
  • Trigonometric Functions 144/186
  • Biomolecules 162/186
  • Chemical Kinetics 169/186
  • Gravitation 152/186
  • Atomic Structure 161/186
  • Electronic Devices 145/186
  • Circles 142/186
  • Dual Nature of Matter and Radiation 155/186
  • Amines 133/186
  • Quadratic Equations 148/186
  • Work, Energy and Power 132/186
  • Some Basic Concepts in Chemistry 129/186
  • Electromagnetic Induction 120/186
  • Wave Optics 130/186
  • Area Under Curves 139/186
  • Kinetic Theory of Gases 135/186
  • Alcohols and Ethers 106/186
  • Alternating Currents 108/186
  • Nuclei 116/186
  • Straight Lines 114/186
  • Capacitors and Dielectrics 115/186
  • Atoms 112/186
  • Classification of Elements and Periodicity in Properties 113/186
  • Parabola 101/186
  • Ellipse 103/186
  • Differentiability 91/186
  • Experimental Skills 68/186
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